Let P be the parallelogram with vertices (-1, -1), (1, -1), (2, 2), (0, 2). Compute S'p xy dA.

a) The expected number of solar energy construction firms that will be in indiana

is equal to 200 firms.

b) In case of exponential Probability distribution that there will be more than 300 solar energy firms in business is equals to the 0.305 × 10⁻⁵ .

The Poisson process is used when events are independent of each other and the average rate is constant. Two events cannot occur simultaneously. We have a data of about the number of solar energy construction firms in the state of indiana. Number of solar energy construction firms in the state at present

= 40

Average of solar energy construction firms open each year in the state = 20

For number of year average firm stays in business = 10 years.

We have to determine the expected number of solar energy construction firms that will be found in indiana. Let X be excepted value,then (X∼Poi(λt)X∼ Poi(200),

a) If the present trends continue, then the expected number of energy construction firms that will be found in Indiana will be

Expected Number of firms = 20× 10

= 200 firms

(b) If the time between the entries of firms into the industry is exponentially distributed. Then the probability that there will be more than 300 solar energy firms in business, P ( x> 300) = e⁻ᵐˣ , where m = 1/20 and x

= 300

=> P( x> 300) = 1/exp.( 300/20)

= e⁻¹⁵

= 0.0000003059 = 0.305 × 10⁻⁵

Hence, required probability value is 0.305 × 10⁻⁵.

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Therefore, the equation of the line that passes through the points (-3, 6) and (-5, 9) in slope-intercept form is:

y = -3/2 x + 3/2

Step-by-step explanation:

To find the equation of the line that passes through the points (-3, 6) and (-5, 9) in slope-intercept form (y = mx + b), we need to first find the slope of the line using the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) = (-3, 6) and (x2, y2) = (-5, 9).

m = (9 - 6) / (-5 - (-3))

m = 3 / (-2)

m = -3/2

Now that we have the slope, we can use either of the two given points and the slope to find the y-intercept (b) of the line:

y = mx + b

6 = (-3/2)(-3) + b

6 = 9/2 + b

b = 6 - 9/2

b = 3/2

To determine if the 275 fish are the right number for the cylindrical fish tank, we need to calculate the tank's capacity and compare it to the recommended average density of 16 fish per 100 gallons of water.

The volume of a cylinder is given by the formula V = πr^2h, where V is the volume, r is the radius, and h is the height of the cylinder.

Assuming the tank has a height of h and a radius of r, we can calculate its volume as follows:

[tex]V = πr^2h[/tex]

Since the tank has a vertical tube in the middle, we need to subtract the volume of the tube from the total volume of the tank. Let's assume the tube has a radius of 2 feet and a height of 8 feet. Then the volume of the tube is:

Vtube = π(2)^2(8) = 100.53 cubic feet

Thus, the volume of the tank without the tube is:

Vtank = πr^2h - Vtube

To find the value of r, we need to know the diameter of the tank. Let's assume the tank has a diameter of 10 feet, which means the radius is 5 feet.

Then the volume of the tank without the tube is:

Vtank = π(5)^2h - 100.53

We need to convert the volume of the tank from cubic feet to gallons, so we multiply by 7.48 (1 cubic foot = 7.48 gallons):

Vtank(gallons) = 7.48[π(5)^2h - 100.53]

Now we can calculate the recommended number of fish for the tank:

Recommended number of fish = 16 fish/100 gallons x Vtank(gallons)

Recommended number of fish = 16 fish/100 gallons x 7.48[π(5)^2h - 100.53]

Recommended number of fish = 1.175[π(5)^2h - 100.53]

So, if the number of fish available is 275, we can set up the following equation:

275 = 1.175[π(5)^2h - 100.53]

Solving for h, we get:

h = (275/1.175π(5)^2) + (100.53/π(5)^2)

h ≈ 8.3 feet

Therefore, the cylindrical fish tank with a height of 8.3 feet and a radius of 5 feet can hold 275 fish with an average density of 16 fish per 100 gallons of water. If the aquarium manager wants to add more fish, they should recalculate the volume of the tank and adjust the height accordingly to maintain the recommended density of 16 fish per 100 gallons of water. Conversely, if they want to remove fish, they can do so without changing the height of the tank.

