The given question incomplete, the complete question is:
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.
Answer:
The correct answer is 6.2114 grams.
Explanation:
Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.
Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,
w = 27*1800*37 / 3*96500
w = 1798200 / 289500
w = 6.2114 grams
Hence, pure aluminum produced in the process is 6.2114 grams.
The ingredients of the soda are best described as : Mixtures, compounds, or elements.
Answer:
Compound
Explanation:
Soda itself is a mixture made out of compounds.
Answer:
Its B - Compounds
Explanation:
On Edge 2021
Which one of the following bonds would be best categorized as covalent
(molecular)? 1. H--S 2. S--O 3. N--F
1 only
1 and 2
1 and 3
1, 2 and 3
Answer:
1, 2 and 3
Explanation:
A covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons , is known as covalent bonding.
A covalent bond involves as stated above, the mutual sharing of one or more electron pairs of between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions. Shared electrons located in the space between the two nuclei are called bonding electrons. The bonded pair is the binding factor that holds the two atomic nuclei together in molecular units.
A covalent bond is commonly formed between two nonmetals. As we can see in the question; 1, 2 and 3 represents bonds formed between two nonmetallic elements. Hence they are rightly classified as molecular or covalent bonds.
Explain in terms of bonding why the hydrocarbon 2-methylpropane is saturated
Answer:
because no 2 or 3 bond so it is saturated
The reform reaction between steam and gaseous methane () produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen. Suppose a chemical engineer studying a new catalyst for the reform reaction finds that liters per second of methane are consumed when the reaction is run at and . Calculate the r
Answer:
The rate at which dihydrogen gas is being produced = 0.018 kg/s
Explanation:
Firstly, we write the balanced equation for the production of the synthesis gas
CH₄ + H₂O → CO + 3H₂
The rate of consumption of CH₄ is 159 litres per second. With the reaction ran at T = 294°C and a pressure of 0.86 atm
Using the ideal gas equation, we can convert the volumetric rate of consumption of methane to molar rate of consumption
PV = nRT
PV' = n'RT
P = pressure = 0.86 atm = 87,139.5 Pa
V' = 159 L/s = 0.159 m³/s
n' = ?
R = molar gas constant = 8.314 J/mol.K
T = absolute temperature in Kelvin = 294°C = 567.15 K
87,139.5 × 0.159 = n' × 8.314 × 567.15
n' = (87,139.5 × 0.159) ÷ (8.314 × 567.15)
n' = 2.9383547773 mol/s = 2.938 mol/s
From the stoichiometry of this reaction,
1 mole of methane gives 3 moles of dihydrogen gas
2.938 mol/s of methane will correspond to (3 × 2.938) mol/s of dihydrogen gas, that is, 8.815 mol/s.
Mass flowrate = (molar flowrate) × (molar mass)
Molar flowrate = 8.815 mol/s
Molar mass of dihydrogen gas = 2 g/mol = 0.002 kg/mol
Mass flowrate = 8.815 × 0.002 = 0.0176301287 kg/s = 0.018 kg/s to 2 s.f.
Hope this Helps!!!
Complete Question:
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen.
Suppose a chemical engineer studying a new catalyst for the reform reaction finds that 924. liters per second of methane are consumed when the reaction is run at 261.°C and 0.96atm. Calculate the rate at which dihydrogen is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.
Answer:
Rate at which H₂ is produced = 0.12 kg/s
Explanation:
Volume of methane produced, V = 924 litres
Temperature, T = 261.°C = 261 + 273
T = 534 K
Pressure, P = 0.96 atm
Gas constant, R = 0.0821 L-atm/ K-mol
We will calculate the number of moles of methane used in the reaction.
[tex]n_{methane} = \frac{PV}{RT} \\n_{methane} = \frac{0.96 * 924}{0.0821 * 534} \\n_{methane} = \frac{887.04}{43.8414}\\n_{methane} = 20.23 moles[/tex]
Equation of reaction:
[tex]CH_{4} + H_{2} O \rightarrow CO + 3H_{2}[/tex]
From the reaction above :
1 mole of methane produced 3 moles of H₂
20.23 moles of methane will produce (20.23 * 3 ) moles of H₂
Number of moles of H₂, [tex]n_{H_{2} } = 60.69 moles[/tex]
That is 60.69 moles of hydrogen is produced per second.
Number of moles = Mass/ Molar mass
[tex]n_{H_{2} } = \frac{Mass_{H_{2} }}{Molar mass_{H_{2} }} \\Mass_{H_{2}} = n_{H_{2} } * Molar mass_{H_{2} }\\Mass_{H_{2}} = 60.69 * 2.016\\Mass_{H_{2}} = 122.35 g[/tex]
Rate at which H₂ is produced = 122.35 g/s = 0.12 kg/s
Maybelline Cousteau’s backup oxygen tank reads 650 torr while on her boat, where the temperature is 27 degrees C. When she dives down to the bottom of an unexplored methane lake on a recently-discovered moon of Neptune, the temperature will drop down to –183 degrees C. What will the pressure in her backup tank be at that temperature?
Answer: 180torr
Explanation:
Using P1VI/T1= P2V2/T2
where
p1= 650 torr
p2=??
T1= 27°C = 27°C + 273= 300K
T2= -183°C= -183°C +273=90K
V1= V2 ie volume is constant
SOLUTION
1 torr= 1mmHg
P1VI/T1= P2V2/T2, where V1=V2
= P1/TI= P2/T2
600/300=P2/90
P2= 600X90/300= 180 torr
An experimental procedure says to accurately weigh approximately 1 g of substance an analytical balance. Which of the following measurements are consistent with these instruction select all that apply a 1.0456 g B 1.0 g C 0.9811 g D1 gram 1.01 g E .99
Answer:
B 1.0 g
Explanation:
Hello,
In this case, by means of the significant figures we can see that 1 g has one significant figure only, for that reason, among the options, we should select one having the closest value to it, for that reason, the correct answer should be B 1.0 g as the measurement indicates the desired value.
Best regards.
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank with of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be . Calculate the concentration equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to significant digits.
Answer:
Kc = 15.25
Explanation:
In this case, As I say in the comments, you are missing the following data of moles and volume which are:
Initial moles of ammonia = 29 mol
Final moles of nitrogen = 13 mol
Volume tank = 75 L
Now, if your data is different, just replace the values and follow the same procedure written here to get the accurate result.
With these data, let's write the equilibrium reaction that is taking place here:
2NH₃ <---------> N₂ + 3H₂ Kc = ?
To get the Kc, we need to use the following expression:
Kc = [N₂] [H₂]³ / [NH₃]²
This expression is only usable when we reach the equilibrium. But we don't have the concentrations in equilibrium of any species, so, we need to get those values. To get that, we need to do an ICE chart, write the initial and final concentrations given, and then, replace the values.
First, the concentrations of the species are:
[NH₃] = 29 / 75 = 0.3867 M
[N₂] = 13 / 75 = 0.1733 M
Now that we have these values, we will replace them in the ICE chart, and then, rewrite the Kc expression to get that value so:
2NH₃ <---------> N₂ + 3H₂ Kc = ?
i) 0.3867 0 0
c) -2x +x +3x
e) 0.3867-2x x 3x
However, as we already have the value for concentration of nitrogen, this will be the value of "x", therefore, our final values in equilibrium would be:
[NH₃] = 0.3867 - 2(0.1733) = 0.0401 M
[H₂] = 3(0.1733) = 0.5199 M
Now with these values, we can replace them in the Kc expression to get that value so:
Kc = (0.5199)³ * (0.1733) / (0.0401)²
Kc = 0.0244 / 0.0016
Kc = 15.25
And this is the value of Kc for this reaction.
Two types of alcohols namely as methylcyclohexanol and 2-methyl-2-hexanol were subjected to dehydration reaction and yield a mixture of two isomeric alkenes. Proposed a chemical reaction of both alcohols and determine which one is the major product. Justify your answer.
Answer:
a) Methylcyclohexanol = 1-methylcyclohex-1-ene and methylenecyclohexane
b) 2-methyl-2-hexanol = 2-methylhex-1-ene and 2-methylhex-2-ene
Explanation:
We have to remember that the dehydration of alcohols follows the Zaitsev rule. So, the most substituted alkene would be the major product for both molecules
In the case of methylcyclohexanol we have several options to put the double bond. Inside of the cyclic structure (1-methylcyclohex-1-ene) or between the cyclic structure and the methyl group (methylenecyclohexane). The most substituted one is 1-methylcyclohex-1-ene, so this is our major product.
In the case of 2-methyl-2-hexanol we have again several options for the double bond. Between the tertiary carbon (the carbon that holds the "OH" group) and the carbon in the left (2-methylhex-2-ene). The other option is to put the double between the tertiary carbon the carbon in the right (2-methylhex-1-ene). The most substituted one is 2-methylhex-2-ene, so this is our major product.
See figure 1
I hope it helps!
What inference can be drawn from the graph?
A + B C + D
A
The reaction between A and B is reactant favored.
B.
The amount of product is greater than the amount of reactant.
C. The reaction uses all its reactants to form products.
D
The reaction reaches equilibrium at 15 seconds
which compound is saturated hydrocarbon
Answer:
alkanes are saturated
Answer: alkane
Explanation: because carbon is bonded to the maximum number of hydrocarbons e.gCH4
Examine the reaction equation. CH4 + O2 →H2O + CO2 What coefficients will balance the equation? A) 2, 3, 2, 2 B) 1, 3, 2, 1 C) 1, 2, 2, 1 D) 1, 1, 1, 1
Answer:
B
Explanation:
CH4 + O2 →H2O + CO2
Left side
C = 1
H = 4
O = 2
Right side
C = 1
H = 2
O = 3
So find common denominator in this case would be 6 O
CH4 + 3O2 →2H2O + CO2
Left side
C = 1
H = 4
O = 6
Right side
C = 1
H = 4
O = 6
Answer:
[tex]\huge \boxed{\mathrm{C) \ 1, 2,2,1}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O[/tex]
Balancing the Hydrogen atoms on the right side,
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O[/tex]
Balancing the Oxygen atoms on the left side,
[tex]\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O[/tex]
[tex]\rule[225]{225}{2}[/tex]
How cholestrol transport fatty acids in body ?
In order to use the energy stored in fat, the body breaks dow triglycerides into fatty acids, which individual cells burn for energy
Based on the activity series provided which reactants will form products? F>Cl>Br>l
Answer:
CuI₂ + Br₂
Explanation:
Answer:
CuI₂ + Br₂
Explanation:
1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).
The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.
2) Choice 1: CuI₂ + Br₂
Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:
CuI₂ + Br₂ → CuBr₂ + I₂
Being I less active than Br, it cannot displace Br in CuBr₂.
3) Choice 2: Cl₂ + AlF₃
Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.
4) Choice 3: Br₂ + NaCl
Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.
5) Choice 4: CuF₂ + I₂
Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.
hope this helped!
A person has a height of 65 inches
You want to find out the height of
that person in centimeters. Which
unit conversion would you use?
Answer:
1 inch = 2.54 centimeters
Explanation:
A conversion factor or unit conversion is used to change the units only without affecting the value.
1 inch = 2.54 centimeters
Given, height = 65 inches
So, the height of that person in centimeters = 65 x 2.54
= 165.1 cm
Hence, the person's height in centimeters will be 165.1 cm.
. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH
Answer:
[tex]V_{HCl}=80mL[/tex]
Explanation:
Hello,
In this case, for the given reactants we identify the following chemical reaction:
[tex]KOH+HCl\rightarrow KCl+H_2O[/tex]
Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:
[tex]n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}[/tex]
Hence, we compute the volume of HCl as shown below:
[tex]V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL[/tex]
Best regards.
How many moles are in 42.9 g of Fe2O4
Answer:
0.24375moles
Explanation:
Moles=mass/moler mass
Fe-56
O-16
(56×2)+(16×4)
=176
42.9÷176=0.24375moles
Which hormones are secreted from the posterior pituitary gland?
Answer:
growth hormone is ur answer
Answer:
Explanation:
two hormones are secreted from posterior lobe i.e. oxytocin and vasopressin
Which of the following shows the proper configuration of a straight chain isomer of nonane? A B C
Answer:
C
Explanation:
The correct option is C and the anming is 2-ethyl-3-methylhexane.
Isomers are compounds that have the same molecular formula but different structural formula; that s the way in which the atoms are arranged.
The Molecular formula of nonane is C9H20.
Answer:
C
Explanation:
Potatoes can be peeled commercially by soaking them in a 3M to 6M solution of sodium hydroxide, then removing the skins by spraying them with water. If titration of 12.00 mL of the sodium hydroxide requires 30.6 mL of 1.65 M HCl solution, what is the concentration of NaOH used in potato peeling?
Answer:
4.21 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
30.6 mL of 1.65 M HCl reacted. The reacting moles of HCl are:
[tex]0.0306 L \times \frac{1.65mol}{L} = 0.0505 mol[/tex]
Step 3: Calculate the reacting moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The reacting moles of NaOH are 1/1 × 0.0505 mol = 0.0505 mol.
Step 4: Calculate the molar concentration of NaOH
0.0505 moles of NaOH are in 12.00 mL. The molar concentration of NaOH is:
[tex]M = \frac{0.0505 mol}{0.01200L} = 4.21 M[/tex]
What is the symbol for the chlorine ion that forms when chlorine nonmetal reacts with sodium? A. C +1 B. Cl -1 C. Cl+1 D. C -1
Answer:
B. Cl -1
Explanation:
Chlorine has 7 valence electrons and needs one more to complete its octet thus takes one electron from sodium to become negatively charged Cl^-1.
A houseplant is placed on a window sill that gets direct, bright sunlight
every afternoon. The plant starts to grow toward the window What kind
of response is described by situation?
A
A negative response to a stimulus
6
A learned behavior
c
Gravitropism
D
Phototropism
Answer:
D. Phototropism
Explanation:
Plants, like every other living organism, responds to external stimulus. In this question, the stimulus is LIGHT from the sun entering through the window sill. The plant is responding positively to the light stimuli by growing towards the direction where the light is coming from. This exhibit is called PHOTOTROPISM.
Phototropism, comes from two words viz photo- meaning light and tropism- meaning movement. Hence, phototropism is the growth of an organism (plant in this case) in response to a light stimulus. The case described in this question is POSITIVE PHOTOTROPISM because the growth occurs towards the light source.
A doctor orders 4.0 mg of morphine. The vial of morphine on hand is 20. mg per 2.0 mL . How many milliliters of morphine should you administer to the patient?
A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it reaches a final volume of 13.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Answer:
7.61 moles
Explanation:
Hello, we'll first of all get the required data from the question to enable us find the best approach to the question.
Data;
Initial volume (V1) = 6.13L
Initial number of moles (n1) = 6.51mol
Final volume (V2) = 13.3L
Final number of moles = ?
To solve this question, we'll use Avogadro's law which states that the number of moles of a fixed mass of gas is directly proportional to its volume provided that temperature and pressure remains constant.
Mathematically,
n = kV, k = n / V
n1 / V1 = n2 / V2 = n3 / V3 =..........=Nx / Vx
n1 / V1 = n2 / V2
Substitute the values into the above equation
6.51 / 6.13 = n2 / 13.3
n2 = (6.51 × 13.3) / 6.13
n2 = 14.12moles
The final mole of the gas is equal to 14.12mol
To find the number of moles added to the system, we'll subtract the initial mole from the final mole.
