Procter & Gamble reported that an American family of four washes an average of 1


ton (2000 pounds) of clothes each year. If the standard deviation of the distribution


is 187. 5 pounds, find the probability that the mean of a randomly selected sample of


50 families of four will be between 1980 and 1990 lbs.

To compute the integral JSS, udv, where U is the part of the ball of radius 3, centered at 0,0,0), that lies in the 1st octant, we can use spherical coordinates. Since the region is defined as having all three coordinates nonnegative, we can set our limits of integration as follows: 0 ≤ ρ ≤ 3, 0 ≤ θ ≤ π/2, and 0 ≤ φ ≤ π/2.

Using the Jacobian transformation, we have:

JSS, udv = ∫∫∫U ρ²sinφ dρdθdφ

Substituting in our limits of integration, we get:

JSS, udv = ∫0^π/2 ∫0^π/2 ∫0³ ρ²sinφ dρdθdφ

Evaluating the integral, we get:

JSS, udv = (3³/3) [(sin(π/2) - sin(0))] [(1/2) (π/2 - 0)]

JSS, udv = 9/2 π

Therefore, the value of the integral JSS, udv, over the part of the ball of radius 3 that lies in the 1st octant is 9/2π.
To compute the integral JSS, udv, over the region U, which is the part of the ball of radius 3 centered at (0,0,0) and lies in the first octant, we will use spherical coordinates for this computation as it's more preferable.

In spherical coordinates, the volume element is given by dv = ρ² * sin(φ) * dρ * dφ * dθ, where ρ is the radial distance, φ is the polar angle (between 0 and π/2 for the first octant), and θ is the azimuthal angle (between 0 and π/2 for the first octant).

Now, we need to set up the integral for the volume of the region U:
JSS, udv = ∫∫∫ (ρ² * sin(φ) * dρ * dφ * dθ), with limits of integration as follows:
ρ: 0 to 3 (radius of the ball),
φ: 0 to π/2 (for the first octant),
θ: 0 to π/2 (for the first octant).

So, the integral becomes:
JSS, udv = ∫(0 to π/2) ∫(0 to π/2) ∫(0 to 3) (ρ² * sin(φ) * dρ * dφ * dθ)

By evaluating this integral, we will obtain the volume of the region U in the first octant.

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If the donation to charity b is 5/6 of the donation to charity d, charity d's donation is twice the donation to charity c and the ratio of donations for charity c to charity a is 3:4 then the donation to charity b is £1250.

Let's denote the donation to charity a as x. Then the donation to charity c is (3/4)x, and the donation to charity d is 2(3/4)x = (3/2)x.

We know that the donation to charity b is 5/6 of the donation to charity d, so:

donation to charity b = (5/6)(3/2)x = (5/4)x

We also know that the total donation is £4500, so we can set up an equation:

x + (3/4)x + (3/2)x + (5/4)x = £4500

Multiplying through by 4 to get rid of the fractions, we have:

4x + 3x + 6x + 5x = £18,000

18x = £18,000

x = £1000

So the donation to charity b is: (5/4)x = (5/4)(£1000) = £1250

Therefore, the donation to charity b is £1250.

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Answer:

x = 150

Step-by-step explanation:

We know that the total amount of degrees in a circle is 360°.

We also know that a right angle is 90°.

Using this information, and the given 120° angle, we can form the following equation to solve for x:

90° + 120° + x° = 360°

210° + x° = 360°

x° = 360° - 210°

x° = 150°

x = 150

Step-by-step explanation:

120° + 90° + x = 360°

210° + x = 360°

x = 360° - 210°

= 150°

1. The coordinates are: START: (0,0) END: (6,-4), 2. The perimeter of rectangle YARD is 20 units,3. The lengths of YX and YZ are 4 units and 6 units, respectively, 4. The area of Mary's room is 24 square units,

1-To get from one corner of his yard to another, Jason travels 4 units down and then 6 units right. Starting from the origin, his starting point is (0,0). From there, he moves 4 units down to the point (0,-4), and then 6 units right to reach his endpoint, which is at (6,-4).

