Need help asap I am confused and this is making my brain hurt

Answer:

0.07

Explanation:

Huge Brain

Coefficient of friction between the car and the ground will be 0.07.    

    Given in the question,

Force applied on the car by which the car is accelerated,

F = ma

  = 3000 × 3

  = 9000 N

Force [tex]F_k[/tex] to overcome the friction = 11000 - 9000

                                                         = 2000 N

Gravitational force F' on the car = mg

                                                       = 3000(9.8)

                                                       = 29400 N

Since, [tex]\mu_k=\frac{F_k}{F'}[/tex]

                [tex]=\frac{2000}{29400}[/tex]

                [tex]=0.068[/tex]

                ≈ 0.07

   Therefore, coefficient of friction between the car and the ground will be 0.07.    

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Answer:

The first choice (32m/s) is the closest to the answer

Explanation:

The magnitude of a vector is the distance between the initial and the end point of the vector.

Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

[tex]\mid \vec{V} \mid =\sqrt{V_x^2+V_y^2}[/tex]

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.

Calculate the magnitude of the velocity:

[tex]\mid \vec{V} \mid =\sqrt{28^2+15^2}[/tex]

[tex]\mid \vec{V} \mid =\sqrt{784+225}[/tex]

[tex]\mid \vec{V} \mid =\sqrt{1009}[/tex]

[tex]\mid \vec{V} \mid =31.8 \ m/s[/tex]

The first choice (32m/s) is the closest to the answer

Answer:

bada bop boop pow

Explanation:

answer:

MAXIMUM SPEED

explanation:

IM SURE THAT IS THE ANSWER

Answer:

Velocity

Explanation:

If the position-time graph of the motion of an object is a straight line, it would mean that the object is moving uniformly. The velocity or the slope of the object is constant in such case. If the slope is curved line, it means that the velocity is not constant.

Hence, the correct option is (c).

Answer:

14.4m/s

Explanation:

To calculate the final velocity (V), we use the formula:

v = u + at

Where; v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

According to the provided information in this question, v = ?, u = 0m/s, a = 1.8m/s², t = 8s

Hence, v = u + at

v = 0 + (1.8 × 8)

v = 0 + 14.4

v = 14.4m/s

Therefore, his final velocity at the end of those 8 seconds is 14.4m/s.

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

Answer:

100...................

Answer:

The time taken before the axe hits the ground is 0.385 s.

Explanation:

Given;

initial velocity, u = 50 m/s

height above ground, h = 20 m

To determine the time taken before the axe hits the ground, apply the following kinematic equation;

h = ut + ¹/₂gt²

20 = 50t + ¹/₂(9.8)t²

20 = 50t + 4.9t²

4.9t² + 50t - 20 = 0

Solve this quadratic equation;

a = 4.9, b = 50, c = -20

t = 0.385 s

Therefore, the time taken before the axe hits the ground is 0.385 s.

Answer:

c) marketing and selling products that use ore materials

Answer:

seminal glands or vesicular glands

Answer:

b

Explanation:

Answer:

B

Explanation:

Compression is the region of high pressure in a medium caused by a pressure wave.

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#SPJ2

They try not to influence the subjects

Explanation:

Answer:(0,2)

Explanation:

Take origin (0,0) as point A and when you move one block east to point B then coordinates becomes (1,0)

Now you move 4 blocks north to point C then the coordinates of point C becomes (4,1)

Similarly, You move 1 block west to point D such that its co-ordinates becomes (0,4)

Finally you move from D to E, 2 blocks south such that point E becomes (0,2)

So, E is the friend's house and its coordinates are (0,2)

It can be diagramatically be represented by figure given below

Answer:

The target is 2 meters ahead of you.

If you throw the snowball with a velocity S, then the time that the snowball will need to hit the target is:

2m/S = T

Now let's analyze the vertical problem.

The only force acting on the snowball is the gravitational force, then the acceleration will be -g = -9.8m/s^2.

a(t) = -9.8m/s^2

For the vertical velocity, we need to integrate over time and get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, in this case is zero because the ball is thrown horizontally.

v(t) = (-9.8m/s^2)*t

For the vertical position, we integrate again over time.

p(t) = (-4.9m/s^2)*t^2 + p0.

