How much heat does it lose to change 126 g of water from 67°C to 37°C?​

Answer:

120 N

Explanation:

From the question given above, the following data were obtained:

Angle (θ) = 35°

Mass (m) = 15 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

The normal force acting on the object can be obtained as:

N = mg × Cosθ

N = 15 × 9.8 × Cos 35

N= 147 × 0.8192

N = 120 N

Therefore, the normal force acting on the object is 120 N

Answer:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

Explanation:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

Answer:

a) [tex] E_{p} = 0 [/tex]

[tex] E_{k} = 168.7 J [/tex]

[tex] E_{m} = 168.7 J [/tex]

b) [tex] E_{p} = 73.6 J [/tex]

[tex] E_{k} = 95.8 J [/tex]

[tex] E_{m} = 169.4 J [/tex]

c) [tex] E_{p} = 169.2 J [/tex]

[tex] E_{k} = 0 [/tex]

[tex] E_{m} = 169.2 J [/tex]

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

[tex] E_{p} = mgh = 0 [/tex]

The kinetic energy is:

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]

Now, to find the kinetic energy we need to calculate the speed at 5 m:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]

[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]

c) At its maximum height:

[tex] v_{f}[/tex]: is the final speed = 0

[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]

Now, the potential, kinetic and mechanical energies are:

[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]

[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]

I hope it helps you!    

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

          sin θ = y / L

we substitute

         d y / L = m λ  

         λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

          λ = [tex]\frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }[/tex]

          λ = 4.51699 10⁻⁷ m

          λ = 4.517 10⁻⁷ m (109 nm / 1m)

          λ = 451.7 nm

Digital signals are a more reliable form of transmitting information because an error in the amplitude or frequency value would have to be very large in order to cause a jump to a different value. Signals are composed of infinite possible values. ... Sound signals can vary smoothly in volume and pitchAdvantages to using digital signals, including digital signal processing (DSP) and communication systems, include the following:

Digital signals can convey information with less noise, distortion, and interference.

Digital circuits can be reproduced easily in mass quantities at comparatively low costs.

Answer:

it is easy to change the data if you have the right computer programs

Explanation:

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right thanks to the other user :)

A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

The lenses used to form images of the object placed a distant apart.

The concave mirror form images by virtual meeting of the light rays and appear to meet. They are thin at the middle portion.

The convex mirror form images by real meeting of the light rays. They converge the rays coming from object. They are thick at the middle portion.

Thus, A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

Learn more about concave and convex lens.

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Answer:

the atomic number is the same as the proton numbers so your answer is D.10

Answer:

It contains 10 protons and 10 electrons.

Answer:

0.

Explanation:

rocks dont have energy

Explanation:

This is an exothermic reaction. An exothermic reaction is one which releases heat to the surroundings. When CH3OH reacts with O2, heat is released on the product side of the reaction.

Answer:

The formula, which is fairly easy to derive, is:

The sine of the critical angle = refractive index of the “refracting medium” divided by refractive index of the “incident medium”.

In this case the “refractive medium” is air and the “incident medium” is glass.

The refractive index of air is about 1 (almost exactly).

So, in this case, the sine of the critical angle is 1 divided by 1.5 = 0.6667.

You will find the answer, from sine tables, to be approximately 41.81 degrees.

Remember that the refractive index of air is slightly more than 1. Using a better value for refractive index of air, I get the critical angle to be about

Answer:

~65.9m/min

Explanation:

Excuse the messy handwriting!

The question is incomplete. The complete question is :

A car is stopped at a traffic signal. A second car rear-ends the first car. From the crush of the two vehicles, it is estimated that the second car was traveling at 15 mph when it impacted the first car. If the second car laid down 166 feet of skid marks before the crash took place, how fast was the second car traveling when its brakes were locked up? The approach to the intersection where the accident took place is on a 2.5 percent downgrade. Assume the AASHTO recommended deceleration rate of [tex]$11.2 \ ft/s^2.$[/tex]

Solution :

From the equation, the skid distance is given by

[tex]$S=\frac{u_i^2-u_f^2}{2g\left(\frac{a_d}{g}+h\right)}$[/tex]

Here, [tex]$a_d$[/tex] = deceleration rate, [tex]$11.2 \ ft/s^2.$[/tex]

         h = [tex]$-\frac{2.5}{100}$[/tex] = -0.025

         [tex]$u_i$[/tex] = initial speed of the car

         [tex]$u_f$[/tex] = speed when impacted

Therefore,

[tex]$166=\frac{u_i^2-(15 \times 1.467)^2}{2\times 32.2\left(\frac{11.2}{32.2}+0.025\right)}$[/tex]

[tex]$\Rightarrow u_i^2 = 3935.36$[/tex]

[tex]$\Rightarrow u_i = 62.73 \ ft/s$[/tex]

or [tex]$ u_i = \frac{62.73}{1.467} $[/tex]

   [tex]$ u_i = 42.76 \ mph $[/tex]

Answer:

2. Socially constructed

Explanation:

Answer:

explanation of this effect  is  the photoelectric effect

Explanation:

Let's describe the process, when light of large wavelength falls, this implies a small energy, according to Planck's equation

           E = h f = [tex]\frac{h \ c}{ \lambda}[/tex]

the energy of the photons is not enough to carry out an electronic transition between two states of the material, when we decrease the wavelength (the energy of the photons increases), the point is reached where the energy of the beam is equal to some energy of a transition, by which the electrons are promoted and since we can see a certain charge, as the atoms are neutral, some electrons must be removed from the material, this is represented in the macroscopic case as the work function of the material, consequently a unbalanced load that is what we can measure.

When we increase the lightning intensity, what we do is that we increase the number of photons and if each photon can remove an electron, by removing the electrons the difference between it and the positive charge (fixed in the nuclei) increases.

We can analyze the interaction of the photon and the electron as a particular collision.

The explanation of this effect was made by Einstein in his explained of the photoelectric effect

Answer:

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

PLEASE GIVE BRAINLIEST

Answer:

there will be a heat flow from water to the metal ball...

Answer: 13.9 m

Explanation:

Answer:

13.9m

Explanation:

Answer on Edge

Answer:

Efficient means something that gives 100% accuracy.

Answer:

Explanation:

in series, resistors just add up

27+33+51+1200+240= 1551 ohms

Answer:

E = 216.76 J

Explanation:

The amount of energy absorbed by the goalkeeper will be equal to the difference between the initial and the final kinetic energy of the ball.

[tex]Energy\ Absorbed = Initial\ Kinetic\ Energy - Final\ Kinetic\ Energy\\Energy\ Absorbed = E = \frac{1}{2}mv_{i}^2 - \frac{1}{2}mv_{f}^2\\E = \frac{1}{2}m(v_{i}^2 - v_{f}^2)\\[/tex]

where,

m = mass of ball = (16 ounce)(0.0283495 kg/1 ounce) = 0.4535 kg

vf = final velocity = 2.25 m/s

vi = initial velocity = 31 m/s

Therefore,

[tex]E = \frac{1}{2}(0.4535\ kg)[(31\ m/s)^2 - (2.25\ m/s)^2][/tex]

E = 216.76 J

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

v = 0.16 m/s in the positive x direction.

Explanation:

       [tex]p_{o} =m_{1} * v_{o1} + m_{2} * v_{o2} (1)[/tex]

       [tex]p_{o} =110 kg * 4.4 m/s + 135 kg * (-3.3 m/s) (2)[/tex]

       [tex]p_{f} =( m_{1} + m_{2} )* v_{f} (3)[/tex]

       [tex]p_{f} =( m_{1} + m_{2} )* v_{f} = (110 kg + 135 kg)* vf (4)[/tex]

       [tex]v_{f} = \frac {110 kg * 4.4 m/s + 135 kg * (-3.3 m/s) }{(110 kg + 135 kg)} = 0.16 m/s (5)[/tex]

Answer:

B because it's on Asia but that pfp tho

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

Answer:

Thermal Expansion

Explanation:

These liquid thermometers are based on the principal of thermal expansion. When a substance gets hotter, it expands to a greater volume. Nearly all substances exhibit this behavior of thermal expansion. It is the basis of the design and operation of thermometers.

Answer: 5 N

Explanation:

Given

Mass of box [tex]m=4\ kg[/tex]

acceleration of box [tex]a=2\ m/s^2[/tex]

Force applied by Manual [tex]F_m=8\ N[/tex]

Friction force [tex]f=5\ N[/tex]

The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]

Suppose [tex]F_c[/tex] is the force applied by Carlos

[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]

The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

The force is defined as the external effort applied on any object to move it or to restrict it.

Here following information is given in the question:

Mass of the box m=4 kg

The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]

The force applied by the Manual [tex]F_m=8\ N[/tex]

The frictional force is [tex]F_f=5\ N[/tex]

The net force on the body will be calculated by

[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]

The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:

[tex]F_m+F_c-F_f=F_{net}[/tex]

[tex]8+F_c-5=8[/tex]

[tex]F_c=5\ N[/tex]

Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

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