How many moles of chlorine gas react when 320. 5 grams of aluminum chloride is formed?

The pressure of the gas can be calculated using the combined gas law equation. The pressure of the gas at STP is 1 atm. Therefore, the pressure of the gas at 85.0°C is 0.289 atm.

Given that a gas occupies 3.05 L at STP, we can assume that the gas is at a pressure of 1 atm and a temperature of 273 K. We can use the ideal gas law to find the number of moles of gas in the container at STP:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for n, we get:

n = PV/RT

Substituting in the values for P, V, R, and T, we get:

n = (1 atm)(3.05 L)/(0.0821 L·atm/mol·K)(273 K)

n = 0.125 mol

Now, we know that the volume of the gas has increased to 9.85 L and the temperature has increased to 85°C. We need to find the new pressure of the gas.

First, we need to convert the temperature to Kelvin:

85°C + 273 = 358 K

Next, we can use the combined gas law to find the new pressure of the gas:

P1V1/T1 = P2V2/T2

Substituting in the values we know:

(1 atm)(3.05 L)/(273 K) = P2(9.85 L)/(358 K)

Solving for P2, we get:

P2 = (1 atm)(3.05 L)/(273 K)(9.85 L/358 K)

P2 = 0.289 atm

Therefore, the pressure of the gas at the new volume and temperature is 0.289 atm.

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The amount of Ca(OH)₂ produced = 5.2 g which is calculated in the below section.

NUMBER OF MOLES of HCl = Molarity of solution x Volume of Solution

# of moles of HCl = (0.40 mol/L ) x 350 mL

                              = (0.40 mol/L ) x 0.350 L

                              = 0.14 mol

The mass of HCl that makes 0.14 mol of HCl

Mass of HCl= # of moles x molar mass of HCl

Mass of HCl = 0.14 mol x 36.5 g/ mol

Mass of HCl = 5.11g

As per Stoichiometry , 1g of HCl reacts with 1.015 g of Ca (OH)₂

So, 5.11g of HCl can react with 5.11 x 1.015  g

                                                 = 5.1865 g or 5.2 g of Ca(OH)₂

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The molar concentration of the solution is 0.25 M.

The molar concentration of a solution, also known as molarity, is defined as the number of moles of solute per liter of solution.

In this case, the amount of Ca(OH)2 dissolved is 0.55 mol and the volume of water used is 2.20 L. Therefore, the molar concentration can be calculated using the formula:

Hence, the molar concentration of the solution is 0.25 M.

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Based on the nitrogen content, you should choose ammonium phosphate as it contains a higher percentage of nitrogen (28.2%) compared to ammonium sulfate (21.2%), which will potentially yield a larger corn crop for ethanol production.

To determine which fertilizer, ammonium sulfate or ammonium phosphate, would yield the largest amount of corn for ethanol production, you need to consider the nitrogen content in each fertilizer.

Ammonium sulfate has the chemical formula (NH4)2SO4. It contains 2 nitrogen atoms (N), 8 hydrogen atoms (H), 1 sulfur atom (S), and 4 oxygen atoms (O). The molar mass of nitrogen is 14 g/mol, so the nitrogen content in ammonium sulfate is:
2(N) = 2(14 g/mol) = 28 g/mol.

The molar mass of ammonium sulfate is 132.14 g/mol. To calculate the percent of nitrogen in ammonium sulfate, divide the nitrogen mass by the total molar mass and multiply by 100:
(28 g/mol) / (132.14 g/mol) × 100 = 21.2%.

Ammonium phosphate has the chemical formula (NH4)3PO4. It contains 3 nitrogen atoms, 12 hydrogen atoms, 1 phosphorus atom, and 4 oxygen atoms. The nitrogen content in ammonium phosphate is:
3(N) = 3(14 g/mol) = 42 g/mol.

The molar mass of ammonium phosphate is 149.09 g/mol. To calculate the percent of nitrogen in ammonium phosphate, divide the nitrogen mass by the total molar mass and multiply by 100:
(42 g/mol) / (149.09 g/mol) × 100 = 28.2%.

Based on the nitrogen content, you should choose ammonium phosphate as it contains a higher percentage of nitrogen (28.2%) compared to ammonium sulfate (21.2%), which will potentially yield a larger corn crop for ethanol production.

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The air temperature difference in 2050 from 2000 could be 1.8 - 4.0 degrees Celsius.

Temperatures refer to the degree of hotness or coldness of a substance or environment. Temperatures are usually measured with thermometers, which measure the thermal energy of a system. Temperatures can be measured in Fahrenheit, Celsius, or Kelvin. In general, temperatures tend to increase as the amount of thermal energy in a system increases.

It is impossible to accurately predict the exact air temperature difference in 2050 from 2000 without more information. However, it is estimated that the global average temperature could increase anywhere from 1.8 - 4.0 degrees Celsius by 2050, compared to pre-industrial levels. Therefore, a reasonable range of the air temperature difference in 2050 from 2000 could be 1.8 - 4.0 degrees Celsius.

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I₂ is a solid, Br₂ is a liquid, while Cl₂ and F₂ are gases because of their increasing molecular size and decreasing strength of their intermolecular forces.

The main factor influencing the physical states of halogens is the strength of the intermolecular forces (Van der Waals forces) between their molecules.

As you move down Group 17 in the periodic table (from F₂ to I₂), the size and mass of the halogen molecules increase. Larger molecules have a greater number of electrons, leading to stronger dispersion forces (a type of Van der Waals forces) between molecules.

For I₂, these forces are strong enough to hold the molecules together in a solid form. For Br₂, the forces are slightly weaker but still strong enough to form a liquid. However, in Cl₂ and F₂, the forces are weaker, allowing the molecules to be in a gaseous state at room temperature.

In summary, the physical states of the halogens depend on the strength of their intermolecular forces, which is influenced by the size and mass of the molecules.

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Without knowing the balanced chemical equation for the reaction involving A2, B, D, and E, it is not possible to determine the equilibrium constant Kp.

The equilibrium constant Kp is specific to a particular chemical reaction at a given temperature, and is determined by the stoichiometry of the reaction and the relative partial pressures of the reactants and products at equilibrium.

Therefore, to calculate Kp, we need to know the balanced chemical equation for the reaction involving A2, B, D, and E, as well as the partial pressures of the gases at equilibrium.

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The mass of copper sulfate in 30.0 cm3 of this solution is 0.957 g.

The concentration of the copper sulfate solution is given by:

c = n ÷ V

c = 0.100 mol/0.500 dm³

c = 0.200 mol/dm³

To calculate the mass of copper sulfate in 30.0 cm³ of this solution, we first need to calculate the number of moles of copper sulfate in this volume:

n = c x V

n = 0.200 mol/dm³ x (30.0 cm³ ÷ 1000 cm³/dm³)

n = 0.006 mol

The mass of copper sulfate can be calculated using its molar mass:

m = n x Mr

m = 0.006 mol x 159.5 g/mol

m = 0.957 g

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Type of Acid-Base Reactions: Acid-Base Neutralization Reactions. A hydroxide ion (OH-) is an anion with a single hydrogen atom and two oxygen atoms.

Hydrogen is the lightest of all elements, and is a colorless, odorless, tasteless, non-metallic gas. It is the most abundant element in the universe, making up around 75% of all matter. Hydrogen has three isotopes: protium (the most common), deuterium, and tritium. Hydrogen is found on Earth in compounds of other elements, such as water (H2O), and in hydrocarbons, such as natural gas (CH4). It is a key component of many fuels and can be used to generate electricity through fuel cells.

All acid-base neutralization reactions produce a salt and water. The salt will depend on the acid and base used in the reaction.The pH of a 0.25M solution of H3O+ is 0.The pH of a 6.3x10-8M solution of H3O+ is 7.21.The pH of 0.25M solution of H3O+ (0) is a base, while the pH of 6.3x10-8M solution of H3O+ (7.21) is neutral.The pH of 0.25M solution of H3O+ (0) is a strong acid, while the pH of 6.3x10-8M solution of H3O+ (7.21) is a weak acid.

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The volume of the 3.5 m solution containing 9.82 g of Pb(NO3)4 is about 4.103 mL.

To calculate the volume of the solution, we need to use the formula for molality:

Molality (m) = moles of solute / kg of solvent

First, we need to find the moles of Pb(NO3)4 in 9.82 g. The molar mass of Pb(NO3)4 is approximately 683.56 g/mol.

Moles of Pb(NO3)4 = 9.82 g / 683.56 g/mol ≈ 0.01436 mol

Now, we can use the given molality (3.5 m) to find the mass of the solvent:

0.01436 mol = 3.5 m * kg of solvent
kg of solvent = 0.01436 mol / 3.5 m ≈ 0.004103 kg

Since the solvent is water, we can assume that 1 kg of water is equal to 1 L. Therefore, the volume of the solution is:

0.004103 kg * 1000 mL/kg ≈ 4.103 mL

So, the volume of the 3.5 m solution containing 9.82 g of Pb(NO3)4 is approximately 4.103 mL.

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The characteristic that would be preferred for a better resonance structure is maximized bond strength. Option B is correct.

Maximizing bond strength is a crucial characteristic for a better resonance structure because it leads to a more stable structure. Resonance structures are a set of contributing structures that show the delocalization of electrons in a molecule. These structures should have similar energies and contribute equally to the actual structure of the molecule. The more stable a resonance structure, the greater its contribution to the actual structure.

Formal charges are important for resonance structures, but a minimal formal charge or negative formal charges on the most electronegative atom are not the only factors that contribute to a better resonance structure. In fact, some resonance structures may have formal charges that are not minimized or negative formal charges on less electronegative atoms.

Maximizing bond strength ensures that the structure is stable and contributes significantly to the actual structure of the molecule. Therefore, maximizing bond strength is the most important characteristic for a better resonance structure. Option B is correct.

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At STP, 1.5 L of nitrogen gas will produce 3 L of NH₃ gas.

The balanced chemical equation for the reaction is N₂(g) + 3H₂(g) --> 2NH₃(g). According to the stoichiometry, 1 mole of nitrogen gas (N₂) reacts with 3 moles of hydrogen gas (H₂) to produce 2 moles of ammonia gas (NH₃). At STP, the volume of one mole of any gas is 22.4 L.

Step 1: Calculate the moles of N₂ in 1.5 L.
Moles of N₂ = (Volume of N₂ / 22.4 L/mol) = 1.5 L / 22.4 L/mol = 0.067 moles.

Step 2: Use the stoichiometry to find the moles of NH₃ formed.
Moles of NH₃ = 2 * Moles of N₂ = 2 * 0.067 moles = 0.134 moles.

Step 3: Calculate the volume of NH₃ formed at STP.
Volume of NH₃ = (Moles of NH₃ * 22.4 L/mol) = 0.134 moles * 22.4 L/mol = 3 L.

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Dalton's theory of the "indivisible" atom was refuted by the discovery of subatomic particles by J.J. Thompson and the Rutherford model.

Spectral lines of elements are discrete wavelengths of light, unlike the continuous spectrum of white light. Electrons in the ground state have the lowest energy, while those in the excited state have higher energy. The Balmer series produces specific wavelengths, frequencies, and energies when n2=3 and n1=2.

The wave number of a line in the Lyman series is 10282383.75 m^-1, with a frequency of 2.92 x 10^14 Hz and an energy of 1.94 x 10^-19 J. The nucleus accounts for an atom's mass, and the number of protons determines the element's identity.

Atomic masses are not whole numbers because they reflect the abundance of different isotopes. The atomic mass of magnesium is 24.31, calculated using the percent abundance and mass of each isotope.

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The first substance that Jake collected is likely a base. The slippery feel is a common characteristic of bases, and the ability to conduct electricity in water indicates the presence of ions (typically hydroxide ions, OH-) which are formed when the base dissolves in water.

The second substance that Jake collected is likely an acid. The formation of hydrogen gas when magnesium is added to an acid is a common characteristic of acids. The reaction can be written as:

Mg + 2HCl → MgCl2 + H2

where HCl represents hydrochloric acid. The production of hydrogen gas indicates the presence of H+ ions, which are characteristic of acids.

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The best option to help you see if the crime scene sample can be linked to the suspect would be the suspect's twin brother. The correct answer choice is "The suspect’s twin brother"

This is because twins, specifically identical twins, share almost 100% of their DNA. Comparing the DNA sample from the crime scene to the twin brother's DNA would provide the most accurate and reliable indication of whether the suspect is linked to the crime scene or not.

Other family members, such as the cousin, grandfather, and stepmother, would share a lesser degree of genetic similarity with the suspect, making it less conclusive for establishing a link.

Therefore, "The suspect’s twin brother" is the correct answer choice.

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The retentate flow rate is 5,021.862 kg/h and the permeate flow rate is 5,021.862 kg/h. The membrane surface area required is 3,517.948 m².

Permeate flow is the rate at which a fluid passes through a membrane. It is a measure of the membrane's permeability, which is the ability of a substance to pass through a membrane. Permeate flow is used in many industrial processes, such as purification of fluids, separation of compounds, and concentration of liquids.

The first step is to calculate the mass flow rate of the feed. This is given by the equation:

Mass flow rate (kg/h) = Feed flow rate (kg/h) x Feed concentration (wt%)

Mass flow rate = 9,905 kg/h x 57.5 wt% = 5,686.625 kg/h

Next, we need to calculate the flow rate of the retentate and permeate in kg/h. This is given by the equation:

Flow rate (kg/h) = Mass flow rate (kg/h) x Retentate/Permeate concentration (wt%)

Retentate flow rate = 5,686.625 kg/h x 16.4 wt% = 931.939 kg/h

Permeate flow rate = 5,686.625 kg/h x 88.2 wt% = 5,021.862 kg/h

Finally, we need to calculate the membrane surface area in m². This is given by the equation:

Membrane surface area (m²) = Permeate flow rate (kg/h) / Total permeate mass flux (kg/m²-h)

Membrane surface area = 5,021.862 kg/h / 1.43 kg/m²-h = 3,517.948 m².

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The solvation of borax in water is an exothermic process. This means that energy is released when borax dissolves in water.

This can be seen in the fact that the temperature of the solution increases as borax dissolves in water, indicating that energy is being released into the surroundings.

The reason for this exothermic behavior is that the solvation process involves the breaking of the ionic bonds between borax molecules and the formation of new bonds between the borax ions and water molecules.

The energy released in the formation of these new bonds is greater than the energy required to break the existing bonds, resulting in a net release of energy.

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Answer:

Welcome to the project on communicating design details for the properties and uses of unsaturated hydrocarbons. This project aims to enhance your understanding of the characteristics and applications of unsaturated hydrocarbons.

Here are the steps to complete this project:

Step 1: Research

Research the different types of unsaturated hydrocarbons, including alkenes and alkynes. Find out their general properties, such as their reactivity, flammability, and solubility. Also, identify their uses in various industries, such as plastics, rubber, and fuel.

Step 2: Create a Design

Using your research findings, create a design to visually communicate the properties and uses of unsaturated hydrocarbons. You can use tools like Canva, PowerPoint, or other design software to create infographics, posters, or slideshows.

Step 3: Incorporate Key Information

Incorporate the key information you gathered in step 1 into your design. Make sure to include the following details:

Definitions of unsaturated hydrocarbons, alkenes, and alkynes

Properties of unsaturated hydrocarbons, including reactivity, flammability, and solubility

Applications of unsaturated hydrocarbons in various industries, such as plastics, rubber, and fuel

Examples of unsaturated hydrocarbons, such as ethene and propene for alkenes, and ethyne for alkynes

Step 4: Review and Refine

Review your design and refine it to make sure it effectively communicates the properties and uses of unsaturated hydrocarbons. Check for spelling and grammar errors, and ensure that the information is accurate and easy to understand.

Step 5: Present Your Design

Present your design to your class or teacher, and explain the properties and uses of unsaturated hydrocarbons. You can also invite feedback and questions to enhance your understanding of the topic.

In conclusion, the properties and uses of unsaturated hydrocarbons are essential for many industries. Through this project, you will gain a better understanding of unsaturated hydrocarbons and develop your communication skills to effectively present your findings. Good luck!

Explanation:

Answer:

Explanation:

The three types of unsaturated hydrocarbons is alkynes, alkenes, and aromatic hydrocarbons. Which is composed of alkynes? acetylene. brainlist

Answer: 64 I think

Explanation:

unsure of wether or not there is a specific shape given but the original equation for volume is length x width x height so just multiply all..

4 x 4 = 16

16 x 4 = 64

The predicted phenotypic outcome of this cross will be that 75% of the offspring will have a round phenotype, while 25% will have a wrinkled phenotype.

To predict the phenotypic and genotypic outcome of a cross between two plants heterozygous for round peas, we need to first understand the genetics involved.

Round peas are dominant over wrinkled peas, which means that the genotype for round peas can be either homozygous dominant (RR) or heterozygous (Rr), while the genotype for wrinkled peas is homozygous recessive (rr).

When two plants heterozygous for round peas are crossed (Rr x Rr), there are three possible genotypic outcomes for their offspring: RR, Rr, or rr. However, because round peas are dominant, any offspring with at least one R allele (RR or Rr) will have a round phenotype.

Therefore, the predicted phenotypic outcome of this cross will be that 75% of the offspring will have a round phenotype, while 25% will have a wrinkled phenotype. The predicted genotypic outcome will be that 25% of the offspring will be homozygous dominant (RR), 50% will be heterozygous (Rr), and 25% will be homozygous recessive (rr).

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The pH of the resulting solution is 1.08 (rounded to two decimal places).

First, we need to calculate the amount of acid and base present:

moles of HCl = (0.10 mol/L) * (0.025 L) = 0.0025 mol \\moles of NaOH = (0.10 mol/L) * (0.005 L) = 0.0005 mol

Since HCl and NaOH react in a 1:1 ratio, all of the NaOH will be used up in the reaction and 0.0005 moles of HCl will be left unreacted.

So, total volume of the solution will be [tex]25.0 ml + 5.0 ml = 30.0 ml = 0.03 L[/tex]

The concentration of unreacted HCl will be:

C(HCl) = (0.0025 mol) / (0.03 L) = 0.0833 M

Now we can calculate the pH :  pH = -log[H+]

[H+] = 0.0833 M \\pH = -log(0.0833) = 1.08

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Answer:

pH = 1.18

Explanation:

First, calculate the moles of acid in the solution:

(0.0250 L )(0.10molL)=0.0025 mol acid

Next, calculate the moles of base:

(0.0050 L)(0.10molL)=0.00050 mol base

The strong acid and strong base will dissociate completely to generate the same number of moles of hydronium and hydroxide, respectively. The amount of acid exceeds the amount of base, so all the added hydroxide will neutralize an equivalent amount of hydronium. To find the remaining amount of hydronium, we subtract the moles of hydroxide added (equal to the moles of hydronium neutralized) from the moles of hydronium added:

0.0025 mol H3O+−0.00050 mol OH−=0.0020 mol H3O+

To find the concentration of hydronium, we must divide this number of moles by the total volume of solution, being sure to add the volumes of acid and base added together:

0.0020 mol H3O+0.0300 L≈0.06667 M H3O+

Finally, take the negative logarithm of this amount to obtain the pH.

-log(0.06667)=1.18

Since the hydronium concentration is only precise to two significant figures, the logarithm should be rounded to two decimal places.

The balanced molecular chemical equation for the reaction below is as follows;

H₂SO₄(aq) + 2CsOH(aq) → Cs₂SO₄(aq) + 2H₂O(l)

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

According to this question, a chemical equation occurs between sulfuric acid and caesium hydroxide to produce caesium sulphate and water.

The equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

The balanced chemical equation of the reaction is as illustrated above.

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An object in motion will continue to move at a constant velocity unless acted upon by an external force. This principle is known as Newton's First Law of Motion, also referred to as the law of inertia.

Inertia is the tendency of an object to resist changes in its state of motion.

Similarly, an object at rest will remain at rest unless acted upon by an external force. This means that if an object is not moving, it will continue to stay still until a force is applied to it.

Newton's First Law of Motion is a fundamental concept in physics that explains how objects behave when in motion or at rest. It is important to understand this law because it helps us to predict how objects will move and interact with each other.

Additionally, it is also essential in the design and engineering of machines and structures that require a thorough understanding of motion and force.

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The empirical formula for this compound is H1O1.

To find the empirical formula of a compound with 94.1% oxygen and 5.9% hydrogen, we first assume a 100g sample. This gives us 94.1g of oxygen and 5.9g of hydrogen. Next, we'll convert these values to moles:

Oxygen: 94.1g / 16g/mol (molar mass of O) ≈ 5.88 moles
Hydrogen: 5.9g / 1g/mol (molar mass of H) ≈ 5.9 moles

Now, we'll find the mole ratio by dividing both values by the smallest number of moles:

Oxygen: 5.88 / 5.88 ≈ 1
Hydrogen: 5.9 / 5.88 ≈ 1

The empirical formula for this compound is H1O1, which can be simplified to H2O (water).

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When a 7.15L balloon filled with gas is warmed from 256.1K to 297.1K, the volume of the gas inside the balloon increases to 8.27L.

The volume of the gas in the balloon can be calculated using the Ideal Gas Law, which states that the product of pressure, volume, and temperature is proportional to the number of molecules in the gas.

This law is expressed mathematically as PV = nRT, where P is the pressure of the gas, V is its volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature in Kelvin.

In this case, the pressure and number of molecules of the gas remain constant, so we can simplify the Ideal Gas Law to V1/T1 = V2/T2, where V1 is the initial volume of the gas, T1 is the initial temperature, V2 is the final volume of the gas, and T2 is the final temperature. Solving for V2, we get V2 = (V1 x T2) / T1.

Substituting the given values, we get V2 = (7.15L x 297.1K) / 256.1K = 8.27L. Therefore, the volume of the gas in the balloon after it is heated to 297.1K is 8.27L.

In conclusion, when a 7.15L balloon filled with gas is warmed from 256.1K to 297.1K, the volume of the gas inside the balloon increases to 8.27L.

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Coach Pollard used about 544 J of kinetic energy during his sprint.

Kinetic energy is the energy possessed by a moving object due to its motion. In this case, Coach Pollard's kinetic energy is directly proportional to his mass and the square of his velocity. As he runs faster or has more mass, his kinetic energy will increase accordingly. This is important to consider in athletics and sports where energy and power are key factors in performance.

The kinetic energy of Coach Pollard can be calculated using the formula KE = 1/2mv², where m is the mass of Coach Pollard and v is his velocity. Substituting the given values, we get KE = 1/2 × 68 kg × (4 m/s)² = 1/2 × 68 kg × 16 m²/s² = 544 J. As a result, Coach Pollard used approximately 544 J of kinetic energy throughout his sprint.

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The changes that occur in the parent nucleus during gamma decay are limited to the emission of a gamma ray and the associated decrease in energy. The mass and atomic number of the nucleus remain unchanged.

In gamma decay, the parent nucleus does not undergo any changes in terms of its mass or atomic number. Instead, the nucleus emits a gamma ray, which is a high-energy photon. This gamma ray is released as the nucleus transitions from an excited state to a lower energy state.

The emission of a gamma ray does not affect the number of protons or neutrons in the nucleus. This means that the atomic number and mass number of the nucleus remain the same before and after gamma decay.

However, the emission of a gamma ray does result in a decrease in the energy of the nucleus. This is because gamma rays have a very high frequency and carry a lot of energy. By releasing a gamma ray, the nucleus is able to shed some of this excess energy and move to a lower energy state.

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At 280 K and 1.50 atm, the mass of NaCl required to react with F₂ is 115.83 g; at STP, the mass of NaCl required to react with F₂ is 78.39 g.

Using the ideal gas equation, we will first determine the number of moles in F2:

Volume (V) = 15 L

Temperature (T) = 280 K

Pressure (P) = 1.5 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?  

                                F₂ + 2NaCl → Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

0.98 mole of F₂ will react with = 0.98 × 2

                                          = 1.96 moles of NaCl

Mole of NaCl = 1.96 moles

Molar mass of NaCl = 58.5 g/mol

Mass of NaCl =?

At standard temperature and pressure (STP),

22.4 L = 1 mole of F₂

15 L = 15 / 22.4

15 L = 0.67 mole of F₂

                            F₂ + 2NaCl → Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

0.67 mole of F₂ will react with = 0.67 × 2 = 1.34 moles of NaCl

Mole of NaCl = 1.34 moles

Molar mass of NaCl = 58.5 g/mol

Mass of NaCl =?

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When a 27. 7 g sample of ethylene glycol (C = 2. 42 J/gºC) at 42. 76°C is cooled to 32. 5°C the amount of heat released is  685.87 joule.

To calculate the heat released when a 27.7 g sample of ethylene glycol is cooled from 42.76°C to 32.5°C, you can use the formula:

q = mcΔT

where q represents the heat released, m is the mass (27.7 g), c is the specific heat capacity (2.42 J/gºC), and ΔT is the change in temperature (42.76°C - 32.5°C).

ΔT = 42.76°C - 32.5°C = 10.26°C

Now plug in the values into the formula:

q = (27.7 g) × (2.42 J/gºC) × (10.26°C) = 685.87 J

So, 685.87 Joules of heat are released when the 27.7 g sample of ethylene glycol is cooled from 42.76°C to 32.5°C.

Know more about Specific heat capacity here:

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