Pls help answer this question. Shape P is translated to shape q using vector a b. write down the values of a and b.​

The probability of z being greater than 1.62 using the standard normal distribution is 5.26%.

The standard normal distribution is a type of probability distribution with a mean of 0 and a standard deviation of 1.

It is often denoted by the letter Z.

To find the probability P(z > 1.62) using the standard normal distribution, you can use a standard normal distribution table or a calculator that has this functionality.

Here are the steps to calculate the probability using a standard normal distribution table:1.

Look up the z-score of 1.62 in the table.

This value is located in the row labeled 1.6 and the column labeled 0.02.

The value in the corresponding cell is 0.9474.2. Subtract this value from 1 to find the probability of z being greater than 1.62. 1 - 0.9474 = 0.0526

Therefore, the probability of z being greater than 1.62 using the standard normal distribution is 0.0526 or approximately 5.26%.

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Based on the classical method, we fail to reject the null hypothesis, indicating that the average velocity of the following month is not significantly greater than 8 m/s. However, using the p-value method, we reject the null hypothesis, suggesting that the average velocity of the following month is significantly greater than 8 m/s.

The classical method involves calculating the test statistic and comparing it to the critical value, while the p-value method involves comparing the p-value to the significance level.

To determine whether the average velocity of the following month would be greater than 8 m/s, we will perform a hypothesis test.

The null hypothesis ([tex]H_0[/tex]) is that the average velocity is not greater than 8 m/s, and the alternative hypothesis ([tex]H_a[/tex]) is that the average velocity is greater than 8 m/s.

Using the classical method, we can calculate the test statistic, which is the z-score.

The formula for the z-score is given by ([tex]\bar{x}[/tex] - μ) / (σ / √n), where [tex]\bar{x}[/tex] is the sample mean, μ is the population mean (8 m/s in this case), σ is the population standard deviation (1.64 m/s), and n is the sample size (50).

Plugging in the values, we have z = (7.514 - 8) / (1.64 / √50) ≈ -2.168.

Next, we compare the test statistic to the critical value. Since we are testing for the average velocity being greater than 8 m/s, we are performing a one-tailed test.

At a significance level of 0.05, the critical value is approximately 1.645. Since the test statistic (-2.168) is less than the critical value (-1.645), we fail to reject the null hypothesis.

Using the p-value method, we calculate the p-value associated with the test statistic.

The p-value represents the probability of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true. In this case, the p-value is approximately 0.015.

Comparing the p-value to the significance level of 0.05, we see that the p-value is less than the significance level. Therefore, we reject the null hypothesis.

In conclusion, based on the classical method, we fail to reject the null hypothesis, indicating that the average velocity of the following month is not significantly greater than 8 m/s.

However, using the p-value method, we reject the null hypothesis, suggesting that the average velocity of the following month is significantly greater than 8 m/s.

This discrepancy highlights the importance of the chosen statistical method and interpretation, which can lead to different conclusions.

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To simplify the expression (3+2i)/(2-5i), we need to multiply the numerator and denominator by the conjugate of the denominator. After simplifying, we can express the result in the form a + bi, where a and b are real numbers.

To simplify (3+2i)/(2-5i), we start by multiplying the numerator and denominator by the conjugate of the denominator. The conjugate of 2-5i is 2+5i.

(3+2i)/(2-5i) * (2+5i)/(2+5i)

Multiplying the numerators and denominators together, we get:

(6 + 15i + 4i + 10i^2)/(4 + 10i - 10i - 25i^2)

Simplifying further:

(6 + 19i - 10)/(4 + 25)

( -4 + 19i)/(29)

So, the simplified form of (3+2i)/(2-5i) is (-4 + 19i)/29.

The expression is now in the form a + bi, where a = -4 and b = 19/29.

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To calculate the z-test statistic, we need to use the standard deviation of the sampling distribution of the sample mean.

The standard deviation of the sampling distribution of the sample mean (also known as the standard error) can be calculated by dividing the population standard deviation by the square root of the sample size.

Given that the population standard deviation is 3.7 mm and the sample size is 20, we can calculate the standard deviation of the sampling distribution as follows:

Standard deviation = 3.7 / sqrt(20) ≈ 0.827

Rounding to two decimal places, the standard deviation used in this calculation is 0.83.

