PLEASE HELP!! I WILL GIVE YOU EVERYTHING

PLEASE HELP!! I WILL GIVE YOU EVERYTHING

Answers

Answer 1

Answer:

Step-by-step explanation:

7.9

Answer 2

Answer:

y - 4 = (-3/2)(x - 4)

Step-by-step explanation:

Here's how we obtain the blue graph:

1) translate the red graph 5 units to the right, and

2) translate the resulting graph 5 units upward.

The equation of the blue graph is y - 4 = (-3/2)(x - 4)


Related Questions

Find the value of 5(x - y)

Answers

Answer:

= 5x-5y

Step-by-step explanation:

Multiply 5to x and y

Answer:

5x-5y

Step-by-step explanation:

multiply both the terms x and y by 5.

ANSWER A water tower in New York City has the shape of a cylinder with a cone on top. The cylinder has a diameter of 12 feet and a height of 15 feet. The roof has an inclination angle of 25o . There are 7.48 gallons in a cubic foot. If residents of an apartment building are using the water from the tower at an average rate of 56 gallons per minute, determine how long, to the nearest minute, it will take to drain the entire tower.

Answers

Answer:

241 minutes

Step-by-step explanation:

Given:

Height of cylinder, h = 15 ft

Radius, r = [tex] \frac{d}{2} = \frac{12}{2} = 6 [/tex] (both cylinder and cone have same radius)

Let's find the height of cone, since angle of inclination = 25°C.

[tex] tan25 = \frac{h}{r} [/tex]

[tex] h = r tan25 [/tex]

[tex] h = 6 tan25 = 2.8 [/tex]

Height of cone = 2.8 ft

Let's find colume of tower.

Volume = Volume of cone + volume of cylinder.

Formula for volume of cone = ⅓πr²h

Volume of cylinder = πr²h

Therefore,

V = ⅓πr²h + πr²h

V = ⅓π*6²*2.8 + π*6²*15

V = 105.558 + 1696.46

V = 1802.02 ft³

Since volume is 1802.02 ft³, and there are 7.48 gallons in a cubic ft, the total gallon =

1802.02 * 7.48 = 13479.11 gallons

Water is used at an average rate of 56 gallons per minute.

Amount if time to drain the water:

Total gallons / average rate

[tex] = \frac{13479.11}{56} = 240.698 [/tex]

≈ 241 minutes

The housing commission of King County is interested in finding out more about the number of rental units that qualify as low-income housing but do not meet the minimum standard living requirements in Seattle and Renton. Units are randomly selected in both cities. Of the 85 low-income units sampled in Seattle (City 1), 17 do not meet minimum requirements. Of the 80 units sampled in Renton (City 2), 24 do not meet minimum requirements. The value of the z-statistic for testing equality of the proportion of low-income rental units that do not meet minimum standards in the two cities is
a) z=-2.33
b) none of these choices
c) Z=-1.96
d) Z= -1.49
e) z=-1.65

Answers

Answer:

d) Z= -1.49

Step-by-step explanation:

sample #1   ----->              

first sample size,[tex]n_1= 85[/tex]

number of successes, sample 1 =   [tex]x_1= 17[/tex]

proportion success of sample 1 ,

[tex]\bar p_1= \frac{x_1}{n_1} = 0.2000000[/tex]                  

sample #2   ----->              

second sample size,

[tex]n_2 = 80[/tex]

number of successes, sample 2 = [tex]x_2 = 24[/tex]

proportion success of sample 1 ,

[tex]\bar p_2= \frac{x_2}{n_2} = 0.300000[/tex]            

difference in sample proportions,

[tex]\bar p_1 - \bar p_2 = 0.2000 - 0.3000 \\\\= -0.1000[/tex]

pooled proportion ,

[tex]p = \frac{ (x_1+x_2)}{(n_1+n_2)}\\\\= 0.2484848[/tex]

std error ,

   [tex]SE=\sqrt{p*(1-p)*(\frac{1}{n_1}+\frac{1}{n_2} )} \\\\=0.06731[/tex]

Z-statistic = [tex](\bar p_1 - \bar p_2)/SE = ( -0.100 / 0.0673 ) = -1.49[/tex]

Choose the slope Y intercept that corresponds with the graph

Answers

Answer:

A

Step-by-step explanation:

First, find the y-intercept by seeing where the line goes through the y-axis

This is at (0, -2) so the y-intercept is -2.

