Answer:
10,000 N
Explanation:
Using Newton's Second Law of Motion, Force = Mass*Acceleration.
Plugin 2500 kg for the mass and 4 m/s^2 for the acceleration.
Force = 2500 kg*4 m/s^2 = 10000 Newtons
(SI unit of force is Newtons)
I need help with science please, ill give brianlist’s :
Question 1 :The size of a plant cell may change depending upon the amount of water it receives.
True
False
________________________________
Question 2: Chloroplasts are a category of organelles found in the cells of green plants.
True
False
_______________________________
Question 3: Photosynthesis in plants produces water and carbon dioxide.
True
False
Answer:
true , true, and I'm not sure about the last one!
Explanation:
how could you increase the gravitational potential energy of an object without changing its mass and gravity
When will heat STOP flowing
between two objects?
A. When one object is significantly
warmer than the other
B. When one object is significantly cooler
than the other
C. Never
D. When both objects reach the same
temperature
Answer: D. When both objects reach the same temperature.
Explanation: When will heat flow between the objects stop? Heat will always flow from the warmer object to the colder object. The heat transfer will stop when the two objects are at the same temperature and reach thermal equilibrium.
Answer: Heat will always flow from the warmer object to the colder object. The heat transfer will stop when the two objects are at the same temperature and reach thermal equilibrium.
so the answer to your question is c
Explanation:
given that two vectors A=i,2j-2k and B=6i+3j+2k find A +B
Answer:
7i, 5j, 0k
Explanation:
Add up the two vectors.
Add
i+i 1+6 = 7i
j+j 2+3 = 5j
k+k -2+2 = 0k
therefore A+B = (7i, 5j, 0k)
Which types of reactions are also redox reactions?
Answer:
Your ans is B)
Explanation:
Hope its right
if wrong firgive me
What would be the orbital speed and period of a satellite in orbit 1.44 × 10^2 m above Earth?
mass of earth = 5.97x 10 ^ 24 kg , radius of earth = 6.38 x10^6m
pls help
Explanation:
Given that,
We need to find the orbital speed and period of a satellite in orbit [tex]1.44\times 10^2\ m[/tex] above Earth.
The formula for the orbital speed is given by :
[tex]v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times5.97\times 10^{24}}{(1.44\times 10^2+6.38\times 10^6)^2}} \\\\v=3.12\ m/s[/tex]
Let T be the time period of the satellite. It can b solved using Kepler's third law i.e.
[tex]T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2\times (1.44\times 10^2)^3}{6.67\times 10^{-11}\times 5.97\times 10^{24}}\\\\T=5.44\times 10^{-4}\ s[/tex]
Hence, this is the required solution.
The orbital speed of the satellite is 3.13 m/s and the period of the satellite in orbit is 5.44 × 10⁻⁴ s.
The orbital speed of an astronomical object in a gravitational system is the speed at which it revolves around the central point or the speed required to keep an artificial or natural satellite in orbit.
It can be expressed by using the formula:
[tex]\mathbf{v = \sqrt{\dfrac{GM}{r}}}[/tex]
where;
v = orbital velocity of the satelliteG = gravitational constant = 6.67 × 10⁻¹¹M = mass of the satellite body (earth) = 5.97 x 10²⁴ kgr = radius of the satellite
[tex]\mathbf{v = \sqrt{\dfrac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{(1.44 \times 10^2 + 6.38 \times 10^6)^2}}}[/tex]
v = 3.13 m/s
In planetary motion, Kepler's third law states that the square of the period of a planet varies directly proportional to the cubes of the planets' mean distances (d).
The period of the satellite can be estimated by using Kepler's third law. It can be computed by using the formula:
[tex]\mathbf{T^2 =\dfrac{4 \pi^2}{GM}\times r^3}[/tex]
[tex]\mathbf{T^2 =\dfrac{4 \pi^2}{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}\times (1.44 \times 10^2)^3}[/tex]
[tex]\mathbf{T^2 =2.96037718\times 10^{-7}}[/tex]
[tex]\mathbf{T =5.44 \times 10^{-4} \ s}[/tex]
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Sections or chunks of material where atoms are lined up with each other are called...
Answer:
Magnetic domains
Explanation:
Because when the electrons spin around the necleus of an atom, it causes the atom to become a tiny magnet
How much is Coulomb's constant ?
Answer:
8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2
Explanation:
Exact number is 8.9875517923(14)×109 kg⋅m3⋅s−2⋅C−2
Energy is radiated or transmitted in the form of rays or waves or particles.
B. radiation
C. convection
D. conduction
Answer:
B radiation
Explanation:
every type of transmitted waves are radioactive in a way.
What happens when a tennis racket hits
a ball?
A. The ball pushes back on the racket in the opposite
direction.
B. The ball pushes back on the racket in the same
direction.
C. The ball does not push back on the racket.
D. The ball pushes back on the racket perpendicularly.
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a tennis racket hits a ball A. The ball pushes back on the racket in the opposite direction.
When a tennis racket hits a ball, the ball exerts a force on the racket, and according to Newton's third law of motion, the racket exerts an equal and opposite force on the ball. This means that the ball pushes back on the racket in the opposite direction to which the racket struck the ball.
This principle is often referred to as "action-reaction" or "equal and opposite forces." When the racket collides with the ball, the force applied by the racket causes the ball to accelerate in the opposite direction, leading to its movement away from the racket.
Therefore, when a tennis racket hits a ball A. The ball pushes back on the racket in the opposite direction.
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A diagram of a plant cell is shown below.
Which organelle is found in both plant and animal cells?
Cell membrane
Chloroplast
Ο Ο Ο
Large Vacuole
Cell Wall
Answer:
The Cell Membrane is found in both plant and animal cells.
Explanation:
Chloroplast, Large Vacuole and Cell Wall are all found in plant cells.
While eating a peanut butter and jelly sandwich, peanut butter drips on Diana’s shirt. She tries to remove the peanut butter from her shirt by rubbing the spot with water, but it doesn’t work. What is the best explanation for why the water does not remove the peanut butter?
The water and peanut butter have different chemical properties.
The water and peanut butter have different temperatures.
The water and peanut butter have different pressures.
Answer:
The water and peanut butter have different chemical properties.
(Lipids are not soluble in water)
Answer:
a. The water and peanut butter have different chemical properties.
Explanation:
Coulomb is the unit of which quantity?
Answer:
electric charge
Answer:
Electric charge.
Explanation:
Coulomb, unit of electric charge in the metre - kilogram - second - ampere system, the basis of the SI system of physical units. It is abbreviated as C. The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.
A Cambra pouce car traveling at 28 m/s slow
at a rate of at 3.6 m/s every second find.
a) The time taken for the police car to come to Stop?
Answer:
t = 7.8 seconds
Explanation:
Given that,
The initial speed of the car, u = 28 m/s
Acceleration of the car, a = 3.6 m/s²
We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.
[tex]v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s[/tex]
So, the required time is 7.8 seconds.
Find the velocity of a dolphin that swims 55 m in 5.0 s.
Answer: 11 m/s
Explanation: velocity = distance /time = 55 m /5.0 s
Answer:40km/h
Explanation:
Please help
The period of an oscillation is measured to be 0.0833 seconds. What is
the frequency of this oscillation? *
1.0833 Hz
0.287 Hz
9.8 Hz
12 Hz
0.007 Hz
Answer:
your
answer is
12.004
PLEASE HELP ME WITH THIS ONE QUESTION
Two substances of different temperatures are brought into thermal contact. While the objects come to equilibrium, some heat is lost to the environment. How would that affect the final temperature?
A) it would be higher
B) it would change unpredictably
C) it would remain the same
D) it would be lower
Answer:
the correct is D
Explanation:
In the calorimetry exercises, if there are no losses, we assume that all the heat lost by one body is absorbed by the other, but if there are losses
Q_ {yielded} = Q_ {absent} + Q_ {lost}
Since energy cannot be created or destroyed, they only ask to change, therefore the term of the absorbed heat must decrease, consequently the final temperature of the system is lower when there is loss of energy.
When checking the answers, the correct one is D
In fatal crashes, more than __________% of passenger car occupants who were totally ejected from the vehicle were killed.
Answer:
it would be 83% in a fatal crash.
What is the first velocity of the car with three washers
at the 0.25 meter mark?
m/s
Calculate the first and second velocities of the car with
three washers attached to the pulley, using the formulas
V1 = 0.25 m/ty, and
v2 = 0.25 m/(t2- ty)
where t1 and t2 are the average times the car took to
reach the 0.25 and the 0.50 meter marks. Record these
velocities, to two decimal places, in Table E.
What is the second velocity of the car with three
washers at the 0.50 meter mark?
m/s
Answer:
What is the first velocity of the car with three washers
at the 0.25 meter mark? 0.19
What is the second velocity of the car with three
washers at the 0.50 meter mark? 0.45
Explanation:
Look at the question carefully.
The person above me got the answer wrong.
That answer is for a very similar question, but not this one.
(1) The first velocity of the car with two washers at the 0.25 meter mark is 0.125 m/s.
(2) The second velocity of the car with two washers at the 0.5 meter mark is 0.25 m/s.
What is velocity?Velocity is the rate of change of displacement with time. The velocity of the cars depends on displacement and time of motion.
First velocity of the car at the 0.25 meter mark
The first velocity is calculated as follows;
v1 = 0.25 m / t1
let t₁ = 2 s
v₁ = 0.25/2
v₁ = 0.125 m/s
Second velocity of the car at the 0.5 meter mark
v2 = 0.25 m / (t2 – t1)
let t₂ = 3 s
v₂ = 0.25(3 - 2)
v₂ = 0.25 m/s
The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,
v = d/t
Here, d is the distance covered.
And t is the average time taken to cover the distance.
Then the first velocity of the car at 0.25 m is,
v1 = d1/t1
v1 = 0.25 / t1
Here, t1 is the average time for the first distance.
And the second velocity of the car with four washers at the 0. 50 m mark is,
v2 = d2/t2
v2 = 0.50 /t2
Therefore, here, t2 is the average time for the second distance.
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What is the number of waves that pass a fixed ping in a given amount of time?
a car whose tires have radii of 50cm travels at 20km/h. what is the angular velocity of the tire
Answer:
0.225 s^-1
Explanation:
Please mark as brainliest
The angular velocity of the tire is 11.12 rad/s.
Angular velocity: This is the change in angular direction per time. The S.I unit is rad/s.
⇒ Formula:
v = rω.................... Equation 1⇒ Where:
v = linear velocity of the carr = radius of the carω = angular velocity of the car⇒ Make ω the subject of the equation
ω = v/r.............. Equation 2From the question,
⇒ Given:
v = 20 km/h = 20(1000)/(3600) m/s = 5.56 m/sr = 50 cm = 50/100 = 0.5 m⇒ Substitute these values into equation 2
ω = 5.56/0.5ω = 11.12 rad/sHence, The angular velocity of the tire is 11.12 rad/s
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A 1.6 kg ball is attached to the end of a 0.40 m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80 kg block that is at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3 m/s. What is the speed of the ball just after the collision
Answer:
the speed of the ball just after the collision is 1.5 m/s.
Explanation:
Given;
mass of the ball, m₁ = 1.6 kg
initial velocity of the ball, u₁ = 0
mass of the block, m₂ = 0.8 kg
initial velocity of the block, u₂ = 0
final velocity of the block, v₂ = 3 m/s
let the final velocity of the ball after collision = v₁
Apply the principle of conservation of linear momentum for elastic collision;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.6 x 0 + 0.8 x 0 = 1.6 x v₁ + 0.8 x 3
0 = 1.6v₁ + 2.4
-1.6v₁ = 2.4
v₁ = -2.4 / 1.6
v₁ = - 1.5 m/s
v₁ = 1.5 m/s (in opposite direction of the block)
Therefore, the speed of the ball just after the collision is 1.5 m/s.
g A 4 lb weight stretches a spring 2 ft in equilibrium. It is attached to a damping mechanism with constant c. (a) Find the value of c for which the motion is critically damped. (b) If the motion is critically damped, find the displacement y(t) when the spring is initially displaced 6 inches above equilibrium and given a downward velocity of 3 ft/sec.
Solution :
Given :
Weight = 4 lb
Stretched of a spring in equilibrium,Δ = 2 ft
a). We know that
F = kΔ
4 = k x 2
k = 2 lb/ft
∴ Stiffness of the spring is, k = 2 lb/ft
Motion is critically damped.
[tex]$\epsilon = 1$[/tex]
[tex]$\epsilon=\frac{C}{C_c} = 1$[/tex]
[tex]$C=C_c[/tex]
[tex]$C=C_c=\sqrt{4k_m}[/tex]
[tex]$C=\sqrt{4 \times 2 \times \left(\frac{4}{32.174}\right)}[/tex]
C = 0.99729 lb.s/ft.
b). Displacement
[tex]$y(t)=y_0 \sin (\omega t)$[/tex]
[tex]$\dot{y}(t)= y_0 \omega \cos (\omega t)$[/tex]
[tex]$[\dot{y}(t)]_{mon}= y_0 \omega $[/tex]
Initial displacement = 6 inches
[tex]$y_0 = 0.5 \ ft , \ \ \ \dot y (t) = 3 \ ft/sec$[/tex]
[tex]$\Rightarrow 3=0.5 \times \omega$[/tex]
[tex]$\Rightarrow \omega = 6$[/tex]
Therefore, displacement :
[tex]$y(t)=y_0 \sin (\omega t)$[/tex]
[tex]$y(t)=0.5 \sin (6 t)$[/tex]
strong bases are good conductors of
Answer:
Electricity ⚡️
Explanation:
Which bond(s) shown are double bonds?
Answer:
I'm pretty sure its the 2nd one.
A train car, which has a mass of 2000 kg, is rolling along with a velocity of 20 m/s East. It
strikes a stationary car, which also has a mass of 2000 kg, and they stick together after the
collision. What is their final velocity? (include appropriate units in your answer) * 15
10m/s East
Explanation:
p=mv
m1v1 = m2v
p = m1v1
2000kg*(20m/s) = 40000kg*m/s
Add the two masses together for m2
p = m2v2
40000kg*m/s = 4000kg * v2
v2 = 10m/s
Arrange the following substances from the lightest to the heaviest:
Cl2, CH4; H20; NH3, N2
A. H2O<NH,< N2 CH4Cl2
B. CH< NH< H-0< < Cl2
C. Ny< Cl< H2O< CH«<NH3
D. NH;< CH«< Cl< H2O< N2
molecular weights are written in the picture.
CH4<NH3<H2O<Cl2
PLEASE HELP
The spine is part of which system?
A. Circulatory System
B. Central Nervous System
C. Endocrine System
Answer:
Explanation:
B. Central Nervous System
Create a concept map that shows the relationships among the following: crest, trough, compression, rarefaction, wave length, wave frequency, amplitude, and wave
speed.
Uhm.. based on what? Can you please specify/add an image or some more text and elaborate?
A baseball is thrown a distance of 20 m what is its speed if it takes 0.5 seconds to cover the distance
Answer:
40m/s
Explanation:
