Answer:
use proxies, if you cant, then you cant unblock anything thats already blocked
Explanation:
You can't unblock anything on a school chromebook. So it's best to find website alternatives, things your school might use, like Giggl. It's a website with a built in web browser you can do almost anything, watch videos you can't on your school chromebook, netflix, hulu, vumoo, and even nasty sites... just don't go on those though. You can't play a lot of games and some sites are blocked as well. If you want people to send you videos that you can watch in a separate browser, i suggest using pad let. It is a app to post things like pictures or status' but people like me and my friends use it to talk to each other, you can send gifs, voice recordings, and take pictures. I hope this helps you.
Again, consider what you believe to be the goal of performing a penetration test. Why would you worry about doing any privilege escalation or leaving backdoors? What circumstances would cause you to do either of those things? Do you consider this to be practical or theoretical knowledge in light of your beliefs about penetration testing?
Answer:
Penetration monitoring is conducted based on the vulnerability evaluation (Were a susceptibility evaluated and mentioned).
Explanation:
Penetration Test
Penetration testing is carried out from both within (the network or application) as well as outside that aims to gain access to the system to evaluate if any suspicious activity or improper behavior is likely within the device. When there are some other potential security vulnerabilities, they are all found in the integration check that involves vulnerability assessment for frameworks and checking for network management. Automation of penetration testing is used to make it work better. Penetration monitoring deals with the same risk evaluation correlated with a disadvantage.Privilege escalation
They need to think about known vulnerabilities as the system for network management works conditional on the privilege rates. Such that, increasing user has an article has highlighted and the consumer is only allowed to control or use the resources that should be used appropriately, depending on the level of privilege. If he gets elevated access then it will be a failure to have access control mechanism.Leaving backdoors
The creator uses backdoors to test the system's functionality during the designing processes. The loophole can be a workaround overriding the identification for all users, or a default password. They would need to worry about leaving the backdoor because the backdoor.which is performed either deliberately or involuntarily will circumvent the entire security mechanism. During the intrusion testing process, the both privilege increase and the escape from the gateway can be discovered due to the research being done both inside and outside the device. The tester's testing phase acts as various users so that any destabilization of access may be found. The tester will use all numerous methods to supersede the technique of official approval, but when there are certain backdoors, maybe he can start by pointing that out.Which statement most aptly defines the term networking?
Answer: We need more info.
Explanation:
Which are strategies for communicating solutions that include flowcharts? Choose all that apply.
breaking the solution into steps
diagramming the solution
modeling the solution
writing the algorithm
Answer:
The answer is C
Explanation:
Answer:
B and C
Explanation:
Which of the following sorting algorithms could be implemented on a doubly-linked list WITHOUT making the asymptotic worst-case complexity even worse? You must perform the sorting in-place, you CANNOT just copy to an array and then use the normal algorithm
I. Bubble sort
Il. Selection sort
IlI. Insertion sort
IV. Quicksort
V. Heapsort
A. I, II, and IlIl only
B. IV and V only
C. I and II only
D. Iand Il only
E. All except V
Answer:
C. I and II only
Explanation:
Doubly-linked list is used for sorting algorithms. To sort doubly-linked lists first sort the nodes current and nodes index then compare the data of current and index node. Bubble sort and Selection sort can be used for algorithm sorting without asymptotic complexity. Bubble sort can be created when adjacent nodes are in ascending order.
Click/press _______ to remove the most recently typed text.
Answer:
ctrl Z
Explanation:
ctrl Z is the shortcut for undo it will reverse the last thing you did ctrl Y is redo if i accidently did ctrl Z i can do ctrl Y. Hope this helps!
For this assignment, you will be writing a Deque ADT (i.e., LastnameDeque). A deque is closely related to a queue - the name deque stands for "double-ended queue." The dierence between the two is that with a deque, you can insert, remove, or view, from either end of the structure. Attached to this assignment are the two source les to get you started:
Answer:
Explanation:
The objective here is write a Deque ADT code by using Deque.java - the Deque interface; (i.e the specification we must implement) and BaseDeque.java which is the driver for Deque testing.
For the computation of the code and its output I have written them in a word document due its long array which is much more than the 5000 character this answer box can accommodate.
SEE THE ATTACHED FILE BELOW.
Write down the result of each expression in the output column and specify the datatype of the result.Datatype should follow the Java Standards. If the output is a String, surround it with " ";if the output is char surround it with ‘ ’. Floats should have an ‘f’ or ‘F’ at the end, longs should have an ‘L’ or ‘l’ at the end (generally avoid using lowercase ‘l’ because it can be confusing).
Answer:
Kindly check the explanation section.
Explanation:
Below are the expression given in the question and the corresponding output and Datatype.
(1). Expression = 7/2 + 9.2/2.
Output = 7.6, Datatype = double
(2). Expression = 3.4 + 2 5 f.
Output = 5.9, Datatype = double.
(3). Expression = "whale" . Substring (2,5).
Output = "ale" , Datatype = string.
(4). Expression= (int) 9.2 + 6.0 f.
Output = 15.0 f, Datatype = float.
(5). Expression = (2 <= 1) && (5! = 2) || (8 + 5!= 13).
Output = false, Datatype = boolean
(6) Expression =1.5 f == 1.5?.
Output: “false” , Datatype : “true ”
Output = “false”,
Datatype= String.
(7). Expression = “joey”.charAtt(4).
Output = error, Datatype = error“.
(8). Expression = madmax”.
indexOf(“a”) + 7.
Output: 8 , Datatype = int.
(9). Expression = 2 + 3 + “catdog” + 1 + 2.
Output = “5catdog12”, Datatype = String.
(10). Expression = String.format(“%3.3f”,7.89672).
output = “7.897”, datatype = String.
(11). Expression = “captain”.indexOf(“a”, 2).
Output = 4, datatype = int.
(12). true ? ++3: 3++.
Output = error, dataty = error.
(13). Expression = new String[]{“tony”,“josh”}[0].
Output = “tony”, Datatype = String.
(14). Expression = “patrick”.substring(2) +“lucky”.substring(4).
Output = “tricky”, Datatype = String.
(15). Expression = “popFizz”.indexOf(“o”) + 2.4+ 6L.
Output9.4, Datatype = double.
(16). Expression = “pizza”.indexOf(“z”).
Output = 2, Datatype = int.
Given class Triangle (in file Triangle.java), complete main() to read and set the base and height of triangle1 and of triangle2, determine which triangle's area is larger, and output that triangle's info, making use of Triangle's relevant methods. Ex: If the input is: 3.0 4.0 4.0 5.0 where 3.0 is triangle1's base, 4.0 is triangle1's height, 4.0 is triangle2's base, and 5.0 is triangle2's height, the output is: Triangle with larger area: Base: 4.00 Height: 5.00 Area: 10.00
Answer:
The Triangle.java file is not provided; However, the program is as follows;
Comments are used for explanatory purpose
Also see attachment for Triangle.java program file
import java.util.*;
public class triangle
{
public static void main(String [] args)
{
Scanner input = new Scanner(System.in);
//Declare variables
double base1, height1, base2, height2;
//Prompt user for inputs
System.out.println("Provide values for the base and height of the two triangles");
System.out.print("Base of Triangle 1: ");
base1 = input.nextDouble();
System.out.print("Height of Triangle 1: ");
height1 = input.nextDouble();
System.out.print("Base of Triangle 2: ");
base2 = input.nextDouble();
System.out.print("Height of Triangle 2: ");
height2 = input.nextDouble();
//Compare and Print Results
if(0.5 *base1 * height1 > 0.5 * base2 * height2)
{
System.out.print("Triangle with larger area: Base: "+base1+" Height: "+height1+" Area: "+(0.5 * base1 * height1));
}
else
{
System.out.print("Triangle with larger area: Base: "+base2+" Height: "+height2+" Area: "+(0.5 * base2 * height2));
}
}
}
3. (20 points) Write a C++ recursive function that finds the maximum value in an array (or vector) of integers without using any loops. (a) Test your function using different input arrays. Include the code. i. ii. (b) Write a recurrence relation that represents your algorithm. i. T(n) = T(n-1) + O(1) (c) Solve the recurrence relation and obtain the running time of the algorithm in Big-O notation.
Answer:
Following are the code to this question:
In option (i):
#include <iostream>//defining header file
using namespace std;
int findMax(int B[], int x)//defining recursive method findMax
{
if (x == 1)//defining condition when value of n==1
return B[0];//return array first element
return max(B[x-1], findMax(B, x-1)); // calling recursive method inside max method and return value
}
int main() //defining main method
{
int B[] = {12, 24, 55, 60, 50, 30, 29};//defining array B
int x= 7;//defining integer variable and assign a value
cout << "Maximum element value of the array is: "<<findMax(B, x)<<endl;//calling method findMax and print value
return 0;
}
Output:
Maximum element value of the array is: 60
In option (ii):
[tex]\Rightarrow \ T(n) = 1 + T(n-1)\\\Rightarrow 1 + 1 + T(n-2)\\ \Rightarrow 1 + 1 + 1 + ... n \ times \\\Rightarrow O(n) \\[/tex]
Explanation:
In the above-given program a recursive method "findMax" is defined, which accepts an array "B" and an integer variable "n" in its parameter, inside the method a conditional statement is used that, checks value of x equal to 1.
If the above condition is true it will return the first element of the array and find the max number. Inside the main method, an array B is declared that assigns some values and an integer variable is declared, that also assigns some values, in the last step print method is used that pass value in method and prints its return value. In the option (ii) we calculate the Big-O notation algorithm value.digital crate to miss meat
Im sorry, this makes no sense. i think it is supposed to be an analogy, but i would need more info or background about the question
Answer:
Wait......What is the question or why did u put that??? I am so confused rn. lol
Explanation:
Using a C# program write a program that accepts any number of homework scores ranging in value from 0 through
10. Prompt the user for a new score if they enter a value outside of the specified range. Prompt
the user for a new value if they enter an alphabetic character. Store the values in an array.
Calculate the average excluding the lowest and highest scores. Display the average as well as the
highest and lowest scores that were discarded.
Answer:
The program is written using C# Console
Comments are used for explanatory purpose
Program starts here
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
int num;
Console.WriteLine("Enter digit: [0-10]");
while (!int.TryParse(Console.ReadLine(), out num) || num<0||num>10)
{
Console.WriteLine("That was invalid. Enter a valid digit.");
}
//Declare scores
int[] scores = new int[num];
//Accept Input
for(int i =0;i<num;i++)
{
Console.WriteLine("Enter Test Score "+(i+1));
while (!int.TryParse(Console.ReadLine(), out scores[i]))
{
Console.WriteLine("That was invalid. Enter a valid digit.");
Console.WriteLine("Enter Test Score " + (i + 1));
}
}
//Determine highest
int max = scores[0];
for (int i = 1; i < num; i++)
{
if (scores[i] > max)
{
max = scores[i];
}
}
//Determine Lowest
int least = scores[0];
for (int i = 1; i < num; i++)
{
if (scores[i] < least)
{
least = scores[i];
}
}
int sum = 0;
//Calculate total
for(int i =0; i< num;i++)
{
sum += scores[i];
}
//Subtract highest and least values
sum = sum - least - max;
//Calculate average
double average = sum / (num - 2);
//Print Average
Console.WriteLine("Average = "+average);
//Print Highest
Console.WriteLine("Highest = " + max);
//Print Lowest
Console.WriteLine("Lowest = " + least);
Console.ReadLine();
}
}
}
See Attachment for program source file in txt
Cyclic Redundancy Check (CRC) is an effective error detection mechanism. Suppose you have data bits of 10010011011 and divisor is 10011. As per the given information, what is encoding bits at the sender side? Similarly, at the receiver end ensure syndrome value is zero. Follow all necessary steps to complete calculation at both ends.
Answer:
I've asked the same question bro..if you get answer share with me too
Explanation:
Perform algorithm time measurement for all three quadratic sorting algorithms for Best Case (already sorted), Average Case (randomly generated), and Worst Case (inverse sorted) inputs and compare them with O(N*logN) sorting algorithm using Arrays.sort() method. Use arrays sizes of 50K, 100K, and 200K to produce timing results.
Answer:
Experiment size : 50,000
==================================
Selection sort :
---------------------------------------------------------
Worst case : 0.162
Average case : 0.116
Best case : 0.080
Insertion sort :
---------------------------------------------------------
Worst case : 0.162
Average case : 0.116
Best case : 0.080
Bubble sort:
--------------------------------------------------------
Worst case : 0.211
Average case : 0.154
Best case : 0.117
Experiment size : 100,000
==================================
Selection sort :
---------------------------------------------------------
Worst case : 0.316
Average case : 0.317
Best case : 0.316
Insertion sort :
---------------------------------------------------------
Worst case : 0.316
Average case : 0.317
Best case : 0.316
Bubble sort:
--------------------------------------------------------
Worst case : 0.482
Average case: 0.487
Best case : 0.480.
Experiment size : 200,000
==================================
Selection sort :
---------------------------------------------------------
Worst case : 1.254
Average case : 1.246
Best case : 1.259
Insertion sort :
---------------------------------------------------------
Worst case : 1.254
Average case : 1.246
Best case : 1.259
Bubble sort:
--------------------------------------------------------
Worst case : 1.990
Average case : 2.009.
Best case : 1.950
Explanation:
[NB: since it is very long there is the need for me to put it it a document form. Kindly check the doc. Files. The file A is the sort Analysis.Java file and the file B is the sort.Java file].
The concept of algorithm time measurement strictly depends on the following;
=> The measurement of time, space or energy on different sizes.
=> Plotting of the measurements and characterizing them.
=> Running or implementation of the algorithm.
Programming language such as Java can be used in accessing the operating system clock and Java had two static methods.
KINDLY CHECK BELOW FOR THE ATTACHMENT.
Using the "split" string method from the preceding lesson, complete the get_word function to return the {n}th word from a passed sentence. For example, get_word("This is a lesson about lists", 4) should return "lesson", which is the 4th word in this sentence. Hint: remember that list indexes start at 0, not 1.
def get_word(sentence, n):
# Only proceed if n is positive
if n > 0:
words = ___
# Only proceed if n is not more than the number of words
if n <= len(words):
return(___)
return("")
print(get_word("This is a lesson about lists", 4)) # Should print: lesson
print(get_word("This is a lesson about lists", -4)) # Nothing
print(get_word("Now we are cooking!", 1)) # Should print: Now
print(get_word("Now we are cooking!", 5)) # Nothing
Answer:
def get_word(sentence, n):
# Only proceed if n is positive
if n > 0:
words = sentence.split()
# Only proceed if n is not more than the number of words
if n <= len(words):
return words[n-1]
return (" ")
print(get_word("This is a lesson about lists", 4)) # Should print: lesson
print(get_word("This is a lesson about lists", -4)) # Nothing
print(get_word("Now we are cooking!", 1)) # Should print: Now
print(get_word("Now we are cooking!", 5)) # Nothing
Explanation:
Added parts are highlighted.
If n is greater than 0, split the given sentence using split method and set it to the words.
If n is not more than the number of words, return the (n-1)th index of the words. Since the index starts at 0, (n-1)th index corresponds to the nth word
The required function to obtain the nth word of a sentence is stated below :
def get_word(sentence, n):
# Only proceed if n is positive
if n > 0 :
words = sentence.split()
# Only proceed if n is not more than the number of words
if n <= len(words) :
return words[n-1]
return("")
The split function allows strings to be broken down or seperated into distinct parts based on a stated delimiter or seperator such as (comma(,), hypen(-), whitespace) and so on.
In programming indexing starts from 0, hence, the first value is treated as being in position 0.
To obtain value 4th word in a sentence, it will be regarded as being in position 3.
To split the words in the sentence above, the string will be split based on whitespace(space in between each word).
By default this can be achieved without passing any argument to the split method.
That is ; str.split()
print(get_word("This is a lesson about lists", 4))
#This will print lesson (position 3) counting from 0
print(get_word("This is a lesson about lists", -4))
# This won't print anything as it does not meet the first if condition
print(get_word("Now we are cooking!", 1))
#This will print Now(position 0) counting from 0.
print(get_word("Now we are cooking!", 5))
#This won't print anything as it does not meet the second if condition (n is more than the number of words in the sentence(4)
Learn more : https://brainly.com/question/17615351
Jayden wants to take a current theme but just change a little bit of it. Complete the steps to help Jayden.
Go to the tab on the ribbon and the group.
Click Themes and select one.
Go into the workbook, make the changes, and return to the Themes gallery.
Select to save the changes.
Answer:
C, A, and B.
or
3, 1, and 2
Explanation:
In that order
The first will be to adjust the workbook. then there should be a theme that needs to be selected. And then next is to Select the tab and the box of ribbon on which the theme needs to be presented.
Thus, options C, A, and B are correct.
What is a theme?A theme is made up of window colors, music, and desktop backdrop images. A theme is a collection of window accent colors, noises, and desktop backdrop images. If you don't want to customize your computer cover image, window highlight colors, home screen widget, etc., you can use a theme.
Make the adjustments that are required in the workbook, then go back to the motif gallery.
Choose a theme by clicking Themes.
Go to the tab and box on the ribbon.
A theme often consists of a selection of forms and colors for the window design, the visual control components, and the window. Therefore, options C, A, and B are the correct options.
Learn more about the theme, here:
https://brainly.com/question/12461938
#SPJ3
what are business rules
Answer:
defines or constrains some aspect of business and always resolves to either true or false. It specifically involves terms, facts and rules
Explanation:
Consider the following recursive method, which is intended to return a String with any consecutive duplicate characters removed. For example, removeDupChars("aabcccd") returns "abcd".public static String removeDupChars(String str){if (str == null || str.length() <= 1){return str;}else if (str.substring(0, 1).equals(str.substring(1, 2))){return removeDupChars(str.substring(1));}else{/* missing code */}}Which of the following can replace /* missing code */ so that removeDupChars works as intended?A. return removeDupChars(str.substring(2));B. return removeDupChars(str.substring(1)) + str.substring(0, 1);C. return removeDupChars(str.substring(2)) + str.substring(1, 2);D. return str.substring(0, 1) + removeDupChars(str.substring(1));E. return str.substring(1, 2) + removeDupChars(str.substring(2));
Answer:
D. return str.substring(0, 1) + removeDupChars(str.substring(1));
Explanation:
The logic here is following:
If the there are consecutive duplicate characters, return the removeDupChars method. The parameter of the removeDupChars method is a string, but the duplicate of the first character is removed from the string. The else-if part of the program does this job.
If the consecutive characters are not duplicated, return the first character of the string and the removeDupChars method. The parameter of the removeDupChars method is the rest of the string characters. The else part of the program does this job.
When the length of the str becomes one (or when the str is null), the program reaches its base and returns the str. The if part of the program does this job.
A recursive function is that function that calls itself from within.
The code statement that can replace the comment /* missing code */ is (d) return str.substring(0, 1) + removeDupChars(str.substring(1));
The function definition is given as:
removeDupChars(String str)The function has 3 linked conditional statements, each of which perform three different functions.
The first works for a null string and single characterThe second and the third are to return the intended string for strings with multiple lengths.For the third condition to work, the consecutive characters must not be duplicated.
So, the code statement that does this is (d) return str.substring(0, 1) + removeDupChars(str.substring(1));
Read more about recursive functions at:
https://brainly.com/question/25647517
In this warm up project, you are asked to write a C++ program proj1.cpp that lets the user or the computer play a guessing game. The computer randomly picks a number in between 1 and 100, and then for each guess the user or computer makes, the computer informs the user whether the guess was too high or too low. The program should start a new guessing game when the correct number is selected to end this run (see the sample run below).
Check this example and see how to use functions srand(), time() and rand() to generate the random number by computer.
Example of generating and using random numbers:
#include
#include // srand and rand functions
#include // time function
using namespace std;
int main()
{
const int C = 10;
int x;
srand(unsigned(time(NULL))); // set different seeds to make sure each run of this program will generate different random numbers
x = ( rand() % C);
cout << x << endl;
x = ( rand() % C ); // generate a random integer between 0 and C-1
cout << x << endl;
return 0;
}
*********************************************
Here is a sample run of the program:
Would you like to (p)lay or watch the (c)omputer play?
p
Enter your guess in between 1 and 100.
45
Sorry, your guess is too low, try again.
Enter your guess in between 1 and 100.
58
Sorry, your guess is too low, try again.
Enter your guess in between 1 and 100.
78
Sorry, your guess is too high, try again.
Enter your guess in between 1 and 100.
67
Sorry, your guess is too low, try again.
Enter your guess in between 1 and 100.
70
Sorry, your guess is too high, try again.
Enter your guess in between 1 and 100.
68
Sorry, your guess is too low, try again.
Enter your guess in between 1 and 100.
69
Congrats, you guessed the correct number, 69.
Would you like to (p)lay or watch the (c)omputer play or (q)uit?
c
The computer's guess is 50.
Sorry, your guess is too high, try again.
The computer's guess is 25.
Sorry, your guess is too high, try again.
The computer's guess is 13.
Sorry, your guess is too low, try again.
The computer's guess is 19.
Sorry, your guess is too high, try again.
The computer's guess is 16.
Sorry, your guess is too low, try again.
The computer's guess is 17.
Congrats, you guessed the correct number, 17.
Would you like to (p)lay or watch the (c)omputer play or (q)uit?
q
Press any key to continue
*****************************************************
So far I was able to create the user input ortion of the program, I need help coding the computer generated guessing game,
if the users input choice of computer at the end or choice of play.. if you could help me build on what I have below greatly appreciate it!!! thank you
code I have got so far:
#include
#include
#include
int main(void) {
srand(time(NULL)); // To not have the same numbers over and over again.
while(true) { // Main loop.
// Initialize and allocate.
int number = rand() % 99 + 2; // System number is stored in here.
int guess; // User guess is stored in here.
int tries = 0; // Number of tries is stored here.
char answer; // User answer to question is stored here.
//std::cout << number << "\n"; // Was used for debug...
while(true) { // Get user number loop.
// Get number.
std::cout << "Enter a number between 1 and 100 (" << 20 - tries << " tries left): ";
std::cin >> guess;
std::cin.ignore();
// Check is tries are taken up.
if(tries >= 20) {
break;
}
// Check number.
if(guess > number) {
std::cout << "Too high! Try again.\n";
} else if(guess < number) {
std::cout << "Too low! Try again.\n";
} else {
break;
}
// If not number, increment tries.
tries++;
}
// Check for tries.
if(tries >= 20) {
std::cout << "You ran out of tries!\n\n";
} else {
// Or, user won.
std::cout<<"Congratulations!! " << std::endl;
std::cout<<"You got the right number in " << tries << " tries!\n";
}
while(true) { // Loop to ask user is he/she would like to play again.
// Get user response.
std::cout << "Would you like to play again (Y/N)? ";
std::cin >> answer;
std::cin.ignore();
// Check if proper response.
if(answer == 'n' || answer == 'N' || answer == 'y' || answer == 'Y') {
break;
} else {
std::cout << "Please enter \'Y\' or \'N\'...\n";
}
}
// Check user's input and run again or exit;
if(answer == 'n' || answer == 'N') {
std::cout << "Thank you for playing!";
break;
} else {
std::cout << "\n\n\n";
}
}
// Safely exit.
std::cout << "\n\nEnter anything to exit. . . ";
std::cin.ignore();
return 0;
}
Answer:
A C++ program was used for a user or the computer play a guessing game.
Explanation:
The C++ code to this question:
#include <iostream>
#include <cstdlib> // srand and rand functions
#include <ctime> // time function
using namespace std;
int main()
{
const int C = 100;// constant integer with defined value 100
char type;// type of option chosen
cout<<"Would you like to (p)lay or watch the (c)omputer play?"<<endl;
cin>>type;// input of type
do{// for first iteration you can't choose q
int x;
srand(unsigned(time(NULL))); // set different seeds to make sure each run of this program will generate different random numbers
x = ( rand() % C);
x++;// random value between 1 and 100
int check=-1;// make initial check=-1
int ends=C;// for type selected as c, make the initial guess to be chosen from 1 to 100
int start=1;
while(1)
{
if(type=='p')// if selected type is p
{
cout<<"Enter your guess in between 1 and 100."<<endl;
cin>>check;
}
else if(type=='c')// if selected type is c
{
check=start+(rand()%(ends-(start-1)));//get a random number between updated start and ends for computer guessing
cout<<"The computer's guess is "<<(check)<<"."<<endl;
}
else// if type is not equal to c or p or q
{
cout<<"Invalid option chosen"<<endl;
break;
}
if(check>x)// if the guess is greater
{
cout<<"Sorry, your guess is too high, try again."<<endl;
ends=check-1;// update ends in case type is c
}
else if(check<x)
{
cout<<"Sorry, your guess is too low, try again."<<endl;
start=check+1;// update start
}
else// if right number is selected
{
cout<<"Congrats, you guessed the correct number, "<<x<<"."<<endl;
break;
}
}
cout<<"Would you like to (p)lay or watch the (c)omputer play or (q)uit?"<<endl;
cin>>type;
}while(type!='q');
return 0;
}
Note: Kindly find an attached copy of the screenshot of execution of code below
IF 2+2=4 AND 5+5 IS 10 __________
Answer:
8+8=16?
Explanation:
Answer:
Then 11+11 IS 22
Explanation:
What does this button mean in the computer ????????
Answer:
Context menu
Explanation:
If you want to open a context menu this is the one
Alternative is Shift+F10 in most applications to open a context menu. It's basically the same thing as the menu key
Answer:
Context MenuExplanation:
this button mean in the computer
Define a structure with the tag Consumption to consist of a character array (city[20]), an integer (year), and a double (usage). b) Define a structure with the tag Resource to consist of two character arrays (material [30], and units[20]), and three doubles (longitude, latitude, and quantity). Then in the main function, declare metal and fuel to be variables of type struct Resource, and then declare water and power to be variables of type struct Consumption.
Answer:
..............................................................................
...............................
Explanation:
..............................................................................................................................................
"What router feature provides basic security by mapping internal private IP addresses to public external IP addresses, essentially hiding the internal infrastructure from unauthorized personnel
Answer:
i think phone
hope this helps u stay safe
Explanation:
NAT preserves and safeguards IP addresses that have been lawfully registered. Translation of network addresses with security. NAT enables users to browse the internet more discreetly and securely by hiding the device's IP address from the wireless site even when sending and receiving traffic.
What is NAT outer feature provides basic security?NAT can also offer security and confidentiality. NAT shields the private device from outside access by transferring data packets from public to private addresses. Unwanted data has a harder time slipping through the cracks, since the router organizes the data to make sure everything gets to where it should.
Therefore, NAT outer feature provides basic security by mapping internal private IP addresses to public external IP addresses, essentially hiding the internal infrastructure from unauthorized personnel.
Learn more about router here:
https://brainly.com/question/29869351
#SPJ5
Write a program which increments from 0 to 20 and display results in Decimal on the console 2-b) Modify above program to increment from 0 to 20 and display results in Binary on the console
Answer:
This program is written in C++
Comment are used to explain difficult lines
The first program that prints 0 to 20 (in decimal) starts here
#include<iostream>
int main()
{
//Print From 0 to 20
for(int i = 0;i<21;i++)
{
std::cout<<i<<'\n';
}
}
The modified program to print 0 to 20 in hexadecimal starts here
#include<iostream>
using namespace std;
int main()
{
//Declare variables to use in conversion;
int tempvar, i=1,remain;
//Declare a char array of length 50 to hold result
char result[50];
//Print 0
cout<<"0"<<endl;
// Iterate from 1 to 20
for(int digit = 1; digit<21; digit++)
{
//Start Conversion Process
//Initialize tempvar to digit (1 to 20)
tempvar = digit;
while(tempvar!=0)
{
//Divide tempvar by 16 and get remainder
remain = tempvar%16;
if(remain<10)
{
result[i++]=remain + 48;
}
else
{
result[i++] = remain + 55;
}
//Get new value of tempvar by dividing it by 16
tempvar/=16;
}
//Print result
for(int l=i-1;l>0;l--)
{
cout<<result[l];
}
i=1;
cout<<endl;
}
return 0;
}
//The Program Ends Here
See Attachments for program 1 and 2; program 2 is the modified version of 1
Complete method printPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by "seconds". End with a newline. Example output for ounces = 7: 42 seconds
code:
import java.util.Scanner;
public class PopcornTimer {
public static void printPopcornTime(int bagOunces) {
/* Your solution goes here */
}
public static void main (String [] args) {
printPopcornTime(7);
}
}
Answer:
if(bagOunces < 2){
System.out.println("Too small");
}
else if(bagOunces > 10){
System.out.println("Too large");
}
else{
System.out.println(6*bagOunces+" seconds");
}
Explanation:
The missing code segment is an illustration of conditional statements.
Conditional statements are used to execute statements depending on the truth value of the condition.
The missing code segment, where comments are used to explain each line is as follows:
//If bagOunces is less than 2
if(bagOunces < 2){
//This prints "Too small"
System.out.println("Too small");
}
//If bagOunces is greater than 10
else if(bagOunces > 10){
//This prints "Too large"
System.out.println("Too large");
}
//Otherwise
else{
//This calculates and prints the popcorn time
System.out.println(6*bagOunces+" seconds");
}
Read more about similar programs at:
https://brainly.com/question/7253053
In cell F29, use an IF function to display the correct Shipping Charge, based on the amount of the Discounted Total. If the Discounted Total is greater than or equal to the Free Shipping Minimum found in cell B28, the Shipping Charge is 0 (zero); otherwise, the Shipping Charge is 5% of the Discounted Total. Hint: You will need to use a formula for the Value if False to calculate what 5% of the Discounted Total will be.
Answer:
= IF(B29 >= B28,0,(0.05 * B29))
Explanation:
Given
Free Shipping Minimum = B28
Shipping Charge = F29
Required
Write a formula in F29 to calculate the total shipping charge based on the condition in the question.
To solve this, the following assumption needs to be made.
It'll be assumed that cell B29 contains the value for Discounted Total.
So,
Discounted Total = B29
The condition in the question says
1. If Discounted Total (B29) is greater than or equal to the Free Shipping Minimum (B29), then Shipping Charge (F29) is 0
This can be represented as
If(B29 >= B28)
F29 = 0
2. Else (i.e. if (1) above is false), Shipping Charge (F29) equals 5% of Discounted Total (B29)
This can also be represented as
F29 = 0.05 * B29
Writing the formula in (1) and (2) together in Excel format;
= IF(B29 >= B28, 0, (0.05 * B29))
The above formula will give the desired result based on the condition in the question.
Take for instance;
Free Shipping Minimum = B28 = 28
Discounted Total = B29 = 30
Since 30 >= 28, the value of F29 will be 0 because it satisfies condition 1.
But if
Free Shipping Minimum = B28 = 30
Discounted Total = B29 = 28
Since 28 < 30, the value of F29 will be 5% of 28 = 1.4 because it satisfies condition 2
The goal of this exercise is to determine whether the following system specifications are consistent: If the file system is not locked, then new messages will be queued. If the file system is not locked, then the system is functioning normally, and conversely. If new messages are not queued, then they will be sent to the message buffer. If the file system is not locked, then new messages will be sent to the message buffer. New messages will not be sent to the message buffer.
Answer:
The following specifications are consistent
Explanation:
The file system is locked ⇒ L
New messages will be queued ⇒ Q
The system is functioning normally ⇒ N
The message will be sent to the message buffer ⇒ B
" Now, let us rewrite the specifications"
"If the file system is not locked, then new messages will be queued" ∴ ¬L ⇒ Q
"If the system is not locked, then the system is functioning normally and conversely" ∴ ¬L ⇔ N
"If new messages are not queued, then they will be sent to the message buffer" ∴ ¬Q ⇒ B
"If the file system is not locked, then new messages will be sent to the message buffer" ∴ ¬L ⇒ B
"New messages will not be sent to the message buffer" ∴ ¬B
To get consistency, take N to be false such that ¬N is true.
This mean that both L and Q be true, by the two conditional statements that have N as consequence.
First conditional statement ¬L ⇒ Q is of the form F?T, which is true.
Finally, the ¬L ⇒ B can be satisfied by taking B to be false.
This means that this set of specifications is consistent!
Truth value assignment
B: False
N: False
Q: True
L: True
Observing the Specification, Condition and Truth Value, it is evident that they are consistent.
productivity is the combination of
Answer:
Productivity is the combination of efficiency and effectiveness.
Explanation:
Case 4-1 Santo is creating a company newsletter for his architectural firm. He has solicited contributions from his colleagues on their current projects, and several people have provided photos of homes and businesses they are currently remodeling. Santo is about to begin compiling all the information using desktop publishing in Microsoft Word. Santo wants to use most of the graphics his colleagues asked to display with their articles, but his file size has become unmanageable with so many sketches and photos. Santo might be able to reduce his document file size without leaving out content by _______.
Answer:
Saving all graphics as JPEG files
Explanation:
A JPEG file can be defined as the way in which images ,graphics or photos are been stored after the compression of the images has occured because compression of images help to reduce the quality of the image thereby creating more available space.
Since Santo file size has become unmanageable with so many sketches and photos the best alternative for him is to Save all the graphics as JPEG files which will enable him to have extra space because JPEG files will enable the compression of those images by reducing the quality of the image without leaving out any content.
Tech companies prepare for cyberattacks using common cybersecurity resources. Select one of the resources listed and explain how you could implement that particular policy to prevent an attack: 1. monitoring and assessment, 2. policies and controls, 3. hiring, 4. software, 5. firewalls, 6. authentication and access, 7. encryption.
Explanation:
Tech companies focus on making advancement in technology products and services. They are driven by innovations and the use of technology to make them standout from other companies. They uses technology to render services.
Cyber attack is a deliberate attack on companies' computers or on an individual computer with the intention of stealing information, or other reasons without victim approval.
How policies on encryption could be implemented to prevent cyber attacks by:
Cyber security policies explain the guidelines on how organization staffs and end-users access online applications and internet resources without fear of security details being hacked.
1. Rules should be set on how to use email encryption: This rule should be easy to read. Emails should be encrypted to provide safety from cyber attacks. Contents should not be visible, should only be visible to those sending and receiving such emails.
2. Rules on encryption of sensitive messages and back up data.
3. rules on encryption of Log in details and passwords
Your solution should for this assignment should consist of five (5)files:============================================== FuelGauge.h (class specification file)FuelGauge.cpp (class implementation file)Odometer.h (class specification file)Odometer.cpp (class implementation file)200_assign6.cpp (application program)=================================================★ For your sixth programming assignment, you will be implementing a program that uses two(2)classes that work together to simulate a car’s fuel gauge and odometer. The classes you will design are: TheFuelGaugeClass: This class will simulate a fuel gauge. Its responsibilities are↘To know the car’s current amount of fuel, in gallons.↘To report the car’s current amount of fuel, in gallons.↘To be able to increment the amount of fuel by 1 gallon. This simulates putting fuel in the car. (The car can hold a maximum of 15 gallons)↘To be able to decrement the amount of fuel by 1 gallon, if the amount of fuel is greater than 0 gallons. This simulates burning fuel as the car runs.TheOdometerClass: This class will simulate the car’s odometer. Its responsibilities are:↘To know the car’s current mileage.↘To report the car’s current mileage.↘To be able to increment the current mileage by 1 mile. The maximum mileage the odometer can store is 999,999 miles. When this amount is execeeded, the odometer resets the current mileage to 0.↘To be able to work with aFuelGaugeobject. It should decrease theFuelGaugeobject’s current amount of fuel by 1 gallon for every 24 miles traveled. (The car’s fuel economy is 24 miles per gallon)The FuelGaugeclass should have at least one constructor, and the appropriate member functions to get the number of gallons, increment the number of gallons, and decrement the number of gallons.★ The odometer class should have at least one constructor, and the appropriate member functions to get the mileage and increment the mileage (unfortunately you cannot decrement the mileage!).★ In the odometer class, you can have a member variable that is a pointer to a FuelGauge object. This is how you can establish a relationship between the two classes that allow them to work together. For every mile the car is driven, the odometer is increased by 1, and for every 24 miles the car is driven, the number of gallons is reduced by one.★ So in the Odometer class, one of the private member variables should be of type fuel gauge* (pointer to a FuelGauge object).★ Demonstrate the two classes by creating instances(objects)of each. Simulate filling the car up with fuel, and then run a loop that increments the odometer until the car runs out of fuel. During each loop iteration, print the car’s current mileage and amount of fuel.
Answer: provided in the explanation section
Explanation:
This was implemented in C++
Filename: Car.cpp
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include "Odometer.h"
using namespace std;
int main()
{
char response;
do
{
FuelGuage* myFuel = new FuelGuage(6);
int fuelLevel = myFuel->getFuel();
cout << "Car gas level: " << fuelLevel << endl;
cout << "Car is filling up" << endl;
while(myFuel->getFuel() < 15)
{
myFuel->addFuel();
}
Odometer* car = new Odometer(myFuel, 999990);
cout << "Car gas level: " << car->getFuelGuage()->getFuel() << endl;
cout << "Car is off!" << endl;
cout << "--------------------------" << endl;
while(car->getFuelGuage()->getFuel() > 0)
{
car->addMile();
int miles = car->getMileage();
cout << "Mileage: " << setw(6) << miles << ", Fuel Level: " << car->getFuelGuage()->getFuel() << endl;
cout<<"--------------------------------------------------------------"<<endl;
}
delete myFuel;
delete car;
cout << "Would you like to run the car again(Y/N)? ";
cin >> response;
system("cls||clear");
} while(toupper(response) != 'N');
return 0;
}
Filename: FuelGuage.cpp
#include "FuelGuage.h"
FuelGuage::FuelGuage()
{
init();
}
FuelGuage::FuelGuage(int fuel)
{
init();
this->fuel = fuel;
}
FuelGuage::FuelGuage(const FuelGuage& copy)
{
this->fuel = copy.fuel;
}
void FuelGuage::init()
{
this->fuel = 0;
}
int FuelGuage::getFuel()
{
return fuel;
}
void FuelGuage::addFuel()
{
fuel++;
}
void FuelGuage::burnFuel()
{
fuel--;
}
Filename:FuelGuage.h
#ifndef FUEL_GUAGE_H
#define FUEL_GUAGE_H
class FuelGuage
{
private:
int fuel;
void init();
public:
FuelGuage();
FuelGuage(int fuel);
FuelGuage(const FuelGuage& copy);
int getFuel();
void addFuel();
void burnFuel();
};
#endif
Filename : Odometer.cpp
#include "Odometer.h"
Odometer::Odometer()
{
init();
}
Odometer::Odometer(FuelGuage* inFuel, int inMileage)
{
init();
this->fuel = new FuelGuage(*inFuel);
this->mileage = inMileage;
this->milesSinceAddingFuel = 0;
}
void Odometer::init()
{
fuel = new FuelGuage();
mileage = 0;
milesSinceAddingFuel = 0;
}
FuelGuage* Odometer::getFuelGuage()
{
return fuel;
}
int Odometer::getMileage()
{
return mileage;
}
void Odometer::addMile()
{
if(mileage < 999999)
{
mileage++;
milesSinceAddingFuel++;
}
else
{
mileage = 0;
milesSinceAddingFuel++;
}
if((milesSinceAddingFuel % 24) == 0)
{
fuel->burnFuel();
}
}
void Odometer::resetMiles()
{
milesSinceAddingFuel = 0;
}
Odometer::~Odometer()
{
delete fuel;
}
Filename: Odometer.h
#ifndef ODOMETER_H
#define ODOMETER_H
#include "FuelGuage.h"
class Odometer
{
private:
void init();
int mileage;
int milesSinceAddingFuel;
FuelGuage* fuel;
public:
Odometer();
Odometer(FuelGuage* inFuel, int inMileage);
FuelGuage* getFuelGuage();
int getMileage();
void addMile();
void resetMiles();
~Odometer();
};
#endif
