Answer:
2 meter per second
Explanation:
kinetic energy = 1/2 m v^2
20J = 1/2 × 10 × v^2
v^2 = 4
v= 2 m/s
When the two surfaces of a thin film are parallel and the light is incident at some angle what fringes are formed? A. Circular B. Elliptical C. Parabolic D. Straight and why?
Answer:
The correct option is;
A. Circular
Explanation:
Some of the light that impinges on the surface are reflected and the rest are transmitted to a different medium
At the surface of the next medium also, some of the light are transmitted while the others are reflected and refracted through the first medium
The speed of light (and hence the wavelength and color) refracted through the thin film is changed as the distance the refracted light travels through the thin film is increased as we move away from the point directly in the front view to some distance as the reflected light path from those distance to the eye is increased due to their inclination giving them a different wavelength which are all equal at a radial distance from the eye hence forming a circular fringes.
What happens to energy “lost” during an energy transformation? A. It turns into heat energy. B. It turns into kinetic energy. C. It turns into potential energy. D. It turns into kinetic energy and potential energy.
Answer:
I think it turns into heat (thermal) energy if I'm right
The balloon contain no gas initially.When it is connected to the cylinder gas enters the balloon the pressure in the cylinder decreases.Explain why the molecules inside the cylinder exerts a large pressure initially
Answer:
17
Explanation:
121354
36- Why are sneakers and tires grooved?
SNEAKERS and tires are grooved so that there is some kind of interlock with it and the surface . This interlocking creates more friction and this friction enable the object to have some grip on the surface . If the sneakers or tires werent grooved,then with sneakers we might slip and fall and with tyres the car would skid
What is the kinetic energy of a 108 kg object that is moving with a speed of 11.1 m/s ?
Answer:
6,653.34 J
Explanation:
Kinetic energy can be found using the following formula.
[tex]KE=\frac{1}{2} mv^2[/tex]
where m is the mass in kilograms and v is the velocity in m/s.
The object is 108 kilograms and is moving at a speed of 11.1 m/s. Therefore, the mass is 108 kg and the velocity is 11.1 m/s.
m=108 kg
v=11.1 m/s
Substitute these values into the formula.
[tex]KE=\frac{1}{2}*108*11.1^2[/tex]
Evaluate the exponent first. 11.1^2 is the same as 11.1*1.11, which is equal to 123.21
[tex]KE=\frac{1}{2} *108*123.21[/tex]
Multiply 108 and 123.21
[tex]KE=\frac{1}{2}*13306.68[/tex]
Multiply 1/2 and 13306.68
[tex]KE=6653.34[/tex]
The kinetic energy of the object is 6,653.34 Joules (kg m2/s^2)
I NEED HELP ASAP
please please please
Answer:
B AND D
HOPE ITS HELF FUL .........
PLEASE HELP An object is thrown upward with an initial velocity of 32.1 m/s. What is its velocity in 4.0 s? (use g = 9.81 m/s2). Please include step by step process. -7.14 11.2 7.14 -4.6
Answer:
-7.14
Explanation:
According to equation of motion
v = u + at
where
v is the final velocity at any time t
u is the initial velocity
a is the acceleration
and t is the time
___________________________________________
Given
An object is thrown upward it means
its initial velocity is in upward direction
but acceleration due to gravity is in downward direction which will cause to decrease the velocity of object.
Intial velocity u = 31.1 m/s
final velocity v at 4 second we have to find.
t = 4 second
a = g = 9.81 m/s2 (it is acting in opposite direction of motion hence its sign will be negative ).
Thus
a = - 9.81 m/s2
using the above values in v = u + at
v = 32.1 - 9.81*4
v = 32.1 - 39.24
v = -7.14
Thus, correct option is -7.14.
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.
Answer:
Mass, m = 0.49 kg
Explanation:
It is given that,
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.
We need to find the mass of the ice.
On a sloping surface, the force with which it strikes is given by :
[tex]F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg[/tex]
So, the mass of the ice block is 0.49 kg.
Two identical 82 mg dust particles very far apart (PEE 0) are moving directly toward each other at a speed of 3698 m/s. The charge on each is-719 ?C. Determine how close they will get to each other. Let k = 9x109 N-m2/C2 & ignore gravity.
Answer:
r = 4.139
Explanation:
In order to calculate how close the particles will get to each other, you take into account that all kinetic energy becomes electric potential energy between the particles when they are at the minimum distance. Then, you have:
[tex]U=K\\\\k\frac{q_1q_2}{r}=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2[/tex] (1)
q1 = q2: charge of the dust particles = -719μC = -719*10^-6 C
m1 = m2: mass = 82mg = 82*10^-6 kg
v1 = v2: speed of both particles = 3698 m/s
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
You solve the equation (1) for r:
[tex]q_1=q_2=q\\\\m_1=m_2=m\\\\v_1=v_2=v\\\\k\frac{q^2}{r}=mv^2\\\\r=\frac{kq^2}{mv^2}[/tex]
Finally, you replace the values of all parameters:
[tex]r=\frac{(8.98*10^9Nm^2/C^2)(-719*10^{-6}C)^2}{(82*10^{-6}kg)(3698m/s)^2}\\\\r=4.139m[/tex]
hence, the distance at which both dust particle are closer to each other is r = 4.139m
What is true about the force between charges?
Explanation:
The force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
k is electrostatic constant
r is distance between charges
The force between charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.
Rutherford predicted that an atom has a dense core called a(n) __________
Rutherford predicted that an atom has a dense core called a nucleus.
What is nucleus of atoms?Ernest Rutherford discovered in 1911 that every atom has a nucleus in its center. Electrically charged protons and electrically neutral neutrons make up atomic nuclei. The strongest fundamental force known to science, often known as the strong force, holds these things together.
The nucleus normally comprises more than 99.9% of the atom's mass but occupies far less than.01% of its volume. The negatively charged electrons that surround a substance's nucleus determine its chemical makeup. In most cases, the number of protons in the nucleus corresponds to the number of electrons.
Some nuclei are unstable and can decay radioactively, releasing photons (gamma decay), electrons or positrons (beta decay), helium nuclei (alpha decay), or a combination of these. Eventually, these unstable nuclei reach a stable state.
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A bowling ball collides with a tennis ball. Which object has the larger impact force on the other considering that they have the same acceleration? Why?
This is for an exam could you please answer fast
Answer:
The tennis ball experiences a larger impact force due to its smaller mass.
Explanation:
Considering that they have the same acceleration, and F = ma where F is force and m = mass, the object with the smaller mass has a greater impact force on it.
This is because since force F = ma and a = constant, the object with a larger mass (the bowling ball)has a larger impact force with which it acts on the object with the smaller mass (the tennis ball). So, the tennis ball experiences a larger impact force due to its smaller mass.
At which of the following points does a roller coaster have the most potential energy? As it is going down a hill. At the top of the hill. As it is climbing a hill. At the bottom of the hill.
Answer:
At the top of the hill.
Explanation:
As the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases .
As it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum .
As it goes down the hill, K.E starts to increase and G.P.E decrease .
At the bottom of the hill, K.E reaches maximum and G.P.E becomes zero .
(Correct me it I am wrong)
At the top of the hill.
The following information should be considered:
In the case when the roller coaster goes up the hill, kinetic energy (K.E) decreases, gravitational potential energy (G.P.E) increases . When it reach the top of the hill, K.E becomes zero and G.P.E reaches maximum . When it goes down the hill, K.E starts to increase and G.P.E decrease . When it is the bottom of the hill, K.E reaches maximum and G.P.E becomes zero.Learn more: https://brainly.com/question/1605083?referrer=searchResults
Which statement is part of Dalton's atomic theory?
A. Atoms are composed of protons, neutrons, and electrons.
B. Elements can have atoms that are isotopes.
C. One type of atom cannot be changed to another type by a chemical reaction.
D. Electrons move around the nucleus in an electron cloud.
A. Atoms are composed of protons, neutrons, and electrons.
In the first section of his thesis, he claims that all matter is composed of indivisible atoms. The second part of the theory states that every atom in a certain element has the same mass and properties. Compounds, according to the third section, are combinations of two or more different kinds of atoms. Thus, option A is correct.
