Answer:
c.o Kg • ms 08
Explanation:
put all together
The answer is option c) 0 kg m/s
What is momentum ?It is a property of moving body by virtue of its mass and motion and that is equal to the product of the body's mass and velocity
momentum = mass * velocity
since , momentum is a vector quantity
in order to calculate momentum we need one of the quantity to be vector since , mass can never be vector as it is a scaler quantity we need to use velocity ( vector quantity ) not speed ( scaler quantity ) as multiplication of two scalers can never give rise to a vector quantity
so, the answer is option c) 0 kg m/s
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Identical balls are dropped from the same initial height and bounce back to half the initial height. In Case 1, the ball bounces off a cement floor, and in Case 2, the ball bounces off a piece of stretchy rubber. Two cases of a ball dropping and bouncing off of a surface. In case one, the ball approaches a cement floor, comes in contact, momentarily comes to rest, and then bounces off with a velocity smaller than the approach velocity. In case 2, the ball approaches a piece of stretchy rubber. When the ball comes in contact with the rubber, it deforms the rubber and comes momentarily to rest. The ball bounces off again with a velocity smaller than the approach velocity, and the rubber regains its original shape. In both cases, the balls are dropped from the same initial height and reach the same final height. In which case is the magnitude of the ball's change in momentum the greatest
Answer:
the impulse must be the same in these two cases F t = m ([tex]\sqrt{2g h_f } - \sqrt{2g h_o}[/tex])
Explanation:
For this exercise we use the relationship between momentum and momentum
I = Δp
F t = m v_f - m v₀
To know the speed we use the conservation of energy
starting point. Highest point
Em₀ = U = m g h
fincla point. Just before the crash
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v = [tex]\sqrt{2gh}[/tex]
we substitute in the impulse relation
F t = m ([tex]\sqrt{2g h_f } - \sqrt{2g h_o}[/tex])
therefore we can see that as in case the initial and final heights are equal, the impulse must be the same in these two cases
The masses of astronauts are monitored during long stays in orbit, such as when visiting a space station. The astronaut is strapped into a chair that is attached to the space station by springs and the period of oscillation of the chair in a friction-less track is measured.
(a) The period of oscillation of the 10.0 kg chair when empty is 0.750 s. What is the effective force constant of the springs?
(b) What is the mass of an astronaut who has an oscillation period of 2.00 s when in the chair?
(c) The movement of the space station should be negligible. Find the maximum displacement of the 100,000 kg sace station if the astronaut's motion has an amplitude of 0.100 m.
Answer:
a) k = 701.8 N / m, b) m_{ast} = 61.1 kg, c) v ’= -1.3 10⁻⁴ m / s
Explanation:
a) For this exercise let's use the relationship of the angular velocity
w = [tex]\sqrt{ \frac{k}{m} }[/tex]
k = w² m
the angular velocity is related to the period
w = 2π / T
we substitute
k = 4 π² [tex]\frac{m}{T^2}[/tex]
let's calculate
k = 4 π² 10 /0.75²
k = 701.8 N / m
b) now repeat the measurement with an astronaut on the chair
w = [tex]\sqrt{ \frac{k}{m} }[/tex]
where the mass Month the mass of the chair plus the mass of the astronaut
M = m + [tex]m_{ast}[/tex]
M = k / w²
w = 2π / T
let's calculate
w = 2π / 2
w = π rad / s
M = 701.8 /π²
M = 71,111 kg
now we use that
M = m + m_{ast}
m_{ast} = M - m
m_{ast} = 71.111 - 10.0
m_{ast} = 61.1 kg
c) if the astronaut's movement is simple harmonic
x = A cos wt
therefore the speed is
v = [tex]\frac{dx}{dt}[/tex]
v = -Aw sin wt
maximum speed is
v = - Aw
v = 0.100 π
v = 0.31416 m / s
we can suppose that the movement of the space station and the astronaut is equivalent to division of the same
initial instant. Before the move
p₀ = 0
final instant. When the astronaut is moving
p_f = M_station v’+ m_{ast} v
the moment is preserved
p₀ = pf
0 = M__{station} v ’+ m_{ast} v
v ’= - [tex]\frac{m_{ast} }{M_{station} } \ v[/tex]
we substitute
v ’= [tex]\frac{61.1 }{ 100000 } \ 0.31416[/tex]
v ’= -1.3 10⁻⁴ m / s
the negative sign indicates that the station is moving in the opposite direction from the astronaut
What are the properties of fourth matter plasma?
