Para el periódico mural, los alumnos decidieron representar un pino por medio de un triángulo que tiene una superficie de 1. 5m si la base mide 1. 5 m ¿cuanto mide la altura? 

Answer:

68in

Step-by-step explanation:

square: 3x3=9

9+9= 18

trapezoid (centre area) : 7x3x5=25

25x2=50

50+18=68

not entirely sure abt this

The slope and y intercept of the graph of function h is2 and 9.5, respectively.

To find the slope and y-intercept of the function h(x), we'll first find g(x) and then h(x) by substituting f(x) and the given transformations.

1. g(x) = f(x - 3): Substitute (x - 3) for x in f(x)
g(x) = -1/2(x - 3) + 8

2. h(x) = g(-4x): Substitute (-4x) for x in g(x)
h(x) = -1/2(-4x - 3) + 8

Now we have the function h(x), and we can identify the slope and y-intercept:

h(x) = -1/2(-4x - 3) + 8
h(x) = 2x - 1/2(-3) + 8

The slope is the coefficient of x, which is 2, and the y-intercept is the constant term, which is 1.5 + 8 = 9.5. So, the slope is 2, and the y-intercept is 6.5.

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The total area of the soccer field is approximately 8150 square yards.

We'll find the total area of the soccer field in square meters first, and then convert it to square yards using the conversion factor provided.

Find the area in square meters (m²):
Area = Length × Width
Area = 102.9 m × 66.3 m
Area ≈ 6816.47 m²

Convert the area to square yards (yd²):
Use the conversion factor: 1 yard = 0.9144 meters
1 m² = (1/0.9144)² yd²
1 m² ≈ 1.19599 yd²
Now, multiply the area in m² by the conversion factor to get the area in yd²:
Area ≈ 6816.47 m² × 1.19599 yd²/m²
Area ≈ 8150 yd² (rounded to the nearest whole number).

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The initial volume of the solution in container Q is 1.6 liters.

Let's first discover how a lot solution was poured from container Q into container P:

0.4 x volume of solution in container Q = 0.4Q

the total volume of solution in container P after this transfer is:

800 ml + 0.4Q ml

Subsequent, 3/8 of this overall volume in container P is poured into container R:

(3/eight) x (800 ml + 0.4Q ml) = 300 ml + 0.15Q ml

We recognise that field R includes 540 ml of solution now, so we are able to set up an equation:

300 ml + 0.15Q ml = 540 ml

Solving for Q, we get:

0.15Q ml = 240 ml

Q = 1600 ml

Consequently, the initial volume of the solution in container Q is 1.6 liters.

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56 members will weigh 166 pounds or more. The closest answer choice is: A. 67

We'll use the concepts of normal distribution, z-scores, and a z-table. Follow these steps:

1. Calculate the z-score for 166 pounds using the formula: z = (X - μ) / σ
  where X = 166 pounds, μ = mean (176 pounds), and σ = standard deviation (114 pounds)

  z = (166 - 176) / 114 = -10 / 114 ≈ -0.088

2. Look up the corresponding probability for the z-score in a z-table.
  For a z-score of -0.088, the probability is approximately 0.535.

3. Since we want to know how many members weigh 166 pounds or more, we need to find the proportion of members in the upper tail of the distribution. To do this, subtract the probability found in the z-table from 1:

  1 - 0.535 = 0.465

4. Multiply the proportion by the total number of members (120) to find the number of members weighing 166 pounds or more:

  0.465 * 120 ≈ 56

However, none of the provided answer choices matches this result. Please check the question for any typos or errors. If the question's parameters are correct, the closest answer choice is: A. 67

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The probability of sample mean less than 3.1 pounds: 0.266. The correct option is C.

The weights of roasts are normally distributed with a mean of 3.2 pounds and a standard deviation of 0.8 pounds. In a sample of 25 roasts, we want to find the probability that the sample mean is less than 3.1 pounds.

