Answer:
[tex]2.03~g~Ag_2S[/tex]
Explanation:
For this question we have to start with the reaction:
[tex]Ag~+~H_2S~+~O_2~->~Ag_2S~+~H_2O[/tex]
Now, we can balance the reaction, so:
[tex]4Ag~+~2H_2S~+~O_2~->~2Ag_2S~+~2H_2O[/tex]
With this in mind, we have to start with the amount of [tex]H_2S[/tex]. The first step is to convert from grams to moles. For this, we need to find the molar mass of [tex]H_2S[/tex]. If we check the periodic table we will find the atomic masses for Ag and H; H: 1 g/mol and A: 32 g/mol, so:
(1*2)+ (32*1) = 34 g/mol.
Now we can calculate the moles of [tex]H_2S[/tex]:
[tex]0.280~g~H_2S\frac{34~g~H_2S}{1~mol~H_2S}=0.0082~mol~H_2S[/tex]
With the moles of [tex]H_2S[/tex] we can calculate the moles of [tex]Ag_2S[/tex] if we check the molar ratio in the balanced equation, [tex]2~mol~H_2S=2~mol_Ag_2S[/tex], so:
[tex]0.0082~mol~H_2S\frac{2~mol_Ag_2S}{2~mol~H_2S}=0.0082~mol~H_2S[/tex]
With the molar mass of [tex]Ag_2S[/tex] we can convert from moles to grams (Ag: 107.86 g/mol, S: 32 g/mol), so:
(107.86*1)+(32*2)=247.80 g/mol
[tex]0.0082~mol~H_2S\frac{247.8~g~Ag_2S}{1~mol~H_2S}=2.03~g~Ag_2S[/tex]
I hope it helps!
How many Joules of energy are required to change 10.0 gram of ice at -2.0 C to water at 20.0 C?
(use your constants)
440 J
66,000 J
880
4220 J
The number of molecules in one mole of lithium acetate are...
Answer:
6.0221409e+23
Explanation:
The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.
a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm and it weighs 625 kg. Determine the density. Would it float in water? The density of water is 1 g/cm^3. Show your work.
Explanation:
It is given that,
Dimension of a solid block of substance is 74.0 cm by 55.0 cm by 29.0 cm
Mass of solid block is 625 kg or 625000 grams
We need to find the density of solution. The mass per unit its volume is called density.
[tex]\rho=\dfrac{m}{V}\\\\\rho=\dfrac{625000}{74\times 5\times 29}\\\\\rho=58.24\ g/cm^3[/tex]
So, the density of solid block is [tex]58.24\ g/cm^3[/tex]. The density of water is [tex]1\ g/cm^3[/tex]. The density of block is more than water. Hence, it will sink.
I NEED HELP PLEASE, THANKS!
Solids, liquids and gases are the three most commonly accepted phases of matter. Explain the properties of each phase, including their relative energy.
Answer:
Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.
Explanation:
Answer:
Liquids properties include retention of volume and its conformation to the shape of its container. The
particles in a liquid have more kinetic energy than the particles in the corresponding solid. Solids are
structurally rigid and resist changing shape or volume. Solid particles have the least amount of kinetic
energy. Properties of gas include easily compressible, the expand to fill their container and they occupy
more space than a solid or liquid. Gas particles have the most amount of kinetic energy
Explanation:
Which pathogen do you think responds faster to treatments provided by doctors? Explain your reasoning.
ANSWER: From experience and observation, the pathogen that responds more faster to treatments are PARASITES.
This is because, our body are already used to parasite, as they feed and mostly live inside our body. Parasites becomes harmful to our body, when it is allowed to be much in the body, thereby weakening the immune system of the body. Intake of vaccination reduces the number of parasites in the body, which gives the immune system the chance of recovering and protecting the body.
Parasite does not replicate more faster like viruses and other pathogens. These makes it more easier for treatment to work more faster. They are also easily killed by taking the proper treatment, and the rate of their replications are very slow when compared to the rate of their death when vaccinated.
Some example disease caused by parasites are:
1) Giardiasis
2) Trichomoniasis
3) Malaria
4) Toxoplasmosis
5) Intestinal worms
6) Pubic lice
All this disease above responds very fast to medical treatment, unless when they is complications, which are mostly when the parasite has been allowed to cause more harm and replicate much in the body, without any treatment. This is why doctors advice patients that lives at the tropical regions to periodically vaccinate themselves on parasitic infections.
