If 25 new born babies are randomly selected, what is the probability that the 25 babies are born that their mean weigh less than 3100g?

Answer:

t=13

Step-by-step explanation:

the ratio of the shorter sides is t/4 and the ratio of the longer sides is 26/8 so t=26×4/8=104/8=13

Answer: t=13in

Step-by-step explanation: As you can see in the smaller square, the number 4 is in the place of the letter t. Which means that the width (4) is half of the longitud (8). Therefore, in the bigger square all you need to do it divide the longitud (26) by two, to find the width (t). Which is equal to 13in.

I hope you found this answer helpful! If you did, give it a five-star rating and I thanks! It would really mean a lot.

(Even a brainliest if you feel like it ;D!)

Answer:

Surface area of the smaller pyramid will be 225 cm²

Step-by-step explanation:

Two similar pyramids have their matching or corresponding sides in the ratio of 5 : 7.

In other words,

[tex]\frac{\text{One side of the smaller pyramid}}{\text{One side of the larger pyramid}}[/tex] = [tex]\frac{5}{7}[/tex]

Therefore, [tex]\frac{\text{Surface area of the smaller pyramid}}{\text{Surface area of the larger pyramid}}[/tex] = [tex](\frac{5}{7})^{2}[/tex]

[tex]\frac{S_{\text{small}}}{S_{\text{large}}}=\frac{25}{49}[/tex]

[tex]\frac{S_{\text{small}}}{441}=\frac{25}{49}[/tex]

[tex]S_{\text{Small}}=\frac{441\times 25}{49}[/tex]

          = 225 cm²

Therefore, surface area of the smaller pyramid will be 225 cm².

Answer:

i) [tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

ii) [tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

iii) [tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

Step-by-step explanation:

Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:

[tex]X \sim Binom(n=20, p=0.25)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

Part i

We want this probability:

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

Part ii

We want this probability:

[tex]P(X\geq 3)[/tex]

And we can use the complement rule and we have:

[tex]P(X\geq 3) = 1-P(X<3)= 1-P(X \leq 2) =1- [P(X=0) +P(X=1) +P(X=2)][/tex]

And if we find the individual probabilites we got:

[tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

Part iii

We want this probability:

[tex] P(X <2)= P(X=0) +P(X=1)[/tex]

And replacing we got:

[tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

Answer:

61

Step-by-step explanation:

i got it right

Answer:

The one above me is correct

Step-by-step explanation:

Answer:

-4293272 (y|y>-1)(y|y>-1)

Answer:

Step-by-step explanation:

The function f(x) = x^2 has only one x-intercept which means only {0} is the only number that makes y zero. 

The second function g(x) = (x-2)^2 -3 has also one x-intercept, {3.732} which will make the value of y, zero. 

Answer:

The function started facing up with a vertex at (0, 0). Since 7 was added before squaring, the graph shifts 7 units up so the vertex at (7, 0). Also, the function is negative so the graph is pointing down

This means that there are two x-intercepts in g(x) and there was one x-intercept in f(x).

Step-by-step explanation:

used this and it was right.

Answer:

82cm²

See explanation below

Step-by-step explanation:

The question is incomplete without the diagram of the rectangular prism and it's dimensions. We are to determine the surface area of the rectangular prism using it's net.

I would show you how to determine it using diagram below.

Find attached the diagram used in solving the question as well as the net obtained from the diagram.

Solution:

A net diagram is a 2-dimensional representation of a 3-dimensional solid in which case the solid is unfolded.

The net gives the total area of the sides and faces of the 3 dimensional figure.

The units of the diagram used are all in cm.

Using net diagram:

Area A = Area B = length × height = hl

Area C = Area D = width × length= wl

Area E = Area of F = height × width = hw

surface area of the rectangular prism = 2(wl + hl + hw)

w = width = 2cm

l= length = 7cm

h = height = 3cm

Insert the values in the formular

A = 2(2×7 + 3×7 + 2×3)

A = 2(14+21+6)

A = 2(41) = 82cm²

Surface area of the rectangular prism = 82cm²

Answer: a picture would help

Step-by-step explanation:

lol

Ok to choose a committee of six people and the probability that it will be majority of the party supporters.

Probabilty= 30C6/50C6

Probability= 593775/15890700

Probabilty= 0.037

Answer:

The total number of shoppers that visited the mall in the first 7 days is 234.

Step-by-step explanation:

The number of customers at the new shopping mall on their first day of business was, X = 120.

It is provided that each day the number of shoppers is 10% more than the number of shoppers the day before.

This implies that the number of shoppers on the second day of the opening is:

Number of shoppers on the 2nd day = (120 × 1.10)

Then the number of shoppers on the third day of the opening will be:

Number of shoppers on the 3rd day = (120 × 1.10) × 1.10

And so on.

Compute the total number of shoppers that visited the mall in the first 7 days as follows:

[tex]\text{Number of shoppers on the first 7 days} = 120 \times (1.10)^{7}[/tex]

                                                              [tex]=120\times 1.9487171\\=233.846052\\\approx 234[/tex]

Thus, the total number of shoppers that visited the mall in the first 7 days is 234.

Answer:

1138 shoppers

Step-by-step explanation:

Answer:

The number of students who took English and History, but not Math is 143.

Step-by-step explanation:

Denote the subject choices as follows:

M = a students was taking Math

E = a students was taking English

H = a students was taking History

The data provided is as follows:

N (M) = 257

N (E) = 282

N (H) = 323

n (M ∩ E) = 154

n (M ∩ H) = 171

n (E ∩ H) = 143

n (M ∩ E ∩ H) = 80

Consider the Venn diagram below.

From the provided data and the Venn diagram the value of the set E and H minus M is 143.

Thus, the number of students who took English and History, but not Math is 143.

Answer:

And based on the claim the system of hypothesis are:

Null hypothesis: [tex] \mu = 26589[/tex]

Alternative hypothesis: [tex] \mu \neq 26589[/tex]

And the best alternative would be:

b. [tex]H_1: \neq $26,589[/tex]

Step-by-step explanation:

For this case we want to test the hypotheis that the true mean is different from 26859. We have the following info given:

[tex] \bar X = 26589[/tex] represent the sample mean

[tex] \sigma =2659[/tex] represent the population deviation

And based on the claim the system of hypothesis are:

Null hypothesis: [tex] \mu = 26589[/tex]

Alternative hypothesis: [tex] \mu \neq 26589[/tex]

And the best alternative would be:

b. [tex]H_1: \neq $26,589[/tex]

Answer:

1 us dollar would be worth $0.8333333 Canadian dollars

Step-by-step explanation:

i don't know what you did wrong but you would divide 250/300 to get the amount it's worth. I guess you tried to multiply it, don't do that.

Answer:

Step-by-step explanation:

A) y = -20x + 2500

The above equation is written in slope intercept form - y=mx+b - the y int. is 2500, while the rate of change, aka the slope, is -20 feet per minute.

B) (0,2500)    (1,2480)    (2,2460)    (3,2440)    (4,2420)

For this question just plug in the x values 0 to 4 into the equation above. For example -20(0) +2500 = 2500

C) 1700 feet above the ground

Plug the number 40 into the equation above. -20(40) + 2500 = 1700

D) 125 minutes

The y-int. represents the time it takes him to reach the ground, this means you can set the equation equal to zero and solve to find the answer.

0 = -20x + 2500

subtract 2500 from both sides

-2500 = -20x

divide -20 from both sides

125 = x

Answer:50m

Step-by-step explanation: the highest

Answer:

A warranty of 4.32 years should be provided.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 5.8, \sigma = 0.9[/tex]

What warranty should be provided so that the company is replacing at most 5% of their toasters sold?

The warranty should be the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.645 = \frac{X - 5.8}{0.9}[/tex]

[tex]X - 5.8 = -1.645*0.9[/tex]

[tex]X = 4.32[/tex]

A warranty of 4.32 years should be provided.

Answer:

The conclusion is that people are less likely to prefer dog food over all human food than would be expected by chance

Step-by-step explanation:

From the question we are told that

   The sample size for first sample is  [tex]n_1 = 18[/tex]

     The sample size for second sample  is [tex]n_2 = 18[/tex]

     The number that ranked the dog food first [tex]d = 2[/tex]

     The number that chose one of the other items is  [tex]h = 16[/tex]

The sample proportion for first sample  is  

    [tex]p(d) = \frac{d}{n}[/tex]

=>   [tex]p(d) = \frac{2}{18}[/tex]

=>  [tex]p(d) = 0.11[/tex]

The sample proportion for second sample   is  

         [tex]p(h) = \frac{h}{n}[/tex]

         [tex]p(h) = \frac{16}{18}[/tex]

         [tex]p(h) = 0.8889[/tex]

The value of the pooled proportion is evaluated as

      [tex]\= p = \frac{h+d}{18 +18}[/tex]

       [tex]\= p = \frac{2+16}{18 +18}[/tex]

      [tex]\= p = 0.5[/tex]

[tex]H0: p(d) = p(h)[/tex]

[tex]Ha : p(d) < p(h)[/tex]

Test statistics

        [tex]z = \frac{(p(d)) - (p(h))}{\sqrt{\= p (1- \= p) (\frac{1}{n_1} + \frac{1}{n_2} )} }[/tex]

        [tex]z = \frac{ 0.1111 - 0.8889}{\sqrt{0.5 (1- 0.5) (\frac{1}{18} + \frac{1}{18} )} }[/tex]

       [tex]z = -4.67[/tex]

So since the test  statistics is within the rejection region for the left tailed test

  The null hypothesis is rejected

The conclusion is  that people are less likely to prefer dog food over all human food than would be expected by chance

Answer:

a) [tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

b) [tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex] \bar X= 6.8[/tex] represent the sample mean

[tex] Se= 1.2[/tex] represent the standard error

[tex] n =18[/tex] the sample size

Part a

For this case the confidence interval for the mean is given by:

[tex] \bar X \pm t_{\alpha/2} SE[/tex]

The degrees of freedom are given by:

[tex] df =n-1=18-1=17[/tex]

And the critical value for a confidence interval of 95% is given by:

[tex] t_{\alpha/2}=2.110[/tex]

And the confidence interval would be:

[tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

Part b

The margin of error is given by:

[tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

Answer:

The best correct option is C

x = 1.79 to x = 3

Step-by-step explanation:

Making the sport off all little thing that crowed. They are still grouped into 7. Option C is theost appropriate.

Answer:

An exponential function and a linear function are graphed below

Over which interval does the growth rate of the exponential function continue to exceed the growth rate of the linear function?

a) x=0 to x=3

b) x=0 to x=1.79

c) x=0.38 to x= 1.79

d) x= 1.79 to x=3 <<<<<<< correct answer

Step-by-step explanation:

EDGE 2021

Explanation:

In general, for arbitrary (x, y) pairs, the problem is called an "interpolation" problem. There are a variety of methods of creating interpolation polynomials, or using other functions (not polynomials) to fit a function to a set of points. Much has been written on this subject. We suspect this general case is not what you're interested in.

__

For the usual sorts of tables we see in algebra problems, the relationships are usually polynomial of low degree (linear, quadratic, cubic), or exponential. There may be scale factors and/or translation involved relative to some parent function. Often, the values of x are evenly spaced, which makes the problem simpler.

Polynomial relations

If the x-values are evenly-spaced. then you can determine the nature of the relationship (of those listed in the previous paragraph) by looking at the differences of y-values.

"First differences" are the differences of y-values corresponding to adjacent sequential x-values. For x = 1, 2, 3, 4 and corresponding y = 3, 6, 11, 18 the "first differences" would be 6-3=3, 11-6=5, and 18-11=7. These first differences are not constant. If they were, they would indicate the relation is linear and could be described by a polynomial of first degree.

"Second differences" are the differences of the first differences. In our example, they are 5-3=2 and 7-5=2. These second differences are constant, indicating the relation can be described by a second-degree polynomial, a quadratic.

In general, if the the N-th differences are constant, the relation can be described by a polynomial of N-th degree.

You can always find the polynomial by using the given values to find its coefficients. In our example, we know the polynomial is a quadratic, so we can write it as ...

  y = ax^2 +bx +c

and we can fill in values of x and y to get three equations in a, b, c:

  3 = a(1^2) +b(1) +c

  6 = a(2^2) +b(2) +c

  11 = a(3^2) +b(3) +c

These can be solved by any of the usual methods to find (a, b, c) = (1, 0, 2), so the relation is ...

   y = x^2 +2

__

Exponential relations

If the first differences have a common ratio, that is an indication the relation is exponential. Again, you can write a general form equation for the relation, then fill in x- and y-values to find the specific coefficients. A form that may work for this is ...

  y = a·b^x +c

"c" will represent the horizontal asymptote of the function. Then the initial value (for x=0) will be a+c. If the y-values have a common ratio, then c=0.

__

Finding missing table values

Once you have found the relation, you use it to find missing table values (or any other values of interest). You do this by filling in the information that you know, then solve for the values you don't know.

Using the above example, if we want to find the y-value that corresponds to x=6, we can put 6 where x is:

  y = x^2 +2

  y = 6^2 +2 = 36 +2 = 38 . . . . (6, 38) is the (x, y) pair

If we want to find the x-value that corresponds to y=27, we can put 27 where y is:

  27 = x^2 +2

  25 = x^2 . . . . subtract 2

  5 = x . . . . . . . take the square root*

_____

* In this example, x = -5 also corresponds to y = 27. In this example, our table uses positive values for x. In other cases, the domain of the relation may include negative values of x. You need to evaluate how the table is constructed to see if that suggests one solution or the other. In this example problem, we have the table ...

  (x, y) = (1, 3), (2, 6), (3, 11), (4, 18), (__, 27), (6, __)

so it seems likely that the first blank (x) will be between 4 and 6, and the second blank (y) will be more than 27.

Here is your answer     |  To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.

Answer:

sphere

Step-by-step explanation:

A volleyball is a three dimensional object

It is a three dimensional circle which is called a sphere

Answer:

sphere

Step-by-step explanation:

hope this helps:]

Answer:

(A) The equation for computing Gustin's profit per seminar; given the values of the relevant parameters is:

π = 0.01AC - 3500

Where π = profit per seminar

A = attendance per seminar

C = commission earning per new account opened

(B) A continuous random variable

(C) No

(D) An audience of 71 persons

STEP BY STEP EXPLANATION:

(A) Profit is equal to total revenue minus total cost.

TR = PAC

Where P = probability that an attendee will open a new account

A = number of attendees per seminar

C = commission Gustin gets from each new account opened.

TC = $3,500

Where cost of organizing 1 seminar is constant at $3,500

So the function for profit per seminar is given thus:

π = TR - TC = 0.01AC - 3500

(B) There are 2 types of random variable; discrete random variable and continuous random variable

We say the number of new accounts opened (NNAO) is a continuous random variable because it is not specific. It is a function of both P and A. It depends on both P and A.

From the profit function or equation we have, we can see that you can't derive the exact NNAO per attendee. It is based on probability so if you were to measure it distinctly, you would have a very minimal value.

Discrete random variables occur in specific intervals e.g. 4, 5, 6,... while continuous random variables occur over an interval; e.g. 4.01, 4.02, 4.03,...

(C) Constructing a spreadsheet simulation model to analyze the profitability of Gustin's seminars, I would not recommend that Gustin continue running the seminars!

(D) The question points to A; which is the total attendance per seminar.

So if we calculate profit with the values given in the full question, we see that profit is negative, hence Gustin is running at a loss with 25 people attending one seminar.

π = (0.01 × 25 × 5000) - 3500

π = -$2,250

So, to make a profit greater than zero, we first check how many attendees it takes for TR to equal TC or for Profit to equal 0.

We set pie π to zero.

0 = (0.01 × 5000 × A) - 3500

0 = 50A - 3500

50A = 3500

A = 70 attendees

So Gustin needs an audience of more than 70 persons before a seminars expected profit will be greater than zero.

Answer:

250m

Step-by-step explanation:

2000m/ 8laps = 250m

Answer:

$20.11

Step-by-step explanation:

Solution:-

- We will define the interest rate ( R ) earned on his deposits in the account per annum ( 365 days ).

- He deposits a principal amount of ( P ) = $6,000 once at the start of the accounting period.

- After the principal amount is deposited he deposits $ 150 in the account after every 6 days.

- We will first determine the amount in his account at the end of 30 days.

- We need to see how many additional deposits of $150 were made in these 30 days.

- The ( n ) number of additional deposits can be determined from the ratio of time-span of each deposition and the total accounting period:

                     [tex]n = \frac{30}{6} = 5[/tex]

- Horatio Reyes makes ( n = 5 ) additional deposits after the principal amount till the end of 30th day.

- Now we can calculate the total amount accumulated ( A ) in his account at the end of 30 days time period. It comprises of the initial principal amount and the 5 series of $150 deposits:

                   [tex]A = P + $150*n[/tex]

- Plug in the respective amounts ( P and n ):

                   [tex]A = 6000 + 150*5\\\\A = 6000 + 750\\\\A = 6750[/tex]

- At the end of 30th day Horatio Reyes has $6,750 in his account.

- The interest rate ( r ) applied at the end of the 30-day time period is sub-part of the total interest rate ( R ) applied per annum.

- So the interest rate applied at the end of 30-day tim period is determined from simple proportional ratios of time-period:

                      Rate(%)                     Time(days)

               R:   3.625                             365        

               r:       x                                   30

     ========================================

                      x = 30*3.625 / 365 = 0.29795%

     ========================================

- Now we will apply the rate ( r ) on the accumulated amount ( A ) by the end of 30-day time period in the account to determine the interest earned ( I ):

                        [tex]I= \frac{r*A}{100} \\\\I = \frac{0.29795*6750}{100} \\\\I = 20.111[/tex]

- The amount of interest earned ( I ) is $20.11 after 30 days.

Answer:

1/7

Step-by-step explanation:

Since we do not know the number let us use the alphabet A to represent the unknown number

A × 1/3= 1/21

A/3= 1/21

Cross multiply both sides

A×21= 3×1

21A= 3

Divide both sides by the coefficient of A which is 21

21A/21=3/21

A=1/7

Hence the unknown number is 1/7

Answer:

The number to multiply with 1/3 to get 1/21 is 1/7.

Step-by-step explanation:

The question wants us to find the number you can multiply with 1/3 to get 1/21. The number is unknown but when you multiply that unknown number by 1/3 your answer should be 1/21.

Let

the number to be multiplied with = a

Therefore,

1/3 × a = 1/21

a/3 = 1/21

cross multiply

21a = 3

divide both sides by 21

a = 3/21

a = 1/7

The number to multiply with 1/3 to get 1/21 is 1/7.

Answer:

  (ab)(x)

Step-by-step explanation:

The sum or difference of two linear functions will be a linear function. The product of two linear functions will be a quadratic function.

Answer: BC<MN

Step-by-step explanation:

Answer: BC <MN

Step-by-step explanation: i just took the test on eginuity

[tex]\text{One of the expressions can be the simplified version}\\\\\text{Simplify:}\\\\-f-5(2f-3)\\\\\text{Use the distributive property}\\\\-f-10f+15\\\\\text{Combine like terms}\\\\\boxed{-11f+15}\\\\\text{That expression is equivalent to the expression listed in the question}[/tex]

Answer:

11f+5

Step-by-step explanation:

khan

Answer:

[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]

Step-by-step explanation:

You have the following differential equation:

[tex]e^t(7y-3t)dt+(2+7e^t)dy=0[/tex]

This equation can be written as:

[tex]Mdt+Ndy=0[/tex]

where

[tex]M=e^t(7y-3t)\\\\N=(2+7e^t)[/tex]

If the differential equation is exact, it is necessary the following:

[tex]\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}[/tex]

Then, you evaluate the partial derivatives:

[tex]\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}[/tex]

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

[tex]F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)[/tex]        (1)

Next, you derive the last equation respect to t:

[tex]\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)[/tex]

however, the last derivative must be equal to M. From there you can calculate g(t):

[tex]\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t][/tex]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

[tex]F(t,y)=(2+7e^t)y+3(1-t)e^t +C[/tex]

where C is the constant of integration

Answer:

maybe 3/5

Step-by-step explanation:

I hope it's right

Answer:

x=-1/8

Step-by-step explanation:

You solve this like an regular equation

Hope this Helps

Stay Safe:)