PLS HELP ME WITH THIS ILL GIVE BRAINLIEST

Explanation:

CaCl2 ⇄ Ca-²+2Cl-¹

1mole⇄1mole+2moles

So from above ..

1mole CaCl2 produce 1mole Ca-² & 2 moles of Cl-².

For 2.5 moles we multiply the above chemical eq. With 2.5

2.5CaCl2⇄2.5Ca-²+5Cl-¹

So from 2.5 moles of CaCl2 we get 2.5 mole calcium ion and 5 moles chloride ion…

Answer:

the theory of evolution states that all living things which exist today, and many more that are now extinct, evolved from simple life forms which first developed 3 billion years ago.

Explanation:

A. The properties of matter and how matter changes.

Answer: A. the properties of matter and how matter changes

Explanation:

just got it right

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Explanation:

Hope it is helpful.....

Answer: yes

Explanation:

Answer:

Living in close association

Explanation:

Explanation:

The relationship between H+ and OH-  at 25 °C is given as;

[H+}  x  [OH-]  = 1.0 x 10-14 M

a. 1.0 x 10-5 M OH-

[OH-] = 1.0 x 10-5 M

[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M  / 1.0 x 10-5 M

[H+] = 1.0 x 10^(-14+5)

[H+] = 1.0 x 10^(-9)

pH = - log [H+]

pH = - log [10^(-9)]

pH = 9

This is a basic solution

b. 1.0 x 10-7 M OH-

[OH-] = 1.0 x 10-7 M

[H+] = 1.0 x 10-14 M / [OH-] = 1.0 x 10-14 M  / 1.0 x 10-7 M

[H+] = 1.0 x 10^(-14+7)

[H+] = 1.0 x 10^(-7)

This is a neutral solution since [H+] and [OH-] are equal

c. 10.0 M H+

[H+] = 1.0 x 10 M

[OH-] = 1.0 x 10-14 M / [H+] = 1.0 x 10-14 M  / 1.0 x 10 M

[OH-] = 1.0 x 10^(-14-1)

[OH-] = 1.0 x 10^(-15)

pH = - log [H+]

pH = - log [10^(1)]

pH = -1

This is an acidic solution since it has a pH of -1

Answer:

5 × 10⁻³ mol

Explanation:

Step 1: Given data

Step 2: Convert "V" to dm³

We will use the conversion factor 1 dm³ = 1000 cm³.

25 cm³ × 1 dm³/1000 cm³ = 0.025 dm³

Step 3: Calculate the moles of HCl (n)

We will use the definition of molarity.

C = n/V

n = C × V

n = 0.2 mol/dm³ × 0.025 dm³ = 5 × 10⁻³ mol

Answer:

It bonds with the added H+ or OH in solution.

Explanation:

Answer:

the answer is 29.8814

Explanation:

because this is the answer to your question

Answer:

gay

Explanation:

very gay

Answer:

Due to displacement of water.

Explanation:

If the water is displaced in the cylinder it means that the gas is produced in the reaction while on the other hand, if the water is not displaced in the cylinder so it means that the reaction does not produces any gas yet. So we can say that the displacement of waters indicates or shows us whether the gas is produced in the reaction or not.

Answer:

1) Helium

2) Oxygen

3)Carbon

4) Chlorine

5) Magnesium

Explanation:

Helium has the electron arrangement 2, 2. There are two electrons in the first shell and two electrons in the second shell.

Oxygen is the first member of group 16, there are two energy levels in oxygen which are 2,6.

Carbon is in period 2 and is the first member of group 14 (the silicon family).

Chlorine has 7 valence electrons, the electrons are arranged as 2, 8, 7.

Magnesium has 12 protons and 12 electrons. It is the second member of period 3.

Explanation:

1 mole = 6.02 x 10^23 atoms (Avogadro’s number)

Step 1) Determine how many grams of a substance are in the problem

Step 2) Find the amount of grams in 1 mole of the substance

3) Multiply step one by step two

Answer:

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

Explanation:

Mole percent is the percentage of the total moles that is of a particular component.