Arrange the following compounds in order of increasing solubility in water and explain your sequence: C7H15OH, C6H13OH, C6H6, C2H5OH
Answer:
C6H6 < C7H15OH < C6H13OH < C2H5OH
Explanation:
Hello,
In this case, since the organic molecules solubility is defined in terms of the presence of hydrogen bonds as intermolecular forces, which are formed between oxygen and hydrogen and the length of the organic chain, we can notice that hydroxyl-containing longer chains tend to be less water soluble whereas shorter chains more soluble as the polar part of the chain will lead the solubility. In addition to it, chains with lack of oxygen tend to be highly water insoluble. Therefore, we can notice that C6H6 is the least water soluble, next C7H15OH, then C6H13OH and the most soluble is C2H5OH.
Best regards.
How many K atoms are there in 5K2CO3?
Select one:
15
10
6
2
Answer:
10
Explanation:
The 5 will multiply the subscript 2 on the K atoms making it 10
2) A sample of 113min has a half-life of 100. minutes. What amount of 113m In remains (in CPM) if a
10,000 CPM sample is allowed to decay for 5.0 hours?
Answer:
THE AMOUNT OF THE SAMPLE REMAINING AFTER 5 HOURS IS 1250 CPM
Explanation:
A sample has a half life of 100 minutes. To solve for the amount remaining after a given amount of 10000CPM decay in 5 hours, we use the formula:
Nt = No * (1/2)^t/t1/2
Where:
Nt = amount remaining = unknown
No = initial amount = 10000 CPM
t = time elapsed for decay = 5 hours = 60*5minutes = 300 minutes
t1/2 = half life = 100 minutes
Putting the values into the formula, we have:
Nt = 10000 * (1/2)^ 300/100
Nt = 10000 * (1/2)^3
Nt = 10000 * 0.125
Nt = 1250 CPM
The amount of the sample remaining after 5 hours is 1250 CPM.
2 upper N upper o upper c l double-headed arrow 2 upper N upper O (g) plus upper C l subscript 2 (g).
At equilibrium, the concentrations are as follows.
[NOCl] = 1.4 ´ 10–2 M
[NO] = 1.2 ´ 10–3 M
[Cl2] = 2.2 ´ 10–3 M
Answer: The equilibrium constant for the reaction is 0.000016.
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients.
The given balanced equilibrium reaction is,
[tex]2NOCl(g)\rightleftharpoons 2NO(g)+Cl_2(g)[/tex]
The expression for equilibrium constant for this reaction will be,
[tex]K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}[/tex]
Now put all the given values in this expression, we get :
[tex]K_c=\frac{(1.2\times 10^{-3})^2\times (2.2\times 10^{-3})}{(1.4\times 10^{-2})^2}[/tex]
[tex]K_c=0.000016[/tex]
Thus the equilibrium constant for the reaction is 0.000016.
Karla added green pellets to a container of water before she began watering her lawn. What correctly describes
the solvent in her solution.
The green pellets are the solvent because it is dissolved in water.
The water is the solvent because it is dissolved in the green pellets.
The water is the solvent because the green pellets dissolved in it.
The green pellets are the solvent because it dissolved the water.
The correct answer is C. The water is the solvent because the green pellets dissolved in it.
Explanation:
In solutions, the are two substances involved, the solvent and the solute. The solvent is usually a liquid substance; additionally, the solvent dissolves another substance, which is known as the solute. For example, if you dissolve a spoon of salt in a glass of water, the solute is the salt which is the substance dissolved and the solvent is the water because the solute is dissolved in it. According to this, in the case presented the water is the solvent because the green pellets which are the solute dissolve in it.
In the covalent compound C3H8 the Greek prefix used to represent the cation is?
Answer:the answer is DI
Explanation:APΣX
How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl
2
start text, C, l, end text, start subscript, 2, end subscript?
Answer:
18.7887 g of NaCl
Explanation:
The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?
Let us start by writing out the balanced equation of the reaction:
Na + Cl2 ---> NaCl2
1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.
mole = mass/molar mass
Therefore
18 g of Na = 18/23 = 0.7826 mole
23 g of Cl2 = 23/71 = 0.3239 mole
In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence
0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.
mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g
Hence, 18.7887 grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.
