Match each function with its domain. 1. S(x) = √x 2. H(x) = √2+x 3. Z(x) = √x-2 4. Q(x) = √2-x 5. V(x) = √-x 6. N(x) = ^3√2-x x ≤ 2 x ≥ -2 x ≥ 0 x ≥ 2 x ≤ 0 All real numbers

Answers

Answer 1

Answer:

1. x ≥ 0

2. x ≥ -2

3. x ≥ 2

4. x ≤ 2

5. x ≤ 0

6. All real numbers

Step-by-step explanation:

Domain of square function:

Suppose we have a square function in the following format:

[tex]f(x) = \sqrt[n]{g(x)}[/tex]

If n is even, the domain of f(x) is:

[tex]g(x) \geq 0[/tex]

Otherwise, if n is odd, the domain of f(x) is all real numbers.

1. S(x) = √x

If n does not appear is that it is 2.

g(x) = x

So the domain is:

[tex]x \geq 0[/tex]

2. H(x) = √2+x

g(x) = 2 + x

So

[tex]2 + x \geq 0[/tex]

[tex]x \geq -2[/tex]

3. Z(x) = √x-2

g(x) = x - 2

[tex]x - 2 \geq 0[/tex]

[tex]x \geq 2[/tex]

4. Q(x) = √2-x

g(x) = 2 - x

[tex]2 - x \geq 0[/tex]

[tex]-x \geq -2[/tex]

Multiplying by -1, everything

[tex]x \leq 2[/tex]

5. V(x) = √-x

g(x) = -x

Then

[tex]-x \geq 0[/tex]

Multiplying by -1

[tex]x \leq 0[/tex]

6. N(x) = ^3√2-x

Cubic root(odd number), so all real numbers.


Related Questions

What is the answer to this problem.

Answers

Answer:

[tex]2a^2 + 3x - 2a[/tex]

Step-by-step explanation:

[tex] (6a^2 + 3x) - (4a^2 + 2a) = [/tex]

The first set of parentheses is unnecessary and can be removed.

[tex] = 6a^2 + 3x - (4a^2 + 2a) [/tex]

To remove the second set of parentheses, you must distribute the negative sign to its left as if it were a -1 multiplying the quantity inside the parentheses.

[tex] = 6a^2 + 3x - 1(4a^2 + 2a) [/tex]

[tex] = 6a^2 + 3x - 4a^2 - 2a [/tex]

Now combine like terms. Like terms are terms with the same variable part.

[tex] = 2a^2 + 3x - 2a [/tex]

The equation __ describes the relationship

Answers

Answer:

y= 1/3x

Step-by-step explanation:

points on the graph

(0,0), (3,1)

function as per above two points:

y= 1/3x

a store employees 11 women and 12 men.what percentage of employees are men?

Answers

Answer:

easy just find the total of how many people work there then put that no. as a denominator and put 12 on the numerator then times it by 100 and the answer should be 52.2% or 52.17%

Answer:

52.2% or 52.17%

12 men

Total = 23

12 / 23 =

Easy points for y’all mathy people, fairly easy question. It’s in the photo!!

Answers

W is the correct answer ✌️

Answer:

W

Step-by-step explanation:

The input is the x-axis.

The output is the y-axis.

Make them coordinates. Hope this helped!

Draw the following lines and label them with the matching letter. Then write an equation for each. Slope is 0, y-intercept is 5 Slope is 2, y-intercept is -1 Slope is -2, y-intercept is 1 Slope is -12, y-intercept is -1

Answers

Answer:

See explaination:

Graphs are on the right, equations are on the left, and they are color coded.

Step-by-step explanation:

will mark brainliest!! factor the following equation: f(x)=3x²+7x+2​

Answers

Answer:

(x + 2) (3x + 1)

Step-by-step explanation:

3x² + 7x + 2

3x² + 6x + x + 2

3x(x + 2) + 1(x + 2)

(x + 2) (3x + 1)

(X+2) (3x+1) is the answer!

A box of 120 crayons contains variations of three colors: blue, red, and purple. The ratio of blue crayons to red crayons is 11:2, and the ratio of the number of red crayons to purple crayons is 2:7. If all of the purple crayons were removed, how many crayons would be left in the box?

Answers

Answer: there would be 106,am not sure

Step-by-step explanation:

What segment is a reflection of segment ab over the line x=1

Answers

Answer:

    The correct answer is: (Line segment E F)

Originally the dimensions of a rectangle were 20cm by 23cm. When both dimensions were decreased by the same amount, the area of the rectangle decreases by 120. Find the dimensions of the rectangle.

