Gravitational force between two cars are 2.92 × 10 ⁻¹¹ Nm²/kg.
The universal force of attraction happened between two objects is called as gravitational force.
The mass of the two cars, m₁ = 2565 kg
m₂ = 4264 kg
r = 5m
G = 6.67 ₓ 10 ⁻11 Nm²/kg
How gravitational force can be calculated?
Definition of gravitational force: The force of attraction between any two bodies is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
F ∝ m₁ m₂ ÷ r²
where the force exerted between the two masses m₁ and m₂,
F = G (m₁ m₂) ÷ r²
where as, F - Gravitational force between two bodies,
G - Gravitational constant,
m₁ - mass of the first body,
m₂ - mass of the second body,
r² - square of the distance between two bodies.
F= 6.67 × 10⁻¹¹ Nm²/kg ( 2565 kg × 4264 kg) ÷ ( 5²)
Hence,
F = 2.92 × 10⁻⁵ N
Option D is correct answer.
Learn more about Newton's law of Gravitation,
https://brainly.com/question/9373839
#SPJ5
engine oil reduces friction between the moving parts in in a car energy by
a.) cooling the engine
b.) making the parts sticky so that they move more slowly.
c.) making the parts slippery
d.) two of the above
Answer: C, making the parts slippery
Explanation: I chose d and it said it was wrong so I chose C and it was right lol
a phosphorus atom needs to gain ---electrons to achieve a full octet
Answer:
Three (3).
Explanation:
The octet rule is a rule in chemistry that states that, chemical elements would either gain or loss electrons in their outermost shell in order to attain a stable electronic configuration i.e having eight (8) valence electrons in their outermost shell such as chemical elements found in group 8 (2-8-8) known as noble gas.
A phosphorus atom needs to gain three (3) electrons to achieve a full octet because the atomic number of phosphorus is 15 and as such it has the electronic configuration of 2-8-5 and needs three electron in order to become a stable element.
Four rods that obey Hooke's law are each put under tension. (a) A rod 50.0 cm50.0 cm long with cross-sectional area 1.00 mm21.00 mm2 and with a 200 N200 N force applied on each end. (b) A rod 25.0 cm25.0 cm long with cross-sectional area 1.00 mm21.00 mm2 and with a 200 N200 N force applied on each end. (c) A rod 20.0 cm20.0 cm long with cross-sectional area 2.00 mm22.00 mm2 and with a 100 N100 N force applied on each end. Order the rods according to the tensile stress on each rod, from smallest to largest.
Answer:
c < a = b
Explanation:
The tensile stress = Force applied/(Cross sectional area)
(a) The applied force = 200 N
The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²
The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa
(b) The applied force = 200 N
The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²
The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa
(c) The applied force = 100 N
The cross sectional area = 2.00 mm² = 2 × 10⁻⁶ m²
The tensile stress = 100 N/(2 × 10⁻⁶ m²) = 50,000,000 Pa = 50 MPa
Therefore, the tensile stress from smallest to largest are;
(a) 50 MPa, < (b) 200 MPa = (a) 200 MPa
Therefore, we have;
c < a = b.
Two forces are applied to a 3 Okg block on a
frictionless horizontal surface, as shown in the
diagram below
Fi=25N
F2=10N
The acceleration of the block is
5.0 m/s2 to the left
2.0 m/s2 to the right
O 5.0 m/s2 to the left
6.0 m/s2 to the right
Next
Answer:
daaang i aint this smart :(
Explanation:
Answer:
The 5.0 One
Explanation:
I had this on a test and I guessed correctly
What is his average acceleration from 10 to 20 seconds
Answer:-2.0
Explanation:khan academy
a 32kg object has a momentum of 480kg m/s northward. what is the objects velocity ?
Answer:
velocity = 15m/s
Explanation:
momentum of the object = 480kg/ms
nass of object = 32 kg
velocity of object = ?
momentum = velocity × mass
velocity = momentum / velocity
= 480kg/ms/32kg
= 15m/s
Part of my other question!
