Remember that for a given angle θ, any point on the unit circle is written as:
(cos(θ), sin(θ)).
And remember that:
cos(45°) = sin(45°) = √2/2
Then the angle θ = 45° is a solution.
To find another positive solution, we just add the period of the circle, which is 360°.
θ = 45° + 360° = 405°
Adding the period again:
θ = 405° + 360° = 765°
So the 3 positive solutions can be:
{45°, 405°, 765°}
To get the negative angles we just subtract the period:
45° - 360° = -315°
We can do that again:
-315° - 360° = -675°
So the two negative angles are:
{-315°, -675°}
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Bob has saved $535 each month for the last 3 years to make a down payment on a house. The account earned an interest rate of .34 percent per month. How much money is in Bob's account?
Answer:
The account has $18,795.02.
Step-by-step explanation:
The account has $18,795.02.
3 years * $535 = $1,605
$1,605 * .0034 = $5.481
$5.481 * 36 (months) = $197.146
$18,795.02 = $1,605 + $197.146
Please help me solve this
A function assigns the values. The value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
Given p(x)= x²+5x, therefore, the value of (p·p)(x) can be written as,
(p·p)(x) = p(p(x))
= (x²+5x)²+5(x²+5x)
= x⁴ + 25x² + 10x³ + 5x² + 25x
= x⁴ + 10x³ + 30x² + 25x
Hence, the value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.
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Use Cramer Rule to solve the following system: 8x−5y=70 and 9x+7y=3
Answer:
[tex](x,y) = (5,-6)[/tex]
Step-by-step explanation:
[tex]\underline{\textbf{Determinant of a matrix.}}\\\\\text{For a}~ 2 \times 2 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2\\b_1&b_2 \end{vmatrix} = a_1b_2 - a_2b_1\\\\\\\text{For a}~ 3 \times 3 ~ \text{matrix,}\\\\\begin{vmatrix} a_1&a_2&a_3\\ b_1&b_2&b_3\\ c_1&c_2&c_3 \end{vmatrix} = a_1\begin{vmatrix} b_2&b_3\\c_2&c_3 \end{vmatrix} - a_2 \begin{vmatrix} b_1&b_3\\c_1&c_3 \end{vmatrix}+ a_3 \begin{vmatrix} b_1&b_2\\c_1&c_2 \end{vmatrix}\\\\\\[/tex]
[tex]~~~~~~~~~~~~~~~~~~=a_1(b_2c_3-b_3c_2) -a_2(b_1c_3-b_3c_1) +a_3(b_1c_2-b_2c_1)[/tex]
[tex]\underline{\textbf{Cramer's Rule to solve a system of two equations.}}\\\\\text{Consider the system of two equations:}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_1x + b_1 y= c_1\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~a_2x +b_2 y = c_2\\\\\text{Here,}\\\\x = \dfrac{D_x}{D}= \dfrac{\begin{vmatrix} c_1&b_1\\c_2&b_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\\\ y= \dfrac{D_y}{D}= \dfrac{\begin{vmatrix} a_1&c_1\\a_2&c_2 \end{vmatrix}}{\begin{vmatrix} a_1&b_1\\a_2&b_2 \end{vmatrix}}\\\\[/tex]
[tex]\underline{\textbf{Solution:}}\\\\~~~~~~~~~~~~~~~~~~~~~~~8x-5y = 70~~~~~~...(i)\\\\~~~~~~~~~~~~~~~~~~~~~~~9x +7y = 3~~~~~~~...(ii)\\\\\text{Applying Cramer's rule:}\\\\x = \dfrac{D_x}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 70& -5 \\3&7 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{70(7) -(-5)(3)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{490+15}{56+45}\\\\\\~~=\dfrac{505}{101}\\\\\\~~=5[/tex]
[tex]y = \dfrac{D_y}{D}\\\\\\~~=\dfrac{\begin{vmatrix} 8& 70 \\9&3 \end{vmatrix}}{\begin{vmatrix} 8& -5\\ 9& 7\end{vmatrix}}\\\\\\~~=\dfrac{(8)(3) -(70)(9)}{(8)(7)-(-5)(9)}\\\\\\~~=\dfrac{24-630}{56+45}\\\\\\~~=-\dfrac{606}{101}\\\\\\~~=-6[/tex]
[tex]\textbf{Hence, the solution to the system of equation is}~ (x,y) = (5,-6)[/tex]
pls help with thisc...................................
