If 6.34 g of CuNO, is dissolved in water to make a 0.720 M solution, what is the volume of the solution in milliliters?

Answers

Answer 1

V=n/M

V=(6.34:125.55 g/mol)/0.72

V=0.07 L = 70 ml


Related Questions

balance the chemical
reaction by providing the
correct coefficient

Answers

Answer:

2HBr + Ba(OH)2 ____ BaBr2 + 2H2O

The numbers placed in front of formulas to balance equations

A dunk tank hold 30,533 moles of water? How many grams of water are in the tank?

Answers

30,000 thousand moles is the answer! trust!
the answer is 30,000 moles

How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?

Answers

molarity =wt/M.wt * 1000/V

=> 1.77 = wt/180 * 1000/555

> wt = 1.77 * 180*555 /1000 = 176.823 g

Which of the following statements about carbon dioxide is not true?
Increased carbon dioxide in the atmosphere increases the Greenhouse Effect.
Carbon dioxide is a greenhouse gas.
Atmospheric carbon dioxide levels have slowly declined over the last 50 years.
Burning fossil fuels can increase carbon dioxide levels in the atmosphere.

Answers

3rd one is the correct one because I remember taking a test when i had chemistry

B. Flourine is the right answer

Answers

Answer:

Whts ur question??

..?

Explanation:

Was this by mistake or smthin

Use the chemical equation to answer the question.
2H₂(g) + O₂(g) → 2H₂O(1)
Which statement describes the breaking and forming of bonds in the reaction?

The reaction requires breaking one H-H bond and two O=O bonds, and then forming four O-H bonds.

The reaction requires breaking one O=O bond and two H-H bonds, and then forming four O-H bonds.

The reaction requires breaking four O-H bonds, and then forming one H-H bond and two O=O bonds.

The reaction requires breaking four O-H bonds, and then forming one O=O bond and two H-H bonds

Answers

Answer: The reaction requires breaking one O=O bond and two H-H bonds, and then forming four O-H bonds.

Write and balance molecular equations for the following reactions between aqueous solutions. You will need to decide on the formulas and phases of the products in each of the cases.

An aqueous solution of barium hydroxide is mixed with an aqueous solution of sulfuric acid.

Answers

Answer:

Ba(OH)2(aq) + H2SO4(aq) ----> BaSO4(s) + 2H2O(l)

Use Table B in your Student Guide to answer the questions about ion concentrations.
A solution with a pH = 13 has approximately how many moles of OH ions per liter?
How many moles of H* would this same solution have per liter?
(Use the decimal form of your answer.)
A different solution with an H+ concentration of 1.0 x 10-4 would have a pH =

Answers

Question 1

[tex]\text{pH}=-\log(\text{H}^{+})\\\\13=-\log(\text{H}^{+})\\ \\ \text{[H}^{+}]}=1 \times \boxed{10^{-13} \text{ moles per liter}} \\ \\ \text{[H}^{+}] \times \text{[OH}^{-}] =1 \times 10^{-14} \text{ M}\\\\\text{[OH}^{-}]=\boxed{1 \times 10^{-1} \text{ moles per liter}}[/tex]

Question 2

[tex]\text{pH}=-\log(\text{H}^{+})\\\\\text{pH}=-\log(1.0 \times 10^{-4})=\boxed{4}[/tex]

Determine how many kilojoules are absorbed when 341 g of Ca(OH)2 reacts via the following reaction:

Ca(OH)2(s)→CaO(s)+H2O(l),ΔH=+65.3kJ

Answers

305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex]reacts via the following reaction.

What is enthalpy?

The sum of the internal energy and the product of the pressure and volume of a thermodynamic system.

Given data:

[tex]Ca(OH)_2[/tex] (s) → [tex]CaO(s)+H_2O(l)[/tex],      ΔH=+65.3kJ

Moles of [tex]Ca(OH)_2[/tex]= [tex]\frac{mass}{molar \;mass}[/tex]

Moles of [tex]Ca(OH)_2[/tex] = [tex]\frac{341 g }{74g/mol}[/tex] =4.68 moles

Since, 1 mol [tex]Ca(OH)_2[/tex] absorbs 65.3kJ.

Therefore, 4.68 moles [tex]Ca(OH)_2[/tex] produce energy = 65.3kJ X 4.68 moles

=305.6KJ

Hence, 305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex] reacts via the following reaction.

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Select the correct answer.
In a given chemical reaction, the energy of the products is greater than the energy of the reactants. Which statement is true for this reaction?
A. Energy is absorbed in the reaction.
B. Energy is released in the reaction.
C. No energy is transferred in the reaction.
D. Energy is created in the reaction.
E. Energy is lost in the reaction.