Then, use rise over run to find the slope.

The slope is -3

Answer:

A. Slope -3, y- intercept -2

Step-by-step explanation:

Well the line passes through the point (0,-2) and from there if you draw a line 1 to the left (run) and then up 3(rise) you connect with the line, so the slope is -3(rise over run)

Hope this helps,

plx give brainliest

A travel magazine conducts an annual survey where readers rate their favorite cruise ship. Ships are rated on a 10 point scale, with higher values indicating better service. A sample of 20 ships that carry fewer than 500 passengers resulted in a average rating of 6.93 with standard deviation 0.31. A sample of 55 ships that carry more than 500 passengers resulted in an average rating of 7.07 with standard deviation 0.6. statcrunch. Assume that the population standard deviation is 4.58 for ships that carry fewer than 500 passengers and 3.95 for ships that carry 500 or more passengers.
Round your all answers to two decimal places.
a. What is the point estimate of the difference between the population mean rating for ships that carry fewer than 500 passengers and the population mean rating for ships that carry 500 or more passengers?
b. At 95% confidence, what is the margin of error?
c. What is a 95% confidence interval estimate of the difference between the population mean ratings for the two sizes of ships?

Answers

Answer:

a) The point estimate of the difference between the populations is Md=-0.14.

b) The margin of error at 95% confidence is 0.212.

c) The 95% confidence interval for the difference between means is (-0.352, 0.072).

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (ships under 500 passengers), of size n1=20 has a mean of 6.93 and a standard deviation of 0.31.

The sample 2 (ships over 500 passengers), of size n2=55 has a mean of 7.07 and a standard deviation of 0.6.

The difference between sample means is Md=-0.14.

[tex]M_d=M_1-M_2=6.93-7.07=-0.14[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{0.31^2}{20}+\dfrac{0.6^2}{55}}\\\\\\s_{M_d}=\sqrt{0.005+0.007}=\sqrt{0.011}=0.11[/tex]

The critical t-value for a 95% confidence interval is t=1.993.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_{M_d}=1.993 \cdot 0.11=0.212[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M_d-t \cdot s_{M_d} = -0.14-0.212=-0.352\\\\UL=M_d+t \cdot s_{M_d} = -0.14+0.212=0.072[/tex]

The 95% confidence interval for the difference between means is (-0.352, 0.072).

A high school football coach is trying to decide which quarterback he should start in next week’s game. He examines the win/lose record for the two quarterbacks. Which quarterback should he start? Explain

The player / wins/ losses

Germaine / 8 / 5

Gabriel / 7 / 4

Answers

Answer:

Gabriel has the highest proportion of wins, so he should start.

Step-by-step explanation:

He should start the quarterbacks with the highest proportion of wins.

The proportion of wins is the number of games won divided by the number of games played(wins + losses).

We have that:

Germaine has 8 wins in 8+5 = 13 games. So his proportion of wins is 8/13 = 0.6154.

Gabriel has 7 wins in 7+4 = 11 games. 7/11 = 0.6364

Gabriel has the highest proportion of wins, so he should start.

The linear equation graphed above gives the height in feet above the ground of Shelly t seconds after she opened her parachute when jumping from an airplane. According to the graph, how many seconds after opening her parachute will Shelly be 2,000 feet above the ground?

Answers

Answer:

[tex]\large \boxed{\text{60 s}}[/tex]

Step-by-step explanation:

Assume your graph looks like the one below.

1. Calculate the equation of the straight line

The slope-intercept equation for a straight line is

y = mx + b

where m is the slope of the line and b is the y-intercept.

The line passes through the points (0,2600) and (30, 2300)

(a) Calculate the slope of the line

[tex]\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{2300 - 2600}{30 - 0}\\\\& = & \dfrac{-300}{30}\\\\& = & \text{-10 ft/s}\\\\\end{array}[/tex]

(b) Locate the y-intercept

The y-intercept is at 2600 ft

(c) Write the equation for the line

h = -10t + 2600

(d) Calculate the time to 2000 ft

[tex]\begin{array}{rcl}h & = & -10t + 2600\\2000 & = & -10t + 2600\\-600 & = & -10t\\t & = & \dfrac{-600}{-10}\\\\& = & \text{60 s}\\\end{array}\\[/tex]

Shelley will be at 2000 ft 60 s after opening the parachute.

Let the given line pass through the point that is [tex]\bold{(0,2600)\ \ and\ \ (20, 2400)}[/tex]

[tex]\therefore[/tex]

[tex]\to \bold{\frac{H-2400}{t-20}} \bold{= \frac{2600-2400}{0-20}}\\\\[/tex]

                [tex]\bold{=\frac{200}{-20} }\\\\ \bold{= -\frac{200}{20}}\\\\ \bold{= - 10}\\\\[/tex]

[tex]\to \bold{H-2400=-10t+200}\\\\\to \bold{H+10t=2400+200}\\\\\to \bold{H+10t=2600}\\\\\to \bold{H=2600-10t}\\\\[/tex]

Let

time (t) in second

Height (h) in feet

for [tex]\bold{\ H=2000\ feet\\}[/tex]

[tex]\to \bold{2000=2600-10t}\\\\\to \bold{10t = 2600- 2000}\\\\\to \bold{10t = 600}\\\\\to \bold{t=\frac{600}{10}}\\\\\to \bold{t= 60\ second}\\\\[/tex]

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The earth moves at about 98,000 feet per second as it resolves around the Sun. How fast is that in miles per hour?> (recall that 1 mile is 5,280.00 feet.)

Answers

Answer:

[tex]\frac{98000 ft}{1 second}\times \frac{? second}{1 hour}\times \frac{1 mile}{5280 ft}[/tex]

Step-by-step explanation:

If you cancel out the same unit, one from numerator and one from denominator, you will get mile/ hour as asked. The leftover is doing your math.

You finish your work!!

I don't care about the evaluation. I do care if you can work by yourself and understand the work

Suppose a basketball player has made 184 out of 329 free throws. If the player makes the next 2 free throws, I will pay you $24. Otherwise you pay me $12. Step 1 of 2 : Find the expected value of the proposition. Round your answer to two decimal places. Losses must be expressed as negative values.

Answers

Answer:

The expected value of the proposition is -$12.74.

Step-by-step explanation:

Expected value:

It is the multiplication of each outcome by it's probability.

For each free throw, there are only two possible outcomes. Either the player makes, or he does not. Each free throw is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Suppose a basketball player has made 184 out of 329 free throws.

This means that [tex]p = \frac{184}{329} = 0.5593[/tex]

2 free throws:

This means that [tex]n = 2[/tex]

Probability of making two free throws.

This is P(X = 2).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{2,2}.(0.5593)^{2}.(0.4407)^{0} = 0.3128[/tex]

Expected value:

If he makes both free throws, you earn $12. So 0.3128 probability of you earning $12.

Otherwise, you have to pay $24. 1 - 0.3128 = 0.6872 probability of you losing $24.

So

E = 0.3128*12 - 0.6872*24 = -12.74

The expected value of the proposition is -$12.74.

Answer:

-.74

Step-by-step explanation:

I just did the homework and this is the correct answer

Some accounting firms give the client an option to pay a fee when the tax return is completed that guarantees tax advices and support from the accountant if the client were audited. A large accounting firm is trying to determine what fee to charge for next​year's returns. In previous​ years, the actual mean cost to the firm for attending a client audit session was $690. To determine if this cost has​ changed, the firm randomly samples 35 client audit fees. The sample mean audit cost was $700 with a standard deviation of $65.

Required:
a. Develop a 90% confidence interval estimate for the mean audit cost.
b. Based on your confidence​ interval, what do you think of the claim that the mean cost has​ changed?

1. The interval does not contain the historical data mean $690, which supports claim the mean cost has changed.
2. The interval contains historical data mean $690, which supports the claim the mean cost has changed.
3. The interval does not contains historical data mean $690, which does not support the claim it has changed.
4. The interval contains historical data mean $690, which does not support the claim the mean cost has changed.

Answers

Answer:

a) $700+/-$18.07

Therefore,the 90% confidence interval (a,b)

= ($681.93, $718.07)

b) 4. The interval contains historical data mean $690, which does not support the claim the mean cost has changed.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $700

Standard deviation r = $65

Number of samples n = 35

Confidence interval = 90%

z(at 90% confidence) = 1.645

a. Develop a 90% confidence interval estimate for the mean audit cost.

Substituting the values we have;

$700+/-1.645($65/√35)

$700+/-1.645($10.98700531147)

$700+/-$18.07362373736

$700+/-$18.07

Therefore,the 90% confidence interval (a,b) = ($681.93, $718.07)

b) Since, $690 is contained between the 90% confidence interval of ($681.93, $718.07). It implies that the mean cost has not changed.