Therefore, the standard deviation value is 0.83.

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The given demand equation is x = √3125 - p², where p is the price in dollars. To find dp/dx, differentiate both sides of the given equation with respect to p. We get,dx/dp = -2p / (2 √3125 - 2p²)dx/dp = -p / (√3125 - p²)Solve for dp/dx,dp/dx = (dx/dp)^-1dp/dx = - (√3125 - p²)/pWhen p = 50,dp/dx = - (√3125 - 50²)/50dp/dx = - 5√5/2The given dp/dx is negative, which means as the price increases, the quantity demanded decreases.

The value of dp/dx is 5√5/2. The correct interpretation of this value is that as the price increases by $1, the quantity demanded decreases by 5√5/2. Therefore, option (a) Prices decrease by the absolute value of dp/dx for each increase of 1 in quantity is the correct answer.

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a. The distribution of X is a discrete uniform distribution.

b. The distribution of x for the selection of 37 numbers is still a discrete uniform distribution.

c. The probability that the average of 37 numbers will be more than 6.1 is approximately 0.0452 or 4.52%.

a. The distribution of X is a discrete uniform distribution because the computer selects a number uniformly at random from a range of values (2 to 9) with equal probability for each number.

b. If the computer randomly picks 37 numbers from the range of 2 to 9, the distribution of x for this selection of numbers will still be a discrete uniform distribution. The probability of selecting any particular number from the range is still equal, and each number has the same chance of being selected.

c. To calculate the probability that the average of 37 numbers will be more than 6.1, we can use the Central Limit Theorem, which states that for a large enough sample size, the distribution of sample means will be approximately normally distributed regardless of the shape of the original distribution.

Given that the distribution of X is a discrete uniform distribution, the mean of the distribution is (2 + 9) / 2 = 5.5, and the standard deviation is (9 - 2 + 1) / sqrt(12) = 2.160246899.

To calculate the probability, we need to convert the average of 6.1 to a z-score using the formula:

z = (x - μ) / (σ / sqrt(n))

Where:

x = 6.1 (average)

μ = 5.5 (mean)

σ = 2.160246899 (standard deviation)

n = 37 (sample size)

Substituting the values into the formula:

z = (6.1 - 5.5) / (2.160246899 / sqrt(37))

z = 0.6 / (2.160246899 / 6.08276253)

z = 0.6 / 0.355117496

z ≈ 1.6886

Now, we can find the probability using a standard normal distribution table or a statistical software. Using Excel, we can use the NORM.S.DIST function to find the probability.

The probability that the average of 37 numbers will be more than 6.1 is given by:

1 - NORM.S.DIST(1.6886, TRUE)

≈ 1 - 0.954798595

≈ 0.0452

Therefore, the probability that the average of 37 numbers will be more than 6.1 is approximately 0.0452, or 4.52%.

The correct question should be :

A computer selects a number X from 2 to 9 randomly and uniformly. Round all answers to 4 decimal places where possible.

a. What is the distribution of X?

b. Suppose that the computer randomly picks 37 such numbers. What is the distribution of x

for this selection of numbers?

c. What is the probability that the average of 37 numbers will be more than 6.1?

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Solving a three by three system of linear equations using augmented matrix and elementary row operations.


(a) The augmented matrix represents the system of linear equations. For the given system:

x - y + z = 2 --> [1 -1 1 | 2]
x + y + 3z = 5 --> [1 1 3 | 5]
2y + 3z = 5 --> [0 2 3 | 5]

The augmented matrix is formed by arranging the coefficients of the variables and the constants in a matrix.

(b) To solve the system using elementary row operations, we perform operations to transform the augmented matrix into row-echelon form or reduced row-echelon form. We'll illustrate the steps:

Row 2 = Row 2 - Row 1: [1 -1 1 | 2]
[0 2 2 | 3]
[0 2 3 | 5]

Row 3 = Row 3 - 2 * Row 2: [1 -1 1 | 2]
[0 2 2 | 3]
[0 0 -1 | -1]

Row 2 = Row 2/2: [1 -1 1 | 2]
[0 1 1 | 1.5]
[0 0 -1 | -1]

Row 1 = Row 1 + Row 2: [1 0 2 | 3.5]
[0 1 1 | 1.5]
[0 0 -1 | -1]

Row 3 = -Row 3: [1 0 2 | 3.5]
[0 1 1 | 1.5]
[0 0 1 | 1]

From the row-echelon form, we can read the solution directly:
x = 3.5, y = 1.5, z = 1.

