The graph of f(x) = -x² + 2x + 1 and g(x) = 2ˣ, have the same y-intercept of (0, 1)
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Given the polynomial function f(x) = -x² + 2x + 1 and an exponential function g(x) = 2ˣ
From the graph of f(x) = -x² + 2x + 1 and g(x) = 2ˣ, have the same y-intercept of (0, 1)
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if f(c)=2x^2-x, find f(-4) - f(9)
Answer:
-13f
Simplify by combining the sum of 4 + 9 with the term "f" and assume integers will be negative.What is the decimal that is grater than 3/10 and less than 2/5.
The options are 0.32 , 0.035, 0.4 , 0.24
Answer:
0.32
Step-by-step explanation:
3/10=0.3
2/5=0.4
0.32 is between these two numbers.
Hope this Helps
evaluate the expression [tex](-0.3)^4[/tex]
the value of the expression is
The value of the expressions (-0.3)⁴ equal to 0.0081.
What is a mathematical expression?A mathematical expression is the representation of numbers in the form of powers or mathematical signs.
Here we have the (-0.3)⁴
Now by evaluating the expression we will get:
(-0.3)⁴=(-0.3x-0.3x-0.3x-0.3)
Hence the value of the given expression will be 0.0081
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Evaluate:
(34x3)+7+ 24/6
Answer: 113 ( 34x3+11
Step-by-step explanation:
Step 1- Divide the numbers34x 3 on top + 7 + 24/6
34 x 3 on top + 7 = 4
Step 2- Add the numbers34 x 3 on top + 7 + 4
34 x 3 on top + 11
34 x 3 on top + 11
how do i do this I forgot how to do this and I have a test tomorrow
Answer:
Step-by-step explanation:
(1 + 11)/(-2+5)= 12/3=4
y + 11 = 4(x + 5)
y + 11 = 4x + 20
y = 4x + 9
A particle moves on the circle x2 y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=6. What is the value of dydt at this time?
The movement of the particle on the circle is its displacement.
The value of dy/dt at this time is -9/2.
What is the differentiation?Differentiation is a process, in Maths, where we find the instantaneous rate of change in function based on one of its variables.
A particle moves on the circle x^2 + y^2=25 in the XY-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=6.
The equation of the circle is given as:
[tex]\rm x^2 + y^2=25[/tex]
Differentiate with respect to time
[tex]\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0[/tex]
Substitute all the values in the equation
[tex]\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0\\\\2(3) \times 6+2(4)\times \dfrac{dy}{dt}=0\\\\ 6 \times 6+8 \times \dfrac{dy}{dt}=0\\\\ 36+8\times \dfrac{dy}{dt}=0\\\\ 8\times \dfrac{dy}{dt}=-36\\\\ \dfrac{dy}{dt}= \dfrac{-36}{8}\\\\ \dfrac{dy}{dt}= \dfrac{-9}{2}[/tex]
Hence, the value of dy/dt at this time is -9/2.
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Mrs. Eaton's dass is participating in the "Box Teps for Education campaign. On the first day, her
class collected 2 lops. On the third day, her dass collected 8 tope. Let D represent each collection
day and N represent the number of tops collected on that day.
Based on the situation, John daims the number of tops colected can be modeled by an exponential
function. Riley disagrees and claims the number of tops can be modeled with a linear function. What
Is the number of tops collected on the abath day based on the exponential model? What is the
number of tops collected on the sixth day based on the linear model?
Number of tops on 6th day based on exponential model:
Number of tops on the 6th day based on the linear model:
The number of tops on the 6th day based on the exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.
What is an exponential function?It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent [tex]\rm y = a^x[/tex]
where a is a constant and a>1
First day class collected = 2 tops
Third day class collected = 8 tops
The exponential function can be modelled:
[tex]\rm D(N) = 2^N[/tex]
D(1) = 2 (first day)
D(3) = 8 (third day)
D(6) = 64 (sixth day)
The linear function can be modeled:
D(N) = 3N -1
D(1) = 2 (first day)
D(3) = 8 (third day)
D(6) = 17 (sixth day)
Thus, the number of tops on 6th day based on exponential model is 64, and the number of tops on the 6th day based on the linear model is 17.
