Mario was riding a bicycle with wheels 26 inches in diameter. During one minute of Mario’s ride, the wheels made exactly 200 revolutions. At what average speed, in feet per second, was Mario riding during that minute?
The correct answer is A.
Step - by - step answer:
Mario will travel a distance equal to 1 circumference of the wheel for each complete revolution of the wheel.
Circumference of Mario's wheel, C = πD, where D is the diameter of the circle.
Hence, C = 26π inches
Speed = Distance / Time
Distance for 200 revolutions in ft = 26π x 200 x 1/12
Time in sec = 60
So, speed = (26π x 200)/(12 x 60)
= 65π/9
=22.69 is the average speed.
P.s: Answer is copied from https://www.myactguide.com/math/mario-was-riding-a-bicycle-with-wheels-26-inches-in-diameter
What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−7)2+11?
Enter your answer as the correct equation, like this: x = 42
Answer:
I think its x = 7
I belive it is
which set of ordered pairs corresponds to the graph ?
Answer:
Let first check the coordinates of the points
A = (1 , -6)
B = (2 , -4)
C = (2, -2)
D = (4, -2)
E = ( 6, 0)
Option 4 is correct..
Explanation -
to find the coordinates we have to find the distance of that point from x Axis and then y axis. from origin.
ADVANCED COSTING AND MANAGEMENT ACCOUNTING
A car engine manufacturer is trying to make an assessment of its operations for the past year. The
entity operates a standard marginal costing system and manufactures a state-of-the-art engine for
which the following standard revenue and cost data per unit of product is available:
Selling price $60.00
Direct material A 2.5 kg at $8.50 per kg
Direct material B 1.5 kg at $6.00 per kg
Direct labour 0.45 hrs. at $30.00 per hour
Actual data for the twelve-month period was as follows:
Sales and production 48,000 units of the blaster were produced and sold for $2,904,000
Direct material A 121,900 kg were used at a cost of $1,005,675
Direct material B 67,200 kg were used at a cost of $420,000
Direct labour Employees worked for 18,900 hours, but 19,200 hours were paid at a cost
of $585,600.
Budgeted sales for the period were 50,000 units of Product Blaster. A recession last year meant
that the market for the product declined by 5%.
Required:
(a) Calculate the following variances.
(i) Sales volume variance.
The Sales Volume Variance of the car manufacturer for the twelve-month period is $96,000.
What is the sales volume variance?The sales volume variance measures the financial impact of not meeting or exceeding the budgeted sales for a period.
It can be computed by finding the difference between actual and budgeted sales quantities and then multiplied by the unit selling price.
Data and Calculations:Budgeted sales units = 50,000
Actual sales units = 48,000
Sales price per unit = $60
Actual sales revenue = $2,904,000
Budgeted sales revenue = $3,000,000 ($60 x 50,000)
Sales volume variance = $96,000 ($3,000,000 - $2,904,000)
Thus, the Sales Volume Variance is $96,000.
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Find the formula for the area of the shaded region in the figure.
x² = 4py
ہے
The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
What is the formula for the area of the shaded region in the figure?Parameters
[tex]$x^{2}=4 p y$[/tex]
[tex]$y=h$[/tex]
[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]
Generally, the equation for the Area is mathematically given as
[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]
[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
In conclusion, the equation for the Area is
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
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Solve each inequality and graph the solution on a
number line.
a.) -12a +7 ≤31
b.) -9 > 3b +6
The solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)
What is inequality?It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.
We have two inequalities:
a.) -12a +7 ≤31
b.) -9 > 3b +6
a) -12a +7 ≤ 31
-12a ≤ 31 - 7
-12a ≤ 24
-a ≤ 2
a ≥ 2 (sign changed because multiplied by a negative number)
a ∈ [2, ∞)
b.) -9 > 3b +6
-15 > 3b
-5 > b
or
b < -5
b ∈ (-∞, -5)
Thus, the solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)
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The midpoint of FG is point H at (–5, 2). One endpoint is G(–9, –6). What is the y-coordinate of the other endpoint? The y-coordinate of the other endpoint is
The y-coordinate of the other endpoint is 10 units.
The given coordinates are H (-5, 2) and G (–9, –6).
We need to find the y-coordinate of the other endpoint.
What is the midpoint formula?The mid-point formula is [tex](x, y)=(\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2})[/tex]
Now, [tex](-5, 2)=(\frac{x_{1} +(-9)}{2} , \frac{y_{1} +(-6)}{2})[/tex]
⇒[tex]2=\frac{y_{1}-6 }{2}[/tex]
⇒[tex]4=y_{1}-6[/tex]
⇒[tex]y_{1}=10[/tex]
Therefore, the y-coordinate of the other endpoint is 10 units.