Answer:
D
598*47+38=
28106+38=
28134
only 2/3 of the school districts kindergarten teachers are women. if 59 are men, how many kindergarten teachers in all are employed by the school district
Answer:
177
Step-by-step explanation:
2/3 are women.
that means the remainder, 1/3, are men.
59 = 1/3 of all kindergarten teachers (3/3 = 1 representing the "whole").
so,
59×3 = 177
is the number of all kindergarten teachers employed by the school district.
54-90.27-90.22-90.87-90
Answer: -307.36 I think
Step-by-step explanation:
the polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity at x=-2.
find a possible formula for P(x)
P(x)=
Polynomial is an expression that consists of indeterminates(variable) and coefficients. The possible formula for P(x) is x⁵ - 2x⁴ - 4x³ + 8x².
What are polynomials?Polynomial is an expression that consists of indeterminates(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponentials.
Given the roots of the polynomial, therefore, the following details can be written as,
The polynomial has a root of multiplicity 2 at x=2, (x-2)²The polynomial has a root of multiplicity 2 at x=0, (x-0)²The polynomial has a root of multiplicity 1 at x=-2, (x+2)¹Therefore, the polynomial will become,
P(x) = (x-2)²(x-0)²(x+2)¹
= (x²+4-4x) (x)² (x+2)
= (x²+4-4x) (x³+2x²)
= x⁵ + 2x⁴ + 4x³ + 8x² - 4x⁴ -8x³
= x⁵ - 2x⁴ - 4x³ + 8x²
Hence, the possible formula for P(x) is x⁵ - 2x⁴ - 4x³ + 8x².
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What does each decreasing portion of the graph represent? bouncing a ball
Each decreasing portion of the graph indicates the ball has been thrown upward and is traveling toward the ground.
What is a graph?A graph can be defined as a type of chart that is used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate i.e x-axis and y-axis.
By critically observing the graph attached in the image below, we can infer and logically deduce that each decreasing portion of the graph indicates the ball has been thrown upward and is traveling toward the ground.
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The volume of the above solid is
Need number 2 please!!
Answer:
A
Step-by-step explanation:
note that i = [tex]\sqrt{-1}[/tex]
given
- 1 + 2i[tex]\sqrt{3}[/tex]
= - 1 + [tex]\sqrt{2^2(-1)3}[/tex]
= - 1 + [tex]\sqrt{-12}[/tex]
Find the area of the shaded portion of the
figure. All angles are right angles.
Dimensions are in inches.
3
8
5
Answer:
22 [in.²]
Step-by-step explanation:
1. the required area can be calculated as
A=A1-A2, where A1- area of big quadrilateral, A2-area of the small quadrilateral;
2. A=5*8-3*6=40-18=22 [in²].
find the value of x
d:6
[tex] \sf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's solve for x ~
[tex]\qquad \sf \dashrightarrow \: 5x = 3x + 12[/tex]
[ by vertical opposite angle pair ]
[tex]\qquad \sf \dashrightarrow \: 5x - 3x = 12[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x = 12[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 12 \div 2[/tex]
[tex]\qquad \sf \dashrightarrow \: x = 6[/tex]
Therefore, the correct choice is D. 6
Maximiza a: z=5x+2y
Sujeta a: x+2y≤12
x+y≥4
x,y ≥0
Answer:
hi
Step-by-step explanation:
no
Which degenerate conic is formed when a double cone is sliced through the a pex by a plane parallel to the slant edge of the cone?
Circle
Parabola
One line
Two lines
One line will be formed which will be parallel to the slant edge option third is correct.
What is a conic section?It is defined as the curve which is the intersection of cone and plane. There are three major conic sections; parabola, hyperbola, and ellipse (circle is a special type of ellipse).
We have a statement:
Which degenerate conic is formed when a double cone is cut through the top by a plane parallel to the slant edge of the cone?
As we can see in the attached picture if the double cone is cut through the top by a plane parallel to the slant edge of the cone one line will be formed which will be parallel to the slant edge.
Thus, one line will be formed which will be parallel to the slant edge option third is correct.
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Use the point–slope formula to write an equation of the line that passes through(-5, -16 )and has a slope of m=3. Write the answer in slope–intercept form (if possible).
Answer:
Slope-intercept form: y = 3x - 1
Step-by-step explanation:
We are given that a line passes through the point (-5, -16) and has a slope of 3
We want to write the equation in point-slope form, and simplify it to slope-intercept form (if it is possible to do so).