The correct value according to Ruler A is 2.2cm, whereas the correct value according to Ruler B is 2.27 cm.Perform the mathematical operations indicated by the title of each bin using these two values. Round the correct answers to the appropriate number of significant figures or decimal places. Compare the rounded correct answers with the values given and drag the rounded correct answers to the bin that represents the mathematical operation performed. There are also answers that are not rounded to the correct number of significant figures or decimal places. Drag these answers to the bin named �Incorrect rounding.�For example, multiply the number 2.2 by 2.27. Round the answer to the appropriate number of significant figures. Drag the correctly rounded answer to the bin labeled "2.2 x 2.27"Drag the incorrect answers from the multiplication operation to the bin named "Incorrect rounding."Drag the appropriate items to their respective bins.Item: 5.0 cm^2, 4.994 cm^2, 4.5cm, 0.0cm, 4.47cm, 0.07cm, 0.1cm, 1.0, 1, 1, 10.3, 4.99cm^21. 2.27x2.2 =?2. 2.27/2.2 =?3. 2.27 +2.2 = ?4. 2.27-2.2 = ?5. Incorrect rounding?
Answer:
1) 5.0 cm² ( to two significant figures or one decimal place)
2) 1.0 (to two significant figures or to one decimal place)
3) 4.5 cm ( to two significant figures or one decimal place)
4) 0.1 cm ( to two significant figures or one decimal place)
5) The remaining answers due to incorrect rounding are 4.994 cm², 0.0 cm, 4.47 cm, 0.07 cm, 1, 1.03 cm, 4.99 cm²
Explanation:
The answers given are rounded to two significant figures or one decimal places:
1) 2.27*2.2 = 5.0 cm² ( to one decimal place)
2) 2.27/2.2= 1.0 ( to one decimal place)
3) 2.27+2.2 = 4.5 cm ( to one decimal place)
4) 2.27-2.2 = 0.1 cm ( to one decimal place)
5) The remaining answers due to incorrect rounding are 4.994 cm², 0.0 cm, 4.47 cm, 0.07 cm, 1, 1.03 cm, 4.99 cm²
u make 1.000 L of an aqueous solution that contains 35.0 g of sucrose (C12H22O11).Part AWhat is the molarity of sucrose in this solution?Express your answer to three significant figures.M
Answer:
0.102 M
Explanation:
Given data
Mass of sucrose (solute): 35.0 gVolume of solution: 1.000 LStep 1: Calculate the moles of solute
The molar mass of sucrose is 342.3 g/mol. The moles corresponding to 35.0 g of sucrose are:
[tex]35.0g \times \frac{1mol}{342.3g} =0.102mol[/tex]
Step 2: Calculate the molarity of sucrose in the solution
The molarity is equal to the moles of solute divided by the liters of solution.
[tex]M=\frac{0.102mol}{1.000L} =0.102 M[/tex]
A mountain has a height of 2.74 miles. How high is the mountain in meters? Use the fact that 1 mi=1.609 km .
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a
Answer:
Explanation:
Select the statements that correctly describe a buffer. a) An acid added to the buffer solution reacts with the weak base of the buffer. b) The pH of a buffer solution is determined by the ratio of the concentration of conjugate base to the concentration of strong acid. c) A buffer is generally made up of a weak acid and its conjugate base. d) The pH of a buffer solution does not change significantly when any amount of a strong acid is added. e) The Ka of a buffer does not change when any amount of an acid is added to the buffer solution.
Answer:
(B.) The pH of a buffer solution is determined by the ratio of the concentration of conjugate base to the concentration of strong acid.(C.) A buffer is generally made up of a weak acid and its conjugate base. (D.) The pH of a buffer solution does not change significantly when any amount of a strong acid is added.Explanation:
A buffer is solution which resists change in pH upon addition of either acids or bases.
The pH of a buffer is calculated by the ratio of the concentration of base to concentration of acid. The weak acid and conjugate base have a Ka similar to the pH desired.
Statements that are correctly describe a buffer are buffer is generally made up of a weak acid and its conjugate base, pH and Ka of a buffer solution does not change significantly.
What is buffer solution?Buffer solution is a mixture of a weak acid and its conjugate base or weak base with its conjugate acid.
Buffer solutions resists the value of pH of the solution whenever small quantity of strong acid or strong base is added on it. pH of the buffer solution will be calculated by using the Henderson Hasselbalch equation as follow:
For weak acids-
pH = pka + log [conjugate base]/[weak acid]
For weak base-
pH = pka + log [conjugate acid]/[weak base]
Ka is the acid dissociation constant which is not changes too much for the buffer solution.
Hence options (C), (D) and (E) are correct.
To know more about buffer solution, visit the below link:
https://brainly.com/question/22390063
Solution A is a 1.00 L buffer solution that is 1.188 M in acetic acid and 1.188 M in sodium acetate. Acetic acid has a pKa of 4.74. What is the pH change of this solution upon addition of 0.1 mol of HCl? Enter your answer numerically to four decimal places. It will be a negative number.
Answer:
pH change is -0.07
Explanation:
Using H-H equation for acetic acid:
pH = pKa + log [Acetate salt] / [Acetic acid]
Replacing:
pH = 4.74 + log[1.188M] / [1.188M]
pH = 4.74
The HCl reacts with sodium acetate producing acetic acid, thus:
HCl + CH₃COONa → CH₃COOH + NaCl
That means the final moles of sodium acetate are initial moles - moles of HCl and moles of acetic acid are initial moles + moles of HCl.
As the volume of the buffer is 1.0L, initial moles of both substances are 1.188moles. After reaction, the moles are:
sodium acetate: 1.188mol - 0.1mol = 1.088mol
Acetic acid: 1.188mol + 0.1mol = 1.288mol
Using again H-H equation:
pH = 4.74 + log[1.088M] / [1.288M]
pH = 4.67
pH change is: 4.67 - 4.74 = -0.07
Rank the following substances in order from most soluble in water to least soluble in water: methane, CH4; 2-butanol, C4H9OH; potassium chloride, KCl; and propane, C3H8. Rank from most to least soluble in water. To rank items as equivalent, overlap them.
Answer:
Arranged in order of most soluble to least soluble in water:
[tex]KCl > CH_{4} > C_{4} H_{9} OH > C_{3}H_{8}[/tex]
Explanation:
Water is a polar solvent due to the electric charge it possesses. Hence it would only dissolve polar molecules.
Non-polar molecules would be dissolved by non-polar solvents.
Short chain alcohols are more soluble than butanol, but generally the polar -OH group is soluble in water.
It has two substances, muriatic acid and sodium hydroxide. Which of the two substances would you use to unclog the pipes? Please argue your answer.
Answer:
Sodium hydroxide
Out of the two substances, sodium hydroxide would you use to unclog the pipes.
What is the use of sodium hydroxide?Sodium hydroxide is used to produce soaps, rayon, paper, products that explode, dyes, and petroleum products.
The presence of sodium hydroxide in a cleanser or in a homemade aqueous solution converts these pesky fats into soaps and the soap is then easily removed by water.
Hence, out of the two substances, sodium hydroxide would you use to unclog the pipes.
Learn more about sodium hydroxide here:
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The number of moles of O2 in 10.6 grams of Na2CO3:
A. 0.1 moles
B. 0.3 moles
C. 0.2 moles
D. None of these
Explain please
15.00 mL of 0.425 M H2SO4 solution is required to completely react with (neutralize) 23.9 mL
of KOH solution.
What is the
molarity of the KOH solution?
2 KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2 H20 (1)
Answer:
0.533 M KOH
Explanation:
2 KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2 H20 (l}
from reaction 2 mol 1 mol
x 15*10^(-3)*0.425 mol
15.00 mL = 15*10^(-3)L H2SO4 solution
15*10^(-3)L*0.425 mol/L = 15*10^(-3)*0.425 mol H2SO4
x =2*15*10^(-3)*0.425/1 = 2*15*10^(-3)*0.425 mol KOH
23.9mL = 23.9 *10^(-3) L KOH
M(KOH) - molarity KOH
M(KOH)*V(KOH solution) = M(KOH)*23.9 *10^(-3) L KOH - is moles KOH
2*15*10^(-3)*0.425 mol H2SO4 = M(KOH)*23.9 *10^(-3) L KOH
M(KOH) = 2*15*10^(-3)*0.425 /(23.9 *10^(-3)) = 0.533 M
How can you use a red cabbage solution to determine the ph of a solution
Answer:
(PH color chart at the bottom)
Chop the cabbage into small pieces until you have about 2 cups of chopped cabbage. Place the cabbage in a large beaker or other glass container and add boiling water to cover the cabbage. Allow at least 10 minutes for the color to leach out of the cabbage. Alternatively, you can place about 2 cups of cabbage in a blender, cover it with boiling water, and blend it.
Filter out the plant material to obtain a red-purple-bluish colored liquid. This liquid is at about pH 7. The exact color you get depends on the pH of the water.
Pour about 50–100 mL of your red cabbage indicator into each 250 mL beaker.
Add various household solutions to your indicator until it changes color. Use separate containers for each household solution—you don't want to mix chemicals that don't go well together.
2=Red
4=Purple
6=Violet
8=Blue
10=Blue Green
12 = Green Yellow
4) list 3 protest rights you have that are protected under the law. How can you protect these rights? George Floyd’s ?
Help me please urgent
Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
Answer: D=8.27 g/cm³
Explanation:
Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.
[tex]D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}[/tex]
With this equation, the m³ and kg cancel out, and we are left with g/cm³.
D=8.27 g/cm³
Hydrobromic acid solution of unknown concentration is titrated with a 0.500M LiOH solution.