I cant see the numbers but to find them heres an example 17 n would be at the top next to 15 and 20 if there on there and them you find the other number 105 w I think would be on the left then draw a straight line till they touch and wherever it is will be you answer and if you need further help search it up on here or google
Explanation:
ok so start on the latitude which is the lines that go left to right. it would be the first number in the parentheses.(latitude,longitude) so if the number is 17°North you would look on the right side of the map and find 17°N. It might show y 15°N so you have to try and find where you think 17°N would be. place you finger where you think 17°N is. then find 105°West which is longitude and is the lines that go up and down. and drag you fingers together in a straight line until they both meet and that is where the awnser is.
hope u understand
23. Explain how the particles move before, during, and after melting.
Answer:
Answer: Option (D) is the correct answer.
Explanation:
Before placing the spoon in a hot liquid, particles of spoon were closer to each other and vibrating at their respective positions.
But when the spoon is placed in a hot liquid then due to increase in temperature of spoon its particles gain kinetic energy. Therefore, they colloid more frequently.
Thus, we can conclude that switch the labels on the diagrams best explains how to correct Alana’s error.
A roller coaster accelerates from 0 m/s to 25 m/s in 5 seconds. Determine the acceleration of the roller coaster.
The phases of the moon occur because the moon revolves around the earth.
True
False
an automobile was moving at 15m/s and accelerated at 2m/s^2 for 10s. what is the final speed
Answer:
35 m/s
Explanation:
Given that an automobile was moving at 15m/s and accelerated at 2m/s^2 for 10s. what is the final speed ?
The parameters given are :
initial velocity U = 15 m/s
Acceleration a = 2 m/s^2
Time taken = 10s
Using first equation of motion;
V = U + at
V = 15 + 2 * 10
V = 15 + 20
V = 35 m/s
Therefore, The final speed is 35 m/s
The final speed of automobile moving at the given initial speed and acceleration is 35m/s.
Given the data in the question;
Initial velocity of the automobile; [tex]u = 15m/s[/tex]Acceleration of the automobile; [tex]a = 2m/s^2[/tex]Time taken; [tex]t = 10s[/tex]Final velocity of the automobile; [tex]v = ?[/tex]
To determine the final velocity of the automobile, we use the First Equation of Motion:
[tex]v = u + at[/tex]
Where v is final velocity, u is initial velocity, a is acceleration and t is time taken.
We substitute our given values into the equation
[tex]v = 15m/s + [ 2m/s^2 * 10s ]\\\\v = 15m/s + 20m/s\\\\v = 35m/s[/tex]
Therefore, the final speed of automobile moving at the given initial speed and acceleration is 35m/s.
Learn more on Equations of Motion here: https://brainly.com/question/20638167
The speed of an object at a particular point during travel is called
Out of these people who r ur favs?
WilburSoot
TommyInnit
Tubbo
Fundy
Sapnap
Dream
GeorgeNotFound
Quackity
Jschalt
Nikki
Ponk
Skeppy
BBH
Punz
aweSAMedude
HiBomb
TechnoBlade
Answer:
Is it a sin to like them all...? haha
Answer:
Schlatt, Nikki, Tubbo, and Wilbur :O
Explanation:
how is this a question lol-
Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.
Civil Engineers
Carpenters
Landscapers
Plumbers
Surveyors
Civil Drafters
Answer:
A,B,D,E,F
Explanation:
i took the test
Answer: A, B, D, and F all fit the description of professionals in the
Architecture and Construction career cluster
Explanation: Hope this helps!
What happens to the sound an object makes when the speed of vibrtions decreases (slowdown?)
Answer:
the volume increase
Explanation:
because because when the speed of the vibrations decrease the speech of the sounds become loud
The MSDS for chloroform indicates that it is a clear liquid that has a pleasant smell and substantial vapor pressure. People should avoid inhaling its vapors, and it is sensitive to light. Malik needs 10 mls of chloroform for an experiment.
According to this information, how should he safely pour the chloroform?
He should locate the chloroform stored in a transparent container in chemical storage and pour directly into his beaker from that location.
He should locate the chloroform stored in a transparent container in chemical storage and should take it to the fume hood to pour.
He should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour.
He should locate the chloroform stored in a dark container in chemical storage and pour directly into his beaker from that location.