Answers

The answer is 17cm by 20cm.
The original area is 460cm (20x23), minus 120cm gives a new area of 340cm.
20cm-3cm=17cm and 23cm-3cm=20cm
17cmx20cm = 340cm

Find the sum of the first eight terms of the geometric series 1 + 2 + 4 + ...

Answers

8 16 32 64 128 are the next four terms to the sequence

Answer:

The sum of all of the terms would be 255

Step-by-step explanation:You would continue to multiply all of the answers by 2 until you hit 128. Then you would add all of them together 128+64+32+16+8+4+2+1=255

Find the circumference of the circle to the nearest hundredth. Use 3.14 for π. Radius 21 cm.

Answers

Answer:

[tex]131.95[/tex] [tex]cm[/tex]

Step-by-step explanation:

[tex]C=2 \pi r[/tex]

[tex]C=2 \pi \times 21[/tex]

[tex]C=42\pi[/tex]

[tex]C \approx 131.946891451[/tex]

Please answer correctly !!!! Will mark brainliest !!!!!!!!!

Answers

Answer:

[tex]=\left(x-4\right)^2[/tex]

Step-by-step explanation:

[tex]x^2-8x+16\\\mathrm{Rewrite\:}x^2-8x+16\mathrm{\:as\:}x^2-2x\cdot \:4+4^2\\x^2-8x+16\\\mathrm{Rewrite\:}16\mathrm{\:as\:}4^2\\=x^2-8x+4^2\\\mathrm{Rewrite\:}8x\mathrm{\:as\:}2x\cdot \:4\\=x^2-2x\cdot \:4+4^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2\\a=x,\:b=4\\=\left(x-4\right)^2[/tex]

Answer:

0

Step-by-step explanation:

Since it is asking you to factor out the quadratic, you need to make it equal zero first. -4 times -4 is both 16 and -8. So that means (x-4)^2

Brainliest question please help me answer my question please

Answers

Answer:

Step-by-step explanation:

The area for a trapezoid is

[tex]A=\frac{1}{2}h(b_{1}+b_{2})[/tex]

h is the length of ST, one of the bases is the length of MK, and the other base is the length of AS.  First we'll find h:

The coordinates for S are (0, -2) and T are (1, 2). Using the distance formula:

[tex]d=\sqrt{(1-0)^2+(2-(-2))^2[/tex] and

[tex]d=\sqrt{17}[/tex].  So h = √17

Now for the length of MK. The coordinates for M are (-7, 4) and for K (5, 1). Using the distance formula again:

[tex]d=\sqrt{(-7-5)^2+(4-1)^2}[/tex] and

[tex]d=\sqrt{(-12)^2+(3)^2}[/tex] so

[tex]d=\sqrt{153}[/tex] which simplifies to

[tex]d=3\sqrt{17}[/tex]. So MK = 3√17.

Now for the length of AS. The coordinates for A: (-4, -1) and for S: (0, -2). Using the distance formula one more time:

[tex]d=\sqrt{(-4-0)^2+(-1-(-2))^2}[/tex] and

[tex]d=\sqrt{(-4)^2+(1)^2}[/tex] and

[tex]d=\sqrt{17}[/tex]. So AS = √17.

Now we can fill in our area formula:

[tex]A=\frac{1}{2}(\sqrt{17})(3\sqrt{17}+\sqrt{17})[/tex]

Simplifying a bit:

[tex]A=\frac{1}{2}(\sqrt{17})(4\sqrt{17})[/tex] and simplifying a bit more:

[tex]A=\frac{4*17}{2}[/tex] and

A = 34

Please answer correctly !!!!! Will mark brainliest !!!!!!!!

Answers

Answer:

k(-7) = = -89

Step-by-step explanation:

k(t) = 10t -19

Let t = -7

k(-7) = 10*-7 -19

      = -70-19

      = -89

Answer:

-89

Step-by-step explanation:

K(t) = K(-7)

10 is being multiplied by t. t = -7

so:

10(-7) = -70

-70 - 19 = -89

Hope this helps!

Need help ASAP!! Thank youu!

Answers

Answer:

The answer is 7.

Step-by-step explanation:

If you want to find what FE is, you have subtract GF from GE (GE - GF = FE).

Since GE = 13 and GF = 6, you have to subtract 6 from 13 which equals 7.

(13 - 6 = 7)

Please answer correctly !!!!!!!!! Will mark brianliest !!!!!!!!!!!!

