if the atlanta hawks free throw percentage is 82%, what is the probability that a player for the hawks will make 2 free shots in a row?

Answers

Answer 1

Answer:

Approx 67.24%

Step-by-step explanation: If the Atlanta Hawks' free-throw percentage is 82%, the probability that a player will make one free throw is 0.82.

To find the probability that a player will make two free throws in a row, we can use the multiplication rule of probability which states that the probability of two independent events occurring together is the product of their individual probabilities.

Therefore, the probability of a player making two free throws in a row can be calculated as follows:

P(making two free throws in a row) = P(making first free throw) x P(making second free throw)

P(making two free throws in a row) = 0.82 x 0.82

P(making two free throws in a row) = 0.6724 or 67.24%

Therefore, the probability that a player for the Atlanta Hawks will make two free shots in a row is approximately 67.24%


Related Questions

X is a random variable with the probability function: f(x) = x/6 for x = 1, 2, or 3. the expected value of x is _____.

Answers

The expected value of X is 2.33.


To find the expected value of the random variable X, we need to use the given probability function f(x) and the formula for expected value: E(X) = Σ[x * f(x)]. Here's a step-by-step explanation:

1. Identify the possible values of x: 1, 2, and 3.
2. Calculate f(x) for each x value using the given probability function f(x) = x/6:
  f(1) = 1/6
  f(2) = 2/6 = 1/3
  f(3) = 3/6 = 1/2
3. Apply the expected value formula by multiplying each x value by its corresponding f(x) and summing the results:
  E(X) = (1 * 1/6) + (2 * 1/3) + (3 * 1/2) = 1/6 + 2/3 + 3/2
4. Simplify the expression to find the expected value:
  E(X) = 1/6 + 4/6 + 9/6 = (1 + 4 + 9)/6 = 14/6 = 7/3

The expected value of the random variable X is 7/3 or 2.33.

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what is the approximate length of the base of the triangle ? round to the nearest tenth if needed.

Answers

The approximate length of the base of the triangle is 5 units.

Given that, the area of a hexagon is about 65 square units. You decompose the figure into 6 triangles.

A regular hexagon can be decomposed into 6 equal triangles,

So, the area of each triangle is 65/6 = 10.8 square units

The height of one triangle is about 4.3 units.

We know that, the area of a triangle is 1/2 ×Base×Hieght

Now, 10.8=1/2 ×Base×4.3

21.6=Base×4.3

Base=21.6/4.3

Base=5.02

Therefore, the approximate length of the base of the triangle is 5 units.

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Using composition of functions, determine if the to functions are inverses of each othr. f(x)= square root of x, +4, x>0. g(x) x2-4, x>2.

Answers

Using the composition of functions, if the two functions are inverses of each other, therefore, we cannot conclude if f(x) and g(x) are inverses of each other.

To check if the two functions f(x) and g(x) are inverses of each other, we need to verify if their composition f(g(x)) and g(f(x)) results in the identity function f(x) = x.

Let's first find the composition f(g(x)):

f(g(x)) = f(x^2 - 4)

= sqrt(x^2 - 4) + 4

Now, let's find the composition g(f(x)):

g(f(x)) = g(sqrt(x) + 4)

= (sqrt(x) + 4)^2 - 4

= x + 16 + 8sqrt(x)

To check if f(x) and g(x) are inverses of each other, we need to check if f(g(x)) = x and g(f(x)) = x for all x in the domain of the functions.

For f(g(x)):

f(g(x)) = sqrt(x^2 - 4) + 4

This function is only defined for x > 2, since the square root of a negative number is not real. Therefore, the domain of f(g(x)) is (2, infinity).

For g(f(x)):

g(f(x)) = x + 16 + 8sqrt(x)

This function is only defined for x >= 0, since the square root of a negative number is not real. Therefore, the domain of g(f(x)) is [0, infinity).

Since the domains of f(g(x)) and g(f(x)) do not overlap, we cannot check if they are inverses of each other. Therefore, we cannot conclude if f(x) and g(x) are inverses of each other.