Answer:
The correct option is the third option
Explanation:
Firstly, it must be noted that chemicals/reagents that are sensitive to sunlight are stored in dark/amber container in the laboratory. Hence, the chloroform can only be found in an amber/dark bottle.
Also, reagents/chemicals that release poisonous/offensive gases are handled in the fume cupboard in the laboratory. Thus, If Malik is going to pour the chloroform, he should pour it in a fume cupboard to avoid inhaling it because of the toxicity of it's vapor.
From the above explanation, it can be deduced that Malik should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour.
Answer:
He should locate the chloroform stored in a dark container in chemical storage and should take it to the fume hood to pour.
Explanation:
PLEASE HELP! HURRY. ALMOST OUT OF TIME
Answer:
balanced hurry up fam
gurry hurry hurry
I need help with this physics question
A cannonball with a mass of 50 kilograms and a golf ball with a mass of 0. 8 kilograms are dropped in a vacuum from a height of 10 meters. Compare the acceleration of each object as they fall.
It's gonna take a huge amount of time and effort, and we're gonna spend a huge amount of money, to build a vacuum chamber big enough to do this experiment.
So when we're finally ready to try it, the cannonball and golf ball will make a kind of cute experiment, but let's make it really interesting. Let's ALSO try it with a feather, an apple, a watermelon, a tennis ball, a basketball, a coffeepot, a chair, an old computer, a set of dishes, a trombone, a bicycle, a math book, a TV set, a gallon of milk, a skateboard, a shotgun, a concrete block, a car, a waterbed, a schoolbus, a battleship, your dog, and my wife !
Drop every single one of them from a height of 10 meters.
Every single one of them accelerates at 9.8 m/s² as it falls, takes 1.429 seconds to reach the floor, and hits the floor at a speed of 14 m/s. The feather, the schoolbus, and my wife stay together all the way down.
The only way this doesn't happen is if ...
-- you do this experiment in some other place that's not Earth, or
-- you throw one of the objects and you don't just drop it, or
-- the vacuum chamber has a leak and some air gets into it.
Because that's how gravity works.
Jack bought 8 boxes of soda. how many cans did he buy if each box holds 34 cans?
Answer:
272
Explanation:
hope this helps you!!!
The level of toluene (a flammable hydrocarbon) in a storage tank may fluctuate between 10 and 400 cm from the top of the tank. since it is impossible to see inside the tank, an open-end manometer with water or mercury as the manometer fluid is to be used to determine the toluene level. one leg of the manometer is attached to the tank 500 cm from the top. a nitrogen blanket at atmospheric pressure is maintained over the tank contents. felder, richard m.; rousseau, ronald w.; bullard, lisa g.. elementary principles of chemical processes, 4th edition (page 81). wiley. kindle edition.
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
When water is used the reading is [tex] R = 2281.6 \ cm [/tex]
When mercury is used the reading is [tex] R = 23.83 \ cm [/tex]
The best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
Explanation:
From the question we are told that
The length of the leg of the manometer to the top of the tank is d = 500cm
The toluene level where in the tank where the height of the manometer fluid level in the open arm is equal to the height where the manometer is connected to the tank is h =150 cm
The manometer reading is R
Generally at the point where the height of the open arm is equal to the height of the of the point connected to the tank ,
The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal
i.e [tex]P_1 = P_2[/tex]
Here [tex]P_1[/tex] is the pressure of the manometer at the point corresponding to the base of the tank and this is mathematically represented as
[tex] P_{atm} + P_1 = P_{atm} + P_t[/tex]
Here [tex]P_t[/tex] is the pressure due to the toluene level in the tank and in the arm of the manometer connected to the tank and this is mathematically represented as
[tex]P_t = \rho_t * g * h_i[/tex]
Here
[tex]\rho_t [/tex] is the density of toluene with value [tex]\rho_t = 867 kg/m^3 [/tex]
