The pounds of corn in the second month is 390
How to determine the amount?We have:
First month, a = 300
Rate, r = 35%
The pounds of corn in the second month is calculated using:
Pound = a * (1 + r)
So, we have:
Pound = 300 * (1 + 30%)
Evaluate the sum
Pound = 300 * 1.3
Evaluate the product
Pound = 390
Hence, the pounds of corn in the second month is 390
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Account earns 8.5% interest. If you invest $6,609 now how much interest will you earn in 5years
Answer:
simple interest is $281(nearest whole number)
Step-by-step explanation:
S. I=PXTXR
100
P=$6609
T=5
R=8.5 or 85/10
S. I=6609X5X85
100X10
=280.8825
=281
Giving the brainliest to those who answer!
meijun had some money. she used 1/3 of it on a watch and 1/9 of it on a gift. the watch and the gift cost $144 altogether. how much money did she have at first?
Answer:
$324
Step-by-step explanation:
let x be the amount of money she had at first , then
[tex]\frac{1}{3}[/tex] x + [tex]\frac{1}{9}[/tex] x = 144 ( multiply through by 9 to clear the fractions )
3x + x = 1296
4x = 1296 ( divide both sides by 4 )
x = 324
she had $324 at first
What is the rule for the reflection?
rx-axis (x, y) - (-x, y)
ry-axis (x, y) (-x, y)
rx-axis (x, y) - (x, y)
ry-axis (x, y) (x, −y)
When reflected over ry-axis (x, y) (-x, y) , rx-axis (x, y) (x,-y) , Option A and D is the correct answer.
What is rule for the reflection ?The rule for reflection is when an object or a coordinate point is reflected over x axis then the coordinate of the x axis remains the same while the y coordinate changes to be additive inverse.
Vice Versa happens when reflected over y axis.
So,
rx-axis (x, y) - (-x, y) --> (x,-y)
ry-axis (x, y) (-x, y)
Therefore Option A and D is the correct answer.
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Answer: its A not A & D
Step-by-step explanation:
Which numbers are irrational???
Answer:
√2/4, √3/4, and √5/4.
Step-by-step explanation:
A rational number is any integer, fraction, terminating decimal, or repeating decimal.
PLEASE HELP!!!!
Which operation should you perform last in the expression 3^2 + 2?
Answer: the +2
Step-by-step explanation: PEMDAS. Exponents are before addition in the sequence. I hope this helps!
(The E standing for exponents and the A standing for addition)
A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 65% salt and Solution B is 80% salt. She wants to obtain 120 ounces of a mixture that is 70% salt. How many ounces of each solution should she use?
Please Expand the following:
3q(r – 2q)
Answer:
3qr - 6q²
Step-by-step explanation:
3q(r - 2q) ← multiply each term inside the parenthesis by 3q
= 3qr - 6q²
Answer:
3qr – 6q²
Step-by-step explanation:
3q(r – 2q)
E X P A N D I N G :-
3qr – 6q²
Bret is planning a long hike. He figures that he will need at least 0.75 liters of water for each hour on the trail. He also wants to have 1.8 liters of water in reserve at all times. If he can only carry 9 liters of water maximum, how many hours can he hike?
The number of hours that Bret can hike with 9 liters of water is 9.6 hours.
What is a linear function?A straight line on the coordinate plane is represented by a linear function.
A linear function always has the same and constant slope.
The formula for a linear function is f(x) = ax + b, where a and b are real values.
As per the given,
Water needed = 0.75 liters per hour
For x number of hours = 0.75x liters
Reserved water = 1.8 liters.
Total water needs for x hours = (0.75x + 1.8)
The number of hours that can be hiked with 9 liters will be as,
(0.75x + 1.8) = 9
x = 9.6 hours.
Hence "The number of hours that Bret can hike with 9 liters of water is 9.6 hours".
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The function below has at least one rational zero.
