The correct answer is C. The water is the solvent because the green pellets dissolved in it.
Explanation:
In solutions, the are two substances involved, the solvent and the solute. The solvent is usually a liquid substance; additionally, the solvent dissolves another substance, which is known as the solute. For example, if you dissolve a spoon of salt in a glass of water, the solute is the salt which is the substance dissolved and the solvent is the water because the solute is dissolved in it. According to this, in the case presented the water is the solvent because the green pellets which are the solute dissolve in it.
The number of molecules in one mole of lithium acetate are...
Answer:
6.0221409e+23
Explanation:
The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.
The pyruvate dehydrogenase complex is subject to allosteric control, especially inhibition by reaction products. From the list below, select the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes.
a. AMP binding to and activating the enzyme.
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
c. Exchange of ADP and ATP on the pyruvate dehydrogenase complex.
d. Phosphorylation by a kinase using ATP (which turns the complex on) and dephosphorylation by a phosphatase (which tums the complex off).
Answer:
The correct option is B
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
Explanation:
The pyruvate dehydrogenase complex is described as a complex having many enzymes that catalyse decarboxylation of pyruvate by oxidation to yield NADH and acetyl‐CoA, which makes the influx of acetyl-coA from glycolysis to increase into the Krebs cycle.
It can be found in the mitochondrial matrix and pyruvate which is conveyed through enzyme Pyruvate Translocase to PDH complex.
Regulation of pyruvate dehydrogenase complex occured through allosteric effectors as well as phosphorylation.the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes such as plants and animals Phosphorylation is by a kinase using ATP which first turns the complex off and the later dephosphorylation by a phosphatase which turns the complex on
Is water the most common acid?
Answer: Yes
Explanation: Since strong acids react with and use up water molecules, and strong bases do not
I NEED HELP PLEASE, THANKS!
Solids, liquids and gases are the three most commonly accepted phases of matter. Explain the properties of each phase, including their relative energy.
Answer:
Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.
Explanation:
Answer:
Liquids properties include retention of volume and its conformation to the shape of its container. The
particles in a liquid have more kinetic energy than the particles in the corresponding solid. Solids are
structurally rigid and resist changing shape or volume. Solid particles have the least amount of kinetic
energy. Properties of gas include easily compressible, the expand to fill their container and they occupy
more space than a solid or liquid. Gas particles have the most amount of kinetic energy
Explanation:
Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?
Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
3.1°C
Why do heart diseas patient's eat oil instead of fat? please explain
Answer:
substituting unsaturated fats—like those found in olive oil—for saturated fats could lower your chance of developing heart disease.
Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water
and another formed by adding 10.0 grams of sucrose (C12H22O11) to 1.0 L of water. Which of the
two solutes produces the lower reduction in the vapor pressure of the solvent? Explain fully.
Answer:
Explanation:
Lowering of vapour pressure of solvent is proportional to number of moles of solute dissolved in it per litre .
No of moles of glucose dissolved
= mass dissolved / molecular weight of glucose
= 10 / 180
= .055 moles.
No of moles of sucrose dissolved = 10 / 342
= .029 moles.
So reduction in vapour pressure will be lower of solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.
Acetic acid has a pKa of 4.74. Buffer A: 0.10 M HC2H3O2, 0.10 M NaC2H3O2 Buffer B: 0.30 M HC2H3O2, 0.30 M NaC2H3O2 Buffer C: 0.50 M HC2H3O2, 0.10 M NaC2H3O2 Which of the above buffers has the highest buffer capacity? [ Select ] Which of the above buffers has the lowest buffer capacity? [ Select ]
From the data provided;
Buffer B has the highest buffer capacityBuffer C has the lowest buffer capacityWhat is a buffer?A buffer is a solution which resists changes to its pH when a small quantity of acid or base is added to it.
The buffer capacity is determined using the Henderson-Hasselbach equation:
pH = pKa + log ([CH3COO-]/[CH3COOH])For Buffer A: pH = 4.74 + log(0.10/010) = 4.74
Buffer B: pH = 4.74 + log(0.30/030) = 4.74
For Buffer C: pH = 4.74 + log (0.10/0.50) = 4.04
Buffer A and Buffer B has same pH value as the pKa of acetic acid.
However, Buffer B has higher concentration of the components compared to buffer A, therefore, Buffer B has the highest buffer capacity.
The pH of buffer C is lower than pKa of acetic acid. Hence, buffer C has the lowest buffer capacity.
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Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
Answer: D=8.27 g/cm³
Explanation:
Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.
[tex]D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}[/tex]
With this equation, the m³ and kg cancel out, and we are left with g/cm³.