What best define about Dalton's atomic theory?Atoms are the incredibly minuscule building blocks of all stuff. A given element's atoms are all the same size, mass, and other characteristics. Distinct elements' atoms have different mass, size, and other characteristics. Atoms can never be divided, produced, or eliminated.
Atoms are indivisible units that cannot be created or destroyed during a chemical process. Each atom of a certain element has the same mass and chemical properties. Atoms of various elements have weights and chemical properties that differ.
Therefore, Compounds are created when atoms combine in ratios of small whole numbers.
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A projectile is launched with an initial velocity of 25 m/s at an angle of 30° above the horizontal. The projectile reaches maximum height at point p then falls to point a, which is 65 m below the cliff. What is the horizontal distance that it travels (labeled x in the diagram)
Answer:
x ≈ 56 m
Explanation:
vertical initial velocity =[tex]v_{0y}(t)[/tex] = 25 m/s* sin(30°)= 12.5 m/s
height = h
[tex]h =v_{0y}t+\frac{at^{2}}{2} \\\\65m = 12.5m/s*t + \frac{9.8m/s^{2}*t^{2}}{2} \\\\t=2.584 s[/tex]
t- time is found solving quadratic equation.
horizontal velocity = [tex]v_{0x}=25m/s*cos(30^{o})=21.65 m/s[/tex]
Horizontal velocity is constant, so distance [tex]x=v_{0x}*t =21.65 m/s *2.584 s=55.9 = 56 m[/tex]
The horizontal distance travelled by the object will be "111.07 m".
According to the question,
[tex]u_v = u sin\Theta[/tex]
[tex]= 25 \ sin30^{\circ}[/tex]
[tex]= 12.5 \ m/s[/tex]
As we know,
→ [tex]s = ut +\frac{1}{2} at^2[/tex]
[tex]-y = u_vt-\frac{1}{2}gt^2[/tex]
[tex]-65 =12.5t - \frac{1}{2}\times 9.8t^2[/tex]
[tex]0 = 4.9t^2-12.5t-65[/tex]
[tex]t = \frac{12.5 \pm \sqrt{(-12.5)^2-4\times 4.9\times (-65)} }{2\times 4.9}[/tex]
[tex]= 5.13 \ s[/tex]
hence,
The horizontal distance will be:
→ [tex]u_x = ucos \Theta[/tex]
[tex]= 25 cos 30^{\circ}[/tex]
[tex]= 21.65 \ m/s[/tex]
or,
→ [tex]x = 21.65\times 5.13[/tex]
[tex]= 111.07 \ m[/tex]
Thus the response above is right.
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Which statement describes the energy involved in diffusion?
hope that helps
Explanation: Diffusion requires energy only to move material in through the cell membrane. Diffusion does not require energy in any situation. Diffusion requires energy only to move material out through the cell membrane.
Answer:
The answer is B >:3
Explanation:
Una pelota cae con una energía de 1 J y bota al llegar al suelo. Si tras el bote su energía es de 0,998 J, ¿podemos afirmar que la energía se ha destruido?
Answer:
The energy is not destroyed, the energy has been transformed into another kind of energy, in this case to heat with energy of 0,002 J
Explanation:
One of the fundamental principles of physics states that energy is neither created nor destroyed, it is only transformed.
In this case, when the ball with an energy of 1 J bounces on the ground, it loses an energy equivalent to 1-0.998 J = 0.002 J. This energy of 0.002 J is not destroyed in the process, but is transformed into another type of Energy. In this case, said energy has been converted to heat. A heat equivalent to 0.002 J of energy.
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Translation to spanish
Uno de los principios fundamentales de la física afirma que la enegía no se crea ni se destruye, sólo se transforma.
En este caso, cuando la pelota con una energía de 1 J rebota en el suelo pierde una energía equivalente a 1-0,998 J = 0,002 J. Esta energía de 0,002 J no se destruye en el proceso, sino que se transforma en otro tipo de energía. En este caso dicha energía se ha convertido en calor. Un calor equivalente a 0,002 J de energía.
Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles
traveled in a straight line and some were deflected at different angles.
Which statement best describes what Rutherford concluded from the motion of the particles?
Answer:
C
Explanation:
I just took the quiz
which statement BEST compares the force of gravity on a school bus on a school day and a weekend? *
(A) The force would be lower on the school day than the weekend.
(B) The force would be higher on the school day than the weekend.
(C) The force would be different on the school day than the weekend.
(D) The force would stay the same on the school day and the weekend.
Answer:
(A) The force would be lower on the school day than the weekend.
Explanation:
In a school day the bus is on the road travelling with kids. But in a weekend it is parked. When a object stays still that means the the force which is working on the earth by the bus is equal to the force which works on the bus by the earth. we can understand it clearly by, Newton's second law of motion.
This pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. so as it is when it is balanced it is not moving.
And on a school day the bus is moving so it has a force pulling itself forward . so it means that the force which the bus has is greater than the gravitational force.
Please help me out
1. A 5.0 V battery contains 775 C of charge. How much electricity energy can it produce?
2. 200 C of charge passes through a circuit in 20 minutes. What is the current?
3. A battery can produce 337 joules of energy for every 9.5 coulombs of charge. What is its voltage?
Answer:
1.3875 Joules. 2. 0.17A 3. 35.47volts
Explanation:
1. Energy = Q × V = 5 × 775 = 3875 Joules.
Q is quantity of electricity in Columbs
V is Voltage in volts
2. From Q = I × t
Q is quantity of electricity in Columbs
T is time taken
I is current
Now we define I as the quantity of electricity in 1 sec; hence;
200= I × 20× 60 [ 20minutes converted to seconds ]
I = 200/ 20× 60.= 200/1200=0.1667
= 0.17A( to the nearest hundredth)
3.v = E/ Q ( from equation in question 1)
V = 337/9.5 = 35.47volts
When you push with a horizontal 15-N force on a book that slides at constant
velocity, the force of friction on the book is
A.Slightly more than 15 N
B.0N
C.Slightly less than 15 N
D.15 N
Answer:
f = 15 N
Explanation:
It is given that, when you push with a horizontal 15-N force on a book that slides at constant velocity, a frictional force also acts on it. Frictional force is an opposing force. The magnitude of applied force and frictional forces are same. So, the force of friction on the book is equal to 15 N.
Find the average speed of a car that is travelling 45 km in 5 hours. *
4 points
6 km/h
8 km/h
9 km/h
20 km/h
Answer:
9 km/h
Explanation:
Speed can be found using the following formula.
s=d/t
where d is distance and t is time.
The car traveled 45 kilometers in 5 hours.
d=45 km
t=5 h
Substitute these values into the formula
s=45 km/5 h
Divide 45 by 5
s=9 km/h
The average speed of the car is 9 kilometers per hour.
The mass of the jupiter is 19*10^26kg &the mass of the earth is 6*10^24kg.if the distance between the jupiter &earth is 6.29*10^6km.what will be the gravitational force between these two masses?
Jack plays floor hockey. He moves with a velocity of 7.5 m/s [East] for 2.25 seconds. What is his displacement during this time? show your work below.
Answer:
16.875 m [East]
Explanation:
In a velocity time displacement problems
displacement is given by
displacement of moving body = velocity of the that body * time
displacement will be in the direction of velocity of body.
Given
velocity = 7.5 m/s [East]
time = 2.25 seconds
displacement = 7.5 m/s [East] *2.25 seconds
displacement = 16.875 m [East]
Thus, displacement of jack is 16.875 m [East].
A boat sends an ultrasound signal of frequency 30 kHz, and receives the signal after 6 s. If the speed of sound in water is 1500 m/s, then find the depth of the ocean.
PLEASE HELP
Answer:
4500
Explanation:
hey there!
first we convert the khz to hz=30000hz
we use the formula 2d=distance×time
2d=1500×6
d=9000/2=4500
i think this is the right answer....
hope this helps u :)
An object started at
x = -22 meters and undergoes
a displacement of -10.4 meters.
