p ⇒ q, r ⇒ s, p ∨r q ∧ s is invalid

The gauge pressure at bottom of vaccine solution will be 16 kPa

Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.

Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.

We have to find the gauge pressure at bottom of vaccine solution

Since the 5N force is applied to vaccine solution the pressure exerted will be much more

Hence the gauge pressure at bottom of vaccine solution will be 16 kPa

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The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.

Solve for the electric flux through the cylinder due to this infinte line:

As below equation mentions, the electric flux for a uniform electric filed is given by:

Фₓ = EA cosΦ

Φₓ = λLcosΦ)/ε

Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))

Φₓ = 1.355 x 10^(5) Nm²/C

Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

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Answer:

inertia of motion

Explanation:

it's because when a passenger is jumping from a bus his/her body is in motion after falling in a road he/she remains or tends to remain in the state of motion that is the reason

Hi there!

The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.

Initially, we only have kinetic energy:

[tex]KE = \frac{1}{2}mv^2[/tex]

KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)

Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:

[tex]U_s = \frac{1}{2}kx^2[/tex]

k = Spring Constant (1.14 × 10⁷ N/m)

x = compressed distance of bumper (? m)

Since energy is conserved:

[tex]E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2[/tex]

We can simplify and solve for 'x'.

[tex]mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}[/tex]

Plug in the givens and solve.

[tex]x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}[/tex]

It then can be stated:

[tex]\large\red\hookrightarrow \rm \large \: \:X_m \: = \: \frac{X_1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]

[tex]\large\red\hookrightarrow \rm \large \: \:Y_m \: = \: \frac{Y_1 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]

Since, Xm = -1 and X1 = 1 we can write equation (1) as

[tex]\large\purple\longrightarrow \rm \large \: \:-1 \: = \: \frac{1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:-2 \: = \:1 \: + \: X_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \: - 2 \: - 1 \: = \: X_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \: - 3 \: = \: X_2[/tex]

Since , Ym = 4 and Y1 = 2 we can write the equation (2) as

[tex]\large\purple\longrightarrow \rm \large \: \:4 \: = \: \frac{2 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:8 \: = \: 2 \: + \: Y_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:8 \: - \: 2 \: = \: Y_2[/tex]

[tex]\large\purple\longrightarrow \rm \large \: \:6 \: = \: Y_2[/tex]

Therefore the other endpoint of the line (X2, Y2) is (-3 , 6)

Answer:

1.1299 x 10^-8   second    

Explanation:

Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8  sec

When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.

Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.

As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.

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Answer:

D. 49N

Explanation:

Because there is no acceleration the sum of the forces in the x-direction is zero. Your weight force is mass x gravity which is 98N. The x-component of which is sin(30). 98sin30 = 49N in the negative x-direction. -49N + The force applied by the worker must equal zero. So, the force applied by the worker must be 49N.

The motion of the elevator can best be described as motion against gravity with negative acceleration.

Motion refers to a change in position of an object when it moves from one point another along a reference frame.

An object moving in a downward direction is moving in a positive direction and its velocity increases relative to the earth since gravity acts downwards.

An object moving in a upward direction is moving in a negative direction and its velocity decreases relative to the earth since gravity acts downwards.

Therefore, the motion of the elevator can best be described as motion against gravity with negative acceleration.

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Answer:

D. 20m

Explanation:

this answer is 20 m.

wavelength = velocity / frequency

Answer:

c

Explanation:

Answer:

c

Explanation:

im smart

This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

To calculate distance, speed is multiplied by time.

We apply the following formula: d = v * t.

We substitute the data in the formula: the speed is equal to 4.6 m/s, the time is equal to 10 s, which is left as follows:

[tex]\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }[/tex]

[tex]\bf{d=46 \ m}[/tex]

Therefore, the speed at 10 seconds is 46 meters.

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

shown below

Explanation:

2 x 10⁷ as a number is 20,000,000

20,000,000 - 10 = 19,999,990

It went 19,999,990 m/h

in km/h:

19,999,990 / 1000 = 19,999.99 km/h

in km/s

19,999,990 / 3,600,000 = ~5.56 km/s

in m/s

19,999,990 / 3600 = ~5555.56 m/s

Weight is compared with the gravitational force exerted on each of them by the Earth.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.

The gravitational force is balanced by weight;

[tex]\rm F = W \\\\ G\frac{mM}{r^2} =mg[/tex]

Hence, weight is compared with the gravitational force exerted on each of them by the Earth.

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By counting the number of crests that pass a point in a specific amount of time, one may determine the frequency of a waveform. Option a is correct.

