let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)

Answers

Answer 1

Answer:

12

Step-by-step explanation:

so basically

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped :)

Answer 2

The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.

Given functions are:

[tex]f(x) = x^2+2[/tex]

[tex]g(x) = 1-3x[/tex]

Now,

⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]

By applying multiplication, we get

           [tex]=x^2+2-3x^3-6x[/tex]

           [tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)

By substituting the value "-1" in place of "x" in equation 1, we get

⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]

                  [tex]=-3(-1)+1+6+2[/tex]

                  [tex]=3+1+6+2[/tex]

                  [tex]=12[/tex]

Thus the right answer is (fg)(-1) = 12.

Learn more:

https://brainly.com/question/10057660

Let F(x)=x^2 +2 And G(x)=1-3x. Find Each Function Value: (fg)(-1)

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

50

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

h(x) = f(g(x)) = f(x-6) = 1/x-6

1/x-6 could only be accomplished if f(x) = 1/x

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https://brainly.com/question/8776301

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