First, point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
We have both the slope and a point, but let's label the values of everything to avoid confusion + mistakes:
m = 3
[tex]x_1=-5\\y_1=-16[/tex]
Now substitute into the formula (remember: we have NEGATIVE numbers, and the formula uses SUBTRACTION):
[tex]y--16=3(x--5)[/tex]
The equation can be simplified
[tex]y+16=3(x+5)[/tex]
We can also write this in slope-intercept form
Start by distributing 3 to both x and 5 (multiply both x and 5 by 3)
[tex]y+16=3x + 15[/tex]
Subtract 16 from both sides
y = 3x - 1
Find the interval in which the function f(x) = |x + 4| is increasing.
[tex]f { }^{ - } (x) = \frac{2(x + 4)}{2 |x + 4| {}^{} } = \frac{x + 4}{ |x + 4| } [/tex]
[tex] |x + 4| \: is \: always \: positive[/tex]
[tex]solve \: x + 4 > 0[/tex]
[tex]x > - 4[/tex]
[tex]f(x) \: is \: incresing \: from \\[/tex]
]-4,∞[A 450-pound circus tiger eats 15 pounds of meat per day. How many pounds of meat would you expect a 360-pound tiger to eat per day? A 450 - pound circus tiger eats 15 pounds of meat per day . How many pounds of meat would you expect a 360 - pound tiger to eat per day ?
Part A
Which shapes can you use to model the log and the board?
Answer:
A cylinder
Step-by-step explanation:
Hope this helps :)
If the line segment AB is on a number line, and point A is at 6 and Point B is at 13, then the length of AB is ____.
Answer:
7
Step-by-step explanation:
The length of AB is the distance between A and B which is B-A -> 13-6= 7
Write an expression that can be used to produce vector b from vector a, and explain how you determined that expression.
Answer:
Expression that can be used to produce vector b from vector a
= T× magnitude of vector a × vector 'a'
Step-by-step explanation:
Given question is based on the concept of vectors
Vectors:- Vectors is a geometric entity that has both magnitude and direction. Vectors have an initial point at the point where they start and a terminal point that tells the final position of the point. Various operations can be applied to vectors such as addition, subtraction, and multiplication
To produce an another vector form a given vector we increase its magnitude only not its direction as we have to produce another vector 'b' with increased magnitude from a given vector 'a'.
its clear from the question that only the magnitude of vector a is increased to produce another vector b
hence we multiply any constant ('T') with the magnitude of vector a to increase its magnitude.
and finally multiply the increased magnitude with the vector 'a' itself to get the answer.
so, the final expression that can be used to produce vector b from vector a is = T× magnitude of vector a × vector 'a'.
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12x² + 9x² =
A. 21x²²
B. 21x
C. 22x²
D. 22xA
Answer:
21x²
Step-by-step explanation:
hopefully A is a typo
Answer: A (if it's just a typo) or [tex]21x^{2}[/tex]
Step-by-step explanation:
Since it's the same variable and same exponent, you just need to add the whole numbers and put the same variable and exponent.
12 + 9 = 21
[tex]21x^{2}[/tex]
f(x)=1/x at x=1 find slope of tangent
Answer:
f'(1)=-1
Step-by-step explanation:
You can just find the derivative using the power rule for d/dx (x^-1)=-1x^-2=-1/x^2 then find f'(1)=-1.
I used the limit definition of the derivative to find the slope in the picture attached
The scale on a map says 1 inch = 25 miles. If two towns are 3 1/2
apart on the map, what actual distance separates them?
Answer:
87.5 miles
Step-by-step explanation:
Distance between points = 3 1/2 × 25 = 87.5 miles
Given a_4=135\;and\;a_6=1215a
4
=135anda
6
=1215, find the explicit rule for the geometric sequence, given that the common ratio is positive.
Answer:
Step-by-step explanation:
let a be first term and r be c.r.
a_{n}=ar^{n-1}
a_{4}=ar^{4-1}=ar^3=135
a_{6}=ar^{6-1}=ar^5=1215a_{4}=1215 \times 135
divide
r^2=1215
r=√1215=35
a_{n}=35 a_{n-1}
A snack bar offers chili and/or cheese on its hot dogs for an additional fee.
The owner kept track of the hot dog orders over the course of a week. His
data are shown in a relative frequency table.
Answer:
the answer is c. the row is chili, the column is no cheese
P(-4, 6), Q(2, 5), R(3, -1), S(-3, 0)
Use slope to determine whether the following is a parallelogram. Explain why or why not.
