i need help with this geometry question
Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS = [tex]\sqrt{240}[/tex] ≈ 15.5 ( to 1 dec. place )
Acontinous random variable X has a pdf given by p(x) = (5x4 0≤x≤1 0, otherwise) Let Y=X3. Find the probability distribution function
I'll use the method of transformations.
If [tex]f_X(x)[/tex] denotes the PDF of [tex]X[/tex], and [tex]y=g(x)=x^3 \iff x=g^{-1}(y) = y^{1/3}[/tex], we have
[tex]f_Y(y) = f_X\left(g^{-1}(y)\right) \left|\dfrac{dg^{-1}}{dy}\right|[/tex]
[tex]\dfrac{dg^{-1}}{dy} = \dfrac13 y^{-2/3}[/tex]
[tex]\implies f_Y(y) = f_X\left(y^{1/3}\right) \left|\dfrac13 y^{-2/3}\right| = \boxed{\begin{cases} \dfrac53 y^{2/3} & \text{if } 0 \le y \le 1 \\ 0 & \text{otherwise} \end{cases}}[/tex]
which ordered pair is a solution to the following system of inequalities
Answer:
it's 1,1 is the correct ans
Step-by-step explanation:
Because my teacher told its absolutely correct answer I got the same question in exam
Answer:
the answer should be the 2 one
Step-by-step explanation:
I got it right just had it.
Which of the following best describes the set of complex numbers?
OA. The set of all numbers of the form a+bi, where a and bare any
real numbers and i equals -1
B. The set of all numbers of the form abi, where a and bare any real
numbers and i equals 1
C. The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1
OD. The set of all numbers of the form abi, where a and b are any real
numbers and / equals -1
Answer:
C
Step-by-step explanation:
The correct statement is option C.
What is complex number?A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.
Since we know that
Complex number is of the form a+ib
Where,
a is real number belongs to real axis
And b is also a real number belongs to imaginary axis.
And the value of i = √-1
Thus,
The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1 is the correct statement.
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If 6^(2x)=4 find 36^(6x-2) could anyone help me please?
Answer:
3.160
Step-by-step explanation:
You can solve for x using logarithm.
Rewrite in logarithm form
[tex]log_{6}4=2x\\\\x=\frac{log_64}{2}\\x=\frac{\frac{log4}{log6}}{2}\\x=\frac{log4}{log6} * \frac{1}{2}\\x=\frac{log4}{log6 * 2}\\x\approx0.386852807\\36^{6(0.386852807)-2} \approx3.160[/tex]
Need help with algebra homework
Answer:
the answer for this problem is A, big
Which values of x and y would make the following expression represent a real number?
(4 +51)(x + yı)
O x = 4, y =
O x=-4, y = 0
Ox = 4, y = -5
O x = 0, y = 5
The values of x and y would make the following expression represent a real number is 4 and -5 respectively
Complex and real numberThe standard form of writing a complex number is given asl
z= x + iy
where
x is the real part
y is the imaginary part
Given the expression below;
(4 +5i)(x + yi)
Expand
4x + 4yi + 5ix + 5y(-1)
4x + 4yi + 5ix - 5y
Hence the values of x and y would make the following expression represent a real number is 4 and -5 respectively
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Determine whether or not each of the following is a partition of set N of natural numbers. (With reason)
(a) {{n | n > 5}, {n | n < 5}]
(b) [{n | n > 6}, {1, 3,5} , {2, 4}]
(c) {{n | n^2 > 11}, {n | n^2 < 11}
Only Set B is a partition of set N of natural numbers .
What are Natural Numbers ?Numbers starting from 1 to infinity comes under Natural Numbers.
It is asked in the question that to determine whether or not each of the following is a partition of set N of natural numbers
A ) {{n | n > 5}, {n | n < 5}]
It is not a set of natural numbers as it does not include 5.
B ) [{n | n ≥ 6}, {1, 3,5} , {2, 4}]
{1,3,5} {2,4}and {n|n≥6} include all the natural numbers
Therefore , it forms a partition of N.
C ) {{n | n^2 > 11}, {n | n^2 < 11}
Every natural number n must satisfy either n^2 > 11 or n^2 < 11
This cannot be possible , therefore it is not the partition of Natural Numbers.
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BRAIN WARM UP MATHS?
We can make 64 different equations using the power of ten.
What is the power of a number?The power of a number identifies how many times that particular number is multiplied by itself.
Here, let us assume that the different equations = x
Using a power of 10, we have 10x making a total of 640.
10x = 640Divide both sides by 10
10x/10 = 640/10
x = 64
Therefore, we can conclude that we can make 64 different equations using the power of ten.
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Sum to n terms of each of following series. (a) 1 - 7a + 13a ^ 2 - 19a ^ 3+...
Notice that the difference in the absolute values of consecutive coefficients is constant:
|-7| - 1 = 6
13 - |-7| = 6
|-19| - 13 = 6
and so on. This means the coefficients in the given series
[tex]\displaystyle \sum_{i=1}^\infty c_i a^{i-1} = \sum_{i=1}^\infty |c_i| (-a)^{i-1} = 1 - 7a + 13a^2 - 19a^3 + \cdots[/tex]
occur in arithmetic progression; in particular, we have first value [tex]c_1 = 1[/tex] and for [tex]n>1[/tex], [tex]|c_i|=|c_{i-1}|+6[/tex]. Solving this recurrence, we end up with
[tex]|c_i| = |c_1| + 6(i-1) \implies |c_i| = 6i - 5[/tex]
So, the sum to [tex]n[/tex] terms of this series is
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \underbrace{\sum_{i=1}^n i (-a)^{i-1}}_{S'} - 5 \underbrace{\sum_{i=1}^n (-a)^{i-1}}_S[/tex]
The second sum [tex]S[/tex] is a standard geometric series, which is easy to compute:
[tex]S = 1 - a + a^2 - a^3 + \cdots + (-a)^{n-1}[/tex]
Multiply both sides by [tex]-a[/tex] :
[tex]-aS = -a + a^2 - a^3 + a^4 - \cdots + (-a)^n[/tex]
Subtract this from [tex]S[/tex] to eliminate the intermediate terms to end up with
[tex]S - (-aS) = 1 - (-a)^n \implies (1-(-a)) S = 1 - (-a)^n \implies S = \dfrac{1 - (-a)^n}{1 + a}[/tex]
The first sum [tex]S'[/tex] can be handled with simple algebraic manipulation.
[tex]S' = \displaystyle \sum_{i=1}^n i (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} (i+1) (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} i (-a)^i + \sum_{i=0}^{n-1} (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=1}^{n-1} i (-a)^i + \sum_{i=1}^n (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=1}^n i (-a)^i - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a \sum_{i=1}^n i (-a)^{i-1} - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a S' - n (-a)^n + \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle (1 + a) S' = \dfrac{1 - (-a)^n - n (1 + a) (-a)^n}{1 + a}[/tex]
[tex]\displaystyle S' = \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2}[/tex]
Putting everything together, we have
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 S' - 5 S[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2} - 5 \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} =\boxed{\dfrac{1 - 5a - (6n+1) (-a)^n + (6n-5) (-a)^{n+1}}{(1+a)^2}}[/tex]
hi can you please help me with this question.
I need explanation too.
I'll like and rate your answer if your answer is right.
0 like and 1 rate for nonsense answer.
0 like and 2 rate if it's incorrect.
0 like and 3 rate if it is un-answer
1 like and 4 rate if it's correct a bit
1 like and 5 rate if it's very good answer.
Answer:
It appears to already be solved. What do you need help with?
Step-by-step explanation:
A scientist studying insects start with a population of 10. the population triples every hour. how many insects wil there be after 20 minutes
The question is asking you to understand that a population which is raised by a common ratio over a certain time period follows an exponential pattern. See:
After 1 hour, the population is 3*10
After 2 hours, the population is 3*3*10
After 3 hours, the population is 3*3*3*10
.....
This can be generalised as a function of t, the time in hours:
f(t) = (3^t) * 10
Since the function determines the population at a given time, it is more prudent to replace f(t) with P, the population after time t:
P = (3^t) * 10
Since 20 minutes is equal to (1/3) hours, t can be substituted for (1/3) in order to calculate the population size after 20 minutes:
P = (3^(1/3)) * 10 = 14.4224957031 ≈ 14
Therefore the population after 20 minutes is 14.
The point A(0,3) and point B(4,19) lie on the line L.
Find the equation of line L
Answer: The equation is y = 4x+3
Slope = 4
y intercept = 3
========================================================
Explanation:
Let's start off by finding the slope.
[tex]A = (x_1,y_1) = (0,3) \text{ and } B = (x_2,y_2) = (4,19)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{19 - 3}{4 - 0}\\\\m = \frac{16}{4}\\\\m = 4\\\\[/tex]
The slope is 4.
The y intercept is 3 because of the point (0,3)
We go from y = mx+b to y = 4x+3
m = slope
b = y intercept
---------------
Check:
Plug in x = 0 and we should get to y = 3
y = 4x+3
y = 4(0)+3
y = 0+3
y = 3
That works out. Now try x = 4. It should lead to y = 19
y = 4x+3
y = 4(4)+3
y = 16+3
y = 19
The answer is confirmed.
