he Anwar family is planning to build a new home. They have hired 2 different architects to create blueprints for the house. Anderson Architects uses a scale of 1 in. to represent 1.5 feet. Charleston Architects uses a scale of 1.5 inches to represent 1 foot. If each group draws a room that is 12 inches by 12 inches on the plans, what is the difference in size in real life of the two drawings?

Answer:

1/3

Step-by-step explanation:

Number of pizza=12

Number of students=4

Therefore,4/12=4/4

=1/3

[tex]\csc \theta \tan \theta - \tan \theta \sin \theta \\\\\\=\dfrac 1{\sin \theta} \cdot \dfrac{\sin \theta }{\cos \theta }- \dfrac{\sin \theta }{\cos \theta} \cdot \sin \theta\\\\\\=\dfrac{1}{\cos \theta}-\dfrac{\sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{1- \sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{\cos^2 \theta}{\cos \theta}~~~~~~~~~~~~~~;[\sin^2 \theta + \cos^2 \theta =1 ]\\\\\\=\cos \theta[/tex]

Let's write out some trigonometric identities that we can use:

Now let's try solving them out:

  [tex]csc(x)tan(x)-tan(x)sin(x)=\frac{1}{sin(x)}tan(x)-sin(x)tan(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)}-sin(x))\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)} -\frac{sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=tan(x)*(\frac{1-sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{cos(x)}*\frac{cos^2(x)}{sin(x)} \\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{sin(x)}*\frac{cos^2(x)}{cos(x)}\\\\csc(x)tan(x)-tan(x)sin(x)=1 * cos(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=cos(x)[/tex]

  *I used a different variable, but that doesn't change the answer

Answer: cos(x)

Hope that helps!

Answer:

Step-by-step explanation:

167.00 / 100 = $1.67

Answer:

129060

Step-by-step explanation:

135 000 - .044(135000) = 129 060

Answer:

Step-by-step explanation:

Multiplying or dividing an inequality by a negative number requires that the inequality symbol be reversed.

__

To solve this inequality, we can divide by the coefficient of x, which is -8. Dividing by -8 means we need to reverse the inequality symbol.

_____

Additional comment

Actually, applying any function that has a negative slope means the ordering is reversed. That is the more general case.

Here, we're specifically concerned with division by a negative number. You can see the effect on the ordering relation by considering ...

Answer:

y intercept: 65

rate of change: $2.75

Step-by-step explanation:

Really quite simple lad. Your equation is y=2.75x+65. 65 is your y-intercept, and you have a rate of change of 2.75 per bouquet.

Answer:

18cm

Step-by-step explanation:

Given:

- The length of AB is 9 centimeters

- A dilation with a scale factor of 2

The length of the image AB after the dilation is applied:

9 x 2 = 18

dilation is used to make an image or in this case AB, with a scale factor of 2 means that its doubling in size. If the scale factor was 1/2 that it would be decreasing in size since it will be half of the original size

Answer:

x=120°

Step-by-step explanation:

sum of all angles in a triangle is equal to 180

let the unknown angle be

[tex] \alpha [/tex]

[tex]60 + 60 + \alpha = 180 \\ \alpha = 180 - 60 - 60 \\ \alpha = 60 \\ [/tex]

[tex] \alpha + x = 180 \\ x = 180 - \alpha \\ x = 180 - 60 \\ x = 120[/tex]

Answer:

Number of terms  = 31.

Step-by-step explanation:

Sum of n terms of an A S with first term 1 and common difference 1:-

496 = (n/2)(2(1) + 1(n - 1))

496 = (n/2)(n + 1)

n^2/2 + n/2 = 496   Multiply through by 2:-

n^2 + n = 992

n^2 + n - 992 = 0

(n - 31)(n + 32) = 0

n = 31   (we ignore the negative).

