Mr. Agber needs to employ 48 workers to cultivate his 8 acres of farmland in 6 days. The exact relationship between the parameters is W × D = K × L, and the constant (K) in this case is 36.
To solve this problem, we can use the concept of direct variation. The relationship between the number of workers, the size of the land, and the number of days can be expressed as follows:
Number of Workers (W) × Number of Days (D) = Constant (K) × Size of the Land (L)
In Mr. Agber's case, we know the initial situation is:
20 workers × 9 days = K × 5 acres
To find the constant, K, we can rearrange the equation:
K = (20 workers × 9 days) / 5 acres
K = 180 / 5
K = 36
Now that we have the constant, we can use it to determine the number of workers needed for the 8 acres of land in 6 days:
W × 6 days = 36 × 8 acres
Again, rearrange the equation to find the number of workers, W:
W = (36 × 8 acres) / 6 days
W = 288 / 6
W = 48 workers
So, Mr. Agber needs to employ 48 workers to cultivate his 8 acres of farmland in 6 days. The exact relationship between the parameters is W × D = K × L, and the constant (K) in this case is 36.
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Three-fifths of seventh graders have a cell phone. in a seventh grade class of 450, how many students would you predict to have a cell phone
270 students in a seventh-grade class of 450 would have a cell phone which denotes three-fifths of seventh graders using fractions.
Total number of students = 450
Percent of students who have cell phones = 3/5 th
In a class, if there are three-fifths of students have cell phones, that means we need to calculate the remaining percent of students who did not have cell phones.
Students without cell phones = 1 - 3/5 = 2/5
The total number of students with cell phones = (3/5) x 450
The total number of students with cell phones = 270
Therefore, we can conlcude that 270 students in a seventh-grade class of 450 would have a cell phone.
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1. If tan theta < 0 and sec theta > 0, which quadrant(s) could the terminal side of theta lie?
2. If csc theta > 0, which quadrant(s) could the terminal side of theta lie?
3. If sin theta < 0 and cot theta < 0, which quadrant(s) could the terminal side of theta lie?
I need help really quick, thank you to whoever can help! :)
If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant.
If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant.
If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant.
1. If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant. This is because tan theta is negative in the second and fourth quadrants, and sec theta is positive in the first and fourth quadrants.
2. If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant. This is because csc theta is positive in the first and second quadrants.
3. If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant. This is because sin theta is negative in the third and fourth quadrants, and cot theta is negative in the second and third quadrants.
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Pentagon A'B'C'D'E'A
′
B
′
C
′
D
′
E
′
A, prime, B, prime, C, prime, D, prime, E, prime is the image of pentagon ABCDEABCDEA, B, C, D, E under a dilation with a scale factor of \dfrac{1}{2}
2
1
start fraction, 1, divided by, 2, end fraction.
The length of segment C'D' is given as follows:
C'D' = 2.
What is a dilation?A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.
The length of segment CD is given as follows:
CD = 4. (4 vertical units of difference).
The scale factor is given as follows:
k = 1/2.
Hence the length of segment C'D' is given as follows:
C'D' = 1/2 x 4 = 2.
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The diameter of Circle Q terminates on the circumference of the circle at (0,3)and (0,−4). Write the equation of the circle in standard form. Show all of your work.
Need answer ASAP Please!!
Answer:
[tex]x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}[/tex]
Step-by-step explanation:
The center of the circle is the midpoint of its diameter.
[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}[/tex]
Given the endpoints of the diameter are (0, 3) and (0, -4), to find the coordinates of the center of the circle, substitute the two endpoints into the midpoint formula:
[tex]\text{Center}=\left(\dfrac{0+0}{2},\dfrac{-4+3}{2}\right)=\left(0,-\dfrac{1}{2}\right)[/tex]
As the x-values of the endpoints of the diameter are the same, the length of the diameter, d, is the absolute value of the difference in y-values of the endpoints:
[tex]d=|3-(-4)|=7[/tex]
Therefore, the diameter of circle Q is 7 units.