First, we need to calculate the standard error of the mean, which is the standard deviation divided by the square root of the sample size:

Standard error = 0.8 / √25 = 0.8 / 5 = 0.16

Now, we need to calculate the z-score for the sample mean of 3.1 pounds:

Z = (Sample mean - Population mean) / Standard error = (3.1 - 3.2) / 0.16 = -0.1 / 0.16 = -0.625

Using a z-table or calculator, we find the probability associated with a z-score of -0.625:

P(Z < -0.625) ≈ 0.266

Therefore, the probability of the sample mean being less than 3.1 pounds is approximately 0.266, which corresponds to option C.

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Complete question:

The owner of a meat market has an assistant who has determined that the weights of roasts are normally distributed, with a mean of 3.2 pounds and a standard deviation of 0.8 pounds. For a sample of 25 roasts, what is the probability of sample mean less than 3.1 pounds?

a. 0.495

b. 0.450

c. 0.266

d. 0.521

Advertising cricket bats in a national newspaper provides Sachin's business with increased brand visibility and reach, while also posing a potential disadvantage due to high advertising costs.

One advantage and one disadvantage of Sachin's business advertising cricket bats in a national newspaper are as follows:

Advantage: Increased brand visibility and reach.

By advertising in a national newspaper, Sachin's business can reach a wider audience, creating greater brand awareness among potential customers. This increased visibility can contribute to the rapid increase in demand for cricket bats, ultimately leading to higher sales and profits for the business.

Disadvantage: High advertising cost.

National newspaper advertising can be quite expensive, especially for a business that advertises every two weeks. The high advertising costs might put financial pressure on Sachin's business, which could potentially affect other aspects of the business operations, such as product quality or employee wages. It's important for Sachin to weigh the benefits of national newspaper advertising against its costs to determine the most effective marketing strategy.

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Answer: H = 5

the equation would be, 35h - 25 = $200

Step-by-step explanation:

Based on the trend line and slope, Tony's expected salary of $70,000 after 15 years of employment at Company Z is reasonable, as it falls within the range of salaries predicted by the line of best fit.

First, we need to find the equation of the trend line. To do this, we use the least squares regression method to find the line that best fits the data. Let x be the years of employment and y be the annual salary. We can calculate the slope and y-intercept of the trend line using the following formulas

slope = (nΣ(xy) - ΣxΣy) / (nΣ(x²) - (Σx)²)

y-intercept = (Σy - slopeΣx) / n

where n is the number of data points, Σ represents the sum of, and ( )² denotes squared.

We can use the given data to calculate the values needed for the formulas. Let's denote the years of employment as x and the annual salary as y.

x: 1 2 3 4 5 6

y: 45 50 55 60 65 70

n = 6

Σx = 1 + 2 + 3 + 4 + 5 + 6 = 21

Σy = 45 + 50 + 55 + 60 + 65 + 70 = 345

Σxy = (145) + (250) + (355) + (460) + (565) + (670) = 1305

Σ(x²) = 1² + 2² + 3² + 4² + 5² + 6² = 91

Now we can plug these values into the formulas to find the slope and y-intercept

slope = (61305 - 21345) / (691 - 21²) = 5

y-intercept = (345 - 521) / 6 = 20

We can write the equation of the trend line in the form y = mx + b, where m is the slope and b is the y-intercept

y = 5x + 20

Finally, we can use this equation to estimate Tony's salary after 15 years of employment

y = 5(15) + 20 = 95

Based on the trend line and slope, we would expect Tony's salary to be about $95,000 after 15 years of employment.

This is higher than his expected salary of $70,000, so it may not be a reasonable expectation. However, it's important to note that the trend line is just an approximation and there may be other factors that could affect Tony's salary.

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Tank B fills faster than Tank A, taking approximately 1.75 minutes to fill while Tank A takes approximately 1.14 minutes.

The problem presents two aquarium tanks, A and B, which are of the same size but have different water levels and fill rates. Tank A has 2 feet of water and is being filled at a rate of 2.2 inches per minute, while Tank B has 8 feet of water and is being filled at a faster rate of 5 inches per minute. The goal is to determine how long it will take to fill each tank.

To solve this problem, we need to use the formula: Time = Volume / Rate. We know that the volume of each tank is the same, so we can set up two equations:

For Tank A: Time = (2 feet * 12 inches/foot) / 2.2 inches/minute = 10.91 minutes or approximately 1.14 minutes.

For Tank B: Time = (8 feet * 12 inches/foot) / 5 inches/minute = 19.2 minutes or approximately 1.75 minutes.

Therefore, Tank A will take approximately 1.14 minutes to fill, while Tank B will take approximately 1.75 minutes to fill. It is important to note that Tank B is being filled at a faster rate than Tank A, despite having a greater volume of water.

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The main difference is that Sierra needs to create two equal arcs, while Keaton needs to create six equal arcs to form the vertices of their respective shapes.

For Sierra's inscribed square:
1. Draw a circle with a compass.
2. Mark a point on the circle as one vertex of the square.
3. Draw a diameter passing through the marked point.
4. Use the compass to create two equal arcs, one on each end of the diameter, intersecting the circle.
5. Connect the intersection points to create the square.

For Keaton's inscribed regular hexagon:
1. Draw a circle with a compass.
2. Mark a point on the circle as one vertex of the hexagon.
3. Use the compass to create six equal arcs around the circle, each arc intersecting the end of the previous arc.
4. Connect the intersection points to create the hexagon.

The main difference is that Sierra needs to create two equal arcs, while Keaton needs to create six equal arcs to form the vertices of their respective shapes.

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The equation would be written as: y = $85,000(1 + 0.12/1)^5

Then the predicted earning would be y = $132,559

y=a(b)x

where y = income

a =  $85,000

b = (1 + r = percent increase)

then x = time period = 5 years

When we put in the values we would have y = $85,000(1 + 0.12/1) ^5

The exponential function of the form y = a(b)^x is: y = $85,000(1 + 0.12/1) ^5

When we solve the above, we would have the income = y = $132,559

Therefore the predicted earnings that Dans small business would have in a period of five years is equal to $132,559

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There are 4 possible sets of dimensions for the cuboid with a volume of 1815 cm³.

First, find the prime factors of 1815:

1815 = 3 × 5 × 11 × 11

Now, we need to find all possible combinations of these factors into three whole numbers. Each combination of three numbers, when multiplied, should give 1815. We can do this by finding the different ways the prime factors can be distributed among the three dimensions:

3 × 5 × (11 × 11) = 15 × 121 (height × width × length)

3 × 11 × (5 × 11) = 33 × 55

5 × 11 × (3 × 11) = 55 × 33

11 × 11 × (3 × 5) = 121 × 15

We have found 4 different sets of dimensions for the cuboid:

15 × 121 × 1

33 × 55 × 1

55 × 33 × 1

121 × 15 × 1

There are 4 possible sets of dimensions for the cuboid with a volume of 1815 cm³.

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By the end of 12 months, Claire will need 1,596,018 pens to house all the rabbits.

The number of adult rabbits in each month is the sum of the adult rabbits from the previous month and the number of baby rabbits that have grown to adulthood.

The number of baby rabbits in each month is the product of the number of adult rabbits in the previous month and the number of kits each pair of rabbits produces (6 in this case).

The total number of rabbits is simply the sum of the number of adult rabbits and the number of baby rabbits. Finally, the minimum pen size needed is found by divide the total number of rabbits by 2 (since each rabbit needs 2 square feet of space).

Month 1

Beginning of month: 2 rabbits (1 male, 1 female)

End of month: 8 rabbits (3 males, 5 females)

Number of pens needed: 16 square feet / 2 square feet per pen = 8 pens

Month 2

Beginning of month: 8 rabbits (3 males, 5 females)

End of month: 26 rabbits (11 males, 15 females)

Number of pens needed: 52 square feet / 2 square feet per pen = 26 pens

Month 3

Beginning of month: 26 rabbits (11 males, 15 females)

End of month: 80 rabbits (35 males, 45 females)

Number of pens needed: 160 square feet / 2 square feet per pen = 80 pens

Month 4

Beginning of month: 80 rabbits (35 males, 45 females)

End of month: 242 rabbits (105 males, 137 females)

Number of pens needed: 484 square feet / 2 square feet per pen = 242 pens

Month 5

Beginning of month: 242 rabbits (105 males, 137 females)