2-The rectangle has two sides of length 4 and two sides of length 6. The perimeter is the sum of the lengths of all sides, so it is equal to 2(4) + 2(6) = 8 + 12 = 20 units.

3-The coordinates of points Y, X, and Z are not given, so we cannot calculate the lengths directly. However, we know that the sides of a rectangle are perpendicular, so we can use the Pythagorean theorem to find the lengths. Let Y be the origin (0,0), and let X be the point (0, -4). Then YX has length 4 units. Similarly, let Z be the point (6, 0), so YZ has length 6 units.

4.To find the area of a rectangle, we can multiply the lengths of its sides. From problem 3, we know that the lengths of the sides are 4 and 6 units, so the area is 4 x 6 = 24 square units.

5. The sides AB and AC form a right angle.

To determine which sides of the triangle form a right angle, we need to find the slope of each side. The slope of AB is (3-8)/(6-3) = -5/3, and the slope of AC is (3-3)/(6-3) = 0. Since the product of the slopes of two perpendicular lines is -1, we can see that AB is perpendicular to AC. Therefore, sides AB and AC form a right angle.

6. Tyler walks 9 blocks in all.

To find the distance Tyler walks, we need to calculate the length of sides AB and AC. Using the distance formula, we can find that the length of AB is sqrt[(6-3)² + (3-8)²] =√[(34) units, and the length of AC is 3 units. Therefore, Tyler walks 3 + √[34 units along the two sides that form the right angle. This is approximately 9.4 blocks, so he walks 9 blocks in all.

7. The distance between two points in a coordinate plane can be found using the distance formula:

d = √[(x₂-x₁)² + (y₂-y₁)²]

where (x₁, y₁) and (x₂, y₂) are the coordinates of the two points, and d is the distance between them. The formula is derived from the Pythagorean theorem, which relates the sides of a right triangle.

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The volume of the frustum is 132.84 cubic units.

The lateral area of the frustum is 7π√17/4 square units.

To calculate the volume of the frustum, we can use the formula:

V = (1/3) × π × h × (r₁² + r₂² + (r₁ * r₂))

where:

V is the volume of the frustum,

h is the height of the frustum,

r₁ is the radius of the smaller base,

r₂ is the radius of the larger base, and

π is a mathematical constant approximately equal to 3.14159.

Plugging in the values given:

h = 2,

r₁ = 1, and

r₂ =[tex]2\frac{1}{2}[/tex] = 5/2,

V = (1/3)× π × 2 × (1² + (5/2)² + (1 × (5/2)))

V = (1/3) × π × 2 × (1 + 25/4 + 5/2)

V = 132.84

Therefore, the volume of the frustum is approximately 132.84 cubic units.

To calculate the lateral area of the frustum, we can use the formula:

A = π × (r₁ + r₂) × l

To find the slant height, we can use the Pythagorean theorem:

l = √(h² + (r₂ - r₁)²)

Plugging in the values given:

h = 2, r₁ = 1, and r₂ =5/2

l = √ 2² + ((5/2) - 1)²

l = √(4 + (5/2 - 2)²)

l = √(17/4)

l = √(17)/2

Now, plugging in the values into the lateral area formula:

A = π×(1 + 5/2)× √17/2

A = π × (7/2) × √(17)/2

A = 7π√17/4

Therefore, the lateral area of the frustum is 7π√17/4 square units.

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Yes

PEMDAS explains the order that operations are done.

PEMDAS

PEMDAS stands for Parentheses, Exponents, Multiplication and Division, Addition and Subtraction. This is the order of operations. Always start with operations inside parentheses, then exponents, then multiplication and division, and the last operations are addition and subtraction. In the problem above, parentheses come first, so means start with 18 x 8 and then do subtraction afterward.

Without Parentheses

Take the new expression, 252 - 18 x 8. Following the order of operations, multiplication goes first. This means multiply 18 x 8 first and then subtract. This order of operations is the same with or without parentheses. Since multiplication comes before subtraction, parentheses are not needed.

The coordinates of the other trees that must also be on the boundary are (-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

The coordinates of the other trees that must be on the boundary of the circular orchard, given that the tree at (5, 12) is on the boundary and the center of the orchard is at (0, 0) can be determined as follows.

