Answer:
10 squirrels/ square mile
Explanation:
Population density can be found by dividing the number of individuals by the area of the land they live in.
population/ land area
We want to find the population density for 40 squirrels that live in 4 square miles. Therefore, the population is 40 squirrels and the area of the land is 4 square miles.
population / land area
40 squirrel/ 4 square miles
Divide 40 by 4
40/4=10
10 squirrels/ square mile
The population density is 10 squirrels per square mile.
2. Why is variety in offspring so important?
Answer:
Important to Darwinian Evolution
Explanation:
Some traits in the offspring will be more useful than others. Because of Natural Selection, the offspring with the more favored traits are more likely to reproduce and pass on their genes.
Anna said that mosquitoes causes malaria
Why is she wrong?
Anyone that answers I will mark as brilliant
Answer:
But, what if the chances of anyone finding out that he has seen the answers are ... on other students will be, or whether he will go on to a brilliant medical career.
Explanation:
In what phase do the organelles disperse out into the daughter cells, and the cell prepares for cytokinesis?
1. Prophase
2. Interphase
3. Mitosis
4. Telophase
1. Which of the following statements explains how N-formylmethionine (fMet) is incorporated only in response to the 5'-AUG initiation codon in E. coli, given that methionine has only one codon?
A. Methionine is only ever found as the first amino acid in a polypeptide
B. There is only one tRNA with the CAU anticodon.
C. Only Met-tRNAmCl can bind to a specific ribosomal entry site.
D. The N-formyl group on methionine prevents fMet from entering interior positions in a polypeptide.
E. fMet is always incorporated at interior AUG sites and then deformylated after translation.
2. Which of the following is not true of the second step of translational elongation in bacteria?
A. Puromycin inhibits translation by mimicking the 3' end of an aminoacyl-tRNA
B. The carboxyl group oxygen of the A-site amino acid is the nucleophile in peptide bond formation.
C. A peptide bond is formed between the two amino acids bound by the tRNAs in the A and P sites.
D. The growing polypeptide chain is transferred to the tRNA in the A site.
E. The a-amino group of the A-site amino acid attacks the carbonyl carbon of the P-site amino acid.
3. Which of the following is not a function of the release factors of bacterial translation termination'?
A. mediating the hydrolysis of the terminal peptidyl-tRNA bond
B. assisting in the initial folding of the nascent polypeptide chain
C. releasing the last uncharged tRNA from the P site
D. recognition of a stop codon
E. occupation of the ribosomal A site
4. Which of the following is NOT a possible outcome of the CRISPWCas9 system?
A. disruption of a gene
B. repair of a gene
C. deletion of a chromosome
D. blocking or enhancing gene expression
E. all of the above are possible
5. Which of the following is NOT true of the reaction catalyzed by RNA polymerases?
A. Template DNA is copied in the 3' to 5' direction.
B. The 3'-hydroxyl group of the growing RNA strand is the nucleophile.
C. The reaction is magnesium ion dependent.
D. U residues are incorporated into the RNA to pair with T residues of the template.
E. The RNA molecule is synthesized in the 5' to 3' direction.
6. The sequence of the messenger RNA molecule (primary transcript) synthesized from a DNA molecule with a template strand having the sequence 5'-ATGCTACCGTTA-3' is:
A. 5 '-UACGAUGGCAAU-3'
B. 5 '-UAACGGUAGCAU-3'
C. 5'-AUGCUACCGUUA-3'
D. 5'-AUUGCCAUCGUA-3'
E. None of these choices is correct
Answer: D. The N-formyl group on methionine prevents fMet from entering interior positions in a polypeptide.
Answer:
1) Option D (The N-formyl group on methionine prevents fMet from entering interior positions in a polypeptide)2) Option B (The carboxyl group oxygen of the A-site amino acid is the nucleophile in peptide bond formation)3) Option B (assisting in the initial folding of the nascent polypeptide chain)4) Option A (disruption of a gene)5) Option A (Template DNA is copied in the 3' to 5' direction)6) Option A (5 '-UACGAUGGCAAU-3')Explanation:
1) Option D(The N-formyl group on methionine prevents fMet from entering interior positions in a polypeptide)
2) Option B (The carboxyl group oxygen of the A-site amino acid is the nucleophile in peptide bond formation) is not responsible for the second part of the translation elongation in bacteria.
