Imagine that a single cell below goes through four cell divisions. How many cells are produced? To find out, draw the parent cell and cells present after each division. Then write the number of cells in the space below each drawing. (Hint: the number of cells doubles with each division.)

The concentration of sodium chloride in the solution is 5.72% (weight/volume percent).

Weight/volume percent concentration (w/v) expresses the amount of solute (in grams) dissolved in a given volume of solution (in milliliters). Specifically, it is defined as the weight of the solute divided by the volume of the solution, multiplied by 100.

To calculate the weight/volume percent concentration, we need to determine the mass of NaCl per volume of the solution.

First, we need to convert the volume of the solution from milliliters (mL) to liters (L):

67.8 mL = 0.0678 L

Next, we calculate the concentration of NaCl in grams per liter (g/L):

Concentration = Mass of solute ÷ Volume of solution

Concentration = 3.88 g ÷ 0.0678 L

Concentration = 57.2 g/L

Finally, we convert the concentration to weight/volume percent by multiplying by 100:

Weight/volume percent = Concentration x 100

Weight/volume percent = 57.2 g/L x 100

Weight/volume percent = 5.72%

Therefore, the concentration of NaCl in the solution is 5.72% (weight/volume percent).

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Answer:

I'm pretty sure the answer is C.

Copper-plating is a chemical change in which copper ions become neutral copper atoms by accepting electrons which then are deposited on the material to be coated.

copper-plating?Copper-plating is the process by which a layer of copper is used to coat another material using the process of electrolysis.

At the molecular level, copper ions in solution accept electrons to become neutral copper atoms which then are deposited on the material, thereby coating.

This is an example of a chemical change since it us not easily reversible and new products are formed.

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The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.

Fluorine Molecule's Speed = 442.4 m/s

The Molar Mass of the F₂ = 38 g/mol

Now as we know that any molecule's

1 mole contain  = 6.022 × 10²³ Molecule

So, 1 Fluorine molecule mass =

Fluorine's Molar mass / Number of Fluorine molecule in 1 mole

So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )

1 Fluorine molecule mass = 6.31 × 10⁻²³ g

1 Fluorine molecule mass = 6.31 × 10⁻²⁶  Kg

So molecule's momentum = Molecule's mass × Molecule's Velocity

So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4

So molecule's momentum = 2.8 × 10⁻²³  Kg.m/s

Now wavelength of Fluorine molecule = λ = planks constant / momentum

wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )

wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre

So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.

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Answer:

B.

Explanation:

customization requires more material, more machine time which can creates a greater impact on the environment in the sense of pollution (travel by the extra employees, creation of custom materials, increased machine running time). Good luck in your studies. Hope this answers your question in full.

The temperature scale required for gas law calculations is Kelvin , The temperature of the gas is 363 in Kelvin.

According to Gas law , for a unit mole of ideal gas the product of pressure to volume is equal to the product of Universal Gas Constant and Temperature.

it is written as

PV = RT

It is given that A reaction forms a gas at 90.4 °C.

The temperature scale required for gas law calculation is Kelvin

Temperature in Kelvin = Temperature in degree Celsius +273

Temperature in Kelvin = 90.4 +273

Temperature in Kelvin = 363 K

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Answer:

9.487 L

Explanation:

argon  mole wt = 39.948 gm/mole

             14.3 gm  / 39.948 gm/mole   = .357965 moles of argon

Use Ideal Gas Law:

PV = n RT     where   R = .082057  L-atm / K-mol

V =  .357965 * .082057 * 436 / 1.35  = 9.487 L

Answer:

= 64584.7176 g

or

= 64.5847 kg

Explanation:

From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.

We know that from Avogadro's constant,

1 mole of a substance contains 6.02 x 10²³ ions/atoms/units

Thus,

1 mole => 6.02 x 10²³ atoms

x moles=> 6.075 × 10²⁶ atoms

We cross multiply;

x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)

= 1009.1362 moles

1 mole of SO2 = 64 g

1009.1362 moles = ?

=>

[tex] \frac{1009.1362 \times 64}{1} [/tex]

= 64584.7176 g

= 64.5847 kg

Answer:31,631.04

Explanation: multiply final temp with initial temp = 42 then multiplied by grams = 7,560 then multiplied by J = 31,631.04

To convert Scientific Notation to a decimal number, Prescribed steps are to be taken given below.

Scientific notation is a way of writing very large or very small numbers.

A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.

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Answer:

Alcohol has considerable toxic effects on the digestive- and cardiovascular systems. Alcoholic beverages are classified as carcinogenic by the International Agency for Research on Cancer and increase the risk of several cancer types.

Explanation:

please mark me brainlist

Alcohol has a fire hazard symbol because it is extremely flammable and can create fires. Too be specific, ethanol alcohol is the flammable substance.

0.761 mol of [tex]C_7H_{16}[/tex]  would you have if you have 76.36 grams.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{76.36 grams}{100.21 g/mol}[/tex]

Moles = 0.761

Hence,  0.761 mol of  [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.

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To ensure data traceability and accessibility is to complete a study beginning-to-end on a closed system or platform.

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Answer:

44.01 g/mol

Explanation:

Carbon dioxide is produced when carbon and oxygen are burned.

To totally burn carbon into carbon dioxide, or CO2, we require one mole of oxygen for every gram of carbon by weight.

or alternatively:

You produce 12+216=44 g of carbon dioxide for every 12 g of carbon.

The weight of CO2 in kg may be calculated if the amount of CO2 in litres is known by converting it to moles and multiplying it by 44.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid [tex]CH_3CO_2H[/tex]  reacts with baking soda [tex]NaHCO_3[/tex] according to the equation:

[tex]CH_3CO_2H + NaHCO_3[/tex] → [tex]CH_3CO_2Na + CO_2 + H_2O[/tex]

1. Molar mass of [tex]NaHCO_3[/tex] is 23+1+12+16×3 = 84 g/mol

= [tex]\frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]

= [tex]\frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]

=0.29 mol [tex]NaHCO_3[/tex]

2. From the balanced equation we see that 1 mole of [tex]NaHCO_3[/tex] reacts with 1 mole of [tex]CH_3CO_2H[/tex] , then 0.29 moles of [tex]NaHCO_3[/tex] react with 0.29 moles of [tex]CH_3CO_2H[/tex].

3. Mass of 1 mole of [tex]CH_3CO_2H[/tex] is 12+ 1×3+12+16×2=60 g/mol

= [tex]\frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}[/tex]

[tex]=17.4 g CH_3CO_2H[/tex]

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g [tex]CH_3CO_2H[/tex] is very close to 17.4 g [tex]CH_3CO_2H[/tex]. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

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Answer:

a.) increase

c.) collide more often with other reactant molecules

Explanation:

Generally, when you increase the quantity of reactants, the rate of the reaction increases (the forward reaction). When there are more reactants, there are more chances for them to interact with each other. More interactions means more reactions.

I predict that using a larger amount of calcium chloride powder will increase the reaction rate because the calcium chloride molecules will collide more often with other reactant molecules.

It becomes fair to assume that the reaction rate would increase when Jon increases the quantity of calcium chloride (CaCl2) powder utilised in the chemical reaction with sodium bicarbonate (NaHCO3).

This is due to the fact that adding more calcium chloride powder to the reaction mixture will add more CaCl2 molecules.

There will be more collisions between CaCl2 and NaHCO3 molecules due to the larger concentration of CaCl2 molecules. Successful collisions between reactant molecules are essential for the production of products in a chemical reaction.

Therefore, a greater reaction rate will result from more CaCl2 and NaHCO3 molecules colliding often. The additional molecules contribute to a higher number of energetic collisions, where the reactant particles possess sufficient energy to overcome the activation energy barrier and undergo the reaction.

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The empirical formula for a compound composed of 0.0683 mol of carbon ( C ), 0.0341 mol of hydrogen ( H ), and 0.1024 mol of nitrogen ( N ) is  [tex]C_2HN_3[/tex].

An empirical formula tells us the relative ratios of different atoms in a compound.

Given data:

Moles of carbon = 0.0683 mol

Moles of hydrogen = 0.0341 mol

Moles of nitrogen = 0.1024 mol

Dividing each mole using the smallest number that is divided by 0.0341 moles.

We get:

Carbon= 2

Hydrogen=1

Nitrogen=3

The empirical formula for a compound is[tex]C_2HN_3[/tex].

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The following is an insoluble compound that is likely to be produced by the reaction below CaSO4 + PbI- CaI + PbSO4. The PbSO4 will be insoluble as The sulfates are insoluble in water besides for the sulfates of calcium, barium, mercury, and lead.

Lead sulphate ($PbS$) is insoluble in water due to the fact water's dipole electricity is simply too vulnerable to shy away the ions (each anion and cations) from the sturdy crystals of lead sulphate.Lead sulfate seems as a white crystalline solid. Insoluble in water and sinks in water. Contact might also additionally aggravate skin, eyes, and mucous membrane.

Thus, PbSO4 is insoluble. In PbSO4 , the electricity of the dipole is vulnerable to interrupting the anionic and cationic bond. So, PbSO4 stays insoluble in solution.

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Answer:

1.57

Explanation:

moles = mass / molar mass

moles = 69 / 44.013

moles = 1.57

moles N₂O = 69 : 44 g/mol = 1.568

N₂O : 2 moles N, 1 mole O

moles N = 1.568 x 2 = 3.136

0.342 x [tex]10^(^1^6^)[/tex])  photons are required to emit 1 joule of energy.

A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.

We need to find the number of photons emitted per second.

So we have E = hc ÷ λ

= (6.6 x [tex]10^-(^3^4^)[/tex]x 3 x [tex]10^8[/tex] m/s) ÷ 6.78 x [tex]10^(^-^7^)[/tex]nm

= 2.92 x [tex]10^(^-^1^9^)[/tex]Joules

Now number of photons per second = I / E (I = intensity)

= 1 x [tex]10^(^-^3^)[/tex] joule / sec ÷ 2.92 x [tex]10^(^-^1^9^)[/tex]joule

= 0.342 x[tex]10^(^1^6^)[/tex]

Hence, 0.342 x [tex]10^(^1^6^)[/tex])  photons are required to emit 1 joule of energy.

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Answer:

Both metals and non-metals when burnt in oxygen form their oxides. Oxides of metals are basic in nature and oxides of non-metals are acidic in nature.

Answer:

An open system is :-

B. A system that allows energy and mass to move in and out of it.

Example :-

Water boiling in a pot on a stove. (Without lid).

Answer:

0.12 M

Explanation:

To find the new concentration, you need to (1) find the moles of Solution A (via the molarity equation), then (2) find the moles of Solution B, then (3) combine all of the moles and volumes, and then (4) calculate the new molarity. The final answer should have 2 sig figs to reflect the lowest amount of sig figs in the given values.

Solution A:

7.7 mL / 1,000 = 0.0077 L

Molarity = moles / volume

0.10 M = moles / 0.0077 L

0.00077 = moles

Solution B:

18.3 mL / 1,000 = 0.0183 L

Molarity = moles / volume

0.20 M = moles / 0.0183 L

0.00366 = moles

New Solution:

11.7 mL / 1,000 = 0.0117 L

New Volume = 0.0077 L + 0.0183 L + 0.0117 L

New Volume = 0.0377 L

New Moles = 0.00077 moles + 0.00366 moles

New Moles = 0.00443 moles

Molarity = moles / volume

Molarity = 0.0043 moles / 0.0377 L

Molarity = 0.1175 M = 0.12 M

Answer: Decide whether they have designed the best possible product.

11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex]  gas measured at 1.3 atm pressure and 298 K

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

Moles = 0.3588 moles

Now,

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.3588 moles = \frac{mass}{32}[/tex]

Mass= 11.48 gram

Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K

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Mendeleev positioned elements in the periodic table in increasing order of their atomic numbers, such that elements having identical chemical properties and characteristics plunge into the same group.

Mendeleev's periodic table may be defined as a collection of elements in an increasing atomic mass hierarchy in a table arrangement, such that it reminisces resemblances and manias according to their chemical properties and characteristics.

Mendeleev found that two elements existed between atomic weights 65.2 and 75 because he comprehended especially pleasingly that the possessions of the elements were more comparable and closer to this degree.

He also anticipated having other elements that would have their possessions comparable to these other elements.

Therefore, he departed a void for these two elements in the periodic table until they were ultimately found in their real existence.

The complete question is as follows:

Look at the two question marks between zinc (Zn) and arsenic (As). At the time, no elements were known with atomic weights between 65.2 and 75. But Mendeleev predicted that two elements must exist with atomic weights in this range. What led Mendeleev to predict that two undiscovered elements existed in that range?

Therefore, it is well described above.

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Answer:

b

Explanation:

D. A change in a substance with no new substances being formed

There are 2 ways a substance can change, physical changes and chemical changes. In all changes, physical or chemical, mass is always conserved.

Physical vs. Chemical

The main difference between a physical and chemical change is the substance at the end.

New substances are only created by chemical changes. Additionally, only chemical changes break apart bonds. Physical changes maintain the same compounds and elements, so bonds are not broken.

Examples of Physical Changes

Physical changes do not change the actual substance, but they can change the form of the substance.

All of these change the state of matter or shape of the substance, but not the chemical makeup.

Answer:

Explanation:

Mining:

    Mining is when certain substances are removed from the Earth, usually in large quantities. Mining can occur below the surface of the Earth via tunnels and caves. It can also occur at surface level through methods such as strip mining, which removes huge amounts of soil in the process