Now, we know that when the ball hit the target, it hits 9 meters below the desired point (where the desired point is p0), so p(2m/S) = p0 - 9m.

Then we have:

(-4.9m/s^2)*(2m/S)^2 = -9m.

We need to solve this for S.

(-4.9m/s^2)*4m^2/-9m = S^2

2.178 m^2/s^2 = S^2

√(2.178 m^2/s^2) = S = 1.48 m/s

The horizontal velocity is 1.48 m/s

Answer:

there was 9 but pluto got kicked out of the solar System so 8

Answer:

Taking it was dropped with inital velocity of 0m/s.

v = u+at

v = 0 + 9.8*1.5

v = 14.7s

(a=9.8m/s^2 << That's the acceleration due to gravity)

Explanation:

Answer:

1 Solid ball, no subatomic particles.

4 Solid ball of positive materials with electrons scattered throughout. (Plum Pudding Model)

3 # The atom is mostly empty space. A dense nucleus with protons and neutrons is in the center and electrons travel around it randomly.

2 A dense nucleus with protons and neutrons is in the center of the atom. The electrons travel around the nucleus in distinct energy levels.

Сл A dense nucleus with protons and neutrons in the center of the atom. The electrons are found in "electron clouds" which surround the nucleus. Electron cloud show where electrons are likely to be, but not exactly where they are.

Explanation:

1 Solid ball, no subatomic particles. This model was proposed by some Greek Philosophers and John Dalton in 1803. That matter was made up of small indivisible substances called atoms.

4 Solid ball of positive materials with electrons scattered throughout. (Plum Pudding Model). This model was proposed by JJ Thomson in 1904. That the atom contained a large positively charged ball with negative charges scattered about.

3 # The atom is mostly empty space. A dense nucleus with protons and neutrons is in the center and electrons travel around it randomly. This model was proposed by Ernest Rutherford in 1911. The center of the atom was dense and positively charged with protons and neutrons surrounded by electrons orbiting it and most of the space between the nucleus and the electron orbit empty.

2 A dense nucleus with protons and neutrons is in the center of the atom. The electrons travel around the nucleus in distinct energy levels. This model was proposed by Niels Bohr in 1913. This was due to the fact that atoms only emit light at certain wavelengths which would imply that they have discrete energy levels which the electrons are contained in.

Сл A dense nucleus with protons and neutrons in the center of the atom. The electrons are found in "electron clouds" which surround the nucleus. Electron cloud show where electrons are likely to be, but not exactly where they are. This model was proposed by Erwin Schrodinger in 1926 through the solution of the Schrodinger wave equation. The position of the electron is assumed to to be a probability in an electron cloud.

The level of flexibility will affect my performances in football. Football

requires some level of flexibility to do certain things.

Flexibility will enable me change speed and direction easily when there is a

counter attack by the opponents. It will also assist in using some techniques

such as adding more curve on the football with the feet in order to score

goals.

Flexibility will also ensure that there will be lesser injury concerns because there will be less sprains or other muscle related injuries.

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Answer:

300,000

Explanation:

Answer:

300m per minute or 5m per second

Answer:

The temperature at which a liquid boils and turns to vapor.

Explanation:

Boiling point, temperature at which the pressure exerted by the surroundings upon a liquid is equaled by the pressure exerted by the vapour of the liquid; under this condition, addition of heat results in the transformation of the liquid into its vapour without raising the temperature. therefore the water is at its boiling point.

Answer:

When a substance starts to boil, like 212° F, that is considered boiling point.

Answer:

99n

Explanation:

Answer:

Its true i think

Explanation:

Time required : 3 s

Power is the work done/second.

[tex]\tt P=\dfrac{W}{t}\\\\P=power,j/s,watt\\\\W=work, J\\\\t=times=s[/tex]

To do 33 J of work with 11 W of power

P = 11 W

W = 33 J

[tex]\tt t=\dfrac{W}{P}\\\\t=\dfrac{33}{11}\\\\t=\boxed{\bold{3~s}}[/tex]

I'm pretty sure its compound