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Transformations and Congruence:Question 3 Triangle ABC is reflected over the x-axis. Which is the algebraic rule applied to the figure? Select one:​

Answers

Hi! I'd be happy to help you with your question about transformations and congruence. When Triangle ABC is reflected over the x-axis, the algebraic rule applied to the figure is:

Your answer: (x, y) → (x, -y)

This rule states that the x-coordinate remains the same, while the y-coordinate is multiplied by -1, resulting in a reflection over the x-axis. This transformation preserves congruence, as the size and shape of Triangle ABC remain the same, only its position changes.

The algebraic rule applied to the figure when Triangle ABC is reflected over the x-axis is (x,y) → (x,-y), where x represents the x-coordinate and y represents the y-coordinate. This is because reflecting a figure over the x-axis involves keeping the x-coordinate the same while changing the sign of the y-coordinate. This preserves the congruence of the original and reflected triangles.

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See image for the work

Answers

Answer:

For 10 sections you would need 60 rails

The rule for posts is to multiply the section by 3

the rule for rails is to multiply the post by 2

Sarah tells her mom that there is a 40% chance she will clean her room, a 70% she will do her homework, and a 24% chance she will clean her room and do her homework. What is the probability of Sarah cleaning her room or doing her homework?

Answers

To find the probability of Sarah cleaning her room or doing her homework, we can use the addition rule for probabilities. However, we need to be careful not to count the probability of Sarah cleaning her room and doing her homework twice. Therefore, we need to subtract the probability of Sarah cleaning her room and doing her homework from the sum of the probabilities of Sarah cleaning her room and doing her homework separately.

Let C be the event that Sarah cleans her room, and let H be the event that Sarah does her homework. Then we know:

P(C) = 0.40 (the probability that Sarah cleans her room)

P(H) = 0.70 (the probability that Sarah does her homework)

P(C and H) = 0.24 (the probability that Sarah cleans her room and does her homework)

Using the addition rule, we can find the probability of Sarah cleaning her room or doing her homework as follows:

P(C or H) = P(C) + P(H) - P(C and H)

          = 0.40 + 0.70 - 0.24

          = 0.86

Therefore, the probability of Sarah cleaning her room or doing her homework is 0.86, or 86%.

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If f(x) = 2x2 - 6x² + 4x – 8 and g(x)= 0, find (fog)(x) and (gof)(x).

Answers

The final values is (fog)(x) = f(g(x)) = f(0) = -8.

In the given problem, we are given two functions, f(x) and g(x). The function f(x) is a polynomial function, and g(x) is a constant function equal to 0. We are asked to find the composition of these two functions, that is, (fog)(x) and (gof)(x).

The composition of two functions f(x) and g(x) is denoted by (fog)(x) and is defined as follows:

(fog)(x) = f(g(x))

This means that we first evaluate g(x) and then use the output of g(x) as the input of f(x) to get the final output of (fog)(x).

In this case, since g(x) = 0, we have:

(fog)(x) = f(g(x)) = f(0)

To evaluate f(0), we substitute x = 0 in the expression for f(x):

[tex]f(x) = 2x^2 - 6x^2 + 4x - 8[/tex]

[tex]f(0) = 2(0)^2 - 6(0)^2 + 4(0) - 8[/tex]

f(0) = -8

Therefore, (fog)(x) = f(g(x)) = f(0) = -8.

Now, to find (gof)(x), we need to evaluate g(f(x)). Since f(x) is a polynomial function, we can find its value for any value of x. However, since g(x) is a constant function equal to 0, its output is always 0 for any input x. Therefore, g(f(x)) = 0 for all values of f(x).

This means that (gof)(x) = g(f(x)) = 0 for all x.

In summary, we found that (fog)(x) = -8 and (gof)(x) = 0.

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Mariah is training for a sprint distance triathlon. She plans on cycling from her house to the library, shown on the grid with a scale in miles. If the cycling portion of the triathlon is 12 miles, will mariah have cycled at least 2/3 of that distance during her bike ride?

Answers

Mariah cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

What is a triathlon?

A triathlon is  described as an endurance multisport race consisting of swimming, cycling, and running over various distances.

The coordinates are given as follows:

Library (4,9).Mariah's House: (9, 2).

Suppose that we have two points,  and . The distance between them is given by:

distance = √(x2 - x1)² + (y2-y1)²

We substitute in the equation

Hence the distance between her house and the library is:

D = 8.6 miles.

She cycles a distance of 8.6 miles, which is more than 8 miles, hence more than 2/3 of the cycling portion of the triathlon.

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Javier's deli packs lunches for a school field trip by randomly selecting sandwich, side, and drink options. each lunch includes a sandwich (pb&j, turkey or ham and cheese), a side (cheese stick or chips), and a drink (water or apple juice)

1. what is the probability that a student gets a lunch that includes chips and apple juice?

2. what is the probability that a student gets a lunch that does not include chips?​

Answers

Answer is: Probability of a student getting a lunch that does not include chips is 6/12 or 0.5.


1. To find the probability of a student getting a lunch that includes chips and apple juice, we need to first find the total number of possible lunch combinations. There are 3 options for sandwiches, 2 options for sides, and 2 options for drinks, so there are a total of 3 x 2 x 2 = 12 possible lunch combinations.

Out of those 12 combinations, there is only 1 combination that includes chips and apple juice: ham and cheese sandwich, chips, and apple juice.

Therefore, the probability of a student getting a lunch that includes chips and apple juice is 1/12 or approximately 0.083.

2. To find the probability of a student getting a lunch that does not include chips, we can count the number of possible lunch combinations that do not include chips and divide by the total number of lunch combinations.

There are 3 sandwich options and 2 drink options, so there are a total of 3 x 2 = 6 possible lunch combinations without chips.

Out of the total of 12 possible lunch combinations, 6 do not include chips, so the probability of a student getting a lunch that does not include chips is 6/12 or 0.5.

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Please helpppp

side lengths, surface areas, and volumes fo...
a designer builds a model of a sports car. the finished model is exactly the same shape as the original, but smaller. the scale factor is 3:11
(a) find the ratio of the surface area of the model to the surface area of the original.
(b) find the ratio of the volume of the model to the volume of the original.
(c) find the ratio of the width of the model to the width of the original.
nrite these ratios in the format m:n.
surface area:

volume:
width:

Answers

The ratios are: surface area 9:121, volume 27:1331, width 3:11.

(a) The ratio of the surface area of the model to the surface area of the original can be found by using the scale factor to find the ratio of the corresponding side lengths. Since surface area is proportional to the square of the side length, we can use this ratio squared to find the ratio of the surface areas.
The ratio of the corresponding side lengths is 3:11, so the ratio of the surface areas is (3/11)^2, which simplifies to 9/121.
Therefore, the ratio of the surface area of the model to the surface area of the original is 9:121.
(b) The ratio of the volume of the model to the volume of the original can be found using the same method as above, but with volume instead of surface area. Since volume is proportional to the cube of the side length, we can use this ratio cubed to find the ratio of the volumes.
The ratio of the corresponding side lengths is 3:11, so the ratio of the volumes is (3/11)^3, which simplifies to 27/1331.
Therefore, the ratio of the volume of the model to the volume of the original is 27:1331.
(c) The ratio of the width of the model to the width of the original can be found directly from the scale factor, since width is one of the corresponding side lengths.
The ratio of the corresponding side lengths is 3:11, so the ratio of the widths is 3:11.
Therefore, the ratio of the width of the model to the width of the original is 3:11.
Overall, the ratios are: surface area  9:121, volume  27:1331, width 3:11.

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Chase was on his school’s track team and ran the 2400m race. He has been working on his pace and can run 1600m in 5. 5 minutes. If he keeps this pace through the entire race, how long will it take him to finish the 2400m race?

A. 8. 25 minutes

B. 7. 75 minutes

C. 8. 5 minutes

D. 8. 42 minutes

Answers

If Chase can run 1600m in 5.5 minutes, then his pace is:

5.5 minutes / 1600m = 0.0034375 minutes/meter

To find out how long it will take him to run 2400m at this pace, we can multiply the pace by the distance:

0.0034375 minutes/meter * 2400m = 8.25 minutes

Therefore, the answer is A. 8.25 minutes.