20.00mL of the acid are poured into an Erlenmeyer flask.
40.00mL of the base solution is required to reach the equivalence point.
What is the molarity of the Hydrobromic acid solution?
Answer:
1.00 M
Explanation:
Step 1: Write the balanced equation
HBr + LiOH ⇒ LiBr + H₂O
Step 2: Calculate the reacting moles of lithium hydroxide
40.00 mL of 0.500 M solution react. The reacting moles of LiOH are:
[tex]40.00 \times 10^{-3} L \times \frac{0.500mol}{L} = 0.0200 mol[/tex]
Step 3: Calculate the reacting moles of hydrobromic acid
The molar ratio of HBr to LiOH is 1:1. The reacting moles of hydrobromic acid are 1/1 × 0.0200 mol = 0.0200 mol.
Step 4: Calculate the molarity of hydrobromic acid
0.0200 moles of HBr are in 20.00 mL of the solution. The molarity of the hydrobromic acid solution is:
[tex]M= \frac{0.0200 mol}{20.00 \times 10^{-3} L } =1.00 M[/tex]
Is water the most common acid?
Answer: Yes
Explanation: Since strong acids react with and use up water molecules, and strong bases do not
What element is missing in the following nuclear equation? bismuth radon lead polonium
Answer:
Lead
Explanation:
Lead (Pb) has atomic number 82
Ex Polonium (Po) has atomic number 84 and mass number 212
Answer:
lead
Explanation:
(a) Show that the pressure exerted by a fluid P (in pascals) is given by P = hdg, where h is the column of the fluid in metres, d is the density in kg/m-3, and g is the acceleration due to gravity (9.81 m/s2). (Hint: See Appendix 2.). (b) The volume of an air bubble that starts at the bottom of a lake at 5.24C increases by a factor of 6 as it rises to the surface of water where the temperature is 18.73C and the air pressure is 0.973 atm. The density of the lake water is 1.02 g/cm3. Use the equation in (a) to determine the depth of the lake in metres.
Answer:
B) THE DEPTH OF THE LAKE IS 0.060 m
Explanation:
b) Determine the depth of the lake in metres
1. Using the general gas law, we will calculate the initial pressure of the air bubbles.
P1V1 /T1 = P2V2/T2
P1 = Unknown
T1 = 5.24 °C
T2 = 18.73 °C
P2 = 0.973 atm
V1 = V1
V2 = 6V1
P1 = P2 V2 T1 / V1 T2
P1 = 0.973 * 6V1 * 5.24 / V1 * 18.73
P1 = 5.09852 * 6 / 18.73
P1 = 30.59112 / 18.73
P1 = 1.633 atm.
2. Calculate the depth of the lake:
Pressure = length * density * acceleration
length = Pressure / density * acceleration
Pressure = 1.633 atm = 1.633 * 101, 325 Nm^2 = 165, 463.725 Nm^2
Density = 1.02 g/cm3 = 1.02 * 10^3 kg/m^3
Acceleration = 9.8 m/s^2
So therefore, the length in metres is:
Length = density * acceleration / pressure
Length = 1.02 *10^3 * 9.8 / 165, 463.725
Length = 9.996 * 10^3 / 165 463.725
Length = 0.06 m
Hence, the depth of the lake is 0.06 m
What is the chemical formula for the compound formed between sodium and sulfur?
Answer:
The formula for sodium sulfide is Na2S.
Answer:
NA2S
Explanation:
the compound formed was sodium sulphide
therefore the chemical formula is NA2S
The pyruvate dehydrogenase complex is subject to allosteric control, especially inhibition by reaction products. From the list below, select the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes.
a. AMP binding to and activating the enzyme.
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
c. Exchange of ADP and ATP on the pyruvate dehydrogenase complex.
d. Phosphorylation by a kinase using ATP (which turns the complex on) and dephosphorylation by a phosphatase (which tums the complex off).
Answer:
The correct option is B
b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).
Explanation:
The pyruvate dehydrogenase complex is described as a complex having many enzymes that catalyse decarboxylation of pyruvate by oxidation to yield NADH and acetyl‐CoA, which makes the influx of acetyl-coA from glycolysis to increase into the Krebs cycle.
It can be found in the mitochondrial matrix and pyruvate which is conveyed through enzyme Pyruvate Translocase to PDH complex.
Regulation of pyruvate dehydrogenase complex occured through allosteric effectors as well as phosphorylation.the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes such as plants and animals Phosphorylation is by a kinase using ATP which first turns the complex off and the later dephosphorylation by a phosphatase which turns the complex on
