is it possible for an atom to lose a proton and have a negative charge?
explain

Answer:

POSITIVE CHARGE,  NEGATIVE CHARGE,  ZERO

Explanation:

To solve this completion exercise, we must remember that charges of the same sign repel each other and in a metallic object (frying pan) the charge is mobile.

Let's analyze the situation when we touch the pan, the charges are neutralized, therefore when we bring the pan to the plate that has a positive charge, it attracts the mobile negative charges in the pan, until it is neutralized, therefore on the opposite side of the pan. pan (edge ​​with a glued tape) is left with a positive charge; therefore the edge and the tape, which is very light, have positive charges and repel each other.

We must assume that the frying pan is insulated so that the net charge is zero, since the induction process.

Consequently the words to complete the sentence are

When the pan is on the plate, the edge of the plate has a _POSITIVE CHARGE_____.

This means that the base of the container is loaded NEGATIVE CHARGE_____ because the net charge of the container is ___ZERO_

Answer:

New force = 2.688 N

Explanation:

Given that,

Two charged particles exert a force of 0.042 N on each other.

Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.

New distance, r' = (r/8)

The force between particles is given by :

[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{8})^2}\\\\F'=\dfrac{kq_1q_2}{\dfrac{r^2}{64}}\\\\F'=64\times \dfrac{kq_1q_2}{r^2}\\\\F'=64\times F\\\\F'=64\times 0.042\\\\F'=2.688\ N[/tex]

So, the new force is 2.688 N.

Answer:

Friction and Air resistence

Explanation:

i already passed this grade years ago...

The forces responsible for exerting forces to the left on a cyclist are -

Air resistance describes the forces that are in opposition to the relative motion of an object as it passes through the air. We can write air resistance as -

[tex]$F_{D}=\frac{1}{2} \rho v^{2} C_{D} A[/tex]

where -

F{D} = drag

{ρ} = density of fluid

{v} = speed of the object relative to the fluid

C{D}  = drag coefficient

{A} = cross sectional area

Given is to find what 2 forces would be responsible for exerting forces to the left on a cyclist that is already in motion moving to the right.

The forces responsible for exerting forces to the left on a cyclist are -

Therefore, the forces responsible for exerting forces to the left on a cyclist are -

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Answer:

waves energy i think

Explanation:

Answer:

6s

Explanation:

Assume it is dropped from rest and the gravitational acceleration is 10

By the equation of motion under constant acceleration:

[tex]s=ut+\frac{1}{2} at^2[/tex]

180 = (0)t+10(t^2)/2

t = 6 or -6 (rejected)

t = 6 s

Answer:

26.833 N

Explanation:

The computation of the resaltant of two forces is shown below:

Given that

Force A = 12N

Force B = 24N

Based on the above information  

Resultant R is

[tex]=\sqrt{A^2 + B^2 + 2AB \times cos \theta}\\\\=\sqrt{144 + 576 + 2\times 24\times 12\times cos90^{\circ}}\\\\=\sqrt{144+576+576\times 0}\\\\=\sqrt{720}[/tex]

=26.833 N

Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.

Explanation:

Answer:

2 seconds

Explanation:

From the question,

Applying the equation of motion for a body falling under gravity

s = ut+1/2gt²................................. Equation 1

Where, s = hieght of fall, u = initial velocity, t = time, g = acceleration due to gravity.

Given: s = 20 m, u = 0 m/s, t = ?, g = 10 m/s²

Substitute these values into equation 1

10 = 0(t²)+1/2(10×t)

10 = 5t

Solve for t

5t/5 = 10/5

t = 2 seconds

Answer:

b)  a = 52.26 m / s², a ’= 13.06 m / s², c) N = 2.79 10⁴ N, d) N = 1.89 10³ N

Explanation:

a) In the attached we can see the free body diagrams for the two positions, position A in the lower part of the circle and position B in the upper part of the circle

b) Let's start at point A

Let's use that the acceleration is centripetal

           a = v² / r

let's calculate

            a = 28² / 15.0

            a = 52.26 m / s²

as they relate it is centripetal it is directed towards the center of the circle, therefore for this point it is directed vertically upwards

Point B

           a ’= 142/15

           a ’= 13.06 m / s²

in this case the acceleration is vertical downwards

c) The values ​​of the normal force

point A

let's use Newton's second law

           ∑ F = m a

           N- W = m a

           N = mg + ma

           N = m (g + a)

           N = 450.0 (9.8 + 52.25)

           N = 2.79 10⁴ N

d) Point B

            -N -W = m (-a)

             N = ma -m g

             N = m (a-g)

             N = 450.0 (14.0 - 9.8)

             N = 1.89 10³ N

Answer:

Part 1

Steve is measuring his average speed

Part 2

Average velocity is equal to 60 miles per hour

Explanation:

Part 1

Average velocity is equal to total distance travelled divided by total time taken. It also takes into consideration the change of direction through out the journey.

Hence, Steve is measuring his average speed

Option A is correct

Part 2

Average velocity is equal to 60 miles per hour only because velocity is a vector quantity

Option B is correct

Answer:

0.08m/s

Explanation:

Given data

M1= 69kg

v1= 2.61m/s

M2= 0.22kg

v2= 25.2m/s

Before snowball is thrown:

Total mass of skater + snowball = 69+ 0.22 = 69.22kg

Total Momentum of skater + snowball = mv = 69.22 x 2.61 = 180.7 kgm/s

After snowball is thrown:

Let's call the velocity of the skater V.

Total momentum = momentum of skater + momentum of snowball

=69.22V + (5.544)

= 69.22V + 5.544

So:

180.7  = 69.22V+5.544

180.7- 5.544= 69.22V

175.156= 69.22V

V= 175.156/69.22

V = 2.53m/s

The total momentum after catching the snowball is mV or:

(69.0 + 0.22) x V

So:

5.544= 69.22V

V= 5.544/69.22

V=0.08m/s

The velocity of the ice skater after throwing the snowball is 0.08m/s

Answer:

c. There is a buoyant force that is proportional to the volume of your body that is below the level of the water.

Explanation:

Buoyancy can be defined as a force which is created by the water displaced by an object.

Simply stated, buoyancy is directly proportional to the amount of water that is being displaced by an object.

Hence, the greater the amount of water an object displaces; the greater is the force of buoyancy pushing the object up.

The buoyancy of an object is given by the formula;

[tex] Fb = pgV [/tex]

[tex] But, \; V = Ah [/tex]

[tex] Hence, \; Fb = pgAh [/tex]

Where;

Fb = buoyant force of a liquid acting on an object.

g = acceleration due to gravity.

p = density of the liquid.

v = volume of the liquid displaced.

h = height of liquid (water) displaced by an object.

A = surface area of the floating object.

The unit of measurement for buoyancy is Newton (N).

In this scenario, you are standing on the bottom of a lake with your torso above water. Thus, there is a buoyant force that is proportional to the volume of your body that is below the level of the water.

Answer:It will take about 3000 years

Explanation:

Answer:

30 000 J/Nm

Explanation:

60 x 10 x 50

=600 x 50

=30000 J/Nm

The change in gravitational potential energy of the student is 18000 Joule.

The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.

Given parameters:

Mass of the student: m = 60 kg.

Weighs of the student: W = 600 N.

the student falls h =50 m.

Hence, change in gravitational potential energy of the student =

Weighs of the student × change in height

= 600 N × 30 m

= 18000 Joule.

So, the change in gravitational potential energy of the student is 18000 Joule.

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Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.

Explanation:

Answer:

[tex]a=20\ m/s^2[/tex]

Explanation:

Given that,

The mass of an object, m = 3 kg

The radius of a circle, r = 0.2 m

The speed of the object, v = 2 m/s

We need to find the centripetal acceleration. Its formula is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(2)^2}{0.2}\\\\a=20\ m/s^2[/tex]

So, the centripetal acceleration is [tex]20\ m/s^2[/tex].

