Oxygen is a non-metal true or false

Answer:

No, the pH scale can not be utilized for all types of acids known

Explanation:

The pH scale is a scale that shows the degree of acidity or alkalinity of a substance. The pH scale is graduated from 0-14. The pH scale is mostly applied to Arrhenius acids. Recall that in the Arrhenius definition, an acid produces hydrogen ion in solution while a base produces hydroxide ion in solution. Hence we could easily measure or calculate the pH and pOH of Arrhenius acids. Arrhenius acids apply mostly to acid-base discussion in Aqueous media.

Beyond aqueous media, we can still apply the Brownstead-Lowry and Lewis definitions for acid and base. Some of these substances to which we apply these other definitions of acid and base do not necessarily contain hydrogen or hydroxide ions hence the pH scale can not be utilized in discussing their acid-base properties, hence the answer.

Answer:

[Ni(CO)2C2O4]- Dicarbonyloxalatonickel(0)

K3[Fe(NCO)3(OCN)3-potassiumtricyanatotriisocyanatoferrate II

diammineaquahydroxoplatinum(II) ion- [Pt(NH3)2(H2O)(OH)]^+

Al[Co(CO3)2(CN)2- Aluminiumdicarbonatodicyanocobalt III

ethylenediaminedinitritozinc(II)- Zn(en)(NO2)2

Explanation:

The international Union of Pure and applied chemistry published a set rules for the nomenclature of inorganic compounds in 1985. This set of rules have been consistently revised ever since.

The rules stipulate the order for naming positive ions, negative ions and neutral ligands and the allowed order of preference for naming. It also stipulates the proper endings for ligands which are positive ions, negative ions or neutral ligands as the case may be.

The compounds named above were named in accordance with the revised IUPAC nomenclature for inorganic compounds.

Answer:

Number of Significant Figures: 5

The Significant Figures are 1 1 0 0 5

Explanation:

Answer:

See attached picture.

Explanation:

Hello,

In this case, given the compounds we notice:

a. Since carbon has four valence electrons (group IVA), it has three hydrogen atoms around it as well as a fluorine atom which has seven valence electrons (group VIIA). Moreover, we notice both carbon and fluorine attaining the octet.

b. In this case, two nitrogen atoms which have five valence electrons each (groupVA) are bonded via a single bond and two hydrogen atoms are bonded to each nitrogen atom in order to attain the octet for nitrogen only.

Thus, structures are given on the attached picture.

Regards.

Lewis structure for each covalent molecule CH₃F and N₂H₄ are attached to the image below.

a. CH₃F:

Carbon (C) has 4 valence electrons, Hydrogen (H) has 1 valence electron, and Fluorine (F) has 7 valence electrons.

The total number of valence electrons in CH3F can be calculated as follows:

1 carbon atom (C) × 4 valence electrons = 4 valence electrons

3 hydrogen atoms (H) × 1 valence electron = 3 valence electrons

1 fluorine atom (F) × 7 valence electrons = 7 valence electrons

Total valence electrons = 4 + 3 + 7 = 14

b. N₂H₄:

Nitrogen (N) has 5 valence electrons, and Hydrogen (H) has 1 valence electron.

The total number of valence electrons in N2H4 can be calculated as follows:

2 nitrogen atoms (N) × 5 valence electrons = 10 valence electrons

4 hydrogen atoms (H) × 1 valence electron = 4 valence electrons

Total valence electrons = 10 + 4 = 14

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Answer:

0.0289 kg of CO2 will be formed

Explanation:

Step 1: Data given

Mass of iron produced = 24.42 grams

Atomic mass iron = 55.845 g/mol

Molar mass CO2 = 44.01 g/mol

Step 2: The balanced equation

Fe2O3 + 3CO → 2Fe + 3CO2

Step 3: Calculate moles iron

Moles iron = mass iron / molar mass iron

Moles iron = 24.42 grams / 55.845 g/mol

Moles iron = 0.437 moles

Step 4: Calculate moles CO2

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.437 moles Fe we'll have 3/2 * 0.437 = 0.6555 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.6555 moles * 44.01 g/mol

Mass CO2 = 28.85 grams = 0.0289 kg

0.0289 kg of CO2 will be formed

Answer:

The pineal, hypothalamus, and pituitary are located in the BRAIN

The thyroid, parathyroid, and thymus are located in the THROAT

The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY

Explanation:

The pineal, hypothalamus, and pituitary are located in the BRAIN

The thyroid, parathyroid, and thymus are located in the THROAT

The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY

Answer:

Throat

Abdomen

Brain

Explanation:

These are correct!

Answer:

They must have the same number of protons.

Explanation:

Protons determine the identity of an element. However, the neutrons can vary, resulting in different masses.

Answer:

Atoms of the same element can have different numbers of neutrons, however. Atoms of the same element (i.e., atoms with the same number of protons) with different numbers of neutrons are called isotopes. Most naturally occurring elements exist as isotopes.

Explanation:

Answer:

AlF3

Explanation:

Aluminum fluoride (AlF3) is an inorganic compound in which aluminum and fluoride has ionic bond between each other.

Aluminum ( atomic number - 13) has 3 valence electrons and can lose 3 electrons to get a stable configuration while fluorine (atomic number - 9) can gain one electron to make a stable configuration. So in order to attain a stable configuration one aluminum (Al) atom form ionic bond with three fluorine atoms and form AlF3.

Hence, the chemical formula between  Al and F is AlF3.

Answer:

Explanation:

mmmmmmmmmmmmmh,mm

Answer:

6.24 x 10-3 M

Explanation:

Hello,

In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:

[tex]Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}[/tex]

Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change [tex]x[/tex], we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:

[tex]5.2x10^{-5}=\frac{x*x}{0.749-x}[/tex]

Thus, we obtain a quadratic equation whose solution is:

[tex]x_1=-0.00627M\\x_2=0.00624M[/tex]

Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.

Best regards.

Answer:

6.24×10¯³ M

Explanation:

Step 1:

The equation for the reaction is given below:

HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)

Step 2:

The following data were obtained from the question:

Equilibrium constant, Kc = 5.2x10^-5

Concentration of HBrO, [HBrO] = 0.749 M

Concentration of BrO-, [BrO-] =?

Step 3:

Determination of the concentration of

BrO-.

We can obtain the concentration of BrO- as follow:

Initial concentration:

[HBrO] = 0.749 M

[H3O+] = 0

[BrO-] = 0

During reaction:

[HBrO] = - y

[H3O+] = +y

[BrO-] = +y

After reaction:

[HBrO] = 0.749 - y

[H3O+] = y

[BrO-] = y

Applying the equation constant equation:

Kc = [H3O+] [BrO-] / [HBrO]

5.2x10^-5 = y × y / 0.749

5.2x10^-5 = y² / 0.749

Cross multiply

y² = 5.2x10^-5 x 0.749

Take the square root of both side

y = √(5.2x10^-5 x 0.749)

y = 6.24×10¯³ M

[BrO-] = y = 6.24×10¯³ M

Therefore, the the concentration of BrO- at equilibrium is 6.24×10¯³ M

Answer:

80 ml.

Explanation:

The balanced equation is:

KOH + HNO3 ---->  KNO3 + H2O

So 1 mole of KOH reacts with 1 mole of HNO3

200ml of 0.16M KOH contains 0.16 * 200/1000

= 0.16 * 0.2

= 0.032 M KOH.

So we need the volume (V) of 0.4 M HNO3 which contains 0.032 moles.

0.4 * V = 0.032

V = 0.032 / 0.4

V = 0.08 liters

= 80 mls.

Answer:

The volume of the sample given is 850 ml, the density given is 0.79 gram per cm. Now the weight of the sample will be,  

Weight = volume × density = 850 × 0.79  

= 671.5 grams

Weight of the suspended solids given is 0.001 gram

The concentration of the sample can be determined by using the formula,  

Concentration = wt. of sample/volume

= [671.5 - 0.001) 10³ mg / 0.85 L

= 789998.82 mg/L or 789998.82 ppm

Now the concentration of suspended solids is.  

Css = 0.001 × 10³ mg / 0.85 L = 1.1764 mg per L or 1.1764 ppm

Answer:

4000cm³

Explanation:

2.0moles-1000cm³

8.0moles-?

(8.0×1000)÷2

=4000cm³

Answer:

6.460 gm  is the correct answer .

Explanation:

Given

Kate’s blood volume=[tex]3.8L[/tex]

blood glucose=[tex]170\ mg/dL[/tex]

As we know that

[tex]1\ dL= 10^{-1}\ litre[/tex]

The [tex]10^{-1}[/tex]   includes the blood glucose of the [tex]170\ mg/dL,[/tex]

So [tex]3.8L.[/tex] of the Kate’s blood volume  can be determined by

[tex]=\ \frac{170 * 3.8 }{10^{-1} }[/tex]

[tex]=170 * 38 \ mg[/tex]

[tex]=6460\ mg[/tex]

To convert into the gm we have divided by the 1000

[tex]6.460 \ gm[/tex]

Therefore the glucose in her blood=

[tex]6.460 \ gm[/tex]

Answer:

6.460 g

Explanation:

Glucose is a simple carbohydrate molecule which circulates in the blood along with other substances. The amount of glucose is measured to treat the medical conditions of patients which is measured as mg/dL.

1 liter of liquid contains 10 deciliters therefore 1 dL will have 0.1 liter or

1 dL= 10^-1 liter (0.1)

In the given question,  

the total volume of blood = 3.8 L

1 dL of blood contains = 170 mg

3.8 L will have = (3.8 x 170)/0.1

=6460 mg

= 6.460 g

Thus, 6.460 g is the correct answer.

Answer:

mole fraction of Oxygen = mole of oxygen/ total mole

Explanation:

The element fluorine is more electronegative than the element chlorine. Fluorine has an electronegativity value of 4.0 and Carbon has an electronegativity value of 2.5.

The term electronegativity is defined as a chemical property that describes the capacity of an atom or a functional group to attract electrons toward itself.

Electronegativity is refer to the ability of an atom to attract shared electrons in a covalent bond. The grater the value of the electronegativity, the more strongly that element attracts the shared electrons.

In fluorine electronegativity value is more than carbon. Therefore, it strongly attracts the shared electrons.

Thus, The element fluorine is more electronegative than the element chlorine.

To learn more about an electronegativity, follow the link;

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Answer:

CF₂O

Explanation:

To determine how the molecule will be made think about the valence number of each element in molecule:

 F= -1 , O= -2 , C= +4

because the C is positive atom it  will be the central atom with a double bond to the O and a single bond to each F.

this way all atoms completed the octet and stability

Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

Answer: 0.05 moles

Explanation:

To convert from atoms to moles, you will need Avogadro's number.

Avogadro's number: 6.022×10²³atoms/moles

(3.13×10²²atoms)×(moles/6.022×10²³ atoms)=0.05 moles

The atoms would cancel out and we will be left with our moles.

Answer:

The empirical formula for this compound is thus CH2.

Explanation:

Answer:

0.76 mole of Fe2S3.

Explanation:

Step 1:

Determination of the number of mole in 449g iron(III)bromide, FeBr3. This is illustrated below:

Mass of FeBr3 = 449g

Molar mass of FeBr3 = 56 + (80x3) = 296g/mol

Mole of FeBr3 =..?

Mole = Mass /Molar Mass

Mole of FeBr3 = 449/296

Mole of FeBr3 = 1.52 moles

Step 2:

The balanced equation for the reaction. This is given below:

2FeBr3 + 3Na2S —> 6NaBr + Fe2S3

Step 3:

Determination of the number of mole of Fe2S3 produced from the reaction of 449g ( i.e 1.52 moles) of FeBr3. This is illustrated below:

From the balanced equation above,

2 moles of FeBr3 reacted to produce 1 mole of Fe2S3.

Therefore, 1.52 moles of FeBr3 will react to produce = (1.52 x 1)/2 = 0.76 mole of Fe2S3.

Therefore, 0.76 mole of Fe2S3 is produced from the reaction.

Answer: 0.76

Explanation:

Answer:

3920kg of lime(CaO)   1568m^3 of CO2

Explanation:

I attached the explanation!

also for calculating the volume I assumed Standard Temperature and Pressure(STP).

Answer: b. -100 kJ

Explanation:

Heat of reaction is the energy released or absorbed during the course of the reaction. It is represented by the symbol [tex]\Delta H[/tex].

[tex]\Delta H=H_{products}-H_{reactants}[/tex]

[tex]\Delta H[/tex] = enthalpy of reaction = ?

[tex]H_{products}[/tex] = enthalpy of products = 0 kJ

[tex]H_{reactants}[/tex] = enthalpy of reactants = 100 kJ

[tex]\Delta H=0kJ-100kJ[/tex]

[tex]\Delta H=-100kJ[/tex]

Thus the ΔH for the reaction is -100kJ

Answer:

0.0036

Explanation:

SEE THE ATTACHMENT BELOW FOR DETAILED EXPLANATION

Answer:

I.  1.743mg/mL

II. 0.174g

III. 8.7 wt%

Explanation:

As absorbance is directly proportional to concentration. The calibration curve was:

Y = 1.6421X - 0.1113

Where Y is absorbance of sample and X its concentration in mg/mL

The diluted sample obtains an absorbance of 0.461, that means its concentration is:

0.461 = 1.6421X - 0.1113

0.3485mg/mL = X

I. The sample was diluted to 50.0mL from an aliquot of 10.0mL, thus, concentration in the original fruit sample was:

0.3485mg/mL × (50.0mL / 10.0mL) = 1.743mg/mL

II. The total mass of vitamin C in the sample (100.0mL) is:

100.0mL × (1.743mg/mL) = 174mg = 0.174g

III. As the fruit sample was of 2.0g, the wt% is:

0.174g / 2.0g = 8.7 wt%

Answer:

Explanation:

The equation of above line , y = 0.0005x+ 0.458

This can be compared with y = mx+c

Hence slope, m = 0.0005 and Y-intercept, c = 0.458

Or it can be plotted manually where straight line has to be drawn touching maximum number of data points. After drawing a straight linear line, we need to take any two points from the straight line and slope is calculated

Slope,

[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]

and y -intercept is calculated using extraplotting backwards such that it touches the Y-axis. the point where straight line touches Y-axis is Y-intercept (c).

Plot the average cell potentials E (y-axis) vs T (x-axis). image attached

Answer:

Percentage yield = 38.37%

Explanation:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃

2 moles of Al contains = (2 × 27) = 54g of Al

1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃

54g of Al produces 342.15g of Al₂(SO₄)₃,

46g of Al will produce x g of Al₂(SO₄)₃

Solve for x

X = (46 × 342.15) / 54

X = 15738.9 / 54

X = 281.46g

Theoretical yield of Al₂(SO₄)₃ = 281.46g

Percentage yield of a substance = (actual yield / theoretical yield) × 100

Actual yield = 108g

Theoretical yield = 281.46

% yield = (108 / 281.46) × 100

% yield = 0.3837 × 100

%yield = 38.37

The percentage yield of Al₂(SO₄)₃ is 38.37

Answer:  Percentage yield = 38.37%

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂  from the equation of reaction, 2 moles of Al reacts to produce 1 moles of Al₂(SO₄)₃ .

2 moles of Al contains = (2 × 27) = 54g of Al

1 mole of Al₂(SO₄)₃ contains (1 × 342.15) = 342.15g of Al₂(SO₄)₃

54g of Al produces 342.15g of Al₂(SO₄)₃,

46g of Al will produce x g of Al₂(SO₄)₃

Solve for x  

X = (46 × 342.15) / 54

X = 15738.9 / 54

X = 281.46g

Theoretical yield of Al₂(SO₄)₃ = 281.46g

Percentage yield of a substance = (actual yield / theoretical yield) × 100

Actual yield = 108g

Theoretical yield = 281.46

% yield = (108 / 281.46) × 100

% yield = 0.3837 × 100

%yield = 38.37

The percentage yield of Al₂(SO₄)₃ is 38.37