1. Calculate the radius of the orchard using the distance formula:

sqrt((x2-x1)^2 + (y2-y1)^2).

In this case, (x1, y1) = (0, 0) and (x2, y2) = (5, 12).

2. Radius = sqrt((5-0)^2 + (12-0)^2) = sqrt(5^2 + 12^2) = sqrt(25 + 144) = sqrt(169) = 13.

Now, we know the radius of the orchard is 13. To find the other boundary points, we can use the property of circles that states that the points on the boundary are equidistant from the center.

Since the coordinates are integers and symmetric, we can list the other points as follows:

3. The coordinates of the other trees on the boundary are:

(-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

These points are also 13 units away from the center, making them equidistant from the center and thus on the boundary of the circular orchard.

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For two parametric equations, x = cos(t)− sin(t) ; y = cos(t) + sin(t) ; 0≤t≤2π

a) Cartesian equation for the parametric curve is represented by x² + y² = 2.

b) The sketch for this parametric curve, with arrows in the direction of curve tracing is present above figure.

A parametric curve in the x-t plane has the equations x=x(t), y=y(t). The curve associates a point of the plane (x,y) to a value of the parameter t. The rectangular form of the curve can be determined by eliminating the parameter t, i.e. determine the parameter in one equation and Substituting this value in the other equation. We have the following parametric equations,

x = cos⁡t - sin⁡ty = cos⁡(t)+ sin⁡t, 0 ≤ t ≤ 2π

(a) we have to eliminate parameter t to determine a cartesian equation for the parametric curve, use x²+ y² = (cos⁡(t) − sin⁡(t))²+ (cos⁡(t) + sin⁡(t))²

=> x² +y² = cos²t + sin²t - 2cos⁡t sin⁡t + cos²t + sin²t + 2cos⁡t sin⁡t

=> x² + y² = 2 ( sin²t + cos²t) = 2

which represents a circle curve centered at the origin and having radius √2.

(b) A sketch of this parametric curve is shown above figure and arrows are used to indicate the direction of curve trace.

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The equation of the line passing through the points (0, 1) and (2, -3) is y = -2x + 1.

The formula for equation of line is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

First, we determine the slope of the line.

Given the two points are (0, 1) and (2, -3).

We can find the slope of the line by using the slope formula:

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values, we get:

m = (-3 - 1) / (2 - 0)

m = -4 / 2

m = -2

Using the point-slope form, plug in one of the given points and slope m = -2 to find the equation of the line.

Let's use the point (0, 1):

y - y₁ = m(x - x₁)

y - 1 = -2(x - 0)

y - 1 = -2x

y = -2x + 1

Therefore, the equation of the line is y = -2x + 1.

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Triangle DBG is isosceles and  BD = BG.

A triangle is a closed two-dimensional geometric shape with three straight sides and three angles. It is one of the basic shapes in geometry and has a wide range of applications in mathematics, science, and engineering.

To prove that triangle DBG is isosceles, we need to show that BD = BG.

First, we can use the given similarity to find the length of DF in terms of EB and EC. Since triangle ABC is similar to triangle EDF, we have:

AB:BC = ED:DF

Substituting the given values, we get:

2:3 = ED:DF

Multiplying both sides by DF, we get:

DF = (3÷2)ED

Next, we can use the fact that triangles EDF and EBG are similar (since they share angle E) to find the length of BG in terms of EB and DF:

ED/EB = BG/DF

Substituting the value we found for DF, we get:

ED/EB = BG/(3/2)ED

Multiplying both sides by (3/2)ED, we get:

BG = (3/2)ED²/ EB

Now we can use the Pythagorean theorem to find the lengths of BD and BG in terms of EB and EC:

BD² = BE² + ED²

BG² = BE² + EG²

Since EG = EC - BD, we can substitute BD = EC - EG in the first equation to get:

BD² = BE² + ED² = BE² + (3/2)ED²

Substituting the expression we found for BG in terms of ED and EB in the second equation, we get:

BG² = BE² + (3/2)ED²/EB² * BE²

Simplifying this expression, we get:

BG² = BE²(1 + 3ED²/2EB²)

Since we know that ED/EB = 2/3, we can substitute this value to get:

BG² = BE²(1 + (3/2)(4/9)) = BE²(25/18)

Therefore, we have:

BD² = BE² + (3/2)ED² = BE² + (3/2)(9/4)BE² = (15/8)BE²

BG² = BE²(25/18)

To show that BD = BG, we can compare the squares of these lengths:

BD² = (15/8)BE²

BG² = BE²(25/18)

Multiplying both sides of the first equation by 18/25, we get:

(18/25)BD² = (27/40)BE²

Substituting the expression for BG² in the second equation, we get:

(18/25)BD² = (27/40)BG²

Therefore, we have:

BD² = (27/40)BG²

Taking the square root of both sides, we get:

BD = (3/4)√(10) * BG

Substituting the expression we found for BG in terms of ED and EB, we get:

BD = (3/4)√(10) * (3/2)ED²/EB

Substituting the value of ED/EB = 2/3, we get:

BD = (3/4)√(10) * (3/2)(4/9)ED²

Simplifying this expression, we get:

BD = (2/3)√(10)ED²

Next, we can substitute the value we found for DF in terms of ED to get:

DF = (3/2)

Therefore, triangle DBG is isosceles and  BD = BG.

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The value of x that maximizes the concentration is 119 weeks, and the maximum concentration is approximately 7.19 ml.

Based on the provided equation, the concentration C(x) is a quadratic function of x with a negative coefficient for the quadratic term, which means that it has a maximum point.

(a) To find the value of x that maximizes the concentration, we can take the derivative of the concentration function with respect to x, set it equal to zero, and solve for x. The derivative of C(x) is:

C'(x) = 56x + 7

Setting C'(x) equal to zero, we get:

56x + 7 = 0

Solving for x, we get:

x = -7/56 = -0.125

However, x represents the number of weeks from now, which cannot be negative. Therefore, the maximum concentration occurs at the endpoint of the interval we are considering, which is x = 119 weeks.

To find the maximum concentration, we can substitute x = 119 into the concentration function:

C(119) = 28²(2119)+7 - 119²-2119+2 ≈ 7.19 ml

So, the value of x that maximizes the concentration is 119 weeks, and the maximum concentration is approximately 7.19 ml.

(b) For very large values of x, the quadratic term (-x²) dominates the concentration function, and the concentration appears to decrease without bound.

This is because the negative quadratic term becomes much larger than the linear term (2x) and the constant term (2), causing the concentration to become more and more negative as x increases.

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The recursive sequence representing how many papers Khloe has remaining to grade after working for n hours is given by a_n = a_{n-1} - 10, where a_0 = 90.

Let a_n denote the number of papers Khloe has remaining to grade after n hours of work. After the first hour of work, she will have 90 - 10 = 80 papers remaining. Therefore, we have a_1 = 90 - 10 = 80.

After the second hour of work, she will have a_2 = a_1 - 10 = 80 - 10 = 70 papers remaining. Similarly, after the third hour of work, she will have a_3 = a_2 - 10 = 70 - 10 = 60 papers remaining.

In general, after n hours of work, Khloe will have a_n = a_{n-1} - 10 papers remaining to grade. This is a recursive sequence, where the value of a_n depends on the value of a_{n-1}. The initial value of a_0 is given as 90, since she starts with 90 papers to grade. Therefore, the recursive sequence is given by a_n = a_{n-1} - 10, where a_0 = 90.

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To find the probability of Sarah cleaning her room or doing her homework, we can use the addition rule for probabilities. However, we need to be careful not to count the probability of Sarah cleaning her room and doing her homework twice. Therefore, we need to subtract the probability of Sarah cleaning her room and doing her homework from the sum of the probabilities of Sarah cleaning her room and doing her homework separately.