Therefore, the system of linear equations is solved, and the solution is x = 3.5, y = 1.5, z = 1.

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The given equation is not an exact differential equation. The differential equation can be determined to be exact if the partial derivatives of its terms with respect to the variables are equal. However, in this case, the partial derivatives of the terms with respect to y and x do not match, indicating that it is not an exact differential equation.

To determine if the given equation is an exact differential equation, we check if the partial derivatives of the terms with respect to y and x are equal. The equation is of the form (y^2 - 4xy - 2x^2) * dy + (x^2 - 4xy + 5λy^2) * dx = 0.

Taking the partial derivative of the first term with respect to y gives 2y - 4x, while the partial derivative of the second term with respect to x gives 2x - 4y. Since these derivatives do not match, the equation is not exact.

When an equation is not exact, it is possible to check if it can be made exact by multiplying an integrating factor. However, in this case, further manipulation of the equation does not yield an exact differential form.

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Advantages of buying a new vehicle:

Reliability and Warranty: New vehicles generally come with a warranty that covers repairs and maintenance for a certain period. This provides peace of mind and assures buyers of a reliable vehicle with minimal immediate repair costs.

Latest Features and Technology: New vehicles often come equipped with the latest features, technology, and safety advancements. This can include improved fuel efficiency, advanced driver-assistance systems, connectivity options, and entertainment features.

Customization and Personalization: Buying a new vehicle allows buyers to select the specific make, model, trim level, color, and additional options according to their preferences. It provides the opportunity to personalize the vehicle to meet individual needs and style.

Disadvantages of buying a new vehicle:

Higher Cost: New vehicles typically have a higher upfront cost compared to used vehicles. The depreciation rate is also steeper in the first few years, resulting in a larger financial loss if the vehicle is sold or traded-in.

Insurance and Taxes: New vehicles often have higher insurance premiums due to their higher value. Taxes, such as sales tax or luxury tax, may also be higher for new vehicles, further increasing the overall cost of ownership.

Limited Choice and Availability: The range of options for new vehicles is limited to the current models offered by manufacturers. Buyers may have to wait for a specific configuration or face potential supply constraints, especially for popular models.

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The equation of the hyperbola with the given foci and vertices is (x+6)²/25 - (y-4)²/39 = 1, making option (b) the correct choice.

To determine the standard form of the equation of a hyperbola, we consider the coordinates of the foci and vertices. The foci are given as (2, 4) and (-14, 4), while the vertices are given as (-11, 4) and (-1, 4).

Since the foci and vertices have the same y-coordinate, we know that the hyperbola has a horizontal transverse axis. This implies that the equation will have the form (x-h)²/a² - (y-k)²/b² = 1.

Comparing the coordinates, we find that the center of the hyperbola is (-6, 4). By calculating the differences in x-coordinates, we determine that a² = 25.

By calculating the differences in y-coordinates, we determine that b² = 39. Substituting these values, we arrive at the equation (x+6)²/25 - (y-4)²/39 = 1.

Therefore, option (b) is the correct standard form equation for the given hyperbola.

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The expression tan[cos¹(-2)] is undefined as cos¹(-2) is not a valid input for the inverse cosine function.

To find the exact value of the expression tan[cos¹(-2)], we need to evaluate the inner expression, cos¹(-2), and then take the tangent of that value.

Step 1: Evaluate cos¹(-2).

The inverse cosine function, cos¹(x), gives the angle whose cosine is x. However, the range of the inverse cosine function is restricted to [0, π], and cos(x) is only defined for -1 ≤ x ≤ 1. Since -2 is outside this range, cos¹(-2) is undefined.

Step 2: Take the tangent of the undefined value.

Since the inner expression, cos¹(-2), is undefined, we cannot proceed to find the tangent of that value.

Therefore, The expression tan[cos¹(-2)] is undefined, as cos¹(-2) is not a valid input for the inverse cosine function. Therefore, there is no exact value for this expression.