Answers

Energy is absorbed in the reaction

What type of reaction is illustrated?

Answers

Answer:

Synthesis

Explanation:

Carbon + Difluorine = Tetrafluoromethane.

1 mole of Carbon [C] reacts with 2 moles of Difluorine [F2] to form 1 mole of Tetrafluoromethane [CF4]

i think it would be A

What type of reaction is represented by the following equation?

Mg(OH)2 (aq) + 2 HCl (aq) --> MgCl2 (aq) + 2 H2O (l)

Answers

Answer: Double replacement reaction

Explanation:

Explain how you would determine the charge of a metal, a non
metal and a transition metal for an ion within a compound. Be
prepared to provide the charge of an element on the periodic
table from each of these categories.

Answers

Answer:

In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.

Explanation:

To further explain this, there is 18 groups of the periodic table.  These groups include:

Group 1: The alkali metals have a 1+ charge for their entire group.

For example: Sodium would have a charge of 1+.

Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.

Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.

Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.

Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+

Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.

Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.

Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.

Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.  

A

Calculate the number of C atoms in 0.524 mole of C.

B

Calculate the number of SO2 molecules in 9.87 moles of SO2

C

Calculate the moles of Fe in 1.40x10^22 atoms of Fe

D

Calculate the moles of C2H6O in 2.30x10^24 molecules of C2H6O

Answers

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of [tex]SO_2[/tex] molecules in 9.87 moles  [tex]SO_2[/tex] is 59.43 molecules.

The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe is 0.23 x [tex]10^{-1}[/tex]

The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex] is 3.81.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × [tex]10^{23}[/tex] x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of [tex]SO_2[/tex] molecules in 9.87 moles of [tex]SO_2[/tex]:

6.02214076 × [tex]10^{23}[/tex] x 9.87

59.4385293 molecules= 59.43 molecules

C. The moles of Fe in 1.40 x [tex]10^{22}[/tex] atoms of Fe:

1.40 x [tex]10^{22}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

0.2324754694 x [tex]10^{-1}[/tex] moles.

0.23 x [tex]10^{-1}[/tex] moles.

D. The moles of [tex]C_2H_6O[/tex] in 2.30x[tex]10^{24}[/tex] molecules of [tex]C_2H_6O[/tex]:

2.30x[tex]10^{24}[/tex] ÷ 6.02214076 × [tex]10^{23}[/tex]

3.819239854 moles=3.81 moles

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Under which conditions of temperature and pressure, the real gas behave ideally?​

Answers

Answer:

A real gas will act as an ideal gas under high temperature and at a low pressure.

Real gases are non-ideal gases whose molecules occupy space and have interactions, consequently, they do not adhere to the ideal gas law.

An ideal gas has molecules that occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Explanation:

The physical matter of which living or nonliving things are composed is called a ___
(Fill in the blank one word)

100 POINTS TO WHO EVER IS CORRECT!

Answers

Answer:

Substance

Explanation:

Any physical matter despite of living or non living things are composed by a set of molecules or atoms commonly known as substance

On specific living things are composed of biomolecules or cells where as non living things are composed of molecules and atoms

Answer:

Substances

Physical matters are divided into 3 states

solid stateLiquid stateGaseous state

As per randomness of particles the order is

Gaseous>Liquid>Solid

What would most likely happen when a metal is heated?

It will melt.
It will solidify.
Its temperature will decrease.
Its particles will move slower.

Answers

It will melt

This is because the molecules in the metal begin to move faster and faster turning from solid to liquid

Answer: it is A i took the test i got it right

Explanation: i took the test

Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

Answers

Avogadro's law states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] atoms. This means that in the given sample, there are

[tex]\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}[/tex]

The atomic mass of sulfur is 32.06 amu.The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is

[tex]32.06+2(15.9994=64.0588 \text{ g/mol}[/tex]

Therefore, the mass is:

[tex](64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}[/tex]

Which of the following alkali metal is expected to melt if the room temperature
rise to 30oc (a) Na (b) K (c) Rb (d) Cs

Answers

The answer is the first option that is Na

Hydrogen and iodine vapour exist in equilibrium with hydrogen iodide at a constant temperature in a gas syringe.

H2 + I2

2HI

Which of the following will increase when the pressure is increased at constant temperature? [Assume that the mixture shows ideal behavior.]

Answers

The pressure has no effect on the equilibrium constant.

What is Equilibrium ?

Equilibrium is a state when the forward reaction rate is equal to the backward reaction rate .

The equation given is

H₂ + I₂ ⇄ 2HI

The Equilibrium constant depends only upon temperature and nature of reaction ,

It is independent of  catalyst presence , initial concentration of reactants,and pressure.

