Lee put $10,000 into a stock market index mutual fund that grew at an average of 7% per year for 10 years. About how much is in Lee's mutual fund account after 10 years? Ignore compounding.

Answers

Answer 1

Answer:

17000

Step-by-step explanation:

we can use the equation I=PRT

I=10,000(10)(0.07)

I=100,000(0.07)

i=7000

7000+ the initial 10,000=17000


Related Questions

Y is directly proportional to (x+2)2 when x=8 y=250 find y when x=4

Answers

Answer:

Y=150

Step-by-step explanation:

Just apply the proportionality rulw and solve for k. Then substitute the value of k into the equation.

Answer:

90

Step-by-step explanation:

Let the constant of proportionality be K

So that;

Y= K(x+2)^2

This means

For two corresponding points (x1,y1) and (x2,y2) we have;

Y1/(x1+2)^2= Y2/(x2+2)^2

If we consider x=8 y=250 as point (x1,y1) and y when x=4 as (x2,y2) we have ;

250/(8+2)^2 =y/(4+2)^2

250/(10)^2 = y/(6)^2

250/100 = y/36

250/100 × 36 = y

90= y

y=90

The sets F and H are given below.
F={c,f,g}
H= {d,e,h)
Find the union of F and H.
Find the intersection of F and H.

Answers

Answer:

  F ∪ H = {c, d, e, f, g, h}

  F ∩ H = { }

Step-by-step explanation:

The union is the list of elements that are in either of the two sets.

  F ∪ H = {c, d, e, f, g, h}

The intersection is the list of only those elements that appear in both sets. (There are none.)

  F ∩ H = { } . . . . the empty set

The HR department of a large company wants to determine how often to bring representatives from the financial firm managing employee pensions on site to meet with individuals about their retirement plans. In order to determine level of interest, they decide to survey employees. Suppose they group employees by age categories (e.g., under 30; 30 – under 45; 45 – under 60, 60 or older) and randomly select 50 individuals from each category. This sampling plan is called ________________________ .

a) stratified samplingb) simple random samplingc) cluster samplingd) convenience samplinge) systematic sampling

Answers

Answer:

Systematic Sampling

Step-by-step explanation:

a trapazoid is a quadrilateral with one or more pairs of paralllel sides true or false

Answers

yes the answer is( true).

Answer:

The answer is (True)

Step-by-step explanation:

Tomas has two boxes to be shipped. One box weighs 3 \text{ kilograms}3 kilograms3, start text, space, k, i, l, o, g, r, a, m, s, end text. The other box weighs 720 \text{ grams}720 grams720, start text, space, g, r, a, m, s, end text.

Answers

Answer:

3.72kg

$29.76

See explanation below

Step-by-step explanation:

The question is incomplete as we are not told what we are to determine. Consider the following question

Question:

Tomas has two boxes to be shipped. One box weighs 3 kilograms. The other box weighs 720 grams.

a) What is the total weight of the boxes in kilogram?

b) If the shipping cost $8 per kilogram, what is the total cost of shipping.

Solution:

This is a question on measuring mass.

a) Total weight of the two boxes = weight of 1st box + weight of 2nd box

1st box = 3kg

2nd box = 720g

1000 g is equal to 1 kg

720g = (720/1000)kg = 0.72 kg

2nd box = 0.72 kg

Total weight of the two boxes = 3kg + 0.72kg

Total weight of the two boxes = 3.72kg

b) cost of shipping per kg = $8

cost of shipping for 3.72 kg = 8 × 3.72

Total cost of shipping for both boxes = $29.76

Answer: from my calculations its 3.72

which is also 3720 grams

A bottle of water is supposed to have 12 ounces. The bottling company has determined that 98% of bottles have the correct amount. Which of the following describes a binomial experiment that would determine the probability that a case of 36 bottles has all bottles properly filled?
A. Zn=36, p=0.98, x=0
B. n=36, p=0.98, x=12
C. n=0, p=0.98, x=36
D. n=12, p=36, x=98

Answers

Answer:

B. n=36, p=0.98, x=12

Step-by-step explanation:

98% of bottles have the correct amount.

The probability is equal to 0.98

That is p = 0.98

A bottle of water is supposed to have 12 ounces.

That is the expected value is 12

X = 12

36 bottles has all bottles properly filled

The possible sample space is 36

N = 36

The volume of gas V held at a constant temperature in a closed container varies inversely with its pressure P.If the volume of gas is 400 cubic centimeters (cc) . When The pressure is 300 millimeters of mercury ( mm Hg) , find the volume when the pressure is 500 mm Hg .

When the pressure is 500 mm Hg, the volume is

Answers

Answer:

240cc

Explanation:

From the expression of the relationship between pressure and volume, we can state mathematical that for two successive volume V1 and V2 and Pressure P1 and P2 we have:

P1V1 = P2V2

V2 = P1V1 / P2

=400×300/500= 240cc

The radius of a 10” pizza is 5”. Using A= pi2, what is the area of the 10” pizza? (Round to the nearest tenth)

How many times larger is the 15” than 10” pizza?

Is this surprising? Why or why not?


If you doubled the diameter of a circle, how many times larger would it’s area become?

Answers

Answer:

846^% and then to rond it is 850^%

Step-by-step explanation:

e radius of a 10” pizza is 5”. Using A= pi2, what is the area of the 10” pizza? (Round to the nearest tenth)

C. One half of the sum of six times a number and twenty-two

Answers

Answer:

Step-by-step explanation:

One half

On June 18, Smith Technologies issued a $75,000, 6%. 180-day note payable to Johnson Company. What is
the due date of the note? 15
a. December 16

b. December 17​

Answers

Answer:

a. December 16

Step-by-step explanation:

18 June + 180 days = 15 December

Since 2 options given,

a. December 16 is the answer

The correct answer is B

Q 3.28: To create a confidence interval from a bootstrap distribution using percentiles, we keep the middle values and chop off a certain percent from each tail. Indicate what percent of values must be chopped off from each tail for a 97% confidence level. A : We keep the middle 97% of values by chopping off 1.5% from each tail. B : We keep the middle 1.5% of values by chopping off 97% from each tail. C : We keep the middle 3% of values by chopping off 97% from each tail. D : We keep the middle 3% of values by chopping off 1.5% from each tail. E : We keep the middle 97% of values by chopping off 3% from each tail.

Answers

Answer:

A : We keep the middle 97% of values by chopping off 1.5% from each tail.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.97}{2} = 0.015[/tex]

This means that for a 97% confidence interval, 1.5% of each tail is removed, while the middle 97% of values are kept.

So the corect answer is:

A : We keep the middle 97% of values by chopping off 1.5% from each tail.

factoriza C (x) 42x4 − 36x2 + 24x + 12

Answers

Answer:

factor out 12

[tex]12(14cx - 5 + 2x)[/tex]

Imagine that you are conducting a one-variable chi-square test to investigate the hypothesis that there are equal numbers of cat lovers and dog lovers in the office at work. Having conducted a survey, you found 150 preferred dogs and 120 preferred cats. What would the expected frequencies be in each cell? 135 150 and 120 270 More information is needed to calculate the expected frequencies.

Answers

Answer:

135

Step-by-step explanation:

Based on the following information:

- There are 150 dog lovers

- There are 120 cat lovers

So:

The null hypothesis:

H, there are an equal number of dog lovers and cat lovers, so the expected frequency in each cell will be the same and that is:

f = (150 + 120) / 2

f = 270/2 = 135

then the first option of 135 is correct

A tour operator has a bus that can accommodate 20 tourists. The operator knows that tourists may not show up, so he sells 21 tickets. The probability that an individual tourist will not show up is 0.02, independent of all other tourists. Each ticket costs 50, and is non-refundable if a tourist fails to show up. If a tourist shows up and a seat is not available, the tour operator has to pay 100 (ticket cost + 50 penalty) to the tourist. What is the expected revenue of the tour operator?

Answers

Answer:

The expected revenue is $984.6.

Step-by-step explanation:

The tourist operator sells 21 non-refundable tickets, as the tourist may not show up.

The tourist have a probability of 0.02 of not showing up, independent of each other.

The income is the selling of the 21 tickets at $50 each.

[tex]I=21*50=1,050[/tex]

The only cost considered in this problem is the refund if a tourist show up and a seat is not available.

This only happens when the 21 tourists show up. If each tourist has a probability of 0.02 of not showing up, they have a probability of 0.98 of showing up.

For the event that the 21 tourists show up, we have the probability:

[tex]P=0.98^{21}\approx0.654[/tex]

For each of this event, the tour operator has to pay $100, so the expected revenue of the tour operator is:

[tex]E(R)=I-E(C)=1,050-0.654\cdot 100=1,050-65.4=984.6[/tex]

Suppose a standard six-sided die is rolled and you receive $0.50 for every dot showing on the top of the die. What should the cost of playing the game be in order to make it a fair game?
The cost of playing the game should be $. ?

Answers

the cost of playing the game should be $14

A number is randomly selected from {1, 2, 3, 4, 5, 6, 7, 8, 9, 10).
What is the COMPLEMENT of selecting a number greater than 7?
Enter your answer as a FRACTION.

Answers

In this case, the complement would be selecting a number less than or equal to 7; the probability of this occurring is [tex]\boxed{\frac{7}{10}}.[/tex]

Answer:

it is 3/10

Step-by-step explanation:

1, 2, 3, 4, 5, and 6 are all LESS than 7. 8, 9, and 10 are all GREATER than 7, therefor, [tex]\frac{3}{10}[/tex] is the complement.

00:00
Gavin counted the number of days until the end of school.
If he counted the days in groups of 7, which list shows the numbers Gavin could have
named?
O
A. 7, 15, 22, 30
B. 7, 14, 21, 30

C. 7, 14, 21, 28
D. 14, 21, 32, 38

Answers

Answer:

  C.  7, 14, 21, 28

Step-by-step explanation:

Since you know your times tables, you know that multiples of 7 are ...

   7, 14, 21, 28

Question 7 (5 points)
Consider the function f(x) = f(x)=-x^4+ 9. Determine which of the following is its
graph, based on end behavior.​

Answers

Answer:

.

Step-by-step explanation:

What are the factors of the expression below 9x^2+6x+1?

Answers

[tex]answer = (3x + 1)\\ solution \\ {9x}^{2} + 6x + 1 \\ = {9x}^{2} + (3 + 3)x + 1 \\ = {9x}^{2} + 3x + 3x + 1 \\ = 3x(3x + 1) + 1(3x + 1) \\ = (3x + 1)(3x + 1) \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]


Here,
9x^2+6x+1
9x^2+(3+3)x+1
9x^2+3x+3x+1
3x(3x+1)+1(3x+1)
(3x+1)(3x+1)
(3x+1)^2

] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was found that 502 out of 1045 had a mentor in college. Test the claim that the proportion of college grads in Colorado who had a mentor is greater than that of all US college grads. Set up a sampling distribution of proportions.

Answers

Answer:

[tex]z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930[/tex]  

The p value for this case would be given by:

[tex]p_v =P(z>3.930)=0.0000443[/tex]  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

[tex]\hat p=\frac{502}{1045}=0.480[/tex] estimated proportion of college graduates with a mentor

[tex]p_o=0.42[/tex] is the value that we want to test

z would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:[tex]p \leq 0.42[/tex]  

Alternative hypothesis:[tex]p > 0.42[/tex]  

The statistic is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

Replacing the info we got:

[tex]z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930[/tex]  

The p value for this case would be given by:

[tex]p_v =P(z>3.930)=0.0000443[/tex]  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Find the volume. Round your answer to one decimal place.
(PLZ SOMEBODY HELP ASAP)

Answers

Answer:

32.738ft³

32.7ft³

Step-by-step explanation:

This is half a sphere therefore volume=4/3πr³×1/2

4/3×22/7×2.5³×1/2

=32.738ft³

Find the intersection(s) of the line y = 2x - 3 with the circle whose center at origin, radius = 4

Answers

Answer:

[tex] x = \frac{12 \pm \sqrt{(-12)^2 -4(5)(-7)}}{2(5)}[/tex]

And we got for the solution:

[tex] x_1= 2.885 , x_2 = -0.485[/tex]

And the value sof y are using the function y =2x-3:

[tex] y_1=2.77, y_2=-3.97[/tex]

Step-by-step explanation:

For this case we have this function given:

[tex] y = 2x-3[/tex]  (1)

And the circle with center the origin and radius 4 is given by;

[tex] x^2 +y^2 = 16[/tex]  (2)

We can solve fro y from the last equation and we got:

[tex] y = \pm \sqrt{16-x^2}[/tex]   (3)

Now we can set equal equations (3) and (1) and we got:

[tex] 2x-3 = \sqrt{16-x^2}[/tex]

[tex] (2x-3)^2=16-x^2[/tex]

[tex] 4x^2 -12x +9 = 16-x^2[/tex]

[tex] 5x^2 -12x -7=0[/tex]

And using the quadratic equation we got:

[tex] x = \frac{12 \pm \sqrt{(-12)^2 -4(5)(-7)}}{2(5)}[/tex]

And we got for the solution:

[tex] x_1= 2.885 , x_2 = -0.485[/tex]

And the value sof y are using the function y =2x-3:

[tex] y_1=2.77, y_2=-3.97[/tex]

A bag contains four red, three green, and five yellow marbles. Three marbles are drawn,
One at time, without replacement. Determine the probability that the order in which they
are selected is(9A)
Ca) Yellow, red, green
(b) Yellow, green, green
(c) Yellow, Yellow, red
m how many ways can neople be selected from a group that consists of four adults a

Answers

Probability simplified is almost like asking how much are you likely to do something,in this case; select a certain color of marbles.

The Probability of choosing a red marble is 4 expressed as a numerator to the total number of marbles.(4/12---> 1/3)

Green- (3/12---> 1/4)


Yellow- (5/12)

For this question you don't even have to calculate the probability. You're most likely to select the yellow ones because they're the majority.


Hope this helped:)

The improper fraction 37/6 can be changed to the mixed number​

Answers

Answer: 6 1/6

Step-by-step explanation:

6 can go into 37 6 times

6x6=36

with 1 left over

The fraction 37/6 can be changed to the mixed number​ as 6 1/6 if the fraction is 37/6.

What is a fraction?

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

The fraction is:

= 37/6

We can write the above number as:

= (36 + 1)/6

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

= 36/6 + 1/6

= 6 + 1/6

Or

= 6 1/6 (mixed fraction)

Thus, the fraction 37/6 can be changed to the mixed number​ as 6 1/6 if the fraction is 37/6.

Learn more about the fraction here:

brainly.com/question/1301963

#SPJ2

In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is supposed to increase reliability by increasing the time between failures. Tests on a sample of 36 modified components produce a mean time between failures of 960 hours, with a standard deviation of 52 hours. Using a significance level of .01, test the claim that, for modified components, the mean time between failures is greater than 937 hours. Find the appropriate p-value.

Answers

Answer:

Null hypothesis is [tex]\mathbf {H_o: \mu > 937}[/tex]

Alternative hypothesis is [tex]\mathbf {H_a: \mu < 937}[/tex]

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean [tex]\overline x[/tex] = 960 hours

Sample size n = 36

Mean population [tex]\mu =[/tex] 937

Standard deviation [tex]\sigma[/tex] = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is [tex]\mathbf {H_o: \mu > 937}[/tex]

Alternative hypothesis is [tex]\mathbf {H_a: \mu < 937}[/tex]

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

[tex]Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}[/tex]

[tex]Z = \dfrac{23}{8.66}[/tex]

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

The mean percent of childhood asthma prevalence in 43 cities is 2.22​% . A random sample of 30 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.5​%? Interpret this probability. Assume that sigma equals 1.39​%. nterpret this probability. Select the correct choice below and fill in the answer box to complete your choice. ​(Round to two decimal places as​ needed.) (A. What % of samples of 43 cities will have a mean childhood asthma prevalence greater than 2.5​%? (B. What ​% of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.22​%? (C. What% of samples of 30 cities will have a mean childhood asthma prevalence greater than 2.5?

Answers

Answer:

C.

Step-by-step explanation:

Hello!

Given the variable:

X: childhood asthma prevalence

With mean μ= 2.22%

and standard deviation σ= 1.39%

You have to calculate the probability of the sample average of childhood asthma prevalence in a sample of n= 30 cities is greater than 2.5%

We don't know the distribution of the variable, but remember that thanks to the central limit theorem, since the n ≥ 30, we can approximate the sampling distribution to normal:

X[bar]≈N(μ;σ²/n)

And use the standard normal distribution to calculate the asked probability:

P(X[bar]>2.5)= 1 - P(X≤2.5)

Calculate the Z value for the given X[bar] value:

[tex]Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } = \frac{2.5-2.22}{\frac{1.39}{\sqrt{30} } }= 1.10[/tex]

Using the Z-tables you have to look for the value of

P(Z≤1.10)= 0.86433

1 - 0.86433= 0.13567

Then P(X[bar]>2.5)= 1 - P(X≤2.5)= 1 - P(Z≤1.10)= 1 - 0.86433= 0.13567

13.567% of the 30 cities will have a mean childhood asthma prevalence greater than 2.5%

I hope this helps!

