Libby built a fence that was 56 \text { feet}56 feet56, start text, space, f, e, e, t, end text long over 444 days. She built the same length of fence each day.
How many inches of fence did Libby build each day?

Answer:

1/8 of males as females are 7 times of males are x then females are 7x so the fraction of males x will be 1/8

Step-by-step explanation:

Standard form ax²+bx+c=0

Done

The time used for the first part of the trip in minutes is 270 minutes.

Total distance travelled = 675 km

He travelled from 1pm to 9pm.

He rested for 1 hour 30 minutes. The total time used for the trip is 6 hours 30 minutes.

let

the time used for the first part of the trip = x

Therefore,

speed = distance / time

distance = 110x

the time used for the first part of the trip = 6.5 - x

distance = 90(6.5 - x)

distance = 585 - 90x

Hence,

110x + 585 - 90x = 675

20x + 585 = 675

20x = 675 - 585

20x = 90

x  = 90 / 20

x = 4.5 hours = 270 minutes

Therefore, the time used for the first part of the trip is 270 minutes.

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The system of equation 2x + y = 2 y = –2x – 1 has infinitely many solutions because the coefficient of the x and y in the equations are same.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have a system of equations:

2x + y = 2  …(1)

y = –2x – 1  or

2x + y = -1 ...(2)

As we can see the coefficient of the x and y in the equation (1) and (2) are same which means they infinitely many solutions.

Thus, the system of equation 2x + y = 2 y = –2x – 1 has infinitely many solutions because the coefficient of the x and y in the equations are same.

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2.5 quarts will be needed to paint the wall on the right.

The product of length and breadth.

Area of rectangle=  length * breadth

Area of first wall = l * b

= 12*7

= 108 st. ft.

Area of 2nd wall

= l*b

=18*10

=180 sq. ft.

If 1.5 qt required to paint the 108 sq. ft. area

For 1 sq ft, paint would be need= 1.5/108

For 180 sq ft paint needed = 1.5*180/108

                                            = 2.5 qt

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Answer:

25 houses in 5 weeks

Step-by-step explanation:

15 house / 3 week    *   5 week = 25 houses

Answer: D

Step-by-step explanation:

This is the only option that is a line.

Answer:

The answer is (x + 10)² + (y – 7)² = (4)².

Step-by-step explanation:

Here, a = (-10), b = 7 and r = 4.

So,

(x – a)² + (y – b)² = r²

[x – (-10)]² + (y – 7)² = (4)²

(x + 10)² + (y – 7)² = (4)²

Thus, The standard equation of the circle with the centre of (-10, 7) and a radius of 4 is

(x + 10)² + (y – 7)² = (4)².

Answer:

1/4

Step-by-step explanation:

2 to the power of -2 would be 1/4.

This is because 2 to the power of -1 would be 1/2. And the power of 2 would square the 2 as the denominator making it 1/4.

The reason -1 makes the 2 turn into a fraction is that to the power of 2 means 2x2, to the power of one means 2, The power of zero would therefore divide by 2 so 2/2 = 1 and so 2 to the power of -1 would be 1/2.

         [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

    What is 2 to the power of -2?

   [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}[/tex]

Let's look at the last property of exponents - [tex]\bold{\#7 - negative\:exponents}[/tex]

                                    [tex]\Large\text{$a^{-n}=\displaystyle\frac{1}{a^n}$}[/tex]

So if we have a number with a negative exponent, we flip it over.

According to Property #7,

      [tex]\Large\text{2^{-2}=\displaystyle\frac{1}{2^2} =\frac{1}{4}$}[/tex]

                    [tex]\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{60}{1}[/tex]

Answer:

2.99924 in

Step-by-step explanation:

Volume of a cone

V = pi x r^2 x h/3

So to solve this problem you plug in the number we already have which is the volume and the height

103.62 = pi x r^2 x 11/3

28.26 = pi x r^2

28.26/pi = r^2

[tex]\sqrt{\frac{28.26}{\pi } }[/tex] = r ≈ 2.99924

[tex]3 b(broccolis=\frac{1}{8} )=\frac{3}{8}[/tex]

[tex]4c(carrots=\frac{1}{6})=\frac{4}{6}[/tex]

Lastly:

[tex]2t(tomatoes=\frac{1}{4})=\frac{2}{4}[/tex]

Answer:

what?

Step-by-step explanation:

Answer:

please reformat the question to be readable !