Use this fact to find all zeros of the function.
f(x)=7x³ +9x²-12x-4
Answer:
Using the rational root theorem, we know to divide the function by (x - 1).
(7x³ + 9x² - 12x - 4) / (x - 1) = 7x^2 + 16x + 4
Now we can further factorize 7x^2 + 16x + 4 into (7x + 2) and (x + 2).
Therefore, the original function can be rewritten as (x - 1) (7x + 2) (x + 2).
Using the factorized form above, the zeros of the function are 1, -2/7, and -2.
4x+7-(x+6)=68
Solve.
[tex]4x + 7 - (x + 6) = 68 \\ \\ 4x + 7 - x - 6 = 68 \\ \\ 3x + 1 = 68 \\ \\ 3x = 68 - 1 \\ \\ 3x = 67 \\ \\ x = \frac{67}{3} \\ \\ x = 22.3[/tex]
The value of x is 67/3 or 22.3 .
Hi!
__________________________________________________________
[tex]\rightsquigarrow\circ\boldsymbol{Answer}\circ\leftharpoonup[/tex]
x=
[tex]\rightsquigarrow\circ\boldsymbol{Explanation}\circ\leftharpoonup[/tex]
First let's distribute the minus sign.
[tex]\twoheadrightarrow\sf 4x+7-x-6=68[/tex]
[tex]\bullet[/tex] Add 6 to both sides
[tex]\twoheadrightarrow\sf 4x+7-x=74[/tex]
[tex]\bullet[/tex] Subtract the x's
[tex]\twoheadrightarrow\sf 3x+7=74[/tex]
[tex]\bullet[/tex] Subtract 7 from both sides
[tex]\twoheadrightarrow\sf3x=67[/tex]
[tex]\bullet[/tex] Divide both sides by 3
[tex]\twoheadrightarrow\sf x=\cfrac{67}{3}[/tex]
[tex]\bullet[/tex] Great job! We solved for the variable
--
Hope that this helped! Best wishes.
[tex]\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}[/tex]
--
0000
O
1. Simplify 3 + 2 - 1
+6
2-5
03 A
О 25
Answer:
10
Step-by-step explanation:
3+2-1+6=5-1+6=4+6=10
3 more than half a number
Answer:
3 + a/2
Step-by-step explanation:
3 + a/2
What is 4 third written in expanded form
John is buying a new car. The value of one car he is considering is $20,000. The value of the car as it ages can be modeled by the function V = 20 , 000 ( 0 . 84 ) t , where t is the number of years from the time of purchase. One of the factors John is using to make his decision is the value of the car over time until it reaches half its original value. What values of domain are reasonable for the given function in this context?
A. all real numbers greater than or equal to 0 and less than 2.8
B. all real numbers greater than or equal to 10,000 and less than or equal to 20,000
C. all real numbers greater than or equal to 0
D. all real numbers greater than or equal to 0 and less than 4
Option D is the correct answer.
All real numbers greater than or equal to 0 and less than 4.
What is Domain?The domain of a function is the set of its possible inputs, i.e., the set of input values where for which the function is defined.
Here, The function of the car value is given as:
V(x) = 20000 X (0.84)ˣ
When the car reaches half its value, we have:
V(x) = 10000
Substitute V(x) = 10000 in V(x) = 20000 * (0.84)ˣ
10000 = 20000 X (0.84)ˣ
Divide both sides by 20000
0.84ˣ = 0.5
Take the logarithm of both sides
x log(0.84) = log(0.5)
Divide both sides by log(0.84)
x = 4
This means that the maximum value of x is 4.
Thus, all real numbers greater than or equal to 0 and less than 4.
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find the area for this pls
Answer:
Area = 3.36 in²
Step-by-step explanation:
[tex]Area\space\ of \space\ trapezium = \frac{a \space\ + \space\ b}{2} h[/tex] ,
where a and b are the two parallel sides, and h is the height.
[tex]Area = \frac{1.3 \space\ + \space\ 3.5}{2} (1.4)\\\\Area = 3.36 \space\ in^{2}[/tex]
what is the value of the rational expression below when is equal to 5?
15-(5)/5-10=10/-5=-2 hope it helps!
Which of the following equations would correspond to a conic section formed when a plane intersects a cone parallel to the base?
x2 + y2 = 32
x squared over 2 squared plus y squared over 3 squared equals 1
x2 = 8y
x squared over 2 squared minus y squared over 3 squared equals 1
The equation of the circle, ellipse, and hyperbola will be x² + y² = 3², x² + y² / 3² = 1, and x² / 2² - y² / 3² = 1, respectively.
What is the conic section?The curve that is derived from the section of the cone is known as conic section.
The following equations are given below.
x² + y² = 3², this is the equation of the circle.
x² + y² / 3² = 1, this is the equation of the ellipse.
x² / 2² - y² / 3² = 1, this is the equation of the hyperbola.
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Students returning to a secondary school have to pass through a check point at the rate of 50 per though. The average time for checking is 35 seconds. The arrival rate and service rate follow a Poisson distribution. There is a delay and the principal is willing to include another check point to reduce the average time of checking to 28 seconds if the idle time is less than 10% and the average queue length is more than 10 students, check whether the introduction of an extra check point is justifiable.
The average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.
How to explain the information?Since the arrival rate and service rate follow a Poisson distribution, we can use the Poisson arrival rate formula to calculate the average queue length.
Average queue length = (arrival rate * service time) / (1 - arrival rate * service time)
For the given problem, the average queue length is:
Average queue length = (50 * 35) / (1 - 50 * 35)
= 175
Since the average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.
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If a participant skips hard to answer questions in a survey, it causes
A.nonadherent bias
B.sampling bias
C.response bias
D.nonresponse bias
E.researcher bias
Answer:
I think non response bias because response bias includes answering incorrectly on a survey to get it over with so that is my answer
Step-by-step explanation:
Let f(x)=(3)^x−3. What is f(0) in fraction form?
Answer:
1/27
Step-by-step explanation:
We can substitute x=0 into the function to get:
f(0) = 3^(0-3)f(0) = 3^(-3)f(0) = 1/27Solve the following subtraction problem. Remember to borrow as necessary.
9cu yd113cu in
− 4cu ft129cu in
−−−−−−−−−−−−−−−−−−−−−−
The subtraction of the expression will be 238 cubic feet, 551 cubic inches.
What is subtraction?It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.
The expressions are given below.
9 cubic yd 113 cubic in and 4 cubic ft 129 cubic in
1 cubic yard = 27 cubic feet
1 cubic feet = 1728 cubic inches
Then the subtraction will be
242 cu ft 1841 cu in
− 4 cu ft 1290 cu in
238 cu ft 551 cu in
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The power 3 Superscript negative 3 equals StartFraction 1 Over 27 EndFraction . Which expression is equivalent to 3 Superscript negative 3?
Applying the negative exponent, it is found that the equivalent expression to [tex]3^{-3}[/tex] is [tex]\frac{1}{27}[/tex].
How to deal with a negative exponent?When we have a negative exponent, we use a fraction, with the term with the exponent going to the denominator, as follows:
[tex]a^{-b} = \frac{1}{a^b}[/tex]
Hence, in this problem, the equivalent expression is:
[tex]3^{-3} = \frac{1}{3^3} = \frac{1}{27}[/tex]
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Question:-
[tex] \dfrac{1}{2} + \dfrac{1}{4} [/tex]
Help!!
:"(
[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \red{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{3}{4} }[/tex]
Step by step explanation :-
The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \gray{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{1}{4} + \dfrac{1}{2} }}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \green{\dfrac{2 + 1}{4} = \dfrac{1 + 2}{4} }}[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{3}{4} = \dfrac{3}{4}} }[/tex]
Answer :- The answer is 3/4
¿What is commutative property?