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After these 90 seconds, the time, in seconds, that it will take for the scientist to travel back to sea level at 3.6 feet per second is 12.3 seconds, rounded to the nearest tenth of a second.

The descent rate = 4.9 feet per second

The descent time = 41 seconds

The total descent distance = 200.9 feet (4.9 x 41)

The ascent rate = 3.2 feet per second

The ascent time = 49 seconds

The total ascent distance traveled = 156.8 feet (3.2 x 49)

The difference between descent and ascent distances = 44.1 feet (200.9 - 156.8)

Traveling speed to sea level = 3.6 feet per second

The time to be taken to travel to sea level = 12.25 (44.1 ÷ 3.6)

= 12.3 seconds

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The total number of ounces of hydrogen peroxide, rounded to up to 1 significant digit after the decimal point, is 10.5 ounces.

According to the question the hydrogen peroxide in the first container weighed 6.4 ounces, and the hydrogen peroxide in the second container weighed 4.07 ounces.

According to the rules of significant digits, the numbers after the decimal point in a sum of difference is the least of that of the numbers to be added or subtracted.

This means that when 6.4 and 4.07 is added, then we will see numbers of decimal places in each number. 6.4 has 1 number after decimal point and 10.47 has 2.

Hence the result of 6.4 + 10.47 will have a minimum of 2 which is 1 decimal place.

Now, 6.4 + 4.07

= 10.47

Rounding it off from the above-mentioned criteria gives us 10.5 ounces.

Therefore, the total number of ounces of hydrogen peroxide, rounded to up to 1 significant digit after the decimal point, is 10.5 ounces.

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You can drive at most 700 miles within the $180 budget for weekly transportation.

To determine how many miles can be driven with a budget of $180 for weekly transportation, we'll use the given information: $75 per week for car rental and $0.15 per mile driven. First, subtract the weekly rental cost from the total budget:

$180 - $75 = $105

Now, divide the remaining budget by the cost per mile to find the maximum number of miles that can be driven:

$105 ÷ $0.15 ≈ 700 miles

So, you can drive at most 700 miles within the $180 budget for weekly transportation.

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Answer:

P = (5.4, -2.6)

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{5 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

As the given circle has a radius of 6 units and is centred at the origin, the equation of the circle is:

[tex]x^2+y^2=36[/tex]

The formula for the equation of the tangent line to a circle with the equation x² +  y² = a² is:

[tex]\boxed{y = mx \pm a \sqrt{1+ m^2}}[/tex]

where:

To find the slope of the equation of the tangent line to the circle that passes through the point (0, -14), substitute a = 6, x = 0 and y = -14 into the formula and solve for m:

[tex]\implies -14 = m(0) \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies -14 = \pm 6 \sqrt{1+ m^2}[/tex]

[tex]\implies \pm\dfrac{14}{6} =\sqrt{1+ m^2}[/tex]

[tex]\implies \left(\pm\dfrac{14}{6}\right)^2 =1+m^2[/tex]

[tex]\implies m^2= \left(\pm\dfrac{14}{6}\right)^2-1[/tex]

[tex]\implies m^2=\dfrac{40}{9}[/tex]

[tex]\implies \sqrt{m^2}= \sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\sqrt{\dfrac{40}{9}}[/tex]

[tex]\implies m=\pm\dfrac{2\sqrt{10}}{3}[/tex]

The slope-intercept form of a straight line is y = mx + b, where m is the slope and b is the y-intercept.

As the slope of the given tangent line is positive, and the y-intercept is (0, -14), the equation of the tangent line is:

[tex]\boxed{y=\dfrac{2\sqrt{10}}{3}x-14}[/tex]

As point P is the point of intersection of the circle and the tangent line, substitute the tangent line into the equation of the circle and solve for x:

[tex]x^2+\left(\dfrac{2\sqrt{10}}{3}x-14\right)^2=36[/tex]

Expand the brackets:

[tex]x^2 +\dfrac{40}{9}x^2-\dfrac{56\sqrt{10}}{3}x+196=36[/tex]

Subtract 36 from both sides of the equation:

[tex]\dfrac{49}{9}x^2-\dfrac{56\sqrt{10}}{3}x+160=0[/tex]

Multiply both sides of the equation by 9:

[tex]49x^2-168\sqrt{10}x+1440=0[/tex]

Rewrite the equation in the form a² - 2ab + b²:

[tex](7x)^2-2 \cdot 7 \cdot 12\sqrt{10}x+(12\sqrt{10})^2=0[/tex]

Apply the Perfect Square formula: a² - 2ab + b² = (a - b)²

[tex](7x-12\sqrt{10})^2=0[/tex]

Solve for x:

[tex]7x-12\sqrt{10}=0[/tex]

[tex]7x=12\sqrt{10}[/tex]

[tex]x=\dfrac{12\sqrt{10}}{7}[/tex]

To find the y-coordinate of point P, substitute the found value of x into the equation of the tangent line:

[tex]y=\dfrac{2\sqrt{10}}{3}\left(\dfrac{12\sqrt{10}}{7}\right)-14[/tex]

[tex]y=\dfrac{2\sqrt{10}\cdot 12\sqrt{10}}{3\cdot 7}\right)-14[/tex]

[tex]y=\dfrac{240}{21}-14[/tex]

[tex]y=\dfrac{80}{7}-\dfrac{98}{7}[/tex]

[tex]y=-\dfrac{18}{7}[/tex]

Therefore, the exact coordinates of point P are:

[tex]\left(\dfrac{12\sqrt{10}}{7}, -\dfrac{18}{7}\right)[/tex]

The coordinates of point P to 1 decimal place are:

[tex](5.4, -2.6)[/tex]

The value of the distance you will run is 5.62500 miles

From the question, we have the following parameters that can be used in our computation:

This means that

Speed = 7.5 miles per hour

Time = 45 minutes

The distance you will run is calculated as

Distance = Speed * Time

Substitute the known values in the above equation, so, we have the following representation

Distance = 7.5 miles per hour * 45 minutes

Evaluate the product

Distance = 5.62500 miles

Hence, the distance is 5.62500 miles

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The cost of the Portrait frame cost is: $32.8

The formula for the perimeter of a rectangle is given by the expression:

A = 2(L +  W)

Where:

L is Length

W is Width

We are given that:

Width: W = 4 ft

Height: H = 6 ft

Thus:

Perimeter = 2(6 + 4)

= 20 ft

Cost of the rectangular portrait per foot is $1.64

Thus:

Total cost = 20 * 1.64

= $32.8

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A graph of the points that represent this data are shown on the coordinate plane attached below.

In this scenario, the week number would be plotted on the x-axis (x-coordinate) of the scatter plot while the amount of money (in dollars) would be plotted on the y-axis (y-coordinate) of the scatter plot through the use of Microsoft Excel.

On the Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the line of best fit (trend line) on the scatter plot.

From the scatter plot (see attachment) which models the relationship between the week number and the amount of money (in dollars), a linear equation for the line of best fit is as follows:

y = 1.19x + 1.05

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The expression for the given statement is √3².

We have,

The expression that can be written from the statement.

3 square root = √3

Second power of x = x²

Now,

We can write the expression as,
= √3²

Thus,

The expression for the given statement is √3².

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The term "mapping" refers to the process of creating a mathematical correspondence between points or objects in two different sets. In this case, the mapping found in part b tells us that there exists a one-to-one correspondence between the points in Circle A and the points in Circle B.

There is a one-to-one correspondence between the points in Circle A and the points in Circle B, and that this correspondence preserves distance.

This means that for every point in Circle A, there is exactly one corresponding point in Circle B that is the same distance away from the center of the circle as the original point.

Since the correspondence is one-to-one, it follows that the two circles have the same number of points. That is, if Circle A has n points, then Circle B also has n points.

Therefore, we can conclude that the two circles have the same size.

Furthermore, because the correspondence preserves distance, any transformation that maps one circle onto the other must be a rigid motion, meaning it preserves angles and distances.

In particular, the transformation must be an isometry.

Therefore, we have shown that the two circles are congruent. That is, they have the same size and shape, and can be transformed onto one another by a combination of translations, rotations, and reflections.

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To find the volume of the solid generated by revolving the region bounded by the curve y=7secx and the line y=72 over the interval − π/4≤x≤π/4 about the​ x-axis, we can use the method of cylindrical shells.

First, we need to find the equation of the curve of the region being revolved. We have y=7secx and y=72, so at the intersection point, we have 7secx=72, which gives us secx=10.285. Taking the inverse secant function of both sides, we get x=1.37 (approximately).

Now, we can set up the integral for the volume using cylindrical shells. The radius of each shell is y-72, and the height of each shell is 2π times the distance from x to the intersection point, which is x-1.37. The integral is:

V = ∫(2π)(y-72)(x-1.37) dx, from -π/4 to π/4

We can substitute y=7secx into the integral:

V = ∫(2π)(7secx-72)(x-1.37) dx, from -π/4 to π/4

Using integration by parts, we can evaluate the integral:

V = (2π)[(7/2)ln|secx+tanx| - 72x + (1.37)(7/2)ln|secx+tanx| + 46.8] from -π/4 to π/4

V = (2π)(7/2)(ln|11+6√3| + ln|11-6√3| + 1.37ln|11+6√3| + 1.37ln|11-6√3| - 144)

V ≈ 305.64 cubic units.

Therefore, the volume of the solid generated by revolving the region bounded by the curve y=7secx and the line y=72 over the interval − π/4≤x≤ π/4 about the​ x-axis is approximately 305.64 cubic units.
To find the volume of the solid generated by revolving the region bounded by the curve y=7sec(x) and the line y=72 over the interval -π/4≤x≤π/4 about the x-axis, you can use the disk method. The formula for the disk method is:

Volume = π * ∫[R(x)² - r(x)²] dx from a to b

In this case, R(x) represents the outer radius, which is given by y=72, and r(x) represents the inner radius, which is given by y=7sec(x). The limits of integration are a=-π/4 and b=π/4. Therefore, the volume can be calculated as:

Volume = π * ∫[72² - (7sec(x))²] dx from -π/4 to π/4

Now, evaluate the integral and multiply by π to find the volume of the solid.

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If a scale model of the plane is 40.6 cm long, the scale factor used to create the model is approximately 1:142.857 or 0.007 rounded to the nearest thousandth.

To determine the scale factor used to create the model, we need to divide the length of the actual airplane by the length of the model airplane:

58 m / 40.6 cm

To perform this calculation, we need to convert the units so that they match. We can convert 58 m to cm by multiplying by 100:

58 m = 58 × 100 cm = 5800 cm

Now we can divide:

5800 cm / 40.6 cm = 142.857...

Rounding to the nearest thousandth, we get:

142.857... ≈ 142.857

Therefore, the scale factor used to create the model is approximately 1:142.857 or 0.007 rounded to the nearest thousandth.

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The expression for the area of the flower garden is (45+2x)(20+2x) - 900.

Area of vegetable garden:

[tex]A_v = 45 ft * 20 ft[/tex] = 900 sq ft

Dimensions of entire garden:

Length = 45 ft + 2x

Width = 20 ft + 2x

Area of entire garden:

[tex]A_e = (45+2x)(20+2x)[/tex]

Area of flower garden:

[tex]A_f = A_e - A_v = (45+2x)(20+2x) - 900 sq ft[/tex]

So, the expression for the area of the flower garden is (45+2x)(20+2x) - 900.

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The value of the coordinates of point D is, (3, - 1)

We have to given that;

All the coordinates of rectangles are,

A(-2,1), B(-6, -9), C(-1, -11)

Now, Let the fourth coordinate of rectangle is,

D (x, y)

Hence, Midpoint of AC and BD are same.