A sound pressure wave's frequency, also known as pitch, is the number of times it repeats itself every second.

The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.

The frequency of a waveform is found by determining the number of crests passing a point in a given time.

Hence option a is correct.

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Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.

According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.

Energy cannot be created nor destroyed and can be transferred from one form to the other form.

The complete question is

"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.

Which two statements provide examples?

A. Friction between a car's tires and the road produces heat.

B. Sunlight strikes a solar panel, generating electricity.

c. Stereo speakers emit a sound when powered by electrical energy,

D. Wind moves a turbine, generating electricity.

I E. Power lines heat up as electricity flows through them."

Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.

Hence, sentences A and D describe examples of energy transformation.

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The term temperature has to do with the  measure of an object's "hotness".

The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.

Succinctly put, the term temperature has to do with the  measure of an object's "hotness".

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Answer:

A

Explanation:

5.2mm/s

hope this helps

The centripetal force is obtained by its formulas is,[tex]\rm F_C= \frac{mv^2}{r}[/tex]

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.

The formula for the centripetal force is ;

[tex]\rm F_C= \frac{mv^2}{r}[/tex]

Where,

r is the radius

v is the linear speed

m is the mass of an object

Hence, the centripetal force obtained by its formulas as,[tex]\rm F_C= \frac{mv^2}{r}[/tex]

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The distance covered by an accelerating object starting from rest is

D = (1/2 of acceleration) x (time²).

In this question,

D = 100 m

time = 3.8 s

100 = (1/2 acceleration) x (3.8s²)

100 = (1/2 a) x (14.44)

100/14.44  =  1/2 a

200/14.44  =  a

a = 13.85 m/s²

a. Ball P

Density is define as mass per unit volume or the quantity per unit volume, unit area, or unit length.

If [tex]m_{1}[/tex] is mass ,  [tex]V_{1}[/tex] is volume and [tex]D_{1}[/tex]  is density of ball P

[tex]m_{2}[/tex]  is mass ,  [tex]V_{2}[/tex] is volume and [tex]D_{2}[/tex] is density  of ball Q

It is given that  ,

[tex]V_{1}[/tex] = [tex]V_{2}[/tex];

But  [tex]m_{1}[/tex]= [tex]2m_{2}[/tex]

Based on above equation we have:

[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{2m_{2} }{V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 2[/tex]

Thus, density of ball P is twice that of Q.

Therefore ,

Ball  P will have a greater density than Q

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Answer:

i don't know sorry

i know a good website that may help you

it's called https://skyandtelescope.org/observing/telescope-calculator/

Explanation:

Answer:

Explanation:

Half-life problems are modeled as exponential equations.  The half-life formula is [tex]P=P_o\left (\dfrac{1}{2} \right)^{\frac{t}{k}}[/tex] where [tex]P_o[/tex] is the initial amount, [tex]k[/tex] is the length of the half-life, [tex]t[/tex] is the amount of time that has elapsed since the initial measurement was taken, and [tex]P[/tex] is the amount that remains at time [tex]t[/tex].

[tex]P=14.2\left (\dfrac{1}{2} \right)^{\frac{t}{8.0252}}[/tex]

Deriving the half-life formula

If one forgets the half-life formula, one can derive an equivalent equation by recalling the basic an exponential equation, [tex]y=a b^{t}[/tex], where [tex]t[/tex] is still the amount of time, and [tex]y[/tex] is the amount remaining at time [tex]t[/tex].  The constants a and b can be solved for as follows:

Knowing that amount initially is 14.2g, we let this be time zero:

[tex]y=a b^{t}[/tex]

[tex](14.2)=ab^{(0)}[/tex]

[tex]14.2=a *1[/tex]

[tex]14.2=a[/tex]

So, [tex]a=14.2[/tex], which represents out initial amount of the substance, and our equation becomes: [tex]y=14.2 b^{t}[/tex]

Knowing that the "half-life" is 8.0252 days (note that the unit here is "days", so times for all future uses of this equation must be in "days"), we know that the amount remaining after that time will be one-half of what we started with:

[tex]\left(\frac{1}{2} *14.2 \right)=14.2 b^{(8.0252)}[/tex]

[tex]\dfrac{7.1}{14.2}=\dfrac{14.2 b^{8.0252}}{14.2}[/tex]

[tex]0.5=b^{8.0252}[/tex]

[tex]\sqrt[8.0252]{\frac{1}{2}}=\sqrt[8.0252]{b^{8.0252}}[/tex]

[tex]\sqrt[8.0252]{\frac{1}{2}}=b[/tex]

Recalling exponent properties, one could find that  [tex]\left ( \frac{1}{2} \right )^{\frac{1}{8.0252}}=b[/tex], which will give the equation identical to the half-life formula.  However, recalling this trivia about exponent properties is not necessary to solve this problem.  One can just evaluate the radical in a calculator:

[tex]b=0.9172535661...[/tex]

Using this decimal approximation has advantages (don't have to remember the half-life formula & don't have to remember as many exponent properties), but one minor disadvantage (need to keep more decimal places to reduce rounding error).

So, our general equation derived from the basic exponential function is:

[tex]y=14.2* (0.9172535661)^t[/tex]  or [tex]y=14.2*(0.5)^{\frac{t}{8.0252}}[/tex] where y represents the amount remaining at time t.

Solving for the amount remaining

With the equation set up, substitute the amount of time it takes to cross the Pacific to solve for the amount remaining:

[tex]y=14.2* (0.9172535661)^{(31.8)}[/tex]          [tex]y=14.2*(0.5)^{\frac{(31.8)}{8.0252}}[/tex]

[tex]y=14.2* 0.0641450581[/tex]                    [tex]y=14.2*(0.5)^{3.962518068}[/tex]

[tex]y=0.9108598257[/tex]                              [tex]y=14.2* 0.0641450581[/tex]

                                                        [tex]y=0.9108598257[/tex]

Since both the initial amount of Iodine, and the amount of time were given to 3 significant figures, the amount remaining after 31.8days is 0.911g.

10¹¹ is the approximate number of atoms in a bacterium.

The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu).

Given,

Mass of a bacterium atom = 10⁻¹⁵ kg.

Mass of a hydrogen atom  = 10⁻²⁷ kg.

From the above observation ,

The average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.

Atomic mass 1 bacterium atom = 10 x mass of hydrogen atom

                                                  = 10 x 10⁻²⁷ kg.

                                                  = 10⁻²⁶ kg.

Thus,

The number of atoms in a bacterium

=  [tex]\frac{Total mass}{Atomicmass of 1 bacterium}[/tex]

= [tex]\frac{10^{-15} }{10^{-26} }[/tex]

=  [tex]10^{11}[/tex]

The approximate number of atoms in a bacterium  is [tex]10^{11}[/tex].

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The coefficient of friction between the block and the surface is determines as 0.1.

Apply the principle of conservation of linear momentum;

0.05(400) = v(0.05 + 25)

20 = 25.05v

v = 0.8 m/s

Apply the principle of conservation of energy

P.E  - K.E = Ux

μmgx - ¹/₂mv²  = ¹/₂kx²

μ(25.05)(9.8)(0.12) - 0.5(25.05)(0.8)² = 0.5(180)(0.12)

29.459μ - 8.016   = 10.8

29.459μ = 2.784

μ = 0.1

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Answer:

0.159

Explanation:

the formula to find its is 1÷2*gt^2

Answer:

D

Explanation:

v= a t

 = 5.1 * .25 = 1.275 m/s

The friction force is 1.5N

Now, using the third equation of motion-

[tex]v^{2}= u^{2} +2as[/tex]

v=final velocity

u=initial velocity

a=acceleration

s=distance

substitute the values in the above equation

1.2=0+ 2a×20

a=1.2/40

a=0.03

friction force=mass ×acceleration

                    =50×0.03

                    =1.5N

hence, The friction force is 1.5N

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• The speed change between T and S is greater between S and R.

• The speed of m at X is  greater that at Q.

• The size of the total force on m at P is less at U.

• The mechanical energy of m at P is equal to that at V.

• The size of the total force on m at S is greater at P.

• The velocity of m at X is equal to that at V.

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

Given is a small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.

The picture shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V.

Between T to S and S to R, the mass is under constant acceleration. Time taken to move from T to S is greater than S to R. Thus, the speed change between T and S is greater than between S and R.

At Q, there is only a horizontal velocity component, but at X. the speed will be greater and has both vertical and horizontal component. Thus, the speed of m at X is greater than that at Q.

Force is given as the rate of change of momentum with time. At U, change in momentum is large compared to P. Thus, the size of the total force on m at P is less at U.

There is no friction acting on the system. So the energy remains conserved. Mechanical energy at P = V.

The force on mass m at S is only the gravity force. The remaining forces are cancelled by the normal force. Thus, size of the total force on m at S is greater at P.

The energy is conserved at each point of motion of mass. If X and V are at same height, they have same potential energy and so their kinetic energy. Thus, velocity of m at X is equal to that at V.

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