D=8.27 g/cm³
How many moles of HCI are needed to prepare 8.0 liters of a 4.0 M solution of HCI?
0.5 mol HCL
32 mol HCI
12 mol HCL
2 mol HCI
Answer: 32 mol HCI
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in Liters
Now put all the given values in the formula of molarity, we get
[tex]4.0M=\frac{moles}{8.0L}[/tex]
[tex]moles={4.0M\times 8.0L}=32mol[/tex]
Therefore, the moles of HCI needed to prepare 8.0 liters of a 4.0 M solution of HCI are 32.
How many Joules of energy are required to change 10.0 gram of ice at -2.0 C to water at 20.0 C?
(use your constants)
440 J
66,000 J
880
4220 J
If you are diving and playing in the waves near a beach and suddenly find that you are being
pulled out into the ocean at a relatively quick pace, what current are you most likely trapped in?
Answer: Wind current
Explanation:
The wind current is the main driving force along with the water currents when one reaches to the seashore. The wind currents above surface of water generates due to the evaporation of water.
The strong wind currents can pull any animal or human walking or running near the sea shore. These currents bring the animal or human towards the sea.
A chemistry student needs of ethanolamine for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of ethanolamine is . Calculate the mass of ethanolamine the student should weigh out. Round your answer to significant digits.
Answer:
mass of ethanolamine 61.2 g
Explanation:
Data:
V (Volume) = 60 mL
ρ (Density)= 1.02 [tex]\frac{g}{cm^{3} }[/tex] = 1.02 [tex]\frac{g}{mL}[/tex]
With the given data and using the density formula:
ρ = [tex]\frac{mass}{volume}[/tex]
It is possible to calculate the grams of ethanolamine that the student should weigh out. The mass in the formula is cleared and the data is replaced.
mass = ρ * volume
mass = 1.02 [tex]\frac{g}{mL}[/tex] * 60 mL = 61.2 g of ethanolamine
How does the disturbance travel through the coil when you raise your arm up and down?
Answer:
What happens to the wavelength when you increase the rate of vibration (how fast your hand moved back and forth). After increasing the rate of vibration, the wavelength decreased.\
Suppose of potassium iodide is dissolved in of a aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the potassium iodide is dissolved in it.
The given question is incomplete, the complete question is:
Suppose 1.27 g of potassium iodide is dissolved in 100. mL of a 44.0 m M aqueous solution of silver nitrate. Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn't change when the potassium iodide is dissolved in it. Round your answer to 3 significant digits.
Answer:
The correct answer is 0.0325 M.
Explanation:
The mass of potassium iodide or KI mentioned in the question is 1.27 grams, the molar mass of KI is 166 g/mol. The formula for determining the no of moles of the substance is mass/molar mass. Thus, the moles of KI in 1.27 grams will be,
= 1.27g / 166 g/mol = 0.00765 moles.
KI = K⁺ + I⁻
Therefore, the moles of KI will be equivalent to moles of iodide anion, that is, 0.00765 moles.
The moles of silver nitrate or AgNo3 in the solution can be determined by using the formula, molarity (M) * volume in liters. The molarity of silver nitrate given in the question is 44 mM and the volume used is 100 ml or 100/1000 L. Now putting the values we get,
= (44 M/1000) * (100 L/1000) = 0.0044 moles
The moles of silver nitrate is equivalent to moles of silver ion, which is further equivalent to the moles of iodide ion that has taken part in precipitation = 0.0044 moles.
The moles left of I⁻ in the solution will be,
0.00765 - 0.0044 = 0.00325
Now, the final molarity of iodide ion in the solution will be,
= moles/volume in liters
= 0.00325 moles / 0.100 L = 0.0325 M
What are examples of a chemical reaction?
Select all that apply.
A(2AgI + Na2S → Ag2S + 2NaI
B)4FeS + 7O2 → 2Fe2O3 + 4SO2
C) H2O → SiO2
D)SnO2 → Sn + 2H2O
Examples A and B are examples of chemical reaction as new substances are formed in these reactions which have different chemical compositions.
What are chemical reactions?
Chemical reactions are defined as reactions which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.
There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.
There are three types of chemical reactions:
1) inorganic reactions
2)organic reactions
3) biochemical reactions
During chemical reactions atoms are rearranged and changes are accompanied by an energy change as new substances are formed.
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Which of the following is not a reason that power plants are unable to achieve 100 percent efficiency?