Step-by-step explanation:

Answer:

Area=153.75 divdided by 2 = 76.88

permitere= 8 + 10.25+18.8=37.05

Step-by-step explanation:

Answer:

0.01%

Step-by-step explanation:

There's no need to worry about a problem like this, it's easy. All you have to do is find the area of the smaller rectangle, being 50, then find the area of the other one, 5000, and divide the smaller by the larger and transfer it to a percentage. 50/5000 = 0.01 = 0.01%

The probability that the news and weather report Is NOT on will be 0.8. Then the correct option is J.

Its simple notion is that something will most likely occur. The favorable event's proportion to the overall number of occurrences.

A radio station reports news and weather, every 20 minutes for 4 minutes.

If the radio is turned on at a random time.

Then the probability that the news and weather report Is NOT on will be

P = 1 - 4/20

P = 1 - 0.20

P = 0.8

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Answer:

The number closest to 300 would end up being 310!

Step-by-step explanation:

Answer:

Show that if [tex]f(a) = f(b) = 0[/tex] for some [tex]a,\, b \in [-2,\, 2][/tex] where [tex]a \ne b[/tex], then by Rolle's Theorem [tex]f^{\prime}(x) = 0[/tex] for some [tex]x \in (-2,\, 2)[/tex]. However, no such [tex]x[/tex] exists since [tex]f^{\prime}(x) < 0[/tex] for all [tex]x \in (-2,\, 2)\![/tex].

Note that Rolle's Theorem alone does not give the exact value of the root. Neither does this theorem guarantee that a root exists in this interval.

Step-by-step explanation:

The function [tex]f(x) = x^{3} - 12\, x + 11[/tex] is continuous and differentiable over [tex][-2,\, 2][/tex]. By Rolle's Theorem. if [tex]f(a) = f(b)[/tex] for some [tex]a,\, b \in [2,\, -2][/tex] where [tex]a \ne b[/tex], then there would exist [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex].

Assume by contradiction [tex]f(x)[/tex] does have more than one roots over [tex][-2,\, 2][/tex]. Let [tex]a[/tex] and [tex]b[/tex] be (two of the) roots, such that [tex]a \ne b[/tex]. Notice that [tex]f(a) = 0 = f(b)[/tex] just as Rolle's Theorem requires. Thus- by Rolle's Theorem- there would exist [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex].

However, no such [tex]x \in (a,\, b)[/tex] could exist. Notice that [tex]f^{\prime}(x) = 3\, x^{2} - 12[/tex], which is a parabola opening upwards. The only zeros of [tex]f^{\prime}(x)[/tex] are [tex]x = (-2)[/tex] and [tex]x = 2[/tex].

However, neither [tex]x = (-2)[/tex] nor [tex]x = 2[/tex] are included in the open interval [tex](-2,\, 2)[/tex]. Additionally, [tex]a,\, b \in [-2,\, 2][/tex], meaning that [tex](a,\, b)[/tex] is a subset of the open interval [tex](-2,\, 2)[/tex]. Thus, neither zero would be in the subset [tex](a,\, b)[/tex]. In other words, there is no [tex]x \in (a,\, b)[/tex] such that [tex]f^{\prime}(x) = 0[/tex]. Contradiction.

Hence, [tex]f(x) = x^{3} - 12\, x + 11[/tex] has at most one root over the interval [tex][-2,\, 2][/tex].

Answer:

i think the answer is (-4,2)

Step-by-step explanation:

The area of the walkway itself is π[(y + 4)²- (y - 4)²] the radius of the pool is y − 4 and the radius of the full circle formed by the walkway is y + 4

An equation is an expression that shows the relationship between two or more numbers and variables.

Area of circle = π * radius²

The area of the walkway itself = π(y + 4)² - π(y - 4)² = π[(y + 4)²- (y - 4)²)

The area of the walkway itself is π[(y + 4)²- (y - 4)²] the radius of the pool is y − 4 and the radius of the full circle formed by the walkway is y + 4

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Step-by-step explanation:

option D is correct answer

Answer:

C

Step-by-step explanation:

[tex]\text{Plug} ~(x,y) = ( 2,0)~ \text{in both equations.}\\\\3*0 = 2-2\implies 0=0\\\\0 = -2(2) +4 \implies 0=0\\\\\text{Hence x =2 and y =0.}[/tex]

Answer:

  0.9%

Step-by-step explanation:

The percentage change is found by multiplying the fractional change by 100%. The fractional change is the change amount divided by the original amount.

__

  change in height = 100/11013 × 100% ≈ 0.0090802 × 100% ≈ 0.9%

Answer:

V=14.12 in³

Step-by-step explanation:

This is a tough one. To find the volume, you'll need the followimg equation:

[tex]\frac{4}{3} \pi {r}^{3}[/tex]

The 3 next to the R is an exponent. An exponent involves multiplying the radius by itself. So it would look like this: 1.5×1.5×1.5

Next, you must multiply the result by 3.14. So it would be 3.375×3.14. And finally, you must multiply that result by 4 and divide by 3. So 10.59×4 to get 42.36 then divide that by 3. 42.36 divided by 3 is 14.2. (Answer can vary from time to time and you may need to round up)

If it is enlarged by a scale factor of 2. Then the coordinates of the translated triangle will be (2, -2), (6, 0), and (2, -8).

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

The coordinates of a triangle are (1,-1), (3,0), and (1,-4).

If it is enlarged by a scale factor of 2.

Then the coordinates of the translated triangle

(1,-1) → (2, -2)

(3,0) → (6, 0)

(1,-4) → (2, -8)

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Answer:

x = 36.9°

Given:

opposite side: 9

adjacent side: 12

angle: x

Using tane rule:

[tex]\sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

Solve:

[tex]\sf tan(x) = \dfrac{9}{12}[/tex]

[tex]\sf x = tan^{-1}(\dfrac{9}{12})[/tex]

[tex]\sf x = 36.87[/tex]

[tex]\sf x = 36.9[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

since the given triangle is an right angled triangle we can use Trigonometric ratios here :

[tex]\qquad \sf  \dashrightarrow \: \tan(x) = \dfrac{9}{12} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \tan(x) = \dfrac{3}{4} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x= tan { }^{ - 1} \bigg( \dfrac{3}{4} \bigg)[/tex]

[tex]\qquad \sf  \dashrightarrow \:x \approx37 \degree[/tex]

A force of 4.05×10⁶ N was exerted on one side of the wall.

Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction.

The following data were obtained from the question:

Breadth (B) = 4 m

Length (L) = 10 m

Standard pressure (P) = 101325 Nm¯²

Next, we shall determine the area of the wall. This can be obtained as follow:

Area (A) = length (L) × breadth (B)

A = 10 × 4

A = 40 m²

Finally, we shall determine the force exerted on one side of the wall as follow:

Standard pressure (P) = 101325 Nm¯²

Area (A) = 40 m²

Pressure (P) = Force (F) /Area (A)

101325 = F/40

F = 101325 × 40

F = 4.05×10⁶ N.

Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.

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The confidence interval at a 90% confidence level is (60.9%,75.1%) if in the end of a semester, she loaned 115 highlighters and found that 68% were not returned option (A) is correct.

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

[tex]\rm MOE = Z\times{\sqrt \dfrac{p(1-p)}{n}\\[/tex]

Where   Z is the z-score at the confidence interval

            p is the population proportion

            n is the number of samples.

We have p = 68% = 0.68

n = 115

Z score for 90% confidence interval = 1.64

[tex]\rm MOE = 1.64\times{\sqrt \dfrac{0.68(1-0.68)}{115}\\[/tex]

MOE = 0.071

So the confidence interval will be:

= (0.68-0.071, 0.68+0.071)

= (0.609, 0.751)  or

= (60.9%, 75.1%)

Thus, the confidence interval at a 90% confidence level is (60.9%,75.1%) if in the end of a semester, she loaned 115 highlighters and found that 68% were not returned option (A) is correct.

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Answer:

Step-by-step explanation:

   r = 3 cm

Volume = 27π cm³

                       [tex]\sf \boxed{\text{Volume of cylinder=$\pi r^2h$}}[/tex]

[tex]\sf \pi*3*3*h = 27 \pi\\[/tex]

              [tex]h = \dfrac{27 \pi}{\pi * 3 * 3}\\\\ \boxed{\bf h = 3 \ cm}[/tex]

      [tex]\sf \r_A : r_B = 3 : 9[/tex][tex]\sf r_A : r_B = 3 : 9[/tex]

                 = 1 : 3

      [tex]\sf h_A : h_B = 1 : 3\\[/tex]

            [tex]\sf \dfrac{3}{h_B}=\dfrac{1}{3}\\\\ cross \ multiply,\\\\ 3*3 = 1*h_B\\\\ h_B = 9 \ cm[/tex]

Volume of cylinder B = π * 9 * 9 * 9

                                    = 729π cm³

       [tex]\sf V_A : V_B = 27 \pi :729 \pi[/tex]

                    = 1 : 27

The range of the graph is the set of output values, and the range is (d) (-infinity,infinity)

From the graph in the complete question, we can see that the output values (i.e. the y values) extend indefinitely on both sides of the graph

This means that the range of the graph is the set of all real numbers.

This in other words means that (-infinity,infinity)

Hence, the range of the graph is (d) (-infinity,infinity)

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