It is to change different ways in order of the addends the result would be the same.
Example :-
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d} + \dfrac{a}{b}} }[/tex]
I hope I've helped : )
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: Final \:\: value = \cfrac{3}{4}[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{1}{2} + \cfrac{1}{4} [/tex]
[ take LCM ]
[tex]\qquad \tt \rightarrow \: \cfrac{2}{4} + \cfrac{1}{4} [/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{2 + 1}{4} [/tex]
[tex]\qquad \tt \rightarrow \: \cfrac{3}{4} [/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
can someone turn the equation 3−2=13 into a word problem. (i already know answer)
The word problem for given equation is : When 3 is multiplied with x and subtracted by 2 multiplied by y , the number obtained is 13. Solve the equation for x =1 .
The complete equation will be 3x - 2y =13
What is an Equation ?When an algebraic expression is equated by an equal sign to a constant or any other algebraic expression , then an equation is formed .
The equation given in the question is
3x-2y =13
When 3 is multiplied with x and subtracted by 2 multiplied by y , the number obtained is 13. Solve the equation for x =1 .
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A paramedic maintains a time card for hours she works on the rescue squad. How many hours did she work per week ?
39 hours; she works per week if the paramedic maintains a time card for hours she works on the rescue squad.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
A paramedic maintains a time card for the hours she works on the rescue squad shown in the table:
We can write a mixed fraction in a fraction:
6 1/2 = 13/2
8 1/2 = 33/2
7 3/4 = 31/4
8 1/12 = 97/12
8 5/12 = 101/12
Adding all the fractions:
[tex]=\rm \dfrac{13}{2}+\dfrac{33}{4}+\dfrac{31}{4}+\dfrac{97}{12}+\dfrac{101}{12}[/tex]
[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{97}{12}+\dfrac{101}{12}[/tex]
[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{198}{12}[/tex]
[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{33}{2}[/tex]
[tex]=23+\dfrac{64}{4}[/tex]
= 39 hours
Thus, 39 hours; she works per week if the paramedic maintains a time card for hours she works on the rescue squad.
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if the figure forms the base of a right solid 110 centimeters high, find the surface area
Answer:
60200 cm^2
Step-by-step explanation:
I believe I've answered this question on another post: https://brainly.com/question/27987703
please help! due very soon!
Answer:
{x | x = -6, -1, 0, 3}
(first option listed)
Step-by-step explanation:
The domain of a function is all possible x-values for that function
So, we can see (from the x-value portion of our table) that the possible x-values are:
-6 , -1, 0, and 3
We write domain and range in lowest - highest number value order, so we write our domain as such:
{x | x = -6, -1, 0, 3}
{range is all possible y-values, and this would include -7 , 1, 9, and -2}
hope this helps!!
A man wants to cut down a tree in his yard. To ensure that the tree doesn’t hit anything, he needs to know the height of the tree. He measures the distance from the tree at 14 m and the angle of elevation to the tree at 88°. What is the height of the tree to the nearest tenth of a meter
Answer:
400.9 m
Step-by-step explanation:
the answer to this asap please!
The required work done is 62400 J.
work done to lift a 1500 N object from the ground to the top of a 40 m building if the cable weighs 3 N per m
work done, is define as the product of force and displacement.
since,
work done to lift 1500N to height of 40 m is:
W= FS
= 1500 x 40 = 60000J
now work done for rope
is given by
w = mgΔx(40-x)
w= [tex]\int _0^{40}\left mg(40-x\right)dx[/tex]
w=[tex]3\int _0^{40}\left(40-x\right)dx[/tex]
w= 3[tex][40x-x^2/2]\left \{ {{40} \atop {0}} \right.[/tex]
w= 3[1600-800]
w = 2400
Total work done for lifting 1500N to 40m height
= 6000+2400=62400J
Thus the required work done to lift 1500N weight to 40m is 62400J.
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