[tex] \\ [/tex]
Like gases, plasmas have no fixed shape or volume, and are less dense than solids or liquids. But unlike ordinary gases, plasmas are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roam freely.
[tex] \\ [/tex]
Hope It Helps!
A airplane accelerated from 59 m/s to 95 m/s in a distance of 123 meters what was its acceleration in m/s^2, assumed constant?
Answer:
22.54 m/s^2
Explanation:
vf = final velocity = 95 m/s
vi = initial velocity = 59 m/s
d = displacement = 123 m
a = acceleration, unknown
Use this kinematics equation to find a:
vf^2 = vi^2 + 2a*d
95^2 = 59^2 + 2*a*123
22.54 m/s^2 = a
Hope this helps!! :)
Ocean waves crash on the beach at a velocity of 3.5 m/s. If the distance between the crests of each wave is 4 m, find the frequency of the waves.
a. 0.0088 Hz
b. 14.0 Hz
c. 1.14 Hz
d. 0.88 Hz
Answer:
d
Explanation:
velocity=frequency × wavelength
frequency=speed/wavelength
frequency=3.5÷4
=0.875~0.88
The frequency of the waves is (d) 0.88 Hz. So, correct answer is option (d).
What is frequency of wave?The frequency of a sinusoidal wave is the number of full oscillations performed by any wave constituent in a unit of time. According to the definition of frequency, if a body is moving periodically, it has completed one cycle after going through a number of situations or postures and then returning to its initial position. Therefore, frequency is a quantity that describes the rate of oscillation and vibration.
Given parameter,
Velocity of the waves = 3.5 m/s.
distance between the crests of each wave, that is, wavelength of the waves = 4 m.
We know that, for a wave transmission,
velocity of wave =frequency of wave × wavelength of wave
⇒ frequency of wave=speed of wave/wavelength of wave
⇒ frequency of wave =3.5 m/s ÷4m
=0.875 Hz
≈ 0.88 Hz
Hence, the frequency of the waves is 0.88 Hz.
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Write an article to explain the process that occurs when matter is heated, or cooled. How does matter change its physical state between solid, liquid, and gas? Provide a real-life example. Also, describe the properties of the three main states of matter.
Answer:
when matter is heated or cooled it melts or freezes for at least the atoms do
Explanation:
for example take water when you heat it up the water molecules melt producing vapor water vapor and when you freeze it or cool it down it turns into liquid or turned into a solid by turning into ice. the three main properties of matter are gas liquid and solid and if we put water into these three different categories it turns into water vapor as gas liquid water as liquid and Ice as a solid
hope this helps
231 91 Pa has__neutrons
Answer:
140
Explanation:
What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 44 km from the source?
Answer:
Explanation:
Intensity of a wave is inversely proportional to distance from source
I ∝ 1 / r
I is intensity , r is distance
I₁ / I₂ = r₂² / r₁²
ratio of intensity = 44² / 14²
= 9.87
intensity of earthquake of first place will be 9.87 times that of second place .
a. Using the ideas of electric field and force, explain what would happen to an electron if released from rest at r=2.0m?
b. Would the electron released from rest move to a region of higher electrical potential or lower electrical potential?
c. Would the electron released from rest move such that the system would have higher potential energy or lower potential energy?
your "A" never changes, while your "Y" changes depending on strength of gravity. is it mass or weight?
Answer:
A - mass. B - Weight
Explanation:
This is because weight varies with the strength of gravity. Mass is just the amount of matter in an object
What force is left out of the Quantum Mechanics theory?
Answer:
Quantum mechanics is a key hypothesis in material science that gives a portrayal of the actual properties of nature at the size of iotas and subatomic particles. It is the establishment of all quantum physical science including quantum science, quantum field hypothesis, quantum innovation, and quantum data science.