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What is the area, in square meters, of the shaded part of the rectangle below?
Answer:
45.5 m²
Step-by-step explanation:
Area (Shaded) = Area (Rectangle) - Area (Trapezoid)
Area (Shaded) = lb - 1/2 x (a + b) x hArea (Shaded) = 17 × 13 - 1/2 × (10 + 17) × 13Area (Shaded) = 13 (17 - 27/2)Area (Shaded) = 13 × 7/2Area (Shaded) = 91/2Area (Shaded) = 45.5 m²Area of trapezoid:-
1/2(sum of parallel side)×Height1/2(10+17)(13)1/2(27)(13)13.5(13)175.5m²Area of triangle:-
1/2BH1/2(13)(17-10)1/2(13)(7)91/245.5m²Which part is shaded not said so both shaded regions area calculated
How much paper is used for the label on the can of peas?
Answer:
here
Step-by-step explanation:
find the circumference of the lid (this is like a side length of a rectangle)
2*pi*2= 12.566in
Then multiply by 3 (the other side length)
12.566*3= 37.7in squared :)
PLEASE HELPPP
The function f is giving by
f(x) = (x - 2)(x +4). What are the x-intercepts of the graph representing f?
Answer:
X intercepts are (-4,0) and (2,0)
Step-by-step explanation:
use the desmos graphing calculator for a simple answer
Scores on a recent administration of the SAT were approximately normally
distributed with a mean of 980 and a standard deviation of 135. Between what 2
scores would you expect to find about 95% of all test-takers?
Blank #1
Blank #2
Answer:
25 to 3 power ÷ 3 = 69
What is the median?
Answer:
6
Step-by-step explanation:To find the median, first order your data. Then calculate the middle position based on n, the number of values in your data set. If n is an odd number, the median lies at the position (n + 1) / 2. If n is an even number, the median is the mean of the values at positions n / 2 and (n / 2) + 1.
Answer:
6
Step-by-step explanation:
The mechanic does 6 oil changes 2 hours. How many oil changes can the mechanic do in 8 hours?
Answer:
24
Step-by-step explanation:
6/2 = x/8
x=24
24 oil changes
52% of students in a class have brown hair. If 4 students are chosen at random, what is the probability that exactly 3 have brown hair? Write your answer in percent rounded to the nearest whole number.
Answer:
[tex]P(X=3)\approx27\%[/tex]
Step-by-step explanation:
Use the binomial distribution
[tex]\displaystyle P(X=k)=\binom{n}{k}p^k(1-p)^{n-k}\\\\P(X=3)=\binom{4}{3}(0.52)^3(1-0.52)^{4-3}\\\\P(X=3)=\frac{4!}{3!(4-3)!}(0.52)^3(0.48)^1\\ \\P(X=3)=0.26996736\\\\P(X=3)\approx0.27\\\\P(X=3)\approx27\%[/tex]
Therefore, the probability that exactly 3 students out of 4 randomly chosen students have brown hair is about 27%
please help asap!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
30.96
Step-by-step explanation:
First you must find the diameter of the circle which is 12
Then you must use the formula A=πr²
So it should be = to A = 3.14 ×144 which is 30.96
[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]
[tex] \large\underline{ \boxed{ \sf{✰\:Notes }}}[/tex]
★ Concept ★➣ A square with sides 12m➣then a circle in between➣nd it's diameter is 12m bcz of side of square is equal to radius➣soo here things we to find is the area of circle and then square then by subtracting their will give us the area of shaded part in image[tex] \rule{70mm}{2.9pt}[/tex]
[tex] \large\underline{ \boxed{ \sf{✰\: formule\: used\:✰ }}}[/tex]
[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: circle = \pi {r}^{2} \: }}}✟}}[/tex]
[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: square = side \times side \: or \: ( {s}^{2}) \: }}}✟}}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
✛ 1st taking out the the area of circle✛
➣ value of pi = 3.14➣ diameter = 12m (have to find radius we know that radius is half of diameter) which is[tex] \qquad \rm{➛ \: radius(r) = \frac{12}{2} } \\ \\ \qquad \rm{➛ \: radius(r) = \frac{ \cancel{12}}{ \cancel2} } \\ \\ \qquad \rm{➛ \: radius(r) =6m}[/tex]