Nancy's Cupcakes recorded how many cupcakes it recently sold of each flavor. â
â
âchocolate cupcakes 2
âpistachio cupcakes â 1
âbanana cupcakes â 5
âpumpkin cupcakes â 6

ââConsidering this data, how many of the next 21 cupcakes sold would you expect to be pumpkin cupcakes?â
A
9
B
7
C
6
D
3
Part B
What is probability of a chocolate cupcakes being sold?
â Probability (chocolate cupcakes) =
%
Note: Write your answer as a percentage rounded to the nearest whole number. â

Answers

We would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes. The probability of a chocolate cupcake being sold is approximately 14%.

The question asks to determine how many of the next 21 cupcakes sold would be expected to be pumpkin cupcakes, and also to find the probability of a chocolate cupcake being sold.

First, let's analyze the given data:
- Chocolate cupcakes: 2
- Pistachio cupcakes: 1
- Banana cupcakes: 5
- Pumpkin cupcakes: 6

Total cupcakes sold: 2 + 1 + 5 + 6 = 14

To find the expected number of pumpkin cupcakes in the next 21 sold, calculate the proportion of pumpkin cupcakes in the original data, and then multiply by 21:

(6 pumpkin cupcakes / 14 total cupcakes) * 21 = 9 (rounded)

So, we would expect 9 pumpkin cupcakes to be sold in the next 21 cupcakes (Answer A).

For Part B, we need to find the probability of a chocolate cupcake being sold. To do this, divide the number of chocolate cupcakes by the total number of cupcakes:

Probability (chocolate cupcakes) = (2 chocolate cupcakes / 14 total cupcakes) = 0.142857

Now, convert this probability to a percentage and round to the nearest whole number:

0.142857 * 100 = 14.29% ≈ 14%

So, the probability of a chocolate cupcake being sold is approximately 14%.

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tice Problems
Scientists have calculated that recycling 10 pounds of paper, results in 8 fewer gallons of
water being required to produce an equivalent amount of new paper. If a school begins a
recycling program and is able to increase the amount of paper they recycle by 500 pounds
per month, calculate number of gallons of water this conserves over an entire year.

Answers

By increasing their recycling by 500 pounds per month, the school conserves 4,800 gallons of water in a year.

Determine the ratio of water conserved per pound of paper recycled:

8 gallons of water are saved for every 10 pounds of paper recycled.

Calculate the water saved for each pound of paper:

8 gallons/10 pounds = 0.8 gallons/pound.

Find the increase in paper recycled per month:

500 pounds/month.

Calculate the water saved per month:

[tex]500 $ pounds/month \times  0.8 $ gallons/pound = 400 $ gallons/month.[/tex]

Calculate the water saved in a year:

[tex]400 $ gallons/month \times  12 months = 4,800 $ gallons/year.[/tex]

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Find the value of x.

Answers

Answer:

x = 150

Step-by-step explanation:

We know that the total amount of degrees in a circle is 360°.

We also know that a right angle is 90°.

Using this information, and the given 120° angle, we can form the following equation to solve for x:

90° + 120° + x° = 360°

210° + x° = 360°

x° = 360° - 210°

x° = 150°

x = 150

Step-by-step explanation:

120° + 90° + x = 360°

210° + x = 360°

x = 360° - 210°

= 150°

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Madie and Clyde buy another circular plot of land, smaller than the first, on which to plant an orchard. They have set up coordinates as before, with the center of the orchard at (0, 0). They will plant trees at all points with integer coordinates that lie within the orchard, except at (0, 0).



In this orchard, the tree at (5, 12) is on the boundary. What are the coordinates of the other trees that must also be on the boundary? Explain your answer

Answers

The coordinates of the other trees that must also be on the boundary are (-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

The coordinates of the other trees that must be on the boundary of the circular orchard, given that the tree at (5, 12) is on the boundary and the center of the orchard is at (0, 0) can be determined as follows.

1. Calculate the radius of the orchard using the distance formula:

sqrt((x2-x1)^2 + (y2-y1)^2).

In this case, (x1, y1) = (0, 0) and (x2, y2) = (5, 12).

2. Radius = sqrt((5-0)^2 + (12-0)^2) = sqrt(5^2 + 12^2) = sqrt(25 + 144) = sqrt(169) = 13.

Now, we know the radius of the orchard is 13. To find the other boundary points, we can use the property of circles that states that the points on the boundary are equidistant from the center.