So., Midpoint of AC is,

⇒ AC = (- 2 + (- 1))/ 2, (1 + (- 11))/2

          = (- 3/2 , - 5)

And, Midpoint of BD,

⇒ BD = (- 6 + x)/2, (- 9 + y)/2

By comparing;

⇒ (- 6 + x)/2 = - 3/2

⇒ - 6 + x = - 3

⇒ x = - 3 + 6

⇒ x = 3

⇒ (- 9 + y)/2 = - 5

⇒ - 9 + y = - 10

⇒ y = -10 + 9

⇒ y = - 1

Thus, The value of the coordinates of point D is, (3, - 1)

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Answer:

A dilation always produces a similar figure. Similar figures have the same shape but different sizes.

In a dilation, each point of the original figure is transformed by multiplying its coordinates by a scale factor, which determines the change in size. However, the shape and proportions of the figure remain unchanged. Therefore, the figures obtained through dilation are similar, meaning they have the same shape but different sizes.

The regression line equation, can be found to be y = 0.90x - 3.79

Find the slope using the slope formula :

m = ( 5 x 1944 - 98 x 69 ) / ( 5 x 2580 - 98² )

m = ( 9720 - 6762 ) / ( 12900 - 9604 )

m = 2958 / 3296

=  0.8975

Then find the y - intercept :

b = ( 69 - 0. 8975 x 98) / 5

b = ( 69 - 87. 945) / 5

b = - 18. 945 / 5

= - 3.789

The regression equation is:

y = 0.90x - 3.79

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To evaluate the indefinite integral of 3x^2 – 3x +1/ x^3 + 2, we can use partial fraction decomposition.

First, we factor the denominator: x^3 + 2 = (x + ∛2)(x^2 – ∛2x + 2).

Next, we can write the fraction as:

3x^2 – 3x +1/ x^3 + 2 = A/x + B(x^2 – ∛2x + 2) + C(x + ∛2)

Multiplying both sides by the denominator, we get:

3x^2 – 3x + 1 = A(x^2 – ∛2x + 2)(x + ∛2) + Bx(x + ∛2) + C(x^2 – ∛2x + 2)

To solve for A, B, and C, we can plug in specific values of x. For example, if we plug in x = -∛2, we get:

-2√2 + 1 = A(4√2) + C(0)

Therefore, A = (2 – √2)/8.

If we plug in x = 0, we get:

1 = A(2√2) + B(0) + C(√2)

Therefore, C = 1/√2.

Finally, if we plug in x = 1, we get:

1 = A(3√2) + B(1 – √2) + C(1 + √2)

Therefore, B = (-1 + √2)/4.

Now that we have A, B, and C, we can write the original fraction as:

3x^2 – 3x +1/ x^3 + 2 = (2 – √2)/8 * 1/x + (-1 + √2)/4 * (x^2 – ∛2x + 2) + 1/√2 * (x + ∛2)

Using this partial fraction decomposition, we can now integrate each term separately.

Integrating the first term, we get:

∫(2 – √2)/8 * 1/x dx = (1/8)(2ln|x| – √2 ln|x^2 + 2|) + C

Integrating the second term, we can complete the square to get:

∫(-1 + √2)/4 * (x^2 – ∛2x + 2) dx = (-1 + √2)/4 * ∫(x – ∛1/2)^2 + 3/2 dx = (-1 + √2)/4 * ((x – ∛1/2)^2 + 3/2) + C

Integrating the third term, we get:

∫1/√2 * (x + ∛2) dx = (1/2√2) * (x^2/2 + ∛2x) + C

Putting it all together, we have:

∫(3x^2 – 3x +1)/ (x^3 + 2) dx = (1/8)(2ln|x| – √2 ln|x^2 + 2|) + (-1 + √2)/4 * ((x – ∛1/2)^2 + 3/2) + (1/2√2) * (x^2/2 + ∛2x) + C

where C is the constant of integration.

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Therefore, approximately 45.45% of students collected between 49 and 98 kilograms of newspapers.

Total number of students is 22.

To find the percentage of students who collected between 49 and 98 kilograms of newspapers, we first need to count the number of students who collected within this range. From the given data, we can see that the following students collected between 49 and 98 kilograms of newspapers

87, 64, 90, 76, 60, 55, 57, 75, 56, 88

Percentage of students = (number of students in range / total number of students) x 100

= (10 / 22) x 100

= 45.45%

Therefore, approximately 45.45% of students collected between 49 and 98 kilograms of newspapers.