Answers

Answer:

g(x) has a greater y intercept than f(x)

Step-by-step explanation:

f(x) = 6x^2 + 18x +3

f(0) = 0+0+3

The y intercept is 3

g(x) crosses the y axis at 6

The y intercept is 6

g(x) has a greater y intercept than f(x)

Answer:

g(x) has a greater y intercept than f(x)

Step-by-step explanation:

f(x) = 6x^2 + 18x +3

f(0) = 0+0+3

The y intercept is 3

g(x) crosses the y axis at 6

The y intercept is 6

g(x) has a greater y intercept than f(x)

hope I could help

Estimate the solution to the system of equations.
You can use the interactive graph below to find the solution.
-3x + 3y = 9
2x – 7y = -14

Answers

Answer:

x= -7/5 y=8/5

Step-by-step explanation:

1. choose a variable to eliminate (i chose 6)

2. multiply the first equation by 2 and the second equation by 3

3. now you have

-6x+6y=18

6x-21y=-42

and the x's can now cancel out when you add the equations together

4. after adding the equations, you get

-15y=-24

5. solve for y (y= 8/5)

6. now plug in 8/5 for the y in one of the original equations to solve for x. (i chose the first one)

7. -3x+3(8/5)=9

-3x+24/5=9

-3x=21/5

x= -7/5

describe fully the single transformation that maps triangle a onto triangle b

Answers

Answer:

Reflection about y=2

Step-by-step explanation:

Triangle A should be reflected about y=2 to map it onto Triangle B.

Answer:

reflection across y=2

Step-by-step explanation:

What are the solutions of 2x²-6x+5=0?

Answers

Answer:

D

Step-by-step explanation:

a = 2 ;  b = -6 ;  c = 5

[-b±√b²-4ac]/2a=[-(-6)±√6²-4*2*5]/2*2

=[6±√√36-40]/4

=[6±√-4]/4

=[6±√i²*2²]/4

=[6±2i]/4

=2[3±i]/4

=3±i/2

= 3+i/2  or 3-i/2

can someone do my ixl its 6th grade math!! only 3 and you have to get 85 and higher i will give 25 points!! and mark as brainlist

Answers

Answer:

Okkk I will answer

Answer:

what question do you have?

Step-by-step explanation:

help me help me help me asap

Answers

Answer:

9 cubic feet

Step-by-step explanation:

Assuming that the garden box is a rectangular prism, its volume is:

[tex]4\dfrac{1}{2} \cdot 4 \cdot \dfrac{1}{2}=9 \text{ ft}^3[/tex]

Hope this helps!

Answer:9

Solution,

Length(L)=4 1/2 ft

Breadth(b)= 4 ft

Height(H)=1/2 ft

Now,

Volume=L*B*H

= 4 1/2*4*1/2

=9/2*4*1/2

= 9 cubic feet

Hope it helps

Good luck on your assignment

what is 9x=4.5 if u can solve this u are very smart

Answers

Answer:

x = 1/2

Step-by-step explanation:

9x=4.5

Divide each side by 9

9x/9 = 4.5/9

x = 45/90

x = 1/2

Answer:

x = 1/2 or x = 0.5

Step-by-step explanation:

9x = 4.5/9

= 45/90

= 1/2 or 0.5

Hope this helps, and please mark me brainliest if it does!

Which ordered pair comes from the table?

Answers

Answer: A. (6,5)

Explanation: (6,5) is the only ordered pair that is in the table shown in the picture, which means it could not be any of the other ordered pairs.

The angle \theta_1θ
1

theta, start subscript, 1, end subscript is located in Quadrant \text{II}IIstart text, I, I, end text, and \cos(\theta_1)=-\dfrac{12}{19}cos(θ
1

)=−
19
12

cosine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis, equals, minus, start fraction, 12, divided by, 19, end fraction .
What is the value of \sin(\theta_1)sin(θ
1

)sine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis?

Answers

Answer:

[tex]sin\theta_1 = \dfrac{\sqrt{217}}{19}[/tex]

Step-by-step explanation:

It is given that:

[tex]cos\theta_1 = -\dfrac{12}{19}[/tex]

And we have to find the value of [tex]sin\theta_1 = ?[/tex]

As per trigonometric identities, the relation between [tex]sin\theta\ and \ cos\theta[/tex] can represented as:

[tex]sin^2\theta + cos^2\theta = 1[/tex]

Putting [tex]\theta_1[/tex] in place of [tex]\theta[/tex] Because we are given

[tex]sin^2\theta_1 + cos^2\theta_1 = 1[/tex]

Putting value of cosine:

[tex]cos\theta_1 = -\dfrac{12}{19}[/tex]

[tex]sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}[/tex]

It is given that [tex]\theta_1[/tex] is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

[tex]\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}[/tex]

Answer:

−  square root 15/4

Step-by-step explanation:

Match the parabolas represented by the equations with their foci.