Since the coordinates are integers and symmetric, we can list the other points as follows:

3. The coordinates of the other trees on the boundary are:

(-5, 12), (5, -12), (-5, -12), (12, 5), (12, -5), (-12, 5), and (-12, -5).

These points are also 13 units away from the center, making them equidistant from the center and thus on the boundary of the circular orchard.

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PLEASE HELP



A cone frustum has height 2 and the radii of its bases are 1 and 2 1/2.



What is the volume of the frustum?



What is the lateral area of the frustrum?

Answers

The volume of the frustum is 132.84 cubic units.

The lateral area of the frustum is 7π√17/4 square units.

To calculate the volume of the frustum, we can use the formula:

V = (1/3) × π × h × (r₁² + r₂² + (r₁ * r₂))

where:

V is the volume of the frustum,

h is the height of the frustum,

r₁ is the radius of the smaller base,

r₂ is the radius of the larger base, and

π is a mathematical constant approximately equal to 3.14159.

Plugging in the values given:

h = 2,

r₁ = 1, and

r₂ =[tex]2\frac{1}{2}[/tex] = 5/2,

V = (1/3)× π × 2 × (1² + (5/2)² + (1 × (5/2)))

V = (1/3) × π × 2 × (1 + 25/4 + 5/2)

V = 132.84

Therefore, the volume of the frustum is approximately 132.84 cubic units.

To calculate the lateral area of the frustum, we can use the formula:

A = π × (r₁ + r₂) × l

To find the slant height, we can use the Pythagorean theorem:

l = √(h² + (r₂ - r₁)²)

Plugging in the values given:

h = 2, r₁ = 1, and r₂ =5/2

l = √ 2² + ((5/2) - 1)²

l = √(4 + (5/2 - 2)²)

l = √(17/4)

l = √(17)/2

Now, plugging in the values into the lateral area formula:

A = π×(1 + 5/2)× √17/2

A = π × (7/2) × √(17)/2

A = 7π√17/4

Therefore, the lateral area of the frustum is 7π√17/4 square units.

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is this a linear function

Answers

no enough info to provide answer.

Since 2005, the amount of money spent at restaurants in a certain country has increased at a rate of 6% each year. In 2005, about $410 billion was spent at restaurants. If the trend continues, about how much will be spent at restaurants in 2017? About $ billion will be spent at restaurants in 2017 if the trend continues

Answers

About $786 billion will be spent at restaurants in 2017 if the trend continues.

To solve this problem

We can use the formula for compound interest:

A = P(1 + r)^n

where:

A is the final amount

P is the initial amount

r is the annual interest rate

n is the number of years

In this instance, we're looking to determine how much will be spent at restaurants in 2017, which is 12 years from now, in 2005. The initial amount was $410 billion in 2005, and the yearly interest rate is 6%. We thus have:

A = 410(1 + 0.06)^12

A ≈ 786.34

Therefore, about $786 billion will be spent at restaurants in 2017 if the trend continues.

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Katie started with $40. how much money did she have left after purchases the supplies.

Answers

If Katie started with $40, the remaining balance after purchasing the supplies is $20.

To determine how much money Katie had left after purchasing the supplies, we'll consider the fraction "1/5" for the storybook and "3/10" for the calculator.

1: Calculate the amount spent on the storybook.

Katie spent 1/5 of her initial $40 on the storybook. To find this amount, multiply the fraction by the total amount:

(1/5) x $40 = $8

2: Calculate the amount spent on the calculator.

Katie spent 3/10 of her initial $40 on the calculator. To find this amount, multiply the fraction by the total amount:

(3/10) x $40 = $12

3: Add the amounts spent on both the storybook and calculator.

$8 (storybook) + $12 (calculator) = $20

4: Subtract the total amount spent from Katie's initial amount of money to find the remaining balance.

$40 (initial amount) - $20 (total spent) = $20

After purchasing the supplies, Katie had $20 left.

Note: The question is incomplete. The complete question probably is: Katie started with $40. He spent 1/5 of the money on a storybook and 3/10 on a calculator. how much money did she have left after purchases the supplies.

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How many possible outcomes are in the sample space if the spinner shown is spun twice?