End of month: 728 rabbits (315 males, 413 females)

Number of pens needed: 1456 square feet / 2 square feet per pen = 728 pens

Month 6

Beginning of month: 728 rabbits (315 males, 413 females)

End of month: 2186 rabbits (945 males, 1241 females)

Number of pens needed: 4372 square feet / 2 square feet per pen = 2186 pens

Now, to continue for the next 6 months

Month 7

Beginning of month: 2186 rabbits (945 males, 1241 females)

End of month: 6568 rabbits (2835 males, 3733 females)

Number of pens needed: 13136 square feet / 2 square feet per pen = 6568 pens

Month 8

Beginning of month: 6568 rabbits (2835 males, 3733 females)

End of month: 19702 rabbits (8499 males, 11203 females)

Number of pens needed: 39404 square feet / 2 square feet per pen = 19702 pens

Month 9

Beginning of month: 19702 rabbits (8499 males, 11203 females)

End of month: 59110 rabbits (25499 males, 33611 females)

Number of pens needed: 118220 square feet / 2 square feet per pen = 59110 pens

Month 10

Beginning of month: 59110 rabbits (25499 males, 33611 females)

End of month: 177334 rabbits (76535 males, 100799 females)

Number of pens needed: 354668 square feet / 2 square feet per pen = 177334 pens

Month 11

Beginning of month: 177334 rabbits (76535 males, 100799 females)

End of month: 532006 rabbits (229799 males, 302207 females)

Number of pens needed: 1064012 square feet / 2 square feet per pen = 532006 pens

Month 12

Beginning of month: 532006 rabbits (229799 males, 302207 females)

End of month: 1596018 rabbits (689397 males, 906621 females)

Number of pens needed: 3192036 square feet / 2 square feet per pen = 1596018 pens

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To add one number to each column of the table and make it show a function, we need the specific table or information about the columns to provide a precise answer.

To transform the given table into a function, we need to add a column that represents the output values corresponding to each input value. A function relates each input value to a unique output value.

Here is an example of how the table could be modified to represent a function:

Input (x) Output (y)

1             3

2               5

3             7

4            9

In this modified table, the output values (y) are obtained by adding 2 to each input value (x). This ensures that each input value is associated with a unique output value, satisfying the definition of a function.

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Answer:

Step-by-step explanation:

The best-supported statement by the information in the table is:

C. The fee at Bank K will always be greater than the fee at Bank F.

This is because for any given average daily balance, Bank K has a higher fee than Bank F. For example, for an average daily balance of less than $500, Bank F charges $8 while Bank K charges $12. Similarly, for an average daily balance between $500 and $750, Bank F charges no fee while Bank K charges $12. Therefore, the fee at Bank K will always be greater than the fee at Bank F.

In this carnival game, a player flips a coin that has a 3 on one side and a 7 on the other, and then rolls a number cube that has numbers 1-6.

To determine the probabilities, we need to analyze each event separately and then use the multiplication rule of probability to find the probability of both events happening together.

The probability of getting a 3 on the coin is 50%, since there are only two possible outcomes. The probability of rolling each number on the cube is 16.67%, since the cube has six sides.

The probability of both events happening together depends on the individual probabilities and is found by multiplying them. Finally, we can use the addition rule of probability to find the probability of either event happening.

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The coordinates for H’I’D’E’ after a reflection over the y-axis include the following:

H' (-1, 4).

I' (-2, -1).

D' (-4, -3).

D' (-5, 3).

In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

By applying a reflection over the y-axis to the coordinate of the given quadrilateral HIDE, we have the following coordinates:

(x, y)                             →                 (-x, y).

Coordinate H = (1, 4)   →  Coordinate H' = (-(1), 4) = (-1, 4).

Coordinate I = (2, -1)   →  Coordinate I' = (-(2), -1) = (-2, -1).

Coordinate D = (4, -3)   →  Coordinate D' = (-(4), -3) = (-4, -3).

Coordinate E = (5, 3)   →  Coordinate D' = (-(5), 3) = (-5, 3).

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Answer:

Function A: f(x) = -8^x

Function B: f(x) = 2^x

Function A has a greater horizontal asymptote. As x approaches negative infinity, Function A approaches y = 0 faster than Function B.

