Answer:
297 J
Explanation:
The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of 1 g of a given substance by 1∘C.
In your case, aluminium is said to have a specific heat of 0.90Jg∘C.
So, what does that tell you?
In order to increase the temperature of 1 g of aluminium by 1∘C, you need to provide it with 0.90 J of heat.
But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by 1∘C. So if you wanted to increase the temperature of 10.0 g of aluminium by 1∘C, you'd have to provide it with
1 gram0.90 J+1 gram0.90 J+ ... +1 gram0.90 J10 times=10×0.90 J
However, you don't want to increase the temperature of the sample by 1∘C, you want to increase it by
ΔT=55∘C−22∘C=33∘C
This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that
1∘C10×0.90 J+1∘C10×0.90 J+ ... +
2). H2S and SO2 as follows,(8pt)
H2S + SO2 ------>S + H2O
In a particular experiment, 7.95 g of sulfur is produced by the reaction of 7.5 g of H2S with 12.75 g of SO2.
What is the % yield of sulfur?
Answer: 75.7 % yield
Explanation:
The balanced chemical equation is:
[tex]2H_2S+SO_2\rightarrow 3S+2H_2O[/tex]
According to stoichiometry :
68.2 g of [tex]H_2S[/tex] will require = 64 g of [tex]SO_2[/tex]
Thus 7.5 g of [tex]H_2S[/tex] will require = [tex]\frac{64}{68.2}\times 7.5=7.0g[/tex] of [tex]SO_2[/tex]
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 68.2 g of give = 96 g of
Thus 7.5 g of [tex]H_2S[/tex] give =[tex]\frac{96}{68.2}\times 7.5=10.5g[/tex] of [tex]S[/tex]
% yield=[tex]\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%[/tex]
Thus 75.7 % yield is there.
what is the total of the amount of energy that is reflected back into space
HELP!!!! ILL GIVE THE CROWN THINGY THING!!!!!!!!!! DUE SOON!!!!!!!!! PLS HELP!!!!!!!!!!
Why must many of the telescopes that detect invisible wave, such as infrared, microwaves, and gamma rays, be placed in space?
a Most radiation reaching Earth from space is blocked by the atmosphere. Therefore, some telescopes must be placed above the atmosphere.
b There are not enough places on land to build observatories that hold large telescopes.
c All telescopes must be placed in space. There are not telescopes on land.
d The waves in the electromagnetic spectrum are all too small to be detected by telescopes on land. Therefore, in order to see any EM radiation, telescopes must be placed in space.
Answer: A. Most radiation reaching Earth from space is blocked by the atmosphere. Therefore, some telescopes must be placed above the atmosphere.
Explanation: Astronomers have a huge problem detecting radiation from space because the Earth's atmosphere blocks most of it and stops it from reaching the surface.
Hope this helps :)
Usually potassium hydrogen phthalate is kept very pure. But Stu Dent thinks the bottle of potassium hydrogen phthalate has been accidently mixed with sodium chloride salt. He decides to use a titration to determine the amount of potassium hydrogen phthalate present. He weighs 2.3854 g of the contaminated potassium hydrogen phthalate mixture. The titration uses 17.47 mL of 0.5000 M sodium hydroxide. Use the titration volume and concentration to calculate the moles of potassium hydrogen phthalate actually reacted. Then use the molar mass (204.2 g/mol) to calculate the mass of potassium hydrogen phthalate actually reacted. Enter the mass to 4 significant digits with units of g.
Answer:
1.784 g
Explanation:
The equation of the reaction is;
NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)
Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M
Number of moles of NaOH reacted =8.735 * 10^-3 moles
From the reaction equation;
1 mole of NaOH reacted with 1 mole of KHC8H4O4
Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.
So,
Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g
Mikayla stands on a beach and sees a sailboat in the ocean. How could Mikayla determine whether the sailboat is moving?
A.
by determining the weight of the boat
B.
by examining the height of the ocean waves
C.
by comparing the wind speed at the beach to the number of ocean waves
D.
by using a reference point to measure the change in the boat’s position over time
Answer:
By using reference point (starting point) to measure the change in boat's position over time. Not 100% sure
Explanation:
Pls mark brainliest
The earth’s crust is subdivided into
A. Lithosphere, hydrosphere and atmosphere.
B. Troposphere, stratosphere and ionosphere.
C. Core, mantle and atmosphere.
D. Hydrosphere, geosphere and stratosphere.
Answer:
c. core, mantle and atmosphere
Answer:
Correct answer is letter A
Because Lithosphere includes the crust and the uppermost mantle.
How many kilograms of phosphorous are in a sample containing 1.00E31 phosphorous atoms?
Answer: [tex]5.15\times 10^5kg[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
[tex]\text{Number of moles}=\frac{1.00\times 10^{31}}{6.023\times 10^{23}}=0.166\times 10^{8}moles[/tex]
1 mole of phosphorous [tex]P[/tex] weighs = 31 g
Thus [tex]0.166\times 10^8[/tex] moles of phosphorous [tex]P[/tex] weigh=[tex]\frac{31}{1}\times 0.166\times 10^8=5.15\times 10^8g=5.15\times 10^5kg[/tex]
what is the molarity of a solution with 130g of CoCl2 in 1/2 liter? (can you show the steps please)
Answer:
2M
Explanation:
M=mol/L
1. Find moles of CoCl2
mass of substance/molar mass = 130/129.833 = 1.001 mol
3. Substitute in molarity equation
M=(1.001/0.5)
M= around 2M
The molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M
HOW TO CALCULATE MOLARITY:
The molarity of a solution can be calculated by dividing the number of moles of that substance by its volume:Molarity = no. of moles ÷ volumeFirst, we convert 130g of CoCl2 to moles as follows:Molar mass of CoCl2 = 129.84 g/molmoles = 130g ÷ 129.84g/molmoles of CoCl2 = 1molMolarity of CoCl2 solution = 1mol ÷ 0.5LMolarity of CoCl2 = 2MTherefore, the molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M.
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Plzz help
How many moles of H2O can be made from the complete reaction of 5.5 moles of C3H8? (Only enter the number, NO UNITS, and round to the tenth place, 1 decimal) Given: C3H8 + 5 O2 → 3 CO2. + 4 H2O
Answer:
22
Explanation:
5.5 mol C3H8 • (4 mol H2O / 1 mol C3H8 ) = 22 mol H2O
can't copy it so here
Answer:
First, third, and sixth
Explanation:
What season is represented in the northern hemisphere? *
5 points
Captionless Image
A. Spring
B. Summer
C. Fall
D. Winter
Answer:
B. summer
Explanation:
The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.
4. If you had.35 grams of chloric acid, how many molecules would you have?
Answer:
.4 moles
Explanation:
this is if it's 35 grams
Why doesn't all soil look and feel the same? List 3 reasons
Answer:
all soil are also different due to how they were form
what is the formula for tetrahydrogen monocarbide
Answer:
CH4
Explanation:
Tetra is the prefix for four. Hence the H4
Mono is the prefix for one, Hence the C
Methane (aka Tetrahydrogen monocarbide) written as CH4
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer:
a
Explanation:
Answer:
c
Explanation:
edge
Change in H for
CO2 -->C+02?
Answer:
−26.4 kcal
Explanation:
According to Hess's law, the total heat changes occuring during a chemical reaction are independent of path.
2CO(g)+O
2
(g)⟶2CO
2
(g)N ,
ΔH=−135.2 kcal
The above reaction is reversed and halved, we get-
CO
2
(g)⟶CO+
2
1
O
2
(g)
ΔH=
2
135.2
kcal ....(i)
C+O
2
(g)⟶CO
2
(g)
ΔH= -94 kcal ...(ii)
Required equation
C(s)+
2
1
O
2
(g)⟶CO(g);
Adding Eqs. (i) and (ii), we get
C(s)+
2
1
O
2
(g)⟶CO(g),
ΔH =
2
135.2
−94=−26.4 kcal
A beaker contains 5.78 ml of water what is the volume in gallons
Answer:
[tex]0.00153\ \text{gallons}[/tex]
Explanation:
[tex]1\ \text{milliliter}=0.000264172\ \text{gallons}[/tex]
The given volume of water is [tex]5.78\ \text{milliliters}[/tex]. So,
[tex]5.78\ \text{milliliters}=(5.78\times 0.000264172)\ \text{gallons}[/tex]
[tex]=0.00153\ \text{gallons}[/tex]
The volume of the given water in gallons is [tex]0.00153\ \text{gallons}[/tex].
NH3(g) + O2(g) + CH4(g) → HCN(aq) + H20(l)
Answer:
2 NH3(g) + 3 O2(g) + 2 CH4(g) = 2 HCN(aq) + 6 H2O(l)
Explanation:
Reaction stoichiometry Limiting reagent
Compound Coefficient Molar Mass Moles Weight
NH3(g) 2 17.03052
O2(g) 3 31.9988
CH4(g) 2 16.04246
HCN(aq) 2 27.02534
H2O(l) 6 18.01528
Instructions on balancing chemical equations:
Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below
Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide
To enter an electron into a chemical equation use {-} or e
To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.
Example: Fe{3+} + I{-} = Fe{2+} + I2
Substitute immutable groups in chemical compounds to avoid ambiguity.
For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,
but PhC2H5 + O2 = PhOH + CO2 + H2O will
Compound states [like (s) (aq) or (g)] are not required.
If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.
Reaction stoichiometry could be computed for a balanced equation. Enter either the number of moles or weight for one of the compounds to compute the rest.
Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents.
The given chemical equation is already balanced and does not require any further balancing.
The chemical equation NH₃(g) + O₂(g) + CH₄(g) → HCN(aq) + H₂O(l) is already balanced because the number of atoms of each element is the same on both sides of the equation.
On the left side of the equation, there is 1 nitrogen (N) atom in NH₃ and 1 nitrogen (N) atom in HCN.
On the right side of the equation, there are 3 hydrogen (H) atoms in NH₃, 2 hydrogen (H) atoms in HCN, and 2 hydrogen (H) atoms in H₂O.
There are 3 oxygen (O) atoms in O₂ on the left side of the equation and 1 oxygen (O) atom in H₂O on the right side of the equation.
Finally, there is 1 carbon (C) atom in CH₄ on the left side of the equation.
Since the number of atoms of each element is balanced on both sides of the equation, we can conclude that the given equation is already balanced and does not require any further adjustments or coefficients.
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The complete question is:
How can I balance NH₃(g) + O₂ (g) + CH₄ (g) -> HCN (aq) + H₂O (l)?
16. When a person looks up into the sky and
sees a full moon, what fraction of the
bright surface of the moon do we see?
Answer:we see 1 side because the other side is not visible
Explanation:
Water’s unique properties, high heat capacity, high density, solid phase less dense than liquid phase can be attributed to
A. The shape of the molecule
B. The polarity of the molecules and hydrogen bonding between molecules.
C. The covalent oxygen hydrogen bonds in the molecule.
D. It’s formula h2o.
Answer:
B- The polarity of the molecules and hydrogen bonding between molecules.
Explanation:
Hope this helps:)
How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7
Answer:
Hyba odpowiedzi c. Hyba
Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.
What is molar mass?The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:
[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]
Substituting the mass of each atom to identify the molar mass of ammonium chromate:
[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]
The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]
The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.
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what mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid
H2SO4 + N2 = 2NH3
Answer:
23.92 g
Explanation:
Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
I mole of H2SO4 = 2 moles of NaOH
24.5/82 = 24.5/82 × 2
= 0.598 moles of NaOH will neutralize
Mass= mole× molar mass
Molar mass of NaOH= 23+16+1 = 40g/mol
Mass= 0.598 × 40 = 23.92g of NaOH
Answer:
20g
Explanation:
First of all, you have got your formula wrong. It should be [tex]H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O[/tex].
Start by finding the Relative Formula Mass for sulfuric acid. [tex]H_{2}SO_{4}[/tex] is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing [tex]Mols=\frac{Mass}{Relative Formula Mass}[/tex]. So, [tex]\frac{24.5}{98} = 0.25[/tex], so the Mols of Sulfuric Acid is 0.25.
The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.
Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or [tex]NaOH[/tex]. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.
Which type of front is most likely moving through this area?
A. cold front
B. warm front
C. occluded front
D. stationary front
Answer:
Cold front
Explanation:
supposing on a hypothetical garden 43 identical trees contains a total of 19565 leaves. if each branch on a given tree consist of 35 leaves how many branches does each tree have?
Answer:
13 branches/tree
Explanation:
Step 1: Given data
Total number of trees (t): 43 treesTotal number of leaves (l): 19565 leavesNumber of leaves per branch (l/b): 35 leaves/branchStep 2: Calculate the total number of branches (b)
We will use the following expression.
b = l × b/l
b = 19565 leaves × 1 branch/35 leaves = 559 branch
Step 3: Calculate the number of branches per tree (b/t)
We will divide the total number of branches by the total number of trees.
559 branches/43 trees = 13 branches/tree
Which of the following components does a disc brake system use?
brake shoe
adjuster screw
wheel cylinder
caliper
The caliper is a component which is used by a disc brake system for performing its function.
What are the components of disc brake system?The disc braking system consist of components such as disc/rotor, a brake calliper and brake pads. When the brake pedal is pushed, brake fluid creates pressure that produces friction.
So we can conclude that the caliper is a component which is used by a disc brake system for performing its function.
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The amount of exposed surface area of the liquid affects how quickly
evaporation occurs.
O True
O False
Need help ASAP PLS SCIENCE
Answer:
3
m/s2
0.2
m/s2
Explanation:
if F=ma, then a = F/m. The unit to measure acceleration is typically m/s2.
Please help I will mark you brainiest
Answer:
Ethylene glycol is a syrupy liquid at room temperature whereas polyethylene glycol is a solid material. The main difference between ethylene glycol and polyethylene glycol is that ethylene glycol has a fixed value for molecular weight whereas polyethylene glycol has no fixed value for molecular weight.
why fermentation carried temperature in range of 30 to 40°C
Answer:
i dont kno
Explanation:
Explanation:
As temperature increases, fermentation rate accelerates. With increased fermentation rate, more aromatic compounds are produced because the metabolic intermediates are excreted from the yeast cells just like people getting sweaty and stinky during vigorous exercise.
For the reaction 2 Al + 3 H2SO4⟶ 3 H2 + H2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely with 53.7 g of aluminum, Al??
Answer:
292.4 g
Explanation:
2Al + 3H₂SO₄ → 3H₂ + Al₂(SO₄)₃First we convert 53.7 g of Al into moles, using its molar mass:
53.7 g ÷ 27 g/mol = 1.99 mol AlThen we convert Al moles into H₂SO₄ moles, using the stoichiometric coefficients:
1.99 mol Al * [tex]\frac{3molH_2SO_4}{2molAl}[/tex] = 2.98 mol H₂SO₄Finally we convert 2.98 moles of sulfuric acid into grams, using its molar mass:
2.98 mol H₂SO₄ * 98 g/mol = 292.4 g