What was the initial quantity of vanadium-49, which has a half-life of 330 days, if after 540 days there is a 1,750 g sample remaining?a.)5,440.42g b.)3,500g C.) 8,700g d.)2,863.63g e.)98g
Answer:
(a) 5440.42 g
Step-by-step explanation:
The amount remaining (Q) is given in terms of the initial amount (Q₀) by the exponential decay formula ...
Q = Q₀(1/2)^(t/330) . . . . . where t is in days
__
The amount after 540 days is ...
1750 g = Q₀(1/2)^(540/330) = 0.321666Q₀
Q₀ = (1750 g)/(0.321666) ≈ 5440.42 g
The initial quantity was about 5440.42 grams.
You can make a tent by throwing a piece of cloth over a clothesline, then securing the edge to the ground with stakes so that an isosceles triangle is formed. How long would the cloth have to be so that the opening of the tent was 8 feet wide and 3 feet high?
Based on the required width and height of the tent, the length of the cloth would have to be 14.4 ft.
How long should the length of the cloth be?The opening of the tent would be an isosceles triangle but if it is divided in two from the top, a right-angled triangle will be formed and the hypotenuse will be the length of the cloth on one side.
That length - according to the Pythagoras theorem - would be:
= √(6² + (8 /2)²)
= √(36 + 16)
= 7.2 ft
As this is the length of one side of the cloth, the length of the entire cloth is:
= 7.2 x 2
= 14.4 ft
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which matrix can be used to solve the system
Answer:
6x + 7y = 14
7x + 8y = 27
6 7. x = 14
7 8. y = 27
option B
The power of an exponential expression raised to a power is the product of the exponents.
Answer:
[tex](y {}^{c} ) {}^{d } = y {}^{c \times d} \\ = y {}^{cd} \\ \\ \\ \\ \\ (v {}^{3} ) {}^{7 } \\ = v {}^{3 \times 7} \\ = v {}^{21} [/tex]HOPE THAT HELPS.Choose the correct graph of the following condition. {(x, y) : x - y6}
The correct graph of the following condition. {(x, y) : x - y6} is depicted in the graph attached.
What is a graph?
A graph is a diagram showing the relation between variable quantities each measured along one of a pair of axes at right angles.
In this case, the correct graph of the following condition. {(x, y) : x - y6} is depicted in the graph attached.
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Solve the right triangle, AABC, for the missing sides and angle to
the nearest tenth given angle B = 27° and side c = 15.
Answer:
please see photo for detailed analysis.
How do I simplify the following expression by writing it as a term with only one trigonometric function?
(4-2sec^2(x))/(sec^2(x))
Answer:
2 cos (2x)
Step-by-step explanation:
[tex]\frac{4 -2 sec^2x}{sec^2x} \\=\frac{4-\frac{2}{cos^2x} }{\frac{1}{cos^2 x} } \\=\frac{\frac{4 cos^2x-2}{cos^2 x} }{\frac{1}{cos^2x} } \\=\frac{2(2 cos^2x-1)}{cos^2x} \times \frac{cos^2x}{1} \\=2(2cos^2x-1)\\=2cos(2x)[/tex]
Order these numbers from least to greatest.
3.3661, 3.5, 3.36, 3.036
Answer:
3.036, 3.36, 3.3661 , 3.5
Step-by-step explanation:
Look at the first 2 numbers
3.3661, 3.5, 3.36, 3.036
We can order them as 3.0 , 3.3 , 3.3 . 3.5
So 3.036 is first one
Now we have 2 of the 3.3's
One is 3.3661 and the other one is 3.3600
Because if you add a number to the end it will always be a zero and it wont change the answer
So 3.36 is second and 3.3661 is third one
3.5 is bigger than 3.3
So 3.5 is last
Which pair of statements describes the end behavior of the graph of the function f(x) = x3 + 2x2 − 5x − 6?
A function assigns the values. The correct option is D.
What is a Function?A function assigns the value of each element of one set to the other specific element of another set.
The complete question is:
Which pair of statements describe the end behavior of the graph of the function f(x) = x³ + 2x² − 5x − 6?
A.) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches infinity.
B.) As x approaches negative infinity, f(x) approaches infinity. As x approaches infinity, f(x) approaches negative infinity.
C.) As x approaches negative infinity, f(x) approaches negative infinity. As x approaches infinity, f(x) approaches negative infinity.
D.) As x approaches negative infinity, f(x) approaches negative infinity. As x approaches infinity, f(x) approaches infinity.
If we draw the graph of the given function f(x) = x³ + 2x² − 5x − 6, then it can be observed that as x approaches -∞, f(x) approaches -∞. As x approaches ∞, f(x) approaches infinity.
Hence, the correct option is D.
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-2/9u=12
Solve for u
u=-54
you have -54 because
-54(-2)=108/9=12
Answer:
u =-54
Step-by-step explanation:
-2/9u=12
To solve for u multiply each side by -9/2 to isolate u
-9/2 * -2/9 u= 12 * -9/2
u =-54
For the data set 7, 5, 10, 11, 12, the mean, X, is 9. What is the standard
deviation?
Answer:
The standard deviation is about 2.915
Step-by-step explanation:
Answer:
= 2.9154759474227
Step-by-step explanation:
Steps are very much required they should be clear and neat please i need to understand this I'm taking a practice test for my future sats
ill report in inappropriate answers
Answer:
2nd option
Step-by-step explanation:
the mean is calculated as
mean = [tex]\frac{sum}{count}[/tex]
= [tex]\frac{4x+5+7x-6-8x+2}{3}[/tex]
= [tex]\frac{3x+1}{3}[/tex]
= [tex]\frac{3x}{3}[/tex] + [tex]\frac{1}{3}[/tex]
= x + [tex]\frac{1}{3}[/tex]
Solve for x : 7x + 8 < 1/6 (42x+48)
X = all real number
X has no solution
X = 0
Answer:
[tex]\fbox {all real numbers}[/tex]
Step-by-step explanation:
7x + 8 = 1/6 (42x + 48)
7x + 8 = 7x + 8
x = all real numbers
14. What is the measure of ZABC in the image shown? OE A B 10x - 10 100 - 2x 2x + 10 C 14. What is the measure of ZABC in the image shown ? OE A B 10x - 10 100 - 2x 2x + 10 C
Answer: 110 degrees
Step-by-step explanation:
By the exterior angle theorem.
[tex]10x-10=100-2x+2x+10\\\\10x-10=110\\\\\therefore \angle ABC=110^{\circ}[/tex]
A pool a possible candidate for a student council consists of 14 freshmen and 8 softwares how many different councils consisting of 5 freshmen and 7 sophomores are possible
The different councils consisting of 5 freshmen and 7 sophomores are possible 9216.
We have given that,
A pool of possible candidates for a student council consists of 14 freshmen and 8 software.
We have to determine the how many different councils consisting of 5 freshmen and 7 sophomores are possible
What is the combination?[tex]_n C_r=\frac{n !}{r ! (n-r) !}_n C_r = number of combinations\\\n = total number of objects in the set\\\r = number of choosing objects from the set[/tex]
The total number of the council is
[tex]_{10} C_5\times _9 C_7[/tex]
=252(36)
=9216
The different councils consisting of 5 freshmen and 7 sophomores are possible 9216.
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A club organises a lottery, selling tickets at 25 cents each. The club will be giving a prize of
€58
to the winner but also plans to make a profit of
€150
from the whole event. What is the least number of tickets that the club needs to sell?
Using proportions, it is found that the club needs to sell at least 832 tickets to make their desired profit.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The prize is of €58, with the event making a profit of €150, hence the amount of money they have to earn from tickets is given by:
A = 150 + 58 = €208.
The tickets are sold at €0.25, hence the number of tickets they have to sell is:
n = 208/0.25 = 208 x 4 = 832.
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Help needed! Thank you!
Part 1
[tex](f\circ g)(x)=f(g(x))=\frac{\frac{1}{x}}{\frac{1}{x}-3}[/tex]
Multiplying the numerator and denominator by x,
[tex](f\circ g)(x)=\boxed{\frac{1}{1-3x}}[/tex]
Part 2
The domain for this function is all values of x except for when the denominator equals 0 (because then, it would be undefined).
The denominator is equal to 0 when x=1/3, so the domain is [tex]\boxed{x \neq \frac{1}{3}}[/tex]
6x+2y=20 2x-3y=3 solve by substitution
The solution of the system of linear equation by substitution method is (3,1).
What is the method of substitution?The method of substitution is the method for solving the linear equation where the value of one variable of one equation is placed in the place of that variable in another equation.
Given here the linear equations are
Equation 1: 6x+2y=20
Equation 2: 2x-3y=3
in equation 1 the value of y will be
6x+2y=20
⇒2y=20-6x
⇒y=(20-6x)/2
⇒y=10-3x
substituting the value of y in the equation 2, we will get
2x-3y=3
⇒2x-3(10-3x)=3
⇒2x-30+9x=3
⇒11x-30=3
⇒11x=30+3
⇒11x=33
⇒x=33/11
⇒x=3
putting the value of x in value of y in equation 1
y=10-3x
⇒y=10-3(3)
⇒y=10-9
⇒y=1
The solution of the system of linear equation by substitution method is (3,1).
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The functions f(x) = x^2 – 2 and g(x) = –x^2 + 5 are shown on the graph.
Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the solution set be identified?
y > x^2 – 2
y ≥ –x^2 + 5
The set of inequalities do not have a solution.
What is inequality?The relationship between two values that are not equal is defined by inequalities. Inequality means not equal. Generally, if two values are not equal. But to compare the values, whether it is less than or greater than, different inequalities are used.
Given:
f(x)= x²-2
g(x) = -x²+5
To derive, y ≤ x² + 5 simply change the equality sign in the function g(x).
To derive y > x² - 2 , following transformation on the function f(x)
Shift the function f(x) down by 2 unitsReflect across the x-axisShift the function g(x) up by 5 unitsChange the equality sign in the function g(x) to greater than.The inequalities of the graphs become
y < x² - 2 and y ≤ x² - 5
From the graph of the above inequalities it can be seen that curves of the inequalities do not intersect.
Hence, the set of inequalities do not have a solution
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The graph shows that is translated horizontally and vertically to create the function .
On a coordinate plane, 2 exponential functions are shown. f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It goes through (negative 1, 0.5) and crosses the y-axis at (0, 1). g (x) approaches y = 2 in quadrant 2 and increases into quadrant 1. It goes through (0, 2) and (2, 3).
What is the value of h?
−2
−1
1
2
According to the function transformations, the value of h is -2
How to determine the value of h?The complete question is in the attachment
The functions are given as:
[tex]f(x) = (2.5)^x[/tex]
[tex]g(x) = (2.5)^{x-h[/tex]
From the question, we understand that the function f(x) is translated to the left to get g(x)
From the attached graph, we can see that the function h(x) is 2 units to the left of f(x).
This transformation is represented by:
(x, y) => (x + 2, y)
So, we have:
x - h = x + 2
Evaluate the like terms
h = -2
Hence, the value of h is -2
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Answer:H=-2
Step-by-step explanation:
The Math Club has 23 members and needs to elect officers. They will need a President, Vice President, Secretary, and Treasurer. How many ways can a 4-member committee be formed?
Answer:
212520 different committees
Step-by-step explanation:
Candidates
For a President: 23
For a Vice President: 22
For a Secretary: 21
For a Treasurer: 20
Number of ways: (23)(22)(21)(20) = 212520
Hope this helps
Answer:
To whom it may concern the answer to this problem would be 212,520.
Step-by-step explanation:
Many people think this problem to be a combination problem, but it is actually a permutation. Since there must be some specific semblance to the order of the equation. Now, to begin with, the work for this problem is...
[tex]_{n}_P_{r}=\frac{n!}{(n-r)!} \\_{23} _P_{4}=\frac{23!}{(23-4)!} \\_{23}_P_{4}=\frac{23!}{19!} \\_{23}_P_{4}=\frac{23*22*21*20*19!}{19!} \\_{23}_P_{4}=\frac{212,520}{1} \\_{23}_P_{4}=212,520[/tex]
Remember that the 19! cancel each other out. Hope this helps!
The radius of a circle is 3ft. What is the circumference of the circle? Use 3.14 for pie.
The measure of B is (3x-4)° and the measure of D is (2x-6)°. What are the measures of angles B and D?
Answer:
5x - 10
Step-by-step explanation:
→ Find the sum of the expression
3x - 4 + 2x - 6
→ Collect all the x terms
3x + 2x - 4 - 6
→ Simplify
5x - 10
Simplify:
(x-1)+(12–7.5x)
Answer:
[tex]-6.5x+11[/tex]
Step-by-step explanation:
Expand The Brackets:
[tex]x-1+12-7.5x[/tex]
[tex]=x+(-1)+12+(-7.5x)[/tex]
Combine Like Terms:
[tex]=x+(-1)+12+(-7.5x)[/tex]
[tex]=(x+-7.5x)+(-1+12)[/tex]
Answer:
[tex]-6.5x+11[/tex]
I Hope This Helps
*30pts*What is the value of x in the triangle?
Answer:
A.4
Step-by-step explanation:
Using the sine rule
sin(α)/A equals sin(β)/B
From the question & inserting values,
sin(90°)/8 equals sin(30°)/x
∴x equals[tex]\frac{sin(30)}{sin(90)}[/tex]×8
∴x equals 4
You can learn more on the sine rule in case you get confused.
Answer:
A
Step-by-step explanation:
using the sine ratio in the right triangle and the exact value
sin30° = [tex]\frac{1}{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{8}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2x = 8 ( divide both sides by 2 )
x = 4
Use Modus Ponens to deduce the conclusion from each of the following pairs of premises:
a = b ∧ b = c
(a = b ∧ b = c) ⇒ a = c
The conclusion is a=c statement
A modus ponens argument has the same structure as a syllogism, with two premises and a conclusion:
If P, then Q.
P occurs.
Consequently, Q occurs.
The Modus Ponens rule of inference or rule of logic requires a single premise and its logical consequences. A conditional statement states that if event 1 occurs, event 2 will also occur and that event 2 will be inferred as the outcome if event 1 occurs. For instance, if A implies B and A is assumed to be true, then it follows that B must also be true according to the Modus Ponens rule.
Hence, By modus Ponens
a=b∧b=c ⇒ a=c
So, given a=b∧b=c Then
⇒a=c.
Hence the conclusion is a=c statement .
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Please help asap! 30 points
Given that f(x)=11, g(x)=x^2-6x+3, and h(x)= -x+4, find the function (g •h)(x).
Answer:
[tex](g \cdot h)(x)=x^2-2x+23[/tex]
Step-by-step explanation:
For composite functions, it's important to understand what the functions mean:
[tex](g\cdot h)(x)[/tex] which is read as "g of h, of x" means [tex]g ( \text{ }h(x) \text{ })[/tex] which is read as "g of, h of x" (with slight pauses at the comma). This means that x goes into the h function, and the output of the h function goes into the g function.
Putting "x" into the h function
[tex]h(x)=-x+4[/tex]
Since it is just "x" going into the h function, the function as written is the output when x is the input.
Putting the h function output, into the g function
[tex]g(x)=x^2-6x+3[/tex]
[tex]g(h(x))=(h(x))^2-6(h(x))+3[/tex]
Substitute
[tex]g(h(x))=(-x+4)^2+-6(-x+4)+3[/tex]
Squaring means the something multiplied by itself
[tex]g(h(x))=(-x+4)*(-x+4)+-6(-x+4)+3[/tex]
Use distributive property; (some people know binomial distribution as "FOIL" -- First, Outer, Inner, Last):
[tex]g(h(x))=[(-x)(-x)+4(-x)+4(-x)+4*4)]+[6x+4]+3[/tex]
Simplify the binomial terms:
[tex]g(h(x))=[x^2-8x+16]+[6x+4]+3[/tex]
Group like terms:
[tex]g(h(x))=x^2-2x+23[/tex]
Remember that [tex](g\cdot h)(x)[/tex] means [tex]g ( \text{ }h(x) \text{ })[/tex]
[tex](g \cdot h)(x)=x^2-2x+23[/tex]
So, [tex](g \cdot h)(x)=x^2-2x+23[/tex]
Question 10 of 33
Which of the following is a characteristic of a regular tessellation?
O A. It uses only one type of regular polygon.
OB. It uses more than one type of regular polygon.
O C. It allows for overlaps and spaces between shapes.
OD. It does not cover a surface completely.
SUBMIT
A tessellation that uses only one type of regular polygon.
What is Polygon?
The definition of a polygon is given as a closed two-dimensional figure with three or more straight lines.
When we cover a surface with a pattern of a flat geometric shapes such that there should have no overlaps or gaps, then the surface is called a tessellation.
A regular tessellation is tessellation made up by using only one type of regular polygon. These are made up of entirely congruent regular polygons all that joining vertex to vertex.
Hence, A is the correct option.
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Q6. This part of the question is for simplifying your work: Make a graph and shadow the interested regions of the inequalities in the given picture.
The following is the actual question: Find the highest and lowest value of the equation in the given picture within the unshadowed region.
The graph of all the inequalities are given below.
What is inequality?Inequality is defined as an equation that does not contain an equal sign.
This part of the question is for simplifying your work: Make a graph and shadow the interested regions of the inequalities in the given picture.
y ≥ x, the region is left to the line.
y < -(3/7)x – 7, the region is left to the line.
y ≤ (5/3)x – 8, the region is right to the line.
y ≥ 14 – (11/12)x, the region is right to the line.
y = -(3/2)x + 5, this is the equation of line.
All the graphs are shown below.
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Examples for Continuous rv X
1. Given the pdf:
f(x) {1/4 e^-1/4x} x>0
0, otherwise
Find: a. E(X) and b. Var(X)
Use the definitions of expectation and variance.
Expectation[tex]E(X) = \displaystyle \int_{-\infty}^\infty x f_X(x) \, dx = \frac14 \int_0^\infty x e^{-x/4} \, dx[/tex]
Integrate by parts,
[tex]\displaystyle \int_a^b u \, dv = uv \bigg|_a^b - \int_a^b v \, du[/tex]
with
[tex]u = x \implies du = dx \\\\ dv = e^{-x/4} \, dx \implies v = -4 e^{-x/4}[/tex]
Then
[tex]E(X) = \displaystyle \frac14 \left(\left(-4x e^{-x/4}\right)\bigg|_0^\infty + 4 \int_0^\infty e^{-x/4} \, dx\right)[/tex]
[tex]E(X) = \displaystyle \int_0^\infty e^{-x/4} \, dx = \boxed{4}[/tex]
(since the integral of the PDF is 1, and this integral is 4 times that)
Variance[tex]V(X) = E\bigg((X - E(X))^2\bigg) = E(X^2) - E(X)^2[/tex]
Compute the so-called second moment.
[tex]E(X^2) = \displaystyle \int_{-\infty}^\infty x^2 f_X(x)\, dx = \frac14 \int_0^\infty x^2 e^{-x/4} \, dx[/tex]
Integrate by parts, with
[tex]u = x^2 \implies du = 2x \, dx \\\\ dv = e^{-x/4} \, dx \implies v = -4 e^{-x/4}[/tex]
Then
[tex]E(X^2) = \displaystyle \frac14 \left(\left(-4x^2 e^{-x/4}\right)\bigg|_0^\infty + 8 \int_0^\infty x e^{-x/4} \, dx\right)[/tex]
[tex]E(X^2) = 8 E(X) = 32[/tex]
and the variance is
[tex]V(X) = 32 - 4^2 = \boxed{16}[/tex]