A. The amount of work obtained from a process never has work needing to go into it.
B. Not all energy is converted heat from chemical reactions into useful work.
C. Entropy increases.
D. Heat is often a waste product
a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm and it weighs 625 kg. Determine the density. Would it float in water? The density of water is 1 g/cm^3. Show your work.
Explanation:
It is given that,
Dimension of a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm
Mass of solid block is 625 kg or 625000 grams
We need to find the density of solution. The mass per unit its volume is called density.
[tex]\rho=\dfrac{m}{V}\\\\\rho=\dfrac{625000}{74\times 5\times 29}\\\\\rho=58.24\ g/cm^3[/tex]
So, the density of solid block is [tex]58.24\ g/cm^3[/tex]. The density of water is [tex]1\ g/cm^3[/tex]. The density of block is more than water. Hence, it will sink.
An unknown substance has a mass of 15.5 g . When the substance absorbs 1.395×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?
Answer:
iron (Fe)
Explanation:
Use q = mcΔT.
q = 1.396 x 10^2 J
m = 15.5g
ΔT = (45.0 - 25.0) = 20 degrees celcius
1.396 x 10^2 = 15.5 x c x 20
c = .450 J/g x degrees celcius
This is closest to the specific heat of iron/steel.
A student wishes to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
What volume of the
12.0 M HCl should he/she start with?
A student should start with 4.74 mL of the 12.0 M HCl to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
What is Molarity ?Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution.
Formula used for the given question ;
M₁V₁ = M₂V₂
M₁ = 12.0 M HCl.V₁ = ?M₂ = 0.875 M HCV₂ = 65.0 mLM₁V₁ = M₂V₂
V₁ = 0.875M x 65.0 mL / 12.0 M HCl.
= 4.74 ml
Therefore , A student should start with 4.74 mL of the 12.0 M HCl to prepare 65.0 mL of 0.875 M HCl from 12.0 M HCl.
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How many moles of hydrogen atoms are there in 120 g of C6H12O6
Answer: 8.0 moles
Explanation:
0.6661 moles×12 H≈8.0 moles
120 g of C₆H₁₂O₆ contain 8 moles of Hydrogen atoms
To obtain the answer to the question given above, we'll begin by calculating the mass of 1 mole of C₆H₁₂O₆
1 mole of C₆H₁₂O₆ = (12×6) + (12×1) + (16×6)
= 72 + 12 + 96
= 180 gFrom the above,
We can see that 180 g of C₆H₁₂O₆ contains 12 moles of Hydrogen.
Finally, we shall determine the number of mole of Hydrogen atoms in 120 g of C₆H₁₂O₆. This can be obtained as follow:
180 g of C₆H₁₂O₆ contains 12 moles of Hydrogen.
Therefore,
120 g of C₆H₁₂O₆ will contain = [tex]\frac{120 * 12}{180}[/tex] = 8 moles of Hydrogen.
Thus, 120 g of C₆H₁₂O₆ contain 8 moles of Hydrogen atoms
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What volume does 49.0g of KBr need to be dissolved in to make a 8.48% (w/v) solution?
Answer:
578mL is the volume you need to dissolve the mass of KBr
Explanation:
The percent by mass volume, % (w/v) is defined as the ratio between mass of solute in grams and volume of the solution in mililiters times 100. The formula is:
% (w/v) = mass solute (g) / volume solution (mL) × 100
As you want a solution 8.48% and the solute is 49.0g of KBr:
8.48% = 49.0 (g) / volume solution (mL) × 100
Volume solution = 578mL is the volume you need to dissolve the mass of KBr
need help asappp please
Answer:
C.POLARExplanation:
According to research :
Methanol is a polar molecule:
The alcohol (-OH) group dominates the molecule making it definitely polar.
Arrange the following compounds in order of increasing solubility in water and explain your sequence: C7H15OH, C6H13OH, C6H6, C2H5OH
Answer:
C6H6 < C7H15OH < C6H13OH < C2H5OH
Explanation:
Hello,
In this case, since the organic molecules solubility is defined in terms of the presence of hydrogen bonds as intermolecular forces, which are formed between oxygen and hydrogen and the length of the organic chain, we can notice that hydroxyl-containing longer chains tend to be less water soluble whereas shorter chains more soluble as the polar part of the chain will lead the solubility. In addition to it, chains with lack of oxygen tend to be highly water insoluble. Therefore, we can notice that C6H6 is the least water soluble, next C7H15OH, then C6H13OH and the most soluble is C2H5OH.
Best regards.