Over what interval is the function in this graph increasing? A. –5 ≤ x ≤ 5 B. –3 ≤ x ≤ 2 C. –4 ≤ x ≤ –2 D. –2 ≤ x ≤ 3
The function in this graph is increasing in the interval –2 ≤ x ≤ 3 , Option D is the right answer.
What is a function ?A function is a mathematical statement used to relate a dependent and an independent variable.
From the graph it can be seen that the graph is increasing in the interval
–2 ≤ x ≤ 3
The graph is said to be increasing when the value of y is getting more and more positive
As –2 ≤ x ≤ 3 , y varies from -3 to +3
Therefore Option D is the right answer.
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Answer:
–2 ≤ x ≤ 3
Step-by-step explanation:
Help me with this piecewise function!
Answer:
According to the given function, the value of h(-1) is -1, h(-0.5) is 0 and h(1) is 1.
Step-by-step explanation:
The given function says that:
If the range of the values of x is x∈(-2,-1], then the value of the function is -1.
If the range of the values of x is x∈(-1,0], then the value of the function is 0.
If the range of the values of x is x∈(0,1], then the value of the function is 1.
If the range of the values of x is x∈(1,2], then the value of the function is 2.
In the first case, we have x = -1. This satisfies the first condition. So accordingly, the value that the function will give is -1.
In the second case, we have x = -0.5. This satisfies the second condition. So accordingly, the value that the function will give is 0.
In the third case, we have x = 1. This satisfies the third condition. So accordingly, the value that the function will give is 1.
So, h(-1) = -1, h(-0.5) = 0 and h(1) = 1.
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Help me please help help
[tex]\angle P = \angle S \Rightarrow \angle S = 42 &^\circ\\\angle Q = \angle T \Rightarrow \angle S = 86 &^\circ\\\angle R = \angle U\\[/tex]
Sum of all angles in a triangle equals 180:
[tex]\angle R = 180 - (86 + 42) = 180 - 128 = 52[/tex]
Answer:
[tex]U = 52 &^ \circ[/tex]
Please help !! I will give 20 points for correct answer !!!!
(a) 3.1563x106
(b) 5.65x10-4 convert to usual form
Answer:
[tex](a) \: 3.1563 \times {10}^{6} = 31563 \times {10}^{6} \times {10}^{ - 4} = 31563 \times {10}^{6 - 4} = 31563 \times {10}^{2} = 3156300[/tex]
__o__o__
[tex](b) \: 5.65 \times {10}^{ - 4} = 565 \times {10}^{ - 4} \times {10}^{ - 2} = 565 \times {10}^{ - 4 - 2} = 565 \times {10}^{ - 6} = 0.000565[/tex]
Is 3.5 greater than 3.39
Answer:
yes
Step-by-step explanation:
Which is not a solution of sin 20 = 1?
A = 90
B = 45
C = 225
D = - 135
Unas deportivas cuestan $600 he visto que hay una rebaja del 20% cuánto dinero rebajado las reporteras
Answer:
600/100*20=6*20=120
600-120=480$
A chain weighs 12 pounds per foot. How many ounces will 7 inches weigh?
Answer:
The chain of the length 7 inches weighs 112 ounces.
Step-by-step explanation:
As we know there are 12 inches in a foot and 16 ounces in a pound
That is 1 foot = 12 inches.
and 1 pound = 16 ounces.
Given that the weight of the chain that is 1 foot long = 12 pounds
So weight of the chain per inch is = 12/12
which is equal to 1 pound
and according to the formula 1 pound = 16 ounces
So weight of the chain per inch is = 16 ounces
therefore weight of the chain that is 7 inch long = 7 × 16
that is 112 ounces.
The chain of the length 7 inches weighs 112 ounces.
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a) Construct a 95% confidence interval for the average test score for Delhi students. (1 Mark)
(b) Is there statistically significant evidence that Delhi students per form differently than other students in India? (1 Mark)
(c) Another 503 students are selected at random from Delhi. They are given a 3-hour preparation course before the test is administered. Their average test score is 1019, with a standard deviation of 95. Construct a 95% confidence interval for the change in average test score associated with the preparation course. (2 Marks)
(d) Is there statistically significant evidence that the preparation course helped? (1 Mark)
The solution to all the answers are given below.
The complete question includes
Grades on a standardized test are known to have a mean of 1,000 for students in the Delhi. 453
randomly selected Delhi students take the test, yielding sample mean of 1,013 and sample standard
deviation (s) of 108.
What is Confidence Interval ?It is given by
Confidence Interval for 95% confidence Interval is given by
[tex]\rm Z = X \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
(a) Construct a 95% confidence interval for the mean test score for Delhi students.
The confidence interval is given by
[tex]\rm 1,013 \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]\rm 1,013 \pm 1.96 \dfrac{108}{\sqrt{453}}[/tex]
1013 ± 5.07
so the interval is [1003.06,1022.94]
(b)Yes, since the null of no difference is rejected at the 5% significance level (interval excludes Delhi sample mean of 1,013)
(c) Another 503 Delhi students are randomly selected to take a 3-hour prep course and then give the test. Their average score is 1,019 with a standard deviation of 95.
The standard deviation now is
[tex]\rm \sqrt{\dfrac{95^2}{453} + \dfrac{108^2}{503}}[/tex]
= 6.61
The interval is given by
[tex](1,019-1,013) \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
= [-7,+19]
(d) No, the interval includes 0, the null difference between the two populations
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How many square decimeters are in 687.1 cm²?
Answer:
6.871 decimeters
Step-by-step explanation:
687.1 square centimeters = 6.871 square decimeters
1 dm² = 100 cm²
Answer:
6.871
Step-by-step explanation:
calculator
Simplify the following expression. (2x − 1)(3x + 2) Simplify the following expression . ( 2x − 1 ) ( 3x + 2 )
Choose the equation that satisfies the data in the table.
[xy−100−41−8]
A. y=−4x−4
B. y=−14x+4
C. y=4x−4
D. y=14x+4
The linear equation that satisfy the data in the table is: A. y = −4x − 4.
How to Find the Linear Equation for a Data in a Table?Given the table attached below, find the slope (m) = change in y / change in x using two pairs of values, say, (-1, 0) and (0, -4):
Slope (m) = (-4 - 0)/(0 - (-1)) = -4/1 = -4
Find the y-intercept (b), which is the value of y when x = 0. From the table, when x = 0, y = -4.
b = -4.
Substitute m = -4 and b = -4 into y = mx + b
y = -4x + (-4)
y = -4x - 4
The equation that satisfy the data is: A. y = −4x − 4.
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Need answers asap please
The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
a(n) = 3n - 30
To find make subject n and solve
a(n) + 30 = 3n
[tex]\rm n = \dfrac{a(n) + 30}{3}[/tex]
Plug n = n(a) and a(n) = a
[tex]\rm n(a) = \dfrac{a + 30}{3}[/tex]
Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
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A chopstick model of a catapult launches a marshmallow in a classroom. The path of the marshmallow can be modeled by the quadratic y=−0.07x2+x+2.2,
where y represents the height of the marshmallow, in feet,
and x represents the horizontal distance from the point it is launched, in feet.
When the marshmallow hits the ground, what is its horizontal distance from the point where it was launched?
The horizontal distance from the point where it was launched is 7.143.
We have given that,
The path of the marshmallow can be modeled by the quadratic y=−0.07x^2+x+2.2,
x represents the horizontal distance from the point it is launched, in feet.
What is the horizontal distance?Horizontal distance means the distance between two points measured at a zero percent slope.
(1) Put x = 7.143 in given equation
y= -0.07(7.143)^2+7.143+2.2
y= 2.2
y= 5.771
We have to determine the what is its horizontal distance from the point where it was launched.
The value of x is called horizontal distance.
Therefore the horizontal distance from the point where it was launched is 7.143.
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cho hàm số f(x) liên tục trên đoạn [a;b] và có nguyên hàm F(x) thỏa F(a)=10;F(b)=2022 Khi đó \int _a^b\: f(x) dx bằng
The result follows from the fundamental theorem of calculus.
[tex]\displaystyle \int_a^b f(x) \, dx = F(b) - F(a) = 2022 - 10 = \boxed{2012}[/tex]
Eric recorded the number of automobiles that a used car dealer in his town sold in different price ranges. From the Histogram given, what is the number of cars sold for the price range of $4000 to $4999? A. 15 B. 20 C. 30 D. 50
The correct answer is option A which is the number of cars sold for the price range of $4000 to $4999 will be 15.
What is a histogram?
A histogram is a graph for the representation of the data on the plot of the rectangular boxes. It has the data sets on the horizontal and the vertical axes.
As we can see from the histogram data we will conclude that the price range of $4000 to $4999 is shown by the third block and this third block reaches the height of 15.
Therefore the correct answer is option A which is the number of cars sold in the price range of $4000 to $4999 will be 15.
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