0.25 kg
Explanation:
[tex]p = m \times v \\ 2.5 = m \times 10 \\ m = \frac{2.5}{10} \\ \boxed{m = 0.25} [/tex]
A particle moves along a line so that at time t0 its acceleration is given by a(t) = 12t
The value of distance covered by the particle during the first 3 second which moves along a line so that its acceleration is 12t, is 54 ft.
What is the acceleration of an object?Acceleration of an object is the rate of change of velocity of the object per unit time.
A particle moves along a line so that at time t0 its acceleration is given by [tex]a(t) = 12t\rm\; ft/sec^2[/tex]
The value of distance covered by the particle during the first 3 second has to be obtained.
Acceleration is the change in velocity (v) per unit time. Thus, the above equation can be written as,
[tex]a(t) = 12t\rm\; ft/sec^2\\\dfrac{dv}{dt}= 12t\rm\; ft/sec^2[/tex]
The equation can be solved as further.
[tex]\dfrac{dv}{dt}= 12t\\v= 6t^2+v_0\rm[/tex]
Here, the vo is the initial velocity which is equal to zero.
[tex]v=6t^2[/tex]
Velocity is the change in distance(s) per unit time. Thus, the above equation can be written as,
[tex]\dfrac{ds}{dt}=6t^2\\\dfrac{ds}{dt}=2t^3+s_0[/tex]
Here, the so is the initial position which is equal to zero. Thus,
[tex]s=2t^3[/tex]
Put the value of time t=3.
[tex]s=2(3)^3\\s=54\rm\; ft[/tex]
Thus, the value of distance covered by the particle during the first 3 second which moves along a line so that its acceleration is given by a(t) = 12t is 54 ft.
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How many stars has been observed by Hubble telescope till now ?
Answer:
More Than 1.3 million.
Hope it helps :))
A narrow beam of ultrasound waves reflects off a liver tumor as illustrated. The speed of sound in the liver is 10\% less than in the surrounding medium. What is the depth of the tumor
When the narrow beam of ultrasound waves reflects off a liver tumor, the depth of the tumor is found to be 6.30 cm.
What is Snell's law?Snell's law states that the ratio of the sin of the angle of incidence to the angle of reflection is equal to the ratio of the speed of the wave in the first medium to the speed of the wave in the second medium.
[tex]\dfrac{sin\:i}{sin\:r} =\dfrac{v_{1} }{v_{2} }[/tex]
Where, i represents the angle of incidence and r is the angle of reflection.
Given the speed of sound in the liver is 10% less than in the medium, so
[tex]\dfrac{v_{liver} }{v_{medium} }=0.900[/tex]
According to the figure, the angle of incidence is 50°, then from the Snell's law, we have
[tex]sin\:r=(\dfrac{v_{liver} }{v_{medium} } )\times sin\:i\\\\r=sin^{-1} [(0.900)sin 50][/tex]
The angle of reflection comes out to be
r = 43.6°
From the law of reflection,
[tex]d =\dfrac{12\:\rm cm}{2} =6\:\rm cm[/tex]
The depth of the tumor is
[tex]h=\dfrac{d}{tan\:r} =\dfrac{6}{tan\:43.6} \\\\h=6.30\:\rm cm[/tex]
The depth of the tumor in the liver is 6.30 cm.
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Draw a schematic diagram of a circuit consisting of a battery of five 2 V cells, a 5 ohm resistor, a 10 ohm resistor, a 15 ohm resistor, an ammeter and a plug key, all connected in series. Calculate the electric current passing through the above circuit when the key is closed..
Please help ASAP..
