If the total cost of a $32 item is $33.60, what is the total cost on a $55 item?

Answer:

angle 7

Step-by-step explanation:

Answer:

angle 7 angle forms a pair of alternate

exterior angles with angle 2.

Answer:

Step-by-step explanation:

look at graph for answers, vertex is at the point

Answer:

B) 256

Step-by-step explanation:

w = 4

l = 12

h = 5

Formula:

SA = 2(wl + hl + hw)

SA = 2(4*12 + 5*12 + 5*4)

SA = 2(48 + 60 + 20)

SA = 2(128)

SA = 256

There are 80 Crayons.

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

The number of crayons in a box is forty less than twice the number of markers.

let the number of markers be x.

So, Number of Crayons = 2x- 40

and, there are 140 coloring tools.

x+ 2x- 40= 140

3x = 180

x= 60

So, Number of Crayons = 2(60) - 40 = 120- 40= 80

Hence, there are 80 Crayons.

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Answer:

a. A point estimate of the mean pull-force of all connectors in the population is approximately 75.7385

The point estimate for the mean used is the sample mean

b. The point estimate of the pull force that separates the weakest 50% of the connectors from the strongest 50% is 74.3131 N

c. The point estimate of the population variance is approximately 2.8577

The point estimate for the population standard deviation is approximately 1.6905

d. The standard error of the mean is approximately 0.3315

e. The point estimate of a proportion of the connectors are;

(72.7, 0.0385) , (73.8, 0.0769) , (73.9, 0.0385) , (74, 0.0385) , (74.1, 0.0385) ,(74.2, 0.0385),  (74.6, 0.0385) , (74.7, 0.0385) , (74.9, 0.0385) , (75.1, 0.0769) , (75.3, 0.0385) , (75.4, 0.0385) , (75.5, 0.0385) , (75.6, 0.0385) , (75.8, 0.0385) , (76.2, 0.0385) , (76.3, 0.0385) , (76.8, 0.0385) , (77.3, 0.0385) , (77.6, 0.0385) , (78, 0.0385) , (78.1, 0.0385) , (78.2, 0.0385) , (79.6, 0.0385)

Step-by-step explanation:

The given data for the pull-force (pounds) for connectors used in an automobile engine are presented as follows;

Pull-force (pounds); 79.6, 75.1, 78.2, 74.1, 73.9, 75.6, 77.6, 77.3, 73.8, 74.6, 75.5, 74.0, 74.7, 75.8, 72.7, 73.8, 74.2, 78.1, 75.4, 76.3, 75.3, 76.2, 74.9, 78.0, 75.1, 76.8

a. A point estimate of the mean pull-force of all connectors in the population is the sample mean given as follows;

[tex]Mean, \ \overline x = \dfrac{\Sigma x_i}{n}[/tex]

[tex]\Sigma x_i[/tex] = The sum of the data = 1966.6

n = The sample size = 26

Therefore, the sample mean, [tex]\overline x[/tex] = 1966.6/26 ≈ 75.7385

The point estimate for the mean is approximately 75.7385

The sample mean was used as the point estimate for the mean because it is simple and representative of the sample

b. The weakest 50% of the connectors are;

72.7, 73.8, 73.8, 73.9, 74, 74.1, 74.2, 74.6, 74.7, 74.9, 75.1, 75.1, 75.3

The sum of forces that separates the weakest 50%, [tex]\Sigma x_{i}_{50 \%}[/tex]  = 966.2

The point estimate of the pull force that separates the weakest 50% of the connectors from the strongest 50% = [tex]\Sigma x_{i}_{50 \%}[/tex]/13 = 966.2/13 = 74.3131 N

c. The estimate of the population variance is the sample variance, given as follows;

[tex]s^2 =\dfrac{\sum \left (x_i-\overline x \right )^{2} }{n - 1}}[/tex]

Where;

[tex]{\sum \left (x_i-\overline x \right )^{2} }[/tex] ≈ 71.4415

Therefore;

[tex]s^2 =\dfrac{71.4415 }{25}} \approx 2.8577[/tex]

The point estimate of the population variance, s², is 2.8577

The point estimate for the population standard deviation, σ, is tha sample standard deviation, 's', given as follows;

s = √s² = √2.8577 ≈ 1.6905

The point estimate for the population standard deviation ≈ 1.6905

d. The standard error of the mean is given as follows;

[tex]SE_{\mu_x} = \dfrac{s}{\sqrt{n} }[/tex]

Therefore, we have;

[tex]SE_{\mu_x}[/tex] = 1.6905/√(26) ≈ 0.3315

The standard error indicates the likely hood of the difference between the sample mean and the population mean

e. The point estimate of a proportion of the connectors are;

(Number of sample with a given pull-force value)/(Sample size (26))

Therefore, using Microsoft Excel, we have

(72.7, 0.0385) , (73.8, 0.0769) , (73.9, 0.0385) , (74, 0.0385) , (74.1, 0.0385) ,(74.2, 0.0385),  (74.6, 0.0385) , (74.7, 0.0385) , (74.9, 0.0385) , (75.1, 0.0769) , (75.3, 0.0385) , (75.4, 0.0385) , (75.5, 0.0385) , (75.6, 0.0385) , (75.8, 0.0385) , (76.2, 0.0385) , (76.3, 0.0385) , (76.8, 0.0385) , (77.3, 0.0385) , (77.6, 0.0385) , (78, 0.0385) , (78.1, 0.0385) , (78.2, 0.0385) , (79.6, 0.0385)

Answer:

True

True

True

False

Step-by-step explanation:

15/18 simplified is 5/6

3/5 multiply both numerator and denominator by 20 to get 60/100

20/14 simplified is 10/7

4/13 multiply both by 2.5 to get 10/32.5 and 32.5 does not equal 32

Answer:

Step-by-step explanation:

[tex]\frac{5}{6}=\frac{15}{18}[/tex]

Cross multiply

5 *18 = 15 *6

90  = 90

True. They are in proportion

[tex]\frac{3}{5}=\frac{60}{100}[/tex]

Cross multiply

3*100 = 60 *5

300   = 300

True. They are in proportion

[tex]\frac{20}{14}=\frac{10}{7}[/tex]

Cross multiply

20*7 = 10*14

140  = 140

True. They are in proportion

[tex]\frac{4}{13}=\frac{10}{32}[/tex]

Cross multiply

4*32  = 10*13

128    ≠ 130

False. They are NOT in proportion

Answer:

UQ = 185

Step-by-step explanation:

the median separates the data set into the lower quartile and upper quartile

The median of this data set is 151

The lower quartile is the median of the lowest five values, or 132

The upper quartile is the median of the highest five values, or 185

The upper quartile score for highest half of the score is 185.

A median is the center value of a given list of observations when arranged in an order. The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average.

For the given situation,

Xavier's bowling scores: 132, 140, 130, 190, 112, 200, 185, 172, 163, 151, 149.

Arrange this scores in the ascending order to find the median.

⇒ [tex]112, 130, 132, 140, 149, 151, 163, 172, 185, 190, 200[/tex].

There are totally 11 scores.

So the median is middle most number, that is 5th score in the list.

The median is [tex]151[/tex].

The scores after 151 are highest half scores. Now there are five scores.

Upper quartile scores list are [tex]163,172,185,190,200[/tex].

Thus, the middle most score [tex]185[/tex] is the upper quartile score.

Hence we can conclude that the upper quartile score for highest half of the score is 185.

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Answer:

For people that are doing this lesson on I-Ready

The points Lie on a straight line that goes through the origin.

The graph shows a relationship that is Proportional.

Step-by-step explanation:

Answer:

Step-by-step explanation:

lie on

goes

Answer:

i

Step-by-step explanation:

dontkow

Answer:

Sample Space = {(OSI), (OSH), (OEI), (OEH), (MSI), (MSH), (MEI), (MEH)}

Step-by-step explanation:

Given

Salad                               Meats                      Dressings

O = Olives                     S = Shrimp                 I = Italian  

M = Mushroom              E = Egg                     H = Honey mustard

To determine the sample space, we simply select one from each column.

Take for instance, a combination of Olives, Shrimp and Italian will be represented as: OSI

So, the following sample space exists:

Sample Space = {(OSI), (OSH), (OEI), (OEH), (MSI), (MSH), (MEI), (MEH)}

Answer:

8

Step-by-step explanation:

4x=32

÷4 ÷4

__________

x=8

Answer:

i need the picture to answer the question, sorry. but if you give me the picture im happy to answer it

Step-by-step explanation:

Answer:

height = 20 km

Step-by-step explanation:

Area of a trapezoid = (base + base / 2) x height

180 km^2 = (4 + 14 / 2) x height

180 km^2 = (18 / 2) x height

180 km^2 = 9 x height

height = 20 km

(fill in the numbers and work backwards)

Answer:

59°

Step-by-step explanation:

a+16+a-18=180

2a-2=180

2a=182

a=91

n=91+16=107

m=91+30=121

l=91-18=73

107+121+73=301

K=360-301=59

Answer:

.30

Step-by-step explanation:

Answer:

$78.24

Step-by-step explanation:

monomial

Step-by-step explanation:

k2 is a monomial because having only one element is monomial

Step-by-step explanation:

first change meter to centimeters

2.5×100= 250

60+35+90=185

250 - 185= 65cm

65 is the final answer

meter to centimeters

2.5×100= 250

60+35+90=185

250 - 185= 65cm

= 65cm

Pleeease mark brainliest (it would make me super happy :))

Answer:

See uploaded image

Step-by-step explanation:

The 3 right angles are WZY, YZX, and WYX. Sides WX, YW, and YX are similar on their respective similar triangles

Answer:

[tex]CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}[/tex]

Step-by-step explanation:

Given

[tex]n = 200[/tex]

[tex]x_1 = 34[/tex] -- City C

[tex]x_2 = 54[/tex] --- City K

Required

Determine the 90% confidence interval

This is calculated using:

[tex]CI = \bar x \± z\frac{\sigma}{\sqrt n}[/tex]

Calculating [tex]\bar x[/tex]

[tex]\bar x = \bar x_1 - \bar x_2[/tex]

[tex]\bar x = \frac{x_1}{n} - \frac{x_2}{n}[/tex]

[tex]\bar x = \frac{34}{200} - \frac{54}{200}[/tex]

[tex]\bar x = 0.17 - 0.27[/tex]

For a 90% confidence level, the ​z-score is 1.65.  So:

[tex]z = 1.65[/tex]

Calculating the standard deviation [tex]\sigma[/tex]

[tex]\sigma = \sqrt{(\bar x_1)*(1 - \bar x_1) + (\bar x_2)*(1 - \bar x_2) }[/tex]

So:

[tex]\sigma = \sqrt{(0.17)*(1 - 0.17) + (0.27)*(1 - 0.27) }[/tex]

[tex]\sigma = \sqrt{(0.17)*(0.83) + (0.27)*(0.73)}[/tex]

So:

[tex]CI = (0.17 - 0.27)\± 1.65\frac{\sqrt{(0.17)*(0.83) + (0.27)*(0.73)}}{\sqrt {200}}[/tex]

[tex]CI = (0.17 - 0.27)\± 1.65\sqrt{\frac{(0.17)*(0.83) + (0.27)*(0.73)}{200}}[/tex]

AB = BD = 10cm

Now using the Pythagorean theorem:

26^2 = 10^2 + BC^2

Simplify:

676 = 100 + BC^2

Subtract 100 from both sides:

576 = BC^2

Take the square root of both sides:

BC - sqrt(576)

BC  =  24 cm

Answer:

a. Linear pair theorem

b. x = 40

Step-by-step explanation:

a. x° and (4x - 20)° are angles on a straight line, so, they are a linear pair. Therefore, we would apply the linear pair theorem, which says the sum of a linear pair gives us 180°.

b. x° + (4x - 20)° = 180° (linear pair theorem)

Solve for x

x + 4x - 20 = 180

5x - 20 + 20 = 180 + 20

5x = 200

5x/5 = 200/5

x = 40

Answer:

hhhhhh

Step-by-step explanation:

i think it is 40

9514 1404 393

Answer:

  A) The angles marked ∠7 and ∠8 are vertical angles.

  B) The angles marked with expressions in y are also vertical angles, so those expressions are equal to each other. Stating this in equation form gives an equation that can be solved for y.

  C) y = 24; ∠7 = ∠8 = 89°

Step-by-step explanation:

A) The angles marked ∠7 and ∠8 are vertical angles, comprised of opposite rays and having a common vertex.

__

B) The angles marked with expressions in y are also vertical angles. Vertical angles are congruent, so those expressions are equal to each other. Stating this in equation form gives an equation that can be solved for y.

__

C) (5y-29)° = (3y+19)°

  2y = 48 . . . . . . . . . . . . divide by °, add 29-3y

  y = 24 . . . . . . . . . divide by 2

Angles 7 and 8 are supplementary to the angles marked with expressions in y.

  ∠7 = ∠8 = 180° -(5y -29)° = 209° -5(24)°

  ∠7 = ∠8 = 89°

Hey! I dont know if this will help though

To solve this question, you must first add together the two halves of the ratio i.e. 4 + 2 = 6. Then you need to divide the total amount using that number i.e. 600/6 = 100. To work out how much each person gets, you then multiply their share by 100.

Answer:

sin(a−28)=cos(4)

sin(a−28)=−0.653644

Step-by-step explanation:

Answer:

x3+2x2-17x+6.

Step-by-step explanation:

(x2+5x-2)(x-3)

= x(x2+5x-2)-3(x2+5x-2)

= x3 +5x2-2x-3x2-15x+6

Simplifying like terms:

= x3+2x2-17x+6

9514 1404 393

Answer:

  B.  f(x) → 1

Step-by-step explanation:

When x is very large, the only terms that matter are the ones of highest degree. That ratio is ...

  f(x) = x^2/x^2 = 1

The function value approaches 1 for very large x.