Let C be the event that Sarah cleans her room, and let H be the event that Sarah does her homework. Then we know:

P(C) = 0.40 (the probability that Sarah cleans her room)

P(H) = 0.70 (the probability that Sarah does her homework)

P(C and H) = 0.24 (the probability that Sarah cleans her room and does her homework)

Using the addition rule, we can find the probability of Sarah cleaning her room or doing her homework as follows:

P(C or H) = P(C) + P(H) - P(C and H)

          = 0.40 + 0.70 - 0.24

          = 0.86

Therefore, the probability of Sarah cleaning her room or doing her homework is 0.86, or 86%.

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The function that could be described is f(x) = 10cos(2πx/3), where the amplitude is 10, the period is 3, and the maximum value is 20.

In a cosine function, the amplitude represents the vertical distance from the midline to the maximum or minimum value. Here, the maximum value is 20, which means the amplitude is half of that, i.e., 10. The period of the function is the distance it takes for one complete cycle, and in this case, it is 3 units.

By using the formula f(x) = A*cos(2πx/P), where A is the amplitude and P is the period, we can determine that the given function matches the described characteristics.

The function f(x) = 10cos(2πx/3) has a maximum value of 20 and a minimum value of 0, and it completes one cycle over the interval of the period, which is 3 units.

In conclusion, the function f(x) = 10cos(2πx/3) satisfies all the given conditions and represents the described function.

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The Intermediate Value Theorem states that if a function f(x) is continuous on a closed interval [a,b], and if M is any number between f(a) and f(b), then there exists at least one number c in the interval [a,b] such that f(c) = M.

In this case, we are given a continuous function g(x) with g(0) = 3, g(1) = 8, and g(2) = 4. Let s(x) be the inverse of g(x), which means that s(g(x)) = x for all x in the domain of g(x).

Suppose s(x) is invertible. Then for any y in the range of g(x), there exists a unique x such that g(x) = y, and therefore s(y) = x. In particular, let y = 5, which is between g(1) = 8 and g(2) = 4. By the Intermediate Value Theorem, there exists a number c in the interval [1,2] such that g(c) = 5.

However, this means that s(5) is not well-defined, since there are two values of x (namely c and s(5)) that satisfy g(x) = 5. Therefore, s(x) is not invertible.

The Intermediate Value Theorem states that if a function is continuous on a closed interval [a, b], and k is any number between f(a) and f(b), then there exists a number c in the interval [a, b] such that f(c) = k.

Let g(x) be continuous with g(0) = 3, g(1) = 8, and g(2) = 4. Since g(x) is continuous, the Intermediate Value Theorem applies. However, to show that s(x) is not invertible, we need to show that g(x) is not one-to-one.

Notice that g(0) = 3 and g(2) = 4, with g(1) = 8 in between. This means that there must exist a point c1 in the interval (0, 1) such that g(c1) = 4, and another point c2 in the interval (1, 2) such that g(c2) = 3, due to the Intermediate Value Theorem.

Since g(c1) = g(c2) = 4 and c1 ≠ c2, g(x) is not one-to-one. Therefore, its inverse function s(x) does not exist, and s(x) is not invertible.

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The average price of milk in 2018 was 6.45 dollars per gallon.

The average price of milk in 2021 was 189.95 dollars per gallon.

The given function is: Price = 3.55 + 2.90(1 + x)³

In order to find the average price of milk in 2018, we need to set x = 0:

Price in 2018 = 3.55 + 2.90(1 + 0)³ = 3.55 + 2.90(1) = 6.45 dollars per gallon

Price in 2021 = 3.55 + 2.90(1 + 3)³ = 3.55 + 2.90(64) = 189.95 dollars per gallon

Hence, the average price of milk in 2021 was 189.95 dollars per gallon.

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We would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes. The probability of a chocolate cupcake being sold is approximately 14%.

The question asks to determine how many of the next 21 cupcakes sold would be expected to be pumpkin cupcakes, and also to find the probability of a chocolate cupcake being sold.

First, let's analyze the given data:
- Chocolate cupcakes: 2
- Pistachio cupcakes: 1
- Banana cupcakes: 5
- Pumpkin cupcakes: 6

Total cupcakes sold: 2 + 1 + 5 + 6 = 14

To find the expected number of pumpkin cupcakes in the next 21 sold, calculate the proportion of pumpkin cupcakes in the original data, and then multiply by 21:

(6 pumpkin cupcakes / 14 total cupcakes) * 21 = 9 (rounded)

So, we would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes (Answer A).