Answer:
Current = 0.33 AExplanation:
For diagram refer the attachment.It is given that five cells of 2V are connected in series, so total voltage of the battery:
[tex]\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V [/tex]
Three resistor of 5[tex]\Omega[/tex], 10[tex]\Omega[/tex], 15[tex]\Omega[/tex] are connected in Series, so the net resistance:
[tex]\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}[/tex]
[tex]\dashrightarrow \: \: \sf R = 5 + 10 + 15 [/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}[/tex]
According to ohm's law:
[tex]\dashrightarrow \sf\: \: V = IR [/tex]
[tex]\dashrightarrow \sf \: \: I = \dfrac{V}{R}[/tex]
On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 [tex]{\pmb{\sf{\Omega}}}[/tex] we get:
[tex]\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}[/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}[/tex]
[tex]\therefore[/tex]The electric current passing through the above circuit when the key is closed will be 0.33 A
Answer:
Resistance = 5 + 10 + 15 = 30
Explanation:
Current= 0.33 Amperes
Motion is a change in
1.Time
2.Speed
3.Position
4.Velocity
Motion is a change in position measured by distance and time.
5) Select the best answer.
Which object will accelerate faster?
an object that has 500 N of force applied to it
an object that has 50 N of force applied to it
Answer:
I think the object with 500 N of force applied.
When white light shines on a thin film of soap, light is reflected from:.
When white light shines on a thin film of soap, light is reflected from back surface of the film only.
What is doppler shift?Doppler Shift is the change in frequency of sound based on the observer’s point of view.
When white light falls on a thin film of soap, light gets reflected and refracted inside the soap. This results in refraction of the reflected light rays.
When white light shines on a thin film of soap, light is reflected from the back surface of the film only.
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Help!
11. A string vibrates at a frequency of 15 Hz. What is its period?
12. A speaker vibrates at a frequency of 292 Hz. What is its period?
13. A swing has a period of 12 seconds. What is its frequency?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
As we know, period (t)of a wave and it's frequency (f) are Reciprocal of each other, so if one is know then we can just reverse the order to get the other one.
that is :
[tex]\qquad \sf \dashrightarrow \: frequency = \dfrac{1}{period} [/tex]
Now, let's move on to problems ~
# 11. f = 15 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{15} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.067 \: \: sec[/tex]
#12. f = 292 hertz, t = ?
[tex]\qquad \sf \dashrightarrow \: t = \dfrac{1}{292} \: \: sec[/tex]
[tex]\qquad \sf \dashrightarrow \: t \approx0.0034 \: \: sec[/tex]
#13. t = 12 seconds, f = ?
[tex]\qquad \sf \dashrightarrow \: f= \dfrac{1}{12} \: \: hertz[/tex]
[tex]\qquad \sf \dashrightarrow \: f \approx0.083 \: \: hertz[/tex]
We know that, frequency = reciprocal of the period of time an object swings or vibrates at. Therefore,
[tex]\tt\:FORMULA \downarrow\\\\\star\boxed{\mathfrak{Frequency = \frac{1}{period \: of \: time}}}[/tex]
Now, let's solve the questions by using this formula.
[tex]\rule{150pt}{2pt}[/tex]
11. Frequency = 15 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:15 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{15} = 0.67 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
12. Frequency = 292 Hz
Period = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:292 = \frac{1}{period}\\\boxed{\bf\:period = \frac{1}{292} = 0.0034 \: s}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
13. Period = 12 s
Frequency = ?
[tex]\sf\:Frequency = \frac{1}{period}\\\sf\:Frequency = \frac{1}{12}\\\boxed{\bf\:Frequency = 0.083 \: Hz}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
Note:The SI units of,
Frequency = Hertz (Hz)Period of time = Second (s / sec)[tex]\rule{150pt}{2pt}[/tex]
A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. it's momentum is 3 kg.m/sec. what is the mass of the beach ball?
Answer:
1/3 kg
Explanation:
Concepts
The formula p = mv tells us that momentum is mass times velocity. We can easily rearrange this equation to solve for m by dividing both sides by v:
p/v = mv/vm = p/vApplication
We are asked to find the mass of a beach ball, given the velocity as 9 m/s and the momentum as 3 kg · m/s. We can use the formula m = v/p to find the mass of the ball in kilograms.
Solution
[tex]m = \frac{3}{9}[/tex] [tex]m = 1/3[/tex]A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in the same direction at a spe
Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
What is conservation of momentum?Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v[/tex]
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,
[tex]v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}[/tex]
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,
[tex]v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}[/tex]
Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,
[tex]v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s[/tex]
Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
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Can someone please answer this, ill give you brainliest Would be very appreciated.
