Number of Potatoes
36
24
12
5
10
Number of Pounds
x
15
Use the graph to find the unit rate.
potatoes per pound

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 6(3x - 7) = 2[/tex]

Step 1 -

[tex]\qquad \tt \rightarrow \: 18x - 42 = 2[/tex]

[ distributive property ]

Step 2 -

[tex]\qquad \tt \rightarrow \: 18x = 2 + 42[/tex]

[tex]\qquad \tt \rightarrow \: 18x = 44[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

d) Step 1: 18x - 42 = 2

Step 2: 18x = 44

Step-by-step explanation:

Given equation,

→ 6(3x - 7) = 2

Now the value of x will be,

→ 6(3x - 7) = 2

→ 6(3x) - 6(7) = 2

→ 18x - 42 = 2

→ 18x = 2 + 42

→ 18x = 44

→ x = 44/18

→ [ x = 22/9 ]

Hence, value of x is 22/9.

Using the z-distribution, it is found that 3,007 passengers must be surveyed.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]

[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]

n = 3007.

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Answer:

54

Step-by-step explanation:

⇒ 1 + 3 = 4

⇒ 4 * 13 = 52

⇒ 52 + 2 = 54 (Basic Operation)

A function assigns the values. The absolute magnitude of a star that has a period of 62 days is -6.3328.

A function assigns the value of each element of one set to the other specific element of another set.

The relationship between the brightness of a Cepheid star and its period, or length of its pulse, is given by

M = − 2.78 (log P) − 1.35,

Given the absolute magnitude of a star that has a period of 62 days is,

M = − 2.78 (log 62) − 1.35

M = -6.3328

Hence, the absolute magnitude of a star that has a period of 62 days is -6.3328.

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The ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)

The given parameters are:

Initial height, h = 8 inches

Rate = 0.5 inches per hour

The height of the candle at x hour is:

y = Initial - rate * x

This gives

y = 8 - 0.5x

Set x  = 0 to 5

y = 8 - 0.5(0) = 8

y = 8 - 0.5(1) = 7.5

y = 8 - 0.5(2) = 7

y = 8 - 0.5(3) = 6.5

y = 8 - 0.5(4) = 6

y = 8 - 0.5(5) = 5.5

So, the ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)

In (a), we have:

y = 8 - 0.5x

The above is a linear relation.

All linear relations are functions

Hence, the relation is a function.

We have

Initial height, h = 8 inches

New rate = 0.4 inches per hour

The height of the candle at x hour is:

y = Initial - rate * x

This gives

y = 8 - 0.4x

The above is a linear relation.

All linear relations are functions

Hence, the new relation is also a function.

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The expression in factored form for the polynomial of least possible degree graphed will be y(x) = (x + 3)(x + 2 )(x - 1 )(x - 3 )

From the graph, the zeros of the polynomial of given graph are:

x = -3

x = -2

x = 1

x = 3

Equate the above equations to zero

x + 3 = 0

x + 2 = 0

x - 1 = 0

x - 3 = 0

Multiply the equations

(x + 3)(x + 2 )(x - 1 )(x - 3 ) = 0

Express as a function gives;

y = (x + 3)(x + 2 )(x - 1 )(x - 3 )

Hence, the factored form of the polynomial will be y = (x + 3)(x + 2 )(x - 1 )(x - 3 )

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Answer:

depends upon the degree of the angle

Step-by-step explanation:

vertically opposite angles are always equal like

80 = 80 sum is equal to 160 degrees not equal to 90

45 = 45 , sums equal to 90 degrees ,equal to 90

30 = 30 sum is equal to 60 degrees, not equal to 90

so we can say it depends what is the no of degrees if it is  45 only we can say  the vertically opposite angles are  complementary angle

We conclude that the interval in which the function decreases is (1.5, 3]

The ball is decreasing when the graph, reading from left to right, is going downwards.

Particularly, in this parabola that opens downwards, the graph will decrease after the vertex.

And we can see that the vertex is at x = 1.5

And we also see that the graph of the function ends at x = 3.

Then we conclude that the interval in which the function decreases is (1.5, 3]

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Step-by-step explanation:

hope you can understand

Answer: d = 40 - 5/2t; 1995

Hope it helps :)

The next step in the series is choice D.