The radius, r, of a circle is half its diameter. Therefore:
[tex]r=\dfrac{d}{2}=\dfrac{7}{2}[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]
Now we have determined the center and radius of circle Q, we can substitute these values into the equation of a circle to write the equation of circle Q in standard form:
[tex](x-0)^2+\left(y-\left(-\dfrac{1}{2}\right)\right)^2=\left(\dfrac{7}{2}\right)^2[/tex]
[tex]x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}[/tex]
Therefore, the equation of circle Q in standard form is:
[tex]\boxed{x^2+\left(y+\dfrac{1}{2}\right)^2=\dfrac{49}{4}}[/tex]
Triangle NMO is drawn with vertices N(−4, −2), M(−1, −1), O(−4 , −5). Determine the image coordinates of N′M′O′ if the preimage is translated 7 units to the left.
A- N′(3, −2), M′(6, −1), O′(3, −5)
B- N′(−4, −9), M′(−1, −8), O′(−4, −12)
C- N′(−4, 5), M′(−1, 6), O′(−4, 2)
D- N′(−11, −2), M′(−8, −1), O′ (−11, −5)
The image coordinates of N′M′O′ if the preimage is translated 7 units to the left is D- N′(−11, −2), M′(−8, −1), O′ (−11, −5)
What is image coordinates?A triangle is seen as a closed, two-dimensional geometric figure that has three straight sides and three angles.
To get the image coordinates of the preimage translated 7 units to the left, we simply subtract 7 from the x-coordinates of each vertex:
N' = (Nx - 7, Ny) = (−4 - 7, −2) = (−11, −2)
M' = (Mx - 7, My) = (−1 - 7, −1) = (−8, −1)
O' = (Ox - 7, Oy) = (−4 - 7, −5) = (−11, −5)
Therefore, the image coordinates of NMO after the translation 7 are: N′(−11, −2), M′(−8, −1), O′ (−11, −5)
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Two factories blow their whistles at exactly the same time. If a man hears the two blasts exactly
4. 2 seconds and 5. 9 seconds after they are blown and the angle between his lines of sight to the two
factories is 40. 8°, how far apart are the factories? Give your result to the nearest meter. (Use the fact
that sound travels at 344 m/sec. )
A) 2903 meters
B) 3263 meters C) 1329 meters D) 1997 meters
The distance between the factories is approximately 1704 meters.
To solve this problem, we can use the Law of Cosines. Let's denote the distance between the man and Factory 1 as x, the distance between the man and Factory 2 as y, and the distance between the factories as z.
Given that the time difference for the man to hear the blasts from Factory 1 and Factory 2 is 4.2 seconds and 5.9 seconds respectively, we can calculate x and y using the speed of sound (344 m/s):
x = 4.2 seconds * 344 m/s = 1444.8 meters
y = 5.9 seconds * 344 m/s = 2030.4 meters
Now, we apply the Law of Cosines using the given angle of 40.8°:
z² = x² + y² - 2xy * cos(40.8°)
z² = 1444.8² + 2030.4² - 2(1444.8)(2030.4) * cos(40.8°)
z² ≈ 2904106.33
Take the square root to find the distance between the factories:
z ≈ √2904106.33 ≈ 1704.14 meters
Rounded to the nearest meter, the distance between the factories is approximately 1704 meters. However, this answer is not included in the given options. There might be an error in the question or the provided options.
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Analyze the diagram below and answer the question that follows.
P
20
10
gg
70
110
A. ZVOU and ZUOS
B. ZROS and ZTOS
C. ZNOP and ZROS
D. ZNOP and ZPOQ
R
80
IN
Image by Scientif38
Name two angles with identical measures.
S
10 110 120
130
ΤΑ
140 150 160 170
30
10
U
By observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.
What is a protractor?An instrument for measuring angles is a protractor, which is often made of transparent plastic or glass.
Protractors might be straightforward half-discs or complete circles. Protractors with more complex features, like the bevel protractor, include one or two swinging arms that can be used to measure angles.
To draw arcs or circles, use a compass.
To measure angles, one uses a protractor.
So, we need to observe the given image of the protractor:
We will easily find that ∠NOP = ∠ROS
Therefore, by observing the given protractor we know that option (C) is correct which says ∠NOP = ∠ROS.
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A closed rigid system has a volume of 85 litres contains steam at 2 bar and dryness fraction of 0.9. calculate the quantity of heat which must be removed from the system in order to reduce the pressure to 1.6 bar. also determine the change in enthalpy and entropy per unit mass of the system
The quantity of heat which must be removed from the system in order to reduce the pressure from 2 bar to 1.6 bar is 4.23 kJ. The change in enthalpy per unit mass of the system is -123 kJ/kg, and the change in entropy per unit mass of the system is 0.134 kJ/kg-K.
To solve this problem, we need to use the steam tables to determine the properties of the steam at the initial and final conditions. We will assume that the system is undergoing a reversible, adiabatic process, so there is no heat transfer into or out of the system.
First, we determine the specific volume and enthalpy of the steam at the initial conditions of 2 bar and 0.9 dryness fraction. From the steam tables, we find that the specific volume is 0.4019 m^3/kg and the specific enthalpy is 2895.5 kJ/kg.
Next, we use the steam tables to find the specific volume and enthalpy of the steam at the final conditions of 1.6 bar. We find that the specific volume is 0.5059 m^3/kg and the specific enthalpy is 2772.5 kJ/kg.
The change in specific enthalpy per unit mass of the system is then given by:
Δh = h2 - h1 = 2772.5 - 2895.5 = -123 kJ/kg
The change in specific entropy per unit mass of the system is given by:
Δs = s2 - s1 = s2 - s1 = s2 - sf - x2*(sg - sf)
where sf and sg are the specific entropy of saturated liquid and saturated vapor at the final pressure of 1.6 bar, and x2 is the final dryness fraction. From the steam tables, we find that sf = 7.4332 kJ/kg-K, sg = 8.1248 kJ/kg-K, and x2 = 0.714.
Thus, we have:
Δs = s2 - s1 = s2 - sf - x2*(sg - sf) = (7.9757 - 7.4332) - 0.714*(8.1248 - 7.4332) = 0.134 kJ/kg-K
Finally, we can calculate the quantity of heat that must be removed from the system using the first law of thermodynamics:
Q = m*(h1 - h2) = m*Δh
where m is the mass of the steam in the system. To determine the mass of the steam, we use the specific volume at the initial conditions:
V = m/v1
where V is the volume of the system and v1 is the specific volume at the initial conditions. Substituting the given values, we have:
V = 85 L = 0.085 [tex]m^3[/tex]
m = Vv1 = 0.0850.4019 = 0.0344 kg
Substituting this value into the equation for Q, we obtain:
Q = mΔh = 0.0344(-123) = -4.23 kJ
Therefore, the quantity of heat which must be removed from the system in order to reduce the pressure from 2 bar to 1.6 bar is 4.23 kJ.
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Examine this system of equations. What integer should the first equation be multiplied by so that when the two equations are added together, the x term is eliminated?
StartFraction 1 Over 18 EndFraction + four-fifths y = 10
Negative five-sixths x minus three-fourths y = 3
Answer:
To solve this problem, we need to find an integer to multiply the first equation by so that when we add the two equations together, the x term is eliminated. Let's first rearrange the equations to make them easier to work with:
1/18 x + 4/5 y = 10
-5/6 x - 3/4 y = 3
To eliminate the x term, we need to multiply the first equation by a certain integer so that when we add it to the second equation, the x terms cancel out. To do this, we need to find a common multiple of the denominators of the x coefficients in both equations, which are 18 and -6. The least common multiple of 18 and -6 is 18, so we can multiply the first equation by 18:
18(1/18 x + 4/5 y = 10)
Simplifying this equation, we get:
x + 72/5 y = 180
Now we can add this equation to the second equation:
x + 72/5 y = 180
-5/6 x - 3/4 y = 3
Multiplying the second equation by 15 to get rid of the fractions, we get:
-25/2 x - 45/4 y = 45
Now we can add the two equations together to eliminate the x term:
-25/2 x + x + 72/5 y - 45/4 y = 180 + 45
Simplifying this equation, we get:
-13/20 y = 225/4
Multiplying both sides by -20/13, we get:
y = -450/13
Therefore, the integer we need to multiply the first equation by is 18, which corresponds to option B.
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Which algebraic expression is equivalent to the expression below? 25/4(5x-4/5)+29 A. 125/4x + 24 B.125/4x + 34 C. 125/4x - 24 D.125/4x - 34
The algebraic expression is equivalent to the expression is 125/4x + 34. Option B
What are algebraic expressions?Algebraic expressions are simply defined as expressions that are composed of terms, variables, constants, coefficients and factors.