The pressure has no effect on the equilibrium constant.

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How many grams of copper

Answers

The mas of copper is 217.3 grams.

You need to measure out exactly 6.7 mL of water for an experiment. Which of the following would be the best tool for the job?

a. A 250 mL beaker​​​

c. A 50 mL graduated cylinder

b. A 10 mL graduated cylinder​​

d. A 150 mL Erlenmeyer flask

Answers

Answer:

The answer for this problem would be "b. A 10 mL graduated cylinder".

Explanation:

The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.

For example using a teaspoon to measure something rather than a cup.

The answer will be 10mL graduated cylinder

An unknown compound contains only C , H , and O . Combustion of 6.80 g of this compound produced 16.0 g CO2 and 4.37 g H2O . What is the empirical formula of the unknown compound?

Answers

Answer:

I am a small palm-sized pointing device

Why is a low concentration of CO2 in our blood good while a high concentration is bad?

Answers

Carbon dioxide in your blood usually causes no problems. But if you have too much or too little of it, you may have a disease or a health emergency.

What is carbon dioxide?

Carbon dioxide (CO2) is an odourless, colourless gas.

A high concentration can displace oxygen in the air. If less oxygen is available to breathe, symptoms such as rapid breathing, rapid heart rate, clumsiness, emotional upsets and fatigue can result.

As less oxygen becomes available, nausea and vomiting, collapse, convulsions, coma and death can occur.

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How many grams of solid barium sulfate form when 32.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate? Aqueous sodium chloride forms also.

Answers

Considering the reaction's stoichiometry and the notion of molarity, 1.167 grams of solid barium sulfate form when 32.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate.

The balanced reaction is:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2 NaCl(aq)

What is a Limiting Reagent?

The reactant that is consumed first in a chemical reaction is the limiting reagent because it stops any more reactions from taking place. The limiting reagent controls how much product is produced during the reaction.

Utilizing the reaction stoichiometry and the estimated number of moles, it is possible to identify the limiting reagent.

According to reaction stoichiometry, which describes the proportions of reagents and products in a chemical reaction, the following numbers of moles of each component are involved in the reaction:

BaCl₂: 1 moleNa₂SO₄: 1 moleBaSO₄: 1 moleNaCl: 2 moles

Molarity, on the other hand, refers to how many moles of solute are dissolved in a certain volume.

Molarity is determined by the expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units[tex]\frac{moles}{L}[/tex].

In this case, 32.0 mL= 0.032L (being 1000 mL= 1 L) of barium chloride reacts. So, by definition of molarity, the number of moles that participate in the reaction is calculated as:

[tex]0.160 M=\frac{No. of moles of solute}{0.032L}[/tex]

No of moles of barium chloride(solute) = 0.160M × 0.032L

No of moles of barium chloride(solute) = 0.00512moles

On the other side,70.0mL= 0.070 L of 0.065 M sodium sulfate reacts. So, by definition of molarity, the number of moles that participate in the reaction is calculated as:

[tex]0.065 M =\frac{No of moles of solute}{0.070L}[/tex]

No of moles of Sodium sulfate= 0.065M × 0.070L

No of moles of Sodium sulfate = 0.0045moles

if by stoichiometry 1 mole of barium chloride reacts with 1 mole of sodium sulfate, 0.00512moles of barium sulfate reacts with how many moles of sodium sulfate?

No. of moles of sodium sulfate=

[tex]\frac{ 0.00512moles of barium sulfate * 1 mole of sodium sulfate}{1 mole of barium chloride}[/tex]

amount of moles of sodium sulfate= 0.00512 moles

But 0.00512moles of sodium sulfate are not available, 0.0045moles  moles are available. Since you have fewer moles than you need to react with  0.00512moles of barium chloride, sodium sulfate will be the limiting reagent.

Then, it is possible to determine the number of moles of barium sulfate produced by another rule of three: if by stoichiometry 1 mole of sodium sulfate produces 1 mole of barium sulfate, 0.00512 moles of sodium sulfate produces how many moles of barium sulfate?

[tex]Amt of mole of barium sulfate=\frac{0.00512 moles of sodium sulfate* 1mole of barium sulfate}{1 mole of sodium sulfate}[/tex]

amount of moles of barium sulfate=  0

Being the mass molar of barium sulfate is 233.34 g/mole, the mass-produced of the compound is calculated as:

                              = [tex]\frac{0.00512 moles * 233.34 gm}{1 mole}[/tex]

                              =1.167 gm

Hence, 1.167 gm of solid barium sulfate is formed.

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Explain how to get it Thanks

Answers

The Ammonia present in 2.5 mole of Ammonia is 42.5grams.

What is a mole ?

A mole is a measuring unit in Chemistry to measure the number of atoms in certain molar mass of a substance.

It is given that 2.5 mole of Ammonia is present

Grams of Ammonia present in 2.5 mole of Ammonia = ?

Molecular weight of Ammonia = 17 grams.

1 mole of Ammonia = 17 grams of Ammonia

2.5 mole of Ammonia = 17 * 2.5

= 42.5 grams

Therefore 42.5 grams of Ammonia is present in 2.5 mole of Ammonia.

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How would you draw the ionic compound Beryllium Arsenide lewis structure?

Answers

Answer:

[Na]^+ [Cl]^-

Explanation:

Lets say its sodium, its number of electrons is 11, but when its stable (an ion), it is 10. and chloride, number of electrons is 17, but when its stable (an ion) it is 18. So the lewis structure for that is, remember with the straight brackets (not sure what it's called, but you know what I mean I guess) its this one: [ ]

Sodium will be + because it has more protons (11-10 = +1), and chloride will be - because it gained an electron, so has more electrons than protons (17-18 = -1)

So the lewis structure would be:

[Na]^+  for sodium

and

[Cl]^- for chlorine

Sodium chloride:

[Na]^+ [Cl]^-

Also just to add, only 1 of each atom (Na and Cl) was needed for the bonding, but if let's say example; 2 Cl was needed to bond with sodium, there would be 2 Cl (same) and 1 Na.

25. What is the equilibrium constant expression for the following? 2Hg (g) + O₂(g) → 2HgO (s) A. K= [Hg] [0₂]. B. K= [HgO]/([Hg]²[0₂]) M C. K=[2HgO]/([2Hg][0₂]). D. K=1/([Hgl [02]) 25. What is the equilibrium constant expression for the following ? 2Hg ( g ) + O₂ ( g ) → 2HgO ( s ) A. K = [ Hg ] [ 0₂ ] . B. K = [ HgO ] / ( [ Hg ] ² [ 0₂ ] ) M C. K = [ 2HgO ] / ( [ 2Hg ] [ 0₂ ] ) . D. K = 1 / ( [ Hgl [ 02 ] )​

Answers

Answer:

2 Hg (g) + o2 ---> 2 H2o

equilibrium constant

K = (c) (d) / (a)(b)

K= ( H2o)²/(He) ²(o2)

12. Consider the system PCl3(g) + Cl2(g) PCl5(g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C. When some Cl2(g) is added at constant volume and temperature, the ratio of the partial pressure of PCl5 to the partial pressure of PCl3 wil

Answers

For a system PCl3(g) + Cl2(g) PCl5(g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C, the ratio of the partial pressure of PCl5 to the partial pressure of PCl3 is will increase

What is the ratio of the partial pressure of PCl5 to the partial pressure of PCl3?

Generally, the equation for chemiecal reaction is mathematically given as

PC3 (g) + C₁₁₂ (g) = PC15 (g) 3

Assuming the addition of some Cl2 gas. The reaction will shift to the right at the invariant volume temperature, maintaining equilibrium. This results in a rise in P9Cl5(g) and a fall in PpCl3(g).

PpCl (g) /PpCl (g) will increase

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The ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increase for a system PCl₃ (g) + Cl₂ (g) --> PCl₅ (g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C when some Cl₂ (g) is added at constant volume and temperature.

What is the ratio of the partial pressure of  PCl₅ to the partial pressure of  PCl₃?

Generally, the equation for chemical reaction is mathematically given as ;

PCl₃ (g) + Cl₂ (g) --> PCl₅ (g)

Assuming the addition of some Cl₂ gas,

The reaction will shift to the right at the constant volume and temperature, maintaining equilibrium.

This results in a rise in PCl₅ (g) and a fall in PCl₃(g).

Hence, the ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increases

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You are working with a concentrated solution of ammonium hydroxide. Which
piece of safety equipment is most important to have on hand?

Answers

Rubber gloves and other chemical resistant protective clothing are necessary when handling concentrated ammonium hydroxide.

Why it is necessary to handle concentrated solution of ammonium hydroxide with care ?

Ammonia is an irritant and corrosive to the skin, eyes, respiratory tract and mucous membranes.

May cause severe chemical burns to the eyes, lungs and skin.

Skin and respiratory related diseases could be aggravated by exposure.

The extent of injury produced by exposure to ammonia depends on the duration of the exposure, the concentration of the liquid or vapor and the depth of inhalation.

Hence, Rubber gloves and other chemical resistant protective clothing are necessary when handling concentrated ammonium hydroxide.

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