Answer:

D

Step-by-step explanation:

if we define the diagrams in terms of their rows and columns, then

1st : 2 by 1

2nd : 3 by 2

3rd : 4 by 3

note that the rows and columns both increase by 1

then the next likely diagram is

5 by 4 , that is diagram D

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{6x = 54}\\\\\large\textbf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6x}{6} = \dfrac{54}{6}}\\\\\textbf{SIMPLIFY IT!}\\\\\mathsf{x = 9}\\\\\huge\text{Therefore, your answer should be: \boxed{\mathsf{x = 9}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

1

Step-by-step explanation:

when we put 1 in the equation the nominator becomes zero and it becomes undefined

Hii!

___________________________________________________________

[tex]\stackrel\star\rightsquigarrow\circ\boldsymbol{\underbrace{Answer:}}}\circ\leftharpoonup[/tex]

The value of x should be 5! ^^

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Explanation:}}}\circ\leftharpoonup[/tex]

[tex]\boxed{\\\begin{minipage}{7cm} For\,an\,expression \\ \boldsymbol{to\,be\,und efined,} \\ \,its\,denominator\,should\,be\,zero \end{minipage}}}[/tex]

Remember this! ^^

Now let's consider this:

Which value of x will make the denominator equal to 0?

Is it 1? If we stick 1 in, we will not obtain 0.

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot1-3}{1-5}[/tex]

[tex]\bullet[/tex] Simplify this

[tex]\twoheadrightarrow\sf y=\cfrac{3-3}{-4}[/tex]

---

We will obtain 0 in the numerator, but not in the denominator; if the numerator is 0, then the fraction, or fractional expression, is 0.

Let's try 5. 5-5 is equal to 0, so this sounds promising! ^^

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot5-3}{5-5}[/tex]

[tex]\bullet[/tex] Look what we obtain when we simplify

Don't we obtain 15-3/0?

Like I said above, if an expression has 0 as its denominator, it's undefined.

--

Hope that this helped! Best wishes.

[tex]\textsl{Reach far. Aim high. Dream big.}[/tex]

--

H0: µ1 = µ2; The exercise program do not have significant effect on physical fitness, H1: µ1 =/ µ2; the exercise program had a significant effect on physical fitness and the  Estimated Cohen's d is 0.82.

A. Significant effect

H0: µ1 = µ2

Based on the above hypothesis the exercise program does not have significant effect on physical fitness

H1: µ1 =/ µ2

Based on the above hypothesis the exercise program had a significant effect on physical fitness

Pooled variance: sp2 = (190 + 120.5/(15-1) + (10-1)

Pooled variance: sp2 = 310.5/23

Pooled variance: sp2 =13.5

Estimated standard error ( sM1-M2):

sM1-M2 =√13.5/15 +13.5/10

sM1-M2 =√2.25

sM1-M2 = 1.5

Tailed test (t)

t = (15.5 - 12)/1.5

t=3.5/1.5

t= 2.33

B. Estimated Cohen's d:

Estimated Cohen's d  = 3/√13.5

Estimated Cohen's d = 3/3.67

Estimated Cohen's d= 0.817

Estimated Cohen's d= 0.82 (Approximately); this is a large effect.

Conclusion demonstrating how the outcome of the hypothesis test would tend to appear in a research report is:  (Reject H0). Because the  group exercise program tend to have a significant effect on the physical fitness of elderly adults, t = 2.33, p <.05, d = 0.82.

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Answer:

3,n-1>9

3>n2+9

3>n11 is ans

Answer:

The answer is 1/42 as you take reciprocal of 6=(1/6) and reciprocal of 7=(1/7) and multiply.

Answer:

[tex]\boxed {\frac{1}{42}}[/tex]

Step-by-step explanation:

Reciprocal of 6 : 1/6

Reciprocal of 7 : 1/7

Their product :

The expression that represents this inequality must relate both temperatures, then it would look like this: -40°F < x < 140°F.

To express this situation in an inequality we must include the temperature values. Additionally, we must include the greater than (>) or less than (<) symbols to relate the values.

According to the above, the expression would look like this:

Note: This question is incomplete because some information is missing. Here is the information:

A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form.

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Answer:

24 square units

Step-by-step explanation:

1) the area can be calculated using the formula:

A=0.5*a*h, where a- base, h-height;

2) if a=8, h=6, then the required area is:

A=0.5*8*6=24 [units²].

Answer: 24 square units

Step-by-step explanation:

The base: 8

The height: 6

The area: 8 x 6 / 2 = 24

/ stands for divided by

Answer:

[tex]11 - 2 {}^{3} [/tex]

[tex]11 - 8[/tex]

[tex]3[/tex]

David will be 10 and John will be 9

Answer:

(2a-b)(3c-d)

Answer:

0.98994949366117

√0.98 = 0.98994949366117

Step 1:

Divide the number (0.98) by 2 to get the first guess for the square root.

First guess = 0.98/2 = 0.49.

Step 2:

Divide 0.98 by the previous result. d = 0.98/0.49 = 2.

Average this value (d) with that of step 1: (2 + 0.49)/2 = 1.245 (new guess).

Error = new guess - previous value = 0.49 - 1.245 = 0.755.

0.755 > 0.01. As error > accuracy, we repeat this step again.

Step 3:

Divide 0.98 by the previous result. d = 0.98/1.245 = 0.7871485944.

Average this value (d) with that of step 2: (0.7871485944 + 1.245)/2 = 1.0160742972 (new guess).

Error = new guess - previous value = 1.245 - 1.0160742972 = 0.2289257028.

0.2289257028 > 0.01. As error > accuracy, we repeat this step again.

Step 4:

Divide 0.98 by the previous result. d = 0.98/1.0160742972 = 0.9644963982.

Average this value (d) with that of step 3: (0.9644963982 + 1.0160742972)/2 = 0.9902853477 (new guess).

Error = new guess - previous value = 1.0160742972 - 0.9902853477 = 0.0257889495.

0.0257889495 > 0.01. As error > accuracy, we repeat this step again.

Step 5:

Divide 0.98 by the previous result. d = 0.98/0.9902853477 = 0.9896137535.

Average this value (d) with that of step 4: (0.9896137535 + 0.9902853477)/2 = 0.9899495506 (new guess).

Error = new guess - previous value = 0.9902853477 - 0.9899495506 = 0.0003357971.

0.0003357971 <= 0.01. As error <= accuracy, we stop the iterations and use 0.9899495506 as the square root.

So, we can say that the square root of 0.98 is 0.989 with an error smaller than 0.01 (in fact the error is 0.0003357971). this means that the first 3 decimal places are correct. Just to compare, the returned value by using the javascript function 'Math.sqrt(0.98)' is 0.9899494936611666.

Note: There are other ways to calculate square roots. This is only one of them.

To round it to the tenths, it's 1

To round to the hundredths, it's.99

Thousandth is.990

The packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

Trajectory is the path followed by a moving object when it is falling under gravitational force.

x = 90 t

y = -4.9 t²2 + 4500

t ≥ 0

y = 0

-4.9t² + 4500 = 0

4.9t²2 = 4500

[tex]\rm t = \sqrt {\dfrac{4500}{4.9}}[/tex]

t = 30.30 seconds

substituting the value to determine the horizontal distance

x = 120 * 30.30

x = 3636.55 meters

Therefore the packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

The complete question is

a drone traveling horizontally at 120m s over a flat ground at an elevation of 4500 meters must drop an emergency package on a target on the ground the trajectory of the package is given by x 120t y 4.9t 2 4500 where the origin is the point on the ground directly beneath the drone at the moment of release. How many horizontal meters before the target should the package be released in order to hit the target? Round to the nearest meter.

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The cost per unit for each product is given as:
x ≈ 0.0067; and

y ≈ 0.0041. See explanation below.

Given that the current production:

Current cost of production is given as:

Current Total Cost = 150y + 245x where;

if doubling the batch sizes will reduce the cost per unit by 50% then the new cost equation will be:

Thus, New Total Cost of production = (150 x 2) (y/2) + (245 x 2) (x/2)

= (300)(y/2) + (490) (x/2)

Since we are looking for the cost per unit of each product:

f(x) = 300 * (x/2)..........Unit cost of Model Gold

If we make x subject of the formula, then we arrive at:
1/300 = x/2
x = (1/300) * 2

x = 0.00666666666

x ≈ 0.0067

f(x) = 490* (x/2)

If we make y subject of the formula, then we arrive at:

i/490 = y/2

y = (1/490) * 2

y = 0.00408163265306122448979591836735

y ≈ 0.0041

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Answer:

False, distributions having the same mean and standard deviation can have very different shape of distribution.

Answer + Step-by-step explanation:

Answer:

Step-by-step explanation:The answer is 45

Probability helps us to know the chances of an event occurring. The probability of tossing heads and rolling a number less than 3 is 1/6.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The number of cases where coins land on heads and a number less than 3 are rolled is 2, which are H1 and H2.

The probability of tossing heads and rolling a number less than 3 is,

Probability = (Outcomes where coins land on heads and a number less than 3 are rolled)/(Total number of cases)

Probability = 2/12 = 1/6

Hence, the probability of tossing heads and rolling a number less than 3 is 1/6.

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