3) Option B (assisting in the initial folding of the nascent polypeptide chain) This is because the folding of the protein does not takes place in the ribosome. Afetr the binding of the release factor into the A site. the nascent peptide is released from the ribosomal complex. This nascent peptide is now present in the primary state and folding occur in secondary or tertiary state of the protein
4) Option A (disruption of a gene)
5) Option A (Template DNA is copied in the 3' to 5' direction) is wrong and not copied by the RNA polymerase. RNA polymerasze copy the Coding strands of the DNA in 3' to 5' direction
6) Option A (5 '-UACGAUGGCAAU-3') During transcrition of the RNA from the template DNA.is done by the enzyme RNA polymerase.
This RNA pol. copy the all the neucleotide from the coding strand of the DNA but replace Thymine by Uracil.
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Which describes the greenhouse effect
What are two examples of extreme weather on exoplanets?
Answer: rock rain on Corot-7b and diamond rain on saturn
Explanation:
The relative effectiveness of different wavelength of light in photosynthesis is demonstrated by:
A. An absorption spectrum C. Photolysis
B. Carbon fixation D. An action spectron
Answer:
D. An action spectrum
which of the following represents a testcross
A- t? x tt
B- XX x XY
C-T? x Tt
D- T? x TT
Answer:
The option should be like this:
A- T? x tt
Explanation:
In an inheritance pattern in which a particular allele is exhibiting doiminance over the other, the dominant phenotype can either be homozygous or heterozygous. Hence, it is impossible to tell the genotype of a dominant phenotype by merely observing it. A cross called TEST CROSS is used.
A test cross is a cross used to determine the actual genotype of a dominant phenotype i.e. whether it is homozygous or heterozygous by crossing tye unknown genotype with a homozygous recessive parent. If all of the offspring of this cross have a dominant phenotype, it means the dominant parent is HOMOZOGOUS but if offsprings with an equal ratio of dominant and recessive phenotypes are produced, it means the dominant parent is HETEROZYGOUS.
In this case, the dominant phenotype whose genotype is unknown is (T*) while the recessive parent will be (tt).
Answer:
a
Explanation:
Photosynthesis is the process by which plants and algae use energy from the sun to synthesize which of the following?
Photosynthesis takes within the CO2 produced by all breathing organisms and reintroduces oxygen into the atmosphere. Photosynthesis is that the process employed by plants, algae and certain bacteria to harness energy from sunlight and switch it into energy
The part of the atom that carries a positive charge is the _____, and the part that carries a neutral charge is the _____
Answer:
The first blank is proton and the second is neutron
Explanation:
A man with type AB blood is married to a woman with type O blood. They have two biological children, and one adopted child. The children’s blood types are: A, B, and O. Which child was adopted?
Answer:
The adopted child is the one with type O blood.
Explanation:
Available data:
A man with type AB blood is married to a woman with type O blood. They have two biological children and one adopted child.The man´s genotype for blood type is AB (Codominant type of blood) and the woman´s genotype for blood type is OO, as this type of blood is expressed by two recessive alleles.
Cross:
Parental) AB x OO
Gametes) A B O O
Punnet square) A B
O AO BO
O AO BO
F1) Half of the biological progeny will be AO and the other half BO.
There are no possibilities that any of the biological child could be OO. This means that the adopted child´s blood type is O and the biological children´s blood type are A and B.
alapogos tortoises have a number of shell variations, shown right. What are the advantages of choosing a system examining the beaks of finches instead of the shells of tortoises? Check all that apply. Birds have shorter lifespans, making generations shorter. The bird population is likely much greater, allowing for more data. Tortoises move too slowly for natural selection to influence shell phenotype. Birds are easier to track and monitor.
The question lacks essential part that is options to answer, however the options are given:
1. Birds have shorter lifespans, making generations shorter.
2. The bird population is likely much greater, allowing for more data.
3. Tortoises move too slowly for natural selection to influence shell phenotype.
4. Birds are easier to track and monitor.
Answer:
The correct options are : 1, 2, and 4.
Explanation:
For the accuracy and dependability of any experiment, various observations must be as extensive as possible. It decreases the impact of any observation or any event which may have occurred by some coincidence or mistake.
Therefore, finches were smarter to record observation as they were accessible in enormous numbers when compared with the turtle.
Likewise, the life cycle of birds is less when contrasted with the turtle which empowered the researchers to observe more generations.