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CAN SOMEONE PLS HELP ME WITH BOTH OF THESE QUESTIONS
EXPLANATION IS NOT NEEDED
WILL MARK BRAINLIEST
The amount in the new checking account is 600 dollars
The operation (5 α 3) + (7 α 5) is 46.
How to find the amount in the checking account?She had 1000 dollars in her checking account. she had a loan of 800 dollars to pay.
After paying her loan form her checking account the balance of the loan reduce to half.
Therefore, she paid 800 / 2 = 400 dollars for her loan
Hence,
Her new checking account = 1000 - 400 = 600 dollars
How to find value of an operation?
a α b = ab - a + b
Therefore,
(5 α 3) + (7 α 5)
(5 α 3) = 5(3) - 5 + 3 = 13
(7 α 5) = 7(5) - 7 + 5 = 33
Therefore,
(5 α 3) + (7 α 5) = 13 + 33 = 46
Note: I can't use the at symbol because it is a swear word.
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8) 3/
of the magazines sold at a newsagents were wedding magazines.
What is this as a percentage?
44
Answer:
0.0085× 100= 0.85℅
Step-by-step explanation:
okay so you want 3/8 from 44 as percentage but how can you put the 3/8 on top of the 44 to multilply it by 100 to get the percentage, ofcourse we will have to change the 3/8 into a whole number. To do that we are going to do the following.
= 3 ÷ 8 = 0.375, so here you got a number that you can put on the 44.
Now to get the percentage we are going to do this:
0.375/44 × 100
= 0.0085 × 100 ( I solved the 0.375/44 as you know that division always comes first in maths)
= 0.85℅ ( I solved the 0.0085 × 100)
°•°•° I hope this helped sorry for taking long °•°•° May I get brainliest if you liked my ans im trying to lvl up ty and its okay if you don't want to
The ratio of the number of picture books encyclopedias, and fairy tale books Annette had is 3:4:5 She have half of her encyclopedias to her brother and he gave her 5 books of fairytales Now she has 14 more books of fairy tales than encyclopedias How many picture books does she have
The number of picture books does Annette have is 76 books.
Given the ratio of picture books , encyclopedias and fairy tales books is 3:4:5 and she have half of her encyclopedias to her brother and he gave her 5 books of fairytales
We need to find the number of picture books does she have
According to the statement the total number of books does Annette have is
3k+4k+5k = 12k
Where k is total number of books
Now , Picture book she have = 3/12k = 1/4k
Encyclopedia she have = 4/12k = 1/3k
Fairy tale she have = 5/12k
Here,
Encyclopedia +14 = Fairy tale
Substituting the values of Encyclopedia and Fairy tale
(1/3 -1/2)k +14 = (5/12k -5 )
Therefore.
(1/6k+14) = (5k/12-5)
Therefore,
14+5 = 5k/12 - k/6
Therefore,
19 = 3k/12
19*4=k
76 = k
Here k = 76 books
Hence the total number of picture books does she have is 76
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The mean of 6 numbers is 17. Four of the numbers are 15, 17, 20, and 22. The remaining two numbers are each equal to x. Calculate the sum of the 06 numbers and the value of x.
Answer:
Sum of 6 no. = 102X = 14
Let the unknown no. be X
mean= sum of all no. / no. of terms
17 = 15 + 17 + 20 + 22 + X+ X / 6
17 * 6 = 74 + 2X
102 - 74 = 2X
28 = 2X
28/2 = X
14= X
four times a number is 48 less than 6 times the number
Answer:
the answer is 24
Step-by-step explanation:
6x - 48 = 4x
6x - 4x - 48 = 0
2x - 48 = 0
2x = 0 + 48
2x = 48
x = 24
Assume that 900 births are randomly selected and 4 at the births are girls. Use subjective judgment to describe the number of girls as significantly high, significantly low, or neither
The number of girls are significantly low.
What is Probability ?Probability is the study of likeliness of an event to happen.
It is given that
900 births are randomly selected
The probability of birth of a boy or a girl is 1/2 = 0.5
Total chances of a girl is 900 * 0.5 = 450
The birth of girl observed is 4
Therefore the number of girls are significantly low.
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Whats the answer… also thats1/3
Find the value of y when x equals 4.