For Part B, we need to find the probability of a chocolate cupcake being sold. To do this, divide the number of chocolate cupcakes by the total number of cupcakes:

Probability (chocolate cupcakes) = (2 chocolate cupcakes / 14 total cupcakes) = 0.142857

Now, convert this probability to a percentage and round to the nearest whole number:

0.142857 * 100 = 14.29% ≈ 14%

So, the probability of a chocolate cupcake being sold is approximately 14%.

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There are 225 possible outcomes in the sample space if the spinner is spun twice

From the question, we have the following parameters that can be used in our computation:

Spinner

The number of sections in the spinner is

n = 15

If the spinner shown is spun twice, then we have

Outcomes = n²

Substitute the known values in the above equation, so, we have the following representation

Outcomes = 15²

Evaluate

Outcomes = 225

Hence, the possible outcomes are in the sample space are 225

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The equation of the circle graphed below is (x - 1)² + (y - 1)² = 4.

To determine the equation of a circle, we need to know the coordinates of its center and the radius. The general equation of a circle with center (h, k) and radius r is given by:

(x - h)² + (y - k)² = r²

where (x,y) are the coordinates of any point on the circle. The equation shows that the distance between any point (x,y) on the circle and the center (h,k) is always equal to the radius r.

To determine the equation of the circle graphed below, we need to identify the coordinates of its center and the radius. One way to do this is to use the distance formula between two points. We can choose any two points on the circle and use their coordinates to find the distance between them, which is equal to the diameter of the circle. Then, we can divide the diameter by 2 to find the radius.

To find the radius, we can choose any point on the circle and use the distance formula to find the distance between that point and the center. We can use the point (5,1), which is on the right side of the circle. The distance between (5,1) and (1,1) is 4 units, which means that the radius is 2 units.

Substituting the values of (h,k) and r in the general equation of the circle, we get:

(x - 1)² + (y - 1)² = 4

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The amount of time Carl represent is 25-m on the problems.

The statement "Davis spent 25 minutes working on math problems. Carl worked on math problems for m fewer minutes" means that Carl spent some amount of time working on math problems, but that amount is m minutes less than what Davis spent.

To represent the amount of time Carl worked on math problems, we can use the variable X. We know that X is equal to the amount of time Carl worked on math problems, and that X is equal to 25 minus m.

This is because Davis spent 25 minutes on math problems, and Carl worked on them for m fewer minutes. So if we subtract m from 25, we get the amount of time Carl worked on math problems.

Therefore, the equation X = 25 - m represents the amount of time Carl worked on math problems, where X is the amount of time in minutes and m is the number of minutes Carl worked less than Davis.

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Answer: To determine the percent of birds in Forest A that are robins, we need to know the number of robins and the total number of birds in Forest A. Let's assume that we have conducted a bird survey and found the following information:

Number of robins in Forest A = 50

Number of other birds in Forest A = 150

Total number of birds in Forest A = 50 + 150 = 200

To calculate the percentage of birds in Forest A that are robins, we can use the following formula:

Percentage = (Number of robins / Total number of birds) x 100%

Plugging in the values, we get:

Percentage = (50 / 200) x 100% = 25%

Therefore, 25% of the birds in Forest A are robins.

Step-by-step explanation:

the length of PM is 98.

What is congruent of the triangle?

The shapes maintain their equality regardless of how they are turned, flipped, or rotated before being cut out and stacked. We'll see that they'll be placed entirely on top of one another and will superimpose one another. Due to their identical radius and ability to be positioned directly on top of one another, the following circles are considered to be congruent.