In conclusion, the birds were anything but difficult to catch and track when contrasted with the turtle. Turtle is a land and water proficient which made it hard to follow them.
Answer:
noe. . g.aa.aaaaaaaaaaaaaaaaas
Explanation:
What is occurring when a transport protein uses energy to pump a solute against its gradient across a
cell membrane
Answer:
Active transportation
Explanation:
Active transportation is happening because energy is need to pump against the gradient. Whenever energy is used the transportation is active.
Chemical reactions convert ____________ to _____________. In nonliving systems, the presence of a(n) __________ allows the reaction to proceed very quickly and have a lower __________. In living systems, this function is carried out by proteins called _____________.
activation energy
catalyst
enzymes
products
reactants
Answer:
1-reactants 2=products 3=catalyst 4=activation energy 5=enzymes
Explanation:
Chemical reactions convert REACTANTS to PRODUCTS. In nonliving systems, the presence of a CATALYST allows the reaction to proceed very quickly and have lower ACTIVATION ENERGY. In living systems, this function is carried out by proteins called ENZYMES.
A reactant is a substance and/or compound which is added to the system in order to produce a particular chemical reaction, thereby being present in the system before the reaction takes place.A product of a chemical reaction is any substance and/or chemical compound which is formed after the reaction.A catalyst is a substance that increases the rate of a particular chemical reaction, thereby lowering the activation energy of the reaction.An enzyme is a biological catalyst that is capable of lowering the activation energy for a chemical reaction.Enzymes generally are proteins, but they can also be composed of RNA molecules (i.e., ribozymes).In conclusion, chemical reactions convert REACTANTS to PRODUCTS. In nonliving systems, the presence of a CATALYST allows the reaction to proceed very quickly and have lower ACTIVATION ENERGY. In living systems, this function is carried out by proteins called ENZYMES.
Which is a density-independent factor in controlling a population? A. Floods B. Access to light C. Water supply D. Predators
Describe the difference between organic and inorganic carbon.
You have a strain of bacteria that is defective for DNA glycosylase activity. You expose one culture of this strain to EMS and the other to cisplatin (a chemotherapy drug that creates bulky adducts on purine bases). You notice that the cisplatin is much more toxic to this mutant strain of bacteria than is the EMS. Explain your observation.
Answer:
Bacteria under successive rounds of selection may acquire genetic resistance to the treatment with mutagenic compounds including ethyl methanesulfonate (EMS).
Explanation:
Artificial selection is a process known to generate resistance of the organisms under treatment. For example, this type of selection has been reported to generate resistance to the treatment with different chemical compounds including mutagenic chemical compounds (in this case EMS), antibiotic drugs, etc.
Which is a characteristic of pseudoscience?
Answer:
Pseudoscience is often characterized by contradictory, exaggerated or unfalsifiable claims; reliance on confirmation bias rather than rigorous attempts at refutation; lack of openness to evaluation by other experts; absence of systematic practices when developing hypotheses; and continued adherence long after the pseudoscientific hypotheses have been experimentally discredited.
Explanation:
The mature ovary of a plant is a _____.
· pistil
· flower
· fruit
· seed
Answer:
The matured ovary of a plant is a seed.
What observation led researchers to propose that chloroplasts evolved from cyanobacteria?
both produce proteins
both contain mitochondria
both provide structure to cells
both preform photosynthesis
Answer:
Both perform photosynthesis.
Explanation:
Both perform photosynthesis led researchers to propose that Chloroplast evolved from Cyanobacteria.
Chloroplast is a organelle that contain the green pigment called chlorophyii which perform photosynthesis. This is found in both plant cell and algae cell. This trap light energy from sunlight and uses carbondioxide with water to produce sugar.
Cyanobacteria are known to be the ancestor of chloroplast and they are also refer to as blue green algae because they contain chlorophyii which is a photosynthetic pigment. The Cyanobacteria are able to perform photosynthesis because of chlorophyii which trap light energy from sunlight and uses carbondioxide and water to produce energy.
Answer:
D.
Explanation:
be
_________6. The molecule of which pigment is located at the reaction center of a photosystem?
A. Accessory pigments C. Chloprophyll b
B. Carotenoid D. Chlorophyll a
Answer:
D. Chlorophyll a
Explanation:
lucky you, had same quiz.
Which substance reduces the level of acid in blood?
sodium
bicarbonate
urea
nitrogen
Answer:
Bicarbonate
Explanation:
What makes a molecule a carbohydrate?
