Which element is represented by the model of the atom above?
Carbon is the element modeled
What is the volume of the rock? A. 7 cm3
B. 12 cm3
C. 19 cm3
D. 5 cm3
As the ball moves from point A to point B, kinetic energy...
Answer:
KE=1/2mv*
Explanation:
write the numbers inorder to the symbols
Ans use this formula to solve the problem
Define heat according to molecular theory .
I think ....... the answer will be ......
like a theory
5. What is the velocity of a 0.5 kg ball that has a momentum of 3.00 kg m/s?
Answer:
6 m/s
Explanation:
p=mv
p=3 kg.m/s
m=0.5 kg
rearrange and substitute to find v:
(3)=(0.5)v
v=3/0.5
v=6 m/s
help me pls. will give brainliest
Answer:
B: Relay
Explanation:
Out of all the options, the only device that relies upon the magnetic field of an electric current.
The principle relies upon the principle of electro magnetic attraction whereby when the circuit detects a faulty current, it makes the electromagnetic field to become energized which in turn produces the temporary magnetic field. This magnetic field then moves the relay armature which is used in opening or closing the connections.
A car covers 400m distance in 50 sec find it's speed?
Answer:
[tex]\boxed {\boxed {\sf 8 \ m/s}}[/tex]
Explanation:
Speed is equal to distance over time.
[tex]s=\frac{d}{t}[/tex]
The distance is 400 meters and the time is 50 seconds.
[tex]d= 400 \ m \\t= 50 \ s[/tex]
Substitute the values into the formula.
[tex]s=\frac { 400 \ m }{ 50 \ s}[/tex]
Divide.
[tex]s= 8 \ m/s[/tex]
The speed of the car is 8 meters per second.
Please explain why
True or False
Burning paper is a formation of a precipitate
You carry a 20. N bag of dog food up a 6.0 m flight of stairs. How much work was done?
Answer:
Solution given:
force=20N
distance travelled=6m
work done=force *displacement=20*6=120joule
Work done=120joule.
Work done=Force×Displacement
[tex]\\ \rm\longmapsto Work\:done=20(6)[/tex]
[tex]\\ \rm\longmapsto Work\:done=120J[/tex]
if a person weighs 140 lb on earth their weight in newtons is
Answer:
623.6N
Explanation:
There are 2.2 pounds in one kilogram, so you must divide 140 lb by 2.2 to convert the units to kilograms.
140/2.2 = 63.6 kg
The gravitational force also known as weight would equal mass times acceleration due to gravity.
Fg = (63.6 kg)(9.8 m/s^2) = 623.6N
The pressure was 50pa ,when a perpendicular force was applied on a surface area of 2.5m2.what is the force applied??????
Answer:
Force = 125 Newton
Explanation:
Given the following data;
Pressure = 50 pa
Area = 2.5 m²
To find the force applied;
Force = pressure * area
Substituting into the formula, we have;
Force = 50 * 2.5
Force = 125 Newton
What is the kinetic energy of a 2.7kg book
moving at 3.5m/s?
Give your answer rounded to one place after the
decimal, no units.
!!
If a car is traveling 35 m/s for 200 seconds, how far will the car travel?
Answer:
7.14285714286
Explanation:
Pls help me find the electrons of these 4 questions asap.
Okay Okay Serious question!!!!
How many times does the earth rotate in a year??
365.25 or 366.25 in a leap year
How would the force of gravity between two objects change if the mass of
each object were doubled?
A. The force between them would be 2 times larger than with the
initial masses.
B. The force between them would be 1/4 the force with the initial
separation.
C. The force between them would be 4 times larger than with the
initial masses.
D. The force between them would be 1/2 the force with the initial
separation
Answer:
Option C. The force between them would be 4 times larger than with the
initial masses.
Explanation:
To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:
From:
F = GMₐM₆/ r²
Keeping G/r² constant, we have
F₁ = MₐM₆
Let the initial mass of both objects to be m
F₁ = MₐM₆
F₁ = m × m
F₁ = m²
Next, let the masses of both objects doubles i.e 2m
F₂ = MₐM₆
F₂ = 2m × 2m
F₂ = 4m²
Compare the initial and final force
Initial force (F₁) = m²
Final (F₂) = 4m²
F₂ / F₁ = 4m² / m²
F₂ / F₁ = 4
F₂ = 4F₁ = 4m²
From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the
initial masses.