4. The interval contains historical data mean $690, which does not support the claim the mean cost has changed.

What two methods are the best choices to factor this expression?

18x2-8

-Factor by grouping.

-Factor out the GCF.

-Use the difference of squares rule.

-Use the perfect square trinomial rule.

Answers

Answer:

- Factor by grouping. - Factor out the GCF.

Step-by-step explanation:

Given the expression 18x²-8, the best method to factor this expression are Factor by grouping and by factoring out the greatest common factor.

Step 1: Factor by grouping

Factor by grouping is done by creating a smaller groups from each term in the expression as shown;

18x² = (2*3*3* x²)

8 =  2*2*2

18x²-8 = (2*3*3* x²) - (2*2*2)

Step 2: Then we will factor out the greatest common factor (GCF) in the expression. GCF is the value that is common to both terms of the expression. The only common term in this case is 2.

Answer:

Factor out the GCF, and Use the difference of squares rule.

Step-by-step explanation:

The terms in the expression have a common factor of 2, so the first step is to factor out the GCF:

2(9x2 − 4).

Then, factor the remaining expression using the difference of squares rule.

Which of following equations are identities. Check all that apply.
A. csc x = 1/sin x
B. tan x = 1/sec x
C. sec x = 1/csc x
D. tan x = sin x/cos x

Answers

Answer: its A and D

Step-by-step explanation:

Ape x

The trigonometric identities are (csc x = 1/sinx ) and ( tan x = sin x/cos x ). Hence, option A and option D are correct.

What is trigonometry?

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

The trigonometric identities are ( csc x = 1/sinx ) and  ( tan x = sin x/cos x ). The other two options are incorrect. The correct values for the other two options are tan x = 1/cot x and sec x = 1/cos x.

Hence, option A and option D are correct.

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If 75 g of active ingredient powder is mixed with 400 mL NS solution, what is the final concentration? Round to the nearest hundredths (w/v).

Answers

75g/400ml: Simplify per unit

÷ by bottom.

0.1875g/ml nearest hundredth

0.19g/ml

Sugar canes have lengths X that are normally distributed with mean 365.45 cm and standard deviation 4.9 cm what is the probability of the length of a randomly selected Cane being between 360 and 370 cm

Answers

Answer:

The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851

Step-by-step explanation:

step(i):-

Let 'X' be the random Normal variable

mean of the Population = 365.45

Standard deviation of the population = 4.9 cm

Let X₁ =  360

[tex]Z= \frac{x-mean}{S.D}= \frac{360-365.45}{4.9}[/tex]

Z₁ = -1.112

Let X₂ =  370

[tex]Z= \frac{x-mean}{S.D}= \frac{370-365.45}{4.9}[/tex]

Z₂ = 0.911

Step(ii):-

The probability of the length of a randomly selected Cane being between 360 and 370 cm

                  P(x₁≤x≤x₂) =    P(z₁≤Z≤z₂)

               P(360 ≤X≤370)   =    P(-1.11≤Z≤0.911)

                                     =    P(Z≤0.911)-P(Z≤-1.11)

                                     =   0.5 +A(0.911) - (0.5-A(1.11)

                                       =    0.5 +A(0.911) - 0.5+A(1.11)

                                      =     A(0.911) + A(1.11)

                                    =    0.3186 + 0.3665

                                     = 0.6851

The probability of the length of a randomly selected Cane being between 360 and 370 cm  P(360 ≤X≤370)    = 0.6851

Select all of the following that are quadratic equations.​

Answers

Answer:

x^2 -2x = 4x+1

2x^2 +12x = 0

9x^2 +6x -3=0

Step-by-step explanation:

A quadratic equation has the highest power of x being squared

x^2 -2x = 4x+1

2x^2 +12x = 0

9x^2 +6x -3=0

These are all quadratic equations

What is the answer? Evaluate.

Answers

It could be possibly 2/8 but when multiplying it could be 3/4 I would think

The area of trapezoid TRAP is 100. Furthermore, TR=32, AP=8, and TP=RA. If

Answers

Answer:

  TP = 13

Step-by-step explanation:

The height of the trapezoid can be found from the area formula:

  A = (1/2)(b1 +b2)h

  h = 2A/(b1 +b2) = 2(100)/(32 +8)

  h = 5

The horizontal length of each triangular end of the trapezoid is ...

  (32 -8)/2 = 24/2 = 12

so the hypotenuse of the triangular end of the trapezoid is ...

  TP = √(12^2 +5^2) = √169

  TP = 13

The sides of the trapezoid have length 13 units.

A line is parallel to y = 3x + 8 and
intersects the point (-3, 7). What is the
equation of this parallel line?
y = [?]X + [ ]

Answers

Answer:

y= 3x+16

Step-by-step explanation:

y = 3x + 8 ║ y= mx +b

Since lines are parallel, m=3

y= 3x+b

(-3, 7) intersect

7= 3*(-3) + bb= 7+9b= 16

y= 3x+16

Wind Mountain is an archaeological study area located in southwestern New Mexico. Potsherds are broken pieces of prehistoric Native American clay vessels. One type of painted ceramic vessel is called Mimbres classic black-on-white. At three different sites the number of such sherds was counted in local dwelling excavations.
Site I Site II Site III
51 47 33
45 19 57
32 9 62
19 18 28
25 28
57 22
35
Shall we reject or not reject the claim that there is no difference in population mean Mimbres classic black-on-white sherd counts for the three sites? Test given b807b7c2-a348-4cb7-8322-f58461059cce.GIF.
What is the level of significance?
a. 90%
b. 1%
c. 5%
d. 99%
e. 95%

Answers

Answer:

Step-by-step explanation:

Hello!

This is an example of an ANOVA hypothesis test, where you'll compare the population means of the number of broken Mimbres in three different excavation sites.

The variable of interest is

Y: Number of broken pieces of prehistoric Native American clay vessels, called Mimbres in an excavation site.

Factor: Site

Treatments: 1, 2, 3

You are asked to identify the level of significance of the test. This value is the probability of committing Type I error, that is, when you fail to reject a false null hypothesis and is always represented with the Greek letter alpha "α"

This level is determined by the researcher when he is designing the experiment and statistical analysis. Normally you'd want this level to be as small as possible to be sure you didn't commit any mistake when deciding over the hypotheses.

The mos common values are 0.01, 0.05 or 0.1 and it can also be expressed as percentages 1%, 5% or 10%. Having a probability of making a mistake greater than 10% is too high so normally you would not encounter significance levels greater than 10%

With this in mind options b. 1% and c. 5% are valid values for α.

Have a nice day!

Next time check that all the information is copied!

Can someone please help? :)

Answers

Solution,

Diameter (d)=24 cm

Radius (r)=24/2 =12 cm

Circumference of circle= 2 pi r

=2*3.14*12

= 75.36 cm

Hope it helps

Good luck on your assignment

Answer:

[tex]c = 75.36cm[/tex]

Step-by-step explanation:

[tex]d = 2r \\ 24 = 2r \\ \frac{24}{2} = \frac{2r}{2} \\ r = 12cm[/tex]

[tex]circumference \\ = 2\pi \: r \\ = 2 \times 3.14 \times 12 \\ = 75.36cm[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

The dimensions of a triangular pyramid are shown below. The height of the pyramid is 6 inches. What is the volume in cubic inches? 1 point

Answers

Answer:

[tex]V=\frac{1}{3}(2.5)(6)=5 \ in^{3}[/tex]

The volume of the pyramid is 5 cubic inches.

Step-by-step explanation:

Assuming that the triangle base dimensions are 1 inche and 5 inches, and the height of the pyramid is 6 inches, the volume would be

[tex]V=\frac{1}{3}Bh[/tex]

Where B is the area of the base (triangle) and h is the height.

[tex]B=\frac{1}{2}bh =\frac{1}{2}(1)(5)=2.5 \ in^{2}[/tex]

Then,

[tex]V=\frac{1}{3}(2.5)(6)=5 \ in^{3}[/tex]

Therefore, the volume of the pyramid is 5 cubic inches.

Find the length of the hypotenuse. 45 degree triangle 3 square root of

2

Answers

Answer:

Hypotenuse = 6

Step-by-step explanation:

Find attached diagram used in solving the question.

