Please help with this difficult one...

Answer:

n(-9+ n) =0

Step-by-step explanation:

-9n+n^2=0   Kind of use 'reverse distributive' property

n (-9 + n) = 0

Answer:

option 4 and option 3 are the answers respectively

Answer:

[tex] \sqrt{ {2}^{3} } \\ \sqrt{3} \\ .............[/tex]

Answer:

370 + 80x ≤ 1090

Step-by-step explanation:

By using letter variables for the unknown numbers, we can break down the question into mathematical terms:

If the cost is $370 per day and the number of days is unknown, we can substitute the number of days with a placeholder. In this case, it'll be a variable such as x. So the cost can be represented by $370y.

If the cost is $80 per hour and the number of hours is unknown, we can substitute the number of hours with a placeholder. In this case, it'll be a variable such as y. So the cost can be represented by $80x.

The questions asks for the total cost not to exceed $1090 per day. This means that we know that the number of days is 1. We're trying to find the maximum number of hours, so our equation will combine the costs of both day costs and hour costs:

$370 (1 day) + $80 (x hours) ≤ $1090 per day

The symbol is the equal to or less than symbol, meaning the combined total costs is either equal to $1090 or less than it.

To simplify this, we can rewrite it as:

370 + 80x ≤ 1090

Answer:

72 Degrees

Step-by-step explanation:

We know that its 72 because of VAT, the vertical angle theorem.

Answer: (1, -10)

Step-by-step explanation:

Since both of the equations are set equal to y, we can conclude that:

[tex]-x^2 -5x-4=-x^2 + 9x-18\\\\-5x-4=9x-18\\ \\ -14x-4=-18\\\\-14x=-14\\\\x=1[/tex]

If x=1, then [tex]y=-(1)^{2}+9(1)-18=-10[/tex]

Thus, the solution is (1, -10)

Answer:

operant conditioning and schedules of reinforcement

Answer:

12

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{ASSUMING}[/tex]

[tex]\mathsf{x^{2y}}[/tex]

[tex]\huge\textbf{IF SO, FOLLOW THESE STEPS TO}\\\huge\textbf{SOLVE FOR YOUR RESULT}[/tex]

[tex]\mathsf{x^{2y}}\\\mathsf{= 3^{2(6)}}\\\mathsf{= 3^{2\times6}}\\\mathsf{= 3^{12}}\\\mathsf{= 3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3}\\\mathsf{= 9\times9\times9\times9\times9\times9}\\\mathsf{= 81\times81\times81}\\\mathsf{= 6,561\times81}\\\mathsf{= 531,441}[/tex]

[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{531,441}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

Gabrielle is 27

Mikhail is 9

Step-by-step explanation:

g = 3m

g + m = 36

since g = 3m we can substitute it in the equation

g + m = 36 as

3m + m = 36

4m = 36

m = 9

3m = 27 which is g

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The inverse of g(5) and the inverse of h(x) are 2 and [tex]h^{-1}=\frac{-x-13}{4}[/tex] respectively

Inverse of a function

Given the following coordinates and function

g = {(-6, -5), (2, 5), (5,6), (6,9)}

The inverse of "g" is determined by switching the coordinates to have:

g^-1(x) =  {(-5, -6), (5, 2), (6, 5), (9,6)}

Since the value of the y-coordinate when x = 5 is 2, hence g^-1(5) = 2

Given the function expressed as:

h(x) = -4x - 13

y = -4x - 13

Replace y with x

x = -4y - 13

4y = -x - 13

y = (-x-13)/4

[tex]h^{-1}=\frac{-x-13}{4}[/tex]

Determine the composite function [tex](hoh^{-1})(-1)[/tex]

h(h(x)) = h(-4x-13)
h(h(x)) =[tex]\frac{-(-4x-13)-13}{4} \\[/tex]

[tex]h(h(x))=\frac{4x}{4} \\h(h(x)) = x\\h(h(-1)) = -1[/tex]

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Answer: Choice B) One-sixth

In other words, the fraction 1/6

===========================================================

Explanation:

The base, aka horizontal component, is 6 units long. Count out the spaces from -5 to 1 to get a result of 6.

Or you could subtract and use absolute value in either of these two ways

Where A = -5 and B = 1 are the endpoints mentioned. Absolute value is used to ensure the result of the subtraction isn't negative. Negative distance on a number line doesn't make sense.

----------

However you determine the base, we'll multiply it by the unknown height which we'll call h. This leads to the area of the rectangle. The area is 6h.

Rule: The area under a probability density curve must always be 1.

So the area 6h must be 1 which helps us see that...

6h = 1

h = 1/6

Divide both sides by 6 to isolate h fully.

Answer:

B

Step-by-step explanation:

Answer:

314 in²  (nearest whole number)

Step-by-step explanation:

Radius of a regular polygon: The distance from the center of the polygon to any vertex.  The radius of a hexagon is equal to the length of one side.

Therefore, from inspection of the given diagram:

To find the area of a regular polygon, we first need to calculate the apothem.   The apothem is the line drawn from the center of the polygon to the midpoint of one of its sides.

[tex]\textsf{Length of apothem (a)}=\dfrac{s}{2 \tan\left(\frac{180^{\circ}}{n}\right)}[/tex]

where:

Given:

Substitute the given values into the formula and solve for a:

[tex]\implies \textsf{a}=\dfrac{11}{2 \tan\left(\frac{180^{\circ}}{6}\right)}=\dfrac{11\sqrt{3}}{2}[/tex]

Area of a Regular Polygon

[tex]\textsf{A}=\dfrac{n\:s\:a}{2}[/tex]

where:

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}[/tex]

[tex]\implies \sf A=314.3672216...[/tex]

[tex]\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)[/tex]

We conclude that the line that passes through (0, 0) and (2, -3) is perpendicular to line l.

Remember that two lines are perpendicular only if the slope of one of the lines is equal to the opposite of the inverse of the slope of the other line.

So, if line l has the slope 2/3.

Then the perpendicular lines have a slope equal to -3/2.

Now, remember that if a line goes through two points (x₁, y₁) and (x₂, y₂), then the slope of that line is:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

So here we just need to find two points (x₁, y₁) and (x₂, y₂) such that the slope is equal to -3/2.

If we define (x₁, y₁) = (0, 0), then the other point must be:

[tex]a = \frac{y_2 - 0}{x_2 - 0} = -3/2\\\\y_2/x_2 = -3/2[/tex]

Then we can write the other point as (2, -3).

So we conclude that the line that passes through (0, 0) and (2, -3) is perpendicular to line l.

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Answer:

See below

Step-by-step explanation:

Slope = rise / run

           from 0,-1   to  1.5 , 0

               this is    1 / 1.5    =   2/3

y xis intercept = -1

y = 2/3 x   -1            Slope intercept form

2/3 x - y   = 1             another form

2x - 3y = 3                Standard form (I think this is 'standard form' ....yah?)

Answer:

[tex]y=-4; y=28[/tex]

Step-by-step explanation:

The way I like to think about it, with absolute value meaning the distance is

"find which number are 16 apart from 12". Which means 28 (to the right) or -4 (to the left).

More formally, applying the definition of absolute value,

[tex]|y-12|=16 \leftrightarrow y-12=\pm16\\y-12=-16 \rightarrow y=-4\\y-12=+16 \rightarrow y=28[/tex]

Answer:

Step-by-step explanation:

Using the Law of Cosines,

[tex]a^{2}=b^2 + c^2 - 2bc \cos A\\\\13^{2}=14^{2}+18^{2}-2(14)(18) \cos A\\\\-351=-504 \cos A\\\\\cos A=\frac{351}{504}\\\\A=\boxed{\cos^{-1} \left(\frac{351}{504} \right)}[/tex]

In logarithmic form, we get In(2e^9)= ln(2)+9.

We are given,

 ln(2[tex]e^{9}[/tex])

We know that, ln(ab) = ln(a) + ln(b)

So we get,

 ln(2[tex]e^{9}[/tex]) = ln(2)+ln([tex]e^{9}[/tex])

Since ln(m^n)=n ln(m)  

And ln(e)= 1, we will get,

ln(2[tex]e^{9}[/tex]) = ln(2) +9 ln(e)

          = ln(2) +9

Hence, the logarithmic form, we get In(2e^9)= ln(2)+9.

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Answer: (0, -6) and (1, -5)

Step-by-step explanation:

If [tex]x-y=6[/tex], then [tex]y=x-6[/tex]. Substituting this into the second equation,

[tex]x-6=x^{2}-6\\\\x^{2}-x=0\\\\x(x-1)=0\\\\x=0, 1[/tex]

If x=0, y=-6.

If x=1, y=-5.

So, the solutions are (0, -6) and (1, -5)

The correct answer is  CI = (71.415%, 78.915%)

The correct option is (A)

A confidence interval is the mean of your estimate plus and minus the variation in that estimate.

Given:

x = 376

Sample = 500 students

CI= [(376/500-1.96 √((376/500)*(124/500)/500) , (376/500-1.96                

                                                                         √((376/500)*(124/500)/500)]

CI = (71.415%, 78.915%)

Hence, CI = (71.415%, 78.915%)

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The dimensions of the garden with the largest area she can enclose are given by 24*14 square yards.

The area (A) of the rectangle with length L and Width W is given by,

A=L*W

The maximum of [tex]y=ax^2+bx[/tex] occurs at x = -b/2a

Let the length and width of the garden be L and W respectively.