Answer:

solar energy

wind power

geothermal energy

hydraulic power

biomass energy

energy storage

(That's all I know).

Answer & Explanation:

1 N-m = 1 Joule

So 82 kJ of energy put into the system during (i).

45 kJ of heat leaves the system, so 82 kJ - 45 kJ  = 37 kJ is remaining.

(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.

The heat given would be equal to the heat emitted from the system and by providing some external source of energy the volume or temperature of the system may increase.

The amount of heat added to the system is 63kJ.

The energy can be estimated as:

Given,

During compression stroke:

We know that,

[tex]\rm Q_{1-2} = (U_{2} - U_{1}) + W[/tex]

Therefore,

[tex]\begin{aligned}-45 &= \rm (U_{2} - \rm U_{1}) + (-82)\\\\\rm (U_{2}-U_{1}) &= 37\rm (U_{2} - U_{1}) = 37\; kJ \end{aligned}[/tex]          (equation 1 )

During Expansion system:

Work done by the piston [tex]\rm (W_{2-1})[/tex] = 100000 Nm or 100 kJ

Now putting values in the equation:

[tex]\begin{aligned}\rm Q_{2-1} &= \rm U_{1} - U_{2} + W\\\\&=\rm (U_{1} - U_{2}) + W\end{aligned}[/tex]

Substituting value from equation 1:

[tex]\begin{aligned}\rm Q_{2-1} &= - 37+100\rm \;kJ\\&= 63\rm \; kJ\end{aligned}[/tex]

Therefore, 63kJ of energy is added to the system.

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Answer:

★ Pressure and depth have a directly proportional relationship. This is due to the greater column of water that pushes down on an object submerged. Conversely, as objects are lifted, and the depth decreases, the pressure is reduced.

Explanation:

Hope you have a great day :)

Answer:

the momentum is 164500 kg m/s

Explanation:

The computation of the momentum is shown below:

As we know that

Momentum is

= mass × velocity

= 9851.6 kg × 16.7 m/s

= 164522 kg·m/s

= 164500 kg m/s

hence, the momentum is 164500 kg m/s

Answer:

the creation of oxygen

Explanation: i just took the k12 test :)

Answer:

apple

Explanation:

Answer:

The purpose of regular health examination is to evaluate health status, screen for risk factors and disease, and provide preventive counseling interventions. The major benefits of regular health examination is early detection of treatable disease.

Answer:

True

Explanation:

Answer:

hello your question is incomplete below is the missing part

Ex = 0

Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]

Explanation:

Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π

Ex = 0

Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]

Answer:

The horizontal distance traveled by the projectile is 373.36 m.

Explanation:

Given;

angle of projection; θ = 30⁰

initial velocity of the projectile, u = 65 m/s

The horizontal distance traveled by the projectile or range of the projectile is calculated as;

[tex]R = \frac{u^2 \times sin(2\theta)}{g} \\\\R = \frac{65^2 \times sin(2\times 30^0)}{9.8}\\\\R = \frac{4225\times sin(60)}{9.8} \\\\R = 373.36 \ m[/tex]

Therefore, the horizontal distance traveled by the projectile is 373.36 m.

You can see if the person your talking to and being mindfull they  will see respect towards you or they see you as a mindful person.It shows a person that you care.

Explanation:

Answer:

the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Explanation:

Given;

energy of Mr. Voytko, E = 7.35 J

mass of the apple, m = 0.3 kg

Apply the principle of conservation of energy.

Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.

E = mgh

where;

h is the height above the ground through Mr. Voytko lifted the apple.

g is acceleration due to gravity = 9.8 m/s²

h = E / (mg)

h = 7.35 / (0.3 x 9.8)

h = 2.5 m

Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.