There is a pattern to the phases of the moon. The time between one full moon to another is about a;new b;waxing crescent c;1st quarter d;full
Answer: a. new
Explanation:
The time between one full moon to another is new moon. The lunation is the average time taken for the formation of new moon to the next. The new moon is the initial visible crescent of the Moon after being conjugated with the Sun. Per lunar cycle can be assigned with a lunation number for the purpose of identification.
Select the correct answer from each drop-down menu.
Describe an oxidation-reduction reaction.
In an oxidation-reduction reaction, oxidation is what happens when a reactant___ . Reduction occurs when a reactant ___ in the reaction.
Explanation:
First off, we have to understand what we means by oxidation and reduction.
Oxidation is the loss of electrons during a reaction by a molecule, atom or ion. Oxidation occurs when the oxidation state of a molecule, atom or ion is increased.
Reduction on the other hand is the opposite of oxidation. It is the gain of electrons during a reaction by a molecule, atom or ion. Reduction occurs when the oxidation state of a molecule, atom or ion decreases.
Back to the question;
oxidation is what happens when a reactant loses electrons.
Reduction occurs when a reactant gains electrons in the reaction.
PLEASE HELP I HAVE LIMITED TIME!!
How many particles are in 0.500 moles of
N.05?
Answer:
3.01×10²³ particles.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ particles. This implies that 1 mole of N2O5 also contains 6.02×10²³ particles.
Now, if 1 mole of N2O5 contains 6.02×10²³ particles ,
Then 0.5 mole of N2O5 will contain = 0.5 × 6.02×10²³ = 3.01×10²³ particles.
Therefore, 0.5 mole of N2O5 contains 3.01×10²³ particles.
Hydrobromic acid solution of unknown concentration is titrated with a 0.500M LiOH solution.
20.00mL of the acid are poured into an Erlenmeyer flask.
40.00mL of the base solution is required to reach the equivalence point.
What is the molarity of the Hydrobromic acid solution?
Answer:
1.00 M
Explanation:
Step 1: Write the balanced equation
HBr + LiOH ⇒ LiBr + H₂O
Step 2: Calculate the reacting moles of lithium hydroxide
40.00 mL of 0.500 M solution react. The reacting moles of LiOH are:
[tex]40.00 \times 10^{-3} L \times \frac{0.500mol}{L} = 0.0200 mol[/tex]
Step 3: Calculate the reacting moles of hydrobromic acid
The molar ratio of HBr to LiOH is 1:1. The reacting moles of hydrobromic acid are 1/1 × 0.0200 mol = 0.0200 mol.
Step 4: Calculate the molarity of hydrobromic acid
0.0200 moles of HBr are in 20.00 mL of the solution. The molarity of the hydrobromic acid solution is:
[tex]M= \frac{0.0200 mol}{20.00 \times 10^{-3} L } =1.00 M[/tex]
Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at that temperature is 90.25 kJ / mol, and that the standard molar enthalpy of the reaction 2 NOCl(g) → 2 NO(g) + Cl2(g) is 75.5 kJ / mol at the same temperature.
Answer:
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
Explanation:
The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:
Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants
In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)
So, ΔH=[tex]2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}[/tex]
Knowing:
ΔH= 75.5 kJ/mol[tex]H_{NO}[/tex]= 90.25 kJ/mol[tex]H_{Cl_{2} }[/tex]= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)[tex]H_{NOCl}[/tex]=?Replacing:
75.5 kJ/mol=2* 90.25 kJ/mol + 0 - [tex]H_{NOCl}[/tex]
Solving
-[tex]H_{NOCl}[/tex]=75.5 kJ/mol - 2*90.25 kJ/mol
-[tex]H_{NOCl}[/tex]=-105 kJ/mol
[tex]H_{NOCl}[/tex]=105 kJ/mol
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
2) A sample of 113min has a half-life of 100. minutes. What amount of 113m In remains (in CPM) if a
10,000 CPM sample is allowed to decay for 5.0 hours?
Answer:
THE AMOUNT OF THE SAMPLE REMAINING AFTER 5 HOURS IS 1250 CPM
Explanation:
A sample has a half life of 100 minutes. To solve for the amount remaining after a given amount of 10000CPM decay in 5 hours, we use the formula:
Nt = No * (1/2)^t/t1/2
Where:
Nt = amount remaining = unknown
No = initial amount = 10000 CPM
t = time elapsed for decay = 5 hours = 60*5minutes = 300 minutes
t1/2 = half life = 100 minutes
Putting the values into the formula, we have:
Nt = 10000 * (1/2)^ 300/100
Nt = 10000 * (1/2)^3
Nt = 10000 * 0.125
Nt = 1250 CPM
The amount of the sample remaining after 5 hours is 1250 CPM.