What is its final position?
(Unit = m)
Answer:
According to me, I think this is the answer
Explanation:
initial position= -22 meters.
this indicates that object is in the negative direction as a negative sign is used to represent the location.
displacement is indicated as -10.4 meters. this is also in the negative direction.
initial + displacement= final
= -22 + (-10.4)
= -32.4 meters
this would be the final position, away from the origin.
displacement is a vector quantity; both magnitude and direction matter.
4. A moped travels 20 kilometers in 30 minutes. Calculate its average speed in km/h?
Answer:
[tex] \boxed{Average \: speed = 40 km/h} [/tex]
Explanation:
Distance travelled = 20 km
Time taken = 30 min
= [tex] \frac{30}{60} [/tex] h
= [tex] \frac{1}{2} [/tex] h
[tex]Average \: speed = \frac{Distance \: travelled}{Time \: taken} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{20}{ \frac{1}{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \div \frac{1}{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 20 \times 2 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 40km/h[/tex]
Distance travelled can be found from the
A area under a velocity-time graph
B area under an acceleration-time graph
C gradient of a force-time graph
D gradient of a velocity-time graph
Answer:
A
Explanation:
This is because distance traveled (i.e. displacement) is the integral of the velocity function, and velocity is the first derivative of the displacement function. To put this in perspective, the area bounded by a curve can be found by taking the integral of the equation of the curve, taking values on the x-axis as limits.
Thermal insulators have _____.
A. high specific heat
B. high kinetic energy
C. lots of air pockets
D. low latent heat
E. strong molecular bonds
Answer:
The correct answer to the following question will be Option A (High specific heat).
Explanation:
A thermal or heat insulator has been used to help avoid heat from travelling from one location to the another.
Specific heat seems to be important unless you consider whether the temperature including its insulator becomes evolving. Whether it has a high specific heat, it will take more energy just to increase the temperature, as well as it can also allow somewhat when it happens to come to insulating material, and therefore heat transaction or energy transactions are often influenced by a temperature gradient.Other given choices are not related to the given scenario. So that Option A seems to be the right answer.
The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give the values r = 32700 ft, r¨ = 85 ft/sec2, and θ˙ = 0.019 rad/sec. Calculate the magnitudes of the velocity and acceleration of the rocket at this position.
Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
The magnitude of the linear velocity of the rocket at the given position is 1,667.2 ft/s.
The magnitude of the acceleration of the rocket at the given position is 90.73 ft/s².
The given parameters;
angular distance, θ = 66⁰radius of the path, r = 32700 ftcentripetal acceleration, ac = 85 ft/s²initial angular velocity, ωi = 0.019 rad/sThe linear velocity and final angular velocity of the rocket is calculated as follows;
[tex]a_c = \frac{v^2}{r} \\\\v^2 = a_c \times r\\\\v = \sqrt{a_c r} \\\\v = \sqrt{85 \times 32700}\\\\v = 1667.2 \ ft/s\\\\\omega_f = \frac{v}{r} = \frac{1667.2}{32700} = 0.051 \ rad/s[/tex]
The radial acceleration of the rocket is calculated as follows;
[tex]\omega_f^2 = \omega_i^2 + 2\alpha _r \theta\\\\(0.051)^2 = (0.019)^2 + 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r)\\\\(0.051)^2 - (0.019)^2 = 2(66^0 \times \frac{2\pi \ rad}{360 ^0} )(\alpha _r) \\\\0.00224 = 2.304\alpha _r\\\\\alpha _r = \frac{0.00224 }{ 2.304} \\\\\alpha _r = 0.00097 \ rad/s^2[/tex]
The tangential acceleration is calculated as follows;
[tex]a_t = \alpha_r \times r\\\\a_t = 0.00097 \times 32700\\\\a_t = 31.72 \ ft/s^2[/tex]
The resultant acceleration of the rocket is calculated as follows;
[tex]a = \sqrt{a_t^2 + a_c^2} \\\\a = \sqrt{31.72^2 \ + \ 85^2} \\\\a= 90.73 \ ft/s^2[/tex]
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