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Answer: a. Using a TVM solver with the following inputs:

Present value (PV) = 150

Interest rate (I/Y) = 6/12 = 0.5 (monthly interest rate)

Number of periods (N) = 40 years x 12 months/year = 480

Payment (PMT) = -150 (negative because it's an outgoing cash flow at the beginning of each month)

Compounding frequency (C/Y) = 12 (monthly compounding frequency)

We get an accumulated amount (FV) of $222,812.64.

b. Using a TVM solver with the following inputs:

Present value (PV) = 900

Interest rate (I/Y) = 4/2 = 2 (semi-annual interest rate)

Number of periods (N) = 40 years x 2 semi-annual periods/year = 80

Payment (PMT) = 0 (because there are no regular payments)

Compounding frequency (C/Y) = 2 (semi-annual compounding frequency)

We get an accumulated amount (FV) of $3,054.58.

c. Using a TVM solver with the following inputs:

Present value (PV) = 450

Interest rate (I/Y) = 5/4 = 1.25 (quarterly interest rate)

Number of periods (N) = 40 years x 4 quarterly periods/year = 160

Payment (PMT) = 0 (because there are no regular payments)

Compounding frequency (C/Y) = 4 (quarterly compounding frequency)

We get an accumulated amount (FV) of $2,109.64.

Step-by-step explanation: can i get brainliest :D

To calculate the accumulated amount in each investment after 40 years, we can use the TVM solver. For each investment, use the appropriate formula to calculate the accumulated amount by plugging in the given values of principal amount, interest rate, number of times interest is compounded per year, and number of years. Finally, calculate the accumulated amount to find the answer.

a. To calculate the accumulated amount in the first investment, $150 invested on the first day of each month at 6% compounded monthly for 40 years, you can use the formula:

A = 150(1 + 0.06/12)^(12*40)

A=1643.61

b. To calculate the accumulated amount in the second investment, $900 invested on January 1st and July 1st at 4% compounded semi-annually for 40 years, you can use the formula:

A = 900(1 + 0.04/2)^(2*40)

A=4387.89

c. To calculate the accumulated amount in the third investment, $450 invested on January 1st, April 1st, July 1st, and October 1st at 5% compounded quarterly for 40 years, you can use the formula:

A = 450(1 + 0.05/4)^(4*40)

A=3284.11

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The sample mean difference in heights for these 24 pairs of siblings is 1.79 inches. So the third option is correct.

The 95% confidence interval for the mean difference in heights for all brother-and-sister pairs in the population was (–0.76, 4.34).

This means that if we were to repeat this sampling process many times, we would expect 95% of the resulting confidence intervals to contain the true mean difference in heights for all brother-and-sister pairs in the population.

To find the sample mean difference from these 24 pairs of siblings, we take the midpoint of the confidence interval. The midpoint is the average of the lower and upper bounds, which is:

(-0.76 + 4.34) / 2 = 1.79

Therefore, the sample mean difference in heights for these 24 pairs of siblings is 1.79 inches.

So the correct answer is third option.

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Answer: yes, the game is fair.

Step-by-step explanation:

The game is fair because:

a. you are playing with multiple players, and they have equal odds

b. the odds of winning are higher, so there is balance since you earn less points.

Give brainliest please!

Walter can stay within his budget by dropping Fes (option ii).

Walter's original itinerary includes trips to Marrakech, Fes, Kenitra, and Oujda, which will cost him a total of 478 + 478 + 778 + 683 = MAD 2,417. This exceeds his budget of MAD 2,500.

Option i suggests replacing Kenitra with Tangier and Oujda with Casablanca, which will cost a total of 610 + 466 + 610 + 466 = MAD 2,152. However, this still exceeds Walter's budget.

Option iii suggests replacing Marrakech with Casablanca, which will cost a total of 965 + 466 + 778 + 683 = MAD 2,892, which is over Walter's budget.