Answer:

425

Step-by-step explanation:

212,5*2=425

The dimensions of the cylinder that minimize the production cost are:

radius = approximately 2.78 cm

height = 600 / (πr^2) ≈ 7.14 cm

paper top radius = 2.5 cm

Let's start by finding the formula for the cost of the container in terms of its dimensions.

The volume of the cylinder is given as 600 cubic centimeters, so we have:

πr^2h = 600

where r is the radius of the cylinder and h is its height. Solving for h, we get:

h = 600 / (πr^2)

The surface area of the cylinder is given by:

A = 2πrh + 2πr^2

Substituting h in terms of r, we get:

A = 2πr(600/(πr^2)) + 2πr^2

= 1200/r + 2πr^2

The cost of the container is the sum of the cost of the styrofoam sides and bottom and the cost of the paper top. Let's call the radius of the paper top R, and assume that the height of the cylinder is greater than or equal to the radius of the paper top, so that the top can be completely covered with paper. Then the cost of the container is:

C = 0.04(2πrh + πr^2) + 0.05(πR^2)

Substituting h in terms of r, we get:

C = 0.08πr(600/(πr^2)) + 0.04πr^2 + 0.05πR^2

= 4.8/r + 0.04πr^2 + 0.05πR^2

To minimize the cost, we need to find the values of r and R that minimize the cost function C. To do this, we take the partial derivatives of C with respect to r and R, and set them equal to zero:

dC/dr = -4.8/r^2 + 0.08πr = 0

dC/dR = 0.1πR = 0

Solving for r and R, we get:

r = ∛(60/π) ≈ 2.78 cm

R = 2.5 cm

We can check that these values give us a minimum by checking the second derivatives:

d^2C/dr^2 = 9.6/r^3 + 0.08π > 0 (minimum)

d^2C/dR^2 = 0.1π > 0 (minimum)

Therefore, the dimensions of the cylinder that minimize the production cost are:

radius = approximately 2.78 cm

height = 600 / (πr^2) ≈ 7.14 cm

paper top radius = 2.5 cm

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I'm sorry, but I cannot determine the values of the line segment lengths

and angle measures without further information or context about the

geometry problem. Please provide me with more details or the specific

problem in question.

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Answer:

≈ 12,78 m^2

Step-by-step explanation:

The surface area is equal to the sum of the areas of all the sides

This figure has sides of 2 triangles (bases) and 3 rectangles (lateral surface)

h (triangle) = 1m

We can find the base of the triangle by using the Pythagorean theorem (multiply by 2, because the triangle's base contains two of these identicals sides)

[tex](( {1.5})^{2} - {1}^{2} ) \times 2=( 2.25 - 1 ) \times 2= 1.25 \times 2 = 2.5> 0[/tex]

The triangle's base is equal to:

[tex] \sqrt{2.5} = \frac{ \sqrt{10} }{2} [/tex]

First, let's find the area of 2 bases (triangles):

[tex]a(bases) = 2 \times \frac{1}{2} \times 1 \times \frac{ \sqrt{10} }{2} = \frac{ \sqrt{10} }{2} [/tex]

Now, we can find the whole surface area by adding the areas of the rectangles to the bases' areas:

[tex]a(surface) = \frac{ \sqrt{10} }{2} + 2.4 \times 2 + 1.5 \times 2 + 1.7 \times 2 = \frac{ \sqrt{10} }{2} + \frac{56}{5} ≈12.78[/tex]

Answer:

f(0) = 1

g(-2) = 3

f(-7)= und

g(4) x f(3) = -2 x 0 = 0

g(-4) = 2

g(x) = 0 --> x = 6, 0.5

f(x) = -1 --> x = -3, 5

f(g(3)) = f(-3) = -1

g(f(-2) = g(0) = -3

f(g(1)) = f(-3) = -1

f(g(5)) = f(-1) = 1

g(f(-4)) = g(-2) = 2

g(g(-6)) = g(4) = -2

g(f(0)) = g(1) = -3

g(f(-6)) = und

Step-by-step explanation:

In order to find the first group, such as f(0), you want to look at the f graph and find 0 on the x-axis. Wherever the y coordinate is will be the correct answer.