Answer:
frost wedging
Explanation:
When glaciers melt and the rock beneath is weathered and broken down, this is called frost wedging.
The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of which function(s)? tangent only cosine only sine and tangent cosine and sine
The formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.
What is vertical motion of a projecile?The vertical motion of a projectile is affected by gravity and the velocity of vertical motion given by the following formula;
Vy = Vsinθ
What is horizontal motion of a projecile?The horizontal velocity of a projectile is given by the following formula;
Vx = Vcosθ
Direction of the motionThe direction of the motion is calculated as follows;
tanθ = Vy/Vx
Thus, the formulas used to analyze the horizontal and vertical motion of projectiles launched at an angle involve the use of tangent, cosine and sine.
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Answer:
d
Explanation:
edg 2022
Starting at a position of 10m [W] of your car, you run to a position of 150m [W] of your car in 35s. What was your
velocity?
Answer:
4 m/s
Explanation:
you moved 140 meters in 35 seconds
v = 140 / 35 = 4 m/s
at 20° c, 33 meters of copper wire has a restaurants of 0.6 ohms. what is the resistance of 165 meters?
Resistance for 165 metres is 3 ohms.
What effect does the pendulum have on the time period if the length of string increases
Answer:
If the length of the pendulum string increases, the period of time increases
Explanation:
The period of a simple pendulum is directly proportional to the square root of length of the pendulum
Question 8 of 10
What type of optical device can be used to project an image onto a screen?
© A. Any mirror
• B. A convex lens
• C. A convex mirror
•
D. Any lens
Answer:
The correct answer is the Convex lens. An image is formed when a ray of light coming from a point intersects at another point. The image is formed by the real intersection of light. The image is formed by the virtual intersection of Light.
here is the site : textbook.com
‼️PLEASE ANSWER WILL MARK BRAINLIEST‼️
Answer:
b 1000
if you multiply 2m/s by 500 you get 1000 it should look like this.
500 x 2m/s
What is the speed of a wave with a frequency of 2 Hz and a wavelength of 87 m? 0. 023 m/s 43. 5 m/s 89 m/s 174 m/s.
The Andromeda Galaxy (our nearest spiral neighbor) has spectral lines that show a blue shift. From this we may conclude that:
The universe is the collection of galaxies, The Andromeda Galaxy has spectral lines with blue shift. The conclusion is that the Universe has stopped expanding.
What is Andromeda Galaxy?The Andromeda Galaxy is the nearest spiral neighbor that has spectral lines showing a blue shift.
Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.
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Consider a pendulum of length 3. 171 m. The acceleration of gravity is 9. 832 m/s2. A) what is its period at the north pole?answer in units of s
The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
What is time period of pendulum?Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.
The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.
It can be given as,
[tex]T=2\pi \sqrt{\dfrac{L}{g}}[/tex]
Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.
A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,
[tex]T=2\pi \sqrt{\dfrac{3.171}{9.832}}\\T=3.57\rm\; s[/tex]
Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.
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A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Another green arrow starts where the first arrow touched the wall and goes up and left at the same shallow angle. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction refraction reflection
Answer:
reflection
Explanation:
Answer: Reflection
Explanation: I have my ways :>
Two cats are sitting on a 30 m hill. One cat
has a mass of 4 kg and the other 6 kg.
Which cat has greater potential energy?
Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
Note:gravitational field in Earth is 10 N/kg = fixed unit
Given:1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
Solve for g.p.e:1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
Please help help help mee
Answer:
.60 A
Explanation:
The RMS (Root Mean Square) voltage (the effective voltage) of the PEAK voltage is .7 * peak
.7 * 425 = 297.5 v
Now, V = IR re-arranged to V/R = I
297.5 v / 500 ohm = .595 A = ~ .6 A
Directions: identify the input work and output work in the different situations.
1. A cyclist is pedaling on his bicycle.
2. You exert force to move a rake.
3. You sweep the dry leaves in your garden using bamboo.
4. Lifting a handless wheelbarrow.
5. Ben lifts the 50 kgs weight of barbel.
Answer:
it would have to be 1 or maybe 2
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm
The acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
What is center of mass?The center of mass of a object or for a system of object is the point, where the center of distribution of mass in space. The center of mass for the two bodies can be given as,
It can be given as,
[tex]x_{cm}=\dfrac{m_1x_1+m_2x_2}{m_1+m_2}[/tex]
Here, (m) represents the mass and (x) represents the distance.
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm has to be find out.
The image of the blocks-string-pulley system is attached below. The acceleration of this system is,
[tex]\vec a_{cm}=\left(\dfrac{m_1-m_2}{m_1+m_2}\right)g[/tex]
Thus, the acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
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Vector Q is 0.321 m long in a
123° direction. Vector S is
0.876 m long in a -32.1°
direction.
magnitude (m)
Find the magnitude of their vector sum
The magnitude of the vector sum of Q and S is determined as 0.6 m.
Resultant vector of Q and S
The magnitude of the vector sum of Q and S is determined from their resultant vector.
Qx = Qcosθ
Qy = Qsinθ
Qx = 0.321 x cos(123) = -0.175 m
Qy = 0.321 x sin(123) = 0.269 m
Sx = 0.876 x cos(-32.1) = 0.742 m
Sy = 0.876 x sin(-32.1) = -0.466 m
Qx + Sx = -0.175 m + 0.742 m = 0.567 m
Qy + Sy = 0.269 m - 0.466 m = -0.197 m
Resultant vectorR = √[(0.567)² + (-0.197) ²]
R = 0.6 m
Thus, the magnitude of the vector sum of Q and S is determined as 0.6 m.
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1. As a person stands on earth they put a force on the ground and the ground puts a force on them.
How do these forces compare?
2. The sheet on your bed gives negative charged electrons to your blanket on your bed. If both objects
started this interaction as neutral, what is the charge of the sheet now?
3. A batter swings a Louisville Slugger Baseball bat that has a charge of +12, while a pitcher throws a
baseball with a charge of -2. What is the net charge of the two objects in this scenario?
4. In the bat and ball example (above in question 3), what will the charge of the ball be after the batter
hits it with the bat?
5. We know that opposite charges attract each other, but according to Coulomb's Law what is the single
most important factor in the strength of these forces?
Answer:
mb
Explanation:
m b
Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
What is pascal law?Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.
Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\[/tex]
In case of radius,
[tex]\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}[/tex]
Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,
[tex]r_1=2.67\rm\; cm[/tex]
[tex]r_2=20.0\rm\; cm[/tex]
The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,
[tex]F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N[/tex]
Put the values in the above formula,
[tex]\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N[/tex]
Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.
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What are the minimum energies of the two oppositely directed gamma rays in a PET procedure?
The minimum energy of the two oppositely directed gamma rays in a PET procedure is : 0.51 MeV
What happens in a PET procedure ?In a PET procedure when an electron and positron collide the energy equivalent of their individual masses are converted into gamma rays which will move in directions opposite to each other.
Given that an electron and a positron posses equal masses the minimum energy of the gamma ray will be 0.51MeV
Hence we can conclude that the minimum energy of the two oppositely directed gamma rays in a PET procedure is 0.51MeV.
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A proton and an antiproton have equal energies of 450gev. The particles collide head-on. Find the available energy ea. The rest energy of the proton is 938mev
The available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
How to find the available energy after the collision?The available energy can be found out with the following formula.
[tex]E_a=\sqrt{2E_tE_k++(m_1c^2)^2+(m_2c^2)^2}[/tex]
Here C is the speed of light (3×10⁸ m/s), Et is the energy of proton, Ek is the rest energy.
A proton and an antiproton have equal energies of 450gev. The particles collide head-on. The rest energy of the proton is 938mev
Thus, put the given values in the above formula,
[tex]E_a=\sqrt{2(450\times\dfrac{10^9eV}{1MeV})(938\times\dfrac{10^6eV}{1MeV})+(938\times\dfrac{10^6eV}{1MeV})^2+(938\times\dfrac{10^6eV}{1MeV})}\\E_a=29\rm\; Gev[/tex]
Thus, the available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
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