If 95.0 g Zn is added to an excess of H2SO4, how many
liters of hydrogen gas will be produced at STP?
Write and balance the equation. Then, calculate the
liters of hydrogen produced.

Please help

If 95.0 G Zn Is Added To An Excess Of H2SO4, How Manyliters Of Hydrogen Gas Will Be Produced At STP?Write

Answers

Answer 1

Answer:

32.7 L of H₂

Explanation:

We'll begin by calculating the number of mole in 95 g of Zn. This can be obtained as follow:

Mass of Zn = 95 g

Molar mass of Zn = 65 g/mol

Mole of Zn =?

Mole = mass /Molar mass

Mole of Zn = 95/65

Mole of Zn = 1.46 mole

Next, we shall determine the number of mole of H₂ produced by the reaction of 95 g (i.e 1.46 mole) of Zn. This can be obtained as illustrated below:

Zn + H₂SO₄ —> ZnSO₄ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 1.46 mole of Zn will also react to produce 1.46 mole of H₂.

Finally, we shall determine the volume of H₂ obtained at STP. This can be obtained as follow:

1 mole of H₂ = 22.4 L at STP.

Therefore,

1.46 mole of H₂ = 1.46 × 22.4

1.46 mole of H₂ = 32.7 L at STP

Thus, 32.7 L of H₂ were obtained from the reaction.


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Answers

Answer:

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Explanation:

Hope this helped Mark BRAINLEST!!!!

In the given question, the chemical name for [tex]\rm OBr_2[/tex] is oxygen dibromide.

A chemical name is a unique name given to a chemical compound that accurately describes its chemical composition.

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Therefore, oxygen dibromide is the chemical name for [tex]\rm OBr_2[/tex]. It is a covalent compound and has oxygen as a central atom.

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A 9.56 sample of CuS is found to contain 6.35 g of copper what is the percent by mass of the copy and sulfur in this compound? (show your work)

Answers

Answer:

%Cu = 66.4%

%S = 33.6%

Explanation:

Step 1: Given data

Mass of CuS: 9.56 gMass of Cu: 6.35 g

Step 2: Calculate the mass of S

The mass of CuS is equal to the sum of the masses of Cu and S.

mCuS = mCu + mS

mS = mCuS - mCu

mS = 9.56 g - 6.35 g = 3.21 g

Step 3: Calculate the percent by mass of each element

We will use the following expression.

%Element = mElement / mCompound × 100%

%Cu = mCu / mCuS × 100% = 6.35 g / 9.56 g × 100% = 66.4%

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Answers

Answer:

See explanation and image attached

Explanation:

The reaction shown here is the reaction between an acyl chloride and a carboxylic acid. This reaction produces an acid anhydride.

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Answers

Answer:

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Explanation:

Hello!

In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:

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I think is D A have a nice day
Good luck bye

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Answers

Answer:

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Explanation:

We'll begin by calculating the mass of oxygen in 1 mole of carbon dioxide (CO₂). This is illustrated below:

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Explanation:

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Answers

Answer:

7.12 × 10⁻³ M/s

Explanation:

Step 1: Write the balanced reaction

2 SO₂ + O₂ ⇒ 2 SO₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to SO₃ is 1:2.

Step 3: Calculate the rate of formation of SO₃

The rate of loss of O₂ is 3.56 × 10⁻³ mol O₂/L.s. The rate of formation of SO₃ is:

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Answers

Answer:

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Answers

Answer:

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Explanation:

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Explanation:

this is the answer please mark me as brainleist

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Answers

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Explanation:

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Answers

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Answers

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