★ Hence radius of circle is 6m★ let's substitute values now ★[tex] \\ \qquad \rm{➛Area \: of \: circle = 3.14 \times {6}^{2} \:} \\ \\ \qquad \rm{➛Area \: of \: circle = \:3.14 \times 36} \\ \\ \qquad \rm{➛Area \: of \: circle = \:113.04 {m}^{2} }[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
✛ now finding the area of square✛
➣ here two given side are 12m★ let's substitute values now ★[tex]\\ \qquad \rm{➛Area \: of \:square = 12×12} \\ \\ \\ \qquad \rm{➛Area \: of \:square = 144 {m}^{2} }[/tex]
✞ Now according to given ques we have to find area of shaded part soo let's solve ! ✞[tex]\\ \rm{➛Area \: of \:shaded \: part = \: area \: of \: circle - area \: of \: squre} \\ [/tex]
★ Let's substitute value ★
[tex]\\ \rm{➛Area \: of \:shaded \: part =113.04-144} \\ \\ \qquad \rm{➛Area \: of \:shaded \: part =30.96 {m}^{2} }[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
★ Hence area of shaded part =
[tex]{ \boxed{✜\underline{ \boxed{ \sf{ \: 30.96 {m}^{2} \green✓\: }}}✜}}[/tex]
★ note here we neglect minus (-)
[tex] \rule{70mm}{2.9pt}[/tex]
Hope it helps !
Please Help! Cube Roots
3 square root 56 + 3 square root 189
Step-by-step explanation:
cubic root(56) + cubic root(189) =
= cubic root(7×8) + cubic root(27×7) =
= 2×cubic root(7) + 3×cubic root(7) = 5×cubic root(7) =
= 9.564655914...
i will mark brainliest!
The completed code to generate and save a number in the program which allow a user to guess a number from (1,10) is input.
What is a program in coding?Program or programming is the combination of codes. These codes are used to generate the program such that a machine can understand the inputs given to it.
The program is written to allow a user to guess a number. This number should be between the number 0 to 10.
Here, the input is needed to a machine or computer, for which it's process the number and show if the guessed number is correct or not.
Hence, the completed code to generate and save a number in the program which allow a user to guess a number from (1,10) is input.
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HELPPP!!!!
Solve this system of equations using the inverse of a matrix.
-x +y = 8
4x + 3y = 12
x - 7y + z = 15
The Solution of -x +y = 84, x + 3y = 12, x - 7y + z = 15 be [tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; =\left[\begin{array}{ccc}-1.76\\6.24\\60.76\end{array}\right][/tex]
The correct option is (C)
What is inverse of Matrix?The inverse of matrix is another matrix, which on multiplying with the given matrix gives the multiplicative identity.
Given equation are:
-x +y = 8
4x + 3y = 12
x - 7y + z = 15
So,
[tex]\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right] \;*\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; = \; \left[\begin{array}{ccc}8\\12\\15\end{array}\right][/tex]
then,
[tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; = \; \left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]^{-1} \; \left[\begin{array}{ccc}8\\12\\15\end{array}\right][/tex]
Now, Calculating the inverse of Matrix we have,
[tex]\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]^{-1} \;[/tex] = [tex]\left[\begin{array}{ccc}-3/7&1/7&0\\4/7&1/7&0\\31/7&6/7&1\end{array}\right][/tex]
so, [tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; = \;\left[\begin{array}{ccc}-3/7&1/7&0\\4/7&1/7&0\\31/7&6/7&1\end{array}\right]\; \left[\begin{array}{ccc}8\\12\\15\end{array}\right][/tex]
[tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; =\left[\begin{array}{ccc}-12/7\\44/7\\425/7\end{array}\right][/tex]
[tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; =\left[\begin{array}{ccc}-1.76\\6.24\\60.76\end{array}\right][/tex]
Hence ,[tex]\; \left[\begin{array}{ccc}x\\y\\z\end{array}\right] \; =\left[\begin{array}{ccc}-1.76\\6.24\\60.76\end{array}\right][/tex]
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14. Find the area under the normal curve to the right of z = 1.84.
A. 0.9671
B. 0.0329
C. 0.2005
D. 0.7995
Answer:
B is the correct answer from my understanding
Step-by-step explanation:
Find the area of the following region. The region outside the circle r=3 and inside the circle r=-6cos theta
The region outside the circle r = 3 and inside the circle r = - 6cos θ is given below.
[tex]\rm Area = \dfrac{12\pi - 9\sqrt3 }{2}[/tex]
What is an area bounded by the curve?When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region outside the circle r = 3 and inside the circle r = - 6cos θ
Then the value of the θ will be
[tex]\begin{aligned} -6\cos \theta &= 3\\\\\cos \theta &= -\dfrac{1}{2}\\\\\theta &= -\dfrac{2\pi}{3}, \dfrac{2\pi}{3} \end{aligned}[/tex]
Then the area will be given as
[tex]\rm Area = \dfrac{1}{2} \int_{-\frac{2\pi}{3}}^{\frac{2\pi}{3}} [-6 \cos \theta)^2 - 3^2 ] d \theta \\\\\\Area = \dfrac{1}{2} \int_{-\frac{2\pi}{3}}^{\frac{2\pi}{3}} [18 (2\cos ^2 \theta ) - 9]d \theta \\\\\\Area = \dfrac{9}{2} \int_{-\frac{2\pi}{3}}^{\frac{2\pi}{3}} [2(1 + \cos 2\theta ) - 1] d \theta \\\\\\Area = \dfrac{9}{2} \int_{-\frac{2\pi}{3}}^{\frac{2\pi}{3}} [2 \cos 2\theta ) + 1] d \theta \\\\[/tex]
[tex]\rm Area = \dfrac{9}{2} [ \sin 2\theta + \theta ] _{-\frac{2\pi}{3}}^{\frac{2\pi}{3}} \\\\\\ Area = \dfrac{9}{2} [ \sin 2( \frac{2\pi}{3}) +\frac{2\pi}{3} - \sin 2 (\frac{2\pi}{3}) - \frac{2\pi}{3}] \\\\\\[/tex]
On simplifying, we have
[tex]\rm Area = \dfrac{12\pi - 9\sqrt3 }{2}[/tex]
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for each pair of functions, find f(g(x)) and g (f(x)).
1. f(x)= x^3 g(x)= 2x
2. f(x)= 3x+5 g(x)= 4x-2
3. f(x)= 2x+5 g(x)= x^2+2
I'd like an answer and explanation pleasee
Answer:
its 3
Step-by-step explanation:
id ont know the formula but im certain im a very smart 6th grader!
I need help for brainliest
Answer:
46 cm²Step-by-step explanation
the figure is composed of a square with an isosceles right triangle inside, we find the area of the square and we take away the area of the triangle.
Triangle area = lxl, right-angled triangle area side by side divided by two.
square area8 * 8 = 64cm²
Triangle area
6 * 6 : 2 = 18 cm²
Area of the shaded region
64 - 18 = 46 cm²
Please help me on this!
The positive integer for which g(x) first exceeds f(x) is 178 according to the number line.
What is the function of f(x)?The function f of (x) is used to denote a linear algebra that can be represented on the graph.
Given that:
f(x) = 2x + 15[tex]\mathbf{g(x) = 11(1.02)^x}[/tex]We are to determine a positive integer for which g(x) first exceeds f(x). Using the following option;
f(x) = 2(371) + 15 = 757g(x) = 11(1.02)³⁷¹ = 17063.04f(x) = 2(177) + 15 = 369g(x) = 11(1.02)¹⁷⁷ = 366.11f(x) = 2(370) + 15 = 755g(x) = 11(1.02)³⁷⁰ = 16728.47f(x) = 2(178) + 15 = 371g(x) = 11(1.02)¹⁷⁸ = 373Therefore, we can conclude that the positive integer for which g(x) first exceeds f(x) is 178 according to the number line.