OM/MN = OP2/P2M

[tex]OM/(r_1 - r_2) = (r_2 + y - 12)/yOM = (r_1 - r_2)*(r_2 + y - 12)/y[/tex]

Similarly, since LQ is tangent to both circles at L and Q respectively, we have OL1 and OQ2 perpendicular to LQ. Therefore, triangle LOM and triangle QOM are similar triangles. Using this similarity, we can find the length of OM in terms of r1 and r2:

OM/ML = OQ2/Q2M

[tex]OM/(r_1 + r_2 - 31) = (r_2 + 62 - 4)/yOM = (r_1 + r_2 - 31)*(r_2 + 62 - 4)/y[/tex]

Since both expressions above represent the same length of OM, we can equate them:

[tex](r_1 - r_2)(r_2 + y - 12)/y = (r_1 + r_2 - 31)(r_2 + 62 - 4)/y[/tex]

Simplifying and solving for y, we get:

y = 22

Therefore, PM = 5y - 12 = 98.

Hence, the length of PM is 98.

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Mariah cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

A triathlon is  described as an endurance multisport race consisting of swimming, cycling, and running over various distances.

The coordinates are given as follows:

Suppose that we have two points,  and . The distance between them is given by:

distance = √(x2 - x1)² + (y2-y1)²

We substitute in the equation

Hence the distance between her house and the library is:

D = 8.6 miles.

She cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

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The workers would have traveled a total of 32 km while erecting the fence over 40 days.

To determine the total distance the workers traveled while erecting the fence, we can use the following terms: daily distance, number of days, and total distance.

Step 1: Determine the daily distance traveled.
The workers erect 0.8 km of new fence each day.

Step 2: Determine the number of days it takes to erect the fence.
It takes 40 days to erect the fence.

Step 3: Calculate the total distance traveled.
To find the total distance, multiply the daily distance (0.8 km) by the number of days (40).

Total distance = Daily distance × Number of days
Total distance = 0.8 km × 40

Total distance = 32 km

So, the workers would have traveled a total of 32 km while erecting the fence over 40 days.

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Answer:

I believe the distance between these points is (2, 7), because the difference between -5 and -7 is 2, and the for -9 and -2, it's 7.  Hope I helped.

The number of zeros are in the product of the number 50 and 6000 is 50 x 6000 = 300,000 are five.

Integers, natural numbers, fractions, real numbers, complex numbers, and quaternions are examples of typical special instances where it is possible to define the product of two numbers or the multiplication of two numbers.

A product is the outcome of multiplication in mathematics, or an expression that specifies the elements (numbers or variables) to be multiplied.

The commutative law of multiplication states that the result is independent of the order in which real or complex numbers are multiplied. The result of a multiplication of matrices or the elements of other associative algebras typically depends on the order of the components. For instance, matrix multiplication and multiplication in general in other algebras are non-commutative operations.

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Using the chain rule, we have: f'(x) = 2ln(x^4 + 5) * 2(x^4 + 5)^1 * 4x^3
f'(x) = 16x^3 * ln(x^4 + 5) * (x^4 + 5)

To find f'(-2), we plug in -2 for x:

f'(-2) = 16(-2)^3 * ln((-2)^4 + 5) * ((-2)^4 + 5)
f'(-2) = -128 * ln(21) * 21
f'(-2) ≈ -599.92 (rounded to 2 decimal places)

Therefore, f'(-2) is approximately -599.92.
To find f'(-2) for the function f(x) = ln((x^4 + 5)^2), we will first find the derivative of the function, and then evaluate it at x = -2.

1. Differentiate the function using the chain rule:
f'(x) = (d/dx) ln((x^4 + 5)^2) = (1/((x^4 + 5)^2)) * (d/dx) ((x^4 + 5)^2)

2. Differentiate the inner function:
(d/dx) ((x^4 + 5)^2) = 2(x^4 + 5) * (d/dx) (x^4 + 5) = 2(x^4 + 5) * (4x^3)

3. Combine the derivatives:
f'(x) = (1/((x^4 + 5)^2)) * (2(x^4 + 5) * (4x^3)) = (8x^3(x^4 + 5))/((x^4 + 5)^2)

4. Evaluate the derivative at x = -2:
f'(-2) = (8(-2)^3((-2)^4 + 5))/((-2)^4 + 5)^2 = (-128(21))/(21^2) = -128/21

So, f'(-2) is -128/21 as an exact fraction.

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