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The path of the particle described by the position function R(t) does not have a closed loop.

To determine if the path has a closed loop, we need to examine the behavior of the position vector R(t). The position vector R(t) = <x(t), y(t), z(t)> represents the position of the particle at time t.

If the path has a closed loop, it means that the particle returns to its initial position after completing a full loop. In other words, there exists a value of t, say a, such that R(a) = R(0), where R(0) represents the initial position.

To investigate this, we would need to solve the system of equations formed by equating each component of R(a) to the corresponding component of R(0). However, since the specific values of x(t), y(t), and z(t) are not provided in the given information, we cannot determine if the path has a closed loop or not.

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The general form of the equation for a line that goes through the points (4,3) and (8,2) is given by the equation 6x + 2y - 12 = 0.

To find the equation of a line passing through two points, we can use the point-slope form of a linear equation. The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) represents a point on the line, and m is the slope of the line.

Using the given points (4,3) and (8,2), we can calculate the slope of the line. The slope (m) is calculated as (change in y)/(change in x), which is equal to (2-3)/(8-4) = -1/4.

Substituting the values of the slope and one of the points into the point-slope form, we have y - 3 = (-1/4)(x - 4).

Simplifying the equation, we get y - 3 = (-1/4)x + 1.

To convert this equation into the general form, we move all the terms to one side and multiply through by 4 to eliminate the fraction. This gives us 4y - 12 = -x + 4.

Rearranging the terms, we have x + 4y - 16 = 0.

The general form of the equation for the line passing through the given points is 6x + 2y - 12 = 0, which matches option (C).

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Answer:

Step-by-step explanation:

all values are true

Answer:

Step-by-step explanation: R=P.Q = [tex]x.(-x+10x+32) = 9x^{2} + 32x[/tex]

R(x) = 0 (x>0) ⇒ ⇒[tex]9x^{2} +32x=0[/tex]⇒ [tex]\left \{ {{x=0} \atop {x=-\frac{32}{9} }} \right.[/tex]

Change x=0 into P(x) ⇒ (D) 32 dollars

The population will be 9 million on January 1, 2068. The population will be growing at a rate of approximately 0.211 million per year on January 1, 2010. The population will be growing at a rate of approximately 0.211 million per year on August 15, 2030.

a) In how many years will the population be 9 million?

Given, P = 9, and the equation to be solved is:

P = 4.5(1.023)¹⁻²⁰⁰⁰9 = 4.5(1.023)¹⁻²⁰⁰⁰

Take logarithms on both sides to solve for t:log(9/4.5) = log(1.023)⁻²⁰⁰⁰t = log(2)/log(1.023)≈ 67.9

Therefore, it will take about 68 years for the population to be 9 million.b) On what date is the population 9 million?

From part (a), we know that it will take about 68 years for the population to be 9 million. To determine the date, we simply add 68 years to January 1, 2000:January 1, 2000 + 68 years ≈ January 1, 2068

Therefore, the population will be 9 million on January 1, 2068.c) At what rate will the population be growing on January 1, 2010?

To find the rate of growth on January 1, 2010, we need to find the first derivative of the population function with respect to time:

t = 10 corresponds to January 1, 2010.P' = 4.5(1.023)¹⁻²⁰⁰⁰ ln(1.023) ≈ 0.211 million per year

Therefore, the population will be growing at a rate of approximately 0.211 million per year on January 1, 2010.d) At what rate will the population be growing on August 15, 2030?

To find the rate of growth on August 15, 2030, we first need to determine the corresponding value of t.

August 15, 2030, is 30 years and 227 days after January 1, 2000, so:t = 30 + 227/365 = 30.62 years

P' = 4.5(1.023)¹⁻²⁰⁰⁰ ln(1.023) ≈ 0.211 million per year

Therefore, the population will be growing at a rate of approximately 0.211 million per year on August 15, 2030.

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The first person will receive £166 and the second person will receive £581.

To divide £747 in the ratio 2:7 between two people, we need to determine the total number of parts that the ratio represents. The ratio of 2:7 means that for every 2 parts of £747 allocated to the first person, 7 parts of £747 will be allocated to the second person. Therefore, the total number of parts of the ratio is:

2 + 7 = 9

To determine the amount of money that each person will receive, we divide the total amount of money by the number of parts in the ratio and then multiply each part of the ratio by the resulting number. This can be written as:

First person's share = (2/9) * £747 = £166

Second person's share = (7/9) * £747 = £581

This division of £747 is consistent with the 2:7 ratio given in the problem.

