Help. Don’t mind the highlighter answers i don’t know if there right

If we rank these magnets from the strongest to the weakest magnetic field the correct order is 4, 3, 2, 1.

The magnetic field and radius are related in the context of a charged particle moving in a circular path under the influence of a magnetic field. When a charged particle moves in a circular path under the influence of a magnetic field, the force on the particle is directed toward the center of the circle. In this force, the radius can be expressed as r = mv / Bq.

This equation shows that the radius of the circular path is directly proportional to the velocity of the particle, and inversely proportional to the magnetic field strength and the charge of the particle.

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No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.

The potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.

A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.

As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.

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The machine changes how work is done, by making the process easier and increasing output with less effort.

Any device that uses energy to carry out a task is a machine. Machines can be simple, like a lever or pulley, or complex, like a computer or a car engine. The purpose of a machine is to make work easier, faster, or more efficient than it would be without the machine. Different types of energy, including human power, electricity, and fuel, can be used to power machines.

Bicycle: A bicycle is a human-powered machine that allows people to move faster and with less effort than walking or running. A person can travel farther distances faster and with less physical effort by turning the wheels and shifting gears with their pedaling motion.

Ax blade: An ax blade is a cutting tool used for chopping wood. It facilitates the process of splitting wood by utilizing a sharp metal blade to cut through the wood fibers, rather than depending exclusively on physical power to break the wood apart.

Car jack: A car jack is a mechanical device used to lift a car off the ground. A person can raise the car to access the underside for repairs or maintenance by pulling a lever and applying hydraulic pressure. Compared to attempting to lift the car manually, this makes maintenance and repairs easier and safer.

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The statement that is true regarding the circuit shown in the question is I₁ > I₃ > I₂ (last option)

To know the true statement, we shall determine the current flowing through each resistance. Details below:

For resistor 1

Voltage (V) = Current (I) × resistance (R)

12 = I₁ × 2

Divide both sides by 2

I₁ = 12 / 2

I₁ = 6 A

For resistor 2

Voltage (V) = Current (I) × resistance (R)

12 = I₂ × 8

Divide both sides by 8

I₂ = 12 / 8

I₂ = 1.5 A

For resistor 3

Voltage (V) = Current (I) × resistance (R)

12 = I₃ × 5

Divide both sides by 5

I₃ = 12 / 5

I₃ = 2.4 A

From the above calculation, we can see that I₁ > I₃ > I₂.

Thus, we can conclude that the true statement is I₁ > I₃ > I₂ (last option)

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(a) The S-P difference (sec) is 40 sec.

(b) The amplitude (mm) is 10 mm

(c) The distance (km) is 380 km

(d) The magnitude (M) is 4.5

The S-P wave difference (sec) is a measure used in seismology to determine the distance between a seismic station and an earthquake source.

From the graph, the S-P difference, that is between S and P = 40 s - 0 s

= 40 s

The distance (km) corresponding to 40 sec is 380 km.

The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.

The corresponding magnitude of the wave is 4.5.

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Answer: 3.99•10⁴ J

Explanation:

The Heat Formula is: Q = m • C • ΔT

Your given C, m, T₀, and T

C = 0.385 J/g•K

m = 1.55 kg or 1,550 g

T₀ = 33.0 °C

T = 99.9 °C

(ΔT = T - T₀)

Your only remaining variable is Q, heat, so you can now plug in your values to solve.

Q = (1550)(0.385)(99.9 - 33.0)

(ΔT(°C) = ΔT(K) because the conversion is linear)

Q = 39,922.575 J

or

3.99•10⁴ J

The recoil speed of the rifle is 0.5 m/s.