Therefore, the only option that allows Walter to stay within his budget is to drop Fes from his itinerary, which will cost a total of 478 + 778 + 683 = MAD 1,939. This is well within his budget of MAD 2,500. So optio 2 is correct.

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Answer:

Si hoy es martes en 300 días será lunes.

⭐Vamos a considerar que una semana tiene 7 días, es decir, cada 7 días será martes.

Pensamos una aproximación de semanas, al dividir 300 entre 7:

300 ÷ 7 = 42,85 ≈ 42 semanas completas

Cantidad de días que hay en 42 semanas:

7 × 41 = 294 días

Cantidad de días que faltan para completar 300:

300 - 294 = 6 días

El día 294 será martes

6 días después (para completar 300) será lunes ✔️

Step-by-step explanation:

Brainlist porfavor

Answer:

Si hoy es martes en 300 días será lunes.

To find the answer, we need to identify the quartiles of the data set and use them to construct the box plot.

First, we need to order the data set in increasing order:

10, 15, 20, 25, 30, 35, 40, 45, 50, 55

Next, we need to find the median (Q2) of the data set. Since we have an even number of data points, we take the average of the two middle values:

Q2 = (25 + 30) / 2 = 27.5

This value represents the median of the data set.

To find Q1 and Q3, we divide the data set into two halves:

10, 15, 20, 25, 30 | 35, 40, 45, 50, 55

Q1 is the median of the lower half:

Q1 = (15 + 20) / 2 = 17.5

Q3 is the median of the upper half:

Q3 = (45 + 50) / 2 = 47.5

We can now use this information to construct the box plot:

     |         -------

     |        /

     |    -------

     |   /

     |-------

     |         10    20    30    40    50

            Q1          Q2         Q3

The box represents the middle 50% of the data (from Q1 to Q3), while the whiskers represent the minimum and maximum values that are not outliers.

Since we want to find the paint time for a student who is slower than 75% of the other students, we need to look at the upper quartile (Q3) of the data set. 75% of the data is contained between Q1 and Q3, so a student who is slower than 75% of the other students would have a paint time greater than Q3.

Therefore, the answer is 46 minutes, which is greater than Q3 (47.5 minutes).

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The probability is 0.125

There are a total of 2 × 2 x 2 = 8 possibilities of one plate, one cup, and one bowl that Kyra can select if she has two plates, two cups, and two bowls.

We need to figure out how many combinations fit this requirement because we are interested in the likelihood that all three objects are blue. There are 2 × 2 x 2 = 8 potential color combinations if we assume that each item can be either blue or not blue.

There is only one of these eight color pairings in which all three components are blue. P(all three are blue) = 1/8 = 0.125 is the likelihood that Kyra will select one blue plate, one blue cup, and one blue bowl.

So, the probability is 0.125.

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The equation representing the value of the stock, V(t), in dollars, t years after 1940 is V(t) = $1.25 * [tex]1.07^t[/tex].

Let V(0) be the value of the stock in 1940, which is given as $1.25. Then, the value of the stock after t years (t > 0) can be found by multiplying the initial value with the growth factor of 1.07 raised to the power of the number of years of growth. Thus, the equation representing the value of the stock, V(t), in dollars, t years after 1940 is:

V(t) = V(0) * [tex](1 + 0.07)^t[/tex]

Substituting the given value of V(0) = $1.25, we get:

V(t) = $1.25 * [tex](1 + 0.07)^t[/tex]

Simplifying this expression, we get:

V(t) = $1.25 * [tex]1.07^t[/tex]

Therefore, the equation representing the value of the stock, V(t), in dollars, t years after 1940 is V(t) = $1.25 * [tex]1.07^t[/tex].

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Step-by-step explanation:

= sqrt ( 28 ÷7) = sqrt (4) = 2

Answer:

2

Step-by-step explanation:

First we put the two equations together so it would be like this

[tex]\sqrt \frac{28}{7}[/tex]

the square root of that is 4 because 7 goes into 28 four times

so now we have this [tex]\sqrt{4}[/tex]

and the square root of 4 is 2