In summary, to divide £747 in the ratio 2:7 between two people, we added the ratio values, 2 and 7, to get the total parts in the ratio of 9, then we divided the total amount £747 by the number of ratio parts (9) to get the value of one ratio part (83). Finally, we multiplied each ratio part by the value of one ratio part to get each person's share of the money, which is £166 for the first person and £581 for the second person.

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The two-year CD from First Command Bank with an initial investment of $40,000 will earn a certain amount of interest at maturity based on the Annual Percentage Yield (APY) provided by the bank.

To determine the interest earned at maturity, we need to refer to the APY provided by First Command Bank. Unfortunately, as an AI language model, I do not have access to real-time data or specific APY rates for First Command Bank. APY rates can vary and are subject to change over time. However, you can refer to the bank's official website or contact them directly to obtain the current APY for a two-year CD. Once you have the APY, you can calculate the interest earned by multiplying the APY by the initial investment of $40,000. For example, if the APY is 2.5%, the interest earned would be $40,000 * 0.025 = $1,000. Remember to consider any potential fees or penalties that may affect the final interest amount.

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The given expression is (-4/x-5) + (3x/7(x+2)) - (1 / (x²+7x)) - (2/(49x²)). We need to simplify this expression.

To simplify the expression, we can start by finding a common denominator for the fractions involved. The common denominator is 7(x+2)(x-5)(49x²). Multiplying each term by the appropriate factors to obtain this common denominator, we get (-4(7(x+2)(x-5)(49x²)) / (x-5)(7(x+2)) + (3x(x-5)(49x²)) / (7(x+2)(x-5)(49x²)) - (1(7(x+2)(x-5)(49x²))) / (x²+7x)(7(x+2)(x-5)(49x²)) - (2(x-5)(7(x+2)(x-5)(49x²))) / (49x²)(7(x+2)(x-5)(49x²)).

Simplifying further, we can cancel out the common factors in the numerator and denominator of each term. This results in (-4(49x²)) / (7(x+2)) + (3x) / 1 - (7(x+2)(x-5)(49x²)) / (x²+7x) - (2(x-5)) / 1.

Combining like terms and simplifying the expression, we obtain (-196x² + 3x - 7(x+2)(x-5)(49x²) - 2(x-5)) / (7(x+2)(x²+7x)(49x²)).

This is the simplified form of the given expression.

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Using an equation, the number of cutting boards sold is:

An equation is a mathematical statement of the equality or equivalence of two or more mathematical expressions.

The above statement shows that equations are formed by using the equal symbol (=) and algebraic expressions.

The selling price per large cutting boards = $18

The selling price per small cutting boards = $14

Let the number of large cutting boards sold at the fall festival = x

Let the number of small cutting boards sold at the festival = 3x

The total revenue generated from the fall festival = $420

18x + 14(3x) = 420

18x + 42x = 420

60x = 420

x = 7

The number of large cutting boards sold = 7

The number of small cutting boards sold = 21 (3 x 7)

The total number of cutting boards sold = 28 (7 + 21)

Thus, based on an equation, the total number of cutting baords sold is 28.

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(a) To find the velocity components u(x, y) and v(x, y) from the given stream function y(x, y) = ln √((x − a)² + (y − b)²), we can use the relationship:

u = ∂ψ/∂y and v = -∂ψ/∂x

where ψ is the stream function.