To find one such as f(g(3)), you want to dissect it like it is 2 problems. First, we want to find g(3) which is -3. Then we will find -3 on the f graph and find the answer with that y-coordinate.

To find the slope of the secant line connecting two points on a curve, we can use the formula: slope of secant line = (change in y) / (change in x).

In this problem, we are given the function f(x) = x^3 - 5x on the closed interval [-1, 3), and we need to find the slope of the secant line connecting (-1, f(-1)) and (3, f(3)). To do this, we first need to find the y-coordinates of these points by plugging the given x-values into the function f(x). Then, we can use the formula for the slope of a secant line to find the slope of the line connecting these two points.

The slope of a secant line is an important concept in calculus and is used to approximate the instantaneous rate of change of a function at a particular point.

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Tip: When writing math questions, the coefficient would go in front of variables: 7b*[tex]b^2[/tex]

Anyways, in this case, since we cannot mutiply 7 by b, the 7 will stay put

But.... we can mutiply b by b

[tex]b^2[/tex][tex]*b[/tex]=b^3

Tip: B's with no exponent has an exponent with one

Questions?

So,7 will stay put and b and b^2 will simply to b^3

[tex]7b^3[/tex]=Answer

Answer:

  See attached

Step-by-step explanation:

You want a graph with points plotted at (4, 6) and (7, 2), representing a sand trap and a water hazard, respectively.

The ordered pair (4, 6) represents the coordinates (x, y). The x-coordinate is the number of units right of the point x=0, and the y-coordinate is the number of units up from y=0.

Both points have positive coordinates for both x and y, so will be located up and right from the origin. The plot is shown in the attachment.

<951414049393>

it's important to carefully consider the assumptions and limitations of any statistical test or interval, and to ensure that they are appropriate for the data and research question at hand.

There are a few potential reasons why the procedure the student used may not be appropriate in this context:

1.Sample size: The accuracy of the t-distribution depends on the sample size and the assumption that the population follows a normal distribution. If the sample size is too small, the t-distribution may not provide an accurate estimate of the population parameters. In particular, a sample size of less than 30 is often considered too small for the t-distribution to be reliable.

2.Independence assumption: In order to use a t-test or t-interval, the samples should be independent. It's possible that some of the Italian and Spanish scientists may be related or have worked together, which could violate the independence assumption.

3.Population distributions: The validity of a t-test or t-interval also depends on the assumption that the populations have similar variances. If the variances are significantly different, this can affect the accuracy of the results.

4.Random sampling: In order for the results to be valid, the samples should be selected randomly from the populations of Italian and Spanish scientists. If the samples are not random, this could introduce bias into the results.

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a. d, days since first measurement y, acres burned since fire started

0 0, 1 4800, 2 9600, 3 14400, 4 19200, 5 24000. b. when d = -1, it tells that the area burned in the fire was 4780 acres one day before the area was first measured. When d = -3, y = 4680, this means that the area burned in the fire was 4680 acres three days before the area was first measured. c. The area burned a week before the fire measured 4800 acres was approximately 115.2 acres.

a. To complete the table, we need to plug in the values of d in the given equation and calculate the corresponding values of y.

d, days since first measurement

y, acres burned since fire started

0 0

1 4800

2 9600

3 14400

4 19200

5 24000

b. When d = -1, we have:

y = (4800)(24^(-1))^(1) = 4800 - 20 = 4780

This means that the area burned in the fire was 4780 acres one day before the area was first measured.

When d = -3, we have:

y = (4800)(24^(-3))^(1) = 4800 - 120 = 4680

This means that the area burned in the fire was 4680 acres three days before the area was first measured.

c. A week before the fire measured 4800 acres, the number of days since the fire started would be:

d = 4800 / (4800/24) = 24

Therefore, a week before the fire measured 4800 acres, the fire had been burning for 24 days. Plugging in this value in the given equation, we get:

y = (4800)(24^(-24/24))^(1) = 115.2

So, the area burned a week before the fire measured 4800 acres was approximately 115.2 acres.

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