Now let my friend use cedar fencing for one width and cheaper metal fencing for rest sides.

Rate of cedar fencing is $17/yard

Then she has to pay for cedar fencing = 17W

rate of cheaper metal fencing is $7/yard

Then she has to pay for metal fencing = 7W+7*2L = 7W+14L

Then according to condition,

17W+7W+14L = 672

24W+14L = 672

12W+7L = 336

7L = 336-12W

L = (336-12W)/7

Then the area of the rectangular garden is given by,

A = L*W

[tex]A=\frac{336-12W}{7}\times W\\A=-\frac{12}{7}W^2+48W[/tex]

So here a = -12/7 and b = 48

Then maximum of W occurs at,

W = -48/(2*(-12/7)) = (48*7)/(2*12) = 336/24 = 14

Then maximum width = 14 yards

then length (L) = (336-12*14)/7 = 168/7 = 24 yards

Hence the dimensions with the leargest area she can enclose is given by = 24 * 14 square yards.

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Answer:

25:16

50:32

100:64

Step-by-step explanation:

The equation to model the above scenario is [tex]x^{2}[/tex] +22x - 23 = 0

The perimeter of the expanded rectangle is 48 units

A rectangle is a quadrilateral with its 4 angles 90°

Analysis:

First rectangle:

length = 10 + x

width = x

Second rectangle:

length = x + 14

width = x + 8

Area of expanded rectangle = 135 square unit

(x+8)(x+14) = 135

[tex]x^{2}[/tex] + 8x + 14x + 112 = 135

[tex]x^{2}[/tex] + 8x + 14x -23 = 0

[tex]x^{2}[/tex] + 22x -23 = 0

[tex]x^{2}[/tex] + 23x - x - 23 = 0

(x-1)(x+23) = 0

Therefore x = 1

Expanded length = 1+14 = 15

Expanded width = 1+8 = 9

Perimeter = 2(9+15) = 48 units

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We have to use the formula  [tex]n = log_{r} (1+\frac{S_{n}(1-r) }{a})[/tex]  to find the number of terms of a finite geometric sequence.

If a be the first term of a finite sequence, r be the common ratio between consecutive terms and n be the number of terms.

So, we have to use the formula of sum of sequence and then calculate it to reduce the equation to find the value of number of terms, that is n.

Then, Sum of the sequence (Sn) = [tex]\frac{a(1-r^{n}) }{1-r}[/tex]

Here, in the given problem,

Sum(Sn) = 280, First term of the sequence(a) = 40, Common ratio(r) = 0.75

So, Sn = [tex]\frac{a(1-r^{n}) }{1-r}[/tex]

   ⇒ [tex]1-r^{n} =\frac{S_{n}(1-r) }{a}[/tex]

   ⇒ [tex]r^{n} =1+\frac{S_{n}(1-r) }{a}[/tex]

   ⇒ [tex]n = log_{r} (1+\frac{S_{n}(1-r) }{a})[/tex]          

Now you have to put the values and get the number of terms.

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Step-by-step explanation:

2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)

2x+4+5x+25=4x-32+2x-4

7x+29=6x-36

7x-6X=-36-29

X=-65

Answer:

x = -65

Step-by-step explanation:

2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2) ​

Distribute:

2(x + 2): 2x + 4

5(x + 5): 5x + 25

=

4(x - 8): 4x - 32

2(x - 2): 2x - 4

Combine like terms:

(2x + 4) + (5x + 25) = (4x - 32) + (2x - 4)

5x + 2x: 7x              =  4x + 2x: 6x

4 + 25 = 29             =  -32 - 4: -36

7x + 29 = 6x - 36

Now we want to separate like terms,

subtract 29 from both sides

subtract 6x from both sides

7x + 29 - 29 - 6x = 6x - 29 - 6x- 36

7x - 6x = - 29 - 36

x = -65

Answer:

=  -10

Step-by-step explanation:

p + (-q) - 2 = x

if:

p = -3

q = 5

then:

-3 + (-5) - 2 = x

we know that:

+(-) = -

then:

-3 +(-5) - 2 = -3 - 5 - 2 = x

x = -10

The value of the expression p + (-q) - 2 is -10 if the p = -3 and q = 5 the answer is -10.

It is defined as the combination of constants and variables with mathematical operators.

We have given an expression:

= P + (-q) - 2

Plug p = -3

q = 5

= -3 + (-5) - 2

= -3 - 5 - 2

= -10

Thus, the value of the expression p + (-q) - 2 is -10 if the p = -3 and q = 5 the answer is -10.

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Answer:

340 i am pretty sure

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

0 + 1 = 1

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

Answer: 83

Step-by-step explanation:

The equation of the line in point-slope form is

[tex]y-3=4(x-2)[/tex]

Substituting in x = 22,