We have to covert the ethanol and water to moles. This is given by the equation;

Number of moles =  Mass / Molar mass

Ethanol;

Number of moles = 71 / 46.07  = 1.5411 mol

Water;

Number of moles = 18.6 / 18  = 1.033 mol

Total mol = 1.5411 mol + 1.033 mol =  2.5741 mol

Mole percent of Ethanol = Number of moles /(Ethanol) / Total moles   * 100

Mole percent of Ethanol =  1.5411 mol / 2.5741 mol   * 100

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

Answer: The vapor pressure of a solution in which the mole fraction of the solute is 0.200 is 80.0 torr

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

[tex]\frac{p^o-p_s}{p^o}=i\times x_2[/tex]

where,

[tex]p^0[/tex]= vapor pressure of pure solvent = 100.0 torr

[tex]p_s[/tex] = vapor pressure of solution = ?

i = Van'T Hoff factor = 1 for nonvolatile, nonelectrolyte solute

[tex]x_2[/tex] = mole fraction of solute  = 0.200  

[tex]\frac{100.0-p_s}{100.0}=1\times 0.200[/tex]

[tex]p_s=80.0torr[/tex]

The vapor pressure of a solution in which the mole fraction of the solute is 0.200 is 80.0 torr

Answer:

The answer to this is solids!

Answer:

1.6666666666666 is the ans bcz in each mole there r 12 grams of carbon so the ans is goingtobe 20÷12

According to the mole concept, there are 1.66 moles in 20 grams of carbon.

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Number of moles is calculated as, mass/molar mass, thus on substitution , number of moles=20/12=1.66 moles.

Thus, there are 1.66 moles in 20  grams of carbon.

Learn more about moles,here:

https://brainly.com/question/26416088

#SPJ6

Answer:

removal of H2O

✔ System will shift toward the products.

addition of O2      

✔ System will shift toward the products.

decrease in pressure

✔ System will shift toward the reactants.

increase in temperature      

✔ System will shift toward the reactants.

Explanation:

The reaction Equation :

2H₂ (g)  + O₂ (g) ↔ 2H₂O (g) + heat

Answer :

a) Removal of H₂O : The system will move towards the products of the reaction

b) addition of O₂ : The system will move towards the products of the reaction

c) decrease in pressure : The system will tend to move towards the reactants

d) Increase in temperature: The system will tend to move towards the reactants as well

Reason

In an equilibrium reaction changes to reactant components surroundings/conditions in which the reaction is been carried out can cause a significant change in the entire reaction process.

Hence; Removal of H₂O will cause the reaction system to move towards the products also the addition of O₂ will make the equation of the  reaction system move towards the product

Decrease in pressure and Increase in temperature causes the equation to move towards the reactants of the reaction

Learn more about equilibrium reaction : https://brainly.com/question/16878977

Answer:

High temperatures

Explanation:

NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)

As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).

As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).

In terms of ΔG:

In order for the reaction to be thermodynamically favorable, ΔH has to be negative, thus:

The greater the temperature, the easier it would be for TΔS to be greater than ΔH.

Answer:

Explanation:

From the given information:

A → B k₁

B → A k₂

B + C → D k₃

The rate law = [tex]\dfrac{d[D]}{dt}=k_3[B][C] --- (1)[/tex]

[tex]\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C][/tex]

Using steady-state approximation;

[tex]\dfrac{d[B]}{dt}=0[/tex]

[tex]k_1[A]-k_2[B]-k_3[B][C] = 0[/tex]

[tex][B] = \dfrac{k_1[A]}{k_2+k_3[C]}[/tex]

From equation (1), we have:

[tex]\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}[/tex]

when the pressure is high;

k₂ << k₃[C]

[tex]\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \ \text{first order}[/tex]

k₂ >> k₃[C]

[tex]\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_2}= \dfrac{k_1k_3}{k_2}[A][C] \ \ \text{second order}[/tex]

Answer:

The common sources of outdoor air pollution are emissions caused by combustion processes from motor vehicles, solid fuel burning and industry. Other pollution sources include smoke from bushfires, windblown dust, and biogenic emissions from vegetation (pollen and mold spores).

smog is produced when sunlight reacts with nitrogen oxides in the atmosphere. Nitrogen oxides come from car exhaust, coal power plants, and factory emissions. When sunlight hits these chemicals, they form airborne particles and ground-level ozone—or smog.

Answer:   m =  4.2 gAgCl

Explanation:  

Answer:

3.40 g

Explanation: don't have one :P