Explanation:
It is the greatest of issues, it is the littlest of issues. At present physicists have two separate rule books clarifying how nature functions. There is general relativity, which perfectly represents gravity and everything it overwhelms: circling planets, impacting worlds, the elements of the growing universe all in all. That is enormous. At that point there is quantum mechanics, which handles the other three powers – electromagnetism and the two atomic powers. Quantum hypothesis is very proficient at portraying what happens when a uranium molecule rots, or when singular particles of light hit a sun based cell. That is little.
What is the correct description of any change in a position farther to the left of zero?
1- negative displacement
2- negative position
Answer:
negative displacement
Explanation:
cause its written farther that means its doin movement
1. A block with mass 20 kg is
sliding up a plane (Ukinetic=0.3,
inclined at 10°) at a speed of
2 m/s to the right (positive
X-direction). How far does it
go up along the plane before
it comes to rest momentarily?
Answer: 0.435 m
Explanation:
Given
mass m=20 kg
initial speed u=2 m/s
coefficient of kinetic friction [tex]\mu_k=0.3[/tex]
deceleration which opposes the motion is given by
[tex]\Rightarrow a=g\sin \theta+\mu_kg\cos \theta\\\Rightarrow a=g(\sin \theta +\mu_k\cos \theta)[/tex]
[tex]\Rightarrow a=9.8(\sin 10^{\circ}+0.3\times \cos 10^{\circ})\\\Rightarrow a=4.59\ m/s^2[/tex]
using [tex]v^2-u^2=2as[/tex]
[tex]\Rightarrow s=\dfrac{2^2}{2\times 4.59}=0.435\ m[/tex]
If a car is moving to the left with constant velocity, one can conclude that :
a. there must be no forces exerted on the car.
b. the net force exerted on the car is directed to the left.
c. the net force exerted on the car is zero.
d. there is exactly one force exerted on the car.
Answer:
b. the net force exerted on the car is directed to the left.
Explanation:
Applying Newton's second law of motion, the car will move in the direction of the applied force. If the applied forces are on different directions, the car will move in the direction of the greater force (net force).
Therefore, if a car is moving to the left with constant velocity, one can conclude that the net force exerted on the car is directed to the left.
The correct option is "b. the net force exerted on the car is directed to the left"
You are designing a new roller-coaster. The main feature of this particular design is to be a vertical circular loop-the-loop where riders will feel like they are being squished into their seats even when they are in fact upside-down (at the top of the loop). The coaster starts at rest a height of 80m above the ground, speeds up as it descends to ground level, and then enters the loop which has a radius of 20m. Suppose a rider is sitting on a bathroom scale that initially reads W (when the coaster is horizontal and at rest). What will the scale read when the coaster is moving past the top of the loop
Answer:
The reading on the scale is N = 9W
Explanation:
Since the roller coaster drops from a height, h of 80 m, the potential energy lost equals the kinetic energy gained as it enters the loop.
So, mgh = 1/2mv² where m = mass of rider, g = acceleration due to gravity = 9.8 m/s², h = initial height of roller coaster above ground level = 80 m and v = speed of roller coaster as it enters the loop.
So, mgh = 1/2mv²
v² = 2gh
v = √(2gh)
v = √(2 × 9.8 m/s² × 80 m)
v = √(1568 m²/s²)
v = 39.6 m/s
Now, as the roller coaster gets to the top of the vertical loop, the centripetal force, F and the weight W acts downwards. For the passenger not to fall off, this must equal the normal force, N
So, F = mv²/r where v = speed of roller coaster = 39.6 m/s and r = radius of vertical loop = 20 m and m = mass of rider = W/g
F = Wv²/gr
F = W(39.6 m/s)²/(9.8 m/s² × 20 m)
F = (1568 m²/s²)W/196 m²/s²
F = 8W
Since F + W = N
8W + W = N
9W = N
So, N = 9W
So, the reading on the scale is N = 9W
What is the maximum centripetal acceleration experienced by a person standing still on the surface of the Earth? Where must they be located?