Answers

Answer:

Step-by-step explanation:

Before we begin this, there are a few things that need to be said and a few formulas you need to know. First is that we need to use the work form of a parabola, which is

[tex]y=a(x-h)^2+k[/tex]

All of the parabolas listed in blue highlight open either up or down, and this work form represents those 2 options. The only thing we need to know is that if there is a negative sign in front of the a, the parabola opens upside down like a mountain instead of up like a cup.

Another thing we need to know is how to find the focus of the parabola. The formula to find the focus for an "up" parabola is (h, k + p) and the formula to find the focus for an upside down parabola is (h, k - p). Then of course is the issue on how to find the p. p is found from the a in the above work form parabola, where

[tex]p=\frac{1}{4|a|}[/tex] .

In order to accomplish what we need to accomplish, we need to put each of those parabolas into work form (as previously stated) by completing the square. I'm hoping that since you are in pre-calculus you have already learned how to complete the square on a polynomial in order to factor it.  Starting with the first one, we will complete the square. I'll go through each step one at a time, but will provide no explanation as to how I got there (again, assuming you know how to complete the square).

[tex]y=-x^2+4x+8[/tex] and, completing the square one step at a time:

[tex]-x^2+4x=-8[/tex] and

[tex]-(x^2-4x+4)=-8-4[/tex] and

[tex]-(x-2)^2=-12[/tex] and

[tex]-(x-2)^2+12=y[/tex]

From this we can see that the h and k values for the vertex are h = 2 and k = 12. Now to find p.

[tex]|a|=1[/tex], ∴

[tex]p=\frac{1}{4(1)}=\frac{1}{4}[/tex]

Using the correct focus formula (h, k - p), we get that the focus is

[tex](2, 12-\frac{1}{4})[/tex] which simplifies to (2, 11.75) which is choice 2 in your options.

Now for the second one (yes, this takes forever...)

[tex]y=2x^2+16x+18[/tex] and completing the square one step at a time:

[tex]2x^2+16x=-18[/tex] and

[tex]2(x^2+8x+16)=-18+32[/tex] and

[tex]2(x+4)^2=14[/tex] and

[tex]2(x+4)^2-14=y[/tex]

From this we can see that the vertex is h = -4 and k = -14. Now to find p from a.

[tex]|a|=2[/tex], ∴

[tex]p=\frac{1}{4(2)}=\frac{1}{8}[/tex] .

Using the correct focus formula for an upwards opening parabola (h, k + p),

[tex](-4, -14+\frac{1}{8})[/tex] which simplifies down to (-4, -13.875) which is choice 3 in your options.

Now for the third one...

[tex]y=-2x^2+5x+14[/tex] and completing the square step by step:

[tex]-2x^2+5x=-14[/tex] and

[tex]-2(x^2-\frac{5}{2}x+\frac{25}{16})=-14-\frac{50}{16}[/tex] and

[tex]-2(x-\frac{5}{4})^2=-\frac{137}{8}[/tex] and

[tex]-2(x-\frac{5}{4})^2+\frac{137}{8}=y[/tex]

From that we can see the vertex values h and k. h = 1.25 and k = 17.125. Now to find p.

[tex]|a|=2[/tex], ∴

[tex]p=\frac{1}{4(2)}=\frac{1}{8}[/tex]

Using the correct focus formula for an upside down parabola (h, k - p),

[tex](1.25, 17.125-\frac{1}{8})[/tex] which simplifies down to (1.25, 17) which is choice 4 in your options.

Now for the fourth one...

[tex]y=-x^2+17x+7[/tex] and completing the square step by step:

[tex]-x^2+17x=-7[/tex] and

[tex]-(x^2-17x)=-7[/tex] and

[tex]-(x^2-17x+72.25)=-7-72.25[/tex] and

[tex]-(x-8.5)^2=-79.25[/tex] and

[tex]-(x-8.5)^2+79.25=y[/tex]

From that we see that the vertex is h = 8.5 and k = 79.25. Now to find p.

[tex]|a|=1[/tex], ∴

[tex]p=\frac{1}{4(1)}=\frac{1}{4}[/tex]

Using the correct formula for an upside down parabola (h, k - p),

[tex](8.5, 79.25-\frac{1}{4})[/tex] which simplifies down to (8.5, 79) and I don't see a choice from your available options there.

On to the fifth one...

