if the battery is a 9-volt battery and the resistance in the circuit is 18 ohm's how much current is flowing through the circuit

Answers

Answer 1

Answer:

0.50 A

Explanation:

According to the formula, V = IR

9 = I×18

I = 9/18

I = 0.50

Answer 2

If the battery is a 9-volt battery and the resistance in the circuit is 18 ohm's then the current is flowing through the circuit would be 0.5 Ampere.


What is resistance?

Resistance is the obstruction of electrons in an electrically conducting material.The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

Where V is the voltage
Where I is the current
Where R is the resistance used in the circuit

As for the given problem  if the battery is a 9-volt battery and the resistance in the circuit is 18 ohm

By using the ohms

V=IR

By substituting the respective value of voltage and resistance
Voltage is 9 volt in the resistance is 18 ohm

9V = 18*I

I= 0.5 Ampere

Thus, the current flowing through the 9 V battery and a 18 Ohm resistor is 0.5 Ampere.

Learn more about resistance from here 

brainly.com/question/14547003

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Explanation:

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hope it helps.

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.........,.............

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A.
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B.
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C.
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D.
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Answer:

Its C

Thank me later

Now bye

I think the answer is *C*

To who shall answer...
Thank You Very much for am eternally grateful.

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I guess the answer is second one

Second one makes more sense

At 10°C, the gas in a cylinder has a volume of 0.250 L. The gas is allowed to expand to 0.285 L.


What must the final temperature be for the pressure to remain constant? (Hint °C + 273 = K.)


282 K


284 K


323 K


248 K

Answers

Explanation :Use the formula: P1V1T1=P2V2T2
We know that we want P1=P2 so the pressure will remain constant, so we can say that: P1V1T1=P1V2T2
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Answers

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Answer:

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Answers

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Mark as brainlist

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