Taking the partial derivatives of the stream function with respect to y and x:

∂ψ/∂y = (∂/∂y)(ln √((x − a)² + (y − b)²))

= (∂/∂y)(1/2)ln((x − a)² + (y − b)²)

= (1/2)((∂/∂y)ln((x − a)² + (y − b)²))

= (1/2)(2(y − b))/(√((x − a)² + (y − b)²))

= (y − b)/(√((x − a)² + (y − b)²))

∂ψ/∂x = (∂/∂x)(ln √((x − a)² + (y − b)²))

= (∂/∂x)(1/2)ln((x − a)² + (y − b)²)

= (1/2)((∂/∂x)ln((x − a)² + (y − b)²))

= (1/2)(2(x − a))/(√((x − a)² + (y − b)²))

= (x − a)/(√((x − a)² + (y − b)²))

Therefore, the velocity components u(x, y) and v(x, y) are:

u(x, y) = (y − b)/(√((x − a)² + (y − b)²))

v(x, y) = -(x − a)/(√((x − a)² + (y − b)²))

(b) To show that the given flow satisfies the continuity equation ∂u/∂x + ∂v/∂y = 0, we need to calculate the partial derivatives and show that their sum is equal to zero.

∂u/∂x = ∂/∂x((y − b)/(√((x − a)² + (y − b)²)))

= (-(x − a))/((x − a)² + (y − b)²)

∂v/∂y = ∂/∂y(-(x − a)/(√((x − a)² + (y − b)²)))

= (-(y − b))/((x − a)² + (y − b)²)

Summing up the partial derivatives:

∂u/∂x + ∂v/∂y = (-(x − a))/((x − a)² + (y − b)²) + (-(y − b))/((x − a)² + (y − b)²)

= (-(x − a) − (y − b))/((x − a)² + (y − b)²)

= -((x − a) + (y − b))/((x − a)² + (y − b)²)

We observe that the numerator -(x − a) − (y − b) equals zero, so:

∂u/∂x + ∂v/∂y = -((x − a) + (y − b))/((x − a)² + (y − b)²) = 0

Therefore, the given flow satisfies the continuity equation ∂u/∂x + ∂v/∂y = 0.

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The annual growth factor represents the rate at which an investment grows each year. It is calculated by adding 1 to the growth rate expressed as a decimal.

In this case, the investment is growing by 7.5% each year. To express this as a decimal, we divide 7.5 by 100, which gives us 0.075. The annual growth factor is then calculated by adding 1 to the growth rate: 1 + 0.075 = 1.075.

Therefore, the annual growth factor is 1.075. This means that the investment grows by a factor of 1.075 each year, which corresponds to a 7.5% increase from the previous year's value.

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Therefore, the degree of the resulting polynomial is m + n when two polynomials of degree m and n are multiplied together.

What is polynomial?

A polynomial is a mathematical expression consisting of variables and coefficients, which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents. Polynomials can have one or more variables and can be of different degrees, which is the highest power of the variable in the polynomial.

Here,

When two polynomials are multiplied, the degree of the resulting polynomial is the sum of the degrees of the original polynomials. In other words, if the degree of the first polynomial is m and the degree of the second polynomial is n, then the degree of their product is m + n.

This can be understood by looking at the product of two terms in each polynomial. Each term in the first polynomial will multiply each term in the second polynomial, so the degree of the resulting term will be the sum of the degrees of the two terms. Since each term in each polynomial has a degree equal to the degree of the polynomial itself, the degree of the resulting term will be the sum of the degrees of the two polynomials, which is m + n.

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The values of x1 and x2 in the LU decomposition equation [3 0][1 -2][x1] = [3][-2 1][0 1][x2] = [-3] can be determined by solving the system of equations formed by equating the corresponding elements of the matrices. We need to find the values of x1 and x2 that satisfy the equation.

Explanation: Let's write the system of equations based on the given LU decomposition equation:

3x1 + 0x2 = 3

1x1 - 2x2 = -2

0x1 + 1x2 = -3

Simplifying the equations, we have:

3x1 = 3

x1 - 2x2 = -2

x2 = -3

From the first equation, we find that x1 = 1. Substituting this value into the second equation, we have:

1 - 2x2 = -2

-2x2 = -3

x2 = -3/(-2)

x2 = 3/2

Therefore, the values of x1 and x2 in the LU decomposition equation are x1 = 1 and x2 = 3/2.

The correct option is not provided in the given choices.

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The sampling technique used in each study is as follows: (a) convenience sampling, (b) systematic sampling, and (c) stratified random sampling.

(a) In the first study, where a journalist goes to a campground to ask people about their feelings regarding air pollution, the sampling technique used is convenience sampling. This is evident because the journalist approaches individuals who are readily available and easily accessible at the campground. However, convenience sampling may introduce bias as it does not ensure a representative sample of the population.

(b) In the second study, where every tenth machine part is selected from an assembly line for measurement, the sampling technique used is systematic sampling. Systematic sampling involves selecting every nth element from a population after establishing a sampling interval. In this case, every tenth machine part is selected to ensure a systematic and unbiased approach to quality assurance.

(c) In the third study, where attitudes about smoking are studied at a college and students are divided by class and then randomly sampled from each class for interviews, the sampling technique used is stratified random sampling. Stratified random sampling involves dividing the population into homogeneous subgroups (strata) and then randomly selecting samples from each subgroup. By dividing the students into different class strata and randomly selecting samples from each class, this study aims to ensure representation from each class in the final sample.

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Qualitative research is an exploratory research method that emphasizes interpreting and analyzing people's subjective experiences, thoughts, and feelings. Quantitative research, on the other hand, is a research method that is centered on generating numerical data and statistical analysis in order to evaluate phenomena.

The basic differences between qualitative and quantitative research are as follows

Qualitative Research:

Qualitative research focuses on understanding the human experience from the viewpoint of the participants being studied.It is an exploratory research method that emphasizes interpreting and analyzing people's subjective experiences, thoughts, and feelings.

Qualitative research relies on non-numerical data and data is collected in an open-ended, unstructured manner.Data analysis in qualitative research is subjective, interpretive, and contextually dependent.

Qualitative research has a small sample size but in-depth data is collected through the use of interviews, observation, and focus groups.

Quantitative Research:

Quantitative research focuses on generating numerical data and statistical analysis in order to evaluate phenomena.It is a deductive research method that emphasizes numerical data, mathematical models, and statistical analysis.

Quantitative research relies on numerical data and data is collected in a structured and standardized manner.Data analysis in quantitative research is objective, empirical, and replicable.

Quantitative research has a large sample size but superficial data is collected through the use of surveys and questionnaires.

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Answer:

180 minutes.

Step-by-step explanation:

Based on the given scatterplot, the only plausible value of correlation 'r' is **d. 0**.

Looking at the scatterplot, we observe that the points form a perfect positive linear relationship, where the points are arranged in a straight line with a positive slope. This indicates a strong positive correlation between the two variables being measured.

The correlation coefficient, 'r', measures the strength and direction of the linear relationship between variables. A value of 0 indicates no linear relationship between the variables, which is not the case here. Therefore, the only plausible value of correlation 'r' based on the scatterplot is 0, making option d the correct choice.

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To find Joann's maximum weekly earnings, we need to maximize the earnings function subject to the given constraints. The constraints are as follows:

m ≥ 10          (Minimum hours spent mentoring)

m ≤ 15          (Maximum hours spent mentoring)

t ≥ 0            (Non-negativity constraint for tutoring)

p ≥ 8            (Minimum hours spent personal grocery shopping)

p ≤ 12          (Maximum hours spent personal grocery shopping)

M + t + p ≤ 40  (Total hours worked constraint)

The objective function is the earnings function:

Earnings = 16m + 14t + 12p

We can set up and solve this linear programming problem using optimization techniques.

The maximum weekly earnings can be found by solving the following linear programming problem:

Maximize: Earnings = 16m + 14t + 12p

Subject to:

m ≥ 10

m ≤ 15

t ≥ 0

p ≥ 8

p ≤ 12

M + t + p ≤ 40

By solving this problem, we can find the values of m, t, and p that maximize Joann's earnings while satisfying the given constraints.

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(a) A checking account overdrawn by $33.91 would be represented as -$33.91.

(b) A river 6.88 feet above flood stage would be represented as +6.88 feet.

(c) 2.6 degrees below zero would be represented as -2.6 degrees.

(d) 16.8 seconds would be represented as +16.8 seconds.

In each situation, a signed number is used to indicate a quantity relative to a reference point or zero.

The sign indicates whether the value is above or below the reference point. In case (a), the negative sign indicates that the checking account balance is below zero, indicating an overdrawn balance.

In case (b), the positive sign indicates that the river level is above the flood stage, indicating a flood.

In case (c), the negative sign indicates that the temperature is below zero, indicating a below-freezing temperature. In case (d), the positive sign indicates a positive quantity of seconds, representing a duration of time.

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