Number of moles added = n2 - n1
Number of moles added = 14.12 - 6.51
Number of moles added = 7.61moles
Therefore, 7.61 moles of the gas was added into the system
Suppose a current of flows through a copper wire for seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.
Answer:
1.20 × 10⁻³ mol e⁻
Explanation:
There is some info missing. I think this is the original question.
Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.
Step 1: Given data
Intensity of the current (I): 0.880 A (= 0.880 C/s)Time elapsed (t): 132 sStep 2: Calculate the charge, in Coulomb, that travel through the wire
We will find the circulating charge (q) using the following expression.
[tex]q = I \times t = \frac{0.880C}{s} \times 132s = 116C[/tex]
Step 3: Calculate the moles of electrons with a charge of 116 C
We will use the relationship 1 mole of electrons = 96,486 C (Faraday's constant)
[tex]116C \times \frac{1mol\ e^{-} }{96,486 C} =1.20 \times 10^{-3} mol\ e^{-}[/tex]
which option describes energy being released as heat?
A- a Child shivering in the cold
B- Lions Sleeping after a big meal
C- A surfer on a Surfboard
D- A Baby Bird eating a Worm
Answer:
a
Explanation:
A child shivering gives off energy to transfer that energy into heat
Answer:
A
Explanation:
A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of the given amounts of HCl .
Answer:
pH =1 2.84
Explanation:
First we have to start with the reaction between HCl and KOH:
[tex]HCl~+~KOH->~H_2O~+~KCl[/tex]
Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:
[tex]M=\frac{mol}{L}[/tex]
We know that [tex]10mL=0.01L [/tex] and we have the concentration of the HCl [tex]0.282M[/tex], when we plug the values into the equation we got:
[tex]0.282M=\frac{mol}{0.01L}[/tex]
[tex]mol=0.282*0.01 [/tex]
[tex]mol=0.00282[/tex]
We can do the same for the KOH values ([tex]50mL=0.05L[/tex] and [tex]0.141M[/tex]).
[tex]0.141M=\frac{mol}{0.05L}[/tex]
[tex]mol=0.141*0.05 [/tex]
[tex]mol=0.00705[/tex]
So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:
[tex]0.00705-0.00282=0.00423mol~of~KOH[/tex]
Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:
[tex]Total~volume=50mL+10mL=60mL[/tex]
[tex]60mL=0.06L[/tex]
Now we can calculate the concentration:
[tex]M=\frac{0.00423mol}{0.06L}[/tex]
[tex]M=0.0705[/tex]
Now, we can calculate the pOH (to calculate the pH), so:
[tex]pOH=-Log(0.0705)[/tex]
[tex]pOH=1.15[/tex]
Now we can calculate the pH value:
[tex]14=~pH~+~pOH[/tex]
[tex]pH=14-1.15=12.84[/tex]
In the following chapter, enzyme catalysis reactions will be extensively reviewed. The first step in these reactions involves the binding of a reactant molecule (referred to as a substrate) to a binding site on the enzyme. If this binding is extremely efficient (that is, equilibrium strongly favors the enzyme–substrate complex over separate enzyme and substrate) and the formation of product rapid, then the rate of catalysis could be diffusion limited. Estimate the expected rate constant for a diffusion controlled reaction using typical values for an enzyme ( and Å) and a small molecular substrate ( and Å).
Complete Question
The complete question is shown on the first uploaded image
Answer:
The rate constant is [tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]
Explanation:
From the question we are told that
The values for an enzyme is given as
[tex]D_1 = 1.00 *10^{-7} \ cm^2 s^{-1}[/tex]
[tex]r_1 = 40.0 \r A = 40*10^{-8} cm[/tex]
The values of a small molecular substrate is
[tex]D_2 = 1.00 *10^{-5} \ cm^2 s^{-1}[/tex]
[tex]r_2 = 5.00 \r A = 5.00*10^{-8} \ cm[/tex]
The equation relating the rate constant is
[tex]k_d = 4 \pi N_A (D_1 +D_2) (r_1 +r_2)[/tex]
substituting values
[tex]k_d = 4 \pi (6.022 *10^{23})(1 *10^{-7} * 1*10^{-5} (40*10^{-8} + 5*10^{-8}))[/tex]
[tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]
Copper metal of 1.23 g sample is reacted completely with chlorine gas to produce
2.61 g of copper chloride. Determine the empirical formula of the compound?
Answer: The empirical formula of the compound is [tex]CuCl_2[/tex]
Explanation:
Mass of Copper (Cu) = 1.23 g
Mass of Chlorine (Cl) = Mass of copper chloride - mass of copper = (2.61 - 1.23) g = 1.38 g
Step 1 : convert given masses into moles
Moles of Cu =[tex]\frac{\text{ given mass of Cu}}{\text{ molar mass of Cu}}= \frac{1.23g}{63.5g/mole}=0.019moles[/tex]
Moles of Cl =[tex]\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{1.38g}{35.5g/mole}=0.038moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Cu =[tex]\frac{0.019}{0.019}=1[/tex]
For Cl = [tex]\frac{0.038}{0.019}=2[/tex]
The ratio of Cu : Cl = 1 : 2
Hence the empirical formula is [tex]CuCl_2[/tex]
This increase in blood pHpH due to hyperventilation disrupts O2O2 transport by causing the deprotonation of various residues of the hemoglobin protein. With less O2O2 reaching the brain, an individual who is hyperventilating may faint. Because the brain needs O2O2 to produce ATP, the brain temporarily shuts down the one function that demands the most ATP—consciousness. Shutting down consciousness conserves energy and allows the brain to devote its resources to maintaining essential life support functions, such as breathing. When O2O2 transport regains its efficiency, the individual regains consciousness. How would rebreathing exhaled air from a paper bag prevent an individual who is hyperventilating from fainting?
The question is incomplete as it does not have the options which has been provided in the attachment.
Answer:
1. sudden decrease
2. Respiratory alkalosis
Explanation:
Hyperventilation is a condition caused by the excess removal of the CO₂ from the blood which leads to the decrease in the pCO₂ of the arteries.
This decrease can cause fainting and death of the individual due to the malfunctioning of the body parts, especially the brain.
The decrease in the CO₂ amount of the blood causes the formation of bicarbonate and H⁺ ions which leads to respiratory alkalosis.
Therefore the selected options are correct.
). In a titration, a student obtained an average titre value of 3.9 cm3 of 0.3 M HCl. If the volume of Na2CO3 solution used is 10 cm3 and the indicator used is phenolphthalein, calculate; (i). the molarity of the Na2CO3 (4 marks) (ii). the mass concentration of the Na2 theCO3. (4 marks)
Answer:
I) 0.0585 M
ii)6.2 g dm-3
Explanation:
The reaction equation is given as;
Na2CO3(aq) +2HCl(aq)------> 2NaCl(aq) + CO2(g) +H2O(l)
Concentration of acid CA= 0.3 M
Volume of acid VA= 3.9 cm^3
Concentration of base CB= the unknown
Volume of base VB= 10 cm^3
Number of moles of acid NA= 2
Number of moles of base NB= 1
From;
CAVA/CBVB= NA/NB
CAVANB=CBVBNA
CB= CAVANB/VBNA
substituting values;
CB= 0.3 × 3.9 × 1/ 10.0 × 2
CB= 0.0585 M
ii) mass concentration= molar concentration × molar mass
Molar mass of Na2CO3= 106 gmol-1
Mass concentration= 0.0585 × 106 = 6.2 g dm-3
