I need help ASAP please

Answer:

A.

1) No

2)yes

3)yes

4)yes

5) it's not a function

11/21    

b/t/w you con go on this website called  calculator soup and it has fraction calculators

and the website it self has nothing to download im pretty sure it doesnt

Answer:

17

Step-by-step explanation:

Answer:

Yes, it is

Step-by-step explanation:

Given

The attached image

Required

Is AB a tangent to the circle

From the attached circle, we can see that AP is the radius of the circle P.

And by definition, a tangent touches the circle at only one point.

Since AB touches the circle at only point A, then AB is a tangent.

Answer:

The print is 18 inches longer then it is wide

Step-by-step explanation:

I multiplied 12 x 4 becuase there are 12 inches in a foot to get 48 inches. So the print is 48 inches long. Then I multiplied 2 times 12 to get 24 and then 24+6 + 30 so the rug is 30 inches wide. Finally I subtracted 30 from 48 to get the diffrence in inches. Which is 18 :)

Answer:

3250

Step-by-step explanation:

5x13x5x10=3250

Answer:

this is the answer

Step-by-step explanation:

hope it helped!!!

Answer:

C. p - 7 + 22 = 22 - 7

D. p - 7 + 7 = 22 - 22

Step-by-step explanation:

p - 7 = 22

Add 7 to both sides

p = 29

An equivalent equation could be;

-7 = 22 - p

Answer:

3x

Step-by-step explanation:

3x(5x-7)

brainliest!

Answer:

The null hypothesis is: [tex]H_{0}: \mu = 100[/tex]

The alternative hypothesis is: [tex]H_{a}: \mu > 100[/tex]

Step-by-step explanation:

At the null hypothesis, we test if the mean is equal to a certain value.

At the alternate hypothesis, we test if the mean is less than, more than, or different from the value tested at the null hypothesis.

The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of 20 lb.

This means that the null hypothesis is: [tex]H_{0}: \mu = 100[/tex]

Could it be that the average tuft strength is above 100 lb?

The world above means that the appropriate alternative hypothesis is: [tex]H_{a}: \mu > 100[/tex]

Answer:

the original price of the book is $20

Step-by-step explanation:

sometimes in a question, they put things in the question that don't actually help us get to the answer. usually we ignore it, but i'm going to list them out just to help you a bit more.

Things that are useless:

Things that are helpful:

Ok, now that we know those, let's work on the question.

let b be the original book price

we need to find 10% so we have to use 90% (because 100 - 10 = 90)

if we needed to find 20% we would use 80% (because 100 - 20 = 80)

and so on.

  90% of b = 18    (90% of the og. book price equals 18)

90/100 × b = 18    (write a correct equation and make the percent a fraction)

    9/10 × b = 18    (simplify both sides of the equation)

         9 × b = 180  (multiply both sides of the equation to get rid of fraction)

               b = 20   (divide both sides of the equ. to get b by itself)

the original price of the book is $20

hope this helped :D

good luck my friend

- cheesetoasty

Answer:

No, it should be 10.

Step-by-step explanation:

The first digit of 4 underlined in 448,023 represents 400,000.

As 448,023 =

(400,000) + (40,000) + (8,000) + (20) + (3).

While the second digit of 4 that is not underlined in 448,023 represents 40,000.

400,000 / 40,000 = 10.

Answer:

y = 3/4x - 2

Step-by-step explanation:

Given:

m = 3/4

b = -2

y = mx + b

m = slope

b = y-intercept

y = 3/4x - 2

Answer:

Number 7 is; -1/7776

number nine is :| −8/ 3 | or 2.666667

Step-by-step explanation:

-1/6)^5=1^5/6^5

=-1/^5/6/5

1^5=1

=-1/6^5

6^5=7776

=-1/7776

|(− 1/ 3 )(110+9−2)|

=| −1/ 3 (110+9−2)|

=| −1/ 3 (1+9−2)|

=| −1/ 3 (10−2)|

=| −1 /3 (8)|

=| −8 /3 | =2.666667

Hope this helped!!!!

Answer:1828

Step-by-step explanation:

Answer:

Substituting 4 for x:

ƒ(4) = 3(4 - 5)

ƒ(4) = -3

So, ƒ(4) = -3

Hopefully you understand now!

Answer:

12.25π m²

Step-by-step explanation:

Circumference = Diameter x pi

Area = radius squared (^2) x pi

7 divided by 2 = 3.5

3.5^2 = 12.25

12.25π

Answer:

A ≈ 3.9

Step-by-step explanation:

How to solve

A=πr2

C=2πr

A=C2

4π = 72

4·π ≈ 3.8993

Therefore, the circle in square meters in the nearest tenths is A ≈ 3.9

Answer:

A

Step-by-step explanation:

Answer:

1=5 so x=4.5

Step-by-step explanation:

so 11x-9=7x+9

4x=18

x=18/4

x=4.5

Answer:

D) 1078

Step-by-step explanation:

Answer:

Year 2004

Step-by-step explanation:

Population of a country in year 1995 = 286

Model that expresses the growth rate of the population is,

P(t) = [tex]286(1.009)^{t-1995}[/tex]

Here, t = year

a). For P = 311 million people

   311 = [tex]286(1.009)^{t-1995}[/tex]

   [tex]\text{log}(\frac{311}{286})=\text{log}(1.009)^{t-1995}[/tex]

   log(311) - log(286) = (t - 1995)log(1.009)

   2.4928 - 2.4564 = (t - 1995)(0.00389)

   [tex]\frac{0.03639}{0.00389}=t-1995[/tex]

   t = 1995 + 9.4

   t = 2004

In year 2004 population of the country will be 311.

Answer:

xy = k

solve for k...

(8) * (8/3) = (64/3) = k

y = k / x

when x = 4,

y = (64/3) * (1/4) = (16/3)

Step-by-step explanation:i g o o g l e it

Answer:

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.

This means that [tex]n = 200, \pi = 0.58[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 - 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.5116[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.58 + 1.96\sqrt{\frac{0.58*0.42}{200}} = 0.6484[/tex]

The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).

Answer:

Lets be honest we all come to this website just to get answers but the answer would be either C or A

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

2 (−2/3) (1/2) + 3 (−2/3)^2

= −4/3 (1/2) + 3 (−2/3)^2

= −2/3 + 3 (−2/3)^2

= −2/3 + 3 (4/9)

= −2/3 + 4/3

= 2/3

Answer:

she paid 420 dollars for it

Step-by-step explanation:

30 percent of 600 is 180

Answer:

[tex](a)\ y =0\ or\ y=4\ or\ y=6[/tex]

[tex](b) \ (-\infty,4)\ u\ (6,\infty)[/tex]

[tex](c)\ (4,6)[/tex]

Step-by-step explanation:

Given

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

Solving (a): The constants

This implies that:

[tex]\frac{dy}{dt} = 0[/tex]

So, we have:

[tex]y^4 - 10y^3 + 24y^2 = 0[/tex]

Factorize:

[tex]y^2(y^2 - 10y + 24) = 0[/tex]

Expand and Factorize the expression in bracket

[tex]y^2(y^2 - 6y - 4y + 24) = 0[/tex]

[tex]y^2(y(y - 6) - 4(y - 6)) = 0[/tex]

[tex]y^2(y - 4)(y - 6) = 0[/tex]

Split

[tex]y^2 =0\ or\ y-4=0\ or\ y-6=0[/tex]

Solve for y

[tex]y =0\ or\ y=4\ or\ y=6[/tex]

The above represents the constants

Solving (b): Increasing values

Here

[tex]\frac{dy}{dx} > 0[/tex]

Follow the same process in (a) but replace all = with >

i.e.

[tex]y^2(y - 4)(y - 6) > 0[/tex]

[tex]y >0\ or\ y>4\ or\ y>6[/tex]

Test the values of each inequality

For [tex]y > 6[/tex]; say [tex]y = 7[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 7^4 - 10*7^3 + 24*7^2[/tex]

[tex]\frac{dy}{dt} = 147[/tex]

[tex]147 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex];  This implies that: [tex](6, \infty)[/tex]

For [tex]y > 4[/tex] Say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is false:

Say [tex]y = 3[/tex] i.e. [tex]y < 4[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

[tex]27 > 0[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that: [tex](0,4)[/tex]

For [tex]y > 0[/tex]

[tex]y > 0[/tex] implies that: [tex]y < 4[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is true for [tex]\frac{dy}{dx} > 0[/tex]. This implies that [tex](-\infty, 0)[/tex]

We have: [tex](-\infty,0), (0,4)\ and\ (6,\infty)[/tex]

[tex](-\infty,0)\ and\ (0,4)[/tex] can be combined to give: [tex](-\infty,4)[/tex]

So, the interval is: [tex](-\infty,4)\ u\ (6,\infty)[/tex]

Solving (c): Decreasing values

Here

[tex]\frac{dy}{dx} < 0[/tex]

i.e.

[tex]y^2(y - 4)(y - 6) < 0[/tex]

[tex]y <0\ or\ y<4\ or\ y<6[/tex]

Test the values of each inequality

For [tex]y < 6[/tex]; say [tex]y = 5[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 5^4 - 10*5^3 + 24*5^2[/tex]

[tex]\frac{dy}{dt} = -25[/tex]

This is true for [tex]\frac{dy}{dx} < 0[/tex];  This implies that: [tex](\infty,6)[/tex]

For [tex]y < 4[/tex]; say [tex]y = 3[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 3^4 - 10*3^3 + 24*3^2[/tex]

[tex]\frac{dy}{dt} = 27[/tex]

This is false

Say [tex]y = 5[/tex] i.e.  [tex]y > 4[/tex]

This is the same as: [tex]y < 6[/tex]

So, we have the interval to be: [tex](4,\infty)[/tex]

For [tex]y < 0[/tex] say [tex]y = -1[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = (-1)^4 - 10*(-1)^3 + 24*(-1)^2[/tex]

[tex]\frac{dy}{dt} = 35[/tex]

This is false

Say [tex]y = 2[/tex] i.e [tex]y > 0[/tex]

[tex]\frac{dy}{dt} = y^4 - 10y^3 + 24y^2[/tex]

[tex]\frac{dy}{dt} = 2^4 - 10*2^3 + 24*2^2[/tex]

[tex]\frac{dy}{dt} = 32[/tex]

This is also false

So, the intervals are: [tex](4,\infty)[/tex] and [tex](\infty,6)[/tex].

This can be merged as: [tex](4,6)[/tex]

Hence, the interval for [tex]\frac{dy}{dt} < 0[/tex] is [tex](4,6)[/tex]

Answer:

( -2 , 1 )

Step-by-step explanation:

••••••••

sorry no explanation for today

Answer:

A. 55°

hope it can help you

Answer: I took a screen shot of it hope it helps

Step-by-step explanation: