How many moles of oxygen gas (02) are
needed to completely react with 54.0 g of aluminum?

4A1+30₂ → 2Al2O3

54.0 g Al

1 mol Al 3 mol O₂
26.98 g Al 4 mol Al



[?] mol O₂

How Many Moles Of Oxygen Gas (02) Areneeded To Completely React With 54.0 G Of Aluminum?4A1+30 2Al2O354.0

Answers

Answer 1

The number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.

Number of moles of the reacting aluminum

moles = reacting mass/molar mass

moles = 54/27

moles = 2 moles

From the given reaction of oxygen and aluminum;

4Al +  30₂   →   2Al₂O₃

4 moles of Al ----------> 3 moles of oxygen

2 moles of AL --------> ? moles of oxygen

= (2 x 3)/4

=  1.5 moles

Thus, the number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.

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Related Questions

Why does carbonic acid gives an acid salt but hydrochloric acid does not?​

Answers

Answer:

Solution. Carbonic acid is a dibasic acid with two replaceable hydrogen ions; therefore it forms one acid salt or one normal salt. Hydrochloric acid is a monobasic acid with one replaceable hydrogen ion and so forms only one normal salt.

Explanation:

Calculate the percent covalent character of a chemical bond between iodine and lithium.

Answers

Answer:

27966692

Explanation:

I don't know if this is right or not

It requires 2,500 joules to raise a certain amount of water (c = 4.186 j/g°c) from 20.0°c to 60.0°c. what is the mass of the water that is being heated? 15 g 40 g 63 g 80 g

Answers

Answer:

15 grams of water will absorb 2,500 Joules  in going from 20.0 to 60.0 C.

Explanation:

The heat involved in raising a mass (m) of a substance with a specific heat (c) from one temperature to another (Delta T) is given by:

Heat = mc(Delta T)

2,500 Joules = m*(4.186J/gC)*(60C-20C)

2,500 Joules = m*(4.186J/gC)*(40C)

2,500 Joules = m*(4.186J/gC)*(40C)

m = (2,500J)/(4.186*40J/g)

m = 14.93 grams

Answer: B (15g)

Explanation:

The volume of a gas is inversely proportional to the pressure of a gas is known as:.

Answers

Answer:

Boyle's law states this.

What is the name of this hydrocarbon?
hexane
O heptane
O octane
O pentane
Mark this and return
H H H H H
|||||
H-C-C-C-C-C-H
|||II
H H H H H
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Submit

Answers

Answer:

alkanes alkens alkenes and a bromatic hydrocarbons

Answer:

[tex]\huge\boxed{\sf Pentane}[/tex]

Explanation:

The given compound has:5 carbonsall single bonds

Prefix for 5 carbons = Pent

Suffix for all single bonds = ane (since the compound is alkane)

So, the name of this hydrocarbon is:

Pentane

[tex]\rule[225]{225}{2}[/tex]

How many grams of nitrogen,
N2, would be required to react with
6.25 moles hydrogen, H2?

N₂ + 3H₂ → 2NH3

[?] g N₂

Answers

Answer: 29.2

Explanation:

From the coefficients of the equation, we know that for every 3 moles of hydrogen consumed, 1 mole of nitrogen is consumed.

This means we would need 6.25/3 = 2.0833333333333 mol of nitrogen.

Nitrogen has an atomic mass of 14.007 g/mol, so 2.0833333333333 moles of nitrogen have a mass of (14.007)(2.0833333333333) = 29.2 g (to 3 sf)

What happens is the PH changes

Answers

The changes in different properties such as concentration etc will change if the pH experiences a change.

What is pH?

This is referred to the power of hydrogen and is a measure of the degree of acidity or alkalinity of a substance.

When pH changes, the concentration as well as other properties in this context.

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Why did mendeleev leave blank spaces in his version of the periodic table?.

Answers

Answer: He left blank spaces for undiscovered elements to be added to the table.

Explanation:

Answer:

Mendeleev left blank spaces in his version of the periodic table because he left the gaps to place elements not known at the time

determine the enthalpy change when 7.08g of Ag is obtained. use the abbreviated form of the unit in your answer.
2AgBr(s) -> 2Ag(s) + Br2(l) deltaH = -220kJ

Answers

2AgBr(s) ⇒ 2Ag(s) + Br₂(l) ΔH = -220kJ ⇒ for 2 mol Ag

mol Ag = 7.08 : 108 g/mol = 0.065

the enthalpy change = 0.065/2 x -220 kJ = -7.15 kJ

How many grams of nitrogen,
N2, would be required to react with
6.25 moles hydrogen, H2?

Answers

N₂ + 3H₂ → 2NH₃

moles N₂ = 1/3 x 6.25 = 2.083

Answer:

2.083 moles of N₂ would be required to react with 6.25 moles of H₂.

Explanation:

Let us first write the balanced chemical equation :

      N₂ + 3H₂ → 2NH₃

Therefore from this equation it is clear that:

3 moles of H₂ require 1 mole of N₂

∵ 1 mole of H₂ requires [tex]\frac{1}{3}[/tex]  moles of N₂

∵ 6.25 moles of H₂ requires [tex]\frac{(1*6.25)}{3}[/tex][tex]=2.083[/tex] moles of N₂

MOLE CONCEPT :

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter. A mole is defined as the amount of substance containing the same number of discrete entities (such as atoms, molecules, and ions) as the number of atoms in a sample of pure 12C weighing exactly 12 g. One Latin connotation for the word “mole” is “large mass” or “bulk,” which is consistent with its use as the name for this unit. The mole provides a link between an easily measured macroscopic property, bulk mass, and an extremely important fundamental property, number of atoms, molecules, and so forth.

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The theoretical yield of silver was
determined at 241 g Ag through
calculation. Instead, the reaction
generated only 192 g Ag. What is the percent yield of the reaction?

2AgNO3 + Zn → 2Ag + Zn(NO3)2

[?] %

Answers

Answer:

79.7%

Explanation:

Percentage yield = (actual yield/theoretical yield)*100%

Therefore percentage yield for this experiment is: [tex]\frac{192}{241} *100%[/tex]%

[tex]= 0.79668*100[/tex]%

Percentage yield = 79.668%

Rounded to 3 significant figures is 79.7%

Hope this helped!

What is the mass percent of Fe in iron(II) chloride

Answers

its

28.090%
hope its helpful >~

Considering the combustion reaction of propane again, what mass of propane (C3Hg) is necessary to react with 4.53 g of oxygen? C3H8 +5023CO₂ + 4H₂O 0.0256 g C3H8 1.13 g C3H8 1.25 g C3H8 2.50 g C3H8

Answers

Answer:

1.25 g C3H8

Explanation:

edge lol

An unidentified element has one electron in the outer most shell. Explain what
characteristics you would expect this element to have? Your response should include
three or four sentences

Answers

Answer:

They are unstable as single atoms, but can become stable by losing or sharing their one valence electron.

Explanation:

hope it helps you and give me a brainliest

Given the balanced equation representing a
reaction:
2H₂ + O₂ → 2H₂O + energy
4. Which mass of oxygen completely reacts with
4.0 grams of hydrogen to produce 36.0 grams of
water?
(1) 8.0 g
(2) 16.0 g
(3) 32.0 g
(4) 40.0 g

Answers

Answer: it would be number 3, 32.0g

Find the magnetic force experienced by a proton moving with the speed of 3 × 105 m/s in the magnetic field B of magnitude 6 × 10-5 T.

Answers

The magnetic force experienced by a proton moving with a speed of 3 ×[tex]10^{5}[/tex] m/s in the magnetic field B of magnitude 6 ×[tex]10^{-5}[/tex] T will be 2.88×[tex]10^{-18}[/tex] N.

Magnetic force can be defined as the attraction or repulsion force that arises between electrically charged particles due to the motion of the charged particles.

Given,

Speed = 3×[tex]10^{5}[/tex] m/s

Magnetic Field, B= 6 ×[tex]10^{-5}[/tex] T

Magnetic force is the product of velocity, the charge of a proton, and the magnetic field present there.

The magnetic force can be represented as:

F=qvB

F=1.6×[tex]10^{-19}[/tex]×3×[tex]10^{5}[/tex] ×6 ×[tex]10^{-5}[/tex]

F=2.88×[tex]10^{-18}[/tex] N

Hence, the magnetic force experienced by the proton will be 2.88×[tex]10^{-18}[/tex] N.

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What type of molecule is pentanal?
o a. aldehyde
o b. ester
o c. ketone
o d. alcohol

Answers

Answer:

aldehyde

Explanation:

it ends with "al" of "al"dehyde, always check the end

What is the change in freezing
point, ATf, when the 0.195 m
aqueous solution of K2S dissolves
into 3 particles?

Answers

The change in the freezing point of the solution is 1.1°C.

What is freezing point depression?

The freezing point depression is a colligative property thus we must take note of the number of particles in solution.

Using;

ΔT = k m i

k = 1.86 °C/m

m = 0.195 m

i = 3

ΔT = 1.86 °C/m *  0.195 m * 3

ΔT = 1.1°C

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Answer:

1.0881

Explanation:

Correct answer for Acellus

If you have half a mole of octane (c8h18), how much water is produced? 2c8h18 + 25o2 --> 16co2 + 18h2o

Answers

Answer:

4.5 moles H₂O

       or

81.072 g H₂O

Explanation:

I am not exactly sure whether you want moles H₂O or grams H₂O. So, I'll calculate both. To find the moles H₂O, you'll need to covert moles C₈H₁₈ to moles H₂O via the mole-to-mole ratio from the reaction coefficients. To find the grams H₂O, you need to convert moles H₂O to grams H₂O via the molar mass.

2 C₈H₁₈ + 25 O₂ ---> 16 CO₂ + 18 H₂O

0.5 mole C₈H₁₈          18 moles H₂O
-----------------------  x  -------------------------  = 4.5 moles H₂O
                                  2 moles C₈H₁₈

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol

Molar Mass (H₂O): 18.016 g/mol

4.5 moles H₂O         18.016 g
----------------------  x  ----------------  =  81.072 g H₂O
                                  1 mole

What will be the next step in this calculation?​

Answers

You have to first do “X” then move on to your other answer then once u get that you add then that would be your final answer:)
Do it how you saw it.

just multiply 2.188x10^6 by 2 and divide the answer by 3, the answer is your V.

let's do it:

V = 2.188x10^6 x 2

————————

3

V = Answer

————

3

V = (what you got)

Try finding them with calculator or something.

Hope this helps.Good luck ✅.And I wish this can still help.

Which of the following reactions depicts a synthesis reaction?

Answers

Answer:

C combination reaction (synthesis) reaction

Explanation:

two chemicals are combined

Answer this please!!!

Answers

Answer:

c

Explanation:

The answer is both i and iii.

what is the empirical formula for a compound if a sample contains 1.0 g of S and 1.5 g of O?
1.SO
2.SO3
3.S202
4. S203

Answers

I think it’s SO3 I’m not quite sure though

How does the number of molecules in 1 mol of oxygen compare with the number of molecules in 1 mol of nitrogen?
O 1 mol of oxygen has fewer molecules.
O 1 mol of oxygen has more molecules.
O Each sample has the same number of molecules.
O The molecules cannot be compared without knowing the mass.
Mark this and return
4
Save and Exit
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Subinit

Answers

Answer:

Each sample has the same number of molecules.

Explanation:

This is true by Avogadro's law.

Rosalind franklin helped discover the structure of what molecule?.

Answers

That would be...*drumroll* the structure of DNA!

If 0.889J of heat causes a 0.124 degree C temperature change, what mass of water is present?

Answers

0.889 ÷ 4187 ÷ 0.124 = 0.00171

Use the periodic table to answer the following questions.

What is the predicted order of first ionization energies from highest to lowest for beryllium, calcium, magnesium, and strontium?

Be > Ca > Mg > Sr

Be > Mg > Ca > Sr

Ca > Sr > Be > Mg

Sr > Ca > Mg > Be

Answers

From the  highest to lowest Ionization Energies for beryllium, calcium, magnesium, and strontium, the order is:  Be > Mg > Ca > Sr

How to use the periodic table?

Ionization energy is defined as a measure of the difficulty in removing an electron from an atom or ion or the tendency of an atom or ion to give off an electron.

Now, ionization energy usually decreases as it descends in a group.  Thus, from the  highest to lowest for beryllium, calcium, magnesium, and strontium, the order is determined as:

Be > Mg > Ca > Sr

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Answer: B (BE > MG > CA > SR)

Explanation: ON EDGE

: 2NaOH + H,S0A - Na,SO A + 2H,0 How many moles of sodium sulfate (Na,SO,) reproduced when 5.0 moles of sodium hydroxide (Na0H) are reacted with excess sulfuric acid? A 2.5 moles B 1.0 moles C 5.0 moles D 2.0 moles

Answers

From the reaction, we can see that the number of moles produced is 2.5 moles of Na2SO4

What is a reaction?

Chemical reaction involves the combination between two or more species. In this case, the reaction  equation is; 2NaOH + H2S04 ----> Na2SO4 + 2H20.

Now we are told that sulfuric acid is in excess hence NaOH is the limiting reactant.

If 2 moles of NaOH produces 1 mole of Na2SO4

5 moles of NaOH produces 5 moles  * 1 mole/ 2 moles

= 2.5 moles of Na2SO4

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You examine an ice core sample from 10,000 years ago when global temperatures were unusually high. Based upon past studies and insights from current GHG levels, we expect that atmospheric levels of carbon dioxide Group of answer choices were high but methane levels were low. and methane were unusually low. and methane were unusually high. were low but methane levels were high.

Answers

Methane was unusually high is the correct option. Hence, option B is correct.

What is methane?

Methane is the simplest member of the paraffin series of hydrocarbons and is among the most potent greenhouse gases. Its chemical formula is [tex]CH_4[/tex].

As the ice compacts over some time, tiny bubbles of the atmosphere or surroundings including greenhouse gases like carbon dioxide and methane—press inside the ice. These air pocket “fossils” give samples of what the atmosphere was kind when that layer of ice formed.

Based upon past studies and insights from current GHG levels, we assume that atmospheric levels of carbon dioxide and methane were unusually low.

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calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​

Answers

Answer:

0.736

Explanation:

*I am not sure what you mean by "carbon tetrahedral". I'm assuming you are just referring to individual carbon.*

To find the mole percent, you need to (1) convert grams benzene and grams carbon to moles (via their molar masses) and then (2) calculate the mole fraction (via the mole fraction formula).

(Step 1)

Benzene = C₆H₆

Molar Mass (C₆H₆) = 6(12.01 g/mol) + 6(1.008 g/mol)

Molar Mass (C₆H₆) = 78.108 g/mol

70 g C₆H₆          1 mole
---------------  x  ------------------  =  0.896 mole C₆H₆
                         78.108 g

Molar Mass (C) = 12.01 g/mol

30 g C           1 mole
------------  x  -----------------  =  2.50 mole C
                       12.01 g

(Step 2)

                                           moles solute
Mole Fraction  =  ----------------------------------------------
                              moles solute + moles solvent

                                              2.50 mole C
Mole Fraction  =  -------------------------------------------------  =  0.736
                             (0.896 mole C₆H₆ + 2.50 mole C)

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