[tex]y=2x^2+11x+5[/tex] and again step by step:

[tex]2x^2+11x=-5[/tex] and

[tex]2(x^2+\frac{11}{2}x+\frac{121}{16})=-5+\frac{242}{16}[/tex] and

[tex]2(x+\frac{11}{4})^2=\frac{81}{8}[/tex] and

[tex]2(x+\frac{11}{4})^2-\frac{81}{8}=y[/tex]

from which we see that h = -2.75 and k = -10.125. Now for p.

[tex]|a|=2[/tex], ∴

[tex]p=\frac{1}{4(2)}=\frac{1}{8}[/tex]

Using the correct focus formula for an upwards opening parabola (h, k + p),

[tex](-2.75, -10.125+\frac{1}{8})[/tex] which simplifies down to (-2.75, -10) which is choice 1 from your options.

Now for the last one (almost there!):

[tex]y=-2x^2+6x+5[/tex] and

[tex]-2x^2+6x=-5[/tex] and

[tex]-2(x^2-3x+2.25)=-5-4.5[/tex] and

[tex]-2(x-1.5)^2=-9.5[/tex] and

[tex]-2(x-1.5)^2+9.5=y[/tex]

from which we see that h = 1.5 and k = 9.5. Now for p.

[tex]|a|=2[/tex], ∴

[tex]p=\frac{1}{4(2)}=\frac{1}{8}[/tex]

Using the formula for the focus of an upside down parabola (h, k - p),

[tex](1.5, 9.5-\frac{1}{8})[/tex] which simplifies down to (1.5, 9.375) which is another one I do not see in your choices.

Good luck with your conic sections!!!

A concrete driveway is 5 feet longer than twice its width. It has a brick walkway 3 feet wide on the front and side of the driveway. The area of the brick walkway is 213
square feet. Find the dimensions of the driveway.​

Answers

Answer:

The dimensions of the driveway are 21 ft x 47 ft, which is option "D" in your list of possible answers

Step-by-step explanation:

Notice that the length "L" of the driveway can be written in terms of its width as:

L = 2 w + 5

based on the given information.

Please see the attached diagram to understand the geometry of the problem, and what the area of the brick walkway involves (depicted in brick color) as the addition of the area of two rectangles:

1) one of length L= 2 w + 5 (w being the width of the driveway - depicted in grey) times 3 feet (the width of the brick walkway

and the other one:

2) w + 3 times 3

Therefore the total area of the brick walkway is given by the formula:

(2 w + 5) * 3 +(w + 3) * 3 = 213 square feet

Now we can solve for "w" in the above equation:

6 w + 15 + 3 w + 9 = 213

9 w + 24 = 213

9 w = 213 - 24

9 w = 189

w = 189/9

w = 21 feet

We can now solve for the L of the driveway, using the first formula we created:

L = 2 w + 5

L = 2 (21) + 5

L = 42 + 5

L = 47 feet

Therefore the driveway's width is w = 21 feet

and its length is L = 47 feet

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym Two-thirds the distance from Ping's home to Ari's home.

x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1

y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1

Where is the gym?

Answers

Answer: (15th street, 14th Avenue)

Step-by-step explanation:

Given the following :

Ping's residence = (3rd street, 6th Avenue)

Ari's residence = (21st street, 18th Avenue)

Gym location = 2/3 the distance of Ping's residence to Ari's residence

So, distance between Ping's home to Ari's home

Distance = (21st street, 18th Avenue) - (3rd street, 6th Avenue)

Distance = (21 - 3) street, (18 - 6) avenue

Distance between ping and Ari = (18th , 12th )

Gym distance = 2/3 of distance between ping and Ari

Gym distance = 2/3 × (18), 2/3 ×(12)

Gym distance = (12, 8)

Gym location = Ping's location + gym distance

Gym location = (3rd street, 6th Avenue) + (12th street, 8th Avenue)

Gym location = (15th street, 14th Avenue)

Answer:

d) 15th Street and 14th Avenue

If 48 % of students in a certain college are female and there are 1,440 female students, what is the total number of students in the college? Please show work

Answers

Answer:

The total number of students in the college is 3,000.

Step-by-step explanation:

[tex]\frac{48}{100}=\frac{1,440}{x}[/tex]               Set up a proportion.

[tex]48x=144,000[/tex]         Cross-multiply.

[tex]x=3,000[/tex]                 Divide both sides by 48.

Felipe is working to find the quotient of 6 and 3/4

Answers

Answer:

Felipe's answer is 8.

6 divided by 3/4

= 6 * 4/3

= 24/3

= 8

Answer:

8

Step-by-step explanation:

6÷3/4=6×4/3=8

PLZ HELP! WILL GIVE BRAINIEST!!

Answers

Answer:

i think its c idk if im wrong im sorry

Step-by-step explanation:

Other Questions
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