The limit of the expressions [tex]3^{2n} + 1[/tex] and [tex]4^{n + 2} - 3[/tex] for n to infinity is infinity

The expressions are given as:

[tex]3^{2n} + 1[/tex]

[tex]4^{n + 2} - 3[/tex]

The limits of the expressions as they approach infinity are represented as:

[tex]\lim_{n \to \infty} 3^{2n} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{n + 2} - 3[/tex]

Substitute [tex]\infty[/tex] for n in both expressions

[tex]\lim_{n \to \infty} 3^{2 * \infty} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{\infty + 2} - 3[/tex]

Solve both expressions independently;

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{2 * \infty} + 1[/tex]

Evaluate the product

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{\infty} + 1[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty + 1[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty[/tex]

Also, we have:

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty + 2} - 3[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty} - 3[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty - 3[/tex]

Evaluate the difference

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty[/tex]

Hence, the limit of the expressions for n to infinity is infinity

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Answer:

See below ~

Step-by-step explanation:

Details of Graph

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]-2x+4y=8\implies 4y=2x+8\implies y=\cfrac{2x+8}{4} \\\\\\ y=\cfrac{2x}{4}+\cfrac{8}{4}\implies y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+2\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

since we know that's its slope, then

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{1}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{1}\implies -2}}[/tex]

so then we're really looking for the equation of a line whose slope is -2 and passes through (2 , 1)

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ y-1=-2x-4\implies y=-2x-3[/tex]

Answer:

33v - 48

Step-by-step explanation:

- 9v - 6(8 - 7v) ← multiply each term in the parenthesis by - 6

= - 9v - 48 + 42v ← collect like terms

= 33v - 48

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: - 9v - 6(8 - 7v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - [(6 \times 8) - (6 \times 7v)][/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - (48 - 42v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - 48 + 42v[/tex]

[tex]\qquad \sf  \dashrightarrow \:33v - 48[/tex]

Hope it helps ~

Answer:

y = 3x + 3

Step-by-step explanation:

when you check, only that equation delivers the correct x and y pairs.

x = 0, => y = 3×0 + 3 = 3

x = 1, y = 3×1 + 3 = 3+3 = 6

x = 2, y = 3×2 + 3 = 6 + 3 = 9

x = 3, y = 3×3 + 3 = 9 + 3 = 12

it all fits.

Answer:

mean is 2 brothers.

mean, means average

The equation that represents the solution of x is x = 2 - y/2

The equation is given as:

14x + 7y = 28

Divide through by 7

2x + y = 4

Subtract y from both sides

2x = 4 - y

Divide both sides by 2

x = 2 - y/2

Hence, the equation that represents the solution of x is x = 2 - y/2

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Answer: B

Step-by-step explanation: There are many less face cards in the deck than other cards, you would think youre getting 3 points each time rather than thinking 10 points each time

Answer:

0.9974

Step-by-step explanation:

[tex]arcsin( \frac{1}{7} ) = 0.1433 \\ cos( \frac{0.1433}{2} ) = 0.9974[/tex]

Answer:

cross multiplication

x

Answer:

y=3x-27

Step-by-step explanation:

[tex]\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

               Write an equation of the line passing through (6, -9) and has a slope of -3.

[tex]\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

First, we need to write the equation in point-slope form:-

[tex]\hookrightarrow\sf{y-y_1=m(x-x_1)}[/tex]

[tex]\hookrightarrow\sf{y-(-9)=3(x-6)}[/tex]

[tex]\bigstar[/tex] On simplification,

[tex]\hookrightarrow\sf{y+9=3(x-6)}[/tex]

[tex]\bigstar[/tex] On further simplification,

[tex]\hookrightarrow\sf{y+9=3x-18}[/tex]

[tex]\star[/tex] Subtract 9 from both sides, which results in:-

[tex]\hookrightarrow\sf{y=3x-27}[/tex]

So we conclude that Option B is correct.

[tex]\rule{300}{1}[/tex]

Answer:

hope you understand......

Answer:

13 m

Step-by-step explanation:

Answer:

A. -2

Step-by-step explanation: