Kylie borrowed a book from a library. The library charged a fixed rental for the book and a late fee for every day the book was overdue. The expression below shows the charges Kylie paid for the book when she returned it x days after the
due date:
2 +0.25x
What does the constant term of the expression represent?
The late fee for the book
The fixed rental for the book
The number of books borrowed
The number of days the book was overdue

Answer:

the right answer is the first one

2x+2 over x >0

A number written in scientific notation has a Negative Exponent that indicates the digits used in the number and is always written with 1 digit to the left of the decimal place.

The coefficient is always a number larger than or equal to one and less than ten in scientific notation. There is an integer exponent. When using scientific notation to write integers bigger than ten

As a result, when a number is smaller than 1, it will have a negative exponent in scientific notation.

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Answer:

x = 9

Step-by-step explanation:

-2x + 3 = -15

-2x = -18

x = 9

Answer:

Step-by-step explanation:

what value of x makes this equation true , use numerals instead of words.

-2x+3=-15

-2x + 3 = -15

-2x = -15 - 3

-2x = -18

x = -18 : (-2)

x = 9

--------------------

check

-2 * 9 + 3 = -15

-18 + 3 = -15

-15 = -15

the answer is good

Answer: [tex]\frac{1}{2} \frac{2}{17} \frac{7}{12}[/tex]

Step-by-step explanation:

Answer:

the algebraic expression is; x+15

Answer:

Step-by-step explanation:

Inequalities help us to compare two unequal expressions. The correct options are 2 and 3.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The inequality for the red portion is,

slope, m = (-2/-4) = 1/2

y-intercept is 2.

y ≤ (1/2)x + 2

The inequality for the blue portion is,
slope, m = (5-0)/(3-0.5) = 2

y-intercept is -1.

y > 2x - 1

Hence, the correct options are 2 and 3.

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The solution to a given word problem by writing it as an equation is k = 253/232

The process of expressing word problems in mathematical forms takes a logical and chronological approach while taking the variables and arithmetic operations given into consideration.

From the given information, to express the word problem in mathematical form, we have:

Making k the subject of the equation, we have:

k = 253/232

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Answer:

f(x) = (x/8)^2       for x ≥ 0

Step-by-step explanation:

y = 8 sqrt x      switch   x and y

x = 8 sqrt y       now solve for y

(x/8)^2 = y

Answer:

nhddhdbndbd

Step-by-step explanation:

jh h benrheoek

The given expression is [tex]\frac{-4}{5} \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})[/tex].

We need to simplify the given expression.

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

Now group the rational numbers [tex](\frac{-4}{5}\times \frac{15}{16} ) \times (\frac{3}{7}\times (\frac{-14}{9}))[/tex]

[tex]=(\frac{-4}{16}\times \frac{15}{5} ) \times (\frac{3}{9}\times (\frac{-14}{7}))[/tex]

[tex]=(\frac{-1}{4}\times \frac{3}{1} ) \times (\frac{1}{3}\times (\frac{-2}{1}))[/tex]

[tex]=(\frac{-3}{4} ) \times (\frac{-2}{3})=\frac{1}{2}[/tex]

Therefore, the simplified value of the given expression is [tex]\frac{1}{2}[/tex].

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Answer:

1

Step-by-step explanation:

(2-0) / (6-4)

2/2

xxxxxxxx

Answer:

1

Step-by-step explanation:

Answer:

5x + 15

Step-by-step explanation:

To expand the binomial, you need to multiply each term inside the parentheses by 5.

(x + 3)5

= (x * 5) + (3 * 5)

= 5x + 15

Answer:

For every 92 cats in the city pound, there are 144 dogs.

OR

For every 144 dogs in the city pound, there are 92 cats

Step-by-step explanation:

You didn't provide the options, so that was my best shot at it.

Answer:

19-73 19-73 and a very nice little

Step-by-step explanation:

19-73 19-73 and he changed

Answer:

x= 2/3, -2/3

Step-by-step explanation:

9x² = 4

To solve this quadratic, divide each side by 9

x^2 = 4/9

Take the square root of each side

sqrt(x^2) = sqrt(4/9)

x = ±2/3

Answer:

x = ± [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

9x² = 4 ( divide both sides by 9 )

x² = [tex]\frac{4}{9}[/tex] ( take square root of both sides )

x = ± [tex]\sqrt{\frac{4}{9} }[/tex] = ± [tex]\frac{\sqrt{4} }{\sqrt{9} }[/tex] = ± [tex]\frac{2}{3}[/tex]

x = - [tex]\frac{2}{3}[/tex] , x = [tex]\frac{2}{3}[/tex]

Answer:

Step-by-step explanation:

Total number of customers

⇒ 15 + 5 + 10 + 14 + 8 + 12 + 6 = 70

Percentage of customers who came on Friday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Friday\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{8}{70} \times 100\\\\& = \sf 11.43\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

Percentage of customers who came on Saturday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Saturday\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{12}{70} \times 100\\\\& = \sf 17.14\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

Percentage of customers who came on Friday and Saturday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Fri\:and\:Sat\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{8+12}{70} \times 100\\\\& = \sf 28.57\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

28.57 is the answer, and its rounded to the nearest hundredth

A mixed number in simplest form, in the box is 40  5/8 cm^3.

We have given that,

The figure contains a right rectangular prism. The length of the prism is labeled 6 and one-half centimeters, the width is labeled 2 and one-half centimeters, and the height is labeled 2 and one-half centimeters.

The figure is a rectangular prism, so the formula would be Volume = length x width x height.

length = 6 .5cm

width  =  2.5cm

height  =  2.5cm

If you plug everything you have in the problem into the volume equation, you would get

volume = 6.5cm x 2.5cm x 2.5 cm.

Without a calculator first, turn the mixed numbers into improper fractions.

6 .5=13/2

2.5 = 5/2

Volume = 13/2  x 5/2   x 5/2

When you multiply everything together you should get.

As a mixed number, that would be 40 5/8.

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Answer:

The reference atomic mass is carbon-12 when calculating atomic masses.

Step-by-step explanation:

The one-twelfth mass of an atom of carbon-12 is known as an atomic mass unit.

Because no other nuclide has a mass that is exactly a whole number in this scale except for carbon-12.

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Step-by-step explanation:

hope you can understand

4x² + 6x = 12

We move all the terms to the left:

The value of Δ is greater than zero, so the equation has two solutions

We use the following formulas to compute our solutions:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a }| \ x_{2}=\dfrac{-b+\sqrt{\Delta} }{2a } } \end{gathered}$}[/tex]

The end solution:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a}=\dfrac{-(6)-2\sqrt{57} }{2*4}=\dfrac{-6-2\sqrt{57} }{8} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b+\sqrt{\Delta} }{2a}=\dfrac{-(6)+2\sqrt{57} }{2*4}=\dfrac{-6+2\sqrt{57} }{8} } \end{gathered}$}[/tex]

2534+?  but its not that clear cant understand it

Answer:

33

Step-by-step explanation:

do it in reverse

there are 3 numbers

average is 20

that means total is 20 times 3 which is

60

7+20+x=60

27+x=60

x=60-27=

33

Answer:

x = 33

Step-by-step explanation:

we find the "average" of a data set by adding all of the numbers in the data set together, and then dividing by the number of numbers/values present

for example,

the average of 2 and 20

2 + 20 = 22

(there are two numbers, so we divide by 2)

22 / 2 = 11

so, this example has an average of 11

we can apply the same logic to a variable:

we know that

[tex]\frac{20+7+x}{3}[/tex]  = 20

We can now solve for x:

[tex]\frac{20+7+x}{3}[/tex] = 20  

 · 3          ·3      {multiply both sides by 3}

20 + 7 + x = 60  {combine like terms}

27 + x = 60  {subtract 27 from both sides to isolate x}

x  = 33

{check answer:
7 + 20 + 33 = 60

60 / 3 = 20      (divided by 3 because we have 3 numbers) }

so, the value of x is 33

(x = 33)

hope this helps!!

Answer:

k = g + a

Step-by-step explanation:

g = k - a ( add a to both sides )

g + a = k , that is

k = g + a

Answer:

The five Platonic solids (regular polyhedra) are the tetrahedron, cube, octahedron, icosahedron, and dodecahedron. In other words the second one.

The approximate distance in km between her house and her job is 9 km.

The map is a scale drawing of the places mentioned. A scale drawing is a smaller image of a larger place or diagram.

The scale of the map = 8cm : 12km

Distance between the house and the job = (12 x 6) / 8 = 9m

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If [tex]f(x)[/tex] has a removable discontinuity at [tex]x=a[/tex], then the limit

[tex]\displaystyle \lim_{x\to a} \frac{f(x)}{x-a}[/tex]

exists and is finite.

A non-removable discontinuity at [tex]x=b[/tex] would entail a non-finite limit,

[tex]\displaystyle \lim_{x\to b} \frac{f(x)}{x-b} = \pm\infty[/tex]

or the limit does not exist (which could be due to the limits from either side of [tex]x=b[/tex] not matching or existing).

For a rational function, we want

[tex]f(x) = \dfrac{p(x)}{q(x)}[/tex]

where [tex]p[/tex] and [tex]q[/tex] are polynomials in [tex]x[/tex]. To get a removable discontinuity at [tex]x=a[/tex], both [tex]p[/tex] and [tex]q[/tex] must be divisible by [tex]x-a[/tex], and the limit of their quotient after removing these factors still exists. That is,

[tex]\displaystyle \lim_{x\to a} f(x) = \lim_{x\to a} \frac{p(x)}{q(x)} = \lim_{x\to a}  \frac{(x-a)p^*(x)}{(x-a)q^*(x)} = \lim_{x\to a} \frac{p^*(x)}{q^*(x)} = \frac{p^*(a)}{q^*(a)}[/tex]

On the flip side, we get a non-removable discontinuity [tex]x=b[/tex] if [tex]p[/tex] is not divisible by [tex]x-b[/tex], in which case

[tex]\displaystyle \lim_{x\to b} f(x) = \lim_{x\to b} \frac{p(x)}{q(x)} = \lim_{x\to b}  \frac{p(x)}{(x-b)q^*(x)} = \frac{p(b)}{0\times q^*(b)}[/tex]

and this is undefined.

Suppose [tex]f(x)[/tex] has a non-removable discontinuity at [tex]x=-5[/tex] and a removable one at [tex]x=4[/tex]. Then one such function could be

[tex]f(x) = \dfrac{x-4}{(x-4)(x+5)} = \dfrac{x-4}{x^2+x-20}[/tex]