Thus, option C gives the correct answer to the question.
joe loves joe so yes
Answer:
noice.
Explanation:
thanks for points.... idrk what im supposed to do
----------------------------------------------------------------------------------------------------------------
yeah same.
WILL MARK BRAINLIEST IF GOTTEN RIGHT!
Answer:
Angle Angle Similarity Postulate
Explanation:
A person can jump out of an airplane at 5000 feet, without a parachute, AND land on the ground safely (without any injury), IF they can manage to do what physics trick?
Lengthen the moment/time of impact
Bend knees right before impact
Spread out arms and legs to slow down
Shorten the length/time of impact
Answer:
Momentum is equal to mass for velocity (p1=mv)
But momentum is also equal to Force for time of impact (p1=Ft). Hence the impact force is inversely proportional to the fall time and directly proportional to the mass and fall velocity : F=mv/t^2 or F=p1/t
If he slows down, v diminishes and F diminishes
Hence correct Answer is C
What are the five elements of fitness?
Answer:
5 Components of Physical Fitness
Cardiovascular Endurance.
Muscular Strength.
Muscular endurance.
Flexibility.
Body Composition.
Who do you simp for in Harry Potter?
Answer:
I don't rlly know anyone in harry Potter so I simp for........MYSELF :)
Answer:
Either Draco Malfoy or Harry Potter
Explanation:
UvU
What is the acceleration of a 24 kg mass pushed by an 8 N force?
Answer:
0.25 m/s squared
Explanation:
Mass of the body (m)= 24kg
Applied force on the body(F)= 6N
Acceleration of the body (a)= ?
Solution
F = ma
a = F/m
a = 6N/24kg
a = 0.25m/s^2
Answer: The acceleration of the body is 0.25m/s^2
I hope this helps
Answer:
[tex]\boxed {\boxed {\sf a=\frac {1}{3} \ m/s^2}}[/tex]
Explanation:
Force is the product of mass and acceleration.
[tex]F=ma[/tex]
The mass is 24 kilograms and the force is 8 Newtons. Let's convert the Newtons to make the problem easier.
1 Newton is equal to 1 kilogram meter per square second. The force of 8 N equals 8 kg*m/s²Substitute the known values into the formula.
[tex]8 \ kg*m/s^2= (24 \ kg )*a[/tex]
Since we are solving for a, we must isolate the variable. It is being multiplied and the inverse of multiplication is division. Divide both sides by 24 kilograms.
[tex]\frac {8 \ kg*m/s^2}{24 \ kg}= \frac{(24 \ kg )*a}{24 \ kg}[/tex]
The kilograms will cancel, hence our earlier unit conversion.
[tex]\frac {8 \ m/s^2}{24 }= a[/tex]
[tex]\frac {1}{3} \ m/s^2=a[/tex]
The acceleration is 1/3 meter per square second.
1.
X, Y and Z are the weights of three objects
suspended by pulleys as shown.
Assuming the pulleys in this system are frictionless
and weightless and that Z= 12 N, what are the
values of X and Y?
24°
50°
Х
Y
Z
Answer:
The weight of the object X is approximately 3.262 N (Acting downwards)
The weight of the object Y is approximately 8.733 N (Acting downwards)
Explanation:
The question can be answered based on the principle of equilibrium of forces
The given parameters are;
The weight of Z = 12 N (Acting downwards)
The weight of the pulleys = Negligible
From the diagram;
The tension in the in the string attached to object Z = The weight of object Z = 12 N
The tension in the in the string attached to object X = The weight of the object X
The tension in the in the string attached to object Y = The weight of the object Y
Given that the forces are in equilibrium, we have;
The sum of vertical forces acting at a point, [tex]\Sigma F_y[/tex] = 0
Therefore;
[tex]T_{1y} + T_{2y} + T_{3y} = 0[/tex]
[tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex]
Where;
[tex]T_{1y}[/tex] = The weight of object Z = 12 N
[tex]T_{1y}[/tex] = 12 N
[tex]T_{2y}[/tex] = The vertical component of tension, T₂ = T₂ × sin(24°)
∴ [tex]T_{2y}[/tex] = T₂ × sin(156°)
Similarly;
[tex]T_{3y}[/tex] = T₃ × sin(50°)
From [tex]T_{1y} = -( T_{2y} + T_{3y} )[/tex], and [tex]T_{1y}[/tex] = 12 N, we have;
12 N = -(T₂ × sin(156°) + T₃ × sin(50°))...(1)
Given that the forces are in equilibrium, we also have that the sum of vertical forces acting at a point, ∑Fₓ = 0
Therefore at point B, we have;
T₁ₓ + T₂ₓ + T₃ₓ = 0
The tension force, T₁, only has a vertical component, therefore;
∴ T₁ₓ = 0
∴ T₂ₓ + T₃ₓ = 0
T₂ₓ = -T₃ₓ
T₂ₓ = T₂ × cos(156°)
T₃ₓ = T₃ × cos(50°)
From T₂ₓ = -T₃ₓ, we have;
T₂ × cos(156°) = - T₃ × cos(50°)...(2)
Making T₃ the subject of equation (1) and (2) gives;
Making T₃ the subject of equation in equation (1), we get;
12 = -(T₂ × sin(156°) + T₃ × sin(50°))
∴ T₃ = (-12 - T₂ × sin(156°))/(sin(50°))
Making T₃ the subject of equation in equation (2), we get;
T₂ × cos(156°) = - T₃ × cos(50°)
∴ T₃ = T₂ × cos(156°)/(-cos(50°))
Equating both values of T₃ gives;
(-12 - T₂ × sin(156°))/(sin(50°)) = T₂ × cos(156°)/(-cos(50°))
-12/(sin(50°)) = T₂ × cos(156°)/(-cos(50°)) + T₂ × sin(156°)/(sin(50°))
∴ T₂ = -12/(sin(50°))/((cos(156°)/(-cos(50°)) + sin(156°)/(sin(50°))) ≈ -8.02429905283
∴ T₂ ≈ -8.02 N
From T₃ = T₂ × cos(156°)/(-cos(50°)), we have;
T₃ = -8.02× cos(156°)/(-cos(50°)) = -11.3982199717
∴ T₃ ≈ -11.4 N
The weight of the object X = -T₂ × sin(156°)
∴ The weight of the object X ≈ -(-8.02 × sin(156°)) = 3.262 N
The weight of the object X ≈ 3.262 N (Acting downwards)
The weight of the object Y = -(T₃ × sin(50°))
∴ The weight of the object Y = -(-11.4 × sin(50°)) ≈ 8.733 N
The weight of the object Y ≈ 8.733 N (Acting downwards)
A skater moves with 15 m/s velocity in a circle of radius circle of radius 30 m. The ice exerts a center force of 450 N. What is the mass of the skater?
what is this simple machines name
Answer:
bottle opener and door knob
Explanation:
Answer:
bottle opener
door handle
who invented Pascal??
Explain the changes in energy as a ball is held in the air , and then dropped
Answer:
Potential Energy to Kenetic Energy
Explanation:
When holding a ball in the air, the ball has potential energy. Once you drop the ball, the ball gains Kenetic Energy
The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.M/s. What is the velocity of the vehicle?
In lab, a radiation detector was used to calculate the background radiation. The
readings taken every minute were recorded in the table below. What is the reason
that the readings are not the same every minute?
Two objects have a gravitational force of 800 N. If they are moved twice as far apart and the mass of one object doubles, what is the new gravitational force?
Answer:
400 N
Explanation:
From the question,
F = kmm'/r²........................ Equation 1
Where F = gravitation force, m and m' = mass 1 and mass 2 respectively, r = distance between the masses.
Given; F = 800 N
Substitute these values into equation 1
800 = kmm'/r².............. Equation 2
If the distance is doubled (2r), and one of the mass is doubled (2m), The new force is
F' = k(2m)(m')/(2r)²
F' = 2kmm'/4r²
F' = kmm'/2r²................. Equation 3
Comparing equation 2 and equation 3
F' = F/2............................ Equation 4
Substitute the value of F into equation 4
F' = 800/2
F' = 400 N