Answer:
The person must be located in the Equator Line. The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.
Explanation:
Physically speaking, the centripetal acceleration ([tex]a_{r}[/tex]), measured in meters per square second, experienced by a person is defined by the following expression:
[tex]a_{r} = \omega^{2}\cdot r[/tex] (1)
Where:
[tex]\omega[/tex] - Angular speed of the Earth, measured in radians per second.
[tex]r[/tex] - Distance perpendicular to the rotation axis, measured in meters.
Since rotation axis passes through poles and distance described above is directly proportional to centripetal acceleration. The person must be located in the Equator Line, which is equivalent to the radius of the planet.
In addition, the angular speed of the Earth can be calculated in terms of its period ([tex]T[/tex]), measured in seconds:
[tex]\omega = \frac{2\pi}{T}[/tex] (2)
If we know that [tex]r = 6.371\times 10^{6}\,m[/tex] and [tex]T = 86400\,s[/tex], then the maximum centripetal acceleration experienced by a person is:
[tex]a_{r} = \left(\frac{2\pi}{86400\,s} \right)^{2}\cdot (6.371\times 10^{6}\,m)[/tex]
[tex]a_{r} = 0.0337\,\frac{m}{s^{2}}[/tex]
The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.
The person standing still on the surface of the earth must be located in the equator line
Recall: the the centripetal acceleration at the Equator is about 0.03 m/s2.
This then means that the maximum centripetal acceleration of a person standing in the equator line is 0.03 m/s2
What is meant by maximum centripetal acceleration?The maximum centripetal acceleration as the name implies is the maximum speed of a body or object in a circular path
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The Sun is spherical due to
gravitation
Earth and Moon circling it.
Earth circling it.
none of the above
Answer:
gravitation
good luck, hope this helps :)
man is walking due east at the rate of of 4kmph and the rain is falling 30° east of vertical with a velocity of 6kmph the velocity of rain relative to the man will be?
Answer:
No answer
Explanation:
no explanation
Write your paragraph explaining why astronomers' minds are more important than the instruments they use? It has to be a paragraph and please make it quick I’m being timed!!
Answer:
Ill just give you some quick pointers
Explanation:
-in order to create the instruments, they need to use their mind
-their minds and creativity are the base and foundation of anything really
-the brain is the most complex part of your body so much more complicated than any intrument
1. If a wave has a wavelength of 5.5m and a frequency of 45hz, what is its speed?
Answer:
By using the most simple velocity equation, velocity = distance / time, meaning the speed would be 247.5 meters per second.
if the
gravitational force f=GM1M2/r2 derive the dimention of G
Answer:
M-1 L3 T-2
Explanation:
Where,
M = Mass
L = Length
T = Time
Derivation
From Newton’s law of gravitation,
Force (F) = [GM1M2] × r-2
Gravitational Constant (G) = F × r2 × [Mm]-1 . . . . (1)
Since, Force (F) = Mass × Acceleration = M × [LT-2]
∴ The dimensional formula of force = M1 L1 T-2 . . . . (2)
On substituting equation (2) in equation (1) we get,
Gravitational Constant (G) = F × r2 × [Mm]-1
Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2].
Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.
If you have a 0.125 kg lead piece at
20.0°C, how much heat must you
add to melt it? (Remember, you
must warm it to its melting point
first.)
Material
Lead
Melt Pt (°C)
327
L (1/kg)
2.32.104
Boil Pt (°C) Lv (1/kg)
1750 8.59.105
c (1/(kg*c)
128
(Unit = J)
Answer:
7,812 J
Explanation:
Using the relation:
Q = mcΔθ
Q = quantity of heat
C = specific heat capacity of lead
Δθ = temperature change (T2 - T1)
M = mass of substance
Q = mass * specific heat * Δθ
Q = 0.125kg * 128 * (327 – 20)
Q = 0.125 * 128 * 307
Q = 4912 J
For melting:
Q = mass * Hf
0.125 * (2.32 * 10^4)
= 2,900 J
Total = 4,912 J + 2,900 J = 7,812 J
if a body of mass m is placed on earth ,what is the amount of potential energy possessed by it (g:-9.8m/s
Answer:
mgh
Explanation:
Assume the height of the body is 1.8m.
The gravity?of the body is G=mg
the height of the gravity center is about 0.9m
E=mgh
=m*9.8m/s*0.9m
= 8.82mJ
You are heating an iron to iron the shirt you're going to wear to school tomorrow. Which of the following best describes the transformation
of energy in this example?
Electrical to radiant
Thermal to electrical
Chemical to radiant
Electrical to thermal
2.
3
4 5 6 7
8
9
10
Next
Answer:
electrical to the thermal
Explanation:
Q:- EXPLAIN WHY THE PLANETS DO NOT TWINKLE.
planets shine more stedily because they are closer to earth and so appear as pinpoints but as tiny disks in our sky.
On the computer, we can only approximate the true Fourier transform because of the need for both time and frequency sampling. Because of the limited frequency resolution, the frequency of a cosine may not line up exactly at a frequency sample, but vou'll still get a peak around that frequency. Assuming that vou sample the signal with fs-8000 Hz, and take its Fourier transform using an FFT with 4096 points, what is the value (in Hz) of the FFT frequency bins closest to the two frequencies of the sinusoids (941 and 1336 Hz)
Answer:
hello your question is incomplete below is the missing part
Consider the sum of sinusoids de (t) = sin(24(941)t) + sin(27(1336)t)
answer : Value of DFT frequency = 684 Hz
Explanation:
Given data:
sample signal ( Fs ) = 8000 Hz
Fourier transform using an FFT with 4096 points
Determine the value of DFT frequency bins closest to the two frequencies of the sinusoids ( 941 and 1336 Hz ) ( in HZ )
fs = 8000 Hz
4096 parts are divided with a gap of Fs/N
attached below is the detailed solution
explain the advantage of polarized sunglasses over normal tinted sunglass
Answer:
Explanation:
Polarized lenses improve vision by making colors appear deeper and bolder and eliminating uncomfortable and often dangerous glare, as well as filtering harmful ultraviolet light
Consider the following scenario. A car for which friction is not negligible accelerates from rest down a hill, running out of gasoline after a short distance (see below). The driver lets the car coast farther down the hill, then up and over a small crest. He then coasts down that hill into a gas station, where he brakes to a stop and fills the tank with gasoline. Identify the forms of energy the car has, and how they are changed and transferred in this series of events.
Answer:
1) U-> K +W
2) K -> W
Explanation:
In this exercise, care must be taken as they indicate that the friction force (rubbing) is not negligible.
1 part at the top of the hill the car has gravitational potential energy, which is transformed in a part into kinetic energy and another part into heat by the work of the friction force that opposes the movement.
2 part when the other hill rises it loses kinetic energy that is transformed into gravitational potential energy and part in heat due to the work of the friction force on this hill.
3rd part in the last descent all the gravitational potential energy is transformed into kinetic energy and the application of the brakes is transformed into heat due to the negative lock of the friction force and filled with gasoline that has chemical energy that can be transformed in the engine.
State four factors affecting thermal conductivity
Answer:
∙ Temperature
∙ Concentration of electrolyte
∙ Nature of the electrolyte added
∙ Nature of solvent and its viscosity
Explanation:
A pipe is closed at one end and the air column vibrate with a fundamental note of 550Hz calculate the length of the resonating air column neglecting end correction
Answer:
The length of the resonating air column is 15 cm.
Explanation:
Given;
fundamental frequency of the air column, F₀ = 550 Hz
Assume speed of sound in air, v = 330 m/s
The wavelength of the air column is calculated as;
[tex]\lambda = \frac{V}{F_o} \\\\\lambda = \frac{330}{550} \\\\\lambda = 0.6 \ m[/tex]
The length of the resonating air column is calculated as;
In fundamental mode for closed pipe;
[tex]L = \frac{\lambda }{4} \\\\L = \frac{0.6}{4} \\\\L = 0.15 \ m\\\\L = 15 \ cm[/tex]
Therefore, the length of the resonating air column is 15 cm.