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What is the length of the hypotenuse of the triangle when x=14
The length of the hypotenuse will be equal to H=122.25 when value of x=14.
What is pythagorean theorem?Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal the square of the sum of the other two sides.
It is given that:
Value of x=14
The perpendicular is =6x+5=6x14+5=89
The base is =6x=84
So by using the Pythagorean theorem:-
[tex]H^2=P^2+B^2\\\\\\H^2=89^2+84^2\\\\\\H=\sqrt{89^2+84^2}\\\\\[/tex]
Hence the value of hypotenuse will be H=122.25
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Find the area inside one leaf of the rose: r=6sin(6theta)
The area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
What is integration?It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
We have:
r=6sin(6θ)
First we have to find the limits:
r = 0
6sin(6θ) = 0
θ = nπ/6
n = 0 to n = 1
θ = 0 to θ = π/6
[tex]\rm Area = \int\limits^{\dfrac{\pi}{6}}_0 {6sin6\theta} \, d\theta[/tex]
After calculating the above definite integral, we will get:
Area = 3π/2
Thus, the area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
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Cscx=cscx+secx/1+tanx
Answer:
[tex]\csc \left(x\right)=\frac{\csc \left(x\right)+\sec \left(x\right)}{1+\tan \left(x\right)}[/tex]
[tex]=\frac{1}{\sin \left(x\right)}[/tex] (expressed with sine and cosine)
[tex]\frac{1}{\sin \left(x\right)}=\csc \left(x\right)[/tex]
[tex]=\csc \left(x\right)[/tex]
Therefore, the identity has been proven true.
i need to find the value of each variable in the following parallelograms
how many times greater is the vuale in 4 in 547 than 4 in 84
Answer:
10 times
Step-by-step explanation:
4 in 547 is equal to 40
4 in 84 is equal to 4
When you separate that number into smaller parts
Ex: 547 = 500 + 40 + 7
I need help on 11A, I got the answer as 5.046cm but the book says it's 8.37 cm
Answer:
[tex]\textsf{Area of a triangle}=\dfrac{1}{2} ab \sin C[/tex]
(where [tex]a[/tex] and [tex]b[/tex] are the sides, and [tex]C[/tex] is the included angle)
[tex]\textsf{Area of a sector}= \dfrac{\theta}{360} \pi r^2[/tex]
(where [tex]\theta[/tex] is the angle in degrees and [tex]r[/tex] is the radius)
Therefore, using the above formulas:
[tex]\begin{aligned}\textsf{Area of segment } \rm (A) & = \textsf{area of sector}- \textsf{area of triangle}\\& = \dfrac{\theta}{360} \pi r^2 - \dfrac{1}{2}r^2 \sin \theta\\\end{aligned}[/tex]
Given:
[tex]\theta[/tex] = 90°A = 20 cm²Substitute the given values into the formula and solve for r:
[tex]\begin{aligned}\implies 20 & = \dfrac{90}{360} \pi r^2 - \dfrac{1}{2}r^2 \sin 90\\\\20 & = \dfrac{1}{4} \pi r^2 - \dfrac{1}{2}r^2 (1)\\\\20 & = \left(\dfrac{1}{4} \pi -\dfrac{1}{2}\right)r^2\\\\20 & = \left(\dfrac{\pi -2}{4}\right)r^2\\\\r^2 & = 20\left(\dfrac{4}{\pi -2}\right)\\\\r^2 & =\dfrac{80}{\pi-2}\\\\r & =\sqrt{\dfrac{80}{\pi-2}}\\\\r & = 8.37\: \sf (2\:dp)\end{aligned}[/tex]
What is 3 3/4 x = 1 1/4
Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
1. Convert both mixed numbers into improper fractions:
[tex]\frac{15}{4} x = \frac{5}{4}[/tex]
2. Multiply both sides by 4:
4 · [tex]\frac{15}{4} x=\frac{5}{4}[/tex] · 4
15x = 5
3. Isolate x:
x = 1/3
hope this helps!