You conduct a series of two-point mapping crosses involving five genes located on chromosome III and obtain the following percentage of recombinant offspring:
h-cu eyg-h eyg-cu rai-eyg rai-h rai-cu th-cu th-h th-eyg th-rai
23.5% 9.0% 14.5% 18.5% 9.5% 33.0% 6.8% 16.7% 7.7% 26.2%
Considering that rai is near the end of chromosome III, construct a map of these genes. Drag gene names to blue targets and map distances to pink targets.
a. 6.8
b. 7.7
c. 9.0
d. 9.5
1. cu
2. eyg
3. h
4. th
1. The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila. Phenotypically wild-type females (m+g / mg+) were mated to miniature-winged males with garnet eyes (mg / mg). Which of the following phenotypic classes reflect offspring that were generated as a result of a crossover event?
a. miniature wings,
b. wild-type eyesminiature wings,
c. garnet eyeswild-type wings,
d. garnet eyeswild-type wings,
e. wild-type eyes
2. If 800 offspring were produced from the cross, in what numbers would you expect the following phenotypes?
a. wild-type wings, wild-type eyes :_____.
b. miniature wings, wild-type eyes :_____.
c. wild-type wings, garnet eyes :_____.
d. miniature wings, garnet eyes:_____.
Answer:
I am not a doctor
Explanation:
I am sorry
How could a tropical storm affect you personally?
Answer:
it can stress you out because of the danger you're in
PLEASEEE HELP!
Which method involves using tools to control invasive species?
a. Mechanical
b. Chemical
c. Manual
d. Monitoring
Answer:
sorry if i get this wrong d. Monitoring
Answer:
A. Mechanical
Explanation:
what features of meiosis are important in sexual reproduction
Answer:
The daughter cells are identical to the mother cell in shape and size but different in chromosome number. The daughter cells are haploid. Recombination and segregation take place in meiosis. The process occurs in the reproductive organs and results in the formation of gametes.
Explanation:
During sexual reproduction, meiosis generates genetic variation in offspring because the process randomly shuffles genes across chromosomes and then randomly separates half of those chromosomes into each gamete. The two gametes then randomly fuse to form a new organism.
during drought years on the galapagos,small easily eaten seeds become rare, leaving mostly large, hard-cased seeds that only birds with large beaks can eat. if drought continues for several years, measurable changes to the beak size of the galapagos bird population can be observed. which of the following identifies the changes to the beak size of the galapagos bird population what would most likely be expected as a result of natural selection? a) more small-beaked birds dying than larger beaked birds. the offspring produced in later generations have a higher percentage of birds with large beaks. b) small birds gaining larger beaks by exercising their mouth parts c) small birds mutating their beak genes resulting in later-generation offspring having larger beaks d) small birds anticipating the long drought and eating more to gain weight, resulting in them growing larger beaks
Answer:
A) More small-beaked birds dying than larger beaked birds
Explanation:
Natural selection will cause the small-beaked birds to die, while large-beaked birds will begin producing more birds with that gene. This causes large-beaked birds to become dominant, and less and less small-beaked birds will survive.
Hope this helps!
Answer:
A.
Explanation:
Considering that the seeds have changed to where larger birds can only consume them (or birds with larger beaks, anyways..) then smaller beaked birds would die or as a result of the changing in the food supply.If the food supply revolves around having a stronger or larger beak, then birds with larger beaks are more likely to flourish.
Question 1
The gaining of electrons from an atom or molecule is an example of:
reduction
a.
b.
adhesion
O c. capillarity
d.
cohesion
oxidation
e.
Answer:
a. reduction
Explanation:
The reduction is an example of the gaining of electrons from an atom or molecule or the loss of oxygen atom from a molecule.
Oxidation and reduction always occur together so in oxidation electrons loss by one substance is fulfil by gaining electrons in reduction process.
For example: The copper ion form copper by gaining electrons and undergoing reduction.
Hence, the correct answer is a. Reduction.
An experiment that
a hypothesis will often provide a new direction for the researcher.
Answer:
fails to verify
Explanation:
An experiment that fails to verify a hypothesis will often provide a new direction for the researcher.
Researchers conduct experiments to develop hypotheses. A hypothesis is a testable and falsifiable explanation. A hypothesis can be tested. It is possible to prove the hypothesis as true or false.
An experiment is a way to test the hypothesis.