-3x + 9y = -57
Answer:
y = -5
Step-by-step explanation:
Isolate y:
-3x + 9y = -57
9y = -57 + 3x
y = (-57/9) + (3/9)x
Substitute for x:
y = (-57/9) + (3/9)(4)
y = (-57/9) + (12/9)
y = (-45/9)
y = -5
Answer:
[tex]\mathsf {y = -5}[/tex]
Step-by-step explanation:
[tex]\textsf {Given :}\\\textsf {-3x + 9y = -57}[/tex]
[tex]\textsf {Divide throughout by 3 :}[/tex]
[tex]\mathsf {\frac{1}{3} \times (-3x + 9y) = \frac{1}{3} \times -57}[/tex]
[tex]\mathsf {-x + 3y = -19}[/tex]
[tex]\textsf {Substitute x = 4 :}[/tex]
[tex]\mathsf {-(4) + 3y = -19}[/tex]
[tex]\mathsf {3y = -15}[/tex]
[tex]\textsf {Divide by 3 on both sides :}[/tex]
[tex]\mathsf {\frac{3y}{3} = \frac{-15}{3} }[/tex]
[tex]\mathsf {y = -5}[/tex]
The average THC content of marijuana sold on the street is 10.9%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street
(a) X ≈ N (0.10 , 0.02²)
(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.
(c) The 60th percentile is 11%.
The complete question is:The average THC content of marijuana sold on the street is 10%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. Round all answers to two decimal places and give THC content in units of percent. For example, for a THC content of 11%, write "11" not 0.11.A. X ~ N( , )
B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.
C. Find the 60th percentile for this distribution.
According to the question,
The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.
(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.
Therefore, X ≈ N (0.10 , 0.02²)
(b) The value of P (X > 0.11) as follows:
P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])
= P(Z > 0.50)
= 1 -P (Z <0.50)
= 1- 0.69146
= 0.30854 ≈ 0.31
Hence,
the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.
(c)Let x represent the 60th percentile value.
Then, P (X < x) = 0.60.
⇒ P (Z < z) = 0.60
The value of z is,
z = 0.26.
Now put the value of x as follows:
z = x - μσ
0.26 = x - 0.100.02
x = 0.10+ ( 0.26 x 0.02)
x = 0.1052
x ≈ 0.11
Therefore,
The 60th percentile is 11%
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There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75%
chance that it will rain here or on Mars. Explain why this is a false statement.
There is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75% chance that it will rain here or on Mars.
The probability that it will rain here:
P(rain here) = 50%
P(rain on mars) 50%
P(not rain here) = 100 - 50 = 50%
P(not rain on mars) = 100 - 50 = 50%
P(rain here and not on mars) = 0.5×0.5 = 0.25 or 25%
Thus, there is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.
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Help please I will give you a lot of points
Answer:
2 5/7 5/7 -1/7, -5/7, 1 2/7, -2 2/7, -1 5/7
Urgent
Solve a=P(1.3)^x/x
The equation of a=P(1.3)^{x/x} is mathematically given as
a=1.3P or P=a/1.3
What is the solution of a=P(1.3)^{x/x}?
Generally, the equation for the statement is mathematically given as
a=P(1.3)^{x/x}
Therefore,
a=P(1.3)^{x/x}
a=P(1.3)^1
a=Px1.3
a=1.3P or P=a/1.3
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Which Graph Represents A function ?
NEED ANSWER ASAP !!!!
Answer:
The very last one is a function
Step-by-step explanation:
The last one is a function because there are no y values that repeat. For example, If the points on one graph are like this; (1, 3) (2, 3); then it cannot be a function, the y values cannot repeat if it is a function.
To make things easier, just try to imagine vertical drawing lines through each point in every graph, if this imaginary vertical line passes more than one point in any graph, then that graph is not a function.
I hope this helps!! :D
Answer:
The last graph represents a function.
Explanation:
A function cannot be one-to-many, i.e., one value of x cannot produce multiple values of y.
In the first graph, when x = 1, y = 3 and y= -2, so it is not a function.
In the second graph, when x = 2, y = 2 and y = -2, so it's not a function.
In the third graph, when x = -3, y = 2 and y = -2, so it's not a function.
∴ In all the graphs except the last, single values of x give multiple values of y on the graph, so they are not functions.
1
2.
3
5 5
6
8
9
12
13
10-
8
6
909
NS
2
-6 -5 -4 -3 -2 -1 1 2 3 4
1 2 3 4 5 6 X
f
-6
-8
-10
-12-
-141
1 1 1
NO
w
f(4) = g(4)
Of(4) = g(-2)
O f2) = g(-2)
Of(-2) = g(-2)
Mark this and return
Answer: f(-3)=g(-3)
Step-by-step explanation:
The graphs intersect at x = -3.
The correct option is f(-3) = g(-3).
What is function?A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Given that two lines are intersecting at point (-3, -4)
Therefore the system of equations of these two have a solution at (-3, -4)
So, if taking the lines as function,
We have f(x) and g(x),
so both of them are intersecting at (-3, -4) so the range when the domain is -3 will be equal.
Hence the correct option is f(-3) = g(-3).
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Solve the inequality
How to convert from vertex to standard y=2(x-2)^2 -2 to standard
The quadratic equation in standard form is:
[tex]y = 2x^2 - 8x + 6[/tex]
How to convert from vertex form to standard?