These algebraic expressions are also composed of mathematical operations, such as;
AdditionsubtractioMultiplicationDivisionBracketParenthesesFrom the information given, we have;
25/4(5x-4/5)+29
expand the bracket, we get;
125x - 100/5 + 29
Find the LCM, we get;
125x - 100 + 145/5
Divide the values
125/4x + 34
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what are 2, 3, and 4
1. The area of square C is 625 ft². 2. The perimeter of square C is 46 ft. 3. The area of square B is 1456 ft². 4. The length of square A is 4√15 ft.
What is Pythagoras theorem?A key idea in geometry that connects the lengths of a right triangle's sides is known as the Pythagorean Theorem. It says that the hypotenuse's square length, which is the side that faces the right angle, is equal to the sum of the squares of the lengths of the other two sides in a right triangle. It has the following mathematical expression:
a² + b² = c²
1. The area of square C can be found using the Pythagorean Theorem:
a² + b² = c²
Using the area the side is calculates as follows:
Side length of A = √225 = 15 ft
Side length of B = √400 = 20 ft
Now,
15² + 20² = c²
225 + 400 = c²
625 = c²
c = √625 = 25 ft
So the area of square C is:
Area of C = 25² = 625 ft²
2. The perimeter of square C can be found by adding up the side lengths of all three squares:
Perimeter of A = 36 ft, so each side length of A is 9 ft.
Perimeter of B = 48 ft, so each side length of B is 12 ft.
Perimeter of C = Side length of A + Side length of B + Side length of C
Perimeter of C = 9 + 12 + c
We found earlier that c = 25 ft, so we can substitute that in:
Perimeter of C = 9 + 12 + 25 = 46 ft
3. The area of square B can be found using the fact that the areas of squares A, B, and C are related by the equation:
Area of A + Area of B = Area of C
We know the area of A and the area of C, so we can solve for the area of B:
Area of A = 15² = 225 ft²
Area of C = 1681 ft²
Area of A + Area of B = Area of C
225 + Area of B = 1681
Area of B = 1456 ft²
4. Perimeter of B = 64 ft
Side length of B = 64 / 4 = 16 ft
Now we can use the Pythagorean Theorem to find the side length of C:
a² + b² = c²
a = 15 ft (side length of A)
b = 16 ft (side length of B)
c = √(a² + b²) = √(15² + 16²) = √481 = 22 ft
Finally, we can use the Pythagorean Theorem again to find the side length of A:
a² + b² = c²
b = 16 ft (side length of B)
c = 22 ft (side length of C)
a = √(c² - b²) = √(22² - 16²) = √240 = 4√15 ft
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subtract -10x+3 from -7x^2 +5x +10
Answer:
-7x^2 + 15x +7
Step-by-step explanation:
-7x^2 + 5x + 10 - (-10x + 3)
-7x^2 + 5x + 10 + 10x -3.......when u distribute it multiple by -1
-7x^2 + 15x +7 ...... simplify by collecting like term.
32
{(-0. 25, 2. 5), (1. 75, -5. 5), (3. 25, -11. 5)}
Write an equation in the form of y = mx + b that represents this linear function?
Therefore, the equation in the form of y = mx + b that represents this linear function is: y = -3.2x + 0.1
To write an equation in the form of y = mx + b for a linear function, we need to find the slope (m) and the y-intercept (b).
We can use any two points from the given set of points to find the slope:
m = (y2 - y1) / (x2 - x1)
Let's use the first and second points:
m = (-5.5 - 2.5) / (1.75 - (-0.25))
m = -8 / 2.5
m = -3.2
Now, we can use the slope and one of the points to find the y-intercept:
y = mx + b
-5.5 = (-3.2)(1.75) + b
b = -5.5 + 5.6
b = 0.1
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In a recent Game Show Network survey, 30% of 5000 viewers are under 30. What is the margin of error at the 99% confidence interval? Using statistical terminology and a complete sentence, what does this mean? (Use z*=2. 576)
Margin of error:
Interpretation:
The margin of error at the 99% confidence interval is 0.018 or 1.8%.
Interpretation: This means that if we were to repeat the survey many times, about 99% of the intervals calculated from the samples would contain the true proportion of viewers under 30 in the population, and the margin of error for each interval would be no more than 1.8%.
The margin of error is the amount by which the sample statistic (in this case, the proportion of viewers under 30) may differ from the true population parameter.
Using the given formula for margin of error:
Margin of error = z* * sqrt(p*(1-p)/n)
Where:
- z* is the z-score corresponding to the confidence level (99% in this case), which is 2.576
- p is the proportion of viewers under 30, which is 0.3
- n is the sample size, which is 5000
Substituting these values, we get:
Margin of error = 2.576 * sqrt(0.3*(1-0.3)/5000) = 0.018
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Select the correct answer from each drop-down menu.
Coach Loren asks Kerry to analyze the batting percentages of players on the softball team.
Complete the sentences with the correct terms.
Coach Loren wants one number to describe how all of the values in the data set vary, so Kerry should tell her to use a measure of
.
Kerry could give her the
or the
of the data set.
Answer:
Kerry could give her the range or the standard deviation of the data set.
Step-by-step explanation:
Coach Loren wants one number to describe how all of the values in the data set vary, so Kerry should tell her to use a measure of variability.
Kerry could give her the range or the standard deviation of the data set.
How could you use a set of coin flips to simulate this situation?
Answer:
Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.
Step-by-step explanation:
Many artists incorporate geometry shapes into their art. an artist wants to make a sculpture shaped like a cone with a height of 4.2 inches and a radius of 2.5 inches.the artist needs to know the volume of the sculpture to purchase the correct amount of materials
part a. which equation shows the art is used to calculate the volume of a cone with the given measurements
part b. what is the volume,in cubic inches,of the cone? use 3.14 for pie and round your answer to the nearest tenth
The volume of the cone is approximately 26.1 cubic inches.
What is the equation used to calculate the volume of a cone with a radius of 2.5 inches and a height of 4.2 inches?The formula used to calculate the volume of a cone is:
V = (1/3) × π ×[tex]r^2[/tex] × h
where V is the volume of the cone, r is the radius of the base of the cone, h is the height of the cone, and π is a mathematical constant that is approximately equal to 3.14.
Part b. Plugging in the given values, we get:
V = (1/3) × 3.14 ×[tex]2.5^2[/tex]× 4.2
V = (1/3) × 3.14 × 6.25 × 4.2
V = 26.125 cubic inches (rounded to the nearest tenth)
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A glass prism on a chandelier is 93 millimeters long. A base of the prism is an equilateral triangle with side lengths of 7 millimeters and a height of about 6. 6 millimeters. What is the approximate surface area of the prism?
The approximate surface area of the glass prism is approximately 1986.66 square millimeters.
To find the surface area of the glass prism, we need to determine the area of each of its faces and then add them together. The prism consists of two congruent equilateral triangles and three rectangular faces.
The area of an equilateral triangle with side length s and height h is given by:
A = (√(3)/4) * s²
Using this formula, we can find the area of each of the two equilateral triangles in the prism:
A = (√(3)/4) * 7² ≈ 21.22 mm²
Next, we need to find the area of each of the three rectangular faces. The length of each rectangular face is equal to the side length of the equilateral triangle (7 mm), and the height is equal to the length of the prism (93 mm). Therefore, the area of each rectangular face is:
A = length x height = 7 mm x 93 mm = 651 mm²
To find the total surface area of the prism, we add the areas of the two equilateral triangles and the three rectangular faces:
Total surface area ≈ 2 x 21.22 mm² + 3 x 651 mm² ≈ 1986.66 mm²
Therefore, the approximate surface area of the glass prism is approximately 1986.66 square millimeters.
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Find the gradients of the lines a and b
The gradient of line A and B are 4 and - 2 respectively.
How to find the gradient or slope of a line?The gradient or slope of a line is a the change in the dependent variable with respect to the change in the independent variable.
Therefore, let's find the gradient of line a and b as follows:
(2, -1)(3, 3)
Gradient of line A = 3 + 1 / 3 - 2
Gradient of line A = 4 / 1
Gradient of line A = 4
Therefore,
(0, 1)(1, -1)
Gradient of line B = -1 - 1 / 1 - 0
Gradient of line B = - 2 / 1
Gradient of line B = - 2
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In a random sample of large cities around the world, the ozone level (in parts per million) and the population (in millions) were measured. Fitting the simple linear regression model gave the estimated regression equation: ozone⌢ = 8. 89 + 16. 6 population. (pretend it's a hat)
Interpret b = 16. 6. For each additional ________________________
million people, the predicted ozone level increases ___________________
ppm.
Rascoville is a large city with a population of 3 million people. What is the average ozone level? __________________________
If the ozone level is approximately 142 ppm, what is the approximate population in millions (round to the nearest million)? __________________________________
Interpretation:
The regression coefficient b = 16.6 represents the change in the predicted ozone level (in parts per million) for each additional million people in the population.
Specifically, for each additional million people, the predicted ozone level is expected to increase by 16.6 parts per million.
For Rascoville, a city with a population of 3 million people, we can use the estimated regression equation to predict the average ozone level:
ozone⌢ = 8.89 + 16.6 × 3 = 8.89 + 49.8 = 58.69
Therefore, the predicted average ozone level for Rascoville is 58.69 parts per million.
If the ozone level is approximately 142 ppm, we can use the estimated regression equation to estimate the population:
142 = 8.89 + 16.6 × population
Solving for population, we get:
133.11 = 16.6 × population
population ≈ 8.02 million
Therefore, the approximate population of the city is 8 million people (rounded to the nearest million).
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Para el periódico mural, los alumnos decidieron representar un pino por medio de un triángulo que tiene una superficie de 1. 5m si la base mide 1. 5 m ¿cuanto mide la altura? 
La fórmula para calcular el área de un triángulo es:
área = base * altura / 2
Podemos despejar la altura de esta fórmula y sustituir los valores que conocemos:
área * 2 / base = altura
1.5 * 2 / 1.5 = 2
Por lo tanto, la altura del triángulo es de 2 metros.
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What is the value of x in degrees?
Please show work if you can!
Answer: 72
Step-by-step explanation:
Q is same as M = 72
N=36
L=x
All 3 angles of a triangle add to 180
72+36+x=180
x=72
The profit (in dollars) from the sale of a palm trees is given by:
P(a) = 20x - 0.1x^2 - 100.
Find the profit at a sales of 13 trees
On a company's income statement, gross profit is computed by subtracting the cost of goods sold (COGS) from revenue. (sales),so the sale of palm tree is $143.10.
To find the profit from the sale of 13 palm trees, we need to substitute 13 for x in the profit function:
P(13) = 20(13) - 0.1(13)^2 - 100
P(13) = 260 - 16.9 - 100
P(13) = $143.10
Therefore, the profit from the sale of 13 palm trees is $143.10.
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answer this geometry question and show work!!
Answer:
x = 58°
Step-by-step explanation:
Label the point where the diagonals cross as T
Diagonals always meet at right angles
m∠SRT = 32
Sum of interior angles of ΔSRT = 180
x = 180 - 90 - 32 = 58
What occurs when a white dwarf in a binary star system if it gains mass beyond the chandrasekhar limit?.
If a white dwarf in a binary star system gains mass beyond the Chandrasekhar limit (approximately 1.4 solar masses), it undergoes a runaway nuclear reaction, causing it to collapse and explode in a Type Ia supernova.
A white dwarf is a dense stellar remnant that is left behind after a star has exhausted all its nuclear fuel and has shed its outer layers. In a binary star system, the white dwarf may gain mass from its companion star, either through accretion or a merger. If the mass of the white dwarf exceeds the Chandrasekhar limit, the gravitational forces become so strong that the electrons in the atoms are forced to combine with the atomic nuclei, forming neutrons. This process is called electron capture, and it releases a tremendous amount of energy.
The energy released is enough to ignite a runaway nuclear reaction, causing the white dwarf to collapse and explode in a Type Ia supernova. Type Ia supernovae are important cosmic events because they are used as standard candles to measure the distance to distant galaxies. These explosions are also believed to play a significant role in the chemical evolution of the universe, as they produce heavy elements such as iron and nickel that are scattered into the interstellar medium.
