Answer:
The new force is 16 times of the initial force.
Explanation:
The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If the distance is halved, d' =d/2 and charges are doubles, [tex]q_1'=2q_1\ \text{and}\ q_2'=2q_2[/tex]
New force becomes,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\F'=\dfrac{k(2q_1)(2q_2)}{(d/2)^2}\\\\F'=16\times \dfrac{kq_1q_2}{r^2}\\\\F'=16F[/tex]
So, the new force is 16 times of the initial force.
If the distance is halved and the charges of both particles are doubled, the force is 16 times as great.
Coulomb's LawAccording to Coulomb's law, the electrostatic force between two charges is given by;
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
Where 'k' is the Coulomb's constant.
If the charges of both particles are doubled and the distance is halved, the new force will be;
[tex]F\,'=k\frac{2q_1 \times 2q_2}{(r/2)^2}=k \frac{4\times 4\times q_1 q_2}{r^2} =16\,F[/tex]
So, the new force will be 16 times greater than the old force.
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What is "In an isolated system two cars, each with a mass of 2,000 kg, collide. Car 1 is initially at rest , while car 2 was moving at 20 m/s. what is their combined momentum after the collision?"
Answer:
Final velocity of the combining cars = 10m/s
combined momentum = 40000kgm/s
Explanation:
Given the following :
Mass of both colliding cars = 2000kg
Initial Velocity of car 1 (U1) = 0
Initial Velocity of car 2 (U2) = 20m/s
Combuned momentum after collision =?
This is an inelastic collision which is calculated thus :
M1U1 + M2U2 = M1V + M2V
M1U1 + M2U2 = (M1 + M2) V
Where V = "final Velocity of the colliding bodies
2000 × 0 + 2000 × 20 = (2000 + 2000) V
0 + 40000 = 4000V
V = 40000 / 4000
V = 10m/s
Therefore combined momentum = (M1 + M2) V
(2000 + 2000) 10
4000(10) = 40000kgm/s
Which statement describes the energy involved in diffusion?
hope that helps
Explanation: Diffusion requires energy only to move material in through the cell membrane. Diffusion does not require energy in any situation. Diffusion requires energy only to move material out through the cell membrane.
Answer:
The answer is B >:3
Explanation:
Convert-
a) 42° to kelvin
b) 56k to °C
c) 37° to °F
d) 32° to °C
Answer:
k is celcius/farhneit +273
c is 5/9 f-32
f is 9/5 (c+32)
Answer:
A. 318.15
B.-217.15
C. 132.8
D. 0
Explanation:
K − 273.15 = °C/°F
°C/ °F + 273.15 = K
(°C × 9/5) + 32 = °F
(°F − 32) × 5/9 = 0°C
I NEED HELP ASAP
please please please
Answer:
B AND D
HOPE ITS HELF FUL .........
Which statement best describes the movement of particles when a wave travels through a medium?
Answer:
The particles of the medium just vibrate in place. Particles of the medium don’t actually travel along with the wave. Only the energy of the wave travels through the medium.
Explanation:
A body is moving vertically upwards. It’s velocity changes at a constant rate from 50m/s to 20m/s in 3 sec. What is it’s acceleration ?
Answer:
-10 m/s²
Explanation:
a = Δv / Δt
a = (20 m/s − 50 m/s) / 3 s
a = -10 m/s²
Answer 10 m/s²
Explanation:
a = Δv / Δt
a = (20 m/s − 50 m/s) / 3 s
a = -10 m/s²
Explanation:
quantities that are pure numbers
Answer:
All pure numbers are dimensionless quantities, for example 1, i, π, e, and φ. Units of number such as the dozen, gross, googol, and Avogadro's number may also be considered dimensionless
Explanation:
What is the kinetic energy of a 108 kg object that is moving with a speed of 11.1 m/s ?
Answer:
6,653.34 J
Explanation:
Kinetic energy can be found using the following formula.
[tex]KE=\frac{1}{2} mv^2[/tex]
where m is the mass in kilograms and v is the velocity in m/s.
The object is 108 kilograms and is moving at a speed of 11.1 m/s. Therefore, the mass is 108 kg and the velocity is 11.1 m/s.
m=108 kg
v=11.1 m/s
Substitute these values into the formula.
[tex]KE=\frac{1}{2}*108*11.1^2[/tex]
Evaluate the exponent first. 11.1^2 is the same as 11.1*1.11, which is equal to 123.21
[tex]KE=\frac{1}{2} *108*123.21[/tex]
Multiply 108 and 123.21
[tex]KE=\frac{1}{2}*13306.68[/tex]
Multiply 1/2 and 13306.68
[tex]KE=6653.34[/tex]
The kinetic energy of the object is 6,653.34 Joules (kg m2/s^2)
What are the materials necessary to create an electromagnet?
A) power source, metallic core, and electrical conductor
B) metallic core and power source only
C)metallic core magnet, and power source
D)electrical conductor and power source only
Answer:
A
Explanation:
Electromagnet: It is a temporary magnet. It consists of wrapping coils around iron core and the power source. When the current passes through the coils around the iron core then it will get magnetized. The domains of the electromagnet gets aligned.
As long as the current passes through it, it will get magnetized. It will loose its magnetism easily when the power is switched off.
In the electromagnet, the strength of the magnetism can be increased or decreased. The poles of the electromagnet are not fixed.
The balloon contain no gas initially.When it is connected to the cylinder gas enters the balloon the pressure in the cylinder decreases.Explain why the molecules inside the cylinder exerts a large pressure initially
Answer:
17
Explanation:
121354
A 15cm long cube made of Oak and of side floats
in water 10.5 cm of its depth below the surface
and with its sides vertical what is the density
of cube. of Water = 1000 kg m-3 ans 7ooR g/m 3
density
Answer: 700 kg/m³
Explanation: Check the solutions , 3 ways :-
The density of cube will be 700 kg/m^3.
What is the density of cube.
Length of cube(l) =15 cm =0.15m
Volume of cube ([tex]V_{c}[/tex]) = l^3=(0.15 m)^3
Volume of water displaced ([tex]V_{w}[/tex]) = Volume of cube inside water
[tex]V_{w}[/tex] =0.15*0.15*0.105 m^3
we know that,
Density of water ([tex]D_{w}[/tex]) =1000 kg/m^3
from law of floatation ,
Weight of floating body= Weight of displaced liquid
[tex]V_{c}[/tex][tex]D_{c}[/tex]g = [tex]V_{w}[/tex][tex]D_{w}[/tex]g
[tex]V_{c}[/tex][tex]D_{c}[/tex]=[tex]V_{w}[/tex][tex]D_{w}[/tex]
0.15*0.15*0.15*[tex]D_{c}[/tex]=0.15*0.15*0.105*1000
[tex]D_{c}[/tex]=0.105*1000/0.15
[tex]D_{c}[/tex] =700
Hence, The density of cube will be 700 kg/m^3.
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A 5.0 V battery contains 775 C of charge. How much electricity energy can it produce?
Answer:
3875J
Explanation:
Energy is defined as the power × time
And it's defined as
Power = IV - I- current and V- voltage
Now quantity of electricity; Q = I × t
Where I is current and t is time
Now Energy = I ×V×t = V× I×t = V× Q;
where Q is quantity of electricity 775C and V is 5.0volt
Hence 775 × (5) =3875J
~Fast-moving currents of air that occur above the friction layer are called?
mesocyclone
wind trains
chinooks
jet streams
Answer:
the answer is jet stream [100%] sure
What is the magnetic force on a 200 cm length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 0.055 T and is directed at an angle of 20 away from the wire
Answer:
F = 0.112 N
Explanation:
To find the magnitude of magnetic force on the wire, you use the following formula:
[tex]|\vec{F}|=|i\vec{L}\ X\ \vec{B}|=iLBsin\theta[/tex] (1)
L: length of the wire = 200cm = 0.2m
i: current in the wire = 30 A
B: magnitude of the magnetic field = 0.055 T
θ: angle between the directions of L and B = 20°
You replace the values of L, i, B and θ in the equation (1):
[tex]|\vec{F}|=(30A)(0.2m)(0.055T)sin(20\°)=0.112N[/tex]
hence, the magnetic force on teh wire is 0.112N
A bowling ball collides with a tennis ball. Which object has the larger impact force on the other considering that they have the same acceleration? Why?
This is for an exam could you please answer fast
Answer:
The tennis ball experiences a larger impact force due to its smaller mass.
Explanation:
Considering that they have the same acceleration, and F = ma where F is force and m = mass, the object with the smaller mass has a greater impact force on it.
This is because since force F = ma and a = constant, the object with a larger mass (the bowling ball)has a larger impact force with which it acts on the object with the smaller mass (the tennis ball). So, the tennis ball experiences a larger impact force due to its smaller mass.
Which change will increase the speed of a sound wave traveling in a solid aluminum rod?
Answer:
Increasing the temperature of the rod
Explanation:
PLEASE HELP An object is thrown upward with an initial velocity of 32.1 m/s. What is its velocity in 4.0 s? (use g = 9.81 m/s2). Please include step by step process. -7.14 11.2 7.14 -4.6
Answer:
-7.14
Explanation:
According to equation of motion
v = u + at
where
v is the final velocity at any time t
u is the initial velocity
a is the acceleration
and t is the time
___________________________________________
Given
An object is thrown upward it means
its initial velocity is in upward direction
but acceleration due to gravity is in downward direction which will cause to decrease the velocity of object.
Intial velocity u = 31.1 m/s
final velocity v at 4 second we have to find.
t = 4 second
a = g = 9.81 m/s2 (it is acting in opposite direction of motion hence its sign will be negative ).
Thus
a = - 9.81 m/s2
using the above values in v = u + at
v = 32.1 - 9.81*4
v = 32.1 - 39.24
v = -7.14
Thus, correct option is -7.14.
Jack plays floor hockey. He moves with a velocity of 7.5 m/s [East] for 2.25 seconds. What is his displacement during this time? show your work below.
Answer:
16.875 m [East]
Explanation:
In a velocity time displacement problems
displacement is given by
displacement of moving body = velocity of the that body * time
displacement will be in the direction of velocity of body.
Given
velocity = 7.5 m/s [East]
time = 2.25 seconds
displacement = 7.5 m/s [East] *2.25 seconds
displacement = 16.875 m [East]
Thus, displacement of jack is 16.875 m [East].
Una pelota cae con una energía de 1 J y bota al llegar al suelo. Si tras el bote su energía es de 0,998 J, ¿podemos afirmar que la energía se ha destruido?
Answer:
The energy is not destroyed, the energy has been transformed into another kind of energy, in this case to heat with energy of 0,002 J
Explanation:
One of the fundamental principles of physics states that energy is neither created nor destroyed, it is only transformed.
In this case, when the ball with an energy of 1 J bounces on the ground, it loses an energy equivalent to 1-0.998 J = 0.002 J. This energy of 0.002 J is not destroyed in the process, but is transformed into another type of Energy. In this case, said energy has been converted to heat. A heat equivalent to 0.002 J of energy.
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Translation to spanish
Uno de los principios fundamentales de la física afirma que la enegía no se crea ni se destruye, sólo se transforma.
En este caso, cuando la pelota con una energía de 1 J rebota en el suelo pierde una energía equivalente a 1-0,998 J = 0,002 J. Esta energía de 0,002 J no se destruye en el proceso, sino que se transforma en otro tipo de energía. En este caso dicha energía se ha convertido en calor. Un calor equivalente a 0,002 J de energía.
The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give the values r = 32700 ft, r¨ = 85 ft/sec2, and θ˙ = 0.019 rad/sec. Calculate the magnitudes of the velocity and acceleration of the rocket at this position.
Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
The magnitude of the linear velocity of the rocket at the given position is 1,667.2 ft/s.
The magnitude of the acceleration of the rocket at the given position is 90.73 ft/s².
The given parameters;
angular distance, θ = 66⁰radius of the path, r = 32700 ftcentripetal acceleration, ac = 85 ft/s²initial angular velocity, ωi = 0.019 rad/sThe linear velocity and final angular velocity of the rocket is calculated as follows;
[tex]a_c = \frac{v^2}{r} \\\\v^2 = a_c \times r\\\\v = \sqrt{a_c r} \\\\v = \sqrt{85 \times 32700}\\\\v = 1667.2 \ ft/s\\\\\omega_f = \frac{v}{r} = \frac{1667.2}{32700} = 0.051 \ rad/s[/tex]
The radial acceleration of the rocket is calculated as follows;
[tex]\omega_f^2 = \omega_i^2 + 2\alpha _r \theta\\\\(0.051)^2 = (0.019)^2 + 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r)\\\\(0.051)^2 - (0.019)^2 = 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r) \\\\0.00224 = 2.304\alpha _r\\\\\alpha _r = \frac{0.00224 }{ 2.304} \\\\\alpha _r = 0.00097 \ rad/s^2[/tex]
The tangential acceleration is calculated as follows;
[tex]a_t = \alpha_r \times r\\\\a_t = 0.00097 \times 32700\\\\a_t = 31.72 \ ft/s^2[/tex]
The resultant acceleration of the rocket is calculated as follows;
[tex]a = \sqrt{a_t^2 + a_c^2} \\\\a = \sqrt{31.72^2 \ + \ 85^2} \\\\a= 90.73 \ ft/s^2[/tex]
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What is the main reason for using a data table for collecting data?
If you put a question in the answer box or anything that isn't a answer in the answer box I will report you!
Answer:
to make calculation more easy to get
Explanation:
if you are using chart or calculate Thermodynamic problems you will not never solve this problem with out using data table for thermodynamic
Rutherford predicted that an atom has a dense core called a(n) __________
Rutherford predicted that an atom has a dense core called a nucleus.
What is nucleus of atoms?Ernest Rutherford discovered in 1911 that every atom has a nucleus in its center. Electrically charged protons and electrically neutral neutrons make up atomic nuclei. The strongest fundamental force known to science, often known as the strong force, holds these things together.
The nucleus normally comprises more than 99.9% of the atom's mass but occupies far less than.01% of its volume. The negatively charged electrons that surround a substance's nucleus determine its chemical makeup. In most cases, the number of protons in the nucleus corresponds to the number of electrons.
Some nuclei are unstable and can decay radioactively, releasing photons (gamma decay), electrons or positrons (beta decay), helium nuclei (alpha decay), or a combination of these. Eventually, these unstable nuclei reach a stable state.
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how much work is done by a force of 20N while moving an object through distance 10 m of the force
Answer:
200 J
Explanation:
Work = Force × Distance
Work = (20 N)(10 m) = 200 N·m = 200 J
200 joules of work are done by a force of 20 N over a distance of 10 m.
A 24 resistor, an inductor with a reactance of 12 , and a capacitor with a reactance of 10 are in series across a 60 V 50 Hz source. Calculate the voltage across the inductor.
Answer:
A⋅24=24A
12=24A
10=24A
a⋅(60V)⋅(50Hz)=3000aVHz
Explanation:
At which of the following points does a roller coaster have the most potential energy? As it is going down a hill. At the top of the hill. As it is climbing a hill. At the bottom of the hill.
Answer:
At the top of the hill.
Explanation:
As the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases .
As it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum .
As it goes down the hill, K.E starts to increase and G.P.E decrease .
At the bottom of the hill, K.E reaches maximum and G.P.E becomes zero .
(Correct me it I am wrong)
At the top of the hill.
The following information should be considered:
In the case when the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases . When it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum . When it goes down the hill, K.E starts to increase and G.P.E decrease . When it is the bottom of the hill, K.E reaches maximum and G.P.E becomes zero.Learn more: https://brainly.com/question/1605083?referrer=searchResults
which household items can combust
Answer:
Explanation:
Rubbing Alcohol
Nail polish and nail polish remover
Linseed oil
Aerosol cans
Non-dairy creamer
Gasoline, turpentine, and paint thinner
Hand sanitizer
Flour
Oranges
60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop
Answer:
[tex]0.25\ cm^3[/tex]
Explanation:
Data provided in the question
Number of drops fell from a burret = 60
The first reading is 28 cm^3
And, the final reading is 43 cm^3
Based on the above information, the average volume of one drop is
[tex]= \frac{Final\ readings - first\ readings}{number\ of\ drops}[/tex]
[tex]= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}[/tex]
[tex]= 0.25\ cm^3[/tex]
Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come
Answer:
0.25\ cm^30.25 cm
3
Explanation:
Data provided in the question
Number of drops fell from a burret = 60
The first reading is 28 cm^3
And, the final reading is 43 cm^3
Based on the above information, the average volume of one drop is
= \frac{Final\ readings - first\ readings}{number\ of\ drops}=
number of drops
Final readings−first readings
= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}=
60 drops
43 cm
3
−28 cm
3
= 0.25\ cm^3=0.25 cm
3
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.
Answer:
Mass, m = 0.49 kg
Explanation:
It is given that,
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.
We need to find the mass of the ice.
On a sloping surface, the force with which it strikes is given by :
[tex]F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg[/tex]
So, the mass of the ice block is 0.49 kg.
4. A moped travels 20 kilometers in 30 minutes. Calculate its average speed in km/h?
Answer:
[tex] \boxed{Average \: speed = 40 km/h} [/tex]
Explanation:
Distance travelled = 20 km
Time taken = 30 min
= [tex] \frac{30}{60} [/tex] h
= [tex] \frac{1}{2} [/tex] h
[tex]Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{20}{ \frac{1}{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \div \frac{1}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40km/h[/tex]
Thermal insulators have _____.
A. high specific heat
B. high kinetic energy
C. lots of air pockets
D. low latent heat
E. strong molecular bonds
Answer:
The correct answer to the following question will be Option A (High specific heat).
Explanation:
A thermal or heat insulator has been used to help avoid heat from travelling from one location to the another.
Specific heat seems to be important unless you consider whether the temperature including its insulator becomes evolving. Whether it has a high specific heat, it will take more energy just to increase the temperature, as well as it can also allow somewhat when it happens to come to insulating material, and therefore heat transaction or energy transactions are often influenced by a temperature gradient.Other given choices are not related to the given scenario. So that Option A seems to be the right answer.