Find the slope of PQ
Find the slope of QR
Find the slope of RS
Find the slope of SP
Use this information to determine if the quadrilateral a parallelogram.
From the slopes it is confirmed that PQ || RS OR|| SP and therefore it is a parallelogram .
What is a Parallelogram ?A parallelogram is a quadrilateral in which the opposite sides are parallel.
The coordinates of a quadrilateral is given
To prove that it is a parallelogram
PQ || RS
OR|| SP
The slope of a straight line is given by
[tex]\rm m = \dfrac{y_2 -y_1}{x_2- x_1}[/tex]
For PQ
m = (-1/6) = -1/6
For QR
m = -6/1 = -6
For RS
m = 1/(-6) = -1/6
For SP
m = -6
From the slopes it is confirmed that
PQ || RS
OR|| SP
and therefore it is a parallelogram
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Make sure you click the image for full picture
Answer:
See below.
Step-by-step explanation:
19.
The spinner has 12 equal-sized sections.
1/3 of 12 = 4
A number that appears in exactly 4 sections has a probability of 1/3. The number 3 appears exactly 3 times.
A number that appears more than 4 times has a probability greater than 1/3. The number 0 appears exactly 5 times.
A number that appears fewer that 4 times has a probability of less than 1/3.
Both 1 and 2 appear fewer than 4 times.
Answer:
Probability greater than 1/3: 0
Probability equal to 1/3: 3
Probability less that 1/3: 1, 2
20.
The amount of concentrate is 12 gallons.
The total amount of drink is 40 gallons.
The fraction of the concentrate out of the total is 12/40.
12/40 = 0.3
0.3 of each gallon is concentrate.
Color the bottom up to 0.30
Find how many quarts of 6% butterfat milk and 3% butterfat milk should be mixed to yield 45 quarts of 4% butterfat milk. Find how many quarts of 6 % butterfat milk and 3 % butterfat milk should be mixed to yield 45 quarts of 4 % butterfat milk .
Answer:
See below
Step-by-step explanation:
x = amount of 6% milk.... amount of fat = .06x
45-x = amount of 3% milk ...amount of fat = .03 (45-x)
Amount of fat in final mix of 45 quarts = .04 (45)
Inputs = output
.06x + .03(45-x) = .04(45)
.06x + 1.35 - .03x = 1.8
.03x = .45
x = 15 quarts of 6% then 30 quarts of 3%
Which of the following points would fall on the line produced by the point-slope form equation y - 2 = 3(x - 5) when graphed?
(4, 5)
(6, 5)
(5, 5)
(1, 4)
The point is (6, 5).
What is graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
Given :
y - 2 = 3(x - 5)
Those point will satisfy after putting the value of x and y we get LHS= RHS.
take (4, 5)
5-2 = 3(4-5)
3= -3
Hence, not satisfied.
take, (6, 5)
5-2 = 3(6-5)
3= 3
Hence, satisfied.
take, (5, 5)
5-2 = 3(5-5)
3= 0
Hence, not satisfied.
take, (1, 4)
4-2 = 3(1-5)
2= -12
Hence, not satisfied.
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Graph A: A horizontal line goes from (1, 0.5) to (2, 0.5). Another horizontal line goes form (2, 0.2) to (7, (0, 2). Graph B: A curve starts at (0, 0), curves up to (1, 1), and then curves down to (2, 0).
Which graph represents a density curve, and why?
graph A only, because the curve is above the horizontal axis, and the area under the curve from 2 to 7 is 1
graph B only, because the curve is above the horizontal axis, and the area under the curve is equal to 1.57
both graph A and graph B, because both curves are above the horizontal axis, and both areas are positive
neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1
Pictures posted below
Answer: neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1
Step-by-step explanation:
Areas under the graphs:
Graph A
[tex](1)(0.5)+(7-2)(0.2)=1.5\\\\[/tex]
Graph B
[tex]\frac{\pi}{2}(1^{2})=\frac{\pi}{2}[/tex]
As neither of these graphs have an area of 1, neither of them are density curves.
The statement - "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.
A few fundamental principles apply to density curves:
A density curve's area beneath it represents probability.A density curve's area under it equals one.Base x height in a uniform density curve equals one.The likelihood that x = a will never occur.The likelihood that x < a is the same as that of x ≤ a.Neither curve of Graph A nor of Graph B has the area under the curve summed up as 1, though the curve is above the horizontal axis.
Hence, because neither graph has an area of 1, even if both curves are above the horizontal axis, the statement "neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1" is true.
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