Answers

There are 225 possible outcomes in the sample space if the spinner is spun twice

How many possible outcomes are in the sample space

From the question, we have the following parameters that can be used in our computation:

Spinner

The number of sections in the spinner is

n = 15

If the spinner shown is spun twice, then we have

Outcomes = n²

Substitute the known values in the above equation, so, we have the following representation

Outcomes = 15²

Evaluate

Outcomes = 225

Hence, the possible outcomes are in the sample space are 225

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Find the area of the shaded region

Answers

The area of the shaded region of the circle is 89.75 mi².

What is the area of the shaded region?

The area of a sector of a circle, you can use the formula:

A = (θ/360) × π × r²

Where A is the area of the sector, θ is the central angle of the sector, r is the radius of the circle, and π is a constant approximately equal to 3.14.

From the diagram, angle of the unshaded sector equals 150 degree.

Angle of the shaded region = 360 - 150 = 210 degree

Radius r = 7 miles.

We can substitute these values into the formula and solve for the area A.

A = (θ/360) × π × r²

A = ( 210/360 ) × 3.14 × 7²

A = ( 210/360 ) × 3.14 × 49

A = 89.75 mi²

Therefore, the area of the sector is approximately 89.75 mi².

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Is 2352 a perfect square? If not, find the smallest number by
which 2352 must be multiplied so that the product is a perfect
square. Find the square root of new number.

Answers

No, 2352 is not a perfect square.

To find the smallest number by which 2352 must be multiplied so that the product is a perfect square, we need to factorize 2352 into its prime factors.

2352 = 2^4 x 3 x 7^2

To make it a perfect square, we need to multiply it by 2^2 and 7, which gives us:

2352 x 2^2 x 7 = 9408

Now, we can take the square root of 9408:

√9408 = √(2^8 x 3 x 7) = 2^4 x √(3 x 7) = 16√21

Therefore, the smallest number by which 2352 must be multiplied so that the product is a perfect square is 2^2 x 7, which gives us the square root of 9408 as 16√21.

Answer:

The smallest number by which 2352 must be multiplied so that the product is a perfect  square = 3

The square root of the new number = 84

Step-by-step explanation:

√2352 ≈ 48.5 so not a perfect square

Prime factorization of 2352 yields

2352 = 2 x 2 x 2 x 2 x 7 x 7 x 3

In exponential form this is
2⁴ x  7² x 3¹

So
[tex]\sqrt{2352} = \sqrt{2^4 \cdot 7^2 \cdot 3}\\\\= \sqrt{2^4} \cdot \sqrt{7^2} \cdot \sqrt{3}\\\\= 2^2 \cdot 7 \cdot \sqrt{3}\\\\= 28 \sqrt{3}[/tex]

To get rid of the radical in the square root and get a whole number, all you have to do is multiply [tex]\sqrt{2352}[/tex]  by √3

[tex]28 \sqrt{3} \cdot \sqrt{3} = 28\cdot 3 = 84\\\\84^2 = 7056 = 2352 \cdot 3\\[/tex]

This means that if you multiply 2352 by 3 it will become a perfect square

Check:
[tex]2352 \cdot 3 = 7056\\\\\sqrt{7056} = 84[/tex]

The talk-time battery life of a group of cell


phones is normally disributed with a mean of 5


hours and a standard deviation of 15 minutes.


a)what percent of the phones have a battery life of at least 4 hours and 45 minutes? b)what percent of the phones have a battery life between 4. 5 hours and 5. 25 hours? c)what percent of the phones have a battery life less than 5 hours of greater than 5. 5 hours?

Answers

a) Approximately 79.38% of the phones have a battery life of at least 4 hours and 45 minutes.

b) Approximately 34.13% of the phones have a battery life between 4.5 hours and 5.25 hours.

c) Approximately 50% of the phones have a battery life less than 5 hours or greater than 5.5 hours.

a) What percentage battery life of 4 hours and 45 minutes?

a) For phones with a mean battery life of 5 hours and a standard deviation of 15 minutes, we can calculate the percentage of phones with a battery life of at least 4 hours and 45 minutes. By converting 4 hours and 45 minutes to minutes (4*60 + 45 = 285 minutes) and using the z-score formula, we find that the z-score is (285 - 300) / 15 = -1. Hence, the percentage is approximately 1 - 0.8359 = 0.1641, which is about 16.41%.

b) What percentage battery life between 4.5 hours and 5.25 hours?

b) To determine the percentage of phones with a battery life between 4.5 hours and 5.25 hours, we need to calculate the z-scores for both values. Converting the hours to minutes, we have 4.5 hours = 270 minutes and 5.25 hours = 315 minutes. The z-scores are (270 - 300) / 15 = -2 and (315 - 300) / 15 = 1. By referring to the standard normal distribution table, we find that the area between -2 and 1 is approximately 0.6141. Thus, the percentage is 0.6141 * 100 = 61.41%.

c) What percentage battery life less than 5 hours?

c) For the percentage of phones with a battery life less than 5 hours or greater than 5.5 hours, we need to calculate the z-score for both cases. The z-score for 5 hours is (300 - 300) / 15 = 0, and the z-score for 5.5 hours is (330 - 300) / 15 = 2. By referring to the standard normal distribution table, we find that the area to the left of 0 is 0.5 and the area to the right of 2 is 1 - 0.9772 = 0.0228. Adding these percentages, we get 0.5 + 0.0228 = 0.5228, which is approximately 52.28%.

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15/51+16/27-(-2/27-2/51)

Answers

Answer:

1

Step-by-step explanation:

USE PEMDAS OR ORDER OF OPERATIONS

1. Evaluate parenthesis.

-2/27 - 2/51 = - 52/459.

2. Add

15/51 + 16/27 = 407/459

3. Subtract to get the final answer

407/459 - -52/459 = 407/459 + 52/459 = 1

So, 15/51+16/27-(-2/27-2/51) = 1

What’s the answer I need help pls?

Answers

The answer is (-8, -4i). Hope this helps you!

A car with a mass of 1200 kg and traveling 40 m/s east runs into the back of a parked truck with a mass of 2000 kg. After the collision the car and truck do not stick together, but the car is stopped. If momentum is conserved, what would the velocity of the truck be after the collision?

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The velocity of the truck after the collision would be 24 m/s east.

The law of conservation of momentum states that the momentum of a closed system remains constant if no external forces act on it. In this case, we can assume that the car and the truck form a closed system.

The momentum of an object is given by its mass multiplied by its velocity, p = mv. Initially, the momentum of the system is:

p_initial = m_car * v_car + m_truck * v_truck

where m_car and v_car are the mass and velocity of the car, and m_truck and v_truck are the mass and velocity of the truck.

After the collision, the car is stopped, so its velocity is 0. The momentum of the system after the collision is:

p_final = m_car * 0 + m_truck * v'_truck

where v'_truck is the velocity of the truck after the collision.

Since momentum is conserved, we can set p_initial equal to p_final:

m_car * v_car + m_truck * v_truck = m_truck * v'_truck

Solving for v'_truck, we get:

v'_truck = (m_car * v_car + m_truck * v_truck) / m_truck

Substituting the given values, we have:

v'_truck = (1200 kg * 40 m/s + 2000 kg * 0 m/s) / 2000 kg

v'_truck = 24 m/s east

Therefore, the velocity of the truck after the collision would be 24 m/s east.

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please help me on this question

Answers

Based on the data, we can infer that Kallie needs 6 teaspoons of water conditioner for the 12 fish tanks.

How to calculate how many teaspoons of water conditioner Kallie needs?

To calculate how many teaspoons of water conditioner we must take into account the information on the capacity of each tank:

Each tank is equivalent to 20 quarts, that is, 5 gallons.There are 12 tanks in total.For every 10 gallons, you need 1 teaspoon of water conditioner.

In accordance with the above, we do the following logical procedure.

We multiply the capacity of each tank by the number of tanks.

5 * 12 = 60

So we need 60 gallons of water to fill the tanks, and we divide by 10 to find how many teaspoons we need to fill all 12 tanks.

60 / 10 = 6

Based on the above, we need 6 teaspoons to condition the water in the 12 tanks.

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Evaluate the integral. 8 Vi s dt Vi 8V1 ſ Vi dt=U Help me solve this Ca

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The integral evaluates to (16/3)s³/² + C.

What is power rule of integration?

The power rule of integration is a method for finding the indefinite integral of a function of the form f(x) = x^n, where n is any real number except for -1. The rule states that the indefinite integral of f(x) is (x^(n+1))/(n+1) + C, where C is an arbitrary constant of integration.

To evaluate the integral 8√(s) ds, follow these steps:


1. Rewrite the integral with a rational exponent: ∫8s¹/² ds
2. Apply the power rule for integration: ∫sⁿ ds = (sⁿ⁺¹/(n+1) + C, where n ≠ -1
3. Substitute n=1/2: (s³/²)/(3/2) + C
4. Multiply by 8: 8*(s³/²)/(3/2) + C
5. Simplify the expression: (16/3)s³/² + C

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Determine the equation of the circle graphed below.

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The equation of the circle graphed below is (x - 1)² + (y - 1)² = 4.

To determine the equation of a circle, we need to know the coordinates of its center and the radius. The general equation of a circle with center (h, k) and radius r is given by:

(x - h)² + (y - k)² = r²

where (x,y) are the coordinates of any point on the circle. The equation shows that the distance between any point (x,y) on the circle and the center (h,k) is always equal to the radius r.

To determine the equation of the circle graphed below, we need to identify the coordinates of its center and the radius. One way to do this is to use the distance formula between two points. We can choose any two points on the circle and use their coordinates to find the distance between them, which is equal to the diameter of the circle. Then, we can divide the diameter by 2 to find the radius.

To find the radius, we can choose any point on the circle and use the distance formula to find the distance between that point and the center. We can use the point (5,1), which is on the right side of the circle. The distance between (5,1) and (1,1) is 4 units, which means that the radius is 2 units.

Substituting the values of (h,k) and r in the general equation of the circle, we get:

(x - 1)² + (y - 1)² = 4

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3. Compute the integral JSS, udv, where U is the part of the ball of radius 3, centered at 0,0,0), that lies in the 1st octant. Recall that the first octant is the part of the 3d space where all three coordinates I, y, z are nonnegative. (Hint: You may use cylindrical or spherical coordinates for this computation, but note that the computation with cylindrical coordinates will involve a trigonometric substitution - 30 spherical cooridnates should be preferable.)

Answers

To compute the integral JSS, udv, where U is the part of the ball of radius 3, centered at 0,0,0), that lies in the 1st octant, we can use spherical coordinates. Since the region is defined as having all three coordinates nonnegative, we can set our limits of integration as follows: 0 ≤ ρ ≤ 3, 0 ≤ θ ≤ π/2, and 0 ≤ φ ≤ π/2.

Using the Jacobian transformation, we have:

JSS, udv = ∫∫∫U ρ²sinφ dρdθdφ

Substituting in our limits of integration, we get:

JSS, udv = ∫0^π/2 ∫0^π/2 ∫0³ ρ²sinφ dρdθdφ

Evaluating the integral, we get:

JSS, udv = (3³/3) [(sin(π/2) - sin(0))] [(1/2) (π/2 - 0)]

JSS, udv = 9/2 π

Therefore, the value of the integral JSS, udv, over the part of the ball of radius 3 that lies in the 1st octant is 9/2π.
To compute the integral JSS, udv, over the region U, which is the part of the ball of radius 3 centered at (0,0,0) and lies in the first octant, we will use spherical coordinates for this computation as it's more preferable.

In spherical coordinates, the volume element is given by dv = ρ² * sin(φ) * dρ * dφ * dθ, where ρ is the radial distance, φ is the polar angle (between 0 and π/2 for the first octant), and θ is the azimuthal angle (between 0 and π/2 for the first octant).

Now, we need to set up the integral for the volume of the region U:
JSS, udv = ∫∫∫ (ρ² * sin(φ) * dρ * dφ * dθ), with limits of integration as follows:
ρ: 0 to 3 (radius of the ball),
φ: 0 to π/2 (for the first octant),
θ: 0 to π/2 (for the first octant).

So, the integral becomes:
JSS, udv = ∫(0 to π/2) ∫(0 to π/2) ∫(0 to 3) (ρ² * sin(φ) * dρ * dφ * dθ)

By evaluating this integral, we will obtain the volume of the region U in the first octant.

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