The triangle is a 45°-45°-90° triangle meaning it's two legs are equal. The opposite = adjacent

Since we are told to find hypotenuse, it means the length given = opposite = adjacent = 3√2

Hypotenuse ² = opposite ² + adjacent ²

Hypotenuse ² = (3√2)² + (3√2)²

Hypotenuse ² = 9(2)+9(2) = 18+18

Hypotenuse ² = 36

Hypotenuse = √36

Hypotenuse = 6

need!!!!!!!!!!!help!!!!!!Asap!!!!!!​

Answers

Answer:

225 feet below sea level (or -225 feet)

Step-by-step explanation:

My apologies in advance if this does not format the way its supposed to. The way I did it includes arrows and may work best on a computer.

Problem: A submarine that is 245 feet below sea level descends 83 feet and then ascends 103 feet. Which represents the location of the submarine compared to sea level.

Math: Ok, so we know that whenever something descends, that means it is going down, so let's use a negative sign. These means when something ascends, it goes up. Let's use a positive sign here. Also, note the fact that we start 245 feet below sea level. This means we should start at -245.

Now, using the data we have, let's create a math problem.

A submarine that is 245 feet below sea level descends 83 feet and then ascends 103 feet. Which represents the location of the submarine compared to sea level.

-245      <---- beginning level

-83        <---- the submarine descends

+103      <---- the submarine ascends

_______

?

So grab a calculator to do this part, or do it on your own. Once you finish, plug in the answer.

-245                                                   -245

-83                                                     -83

+103                             --------------->  +103

______                                          ________

?                                                      -225 feet

So as you can see, the final answer would be -225 feet or 225 feet below sea level.

Hope this helped! Have a great day!

Mary crocheted a rectangular blanket whose diagonal measures approximately 7.21 feet. What are the most likely length and width measurements of the blanket ? Select the two correct answers.

Answers

Answer:

If both sides are integers, one side will be 4 feet and the other will be 6 feet. The other solution is the symmetrical solution (4 feet instead of 6 feet, and 6 feet instead of 4 feet).

Step-by-step explanation:

We have a rectangular blanket, that has a diagonal that measures h=7.21 feet.

The two sides of the rectangle a and b can be related to the diagonal h by the Pithagorean theorem:

[tex]a^2+b^2=h^2[/tex]

Then, we can express one side in function of the other as:

[tex]a^2+b^2=h^2\\\\a^2=h^2-b^2\\\\a=\sqrt{h^2-b^2}=\sqrt{7.21-b^2}=\sqrt{52-b^2}[/tex]

Then, if we define b, we get the value of a that satisfies the equation.

A graph of values of a and b is attached.

If both side a and b are integers, we can see in the graph that are only two solutions: (b=4, a=6) and (a=4, b=6).

The scatter plot below shows one class of Spanish students’ time spent studying for their final versus the grade that they earned on the final. If a student studies for 75 minutes, what is the best estimate for his or her grade?


A.100
B.90
C.45
D.75

Answers

I think is C I’m not sure

Use each number only once. Add, subtract multiply, or divide to get an awnser of 3. Use all numbers, show your work

8,6,5,9,1

Answers

Answer:

these are my answers:

8-5=3

2÷6=3

5-2=3

2+1=3

3÷9=3

Answer:

  9 +6 +1 -8 -5 = 3

Step-by-step explanation:

There are numerous possibilities. Among them are ...

  9 +6 +1 -8 -5 = 3

  (9-5)·1·6/8 = 3

  (9·8)/(6·(5-1)) = 3

PLEASE HELP ITS URGENT! 20 POINTS WORTH (basic inverse function question)

Answers

Answer:I believe the answer is -1,-4 lies on the graph

Step-by-step explanation:

Write a differential equation that is a mathematical model of the situation described. The time rate of change in the temperature T of coffee is proportional to the difference between the fixed temperature M of the air at time t and the temperature of the coffee at time t. The differential​ equation, with proportionality constant​ k, is nothing.

Answers

how to read pathater in himdi

Round 954 to the nearest hundred.

Answers

Answer:

1000

Step-by-step explanation:

5 or more add one more

4 or less let it rest

so it becomes 1000

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2, y2 = y1(x) e−∫P(x) dx y 2 1 (x) dx (5) as instructed, to find a second solution y2(x). x2y'' + 2xy' − 6y = 0; y1 = x2

Answers

Here is the right and correct question:

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2,

[tex]y_2 = y_1 (x) \int\limits \dfrac{e ^{-\int\limits P(x) dx} }{y^2_1 (x)} dx \ \ \ \ \ (5)[/tex]

as instructed, to find a second solution [tex]y_2(x)[/tex]

[tex](1-2x-x^2)y''+2(1+x)y' -2y =0; \ \ \ y_1=x+1[/tex]