A rectangular box with a volume of 684 ftcubed is to be constructed with a square base and top. The cost per square foot for the bottom is 20cents​, for the top is 15cents​, and for the sides is 1.5cents. What dimensions will minimize the​ cost?

Answers

Answer:

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.  

Minimum cost=2046.16 cents      

Step-by-step explanation:

Given that a rectangular box with a volume of 684 ft³.

The base and the top of the rectangular box is square in shape

Let the length and width of the rectangular box be x.

[since the base is square in shape,  length=width]

and the height of the rectangular box be h.

The volume of rectangular box is = Length ×width × height

                                                      =(x²h) ft³

[tex]x^2h=684\Rightarrow h=\frac{684}{x^2}[/tex]  (1)

The area of the base and top of rectangular box is = x² ft²

The surface area of the sides= 2(length+width) height

                                               =2(x+x)h

                                               =4xh ft²

The total cost to construct the rectangular box is

=[(x²×20)+(x²×15)+(4xh×1.5)] cents  

=(20x²+15x²+6xh) cents

=(25x²+6xh) cents

Total cost= C(x).

C(x) is in cents.

∴C(x)=25x²+6xh

Putting [tex]h=\frac{684}{x^2}[/tex]

[tex]C(x)=25x^2+6x\times\frac{684}{x^2} \Rightarrow C(x)=25x^2+\frac{4104}{x}[/tex]

Differentiating with respect to x

[tex]C'(x)=50x-\frac{4104}{x^2}[/tex]

To find minimum cost, we set C'(x)=0

[tex]\therefore50x-\frac{4104}{x^2}=0\\\Rightarrow50x=\frac{4104}{x^2}\\\Rightarrow x^3=\frac{4104}{50}\Rightarrow x\approx 4.345[/tex] ft.

Putting the value x in equation (1) we get

[tex]h=\frac{684}{(4.345)^2}[/tex]

 ≈36.23 ft.

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.  

Minimum cost C(x)=[25(4.345)²+10(4.345)(36.23)] cents

                               =2046.16 cents      

y - ( -3y ) what is the answer????

Answers

Answer:

4y

Step-by-step explanation:

y - -3y

Subtracting a negative is like adding

y+3y

Combine like terms

4y

Answer:

[tex]4y[/tex]

Step-by-step explanation:

[tex]y - ( - 3y) \\ y + 3y \\ = 4y[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Compute the quadratic form xTAx for A = [3 2 0, 2 2 1, 0 1 0].
A. x = [x1 x2 x3].
B. x = [-2 -1 5].
C. x = [1/2 1/2 1/2].

Answers

Answer:

(a)[tex]x^TAx=3x_1^2+4x_1x_2+2x_2^2+2x_2x_3[/tex]

(b) 12

(c)[tex]2\frac{3}{4}[/tex]

Step-by-step explanation:

[tex]G$iven A=\left[\begin{array}{ccc}3&2&0\\2&2&1\\0&1&0\end{array}\right][/tex]

We are to compute the quadratic form [tex]x^TAx[/tex] for A.

Part A

[tex]x=\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right][/tex]

[tex]x^TAx = \left[\begin{array}{ccc}x_1&x_2&x_3\end{array}\right]\left[\begin{array}{ccc}3&2&0\\2&2&1\\0&1&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right][/tex]

[tex]= \left[\begin{array}{ccc}x_1&x_2&x_3\end{array}\right]\left[\begin{array}{ccc}3x_1+2x_2+0x_3\\2x_1+2x_2+1x_3\\0x_1+1x_2+0x_3\end{array}\right][/tex]

[tex]= x_1(3x_1+2x_2+0x_3)+x_2(2x_1+2x_2+1x_3)+x_3(0x_1+1x_2+0x_3)\\= x_1(3x_1+2x_2)+x_2(2x_1+2x_2+x_3)+x_3(x_2)[/tex]

[tex]= 3x_1^2+2x_1x_2+2x_1x_2+2x_2^2+x_2x_3+x_2x_3\\\\x^TAx=3x_1^2+4x_1x_2+2x_2^2+2x_2x_3[/tex]