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Calculate the partial derivative, using implicit differentiation of e⁷xy + sin (5xz) + 4y = 0. (Use symbolic notation and fractions/where needed.) dz/dy
The partial derivative using implicit differentiation is:
[tex]dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]
To calculate the partial derivative of the given equation with respect to y (dz/dy), we'll use implicit differentiation. The given equation is:
[tex]e^(7xy) + sin(5xz) + 4y = 0[/tex]
First, differentiate both sides of the equation with respect to y:
[tex]d(e^(7xy))/dy + d(sin(5xz))/dy + d(4y)/dy = 0[/tex]
Apply the chain rule for the first and second terms:
[tex](7x * e^(7xy)) * (dx/dy) + (5x * cos(5xz)) * (dz/dy) + 4 = 0[/tex]
Now, we are interested in finding dz/dy. To solve for it, rearrange the equation:
[tex](5x * cos(5xz)) * (dz/dy) = -7x * e^(7xy) * (dx/dy) - 4Finally, divide by (5x * cos(5xz)) to isolate dz/dy:dz/dy = (-7x * e^(7xy) * (dx/dy) - 4) / (5x * cos(5xz))[/tex]
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the aspect ratio of a wide screen tv is 2.39:1. what is the length of the diagonal of a wide screen tv screen with an area of 150 in??
The length of the diagonal of a wide screen TV with an area of 150 inches and an aspect ratio of 2.39:1 is approximately 11.25 inches.
Aspect ratio refers to the proportional relationship between the width and height of an image or screen. In the case of a wide screen TV, the aspect ratio is 2.39:1, which means that for every 2.39 units of width, there is 1 unit of height.
To find the length of the diagonal of a wide screen TV with an area of 150 inches, we need to use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the width and height.
First, we need to find the width and height of the TV screen. We can do this by setting up the equation:
2.39x^2 = 150
where x is the width of the screen. Solving for x, we get:
x = √(150/2.39) = 10.87 inches
Now we can find the height by dividing the width by the aspect ratio:
h = 10.87 / 2.39 = 4.55 inches
Using the Pythagorean theorem, we can find the length of the diagonal:
d^2 = 10.87^2 + 4.55^2 = 126.68
d = √126.68 = 11.25 inches
Therefore, the length of the diagonal of a wide screen TV with an area of 150 inches and an aspect ratio of 2.39:1 is approximately 11.25 inches.
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The answer and what is the value of a
Answer:a=40
Step-by-step explanation:
angles on a straight line add to 180. This means that the missing angle that isn't a is 40. Angles in a triangle add to 180 so a=40
let f be the function defined above. what is the integral of f(x) from -1 to 1
The value of given function [tex]\int\limits^1_{-1}[/tex]f(x)dx is equal is 5/6. So, correct option is A.
To find the integral of f(x) from -1 to 1, we need to split the interval [-1,1] into three parts, where f(x) is defined differently.
For x < 0, f(x) = x², so the integral of f(x) from -1 to 0 is:
[tex]\int\limits^0_{-1}[/tex](x²)dx = (-1/3)x³ evaluated at x=0 and x=-1 = (-1/3)(0 - (-1)) = 1/3
For x = 0, f(x) = -1, so the integral of f(x) at x=0 is simply -1.
For x > 0, f(x) = x, so the integral of f(x) from 0 to 1 is:
[tex]\int\limits^1_{0}[/tex](x)dx = (1/2)x² evaluated at x=1 and x=0 = (1/2)(1 - 0)² = 1/2
Therefore, the integral of f(x) from -1 to 1 is:
[tex]\int\limits^1_{-1}[/tex]f(x)dx = [tex]\int\limits^0_{-1}[/tex](x²)dx + [tex]\int\limits^0_{0}[/tex](-1)dx + [tex]\int\limits^1_{0}[/tex](x)dx
= 1/3 + (-1) + 1/2
= 5/6
Thus, the correct answer is (a) 5/6.
So, correct option is A.
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11. A town that uses 68 million BTUs of energy each month is using how many kilowatt-hours of
energy? (1 kWh-3400 BTUS)
Answer:
[tex]20,000 \text{ kWh}[/tex]
Step-by-step explanation:
We can convert 68 million British Thermal Units (BTUs) to kilowatt-hours (kWh) using the given conversion ratio:
[tex]\dfrac{1 \text{ kWh}}{3400 \text{ BTUs}}[/tex]
Multiplying by the ratio:
[tex]68,000,000 \text{ BTUs} \cdot \dfrac{1 \text{ kWh}}{3,400 \text{ BTUs}}[/tex]
↓ canceling the BTU units
[tex]68,000,000\cdot \dfrac{1 \text{ kWh}}{3,400}[/tex]
↓ executing multiplication
[tex]\dfrac{68,000,000}{3,400} \text{ kWh}[/tex]
↓ rewriting as a decimal
[tex]\boxed{20,000 \text{ kWh}}[/tex]