Answer:

[tex]y_2 = -2-x^2-x[/tex]

Step-by-step explanation:

Let take a look at the differential equation:

[tex](1-2x-x^2)y''+2(1+x)y' -2y =0[/tex]

So; [tex]y''+ \dfrac{2(1+x)}{(1-2x-x^2)}y' - \dfrac{2}{(1-2x-x^2)}y =0[/tex]

where;

[tex]P(x) = \dfrac{2(1+x)}{(1-2x-x^2)}[/tex]     ;

Also:

[tex]Q(x) = \dfrac{-2}{(1-2x-x^2)}[/tex]

The task is to find the value of [tex]y_2(x)[/tex] by using the reduction formula [tex]y_2 = y_1 (x) \int\limits \dfrac{e^{-\int\limits P(x) dx }}{y_1^2(x)}dx[/tex]  such that [tex]y_1(x) =x+1[/tex]

simplifying [tex]y_2 = y_1 (x) \int\limits \dfrac{e^{-\int\limits P(x) dx }}{y_1^2(x)}dx[/tex] ;we have:

[tex]y_2 =(x+1) \int\limits \dfrac{e ^{-\int\limits \frac{2(1+x)}{(1-2x-x^2)}}}{(x+1)^2} \ \ dx[/tex]

[tex]y_2 =(x+1) \int\limits \dfrac{e ^{\int\limits \frac{-2(1+x)}{(1-2x-x^2)}}}{(x+1)^2} \ \ dx[/tex]

[tex]y_2 =(x+1) \int\limits \dfrac{e^{In(1-2x-x^2)}}{(x+1)^2}\ \ dx[/tex]

[tex]y_2 =(x+1) \int\limits \dfrac{(1-2x-x^2)}{(x+1)^2} \ \ dx[/tex]

[tex]y_2 =(x+1) \int\limits \dfrac{1}{(x+1)^2}-\dfrac{2x}{(x+1)^2}- \dfrac{x^2}{(x+1)^2} \ \ dx[/tex]

Let assume that [tex]I_1[/tex] = [tex]\int\limits \dfrac{-2x}{(x+1)^2} \ \ dx[/tex]

[tex]= \int\limits \dfrac{-(2x+2-2) }{(x+1)^2} \ \ dx[/tex]

[tex]= \int\limits \dfrac{-(2x+2) }{(x+1)^2} + \dfrac{2}{(x+1)^2} \ \ dx[/tex]

[tex]=- In(x+1)^2 - \dfrac{2}{(x+1)}[/tex]

Also : Let [tex]I_2 = \int\limits \dfrac{x^2}{(x+1)^2} \ \ dx[/tex]

[tex]= \int\limits \dfrac{(x+1-1)^2}{(x+1)^2} \ \ dx[/tex]

[tex]= \int\limits \dfrac{(x+1)^2+1-2(x+1)}{(x+1)^2} \ \ dx[/tex]

[tex]= \int\limits \ 1 + \dfrac{1}{(x+1)^2}- \dfrac{2}{(x+1)} \ \ dx[/tex]

[tex]= x - \dfrac{1}{(x+1)}- 2 \ In (x+1)[/tex]

Replacing the value of [tex]I_1[/tex] and [tex]I_2[/tex] in the  equation

[tex]y_2 =(x+1) \int\limits \dfrac{1}{(x+1)^2}-\dfrac{2x}{(x+1)^2}- \dfrac{x^2}{(x+1)^2} \ \ dx[/tex]

[tex]y_2 =(x+1) [ \ \int\limits \dfrac{-1}{(x+1)}+ (-In(x+1)^2-\dfrac{2}{(x+1)})-(x-\dfrac{1}{(x+1)}-2 In(x+1))][/tex]

[tex]y_2 =(x+1) [ \ \int\limits \dfrac{-1}{(x+1)}- In(x+1)^2-\dfrac{2}{(x+1)}-x+\dfrac{1}{(x+1)}+2 In(x+1))][/tex]

[tex]y_2 =(x+1) [ \ \int\limits \dfrac{-1}{(x+1)}- 2In(x+1) -\dfrac{2}{(x+1)}-x + \dfrac{1}{(x+1)} +2 In(x+1)][/tex]

[tex]y_2 = -2-x(x+1)[/tex]

Therefore;

[tex]y_2 = -2-x^2-x[/tex]

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