Here we have the quadratic equation:
[tex]y = 2*(x - 2)^2 - 2[/tex]
Here we need to expand the right side, remember:
[tex](a + b)^2 = a^2 + 2ab + b^2[/tex]
Using that, we get:
[tex]y = 2*(x - 2)^2 - 2 = 2*(x^2 - 4x + 4) - 2\\\\y = 2x^2 - 8x + 8 - 2\\\\y = 2x^2 - 8x + 6[/tex]
This is the quadratic equation in standard form.
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What are the values for y when x is 2, 4, and 6?
y = 20x + 7
graph the line through (1,1) with slope 3/2
Answer:
y = (3/2)x - (1/2)
Step-by-step explanation:
The general structure of a line in slope-intercept form is:
y = mx + b
In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m" (3/2). To find the value of "b", you should plug "m" into the equation in addition to the "x" and "y" values from the given point (1,1)
(1,1) ----> x = 1, y = 1
m = 3/2
y = mx + b <----- Slope-intercept form
y = (3/2)x + b <----- Plug (3/2) into "m"
1 = (3/2)(1) + b <----- Plug values into "x" and "y" from point
1 = (3/2) + b <----- Multiply (3/2) and 1
(2/2) = (3/2) + b <----- Change 1 into common denominator
(-1/2) = b <----- Subtract (3/2) from both sides
Because you now have values for both variables, you can construct your final equation.
y = (3/2)x - (1/2)
If a patient is given 3 tablespoons of medication for me for 150 ML bottle how many millimeters of medication remain in the bottle
Answer:
105.6397
ROUNDED ANSWER:
105
f(x)= 2x^3 + 6x^2 -5x - 3, g(x)= 3x-4 find (f-g)(x)
The difference in the given functions is 2x^3 + 6x^2 -8x + 1
Difference of functionsGiven the following function a shown
f(x)= 2x^3 + 6x^2 -5x - 3
g(x)= 3x-4
Take the difference
(f-g)(x) = f(x) - g(x)
Substitute
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - (3x - 4)
Expand
(f-g)(x) = 2x^3 + 6x^2 -5x - 3 - 3x + 4
(f-g)(x) = 2x^3 + 6x^2 -8x + 1
Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1
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The quotient of (x5 – 3x3 – 3x2 – 10x + 15) and (x2 – 5) is a polynomial. What is the quotient?
The quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]
How to determine the quotient?The quotient can be represented as:
[tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]
Start by expanding the dividend
[tex]x^5 + 2x^3 - 5x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]
Rewrite as:
[tex]x^5 + 2x^3 - 3x^2 - 5x^3 - 10x + 15 \div x^2 - 5[/tex]
Factorize the dividend
[tex]x^2(x^3 + 2x - 3) - 5(x^3 + 2x - 3) \div x^2 - 5[/tex]
Factor out x^3 + 2x - 3
[tex](x^2- 5)(x^3 + 2x - 3) \div x^2 - 5[/tex]
Cancel out the common factor
[tex]x^3 + 2x - 3[/tex]
Hence, the quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]
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Answer: x3 + 2x – 3
Step-by-step explanation:
Richards Corporation uses the FIFO method of process costing. The following
information is available for October in its Fabricating Department:
Units:
Beginning Inventory: 80,000 units, 60% complete as to materials and 20%
complete as to conversion.
Units started and completed: 250,000.
Units completed and transferred out: 330,000.
Ending Inventory: 30,000 units, 40% complete as to materials and 10%
complete as to conversion.
Costs:
Costs in beginning Work in Process - Direct Materials: $37,200.
Costs in beginning Work in Process - Conversion: $79,700.
Costs incurred in October - Direct Materials: $646,800.
Costs incurred in October - Conversion: $919,300.
Calculate the equivalent units of materials.
If Richards Corporation uses the FIFO method of process costing. The equivalent units of materials is 294,000.
Equivalent unit of material (FIFO)
Using this formula
Equivalent unit of material (FIFO) =[(Beginning inventory×Percentage complete)+Units started and complete+ (Ending inventory× Percentage complete as to materials)]
Let plug in the formula
Equivalent unit of material (FIFO) = [80,000×40%+250,000+30,000×40%]
Equivalent unit of material (FIFO) = 32,000+250,000+12,000
Equivalent unit of material (FIFO) = 294,000
Therefore the equivalent units of materials is 294,000.
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What system of equations would you use to solve the problem below?
A test is worth 100 points. Multiple-choice questions are worth 3 points and
short-answer questions are worth 5 points. If the test has 28 questions, how
many multiple-choice questions are there?
Let x be multiple-choice questions
Let y be short-answer questions
x + y = 28
3x + 5y = 100