Weight of the rifle, W = 30 N

Mass of the rifle, M = W/g = 30/10 = 3 kg

Mass of the bullet, m = 5 g = 5 x 10⁻³kg

Speed of the bullet, v = 300 m/s

a) The expression for the recoil speed of the rifle is given by,

v(r) = mv/M

v(r) = 5 x 10⁻³ x 300/3

v(r) = 0.5 m/s

b) Weight of the man, W' = 700 N

Mass of the man, M' = W'/g = 700/10 = 70 kg

So, the combined mass of the man and the rifle,

M₁ = M + M'

M₁ = 3 + 70

M₁ = 73 kg

Therefore, the recoil speed of man and rifle,

v(r)' = mv/M₁

v(r)' = 5 x 10⁻³ x 300/73

v(r)' = 0.0205 m/s

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Answer:

A screw gauge, also known as a micrometer screw gauge, is a precision measuring instrument used to measure small distances with high accuracy. It consists of a calibrated screw and a calibrated thimble with a spindle and an anvil face. The spindle is attached to the screw, and the anvil face is fixed to the body of the instrument.

To use a screw gauge, the object being measured is placed between the spindle and the anvil face, and the screw is turned until the spindle makes contact with the object. The thimble is then turned, which moves the spindle and the screw, until the spindle is firmly in contact with the object. The reading on the scale of the thimble is then taken, which gives the distance between the spindle and the anvil face, with a high degree of precision.

Screw gauges are commonly used in a variety of fields, including engineering, machining, and scientific research, where accurate measurements are required.

Screw gauge measures diameter with high accuracy using a screw and nut mechanism. It has a pitch and graduated thimble.

A screw check is an estimating instrument used to gauge the width of items, particularly wires and chambers, with high exactness. It deals with the rule of a screw and nut component.The screw measure comprises of a U-molded outline with a screw toward one side and a thimble at the other.

The screw has a pitch, which is the distance gone by the screw in one complete turn. The pitch is as a rule of the request for 0.5 mm. The thimble is graduated into 50 or 100 equivalent parts. The roundabout scale on the thimble must be changed to such an extent that the zero of the scale matches with the zero of the pitch scale.

To utilize the screw check, the item whose width is to be estimated is set between the iron block and the shaft. The screw is turned until the shaft simply contacts the item. The pitch scale perusing is noted.

The thimble is then turned until the zero of the thimble scale concurs with the middle line of the pitch scale. The thimble scale perusing is then noted. The breadth of the item is then determined by adding the pitch scale perusing and the thimble scale perusing.

Along these lines, a screw check can gauge widths to an exactness of 0.01 mm or better. It is broadly utilized in designing, fabricating, and logical applications.

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The angle of arc m RNW is 60°, given that M is the center and RE and AN are diameters.

Since RE and AN are diameters, we know that ∠REO and ∠ANO are right angles, where O is the center of the circle. Since M is also the center of the circle:

m∠RMO = 180° - m∠RMN = 80°

m∠EMO = 180° - m∠EMW = 140°

Since ∠RMO and ∠EMO share a common vertex and their non-common sides are radii of the circle, they are congruent. Therefore:

m∠RMO = m∠EMO

80° = 140° - m∠RNW

m∠RNW = 60°

So m RNW = 60°.

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Image transcribed:

10.5.5 Your Turn! HOMEWORK

1. In Circle M, m∠RMN = 100° and m∠EMW = 40°. Calculate m RNW given that M is the center and RE and AN are diameters.

THE INABILITY OF A BODY TO CHANGE ITS STATE OF MOTION BY ITSELF ⚡

The tendency of matter to resist changes in its velocity or direction of motion is known as the inertia of motion. One of the cornerstones of traditional mechanics, it is also known as the law of inertia.

This principle states that, without an external force, an object at rest tends to remain at rest and an object in motion tends to maintain its current speed and direction. This means that until a force acts on the moving item to cause it to modify its motion, it will continue to proceed in a straight path and at a constant speed due to inertia of motion.

An object's mass affects how much inertia of motion it possesses. An object's inertia of motion increases with bulk, making it more challenging to alter its speed or direction of motion. This feature of matter has a wide range of practical uses, including predicting how moving objects will behave and creating and building systems that need to precisely regulate motion and forces.

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Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.

A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.

The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.

To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:

Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.

Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.

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The total distance covered during all three phases is approximately 882.375 m.

The car undergoes three phases: initial acceleration, constant speed, and deceleration.

In the first phase, it accelerates at 1.8667 m/s² for 15 seconds, covering 210.375 m.

In the second phase, it travels at a constant 28 m/s for 17 seconds, covering 476 m.

In the final phase, it decelerates at 2 m/s² for 14 seconds, covering 196 m.

The total distance covered during all three phases is approximately 882.375 m.

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Ritalin and Demerol are both controlled substances that have a high risk of abuse and dependence.

Schedule II drugs are believed to have a high abuse potential that could lead to severe psychological or physical dependence. They do, however, occasionally have other known medical applications and can be prescribed by a licensed healthcare provider.

Ritalin is an example of a stimulant, whereas Demerol is an example of an opioid. Thus the drugs that have been mentioned here are drugs that are strictly controlled.

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Answer: Velocity=0

Explanation: At equilibrium the spring system is not moving.

The heel of shoe D applies the greatest force to the carpet because it has the largest surface area in contact with it, and thus the largest force is distributed over that larger area.

Half of 87.3 km is 43.65 km.

To convert km to cm, we need to multiply by 100,000 (since there are 100,000 cm in 1 km).

So, 43.65 km = 43.65 x 100,000 = 4,365,000 cm.

To express the answer in multiples of 108 cm, we need to divide by 108 and round to four decimal places.

4,365,000 cm ÷ 108 = 40,416.6667

Rounding to four decimal places gives us 40.4167.

Therefore, half of an 87.3 km road is approximately 40.4167 x 108 cm.

The correct statement explaining how a megaphone amplifies sound is: "A megaphone amplifies sound by focusing sound energy into one specific direction."

By increasing the acoustic impedance perceived by the vocal chords and bringing them into closer proximity to the air, the loudhailer amplifies the sound and increases the amount of sound power that is emitted.

Many people are familiar with the distinctively distorted sound of a human voice amplified by a loudhailer thanks to its use in train and bus stations and sporting venues. It produces the sound of a vintage acoustic phonograph record player when used with music.

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The time it will take the block to fall the entire distance is (a) √3t₁.

Use the equations of motion to solve this problem. The equation to use is:

S = (1/2)gt²

where S = distance, g = acceleration due to gravity, and t = time.

First find the time it takes to fall the first third of the distance. The distance fallen is S₁ = x/3, so:

x/3 = (1/2)gt₁²

Solving for t₁:

t₁ = √((2x)/(3g))

Now, find the time it takes to fall the entire distance. The total distance is S₂ = x, so:

x = (1/2)gt₂²

Solving for t₂:

t₂ = √((2x)/g)

Substituting x with 3S₁:

t₂ = √((6S₁)/g)

Substituting t₁:

t₂ = √((4x)/(3g)) = √(4/3)t₁

Therefore, the answer is (a) √3t₁.

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The natural period of oscillation of a leg when marching is the time it takes for one complete cycle of oscillation. It can be calculated using the formula:

T = 2π √(L/g)

Where T is the natural period of oscillation, L is the length of the leg, and g is the acceleration due to gravity (9.81 m/s^2).

Assuming an average leg length of 1 meter, the natural period of oscillation of a leg is:

T = 2π √(1/9.81) ≈ 0.64 seconds

To compute the velocity of the leg during the march, we can use the formula:

v = 2πL/T

where v is the velocity, L is the length of the leg, and T is the natural period of oscillation.

Substituting the values, we get:

v = 2π(1)/(0.64) ≈ 9.8 m/s

Therefore, This means that during the march, the leg moves back and forth with a velocity of approximately 9.8 meters per second. It's important to note that this calculation assumes a simple harmonic motion, which may not be the case in reality due to the complex motion of various joints and muscles involved in marching.

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Answer:

the learning which is gained through observation and experimentation

Explanation:

arctan ( -7.55/7.14) =  - 46.6 degrees     ( or  313.4 degrees)

We can use the conservation of momentum principle to solve this problem. According to this principle, the total momentum of a system of objects remains constant if there are no external forces acting on the system. In this case, we can assume that there are no external forces acting on the two cars after they collide, so the total momentum of the system before the collision must be equal to the total momentum of the system after the collision.