[tex]h_i[/tex] is the height of the connected arm above the point equivalent to the base of the tank , this mathematically represented as
[tex]h_i = d - h + R[/tex]
and [tex] P_2 [/tex] is the the pressure at the open arm of the manometer at the point equivalent to the base of the base of the tank and this is mathematically represented as
[tex] P_2 = \rho_f * g * h_f [/tex]
Here
[tex]\rho_f[/tex] is the density of the fluid in use , if it is water the density is
[tex]\rho_w = 1000 \ kg /m^3 [/tex]
and if it is mercury the density is
[tex]\rho_m = 13600 \ kg /m^3 [/tex]
[tex]h_f[/tex] is the height of the fluid in the open arm of the manometer from the point equivalent to the base of the tank which is equivalent the manometer reading R
So when the fluid is water we have
[tex] P_{atm} + \rho_t* g *(d - h + R) = P_{atm} + \rho_f * g * h_f[/tex]
=> [tex] \rho_t* (d - h + R) = \rho_w * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 1000 * R [/tex]
=> [tex] R = 2281.6 \ cm [/tex]
So when the fluid is mercury we have
[tex] \rho_t* (d - h + R) = \rho_m * h_f[/tex]
=> [tex] 867 (500 - 150 + R) = 13600 * R [/tex]
=> [tex] R = 23.83 \ cm [/tex]
The difference in the mercury reading for mercury due to the fact that they have different densities as we have seen in this calculation
So the best fluid to use is mercury because for water a slight change in toluene level will cause a large change in height .
What is the current in the 30.0 o resistor?
2.00A
32.0A
4.00A
30.0A
Answer:
4.00 A
Explanation:
An inclined plane of length 12m is used to pull a load of 3000N to height of 3m by applying an effort of 1000N. Calculate its MA, VR and efficiency. Also, find the work done in the machine
Answer:
MA = 4
VR = 3
e = 0.75 or 75%
work = 12000 [J]
Explanation:
The mechanical advantage in an inclined plane is defined as the relationship between the length of the inclined plane and the height of the plane with respect to the ground.
MA = L/h
MA = 12/3 = 4
Now the real advantage can be calculated as the relationship between the weight of the body and the force being applied.
VR = W/F
VR = 3000/1000
VR = 3
Efficiency can be calculated as the relationship between the real mechanical advantage over the ideal mechanical advantage.
e = VR/MA
e = 3/4
e = 0.75 or 75%
The work is defined as the product of the force by the distance, therefore we have:
work = F*d
work = 1000*12
work = 12000 [J]
difinition of gravity
Answer:
it's all around you and it can't be destroyed
I’m so confused I don’t get what I have to put in
Answer:
inner planets are the first couple of planets by the sun so for the character for the internal planets are what they are like are they made up of gas, rock/solid stuff and the atomsphere is like is it toxic or safe to breath
what are some solutions to global temperature changes?
help asap
Answer:
Power your home with renewable energy.
Weatherize, weatherize, weatherize.
Invest in energy-efficient appliances.
Reduce water waste.
Actually eat the food you buy—and make less of it meat.
Explanation:
A go kart is traveling at a constant 13.8 meters per second around a horizontal circular track with a radius of 42.0 meters. The Combined mass of a go kart and the driver is 143 kg. What is the magnitude of the centripetal force acting on the combined mass
Answer:
648.40N
Explanation:
Centripetal acceleration is the acceleration of an object around a circular path. Centripetal for e acting on the combined mass is expressed as:
F = ma
F = mv²/r
m is the mass of the object = 143kg
v is the linear velocity = 13.8m/s
r is the radius = 42.0m
Substitute the given parameters into the formula;
F = 143*13.8²/42
F = 27,232.92/42
F = 648.40N
Hence the magnitude of the centripetal force acting on the combined mass is 648.40N
(ii)
Calculate the amount of energy required to melt 15 kg of ice at 0 °C.
Specific latent heat of fusion of ice = 3.4 x 10J/kg.
why can voyager 1 maintain its speed?
Answer:
based on my opinion
The smart guys at NASA designed the trajectory such that as they passed Jupiter, they gained some speed by being dragged along by Jupiter
This is called a gravity assist . Voyager 2 picked up about 18 km / s of velocity from that Jupiter gravity assist ...
Hope this helps
How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr^2
Answer:
8.8 hours
Explanation:
plz give me a Brainliest