Part B

[tex]x=\left[\begin{array}{ccc}-2\\-1\\5\end{array}\right]\\x^TAx=3x_1^2+4x_1x_2+2x_2^2+2x_2x_3\\=3(-2)^2+4(-2)(-1)+2(-1)^2+2(-1)(5)\\=3*4+4*2+2-10\\=12+8+2-10\\=12[/tex]

Part C

[tex]x=\left[\begin{array}{ccc}\frac{1}{2}\\\frac{1}{2}\\\frac{1}{2}\end{array}\right]\\x^TAx=3x_1^2+4x_1x_2+2x_2^2+2x_2x_3\\=3(\frac{1}{2})^2+4(\frac{1}{2})(\frac{1}{2})+2(\frac{1}{2})^2+2(\frac{1}{2})(\frac{1}{2})\\\\=\frac{3}{4}+1+ \frac{1}{2}+\frac{1}{2}\\\\=2\frac{3}{4}[/tex]

I NEED HELP!!! NOW!!!! A shape is picked at random from the group below.


2 circles, 4 triangles, and 2 squares.


Which event has a theoretical probability of exactly Three-fourths? Select three options.

not picking a square

picking a square

picking a triangle

picking a shape that has only straight edges

not picking a circle

Answers

Theoretical probability formula: Favorable Outcomes/All Possible Outcomes

So let's find the theoretical probability for each option.

"Not picking a square"

So, there are 2 squares out of the 8 total shapes (2 circles + 4 triangles + 2 squares) So do 8-2=6... This is subtracting the number of squares out. So we are now left with 6/8.. Reduce the fraction: GCF is 2, so 6/8 simplifies to 3/4. So, "Not picking a square" is an option!

"Picking a square"

Okay so there are 2 squares (favorable outcome) out of 8 shapes in total (all possible outcomes) so the fraction is 2/8. Now simplify: GCF = 2, so 2/8 = 1/4. "Picking a square" is NOT an option

"Picking a triangle"

There are 4 triangles out of 8 shapes, so the fraction is 4/8 which = 1/2. The theoretical probability of picking a triangle is 1/2 and thus NOT an option.

"Picking a shape that has only straight edges"

So this basically means every shape that's not a circle. So, there are 4 triangles + 2 squares = 6 total shapes with straight edges. So there are 6 shapes with straight edges out of 8 total shapes: 6/8 reduces to 3/4. "Picking a shape that has only straight edges" IS an option! :D

LASTLY!

"Not picking a circle"

There are only 2 circles out of 8 total shapes, so 8-2=6 so the fraction is 6/8. This reduces to 3/4. "Not picking a circle" Is an option!

CORRECT ANSWERS:

Not picking a square

Picking a shape that has only straight edges

Not picking a circle

Have a good day!

Answer:

A, D, and E

Step-by-step explanation:

got it right on edge

Other Questions
The function f is defined by f(x)=2x -1.Find f(2x). The wings of a honeybee move at a frequency of 220 Hz. What is the period for a complete wing-beat cycle? The Air conditioner unit in the classroom uses 120 volts. it requires 2000 watts of usage on the average, and it stays on for 8 hours every day. Find out the Amps, Watt hrs/Day, Watts hrs/yr, Kilowatt Hrs/Yr and cost/Yr if the cost of elelctricity per kilowatt is $0.25 All of the following are TRUE of the prosecution EXCEPT *Represents the governmentBrings criminal chargesRepresent the defensePresents evidence to the court On January 1, 2021, the general ledger of Big Blast Fireworks includes the following account balances:Accounts Debit Credit Cash $ 25,700 Accounts Receivable 46,000 Allowance for Uncollectible Accounts 4,100 Inventory 49,000 Land 90,100 Accounts Payable 25,700 Notes Payable (6%, due in 3 years) 49,000 Common Stock 75,000 Retained Earnings 57,000 Totals $ 210,800 $ 210,800 The $49,000 beginning balance of inventory consists of 490 units, each costing $100. During January 2021, Big Blast Fireworks had the following inventory transactions:January 3 Purchase 1,750 units for $196,000 on account ($112 each).January 8 Purchase 1,850 units for $216,450 on account ($117 each).January 12 Purchase 1,950 units for $237,900 on account ($122 each).January 15 Return 195 of the units purchased on January 12 because of defects.January 19 Sell 5,700 units on account for $855,000. The cost of the units sold is determined using a FIFO perpetual inventory system.January 22 Receive $837,000 from customers on accounts receivable.January 24 Pay $620,000 to inventory suppliers on accounts payable.January 27 Write off accounts receivable as uncollectible, $2,800.January 31 Pay cash for salaries during January, $138,000.The following information is available on January 31, 2021.At the end of January, the company estimates that the remaining units of inventory are expected to sell in February for only $100 each.The company estimates future uncollectible accounts. The company determines $5,900 of accounts receivable on January 31 are past due, and 35% of these accounts are estimated to be uncollectible. The remaining accounts receivable on January 31 are not past due, and 5% of these accounts are estimated to be uncollectible. (Hint: Use the January 31 accounts receivable balance calculated in the general ledger.)Accrued interest expense on notes payable for January. Interest is expected to be paid each December 31.Accrued income taxes at the end of January are $14,200.Record each of the transactions listed above in the 'General Journal' tab (these are shown as items 1 - 10) assuming a FIFO perpetual inventory system. Review the 'General Ledger' and the 'Trial Balance' tabs to see the effect of the transactions on the account balances.2. Record adjusting entries on January 31. in the 'General Journal' tab (these are shown as items 11-14).3. Review the adjusted 'Trial Balance' as of January 31, 2021, in the 'Trial Balance' tab.4. Prepare a multiple-step income statement for the period ended January 31, 2021, in the 'Income Statement' tab.5. Prepare a classified balance sheet as of January 31, 2021, in the 'Balance Sheet' tab.6. Record the closing entries in the 'General Journal' tab (these are shown as items 15 and 16).7. Using the information from the requirements above, complete the 'Analysis' tab. Convert 84 ounces to milliliters What are the excluded values? x = -3; z = 0 y = -5; z = 0 y = 0; z = -5 none of the above Although they are friends, Huck Finn and Tom Sawyer display different character traits and responses to events and toone another's suggested plans. State one trait of each character that is evidenced in this excerpt. Explain howdifferences between the two characters add to the development and resolution of the episode presented. Includeevidence from the text. The word affect is a _____. nounverb The dean of the engineering school at a technical university wants to emphasize the importance of having students who are gifted at reading and writing as well as math. She wants to know if she can accurately claim that graduate students in engineering programs at her school have significantly higher scores on the verbal reasoning section of the GRE (a standardized test used in the admissions process for many graduate programs) than the national average for engineering students. The national average for the verbal reasoning GRE score for engineering students was 150 with a standard deviation of 9. A random sample of 49 engineering graduate students at her school were found to have an average verbal reasoning GRE score of 153. After analyzing the data to determine whether the mean verbal reasoning GRE score of the engineering graduate students at the technical university is higher than the national average, the p-value of 0.0099 was obtained. Using a 0.05 significance level, what conclusion can be drawn from the data? The kitchen-tile installer has 20 green, 14 beige, and 16 white tiles in a box. What is the probability of picking a beige tile from the box without looking? Whats the surface area of this prism? How did Midway show the value of military intelligence? Bad gums may mean a bad heart. Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums. Only 33% of healthy people have this disease. Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability. A. If someone has periodontal disease, what is the probability that he or she will have a heart attack Someone help me with #2 and #3 Can anybody answer these questions. By the way the questions are seperated in different screenshots that i put. Only monks and Nuns are real Buddhists. Do you agree with the statement? Write 5 sentences to explain the answer I need any information on the death of Tupac Shakur I want to investigate this murder myself and see what i can find. The Alexandrian scholar-poet Callimachus a. rejected poetry as unequal to scholarly work. b. rejected Greek philosophy as unequal to the epics of Homer. c. urged poets to write long epic works to rival Homer. d. urged his fellow poets to write short, finely crafted works rather than epics. Calculate Payroll An employee earns $30 per hour and 1.5 times that rate for all hours in excess of 40 hours per week. If the employee worked 54 hours during the week. Assume that the social security tax rate is 6.0%, the Medicare tax rate is 1.5%, and the employe's federal income tax withheld is $295. a. Determine the employe's gross pay for the week.b. Determine the employee's net pay for the week. Round your answer to two decimal places.