The momentum of an object is defined as its mass multiplied by its velocity:

momentum = mass * velocity

Before the collision, the momentum of the first car (m1) is:

p1 = m1 * v1 = (0.1 kg) * (1.0 m/s) = 0.1 kg⋅m/s

Since the second car is stationary, its momentum before the collision is zero:

p2 = m2 * v2 = (0.15 kg) * (0 m/s) = 0 kg⋅m/s

The total momentum of the system before the collision is:

p1 + p2 = 0.1 kg⋅m/s + 0 kg⋅m/s = 0.1 kg⋅m/s

After the collision, the two cars move together with a common velocity (v), so the momentum of the system is:

p = (m1 + m2) * v

We can set the total momentum before the collision equal to the total momentum after the collision:

p1 + p2 = p

0.1 kg⋅m/s + 0 kg⋅m/s = (0.1 kg + 0.15 kg) * v

0.1 kg⋅m/s = 0.25 kg * v

v = 0.1 kg⋅m/s ÷ 0.25 kg

v = 0.4 m/s

Therefore, the two cars move off together at a speed of 0.4 m/s after the collision.

The time taken to get up and out of the way before you and the child collide is 2.82 s.

The time taken to get up and out of the way before you and the child collide is calculated as follows;

s = v + ¹/₂at²

s = v + ¹/₂(g sin (31)t²

where;

The time taken to get up is calculated as;

20 = 0 +  ¹/₂(9.8 sin (31)t²

20 = 2.524t²

t² = 20/2.524

t² = 7.925

t = 2.82 s

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The correct answer is using ultrasonic waves to create images of objects found inside other objects.

Infrasonic Wave: An infrasonic wave is a longitudinal elastic wave whose frequency is lower than that of sound, or 20Hz. For instance: It typically occurs during an earthquake. Ultrasonic Wave: An ultrasonic wave is a longitudinal wave with a frequency greater than the threshold of human hearing, or 20 kHz.

The audible range of frequencies below 20 Hz is known as infrasonic. Volcanoes, earthquakes, and thunder all emit sound in the infrasonic range. Human ears cannot hear this sound, but elephants and whales can. Ultrasonic frequencies are those that are above 20,000 Hz.

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Answer:

The answer is 13.5g/cm³

Explanation:

m1=20g

m3=70g

m2=695g

v=20cm³

m2-m1/m3-m1

R.d=695-20/70-20

R.d=675/50

R.d=13.5

R.d=density of liquid/density of water

density of liquid =R.d×density of water

D=13.5×1

D=13.5g/cm³

The pressure exerted by the girl is approximately 833,333.33 Pa (Pascals).

The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.

This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.

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complete question not found in search engine.

(a) The S-P difference of the wave is determined as is 40 sec.

(b) The amplitude of the wave is determined as is 10 mm

(c) The distance of the wave is determined as is 380 km

(d) The magnitude of the wave is determined as is 4.5

The amplitude of a wave is the maximum displacement or distance that a wave moves from its rest position to its crest (the highest point) or trough (the lowest point). In other words, it is the measure of the strength or intensity of a wave.

Question 1:

From the graph, the S-P difference, that is between S and P = 40 s - 0 s

= 40 s

Question 2:

The distance (km) corresponding to 40 sec is 380 km.

Question 3:

The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.

Question 4:

The corresponding magnitude of the wave is 4.5.

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In the case, Mel stretches a spring exercise device by 0.73 meters with a force of 177 N. We can use Hooke's law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position, to calculate the stiffness constant.

Hooke's law is given by the equation:

F = kx, where F is the force applied to the spring, k is the stiffness constant, and x is the displacement of the spring from its equilibrium position.

Plugging in the given values:

Force (F) = 177 N Displacement (x) = 0.73 m

We can rearrange the equation to solve for the stiffness constant (k):

k = F / x

Plugging in the values:

k = 177 N / 0.73 m

k ≈ 242.47 N/m (rounded to two decimal places)

Therefore, the stiffness constant of the spring exercise device is approximately 242.47 N/m.

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